Which of these reactions is an addition reaction?

A.) H4C2+Br2 → H5C2Br + HBr
B.) H4C2 + HBr → H5C2Br
C.) H5C2CI+ NaOH → H5C20H + NaCl

Parts per million (ppm) is a term used to describe the concentration of a chemical present in the environment.

It represents the ratio of the number of units of the chemical (e.g., weight, volume) to the total number of units in the environment, multiplied by one million. It is commonly used in environmental monitoring and regulations to express low levels of contaminants or pollutants in air, water, soil, or other substances.

Ppm provides a way to quantify trace amounts of substances, indicating the number of parts of the chemical per one million parts of the environment.

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The  water is in the liquid state.

Enthalpy is a thermodynamic property of a system, defined as the sum of the internal energy of the system and the product of its pressure and volume. In other words, it is a measure of the total energy content of a system at constant pressure.

Enthalpy is denoted by the symbol H and is often used in thermodynamics to describe heat exchange between a system and its surroundings.

The change in enthalpy, denoted as ΔH, is the difference between the enthalpy of the products and the enthalpy of the reactants, and is a key parameter in determining the feasibility and energetics of chemical reactions.

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Answer:

see explanation

Explanation:

Break down the following equations into two half equations(One for oxidation, one or reduction )

1. Cu + 2Ag+ ➡️Cu2+ +2Ag

2. Cl2 +2I- ➡️I2 + 2Cl​-

in reaction "1", the copper is being oxidized from 0 to +2 by losing 2 electrons

Cu---->Cu2+   + 2e-in reaction "2

in reaction "1" the silver is being reduced by gaining those 2 e-.

2Ag1+  + 2e----------->2Ag

In reaction "2", the iodine is being oxidized by losing 2 e-

2I- -------------> I2 + 2e

In reaction "2" the chlorine is being reduced by gaining those 2 e

Cl2 + 2e------------> 2Cl-

To solve such this we must know the concept of redox reaction. Therefore, the half reaction for the given reactions can be written as

1. Cu + 2Ag⁺ \(\rightarrow\)Cu²⁺ +2A

Cu \(\rightarrow\)Cu²⁺   + 2e⁻

2Ag⁺ + 2e⁻\(\rightarrow\)2Ag

2.Cl\(_2\)+2I⁻ \(\rightarrow\)I\(_2\) + 2Cl​⁻

2I⁻\(\rightarrow\) I\(_2\) + 2e⁻

Cl\(_2\) + 2e⁻-----------> 2Cl⁻

Chemical reaction is a process in which two or more than two molecules collide in right orientation and energy to form a new chemical compound. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, double displacement reaction.

Redox reaction is a chemical reaction where oxidation and reduction takes place simultaneously. Oxidation is loss of electrons and reduction is gain of electrons. The electron transfer from oxidant to reductant.

1. Cu + 2Ag⁺ \(\rightarrow\)Cu²⁺ +2A

Cu \(\rightarrow\)Cu²⁺   + 2e⁻

2Ag⁺ + 2e⁻\(\rightarrow\)2Ag

2.Cl\(_2\)+2I⁻ \(\rightarrow\)I\(_2\) + 2Cl​⁻

2I⁻\(\rightarrow\) I\(_2\) + 2e⁻

Cl\(_2\) + 2e⁻-----------> 2Cl⁻

Therefore, the half reaction for the given reactions can be written as above.

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Answer:

c elevation

Explanation:

C is the answer for your question

The actual yield of the product obtained in the experiment must be divided by the theoretical yield of the product that could be achieved. The reaction's percent yield is 32% as a result.

The amount of product produced in a chemical reaction or manufacturing process is referred to as yield, and it is typically expressed in mass or volume. Theoretical yield, actual yield, and percent yield are a few of the several types of yield. Theoretical yield, under the assumption that the reaction continues to completion without any losses or side reactions, is the greatest quantity of product that can be produced from a specific amount of reactants. The amount of product that is actually produced during an experiment or production process is known as the "actual yield." The actual yield to theoretical yield ratio, stated as a percentage, is known as percent yield. The efficiency and profitability of a chemical reaction or manufacturing process are significantly influenced by yield.

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At the equivalence point of a titration, the number of moles of acid present in the solution equals the number of moles of base added from the buret.

At the equivalence point of a titration, the number of moles of acid present in the solution equals the number of moles of base added from the buret. Therefore, the first condition is met at the equivalence point of the titration of a monoprotic weak acid with a strong base. The second condition is not necessarily met, as the volume of base added may be less than or greater than the volume of acid titrated depending on the strength of the acid and base used. The third condition is generally not met at the equivalence point of the titration of a monoprotic weak acid with a strong base, as the resulting solution will typically have a pH greater than 7.00 due to the formation of the conjugate base of the weak acid. The pH at the equivalence point of a titration depends on the strength of the acid and base being used.

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The half reaction will be  IO² (j)  6 OH⁻ (aq) → IO³⁻ (aq) 3H₂O (I) 6e⁻.

In this reaction, IO₂ is oxidized to IO³ losing 6 electrons. Hydroxide ions (OH⁻) are added to balance the charge on both sides of the equation, and water molecules are formed as products.

The oxidation of solid iodine dioxide (IO²) to iodine ion (IO³⁻) can be described by the following half-reaction in an alkaline aqueous solution:

IO² (j)  6 OH⁻ (aq) → IO³⁻ (aq) 3H₂O (I) 6e⁻

Note that this is a half-reaction of the oxidation process. To obtain a complete balanced equation for a redox reaction involving IO₂ and some other species, you must also  write the half-reaction for the reduction process and balance the number of electrons transferred.

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The question is incomplete, the complete question is:

What is half-reaction for the oxidation of solid iodine dioxide IO2 to iodate ion IO−3 in basic aqueous solution?

To determine the empirical formula, we need to find the simplest whole number ratio between the elements present in the compound.

Given the percentages:

Aluminum (Al) = 35.98%

Sulfur (S) = 64.02%

Step 1: Convert the percentages to grams.

Assuming we have 100 grams of the compound:

Aluminum (Al) = 35.98 grams

Sulfur (S) = 64.02 grams

Step 2: Convert the grams to moles using the molar mass.

The molar mass of aluminum (Al) is 26.98 g/mol.

The molar mass of sulfur (S) is 32.06 g/mol.

Moles of Aluminum (Al) = 35.98 g / 26.98 g/mol ≈ 1.333 moles

Moles of Sulfur (S) = 64.02 g / 32.06 g/mol ≈ 1.997 moles

Step 3: Divide the moles of each element by the smallest number of moles to obtain the simplest whole number ratio.

Dividing both moles by 1.333 (the smallest number of moles), we get:

Moles of Aluminum (Al) ≈ 1 mole

Moles of Sulfur (S) ≈ 1.5 moles

Therefore, the empirical formula is AlS1.5, which can be simplified to Al2S3 by multiplying all subscripts by 2.

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Answer:

Rate cup 1: 36.00 tsp/h.

Rate cup 2: 59.50 tsp/h.

Rate cup 3: 70.13 tsp/h.

Explanation:

Based on the given example, the units must be in tsp/hour. To do this we just have to divide tsp by seconds and then convert it to hours remembering that 1 hour equals 3600 seconds.

Let's calculate each case:

- Cup 1: 1 tsp, 1 minute 40 seconds. Remember that 1 minute equals 60 seconds, so 1 minute and 40 seconds equals 100 seconds. The calculation of the rate will look like this:

The rate of cup 1 is 36.00 tsp/h.

- Cup 2: 2 tsp, 2 minutes 1 second. As we saw before 1 minute equals 60 seconds, so 2 minutes equals 120 seconds. 2 minutes and 1 second equals 121 seconds. The rate of cup 2 will be calculated as:

The rate of cup 2 is 59.50 tsp/h.

- Cup 3: 3 tsp, 2 minutes 34 seconds. 2 minutes are the same that 120 seconds, so 2 minutes 34 seconds equals 154 seconds. The rate of cup 3 is calculated as follows:

The rate of cup 3 is 70.13 tsp/h.

Answer:

it's blue/green

Explanation:

Answer:

A) Glycerol

Explana

Answer:

True

Explanation:

The electron configuration of calcium (Ca) is 1\(s^{2}\)2  \(s^{2}\)2\(p^{6}\)3  \(s^{2}\)3\(p^{6}\)4  \(s^{2}\).  This tells us that there are 2 electrons in the 4th energy shell of an atom with 8 otyher electrons distributed as described in the electron configuration among the energy shells and orbitals (s, p, d, and f).

Answer:6.02

Explanation:

Answer:

there are about 6 atoms in hydrogen

Answer:

Are you trolling us?

Explanation:

Answer:

5.1 moles of P2O3 are required

Explanation:

Based on the reaction, 1 mole of diphosphorus trioxide, P2O3, reacts with 3 moles of water to produce 2 moles of phosphorous acid, H3PO3. That means the conversion factor is: 1mol P2O3 = 2mol H3PO3.

The moles of P2O3 required to produce 10.2mol H3PO3 are:

10.2mol H3PO3 * (1mol P2O3 / 2mol H3PO3) =

Answer:

4.29 /mL

Explanation:

density= mass/volume

The density of the unknown object is 4.929 centimeter cube ( cm³ ).

Density is the mass of an object in the per unit volume of liquid and can be calculated by dividing the mass of an object to the volume of the object and the unit of density is centimeter cube.

Here, mass of object is 35.49 g and the water displacement to find the volume is 52.3 mL-  45.1 mL = 7.2 ml.

                    Density = mass of object / volume of object

Substituting the value in formula,

                    density = 35.49 / 7.2

                     Density =  4.929 centimeter cube ( cm³ )

Therefore,  4.929 centimeter cube ( cm³ ) is the density of a given object.

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Answer:

B

Explanation:

Answer:

active carriers

Explanation:

Mosquitoes are responsible for transmitting the zika virus. In this case, the mosquitoes are active carriers

Answer:

E -- active carriers

Explanation:

the mosquitos would be active carriers...

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Answer:

2

Explanation:

Answer:

C)peer review

Explanation:

Peer review involves the evaluation of scientific research work by other professionals working in the same field. It is one of the stages a manuscript passes through before it is published in any reputable journal.

Peer review is important because it ensures that only high quality and original scientific research is published for the consumption of other professionals in the same field.

The bond strength in F2- is expected to be weaker than in the F2 molecule. The additional electron in F2- introduces repulsion, destabilizing the bond and reducing its strength.

The F2- ion will have an additional electron compared to the F2 molecule. Using molecular orbital theory, we can determine the electron configuration of F2- as \((σ1s)^2(σ*1s)^2(σ2s)^2(σ*2s)^2(π2p)^4(π*2p)^4.\)

Bond order is calculated by subtracting the number of antibonding electrons from the number of bonding electrons and dividing the result by 2. In the case of F2-, there are 10 bonding electrons and 8 antibonding electrons. Therefore, the bond order is [(10 - 8) / 2] = 1.

The F2- ion has unpaired electrons, making it paramagnetic.

The bond length in F2- is expected to be longer than in the F2 molecule. This is due to the addition of an extra electron, which increases electron-electron repulsion, resulting in an elongation of the bond.

Note: It is important to refer to the specific molecular orbital diagram provided in Figure 10.13 of the mentioned textbook for precise information and calculations.

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There is  18.4 % oxygen in the compound, 12.8 % hydrogen in the compound and  69.0 % carbon in the compound.

The molecular formula of the compound is; C10H22O2. From this, we can calculate the molar mass of the compound as follows;

Molar mass = 10(12) + 22(1) + 2(16) = 120 + 22 + 32 = 174 g

Percent of oxygen in the compound =  32.00 g/174 g × 100/1 = 18.4 %

Percent of hydrogen in the compound = 22.22 g/174 g × 100/1 = 12.8 %

Percent of carbon in the compound = 120.10 g/174 g × 100/1 = 69.0 %

Hence, there is  18.4 % oxygen in the compound, 12.8 % hydrogen in the compound and 69.0 % carbon in the compound.

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The kilojoules of heat released per gram of the compound reacted with oxygen is -72.052 kj/g

The standard enthalpy of formation is a measure of the strength launched or fed on while one mole of a substance is created under trendy situations from its natural elements. The symbol of the standard enthalpy of formation is ΔH f. = A degree means that it's a fashionable enthalpy change.

Enthalpy of a formation refers to the trade in enthalpy for the formation of one mole of a substance from the maximum solid form of its constituent factors. change in enthalpy is symbolized by means of delta H and the f stands for formation.

Given,

compound             ΔH°f

B₅H₉                       73.2

B₂O₃                       -1271.94

H₂O                        -285.83

Balanced chemical equation:-

2B₅H₉  (l)  +  12O₂ +(g) => 5B₂O₃  + 9H₂O(l)

From Hess's law

ΔH°min = Σ enthalpies of products - Σ enthalpies of reactants

             = 5× (-1271.94) + 9×( -285.83) - 2(73.2) kj/mol

ΔH°min = -9078.59 kj/mol

It is seen that 2 moles of B₅H₉    react with O₂ is  -9078.59 kj/mol

For 1 mole = -9078.59 kj/mol/2

                 = 4539.295 KJ/mol

The energy released per gram = energy released per mol/molar mass of B₅H₉

                                            = 4539.295 kj/mol/63 g/mol

energy released per gram = -72.052 kj/g

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Answer:

influence of a business invironment

The concentration of the diprotic acid equals 3.4 M

We'll begin by writing the balanced equation for the reaction.

H₂X + 2NaOH —> Na₂X + 2H₂O

From the balanced equation above,

From the question given above, the following data were obtained:

MaVa / MbVb = nA/nB

(Ma × 25) / (1.95 × 87.42) = 1/2

(Ma × 25) / 170.469 = 1/2

Cross multiply

Ma × 25 × 2 = 170.469

Ma × 50 = 170.469

Divide both side by 50

Ma = 170.469 / 50

Ma = 3.4 M

Therefore, the concentration of the acid, H₂X is 3.4 M

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Answer:

B. Chemical weathering

Explanation:

Erosion is the process whereby the soil and rocks are washed away by wind, water, ice or gravity.

Weathering is the process of weakening and breaking down of rocks and minerals either by non-living (abiotic) or living (biotic) factors or by both, such as temperature changes, plants and animals, acids, salts and water, etc.

From the above definitions, it can be seen that acid wearing away limestone is a rock weathering process by a non-living agent, an acid.

Option A is wrong because the process is weathering

Option B is correct because an acid is a chemical and the process involved is weathering

Option C is wrong because an acid is non-living

Option D is wrong because the process involved is weathering

a. True. Sodium fluoroacetate, also known as "1080," is indeed the most effective fast-acting rodenticide Rodenticide Act available for use throughout the United States.

The Federal Insecticide, Fungicide, and Rodenticide Act (FIFRA) of 1947 is the law that governs the use of pesticides and herbicides in the USA. Certain substances are not allowed to be used as pesticides under this law.

A proper federal regulatory framework for the use, distribution, and sale of pesticides is provided by the Federal Insecticide, Fungicide, and Rodenticide Act (FIFRA) statute.

The purpose of this law (FIFRA) is to safeguard those who use pesticides, consumers, and the environment.

The US Environmental Protection Agency (EPA) is required to grant licences for the use of pesticides throughout the country.

To assure the safety and efficacy of all pesticides used in the US, the EPA reviews and registers them in accordance with FIFRA. The organisation also controls the use, handling, and disposal of pesticides and performs routine inspections to make sure they remain safe.

If someone or a business violates FIFRA rules, the EPA has the authority to file a lawsuit and, if necessary, revoke or suspend pesticide registrations.

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