Which operation is performed to convert a temperature given in degrees Celsius to a temperature in kelvin

Since there is no friction, the momentum before the collision is equal to the momentum after the collision.

(a) To determine the velocities after impact, we can use the conservation of momentum equation:

m1v1i + m2v2i = m1v1f + m2v2f

where m1 and m2 are the masses of the steel blocks, v1i and v2i are their velocities before impact, and v1f and v2f are their velocities after impact.

Plugging in the given values:

m1v1i + m2v2i = m1v1f + m2v2f

(10 kg)(4 m/s) + (20 kg)(-3 m/s) = (10 kg)v1f + (20 kg)v2f

Solving for v1f and v2f:

v1f = (-20 kg)(0.75)(-3 m/s - 4 m/s) / (10 kg) = -1.5 m/s

v2f = (10 kg)(0.75)(-3 m/s - 4 m/s) / (20 kg) = -1.05 m/s

Therefore, the velocities after impact are v1f = -1.5 m/s and v2f = -1.05 m/s.

(b) To determine the energy loss during impact, we can use the conservation of kinetic energy equation:

(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2 + energy loss

Plugging in the given values:

(1/2)(10 kg)(4 m/s)^2 + (1/2)(20 kg)(-3 m/s)^2 = (1/2)(10 kg)(-1.5 m/s)^2 + (1/2)(20 kg)(-1.05 m/s)^2 + energy loss

Simplifying:

80 J + 90 J = 11.25 J + 11.025 J + energy loss

energy loss = 147.925 J - 170 J = -22.075 J

Therefore, the energy loss during impact is 22.075 J. Since the value is negative, it indicates that the system gained energy during impact, which means that work was done by an external force (for example, the surface on which the blocks were sliding) on the system.

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F = m*a Formula (1), where F is the algebraic sum of the forces in Newton (N), m is mass (kg), and an is acceleration (m/s2).

Data, F= 100 N, a= 3.0 m/s²

(a) To get the block's mass, we substitute dta in the formula (1)

   F = m*a

  100 =  m*3

  m = 100 / 3

  m = 33.3 kg

We use the following formulas in kinematic analysis since the block moves with a uniformly accelerated motion:

  d= v₀t+ (1/2)*a*t² Formula (2)

  vf= v₀+a*t   Formula (3)

Where: t: time interval in seconds, and d: displacement in meters (m) (s), Initial speed is given as v0, ultimate speed is given as vf, and acceleration is given as an in m/s2.

Data, a= 3.0 m/s², v₀= 0, t = 10 s

(b) The block's travel distance if the force is applied for 10 seconds; we substitute dta in the formula (2):

   d= v₀t+ (1/2)*a*t²

   d = 0+ (1/2)*(3)*(10)²

   d =150 m

(c) Substituting dta in formula (3), determine the speed of the block after the force has been applied for 10 times:

   vf= v₀+a*t

   vf= 0+(3*(10)

   vf= 30 m/s

F magnitude horizontal force is delivered. Force always results in acceleration. We have motion in the direction of motion since there is no friction force or other force opposing the applied force in this situation.

On a horizontal, frictionless surface, something is resting. F magnitude horizontal force is delivered. Since there is no friction, this force always results in acceleration.

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According to the given statement the number x is 2. The number x represents the dimensions of the term p * a in the given equation.

By comparing the dimensions of both sides of the equation, we find that x is equal to 2.

The equation given is:

Volume per second = k * (p * a) / n

Where:
- k is a constant
- p is the excess pressure (force per unit area)
- a is the radius of the pipe
- n is the frictional quantity of dimension MLT⁻¹


To find the number x, we need to determine the dimensions of each term in the equation.

1. Dimension of Volume per second:

  - Volume has the dimension L³ (length cubed)
  - Time has the dimension T (time)
  - Therefore, Volume per second has the dimension L³  / T

2. Dimension of k:

  - The equation states that k is a constant. Constants are dimensionless.

3. Dimension of p * a:

  - Pressure has the dimension M / (L * T² ) (mass divided by length and time squared)
  - Radius has the dimension L (length)
  - Multiplying pressure by radius results in the dimension M / (L * T² ) * L = M / (L²  * T² )

4. Dimension of n:

  - Given in the question, n has the dimension MLT⁻¹
(mass times length times time to the power of -1)

Now, we can equate the dimensions:

L³  / T = k * (M / (L²  * T² )) * MLT⁻¹


Simplifying the dimensions:

L³  / T = k * M / (L²  * T² ) * MLT⁻¹


L³  / T = k * M / L²  * M / T²  * L^-1 * T⁻¹


L³  / T = k * M²  / L²  * T⁻¹


To equate the dimensions, both sides of the equation must have the same dimensions. Therefore:

L³ / T = k * M² / L² * T⁻¹


Comparing the dimensions on both sides, we can conclude:

L³ / T = k * M² / L²* T⁻¹

The dimensions on the left side are L^3 / T, and the dimensions on the right side are (k * M²) / (L² * T).

Therefore, the number x is 2.

The number x represents the dimensions of the term p * a in the given equation.

By comparing the dimensions of both sides of the equation, we find that x is equal to 2.

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Light acceleration is used to maintain slow forward motion or allow speed to increase gradually with minimum weight shift.

This is referred to the rate of change of velocity with time and  is regarded as a vector quantity.

It is also characterized by a positive forward motion and light acceleration on the other hand maintains slow forward motion or allow speed to increase gradually with minimum weight shift.

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Answer: Heyaa! ~

Microwaves have a little more energy than radio waves.

Explanation:

The prior difference between a radio wave and microwave is that the microwave has a shorter wavelength as compared to radio wave.

Hopefully this helps you!

- Matthew ^^

Microwaves have a higher frequency than radio waves so more information can be conveyed. Not only that, they have the ability to transmit signals over a long distance without losing any data.

i dont know thats why i downloaded brainly... so I COULD LEARN

Answer:

The final temperature is \(29.6^oC\).

Explanation:

When the two masses come in contact, one releases heat and the other absorbs it. The former can be modelled with the equation \(HeatLost = (Mass1 (kg))(c1)(T1-T)\), and the latter by \(HeatGained=(Mass2(kg))(c2)(T-T2)\)

m1=0.15 kg

m2=0.06 kg

T1 = 70 degrees Celsius = 343 K

T2 =  20 degrees Celsius = 293 K

T= Final temperature

c1 = Specific heat capacity of copper

c2 = Specific heat capacity of water

Because there is no heat lost into the surroundings, the heat removed from one substance is the same as the heat gained in the other. Therefore:

\((Mass1)(c1)(T1-T)=(Mass2)(c2)(T-T2)\)

\((0.150)(400)(343-T)=(0.06)(4184)(T-293)\)

\((60)(343-T)=(251.04)(T-293)\)

\(20580-60T=251.04T-73554.72\)

\(-311.04T=-94134.72\)

\(T=302.6 K\)

\(T=29.6^oC\)

Hope this helps! (My apologies if the answer is wrong, it has been a while since I've done this)

Answer:

Explanation:

how far around a circle is once around in degees?

1.5 * 360 = 540°

Explanation:

Weight=force=300N

height=2m

time=6seconds

power=?

now,

power (p)=f×h÷t

power=300×2÷6

power=100w

therefore,A man develops 100 watt power in 6 seconds.

The magnitude of the gravitational force on mass M is: F = G * (M * m) / (L^2 + d^2)

To find the magnitude of the gravitational force on mass M, we will use Newton's Law of Universal Gravitation. The formula for this is:
F = G * (M * m) / r^2
Where F is the gravitational force, G is the universal constant of gravitation, M and m are the masses of the objects, and r is the distance between their centers.

Given the information in the question, we have:
M = mass of the larger object
m = mass of the smaller object
L = distance between the centers of the two objects in the horizontal direction
d = distance between the centers of the two objects in the vertical direction

We need to find the total distance r between the centers of the objects. To do this, we can use the Pythagorean theorem:
r^2 = L^2 + d^2
Now, we can plug this into our gravitational force formula:
F = G * (M * m) / (L^2 + d^2)

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Explanation:

i guess using a ruler.so first on the opposite side use your eye to alighn the ruler to the light from Ray box then draw a line or you can use pins and place them alighned to the Ray box an draw a line connecting the pins

Answer:

C. Hawaiian

Explanation:

Ego's father and all male relatives in his generation have the same kin name. Ego's mother and all female relatives in her generation are referred to by the same kin term.

Similarly, all brothers and male cousins are linked by giving them the same kin term. Sisters and all female cousins are also referred to by the same term.  

The frequency of oscillation for the spring system of part i is 0.719 Hz.

Explanation: The frequency of a system is a measure of the number of cycles it completes per second, which is proportional to the square root of the ratio of the spring constant to the mass of the system.

In this case, the spring constant is given as k=2.5 N/m and the mass of the system is given as m=0.35 kg. Plugging these values into the equation for frequency, we get frequency (f) = 1/2π * sqrt(k/m) = 1/2π * sqrt(2.5/0.35) = 0.719 Hz. This result can be rounded to three decimal places, giving us 0.719 Hz.

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Vertical velocity after is just reversed in direction and came under gravitational acceleration. So correct option is B.

Velocity is a term commonly used in physics and engineering to describe the rate of change of an object's position with respect to time. It is a vector quantity, meaning it has both magnitude and direction, and is usually expressed in units of meters per second (m/s) or feet per second (ft/s).

Velocity can be positive, negative, or zero, depending on the direction of the object's motion relative to a reference point. Positive velocity indicates that the object is moving in the positive direction, negative velocity indicates that the object is moving in the negative direction, and zero velocity indicates that the object is not moving at all.

Velocity is an important concept in physics, as it is used to describe the motion of objects in both linear and circular paths, and is a key factor in determining the energy and momentum of those objects. It is also used in many real-world applications, such

vcosθ is horizontal velocity which will be constant in direction and magnitude.

Vertical velocity after is just reversed in direction and came under gravitational acceleration.

So correct option is B.

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The final speed of the UFO after experiencing a constant acceleration for 63 seconds is 351.3 m/s.

Acceleration is the rate at which an object increases its speed, velocity or rate of change. It is the rate of change of velocity over time, or the rate of change of the position of an object. Acceleration can be either positive, when the speed of an object is increasing, or negative, when the speed of an object is decreasing.

The final speed of the UFO can be determined by using the equation, v = u + at, where u is the initial velocity, a is the acceleration, and t is the time. So, in this case, v = 64 + (21,892.5/63) = 351.3 m/s. Therefore, the final speed of the UFO after experiencing a constant acceleration for 63 seconds is 351.3 m/s.

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Assuming you are supposed to write each conversion in scientific notation:

(2) 1 m = 100 cm, so

(67 cm) × (1/100 m/cm) = 67/100 m = 0.67 m = 6.7 × 10 ⁻¹ m

(3) 1 km = 1,000 m, so

(1.2 km) × (1000 m/km) = 1200 m = 1.2 × 10³ m

(4) 1 m = 1,000 mm = 10³ mm, so

(6.2 × 10 ⁻³ m) × (10³ mm/m) = 6.2 mm

(5) 1 m = 1,000,000,000 nm = 10⁹ nm, so

(4.05 × 10³ nm) × (1/10⁹ m/nm) = 4.05 × 10 ⁻⁶ m

(6) 1 g = 1,000,000 µg = 10⁶ µg, so

(3200 µg) × (1/10⁶ g/µg) = 3200 × 10 ⁻⁶ g = 3.2 × 10 ⁻³ g

The time of flight is obtained as 25.9 seconds

The time of flight is the time taken to move the object that have been projected along the parabolic path. In this case, we have a cannonball that have been fired  from level ground with a velocity of 240.0 m/s at an angle of 32 degrees.

We know that from the question

T = 2usinθ/g

T = time of flight

u = initial velocity

θ = angle of projection

g = acceleration

T = 2 * 240.0 m/s * sin 32 degrees/9.8 m/s^2

T = 25.9 seconds

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The total power dissipated by the circuit is 36W. We can solve this circuit using a combination of Ohm's Law and Kirchhoff's Laws.

(a) To find the effective resistance of the circuit, we can first simplify the circuit by combining the two parallel resistors:

1/Req = 1/2Ω + 1/3Ω

1/Req = 5/6Ω

Req = 6/5Ω

Now, we can combine the two series resistors with Req: Req_tot = 6/5Ω + 4Ω = 14/5Ω

Therefore, the effective resistance of the circuit is 14/5Ω, or 2.8Ω.

(b) Using Ohm's Law, we can find the current through each resistor if we know the voltage across it. Since the 3Ω resistor has a voltage difference of 6V across it, the current through it is:

I = V/R = 6V/3Ω = 2A

Using Kirchhoff's Current Law (KCL), we know that the current through the 2Ω resistor is the same as the current through the 3Ω resistor. Therefore, the current through the 2Ω resistor is also 2A.

(c) Using Kirchhoff's Voltage Law (KVL), we know that the sum of the voltage drops across each resistor must be equal to the battery voltage. Therefore, we can calculate the battery voltage by adding the voltage drops across each resistor: V_battery = V_2Ω + V_3Ω + V_4Ω

We know the current through each resistor, so we can use Ohm's Law to calculate the voltage drop across each resistor:

V_2Ω = IR = (2A)(2Ω) = 4V

V_3Ω = IR = (2A)(3Ω) = 6V

V_4Ω = IR = (2A)(4Ω) = 8V

Substituting these values, we get:

V_battery = 4V + 6V + 8V = 18V

Therefore, the battery voltage is 18V.

(d) To calculate the total power dissipated by the circuit, we can use the formula:

P = IV

We know the current through each resistor, so we can use Ohm's Law to calculate the voltage drop across each resistor, and then use the formula above to calculate the power dissipated by each resistor:

P_2Ω = (2A)(4V) = 8W

P_3Ω = (2A)(6V) = 12W

P_4Ω = (2A)(8V) = 16W

The total power dissipated by the circuit is the sum of the power dissipated by each resistor:

P_tot = P_2Ω + P_3Ω + P_4Ω = 8W + 12W + 16W = 36W

Therefore, the total power dissipated by the circuit is 36W.

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If the ball exits the track while undergoing an acceleration of 3g, 55.4m away from the base of the track does the block land

Acceleration ac = V²/R = 3g

V = √3gR

By using kinematic equation for vertical motion of ball,

S = u t  + 1/2 gt²

S = 2R, U = 0

t = √4R/g

Horizontal distance is given by

D = vt = √3gR × √4R/g

D = 2√3 R

D = 55.4m

To get the equation for the horizontal distance, one can rearrange the slope percent equation. Divide both sides by run to rewrite the equation's terms. The slope percent is applied to both sides. Horizontal distance is calculated as run = (rise 100) / slope%. When two points are separated by a horizontal distance, the slope is zero percent.

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Answer:

NaHCO3 + CaCl2 = CaCO3 + 2NaCl + H2O

Explanation:

It is physically impossible to balance this equation you may be missing another compound

38 nm A waveform signal that is carried in space or down a wire has a wavelength,

A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is typically defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm) (mm).

The wavelength of the wave is the distance covered by it throughout a whole oscillation. A meter is the wavelength's SI unit (m).

*v=c/λ

v: 7.8 × 10^15 Hz c: 3.00*10^8 λ:?

7.8 × 10^15 Hz = 3.0010^8/λ

λ = 3.0010^8 m/s /7.8 × 10^15

λ = 3.8 10^-8

The calculated wavelength is in unit of meter. use the relationship between meter and nanometer to convert to the correct units.

3.8 10^-8 m (1nm/ 110^-9m )

= 38 nm

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Answer:

Non-examples of conduction include convection, radiation, and deformation. Convection is the transfer of heat through the movement of a liquid or gas, whereas radiation is the transfer of energy through electromagnetic waves. Deformation is a change in shape due to force.

Answer:  some examples of non-conductive materials include paper, glass, rubber, porcelain, ceramic and plastic.

Explanation:

Answer:

answer is 1000 N

formula used-

F= m x (v-u/t)

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Let's look at relationship

\(\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{m}{k}}\)

\(\\ \rm\rightarrowtail T\propto \sqrt{m}\)

Hence

\(\\ \rm\rightarrowtail \dfrac{T_1}{T_2}=\sqrt{\dfrac{m1}{m2}}\)

\(\\ \rm\rightarrowtail \dfrac{1.5}{2}=\sqrt{\dfrac{0.5}{m2}}\)

\(\\ \rm\rightarrowtail 0.75^2=\dfrac{0.5}{m2}\)

\(\\ \rm\rightarrowtail m_2=\dfrac{0.5}{0.75^2}\)

\(\\ \rm\rightarrowtail m_2=0.889\)

Hence

Answer

Mass needs to added =0.889-0.500=0.389kg

Explanation:

A galaxy is an enormous collection of gas, dust, billions of stars, and their solar systems all locked together by gravity.

A nebula is a very large cloud of gas and dust in outer space. When a dying star explodes, such as during a supernova, gas and dust are released into space, creating certain nebulae. Other nebulae are places where brand-new stars are only starting to develop.

The substance that fills the void between stars is, in a nutshell, the interstellar medium. Dust makes up the remaining 1% of the interstellar medium, which is 99% gas (mainly hydrogen).

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Answer:

x =

\( - 15 \times \frac{ \sqrt{3} }{2} \frac{m}{s} \)

y = 7.5m/s

Answer:

Umm Lucy will weigh to many pounds

Explanation: