Which physical properties do all stars have? Check all that apply.

They are made of gases.
They shine very brightly.
They have a spherical shape.
They contain iron in their cores.
They make energy through fusion.Which physical properties do all stars have? Check all that apply.

They are made of gases.
They shine very brightly.
They have a spherical shape.
They contain iron in their cores.
They make energy through fusion.

The skateboarder is travelling with a initial velocity of 12 m/s and slid to stop in the next 2.0 seconds. The acceleration of the skateboarder will be -6 m/s².

Acceleration of a body is the change in the velocity with respect to time. Acceleration depends upon factors such as time, initial velocity, final velocity, and distance travelled by the object.

In the given question, the skateboarder is travelling with a initial velocity (u) of 12 m/s

Time (t) after which he comes to a stop is 2.0 seconds

The skateboarder stops and comes to rest therefore, the final velocity (v) of the skateboarder will be zero

The acceleration (a) of the skateboarder can be calculated by the formula:

a = (v - u)/t

where, a = acceleration of the object

v = final velocity of the object

u = initial velocity of the object

t = time elapsed

a = (0 - 12)/2.0

a = -12/2.0

a = -6.0m/s²

Here, the acceleration is negative because the body comes to rest at the end after acceleration.

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Answer:

3.  (a) the amount of energy found in the fatty acid.

4. (d) all of the above

5. (c) DNA is how inherited characteristics are passed from one generation to the next.

6. (b) lipid

7. (c) cellulose

Explanation:

3. Saturated fats have more energy due to the double bonds that are found in the molecules.

4. Different proteins have various and roles within the cell.

5. Each nucleotide, in turn, is made up of a nitrogenous base (not carbon base), a pentose sugar, and a phosphate. DNA is a double chain.

6. Biological membranes consist of a continuous double layer of lipid molecules in which membrane proteins are embedded.

7. The cell wall is composed of a network of cellulose microfibrils and cross-linking glycans embedded in a highly cross-linked matrix of pectin polysaccharides.

The enzyme which allows a modified form of glucose to get confined within the cell since no transporter for this modified form exists is known as hexokinase.

The modification that the enzyme makes is phosphorylation, whereby a phosphate group is added to the glucose molecule, resulting in glucose-6-phosphate. This modification of glucose-6-phosphate is essential as it keeps the glucose within the cell, and thus it can be used as a source of energy for the cell by glycolysis.Glucose-6-phosphate can then enter the glycolytic pathway, whereby it can either be converted into glycogen or pyruvate through a series of reactions.

This pathway is considered to be an anaerobic pathway since it does not require oxygen to occur. The mechanism reaction type in which glucose is phosphorylated is a transferase reaction, whereby a phosphate group is transferred from ATP to glucose, resulting in glucose-6-phosphate. Hexokinase is an essential enzyme in the body since it helps in maintaining glucose homeostasis.

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Answer:

photosynthesis is the process of plants making there own foods

Explanation:

plants can't move and they have trouble finding foord without moving so there is a process called photosynthesis in wich plants seed wish is under the ground has soil around it and in the soil there is dead plants and animals mixed the gathers the material makes food and sends thefood through the stem this process is called photosuthesis

A tertiary structure is the three-dimensional arrangement of the polypeptide chain in a protein. The tertiary structure is stabilized by various interactions such as hydrogen bonds, van der Waals forces, hydrophobic interactions, disulfide bonds, and ionic bonds. The intermediate states that occur during the formation of the tertiary structure are known as molten globules.

Tertiary structure is the final stage of protein folding and is crucial for the protein's function. The formation of the tertiary structure involves the folding of secondary structures such as alpha-helices and beta-sheets into a compact, globular shape.

Molten globules are partially folded structures that have some of the characteristics of the final tertiary structure but are not fully stable. Molten globules are thought to be important in the folding process because they allow the protein to explore different conformations and find the most stable structure.

The formation of the tertiary structure is a complex process that is influenced by various factors such as temperature, pH, and the presence of other molecules. Some proteins require the assistance of chaperone proteins to fold correctly. Misfolded proteins can lead to various diseases such as Alzheimer's and Parkinson's.

In summary, the tertiary structure is the final stage of protein folding and is crucial for the protein's function.

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Most organisms have two copies of each gene, one from their mother and another from their father. These copies can be the same or different because there are different versions of each gene. Each version is called an allele, and it gives a different characteristic to the organism, making them variable.

This means A) allele, is the right answer.

Answer:

Virus

Explanation: They are considered to not be living and have no cells within them and need a host to reproduce by using cells so therefore they are objects that seek detruction like cancer.

Answer: Option E.

All are endoplasmic reticulum functions.

Explanation:

All are function of endoplasmic recticulum because

Endoplasmic recticulum is a membrane organelle that consists of two subunits, rough and smooth endoplasmic recticulum found in eukaryotes that formed flattened sacs within the cytoplasm of eukaryotic cells which syntyensises proteins, lipids and steroids, it metabolised carbohydrates by adding it to protein , help to control the concentration of calcium in the body,it detoxifies drugs, attached protein on receptor cells, assemble multimeric proteins e.t.c.

The endoplasmic recticulum comprises of two subunits which are rough and smooth endoplasmic recticulum. The major differences between rough and smooth endoplasmic recticulum is that smooth do not have RIBOSOMES and it produces lipids and rough have RIBOSOMES and produces proteins.

This advance changed the study of biology as it allowed researchers to study the behavior, physiology, and biochemistry of individual cell types in isolation, which was not possible before.

The ability to isolate a single type of cell from a multicellular organism using cell culture has had a significant impact on the study of biology.

One of the most significant impacts of cell culture is the ability to study the properties and functions of different cell types, such as stem cells, cancer cells, and immune cells. This has greatly increased the understanding of cellular processes and has led to the development of new therapies for diseases.

Cell culture also enables scientists to study the effects of different chemicals, drugs, and genetic manipulations on cells in a controlled environment. This has led to the discovery of new drugs, and the optimization of their efficacy and safety.

Additionally, cell culture techniques have been used to create in vitro models of tissues and organs, which can be used to study the development and function of these structures.

In summary, cell culture has led to a greater understanding of cellular processes, the development of new therapies, and improved drug development. It has also greatly advanced the study of genetics, biochemistry, and pharmacology.

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The law of independent assortment states that the alleles of different traits on separate chromosomes segregate independently during the process of meiosis. The steps of meiosis involve prophase I, metaphase I, anaphase I, and telophase I. During prophase I, the homologous chromosomes (each with two alleles) pair up and line up randomly along the equator of the cell. During metaphase I, the homologous chromosomes are pulled towards opposite poles of the cell. During anaphase I, the homologous chromosomes are separated and move to opposite poles of the cell. During telophase I, the cells divide and each daughter cell now contains only one allele of each gene, which are randomly assorted in the daughter cells. This random assortment of alleles is what explains the law of independent assortment and is why alleles of different traits on separate chromosomes can be inherited independently.

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Answer:

0.28

Explanation:

This allele has incomplete dominance and analysis indicated a phenotypic distribution of 600M, 4000MN, 400N.

Using p+q = 1

Where q is the frequency of the N allele-

400N/5000 = 0.08 is the genotypic frequency out of 5000 in total - q²

Thus the frequency of the allele N is √q² = √0.08 = 0.28

The frequency of the N allele is 0.48

Incomplete dominance occur when a progeny of a particular parents gives or have a phenotype that combines both parents gene.

This phenotype is intermediate of the two parents and often unique.

Total population of Thailand= 5000

Allele P= 600M

Allele pq= 4000MN

Allele Q= 400N

According to hardyweingberg principles,

P+Q= 1

p2+2pq+q2=1

Therefore, to calculate frequency of allele N in the population we have;

N for Q= 400/5000=0.08

N for pq= 4000/5000=0.8

since pq contain both allele q and p in equal proportion we have

N for pq= 0.5*0.8 = 0.4

Frequency of N in allele N and MN is

0.08+ 0.4 = 0.48.

Therefore, the frequency of the N allele is 0.48

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During mRNA splicing, introns are removed and exons are joined to form a mature mRNA molecule that can be translated into a protein. The splicing process involves the formation of a lariat structure, which is created when the 5' splice site of the intron reacts with an adenosine residue located near the 3' end of the intron, forming a loop. This loop is then cleaved, allowing the exons to be joined together.

To select the correct lariat structure from the dropdown menu, we need to consider the location of the 5' and 3' splice sites and the adenosine residue that forms the loop. The correct structure will show the intron being removed and the exons being joined together.

Without seeing the starting structure dropdown menu, it is difficult to provide a specific answer. However, I recommend carefully examining the options and selecting the one that shows the correct sequence of events during mRNA splicing. Remember, the lariat structure is only a temporary intermediate that is formed during splicing and is eventually broken down. The final product is a mature mRNA molecule that can be translated into a protein.

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The parts of the supply chain that are most closely involved with the situation in this case are the suppliers, the manufacturer, the distributor, and the retailer. The responsibility of each part in order to maintain a smooth flow of material is as follows:

Suppliers: The suppliers are responsible for providing the manufacturer with high-quality raw materials on time. The suppliers are also responsible for ensuring that the raw materials are of the required specifications and quality.

Manufacturer: The manufacturer is responsible for converting raw materials into finished products. The manufacturer should ensure that they produce the required products on time and that they meet the desired quality standards. They should also ensure that they are using the right machinery and equipment to produce the required products.

Distributor: The distributor is responsible for transporting the finished products from the manufacturer to the retailer. The distributor should ensure that the products are delivered on time and that they are in good condition.

Retailer: The retailer is responsible for selling the finished products to the consumers. The retailer should ensure that they have the right products in stock and that they are selling them at the right price. They should also ensure that they are providing excellent customer service to their customers.

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Answer:

glycolysis

Explanation:

Factors such as cholesterol and carbohydrate presence, hydrophobicity, phospholipid composition, and differential interaction with the selectivity filter protein all contribute to the function and selectivity of a membrane channel.

1. Presence of cholesterol in the channel: Cholesterol affects membrane fluidity and stability, which can influence the function and selectivity of channels.
2. Presence of carbohydrates in the channel: Carbohydrates may play a role in cell recognition and signaling, potentially affecting channel function.
3. Hydrophobicity of the channel: The hydrophobicity of the channel allows it to interact with the lipid bilayer, thus playing a crucial role in its insertion and function within the membrane.
4. Phospholipid composition of the channel: The specific phospholipids present in the channel can affect its overall function and interactions with other molecules.
5. Differential interaction with the selectivity filter protein: The selectivity filter protein may interact differently with various ions or molecules, thus determining the channel's selectivity and function.

In summary, factors such as cholesterol and carbohydrate presence, hydrophobicity, phospholipid composition, and differential interaction with the selectivity filter protein all contribute to the function and selectivity of a membrane channel.

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Cardiovascular condition is characterized by tachycardia, tachypnea, cough, and wheezes in pediatric patients is Heart failure.

The correct option is A.

Heart and blood vessel disorders are collectively referred to as cardiovascular disease (CVD). The development of fatty deposits inside the arteries (atherosclerosis) and a higher risk of blood clots are typically associated with it.

Heart failure happens when the heart's ability to pump blood is compromised. Blood frequently backs up, which leads to fluid accumulation in the legs and the lungs (congest). Breathing difficulties and swelling in the legs and feet can result from the fluid accumulation. The skin may seem blue due to poor blood flow (cyanotic).

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I understand that the question you are looking for is:

Which cardiovascular condition is characterized by tachycardia, tachypnea, cough, and wheezes in pediatric patients?

A. Heart failure

B. Septic shock

C. Anaphylaxis

D. Hypovolemia

Lyrissa's age and physical condition suggests that she may be suffering from marasmus.

Marasmus is a severe form of malnutrition caused by a lack of protein and calories, forcing the body to break down its own tissues for energy. This causes muscle and fat tissue atrophy, as well as a significant fall in body weight.

Rickets is a disorder caused by a lack of vitamin D that produces weak bones, whereas hypoglycemia is defined as low blood sugar levels. Kwashiorkor is a kind of severe malnutrition, but it is distinguished by a distinct set of symptoms, including edoema, skin and hair abnormalities, and liver damage, which are not addressed in the available material.

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Declining krill populations will have catastrophic consequences for ecosystem homeostasis and it will increase the levels of phytoplankton.

The term ecosystem homeostasis makes reference to the state of equilibrium between different species in an ecosystem.

Krill are fundamental primary consumers in aquatic environments and they eat autotrophic phytoplankton.

In conclusion, declining krill populations will have catastrophic consequences for ecosystem homeostasis and it will increase the levels of phytoplankton.

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The functional state of RNA polymerase II is altered by phosphorylation on its C-terminal domain (CTD).

RNA polymerase II is an enzyme that transcribes DNA into mRNA. The C-terminal domain (CTD) of RNA polymerase II is an essential component that determines the phosphorylation state of the enzyme. The functional state of RNA polymerase II is altered by phosphorylation on its C-terminal domain (CTD).The C-terminal domain (CTD) of RNA polymerase II contains several heptad repeats, and each heptad consists of seven amino acids, namely serine, proline, threonine, and tyrosine. Serine residues are the primary targets of phosphorylation, with threonine and tyrosine residues being phosphorylated less frequently.Phosphorylation of the C-terminal domain (CTD) of RNA polymerase II plays a crucial role in regulating gene expression. The phosphorylation status of the CTD controls RNA processing, chromatin remodeling, and transcription elongation. The CTD must be phosphorylated for RNA polymerase II to progress through the transcription cycle. This modification provides a platform for the recruitment of different factors required for transcription elongation.Longer than 100 wordsThe functional state of RNA polymerase II is altered by phosphorylation on its C-terminal domain (CTD). The C-terminal domain (CTD) of RNA polymerase II is an essential component that determines the phosphorylation state of the enzyme. The C-terminal domain (CTD) of RNA polymerase II contains several heptad repeats, and each heptad consists of seven amino acids, namely serine, proline, threonine, and tyrosine. The primary targets of phosphorylation are serine residues, with threonine and tyrosine residues being phosphorylated less frequently. The phosphorylation status of the CTD controls RNA processing, chromatin remodeling, and transcription elongation. The CTD must be phosphorylated for RNA polymerase II to progress through the transcription cycle.

This modification provides a platform for the recruitment of different factors required for transcription elongation. Phosphorylation of the CTD plays a crucial role in regulating gene expression. In summary, phosphorylation of the C-terminal domain (CTD) of RNA polymerase II plays a significant role in controlling gene expression.

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Your question has been heard loud and clear.

Hormones like oestrogen and progestrone play a good part in being more feminine. More the levels of oestrogen , more is the increase in sexual desire. Whereas progestrone reduces the sexual desire and makes you more feminine in nature.

Hormones like testosterone are present in the female body too and they balance the difference between being too female and normally female. High levels of testosterone makes a girl less feminine , the same way that oestrogen is present in the male body too , to balance the difference between being too male and normally male , high levels of oestrogen in a male's body makes them less male and more feminine.

Thank you

Answer:

Lots of things can effect the lungs and GI systems from virus to bacteria. Any illness in either location can upset homeostasis. homeostasis is just the baseline normal of a human. So, if an illness causes fever then it upsets the balance, both chemical as well as hormonal.

Answer:

Explanation:

Negative feedback refers to a mechanism whereby a change in a specific direction triggers a response that tends to counteract the initial change and return the system to its original state. Related to fluid balance, negative feedback occurs when the body senses changes in fluid levels and adjusts various physiological processes to maintain a stable balance of water and electrolytes in the body. For example

As the renal tubules become less permeable to water, less water is reabsorbed into the bloodstream and a greater volume of diluted urine is produced. This type of control is an example of a negative feedback mechanism. It aims to maintain a constant concentration of blood plasma.

Answer: 2.

Explanation:

Remember diffusion balances the molecules.

water doesn't move freely.

3 and 4 don't make sense for this questions wording.

that's some cool stuffffp

Answer:

Ribosomes

Explanation:

Ribosomes are used in cells for growth and repair they are held in the cytoplasm of the cell not the nucleus therefore they are never in contact with dna

Answer:

 A. They are all in the same group B. They all have the same number of valence electrons C. They all have the same number of protons D. They all share similar properties

Explanation: