Answers
The sentence that best describes Earth's rotation is : Earth rotates on its axis once every 24 hours.
The correct answer is option C.
Earth's rotation refers to the spinning of the Earth on its axis, an imaginary line that runs from the North Pole to the South Pole. This rotation is responsible for the cycle of day and night. As the Earth rotates, different parts of the planet are exposed to the Sun's light, resulting in the alternation between daylight and darkness.
The rotation period of the Earth is commonly referred to as a day. One complete rotation corresponds to 360 degrees of rotation, and it takes approximately 24 hours for the Earth to complete one full rotation. This 24-hour period is the basis for our standard measurement of time, with each day consisting of 24 hours.
Option a, stating that Earth rotates on its axis once every two days, is incorrect because it underestimates the duration of Earth's rotation. Option b, stating that Earth rotates on its axis once every year, is incorrect as it confuses Earth's rotation with its revolution around the Sun, which takes approximately 365.25 days. Option d, stating that Earth rotates on its axis twice every 24 hours, is incorrect as it implies a faster rotation rate than the actual 24-hour period.
In conclusion, Earth's rotation takes approximately 24 hours, causing the cycle of day and night. This rotation is a fundamental aspect of Earth's dynamics and has significant implications for various natural processes and phenomena on our planet.
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Related Questions
Which of the following occurs when a liquid’s thermal energy is increased?
A. The particles break away from one another.
B. The particles give off energy.
C. The particles slow down.
D. The particles move closer together.
Answers
Answer:
I think the answer is c. The particles slow down.
A boat is cruising in a straight line at a constant speed of 2.5 m/s when it is shifted into neutral. After coasting 14 mm the engine is engaged again, and the boat resumes cruising at the reduced constant speed of 1.5 m/s. Assuming constant acceleration while coasting,
a. How much time did it take for the boat to coast the 12 m?
b. What was the boat’s acceleration while it was coasting?
c. What was the speed of the boat when it had coasted for 6.0 m? Explain.
Answers
Answer:
Explanation:
a ) distance s = 12 m .
constant speed = 1.5 m/s
time taken to coast 12 m
= distance / speed
= 12 / 1.5 = 8 s
b ) initial velocity u = 2.5 m /s
final velocity v = 1.5 m /s
displacement s = 14 m
acceleration a = ?
v² = u² + 2 as
1.5² = 2.5² + 2 a x 14
a = - .1428 m /s²
= - 14.28 cm / s²
c )
v = ?
u = 2.5 m /s
s = 6 m
a = - .1428 m /s²
v² = u² - 2 as
= 2.5² - 2 x 6 x .1428
= 6.25 - 1.71
= 4.54
v = 2.13 m /s .
Which of the following is not a metric base unit? *
Meter
Liter
Inch
Gram
Answers
Answer:
Liter
Explanation:
idetify 5 types of kitchen tool Whrite the difinition of each tool.
Answers
(1) wooden spoon - often made from bamboo, is used for mixing and when cooking and stirring hot foods. A wooden spoon will not transfer heat to the hand like a metal spoon.
(2) wire whisk - many wire loops held together in a handle - used to whip eggs or cream or add air to a thin batter.
(3) rubber scraper - A smooth rubber flat spoon on a handle, Used for mixing, folding soft ingredients and to scrape ingredients from a bowl.
(4) peeler - sharp curved metal scraper in a handle - Used to remove the outer layer of fruits and vegetables.
(5) Paring knife - small knife that fits in the hand. It’s an all purpose small knife used for small cuts, garnishes, paring or coring.
a mass of 2.00 kg rest on a rough horizontal table. The coefficient of static friction between the block and the table is 0.60. The block is attached to a hanging mass by a string that goes over a smooth pulley,as shown in the diagram. Determine the largest mass that can hang in this way without forcing the block to slide.
Answers
Answer:
1.2 kg
__________________________________________________________
We are given:
Mass of the block = 2 kg
Coefficient of Static Friction = 0.6
__________________________________________________________
Friction Force on the Block:
Finding the Normal Force:
We know that the normal force will be equal and opposite to the weight of the 2 kg block
So, Normal Force = mg
replacing the variables with the given values
Normal Force = (2)(9.8) [Taking g = 9.8]
Normal Force = 19.6 N
Friction force on the Block:
We know that:
Coefficient of Static Friction = Static Friction Force/Normal Force
replacing the variables
0.6 = Static Friction force / 19.6
Static Friction force = 0.6*19.6 N [Multiplying both sides by 19.6]
Static Friction force = 11.76 N
__________________________________________________________
Largest Mass that can Hang:
We know that the Static Friction force is 11.76 N, this means that a force of 11.76 N will be applied to keep the object at rest
So, if the weight of the second block is less than the static friction force, it will hang
Weight of the second block ≤ 11.76
We know that weight = mg
mg ≤ 11.76
m(9.8) ≤ 11.76 [since g = 9.8]
m ≤ 1.2 kg [dividing both sides by 9.8]
From this, we can say that the maximum mass of the second block is 1.2 Kg
Fill in the blanks in the following paragraph to correctly identify the properties of devices that use electromagnetism. (1 point)
A(n) ____________________ changes mechanical energy into ____________________. A(n) ____________________ changes electric energy into ____________________. A(n) ____________________ changes the voltage of an alternating current. A(n) ____________________ transformer has more loops in the primary coil than in the secondary coil. A(n) ____________________ transformer has ____________________ loops in the primary coil than in the secondary coil.
Answers
Answer:
this answer you question
Answer:
generatorelectricalmotormechanicaltransformerstep-downstep-upfewerExplanation:
A(n) generator changes mechanical energy into electrical. A(n) motor changes electric energy into mechanical. A(n) transformer changes the voltage of an alternating current. A(n) step-down transformer has more loops in the primary coil than in the secondary coil. A(n) step-up transformer has fewer loops in the primary coil than in the secondary coil.
Hope it's helpful!
The speed of a wave travelling along a 0.650 m guitar string is 320 m/s at n = 5 the frequency is 1230 Hz. What is the frequency of a string wave speed of 240.0 m/s is used?
Answers
Answer:
The frequency of a string wave is 922.5 Hz
Explanation:
Given;
length of the string, L = 0.65 m
initial speed of the string wave at n = 5, v₁ = 320 m/s
initial frequency of the wave speed, f₁ = 1230 Hz
final speed of the string wave at n = 5, v₂ = 240.0 m/s
final frequency of the wave speed, f₂ = ?
speed of wave is related to frequency of wave and wavelength by the following equation;
V = Fλ
If the wavelength is constant at n = 5, then
\(\lambda = \frac{V_1}{f_1} = \frac{V_2}{f_2}\\\\f_2 = \frac{f_1V_2}{V_1} \\\\f_2 =\frac{1230*240}{320} \\\\f_2 = 922.5 \ Hz\)
Therefore, the frequency of a string wave, if speed of 240.0 m/s is used is 922.5 Hz
Choose the answer choice that BEST completes the following sentence:
The
of the Sun is the interior or center part of this star.
O Radiative Zone
O Core
O Convective Zone
O Photosphere
Answers
The core of the Sun is the interior or center part of this star.
The features of the sunThe sun is one of the stars of the solar system that gives life to the planet earth. All the other planets revolves round it.
The features of the sun include the following:
sunspots, solar prominences, solar flares, and coronal mass ejections.The sun is also made up of several parts which include:
Hydrogen and helium.The core,The radiative zone,The convective zone, and The photosphere.The innermost or central part of the sun is the core that is made up of the highest amount of hydrogen atoms.
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The kinematic viscosity of oxygen at 40 °C and a pressure of 160 kPa is 0.104 stokes. Determine the dynamic viscosity of the oxygen at this temperature and pressure. (Ro₂ = 0.2598 kPa.m³/kg.K)
Answers
The dynamic viscosity of oxygen at 40°C and 160 kPa is 64.17 × 10⁻⁶ Pa.s.
The dynamic viscosity of a fluid is equal to its kinematic viscosity multiplied by its density.
Given:
Kinematic viscosity of oxygen at 40°C and 160 kPa = 0.104 stokes
Density of oxygen at 40°C and 160 kPa = (160000 Pa / 0.2598 kPa.m³) = 616.55 kg/m³ (using ideal gas law)
Using the formula:
Dynamic viscosity = Kinematic viscosity * Density
We get:
Dynamic viscosity of oxygen = 0.104 stokes * 616.55 kg/m³ = 64.17 × 10⁻⁶ Pa.s
Therefore, the dynamic viscosity of the oxygen at 40°C and 160 kPa is 64.17 × 10⁻⁶ Pa.s.
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. When a parallel plate capacitor is connected to a 12 V battery, each plate requires a charge of magnitude 0.0024 C. Find its capacitance. If the capacitor is connected to 24 V battery, will its capacitance increase? Why?
Answers
The capacitance of the capacitor is 1.7 * 10^-4 F. The capacitance will increase when the voltage is increased.
How does the capacitance relate to the magnitude of the voltage?If we hold the capacitance constant, a higher voltage applied to the capacitor will result in a greater amount of electrical charge stored on the capacitor. Conversely, if we hold the voltage constant, a capacitor with a higher capacitance will be able to store more electrical charge. In other words, the capacitance and the voltage are directly proportional to the amount of electrical charge that can be stored on a capacitor.
We know that;
q = CV
C = q/V
C = 0.0024 C/12 V
C = 1.7 * 10^-4 F
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what i have learned
complete the statements below. write your answers on a separate sheet of paper
even before the advent of the telescope ancient aastronomers were able to observe the following
Answers
Even before the advent of the telescope, ancient astronomers were able to observe the following:
1. Celestial Bodies: Ancient astronomers could observe celestial bodies such as the Sun, Moon, stars, and planets. They could track their movements across the sky and study their patterns and behaviors.
2. Solar and Lunar Eclipses: By carefully observing the positions of the Sun, Moon, and Earth, ancient astronomers could predict and witness solar and lunar eclipses. They noticed that during a solar eclipse, the Moon blocks the Sun's light, creating a temporary darkness on Earth, while during a lunar eclipse, the Earth casts a shadow on the Moon, causing it to appear reddish or darkened.
3. Stellar Positions: Ancient astronomers mapped and observed the positions of stars in the night sky. They recognized patterns and constellations, which helped them navigate and keep track of time.
4. Seasons and Celestial Movements: By observing the changing positions of the Sun and its daily and yearly motions, ancient astronomers could understand the changing seasons. They could determine solstices, equinoxes, and the length of days and nights.
5. Comet Appearances: Ancient astronomers were able to observe and document the appearance of comets in the night sky. They recognized these celestial objects as distinct from stars and noted their unusual and transient nature.
These observations formed the basis of ancient astronomy and laid the groundwork for the development of more advanced astronomical techniques and instruments, including the telescope.
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Need a 5 paragraph essay in the eartsh layers and how they function/ benefit the earth!
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There is more to the Earth than what we can see on the surface. In fact, if you were able to hold the Earth in your hand and slice it in half, you'd see that it has multiple layers. But of course, the interior of our world continues to hold some mysteries for us. Even as we intrepidly explore other worlds and deploy satellites into orbit, the inner recesses of our planet remains off limit from us.
However, advances in seismology have allowed us to learn a great deal about the Earth and the many layers that make it up. Each layer has its own properties, composition, and characteristics that affects many of the key processes of our planet. They are, in order from the exterior to the interior – the crust, the mantle, the outer core, and the inner core. Let's take a look at them and see what they have going on.
Like all terrestrial planets, the Earth's interior is differentiated. This means that its internal structure consists of layers, arranged like the skin of an onion. Peel back one, and you find another, distinguished from the last by its chemical and geological properties, as well as vast differences in temperature and pressure.
Explanation:
2. A student was sitting on one end of a set of metal bleachers outside of a school building. A drumline was practicing on the other end of the bleachers. Some of the musicians are drumming on the bleachers while others are drumming on their drums. The drumming on drums doesn’t bother the student, but the drumming on the bleachers does because he can feel it in the seat. He moves further away, which helps, but not enough. Finally, he decides to sit on his backpack. Compare the two types of waves the student is detecting. In your response, be sure to include: Why the student can feel the vibrations from the bleachers, but not from the drums. Identification of the two types of waves created by the drumming. A description of two similarities between the two wave types A description of two differences between the two wave types. Why moving away and sitting on the backpack helps him feel the waves less.
Answers
The students can feel the vibrations from the bleachers, but not from the drums because of the resonance.
What is the resonance?The resonance condition occurs when the frequency of a wave matches with the resonance frequency.
The transfer of energy becomes maximum when the natural frequency matches with the frequency generated by the source.
The bleacher and student together having the frequency matching with the resonance frequency of the drum.
The bleacher and student with the bag frequency doesn't match with the resonance value of drums. Secondly, as distance increases sound intensity also decreases.
Thus, the student can feel the vibrations from the bleachers, but not from the drums because of the resonance.
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2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
Answers
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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Imagine a negative test charge sitting at the coordinate origin (0,0). Two bunches of positive charges are located on the x-axis and the y-axis, respectively, so that the vectors of the respective electric forces, which the test charge experiences, point from the origin at points (1,0) and (0,1), respectively. The total force vector, which the test charge experiences, points from the origin at the point __________
Answers
Answer:
the total force vector, on test charge is points from origin to point C( 1, 1 )
Explanation:
Given the data in the question, as illustrated in the image below;
from the Image, OA = 1, OB = AC = 1
so using Pythagoras theorem
a² = b² + c²
a = √( b² + c² )
so
OC = √( OB² + AC² )
we substitute
OC = √( OA² + AC² )
OC = √( 1² + 1² )
OC = √( 1 + 1 )
OC = √2
Coordinate of C( 1, 1 )
Hence, the total force vector, on test charge is points from origin to point C( 1, 1 )
The center of a 1500 kg kg satellite is 9.9 ×10^6 m from Earth’s center. What is the gravitational force between the satellite and Earth?
Answers
Answer:
the substitute bride is a good girl who knows
What is the type of friction force if the object appears just about to start motion? Why?
Answer and I will give you brainiliest
Answers
Answer:
static friction
Explanation:
As I mentioned before static is just the object is started to move if it kentic it is moving
A 1.50-kg bucket of water is tied by a rope and whirled in a circle with a radius of 1.00 m. At the bottom of the circular loop, the speed of the bucket is 6.00 m/s. Determine the acceleration, the net force and the individual force values when the bucket is at the bottom of the circular loop.
Answers
The centripetal acceleration of the bucket at the bottom of the circular loop is 36 m/s².
The net force at the bottom of the circular loop is 68.7 N.
The given parameters:
Mass of the bucket, m = 1.5 kgRadius of the circle, r = 1 mSpeed of the bucket at bottom, v = 6 m/sWhat is centripetal acceleration?Centripetal acceleration is the radial acceleration of an object in a circular path.The centripetal acceleration of the bucket at the bottom of the circular loop is calculated as follows;
\(a_c = \frac{v^2}{r} \\\\a_c = \frac{6^2}{1} \\\\a_c = 36 \ m/s^2\)
The net force at the bottom of the circular loop is calculated as follows;
\(F_{net} = m(g + a_c)\\\\F_{net} = 1.5(9.8 + 36)\\\\F_{net} = 68.7 \ N\)
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Which individual or group had perhaps the most profound effect on establishing social work as a specialized practice
Answers
Answer:
Which individual or group had perhaps the most profound effect on establishing social work as a specialized practice
Explanation:
predict the order of increasing electronegativity in each of the following groups of elements. (use < symbol to separate substances in the list.)
Answers
Electronegativity is a tendency of a atom/element to attract the pair of electrons.
B,O,Gaelectronegativity order = O>B>Ga
Mg,Ba,Caelectronegativity order = Mg>Ba>Ca
Ga,Al,Pelectronegativity order =P>Ga>Al
Al,O,Celectronegativity order =O>C>Al
When an atom of a certain chemical element forms a chemical bond, it has a propensity to draw shared electrons (or electron density). The atomic number and the separation of the valence electrons from the charged nucleus have an impact on an atom's electronegativity. An atom or a substituent group will draw electrons in greater amounts the higher the associated electronegativity. The sign and amplitude of a bond's chemical polarity, which characterizes a bond along the continuous scale from covalent to ionic bonding, can be quantitatively estimated using electronegativity. The inverse of electronegativity is electropositivity, which describes an element's propensity to accept valence electrons.
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Find the current if 55 C of charge pass a particular point in a circuit in 5
seconds.
Answers
Answer: The current is 11 Amperes
Explanation:
Think of a book at rest on a flat leveled surface and another book (same type) that is sliding and slowing down to a complete stop on the
same surface.
a. What force(s) is on the sliding book that is not on the book at rest? Explain why.
b. If the sliding book was speeding up instead, describe how the free body diagram would be drawn differently than the book at rest.
Answers
B. The arrow in the direction the book travels is larger than the other lines and there would also be a backwards force from the drag
A rocket sled accelerates to 50 m/s. When the rocket engine stips, the sled skids along its rails. If the coefficient of friction is 0.5, how fast is the sled moving after 2.50 s?
Answers
The sled's speed can be calculated by considering the acceleration, frictional force, and time. After substituting the given values and performing the calculations, the final speed is determined to be 12.25 m/s.
To calculate the speed of the sled after 2.50 seconds, we can use the equations of motion and consider the forces acting on the sled.
Let's denote the initial speed of the sled as v0, the final speed as vf, the acceleration as a, the time as t, and the coefficient of friction as μ.
Initially, the rocket sled is accelerating, so we can use the equation:
vf = v0 + at
Since the sled is skidding along its rails after the rocket engine stops, the only horizontal force acting on the sled is the force of friction. The frictional force can be calculated using the equation:
frictional force = coefficient of friction * normal force
Since the sled is moving horizontally, the normal force is equal to the weight of the sled, which can be calculated as:
weight = mass * gravity
Now, we can determine the acceleration of the sled using Newton's second law:
frictional force = mass * acceleration
Combining the equations and substituting the values, we have:
vf = v0 + (frictional force / mass) * t
To find the frictional force, we need to calculate the weight of the sled and then multiply it by the coefficient of friction:
frictional force = (mass * gravity) * coefficient of friction
Substituting this back into the previous equation, we get:
vf = v0 + ((mass * gravity * coefficient of friction) / mass) * t
Simplifying further, we have:
vf = v0 + (gravity * coefficient of friction) * t
Now we can substitute the given values into the equation. Assuming the acceleration due to gravity is approximately 9.8 m/s², the coefficient of friction is 0.5, the initial speed is 0 m/s (since the sled starts from rest), and the time is 2.50 s, we can calculate the final speed:
vf = 0 + (9.8 * 0.5) * 2.50
vf = 12.25 m/s
Therefore, the sled is moving at a speed of 12.25 m/s after 2.50 seconds.
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define key terms related to the muscular, skeletal, and nervous systems
Answers
Answer:
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can anyone write for me all the equation of linear motion
Answers
All the equations of motion are as follows, Displacement (s) equation, Final velocity (v) equation, Average velocity (v_avg) equation, Displacement (s) equation with average velocity, and Displacement (s) equation.
Equations of MotionIn terms of its motion as a function of time, equations of motion define how a physical system behaves. In more detail, the equations of motion define how a physical system behaves as a collection of mathematical functions expressed in terms of dynamic variables.
s = ut + (1/2)at^2v = u + atv_avg = (u + v) / 2s = v_avg * ts = (u + v) / 2 * tv^2 = u^2 + 2asIn conclusion, equations of motion define how a physical system behaves in terms of how its motion changes over time.
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The fact that all the planets orbit the Sun in the same direction is cited as support for the nebular hypothesis. Imagine that there's a different hypothesis in which planets can be created orbiting the Sun in either direction. Part A Under this hypothesis, what is the probability that eight planets would end up traveling in the same direction
Answers
The probability that eight planets would end up traveling in the same direction is 50%.
Number of planets that will orbit the sun
There are about 8 planets that will orbit the sun.
Current hypothesisUnder this hypothesis that the planets will orbit the sun in the different directions, the following methods can be used to determine the probability that eight planets would end up traveling in the same direction.
P (same direction) = 1 - P(8 planets different direction)
\(P = 1 - \frac{1}{2} \\\\P = \frac{1}{2}\)
Thus, the probability that eight planets would end up traveling in the same direction is 50%.
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Match each term to the best description
a. Coefficient of friction
b. Friction
c. Kinetic friction
d. Normal
e. Static friction
1. A force that acts parallel to the surface.
2. A force that acts perpendicular to the surface.
3. A force that increases as applied force increases up to some maximum value
4. Magnitude depends on the interacting materials
5. A force that is constant regardless of the applied force
Answers
Answer:
Coefficient of friction = Magnitude depends on the interacting materials
Friction = A force that acts parallel to the surface.
kinetic friction = A force that is constant regardless of the applied force
Normal = A force that acts perpendicular to the surface
Static friction = A force that increases as applied force increases up to some maximum value
Explanation:
Let's define all the forces, and then let's solve the problem.
Normal force:
When an object rests on some place (like a book on the table) the force that causes the book to not fall through the table is called the normal force, which is usually equal to the weight of the object and acts perpendicular to the surface where the object is resting.
Friction force.
When an object moves (or tries to move) parallel to a surface, such that the object is in contact with that surface, there appears a force that opposes to the movement (the force is parallel to the surface, and in the opposite direction to the movement).
And this force can be written as:
F = -N*μ
Where μ is the coefficient of friction and N is the normal force.
If the object is not moving yet (but there is applied a force that would move the object) the coefficient is called the coefficient of static friction which increases in a given range, until it can't keep increasing and the object starts to move, while if the object is moving, the coefficient is called the coefficient of kinetic friction and it is constant, where usually the first one is larger than the second, and these coefficients depend on both materials, the surface one and the object one.
Then we have two friction forces, one called the kinetic friction and the other called the static friction.
Then:
Coefficient of friction = Magnitude depends on the interacting materials
Friction = A force that acts parallel to the surface.
kinetic friction = A force that is constant regardless of the applied force
Normal = A force that acts perpendicular to the surface
Static friction = A force that increases as applied force increases up to some maximum value
Which of these is NOT a behavior of light that shows that it is a wave?
- interference
-refraction
-reflection
- the photoelectric effect
Answers
Answer:
the photoelectric effect
Explanation:
Light wave can be defined as an electromagnetic wave that do not require a medium of propagation for it to travel through a vacuum of space where no particles exist.
The behavior of light that shows that it is a wave include the following;
I. Interference: it occurs when two pair of waves such as sound and light waves pass through each other i.e crossing each other's path while traveling through the same medium or space.
II. Reflection: it can be defined as a phenomenon which typically involves a change in the direction of a ray of light or waves as it falls on a smooth surface.
III. Refraction: it's a bend in the direction of light.
However, the photoelectric effect of light describes light as a particle.
will give brainliest :)Two objects having equal masses and velocities collide with each other and come to a rest. What type of a collision is this and why?
A. Elastic collision, because internal kinetic energy is conserved
B .Inelastic collision, because internal kinetic energy is not conserved
C. Elastic collision, because internal kinetic energy is not conserved
D. Inelastic collision, because internal kinetic energy is conserved
Answers
Answer:
B. lnelastic collision, because interest kinetic energy is not conserved .
I hope it helps ❤❤
The type of collision experienced by the two objects is inelastic collision, because internal kinetic energy is not conserved.
There are two types of collisions that two objects moving directly or opposite each may experience:
Elastic collision, andInelastic collision.In elastic collision, both momentum and kinetic energy of the to objects are conserved.
In inelastic collision, only momentum is conserved while kinetic energy decreases after the collision.
Thus, we can conclude that the type of collision experienced by the two objects is inelastic collision, because internal kinetic energy is not conserved.
Learn more here:https://brainly.com/question/18432099
A turtle is moving with a velocity of 0.12m/s. He is trying to move a
distance of 7m. How much time will it take him to get to his destination?
58.3 seconds
O 0.02 seconds
O 0.84 seconds
7.12 seconds