Answer:
I'm not too good at this but I got 10/4??
Step-by-step explanation:
please let me know if I'm right!
This is just a question I had.
If Denny (random name) left to another country and he left the Tuesday of this week (June 20) and he left for a month, what day would he be back on? I though July 18 but I’m not sure. Pls help?
Answer:
Step-by-step explanation:
Well, since the length of a month can vary in the number of days, this answer can also vary.
For example, February is only 28 days long, while December is 31 days long.
That being said, the average length of all 12 months is 30.436875 days, so if Denny left to another country on June 20th, he would most likely be back July 19th of July 20th.
I hope this helps!
Triangles Q R S and X Y Z are shown. Angles Q S R and X Z Y are right angles. Angles Q R S and X Y Z are congruent. The length of Y Z is 9, the length of X Z is 12, and the length of hypotenuse X Y is 15.
Given △QRS ~ △XYZ, what is the value of tan(Q)?
Three-fifths
Three-fourths
Four-fifths
Answer:three-fourths
Step-by-step explanation:
because my dad said it was right
Just need to answer to this geometry question, Its a throw back for me.
As the triangles are similar to each other, using congruent theorem, we get the value of side JK = 63.8.
What are similar triangles?Comparable triangles are those that resemble one another but may not be precisely the same size. Comparable items are those that share the same shape but differ in size.
This shows that when shapes are amplified or demagnified, they superimpose one another. This feature of similar shapes is often known as "similarity".
As per the triangles,
Let JK be = x.
GF/GH = JI/JK
⇒ 11/18 = 36 /x
⇒ x = 36 × 18/11
⇒ x = 63.8.
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Find the x intercept and the y intercept of the line below.
Answer:
x=-2 y=4
the line hits both -2 on the x asis and 4 on the y
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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Who can solve this?
Answer:
$1000
Step-by-step explanation:
Check answers
1000x .03= 30
1000 - 30 = 970
Consider the ODE: (a) To solve, differentiate both sides of the equation and rearrange. Find the general solution (i.e. the one-parameter family of solutions, parameterized by a constant C) and the singular solution (a solution that is not included in the general solution form). (b) Plot the general solution for many values of C. How does the singular solution relate to this plot?
So the points (a, b) are of the form: (a, 1/(9/4 - a))
Differentiation
Differentiation is a method of finding the derivative of a function. Differentiation is a process, in Math's, where we find the instantaneous rate of change in function based on one of its variables. The most common example is the rate change of displacement with respect to time, called velocity.
Solve the differential equation:
a) y = 1/(k - x)
b) y = 0
c) (a, 1/(9/4 - a))
Solve the differential equation are
So
\(\frac{dy}{dx} = y^{2}\)
a) if define:
y = 1/(k - x)
And derivate that,-
\(y^{'} = \frac{1}{(k - x){2} } = y^{2}\)
So that is the general solution.
b) A singular solution that is not included in the general form, use something like:
y = 0 we get:
dy/dx = 0 = 0^2
This is a trivial singular solution.
c) y(a) = b, then:
\(y = \frac{1}{k - a} = b\)
\(\frac{1}{(k - 2){2} } = 4* \frac{1}{k - 2}\)
\(\frac{1}{k - 2} = 4\\\)
(k - 2) = 1 / 4
k = 2 + 1/4 = 9/4
Then
\(y = \frac{1}{9/(4 - a)} = b\)
So the points (a, b) are of the form: (a, 1/(9/4 - a))
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7. A floor is covered by 800 tiles measuring 10 squared cm. How many square tiles of side 8 cm would be needed to cover the same floor?
Answer:
1000 tiles
Step-by-step explanation:
Determine total floor space
800 x 10 = 8000 squared cm total floor space.
Divide floor space by size of tile
8000 / 8 = 1000 tiles now required to cover the floor.
tanx(1+cos2x)=sin2x prove the identity
Using double angle identity, we are able to prove tan(x)(1 + cos(2x)) = sin(2x).
What is the prove of the given identity?To prove the identity tan(x)(1 + cos(2x)) = sin(2x), we can start by using trigonometric identities to simplify both sides of the equation.
Starting with the left-hand side (LHS):
tan(x)(1 + cos(2x))
We know that tan(x) = sin(x) / cos(x) and that cos(2x) = cos²(x) - sin²(x). Substituting these values, we get:
LHS = (sin(x) / cos(x))(1 + cos²(x) - sin²(x))
Next, we can simplify the expression by expanding and combining like terms:
LHS = sin(x) / cos(x) + sin(x)cos²(x) / cos(x) - sin³(x) / cos(x)
Simplifying further:
LHS = sin(x) / cos(x) + sin(x)cos(x) - sin³(x) / cos(x)
Now, let's work on the right-hand side (RHS):
sin(2x)
Using the double angle identity for sine, sin(2x) = 2sin(x)cos(x).
Now, let's compare the LHS and RHS expressions:
LHS = sin(x) / cos(x) + sin(x)cos(x) - sin³(x) / cos(x)
RHS = 2sin(x)cos(x)
To prove the identity, we need to show that the LHS expression is equal to the RHS expression. We can combine the terms on the LHS to get a common denominator:
LHS = [sin(x) - sin³(x) + sin(x)cos²(x)] / cos(x)
Now, using the identity sin²(x) = 1 - cos²(x), we can rewrite the numerator:
LHS = [sin(x) - sin³(x) + sin(x)(1 - sin²(x))] / cos(x)
= [sin(x) - sin³(x) + sin(x) - sin³(x)] / cos(x)
= 2sin(x) - 2sin³(x) / cos(x)
Now, using the identity 2sin(x) = sin(2x), we can simplify further:
LHS = sin(2x) - 2sin³(x) / cos(x)
Comparing this with the RHS expression, we see that LHS = RHS, proving the identity.
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The GCF of 15 and 27
Which number doesn't share the same pattern as
2,20, 4,8,300
Enter your answer in the box. Round your final answer to the nearest degree. B 6cm, A 8cm, C
The measure of Angle C is approximately 26°.
A, B, C are vertices of a triangle, where AB = 8 cm, BC = 6 cm. To determine the measure of angle C, we need to use the cosine rule.
The cosine rule states that the square of one side of a triangle is equal to the sum of the squares of the other two sides minus twice the product of the other two sides and the cosine of the angle between them.
Mathematically, we can represent it as follows:a² = b² + c² - 2bc cos(A)where a is the side opposite to angle A, b is the side opposite to angle B, c is the side opposite to angle C.
In this case, we have AB = c = 8 cm, BC = a = 6 cm, and AC = b. We need to find the measure of angle C, which is represented as cos(C).
Using the cosine rule, we can write the equation as follows:$$\begin{aligned} b^2 &= c^2 + a^2 - 2ca\cos(C) \\ \Right arrow b^2 &= 8^2 + 6^2 - 2 \times 8 \times 6 \cos(C) \\ \Right arrow b^2 &= 64 + 36 - 96 \cos(C) \\ \Right arrow b^2 &= 100 - 96 \cos(C) \end{aligned}$$We know that b is a positive length. Hence, b² > 0 or 100 - 96 cos(C) > 0. Solving for cos(C),
we get: cos(C) < 100/96cos(C) < 1.0417Using a calculator, we can determine the inverse cosine of 1.0417 as:cos⁻¹(1.0417) = 0.4569 radians = 26.201° (rounded to the nearest degree)
Therefore, the measure of angle C is approximately 26°.
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Find the area of the trapezoid.
14 mm
15 mm
36 mm
1. 270 mm²
2. 375 mm²
3. 750 mm²
5. 3780 mm²
Answer: no one cares
Step-by-step explanation:
because it's to hard\(\pi \pi \pi \pi \pi \pi \pi \pi \pi \pi \pi \pi \pi \left \{ {{y=2} \atop {x=2}} \right. x_{123} \left \{ {{y=2} \atop {x=2}} \right. \lim_{n \to \infty} a_n \int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}} \right. \sqrt{x} \sqrt{x} \sqrt{x} \alpha \pi x^{2} x^{2} x^{2} \\ \\ \neq \pi \pi 5069967.94389438.494898 that's the answer\)Help help math math math
Answer:
3 1/4 ÷ 2 2/3 = 3 1/8
Answer:
The answer is 3 1/8. Hope this helps :)
Step-by-step explanation:
5.44 Teaching descriptive statistics: A study compared five different methods for teaching descriptive statistics. The five methods were traditional lecture and discussion, programmed textbook instruction, programmed text with lectures, computer instruction, and computer instruction with lectures. 45 students were randomly assigned, 9 to each method. After completing the course, students took a 1-hour exam. (a) What are the hypotheses for evaluating if the average test scores are different for the different teaching methods?
Answer:
The null hypothesis is that all the different teaching methods have the same average test scores.
H0: μ1 = μ2 = μ3 = μ4 = μ5
The alternative hypothesis is that at least one of the teaching methods have a different mean.
Ha: at least one mean is different. (μ1 ≠ μi)
Step-by-step explanation:
The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.
For the case above, let μ represent the average test scores for the teaching methods:
The null hypothesis is that all the different teaching methods have the same average test scores.
H0: μ1 = μ2 = μ3 = μ4 = μ5
The alternative hypothesis is that at least one of the teaching methods have a different mean.
Ha: at least one mean is different. (μ1 ≠ μi)
5. The ratio of green apples to red apples is 3 to 7. Which combination of green apples to red apples could be used?
2. How much interest is earned by investing $2100 for three years at 4.5% compounded
monthly?
Answer:
The final balance is $2,402.92.
The total compound interest is $302.92.
Step-by-step explanation:
A = P(1 + r/n)^{nt}
A = final amount
P = initial principal balance
r = interest rate
n = number of times interest applied per time period
t = number of time periods elapsed
A=2100(1+.045/12)^(3*12)
A=2100(1.00375)^(36)
A=2100*1.442478322
A=2402.92
gain of 302.92
4) Visitors to an online store can enter a special code to receive a discount. The graph shows
the original price, , and sale price, y, of some items at the store.
What does the point at (60, 55) represent?
The point at (60, 55) means that an item with
an original price of $
?
has a sale price
of $ ?
Sale Price ($)
100
90
80
Online Store Prices
70
60
50
40
30
20
10
0
0 10 20 30 40 50 60 70 80 90 100
Original Price ($)
(30, 25)
(90, 85)
(60,55)
The point at (60, 55) represents an item with an original price of $60 that is now being sold at a sale price of $55.
How to find the function which was used to make graph?There are many tools we can use to find the information of the relation which was used to form the graph.
A graph contains data of which input maps to which output.
Analysis of this leads to the relations which were used to make it.
For example, if the graph of a function is rising upwards after a certain value of x, then the function must be having increasingly output for inputs greater than that value of x.
If we know that the function crosses x axis at some point, then for some polynomial functions, we have those as roots of the polynomial.
We are given that;
The point at (60, 55)
Now,
This means that customers who enter the special discount code can save $5 on this particular item.
In general, the point (x, y) on the graph represents an item with an original price of x dollars that is being sold at a sale price of y dollars. The graph is showing how the sale price of items changes as the original price increases.
Therefore, by the graph the answer will be $60 and $55.
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Construct a tangent to the circle at point B.
Answer:
Step-by-step explanation:
join PB .At B draw ⊥PB.
it is the reqd . tangent at B
Step by step explanation of y-10=9(x+8), written in standard form
Answer:
y-10=9x+72
y-10-72=9x
y-82=9x
y=9x+82
(5x+4)-3x
Solve.
No scam.
Answer:
=2x+4
Step-by-step explanation:
Let's simplify step-by-step.
5x+4−3x
=5x+4+−3x
Combine Like Terms:
=5x+4+−3x
=(5x+−3x)+(4)
=2x+4
Answer:
2x+4
Step-by-step explanation:
Hope fully it is correct
PLEASE HELP! ITS DUE SOON! QUESTION IN PICTURE BELOW! PLEASE HELP!
Answer:
no:- b
i am not that sure but
Solve for angles x and y in the triangle below. Round your angle to the nearest whole degree.
Solve for both x and y
\(\tan(y )=\cfrac{\stackrel{opposite}{6}}{\underset{adjacent}{4}} \implies \tan( y )= \cfrac{3}{2} \implies \tan^{-1}(~~\tan( y )~~) =\tan^{-1}\left( \cfrac{3}{2} \right) \\\\\\ y =\tan^{-1}\left( \cfrac{3}{2} \right)\implies y \approx 56.31^o \\\\[-0.35em] ~\dotfill\\\\ \tan(x )=\cfrac{\stackrel{opposite}{4}}{\underset{adjacent}{6}} \implies \tan( x )= \cfrac{2}{3} \implies \tan^{-1}(~~\tan( x )~~) =\tan^{-1}\left( \cfrac{2}{3} \right) \\\\\\ x =\tan^{-1}\left( \cfrac{2}{3} \right)\implies x \approx 33.69^o\)
Make sure your calculator is in Degree mode.
The drama club is selling tickets to their play to raise money for the show's expenses.
Each student ticket sells for $7 and each adult ticket sells for $10. The auditorium can
hold no more than 85 people. The drama club must make no less than $690 from
ticket sales to cover the show's costs. Also, they must sell a minimum of 10 student
tickets and at least 55 adult tickets. If a represents the number of student tickets sold
and y represents the number of adult tickets sold, write and solve a system of
inequalities graphically and determine one possible solution.
On solving the inequalities a ≥ 10, y ≥ 55, 7a + 10y ≥ 690, the solution is obtained as (20,55).
What is an inequality?
In Algebra, an inequality is a mathematical statement that uses the inequality symbol to illustrate the relationship between two expressions. An inequality symbol has non-equal expressions on both sides. It indicates that the phrase on the left should be bigger or smaller than the expression on the right, or vice versa.
Use the variables a and y to represent the number of student and adult tickets sold, respectively.
Then write the following system of inequalities -
a ≥ 10 (they must sell a minimum of 10 student tickets)
y ≥ 55 (they must sell at least 55 adult tickets)
7a + 10y ≥ 690 (they must make no less than $690 from ticket sales)
The first two inequalities are constraints on the number of tickets sold, and the third inequality represents the revenue constraint.
To find a possible solution, graph these inequalities on a coordinate plane and look for the feasible region that satisfies all three inequalities.
Alternatively, solve the system of inequalities using algebra.
First, simplify the third inequality by subtracting 7a from both sides -
10y ≥ 690 - 7a
Then, divide both sides by 10 -
y ≥ (690 - 7a)/10
This inequality represents the revenue constraint in terms of the number of student tickets sold.
Now combine the revenue constraint with the other two constraints -
a ≥ 10
y ≥ 55
y ≥ (690 - 7a)/10
Use substitution to solve for a in terms of y -
y ≥ (690 - 7a)/10
10y ≥ 690 - 7a
7a ≥ 690 - 10y
a ≥ (690 - 10y)/7
To find a possible solution, substitute a = (690 - 10y)/7 into the other two constraints -
(690 - 10y)/7 ≥ 10
y ≥ 55
These inequalities can be simplified -
690 - 10y ≥ 70
y ≥ 55
The first inequality can be solved for y -
-10y ≥ -620
y ≤ 62
Since it is known y ≥ 55, the feasible values for y are between 55 and 62, inclusive -
55 ≤ y ≤ 62
Now use the expression for a in terms of y to find the corresponding values of a -
a = (690 - 10y)/7
For each value of y between 55 and 62, inclusive, we can calculate a and check whether it satisfies the constraints -
a ≥ 10
y ≥ 55
7a + 10y ≥ 690
For example, when y = 55 -
a = (690 - 10(55))/7 = 20
7a + 10y = 7(20) + 10(55) = 690
Therefore, these values satisfy all three constraints, so one possible solution is a = 20 and y = 55.
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What is the value of x?
65°, 79° , X
Answer:
x=36 degrees
Step-by-step explanation:
Remember that all angles of a triangle must add up to 180 degrees due to the Angle Addition Postulate. So let's plug it in! x+65+79=180
Now you solve, x=180-79-65
x=36!
x=36 degrees
Answer:
Option B
Step-by-step explanation:
All interior angles of a triangle add up to 180°.
\(79+65+x=180\\144+x=180 \\144-144+x=180-144\\\boxed {x=36}\)
The missing angle is 36°.
Option B should be your correct answer.
You are one of 16 finalists on a game show.
One finalist is randomly selected to answer
a trivia question for a prize. What is the
probability that you will be selected?
Write your answer as a percent.
If one finalist is randomly selected for a prize then the probability that person will be selected is 6.25%.
Given A person is one of 16 finalists and one finalist is randomly selected for a prize.
Probability is the likeliness of happening an event among all the events possible. The formula of calculating probability is number of events possible/total outcomes.
The value of probability lies between 0 and 1. It cannot be negative because there might be chances of something and sometimes not so the value be 0.
Total finalists=16
Probability=1/16
When we convert it in percentage it will be 1*100/16
=6.25%
Hence the probability that person will be selected is 6.25%.
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To construct a regular octagon, what measure would be necessary for each interior angle? Construct an angle of that measure.
Answer:
\(135^\circ\)
Step-by-step explanation:
Given that, a regular octagon is to be constructed.
To find:
Each angle in the octagon = ?
Solution:
We know that a regular triangle (polygon with 3 sides) has an interior angle of \(60^\circ\).
And a regular quadrilateral (square) has an interior angle of \(90^\circ\).
Therefore, formula for interior angle of a regular polygon with \(n\) number of sides can be given as:
\(\dfrac{n-2}{n}\times 180^\circ\)
For an octagon, we have \(n=8\).
Value of Interior angle in a regular octagon:
\(\dfrac{8-2}{8}\times 180^\circ=\dfrac{6}{8}\times 180^\circ=\bold{135^\circ}\)
Kindly refer to the attached image for the angle of \(135^\circ\)
O Points: 0 of 1
A 12-sided die is rolled. The set of equally likely outcomes is {1,2,3,4,5,6,7,8,9,10,11,12). Find the probability of rolling a number greater than 17.
The probability of rolling a number greater than 17 is
(Type an integer or a simplified fraction)
Answer:
i dont know
Step-by-step explanation:
i do middle school not
highschool or college
A shop sell bagels for 5$ per dozen
Answer:
1.
6 bagels = 2.50$
2.
120 bagels or 10 dozen for 50$
Step-by-step explanation:
HOPE THIS HELPS
PLZZ MARK BRAINLIEST
Answer:
If the shop sells 12 bagles for $5 that means it must be good bagles
Step-by-step explanation:
They make the doe then cook them then you buy them then you eat them and they tast great!
\( \frac{x}{5} = y + 25\)make x the subject formula
Explanation
Given
\(\frac{x}{5}=y+25\)We are asked to make x the subject of the formula. This can be seen below.
The first step is to multiply through by 5
\(\begin{gathered} 5(\frac{x}{5})=5(y+25) \\ x=5y+125 \end{gathered}\)Answer: x =5y + 125