Which phrase describes velocity?
u
A. A quantity with direction only
B. A quantity with magnitude only
C. A quantity with no units
D. A quantity with magnitude and direction
SUBMI

Answer:

I believe it is C, Potential

Explanation:

Google, since all types are either kinetic or potential, so it wouldn't make sense if kinetic was itself. I also know for a fact it isn't Chemical

The final temperature of the water is approximately 19.8°C.First, we need to calculate the heat lost by the water as it cools down from 80°C to the final temperature.

We can use the formula: Q = m × c × ΔT where Q is the heat lost, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

The mass of water in the calorimeter is:

90 ml = 90 g

The heat lost by the water is:

Q1 = 90 g × 4.18 J/g°C × (80°C - T)

Q = m × Lf + m × c × ΔT

The mass of ice added to the water is 10 g. The heat gained by the ice is:

Q2 = 10 g × 334 J/g + 10 g × 4.18 J/g°C × (T - (-20°C))

where 334 J/g is the heat of fusion of water.

Since the calorimeter is insulated, we know that the heat lost by the water must equal the heat gained by the ice. Therefore:

Q1 = Q2

90 g × 4.18 J/g°C × (80°C - T) = 10 g × 334 J/g + 10 g × 4.18 J/g°C × (T - (-20°C))

Simplifying and solving for T, we get:

T = 19.8°C

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Answer:Type of metal

Explanation:Basically certain types of metal may heat and get cold faster maybe the alumm may collect more sun and heat more and stay that way

Due to the higher thermal conductivity of aluminium, it has higher temperature than gold.

The ability of a material to conduct or transport heat is referred to as thermal conductivity.

Here,

It is not the solid itself that moves in bulk as a result of thermal conductivity; rather, it is molecular agitation and contact.

A region of high temperature and high molecular energy is moved towards a region of lower temperature and lower molecular energy via a temperature gradient.

The density of aluminium is small. It is easily castable, machinable, and formable, and it has a high thermal conductivity and great corrosion resistance.

At 20 °C, gold has an electrical resistivity of 0.022 micro-ohm m and a thermal conductivity of 310 W m-1 K-1.

Aluminium conducts more heat than gold.

Hence,

Due to the higher thermal conductivity of aluminium, it has higher temperature than gold.

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Answer:

wait

Explanation:

Answer:

a) v = 1.1 m/s

b) A = 0.315 m

c) v = 1.1 m/s  A= 0.15 m

Explanation:

a)

        \(v = \lambda * f (1)\)

       \(f = \frac{1}{T} = \frac{1}{5.20s} = 0.19 Hz (3)\)

      \(v = \lambda * f = 5.70 m * 0.19 Hz = 1.10 m/s (4)\)

b)

      \(A = \frac{0.630m}{2} = 0.315 m (5)\)

c)  

       v = 1.10 m/s (6)

       \(A = \frac{0.30m}{2} = 0.15 m (7)\)

Answer: 0N

Explanation: 15N-15N =0N

they are a balanced force,meaning they canceled each other out.

To determine the magnitude of the lift force ⃗ and the force of air resistance ⃗ acting on the jet, we need to resolve the weight ⃗ and the forward thrust ⃗ into their horizontal and vertical components.

The weight ⃗ can be resolved into two components:

- the vertical component, Wsin(30°), acting downward

- the horizontal component, Wcos(30°), acting to the left

The forward thrust ⃗ can also be resolved into two components:

- the vertical component, Tsin(30°), acting upward

- the horizontal component, Tcos(30°), acting to the right

Since the jet is flying at a constant speed, the lift force ⃗ must be equal in magnitude to the weight component acting downward, Wsin(30°). Therefore, the magnitude of ⃗ is 86,500 Nsin(30°) = 43,250 N.

The force of air resistance ⃗ is equal in magnitude to the horizontal component of the weight, Wcos(30°), minus the horizontal component of the forward thrust, Tcos(30°). Therefore, the magnitude of ⃗ is (86,500 Ncos(30°)) - (103,000 Ncos(30°)) = -8,715 N, where the negative sign indicates that the force of air resistance is acting in the opposite direction to the motion of the jet.

Therefore, the magnitude of the lift force ⃗ is 43,250 N and the magnitude of the force of air resistance ⃗ is 8,715 N.

The final speed of cart 2 is -1.0 m/s, and the final speed of cart 3 is 0.5 m/s.

To find the final speeds of cart 2 and cart 3 after the collision, we can use the principles of conservation of momentum and kinetic energy.

Given:

Mass of cart 1 (approaching cart): m = 0.20 kg

Initial velocity of cart 1: v0 = 1.5 m/s

Mass of cart 2: 2m

Mass of cart 3: 3m

Let's denote the final velocities of cart 2 and cart 3 as v2 and v3, respectively.

According to the conservation of momentum, the total momentum before the collision should be equal to the total momentum after the collision.

Initial momentum = Final momentum

(m * v0) + (2m * 0) + (3m * 0) = m * v2 + 2m * v3 + 3m * v3

Simplifying the equation, we have:

m * v0 = m * v2 + 5m * v3    ...(1)

Since the collision is elastic, the total kinetic energy before the collision should be equal to the total kinetic energy after the collision.

Initial kinetic energy = Final kinetic energy

(1/2) * m *\(v0^2 = (1/2) * m * v2^2 + (1/2) * 2m * v3^2 + (1/2) * 3m * v3^2\)

Simplifying the equation, we have:

(1/2) * m *\(v0^2 = (1/2) * m * v2^2 + m * v3^2 + (3/2) * m * v3^2\)

m * \(v0^2 = m * v2^2 + 2m * v3^2 + 3m * v3^2\)

\(v0^2 = v2^2 + 2v3^2 + 3v3^2\)    ...(2)

Now, we have two equations (equation 1 and equation 2) with two unknowns (v2 and v3). We can solve these equations simultaneously to find the values of v2 and v3.

From equation 1, we can rewrite it as:

v2 = v0 - 5v3

Substituting this expression into equation 2, we get:

\(v0^2 = (v0 - 5v3)^2 + 2v3^2 + 3v3^2\)

Expanding and simplifying the equation, we have:

\(v0^2 = v0^2 - 10v0v3 + 25v3^2 + 2v3^2 + 3v3^2\)

\(0 = -10v0v3 + 30v3^2\)

Rearranging the equation, we get:

10v0v3 = 30\(v3^2\)

v0 = 3v3

Solving for v3, we find:

v3 = v0/3 = (1.5 m/s) / 3 = 0.5 m/s

Substituting this value of v3 back into the expression for v2, we have:

v2 = v0 - 5v3 = 1.5 m/s - 5 * 0.5 m/s = 1.5 m/s - 2.5 m/s = -1.0 m/s

Therefore, the final speed of cart 2 is -1.0 m/s (indicating it moves in the opposite direction with respect to the initial velocity), and the final speed of cart 3 is 0.5 m/s.

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The medium in which electromagnetic waves and mechanical waves travel is one of their primary distinctions. Light and other electromagnetic waves, including radio waves, can move through void space without the aid of a physical medium.

They may move through vacuum, air, or other materials and are made up of oscillating electric and magnetic fields. The propagation of mechanical waves, such as sound or water waves, on the other hand, depends on a physical medium.

To transport energy, they rely on particle interactions and displacements in the medium. Since mechanical waves need a physical medium to carry their energy, they cannot move through a vacuum.

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Answer:

The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q.

Explanation:

Electric field strength is a vector quantity; it has both magnitude and direction. The magnitude of the electric field strength is defined in terms of how it is measured. Let's suppose that an electric charge can be denoted by the symbol Q. This electric charge creates an electric field; since Q is the source of the electric field, we will refer to it as the source charge. The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q. When placed within the electric field, the test charge will experience an electric force - either attractive or repulsive. As is usually the case, this force will be denoted by the symbol F. The magnitude of the electric field is simply defined as the force per charge on the test charge.

Answer:

The viscosity is  \(\eta  = 0.76243 \ kg/ m \cdot s \)  

Explanation:

From the question we are told that

  The  density is  \(\rho  =  7.80 *10^{3} \  kg/m^3\)

  The diameter is  \(d =  3.0 \  mm =0.003 \ m\)

    The  time taken is  \(t  =  12 \ s\)

   The  distance covered is  \(d =  0.60 \ m\)

Generally the velocity of the ball is  

      \(v  =  \frac{d}{t}\)

=>    \(v  =  \frac{0.60}{12}\)

=>    \(v  =  0.05 \ m/s \)

Generally the mass of the steel ball is  

    \(m  =  \rho  *  V\)

Here  V  is the volume and this is mathematically represented as

     \(V  =  \frac{4}{3} *  \pi  * [\frac{d}{2}  ]^3\)

=>    \(V  =  \frac{4}{3} *  3.142  * [\frac{0.003}{2}  ]^3\)

=>      \(V  = 1.414 *10^{-8} \  m^3\)

So

     \(m  = 7.80 *10^{3}  *   1.414 *10^{-8}\)

     \(m  = 0.00011 \  kg \)

Generally the viscosity is mathematically represented as  

     \(\eta  =  \frac{m  *  g}{6\pi  *  r  *  v }\)

Here  r is the radius represented as

      \(r =  \frac{d}{2}\)

=>   \(r =  \frac{0.003}{2}\)

\(r =  0.0015  \  m \)

So

  \(\eta  =  \frac{0.00011  *  9.8}{6 *  3.142   * 0.0015  * 0.05 }\)    

=> \(\eta  = 0.76243 \ kg/ m \cdot s \)

The buoyant force can be determined by subtracting the apparent weight of the object in water from its weight in air. In this case, the buoyant force would be 7N - 4N = 3N.

Based on the information provided, since the buoyant force (3N) is less than the weight of the object (7N), the object will not float.

Floating occurs when the buoyant force is greater than or equal to the weight of the object.

In this scenario, the object will experience a net downward force, indicating that it will sink rather than float in water.

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The apparatus that can used to measure the mass of the wooden block​ by the student is called beam balance.

A beam balance, often referred to as a double-pan balance, is a straightforward tool for determining an object's weight. Two pans or trays are hung from either end of a horizontal beam that is suspended from a pivot point in the middle.

The thing to be weighed is put on one tray, and then the second tray is filled with standard weights until it balances, showing the weight of the object. From little ones used in laboratories to larger ones used in enterprises, beam balances can be found in a variety of shapes and sizes. Because they are precise and operate without electricity or batteries, they are widely used.

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The Environmental Justice Movement recognizes that historically environmental burdens are often borne by economic, social and environmental justice.

In order words, it gives fair treatment of justice to its system socially, economically, racially and environmental wise

Environmental justice can simply be defined as the act of being fair to everyone in the environment in aspect of life; be it economically, socially, racially, or even origin wise

This movement of environmental justice is characterized by treating everyone equally regardless of the similarities and differences which exist between nations, countries, individuals, organizations.

For every system who obvserves this impartial movement, they usually, frequently and most of the time gives balanced humanitarian service which helps to promote them in aspect of life as this does not discriminate anyone in any manner

So therefore, the Environmental Justice Movement recognizes that historically environmental burdens are often borne by economic, social and environmental justice.

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Answer:

a. Power = 1000 Watts or 1 Kilowatts.

b. Current = 4 Amperes.

Explanation:

Given the following data;

Energy consumed = 1.8MJ = 1.8 × 10^6 = 1800000 Joules

Voltage = 250V

Time = 30 minutes to seconds = 30 * 60 = 1800 seconds

To find the power rating;

Power = energy/time

Substituting into the equation, we have;

Power = 1800000/1800

Power = 1000 Watts or 1 Kilowatts.

b. To find the current taken from the supply;

Power = current * voltage

1000 = current * 250

Current = 1000/250

Current = 4 Amperes.

The horizontal force that was exerted by the wind on the mast based on the power is 67.3KN.

Blade Stan, d = 75m

Radius of Blade, r = 75m

wind velocity, V = 30 km/h V = 8.333 m/s

Turbine Generator efficiency or Power Co-efficient ((p) = 32% 0.32.

Flow rate across the turbine (in) = 125X8.333X X (75) 2 m

= 46017.583 kg/s

Air Exit velocity, Ve = V×√1 - Nterbine

Ve = 8.333 x √1 1- 0.32

Ve = 6.872 mls

Horizental force in x-direction (F); -

Fx = m (ve-v)

Fx = 46017-583X(6-872-8.333) = 67265.381 N

The Horizental force Extered on the Supporting mast F = -F F= 67.2654 KN

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Determine the horizontal force that was exerted by the wind on the mast base

Answer:

b) The electric field inside is zero.

Explanation:

This is simply because the charges in the field will be in motion, thus this charges kind of spread around to make the conductor field zero.

Answer:

F = 75 N

Explanation:

Given that,

Mass of a sculpture, m = 150 kg

The acceleration of the sculpture, a = 0.5 m/s²

We need to find the force with which the curator pushes the sculpture.

F = ma

Substitute all the values of m and a in it.

F = 150 kg × 0.5 m/s²

= 75 N

So, the required force with which the curator pushes the sculpture is 75 N.

Let's check the formula for a focal length:

Since basically the two lenses have the same form, we can conclude that R1,R2 and d are the same. But n ( refractive index) could be different. n depends on the material, so we can conclude that the answer is:

A.

Lens A and lens B are made from two different materials with different optical properties.

Answer:D

Explanation:D

If a product claims to be low-calorie, then it means that it must contain 40 calories or fewer per saving. Hence, option D is correct.

Our bodies need energy to keep us alive and to make sure that our organs are functioning properly.

When we eat and drink, we provide our bodies with energy. Our bodies consume that energy during routine tasks like breathing and jogging.

To keep a constant weight, the amount of energy we put into our bodies must correspond to the amount of energy we expend during routine biological functions and physical activity.

A key element of a balanced diet is striking a balance between the energy you put into your body and the energy you expend.

For instance, the more physical activity we do, the more energy we use.

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Answer:

When the cold weather fills hard surfaces with water, it causes it to freeze and expand, causing cracks in the surface.

Answer:

Work transfers energy

Explanation:

Work can affect energy by transfering energy between objects to result to a change in the amount and form of energy

The best summary of paragraph 6 is that analog TV signals were incapable of transmitting high-resolution video, while digital TV offers superior image quality. So, the correct statement is "Analog TV signals could not carry high-resolution video."

The sentence emphasises how much better picture quality has been achieved with digital TV than with analogue TV since its launch.

Better picture quality is directly related to the higher resolution offered by digital technology. This sentence emphasises the low video resolution of analogue TV and implies that this was a fundamental issue that could not be solved.

In essence, it emphasises how much better digital TV is at presenting stunning pictures and fixing the problems with analogue TV transmissions. The right answer is thus, "Analogue TV signals could not carry high-resolution video."

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Answer:

0.58 L

Explanation:

For this problem we need to simply use the ideal gas equation to create a proportional comparison for the initial information to the final information.

(P_1 * V_1) / T_1 = (P_2 * V_2) / T_2

Using this, we can solve for V_2 to find the new volume of the gas once pressure and temperature changes.

(P_1 * V_1) * T_2 / T_1 = (P_2 * V_2)

(P_1 * V_1) * T_2 / (T_1 * P_2) = V_2

Consider our givens:

P_1 = 110atm

T_1 = 303K

V_1 = 2L

P_2 = 440atm

T_2 = 353K

Now we simply plug in these values to the equation to find the new volume, V_2.

(P_1 * V_1) * T_2 / (T_1 * P_2) = V_2

(110atm * 2L) * 353K / (303K * 440atm) = V_2

77660 atm*L*K / 133320 K*atm = V_2

0.583 L = V_2

Hence, the new volume is 0.583 L.

Cheers.

Assuming that the speed of sound is 343 m/s at 25 degrees Celsius, we can use the formula:

wavelength = speed of sound/frequency

wavelength = 343 / 666

wavelength = 0.515 meters or 51.5 centimeters

Therefore, the wavelength of a 666 Hz sound wave at 25 degrees Celsius is approximately 51.5 centimeters.

Answer:

Exposure to very high levels of radiation, such as being close to an atomic blast, can cause acute health effects such as skin burns and acute radiation syndrome (“radiation sickness"). It can also result in long-term health effects such as cancer and cardiovascular disease