Answer:
its the 2nd one
Step-by-step explanation:
Marimar buys and old mirrors for $45:00 . She spend $5:00 to fix and paint it . Then she sell the mirror for $78:00 . What is marimar profit ?
Answer:
28 dollars
Step-by-step explanation:
$45+$5= $50 which is how much she spent it total
then she sells it for $78
so her profit would be $28
A borrower wants to take a loan with a maximum effective monthly rate of 1%. What is the maximum APR with quarterly compounding that the borrower will accept from a lender?
The maximum APR with quarterly compounding that the borrower will accept from a lender is 16.132%.
How to calculate APR?To convert the maximum effective monthly rate of 1% into an APR with quarterly compounding, we can use the formula:
\(APR = [(1 + \dfrac{r}{n})^n - 1] \times 4\)
Where r is the effective monthly rate and n is the number of compounding periods per year. In this case, we want to find the maximum APR with quarterly compounding that the borrower will accept, so we can substitute r = 1% and n = 3:
\(APR = ((1 + \dfrac{0.01}{3})^3 - 1) \times 4\)
APR = (1.0100333³ - 1) x 4
APR = 0.04033 x 4
APR = 0.16132 or 16.132%
Therefore, the maximum APR with quarterly compounding that the borrower will accept from a lender is 16.132%.
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NO LINKS!!! URGENT HELP PLEASE!!!
Solve ΔABC using the Law of Sines
1. A = 29°, C = 63°, c = 24
2. A = 72°, B= 35°, c = 21
Answer:
1) B = 88°, a = 13.1, b = 26.9
2) C = 73°, a = 20.9, b = 12.6
Step-by-step explanation:
To solve for the remaining sides and angles of the triangle, given two sides and an adjacent angle, use the Law of Sines formula:
\(\boxed{\begin{minipage}{7.6 cm}\underline{Law of Sines} \\\\$\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}$\\\\\\where:\\ \phantom{ww}$\bullet$ $A, B$ and $C$ are the angles. \\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides opposite the angles.\\\end{minipage}}\)
Question 1Given values:
A = 29°C = 63°c = 24As the interior angles of a triangle sum to 180°:
\(\implies A+B+C=180^{\circ}\)
\(\implies B=180^{\circ}-A-C\)
\(\implies B=180^{\circ}-29^{\circ}-63^{\circ}\)
\(\implies B=88^{\circ}\)
Substitute the values of A, B, C and c into the Law of Sines formula and solve for sides a and b:
\(\implies \dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}\)
\(\implies \dfrac{a}{\sin 29^{\circ}}=\dfrac{b}{\sin 88^{\circ}}=\dfrac{24}{\sin 63^{\circ}}\)
Solve for a:
\(\implies \dfrac{a}{\sin 29^{\circ}}=\dfrac{24}{\sin 63^{\circ}}\)
\(\implies a=\dfrac{24\sin 29^{\circ}}{\sin 63^{\circ}}\)
\(\implies a=13.0876493...\)
\(\implies a=13.1\)
Solve for b:
\(\implies \dfrac{b}{\sin 88^{\circ}}=\dfrac{24}{\sin 63^{\circ}}\)
\(\implies b=\dfrac{24\sin 88^{\circ}}{\sin 63^{\circ}}\)
\(\implies b=26.9194211...\)
\(\implies b=26.9\)
\(\hrulefill\)
Question 2Given values:
A = 72°B = 35°c = 21As the interior angles of a triangle sum to 180°:
\(\implies A+B+C=180^{\circ}\)
\(\implies C=180^{\circ}-A-B\)
\(\implies C=180^{\circ}-72^{\circ}-35^{\circ}\)
\(\implies C=73^{\circ}\)
Substitute the values of A, B, C and c into the Law of Sines formula and solve for sides a and b:
\(\implies \dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}\)
\(\implies \dfrac{a}{\sin 72^{\circ}}=\dfrac{b}{\sin 35^{\circ}}=\dfrac{21}{\sin 73^{\circ}}\)
Solve for a:
\(\implies \dfrac{a}{\sin 72^{\circ}}=\dfrac{21}{\sin 73^{\circ}}\)
\(\implies a=\dfrac{21\sin 72^{\circ}}{\sin 73^{\circ}}\)
\(\implies a=20.8847511...\)
\(\implies a=20.9\)
Solve for b:
\(\implies \dfrac{b}{\sin 35^{\circ}}=\dfrac{21}{\sin 73^{\circ}}\)
\(\implies b=\dfrac{21\sin 35^{\circ}}{\sin 73^{\circ}}\)
\(\implies b=12.5954671...\)
\(\implies b=12.6\)
Write the following fractions in decreasing order: 4/7, 11/15, 2/3.
Answer:
11/15 4/7 2/3
Step-by-step explanation:
What is 6.6 divided by (-3)
Answer:
-2.2
Step-by-step explanation:
If you divide/multiply a positive number by a negative number the product will be negative :)
Hope I helped!
Answer:
-2.2
Step-by-step explanation:
Is the answer
On Thursday, a local hamburger shop sold a combined total of 378 hamburgers and cheeseburgers. The number of cheeseburgers sold was two times the number of hamburgers sold. How many hamburgers were sold on Thursday?
Answer:
252 Cheese Bugers were sold on Thursday
Step-by-step explanation:
378 divided by 3=126
126+126= number of hamburgers
126= number of chese bugers
126+126=252
the highest point in Asia is Mount Everest at 8 850 meters. The shore of the dead Sea, the lowest point in Asia is about 410 meters below sea level. What is the difference between these elevations?
I need to know what the x and y intercepts are for these problems. if you could show work i would appreciate it.
1. f(x)=4x−8
2. f(x)=1/2x+2
3. f(x)=x^2-16
Answer:
1.
x = (2,0)
y = (0,-8)
2.
x = (-2,0)
y = ( 0, 2)
3.
x = ( 4,0)
y = ( 0, -16)
Step-by-step explanation:
aIll do one equation as an example
f(x) = 4x -8
y = 4x - 8
since its an intercept you know the x, for the y intercept will be zero and vice versa. Its like this cause its on the axis.
So you only need to figure out the y for the y intercept and the x for the x intercept.
- 4x + y = -8
after changing the equation to standar form you then ignore the x base so, 4x to get the y intercept.
- 4x + y = -8 becomes y = - 8 then you add the 0 for the coordinate
y = -8 becomes (0,-8)
f(x) = 4x -8
y = 4x - 8
- 4x + y = -8
y = - 8
(0,-8)
f(x) = 4x -8
y = 4x - 8
- 4x + y = -8
-4x = -8
x = 2
(2, 0)
sorry im not really good at explaining lol
can g et a brainliest for effort at least 5 points isnt much
3) Last year the mean salary for professors in a particular community college was $62,000 with a standard deviation of $2000. A new two year contract is negotiated. In the first year of the contract, each professor receives a $1500 raise.
Find the mean and standard deviation for the first year of the contract.
b) In the second year of the contract, each professor receives a 3% raise based on their salary during the first year of the contract. Find the mean and the standard deviation for the second year of the contract.
a) Mean for the first year of the contract: $63,500
The standard deviation for the first year of the contract: $2,000.
b) Mean for the second year of the contract: $65,405.
The standard deviation for the second year of the contract: $60.
We have,
To find the mean and standard deviation for the first year of the contract, we can use the given information and the properties of the normal distribution.
Given:
The mean salary for professors in the previous year = $62,000
Standard deviation in the previous year = $2,000
Raise in the first year = $1,500
Mean for the first year of the contract:
The mean salary for the first year can be obtained by adding the raise to the previous mean:
Mean = Previous Mean + Raise
Mean = $62,000 + $1,500
Mean = $63,500
The standard deviation for the first year of the contract:
Since each professor receives the same raise, the standard deviation remains the same:
Standard Deviation = $2,000
Therefore, for the first year of the contract, the mean salary is $63,500, and the standard deviation remains $2,000.
Now,
In the second year of the contract, each professor receives a 3% raise based on their salary during the first year of the contract.
To find the mean and standard deviation for the second year, we can use the given information and the properties of the normal distribution.
Mean for the second year of the contract:
To calculate the mean for the second year, we need to add a 3% raise to the mean salary of the first year:
Mean = Mean of the first year + (3% * Mean of the first year)
Mean = $63,500 + (0.03 * $63,500)
Mean = $63,500 + $1,905
Mean = $65,405
The standard deviation for the second year of the contract:
Since each professor receives a raise based on their salary from the first year, the standard deviation also increases. To calculate the standard deviation, we multiply the standard deviation from the first year by the percentage increase:
Standard Deviation = Standard Deviation of the first year * (Percentage Increase / 100)
Standard Deviation = $2,000 * (3 / 100)
Standard Deviation = $2,000 * 0.03
Standard Deviation = $60
Therefore, for the second year of the contract, the mean salary is $65,405, and the standard deviation is $60.
Thus,
a) Mean for the first year of the contract: $63,500
The standard deviation for the first year of the contract: $2,000.
b) Mean for the second year of the contract: $65,405.
The standard deviation for the second year of the contract: $60.
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Help please need answers today !!!!!!!
A) The continuous rate of growth of this bacterium population is 45 percent.
B) The initial population of the culture at t=0 is 930.
C) The bacteria that will culture at time t=5 is 8823.59.
What is meant by continuous rate of growth?A = Pert, where "A" is the ending amount, "P" is the starting amount (principal in the case of money), "r" is the growth or decay rate (expressed as a decimal), and "t" is the time (in whichever unit was used on the growth/decay rate).
Given,
n(t)= 930\(e^{0.45t}\)
Also given that t is measured in hours.
We know that the equation for continual growth is ,
A= P\(e^{rt}\)
Where A is the final amount, P is the starting amount, and r is the growth or decay rate.
A) From the above equation,
r=0.45
The continuous rate of growth of this bacterium population is 45 percent.
B) At t=0,
n(0)= 930\(e^{0.45(0)}\)
n(0)=930
The initial population of the culture at t=0 is 930.
C) At t=5,
n(5)= 930\(e^{0.45(5)}\)
n(5)= 8823.59
The bacteria that will culture at time t=5 is 8823.59.
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Type the correct answer in the box. Use numerals instead of words.
What is the solution to this equation?
7 - 32
- I = 12
The solution is r =
Answer:
Step-by-step explanation:
\(7- \sqrt[3]{2-x} =12\)
we have to just keep in mind to do the same operation to both sides of the equal sign
\(7-7- \sqrt[3]{2-x} =12-7\) ; subtract 7 from both sides
\(- \sqrt[3]{2-x} = 5\) ; multiply both sides by -1
\(\sqrt[3]{2-x} = -5\) ; raise both sides to the power 3
2-x = (-5)³
2-x = -125 ; subtract 2 from both sides
-x = -125-2
-x =-127; multiply both sides by -1
x= 127
A $30 shirt is marked, "Get 1/3 off. What is the sale price of the shirt?
Answer:
$20 after the applied coupon
Step-by-step explanation:
The required sale price of the shirt after getting 1/3 off is $20.
What are percentages?The percentage is the ratio of the composition of matter to the overall composition of matter multiplied by 100.
Here,
A $30 shirt is marked, "Get 1/3 off.
The sale price of the shirt,
= 30 - 1 / 3×30
= 30 - 10
= $ 20
Thus, the required sale price of the shirt after getting 1/3 off is $20.
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An odd degree has no maximum or minimum. True or False?
Answer:
answer is false in my opinion not sure
What is the slope-intercept equation
for the following line?
Answer:
y=-1/3 x+1
Step-by-step explanation:
At a hockey game, a vender sold a combined total of 117 sodas and hot dogs. The number of sodas sold was two times the number of hot dogs sold. Find the number of sodas and the number of hot dogs sold.
Answer:
whenimetyouinthesumma
Step-by-step explanation:
Answer:
78 sodas, 39 hot dogs
Step-by-step explanation:
s= sodas d=hot dogs
s:d = 2:1 = 3
?:? =117
117/3 = 39
2 x 39 = 78, 39 x 1 =39
s:d = 78:39
find the area of the segment. also, what is the arc length of AB (curved line over AB)
The area of the shaded region can be obtained by subtraction of the triangle ΔABC from the circular region CAB.
First, for the triangle:
We need to find the length of CH and HB (the height and half of the base of the triangle) in order to calculate the area of the triangle. Using trigonometric functions:
\(\begin{gathered} \sin50\degree=\frac{HB}{18}\Rightarrow HB=18\sin50\degree \\ \\ \cos50\degree=\frac{CH}{18}\Rightarrow CH=18\cos50\degree \end{gathered}\)The area of the triangle is given by:
\(A_{triangle}=\frac{base\cdot height}{2}=18\cos50\degree\cdot18\sin50\degree=324\sin50\degree\cos50\degree\)We know that sin(2x) = 2*sin(x)*cos(x). Then:
\(A_{triangle}=162\sin100\degree\)Now, for the circular region, we have the formula:
\(A_{circ}=\frac{\theta\cdot r^2}{2}\)Where θ is the central angle and r is the radius. From the problem, we identify:
\(\begin{gathered} \theta=100\degree=100\degree\cdot\frac{\pi}{180\degree}=\frac{5\pi}{9} \\ \\ r=18\text{ ft} \end{gathered}\)Using the formula:
\(A_{circ}=\frac{5\pi/9\cdot18^2}{2}=90\pi\)Finally, we subtract A_triangle from A_circ:
\(\begin{gathered} A_{shaded}=90\pi-162\sin100\degree \\ \\ \therefore A_{shaded}\approx123.204\text{ ft}{}^2 \end{gathered}\)For the arc length AB, we use the formula:
\(AB=\theta\cdot r\)Using the values for the angle and the radius:
\(\begin{gathered} AB=\frac{5\pi}{9}\cdot18 \\ \\ \therefore AB=10\pi\approx31.416\text{ ft} \end{gathered}\)Answer:
\(\begin{gathered} \text{ Area }=123.204\text{ ft}^2 \\ \\ \text{ Arc length }=31.416\text{ ft} \end{gathered}\)Which of the following can be used to determine the approximate area of a region on a map? Choose all that apply.
Answer:
square grid, square represents area
Step-by-step explanation:
help fast please i’m bad with math
Answer:
FALSE, TRUE, FALSE, FALSE
Step-by-step explanation:
pi/2>2 - FALSE
3pi>9 - TRUE
2pi-1<5 - FALSE
pi+8<11 - FALSE
please help I'm so stuck on this
Answer:
divide the anser in the pasage
Step-by-step explanation:
divide the two numbers
What is the volume of the cylinder below? Use the formula V = πr²h
Answer:
\(\boxed{V = 339.12 ft^3}\)
Step-by-step explanation:
V = \(\pi r^2 h\)
Where r = 3, h = 12
V = (3.14)(3)²(12)
V = (3.14)(9)(12)
V = 339.12 ft³
List all of the subgroups of S4. Find each of the following sets. Are any of these sets subgroups of S4?(a) {σ ∈ S4 : σ(1) = 3}(b) {σ ∈ S4 : σ(2) = 2}
This set {σ ∈ S4 : σ(1) = 3} contains the following elements of S4: (13), (23), (34), (24), (14), (12)(34), (13)(24), (14)(23) and {σ ∈ S4 : σ(2) = 2} this set contains the following elements of S4: (12), (21), (13)(24), (24)(13).
What are the subgroups of S4The group S4 is the symmetric group on 4 elements and has 24 elements. We can list all of its subgroups as follows:
The trivial subgroup {e}.Three subgroups isomorphic to the cyclic group of order 2: {e, (12)}, {e, (13)}, {e, (14)}.Four subgroups isomorphic to the cyclic group of order 3: {e, (123), (132)}, {e, (124), (142)}, {e, (134), (143)}, {e, (234), (243)}.Two subgroups isomorphic to the dihedral group of order 4: {e, (1234), (13)(24), (1432)}, {e, (1234), (14)(23), (1324)}.The alternating group A4 of even permutations: {e, (123), (132), (124), (142), (134), (143), (234), (243), (12)(34), (13)(24), (14)(23), (12)(34), (13)(24), (14)(23)}.Now, let's consider the sets (a) and (b) and see if they are subgroups of S4:
(a) {σ ∈ S4 : σ(1) = 3}
This set contains the following elements of S4: (13), (23), (34), (24), (14), (12)(34), (13)(24), (14)(23). We can check that this set is not a subgroup of S4 because it is not closed under composition. For example, (13)(14) = (134) is not in the set.
(b) {σ ∈ S4 : σ(2) = 2}
This set contains the following elements of S4: (12), (21), (13)(24), (24)(13). We can check that this set is a subgroup of S4. It is closed under composition, inverses, and contains the identity element e. Therefore, it is a subgroup of S4 and is isomorphic to the cyclic group of order 2.
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2 pounds 6 ounces = ounces
2 pounds 6 ounces in ounces is equivalent to 38 ounces.
The given measurement is -
2 pounds 6 ounces
In 1 pound, there are 16 ounces.
So, we can write that -
2 pounds 6 ounces = 2 x 16 + 6
2 pounds 6 ounces = 38 ounces
So, 2 pounds 6 ounces in ounces is equivalent to 38 ounces.
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Whats the InversE of Y=3x+2
I’m genuinely confused on this, can someone explain how to do this problem?
Answer:
\(n \times 12\)
.......
Find the range of f(x) = 3x + 2 for the domain = {1,2,3}.
Answer:
Range = {5, 8, 11}
Step-by-step explanation:
On the function f(x) = 3x + 2
For the first domain, when x = 1, f(x) = 3(1) + 2 = 3 + 2 = 5
For the second, when x = 2, f(x) = 3(2) + 2 = 6 + 2 = 8
For the third domain, when x = 3, f(x) = 3(3) + 2 = 9 + 2 = 11
which phrase should be inserted in the line to correctly compare the two fractions? use the models for help.
6/10______4/6
A) is greater than
B) cannot be compared to
C) is less than
D) is equal to
Answer:
A.
Step-by-step explanation:
Rewrite the expression with a single base and exponent. (3^2*3^3)^3
The expression can be rewritten by given term as; 3^15
We need to simplify the expression below:
(3^2 x 3^3)^3
Remember that we can add these exponents, so we get:
(9 x 9)^3 = 81^3
Then we can rewrite this as:
531441
Takin the product between the exponents we will get:
(3^5)^3
Thus, the solution is 3^15
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A triangular pyramid is formed from three right triangles as shown below.
Use the information given in the figure to find the length AC.
If applicable, round your answer to the nearest whole number.
The lengths on the figure are not drawn accurately.
A
41
B
85
Answer:
76 units
Step-by-step explanation:
You want the length of AC in the given triangular pyramid.
Pythagorean theoremThe Pythagorean theorem can be used to find the lengths of AD and CD.
AD² + 40² = 41²
AD² = 41² -40² = 81 . . . . . = 9²
and
CD² +40² = 85²
CD² = 85² -40² = 5625 . . . . . = 75²
It can also be used to find AC:
AD² + CD² = AC²
81 + 5625 = AC²
AC = √5706 = 3√634 ≈ 76
The length of side AC is about 76 units.
__
Additional comment
The Pythagorean theorem tells you the square of the hypotenuse is the sum of the squares of the legs of a right triangle.
<95141404393>
(9x+5)+(-2x^2+10x)
(9x+5)+(−2x
2
+10x)
Answer:
If i´m correct and read the answer correct it should be:
-18x³+80x²+65x+5
Step-by-step explanation:
Hopefully this is correct, I couldn't understand if (-2x 2+10x) was spaced or if it was being multiplied.
Question
Example
Step by Step
The endpoints of a side of rectangle ABCD in the coordinate plane are at A (2.11) and
B7, 1). Find the equation of the line that contains the given segment
The line segment is BC.
The equation is y =
llo