Which therapy is associated with light waves, but not sound waves? breaking down kidney stones acoustically targeting the delivery of a drug cauterizing an incision or wound ablating tumors

A. The initial speed in which the ball should be thrown is 27.65 m/s

B. The total time spent by the ball in the air is 5.64 s.

A. Determination of the initial velocity

v² = u² – 2gh (since the ball is going against gravity)

0² = u² – (2 × 9.8 × 39)

0 = u² – 764.4

Collect like terms

u² = 0 + 764.4

u² = 764.4

Take the square root of both side

u = √764.4

u = 27.65 m/s

B. Determination of the total time spent by the ball in the air.

We'll begin by calculating the time taken to reach the maximum height.

s = ½(u + v)t

39 = ½(27.65 + 0)t

39 = ½ × 27.6 × t

39 = 13.825 × t

Divide both side by 13.825

t = 39 / 13.825

t = 2.82 s

Finally, we shall determine the total time.

T = 2t

T = 2 × 2.82

T = 5.64 s

Therefore, the total time spent by the ball in the air is 5.64 s

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A long wire stretches along the x axis and carries a 4.0 a current to the right ( x). the wire is in a uniform magnetic field.

B = (0.22 i - 0.34 j + 0.16 k) T

L = (0.01 i) m

I = 3.2 A

F = I*L cross B = 3.2 * 0.01 * (- 0.16 j - 0.34 k) = (-0.00512 j - 0.01088 k) N

so

Fx = 0

Fy = -0.00512 N

Fz = -0.01088 N

force per CM:

fx = 0

fy = -0.00512 N/cm

fz = -0.01088 N/cm

A uniform magnetic area is represented by means of equally spaced parallel directly traces. The route of the flux is the direction in which the north-seeking pole of a small magnet factors. The strains of flux are continuous, forming closed loops.

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Answer:

Option A. An atom of cobalt contains more neutrons than protons.

Explanation:

From the question given above, the following data were obtained:

Mass number = 59

Atomic number = 27

Next, we shall determine the number of protons in the atom. This is illustrated below:

Atomic number of an element is simply defined as the number of protons in the atom of the element. Thus,

Atomic number = proton number

Atomic number = 27

Therefore,

Proton number = 27

Next, we shall determine the neutron number. This can be obtained as follow:

Mass number = 59

Proton number = 27

Neutron number =?

Mass number = Proton + Neutron

59 = 27 + Neutron

Collect like terms

Neutron = 59 – 27

Neutron number = 32

Next, we shall determine the number of electrons. This can be obtained as follow:

Since the atom is neutral i.e it has no charge, then, the number of protons and electrons are equal. Thus,

Electron number = Proton number

Proton number = 27

Therefore,

Electron number = 27

Summary:

Mass number = 59

Atomic number = 27

Proton number = 27

Neutron number = 32

Electron number = 27

From the above, we can see that the atom of cobalt contains:

1. More neutrons than protons.

2. The same number of protons and electrons.

Therefore, option A gives the correct answer to the question.

When the wall switch is turned off, the light goes out because the switch causes a break in the circuit.

The switch's primary function is to create an open circuit or break in the electrical path. In the "on" position, the switch allows the flow of electrical current through the circuit. This means the electrons can travel from the power source, through the wires, and reach the lightbulb, causing it to illuminate. However, when the wall switch is turned off, it changes the state of the circuit by creating a physical gap or break in the path. By opening the circuit, the switch interrupts the flow of electrical current. This break in the circuit prevents the electrons from moving through the wires and reaching the lightbulb. Without the continuous flow of electrons, the lightbulb is unable to receive the necessary electrical energy to emit light. As a result, the light goes out when the wall switch is turned off. In summary, the act of turning off the wall switch causes a break in the circuit, interrupting the flow of electrical current and preventing the lightbulb from receiving the necessary energy to remain illuminated.

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_______________

\(I_2=2I_1\)

\(L=\text{const}\)

_______________

\(\displaystyle \frac{W_2}{W_1}\; - \;?\)

_______________

\(\displaystyle \boldsymbol{\frac{W_2}{W_1}}=\frac{\dfrac{LI_2^2}{2} }{\dfrac{LI_1^2}{2} } =\frac{I_2^2}{I_1^2} =\bigg(\frac{I_2}{I_1} \bigg)^2=\bigg(\frac{2I_1}{I_1} \bigg)^2=2^2=\boldsymbol{4}\)

Answer: 10 m/s^2

Explanation:

So I think the answer might be 10 m/s^2, following the equation: d=1/2a(t^2).

Variables:

d=45(m)

t=3(s)

a=?

We know the variables "d" and "t" in the equation and have to solve for "a".

So when we plug it in it's:

45=1/2(a)(3^2)

45=1/2(a)(9)

45=4.5(a)

10=(a)

Answer:

The first case requires more force to spin de bucket.

Explanation:

As we know, the centripetal force is directly proportional to the mass, the equation is given by:

\(F_{c}=ma_{c}\)

The first case has a quarter more water than the second case, therefore the first case requires more force to spin de bucket.

I hope it helps you!

Answer:

327 \(^oC\)

Explanation:

The temperature at which the volume would be doubled is 327 \(^oC\).

Using the formula from Charles' law:

V1/T1 = V2/T2, where V1 = initial volume, T1 = initial temperature, V2 = final volume, and T2 = final temperature.

In this case, V2 = 2V1, T1 = 300 K (27 + 273), and T2 is what we are looking for.

Substituting the different entities in the equation:

V1/300 = 2V1/T2

    T2 = 300 x 2 = 600K

Hence, T2 = 600 - 273 = 327 \(^oC\)

Answer:

Fnet = 200 -150

=50N

towards left

Answer:

Velocidad promedio = 5.29 m/s

Explanation:

Dados los siguientes datos;

Distancia = 900 m

Tiempo = 170 segundos

Para encontrar la velocidad media;

La velocidad se puede definir como la distancia recorrida por unidad de tiempo. La velocidad es una cantidad escalar y, como tal, tiene magnitud pero no dirección.

Matemáticamente, la velocidad viene dada por la fórmula;

\( Velocidad = \frac{distancia}{tiempo}\)

Sustituyendo en la fórmula anterior;

\( Velocidad = \frac{900}{170}\)

Velocidad = 5.29 m/s

Por lo tanto, la velocidad promedio del automóvil es 5.29 metros por segundo.

Answer:

Option D. 6.1 m/s²

Explanation:

We'll begin by calculating the acceleration due to gravity in each case. This is illustrated below:

1. For Rock:

Mass (m) = 20 g

Force (F) = 0.1224 N

Acceleration due to gravity (g) =?

Next, we shall convert 20 g to kg. This can be obtained as follow:

1000 g = 1 kg

Therefore,

20 g = 20/1000

20 g = 0.02 kg

Finally, we shall determine the acceleration due to gravity as follow:

Force of gravity (F) = mass (m) x Acceleration due to gravity (g)

F = mg

Mass (m) = 0.02 kg

Force (F) = 0.1224 N

Acceleration due to gravity (g) =?

F = mg

0.1224 = 0.02 × g

Divide both side by 0.02

g = 0.1224/0.02

g = 6.12 m/s²

2. For Grain of sand:

Mass (m) = 0.8 g

Force (F) = 0.00501 N

Acceleration due to gravity (g) =?

Next, we shall convert 0.8 g to kg. This can be obtained as follow:

1000 g = 1 kg

Therefore,

0.8 g = 0.8/1000

0.8 g = 0.0008 kg

Finally, we shall determine the acceleration due to gravity as follow:

Force of gravity (F) = mass (m) x Acceleration due to gravity (g)

F = mg

Mass (m) = 0.0008 kg

Force (F) = 0.00501 N

Acceleration due to gravity (g) =?

F = mg

0.00501 = 0.0008 × g

Divide both side by 0.0008

g = 0.00501/0.0008

g = 6.26 m/s²

3. For Metal bolt:

Mass (m) = 79 g

Force (F) = 0.4871 N

Acceleration due to gravity (g) =?

Next, we shall convert 79 g to kg. This can be obtained as follow:

1000 g = 1 kg

Therefore,

79 g = 79/1000

79 g = 0.079kg

Finally, we shall determine the acceleration due to gravity as follow:

Force of gravity (F) = mass (m) x Acceleration due to gravity (g)

F = mg

Mass (m) = 0.079 kg

Force (F) = 0.4871 N

Acceleration due to gravity (g) =?

F = mg

0.4871 = 0.079 × g

Divide both side by 0.079

g = 0.4871/0.079

g = 6.17 m/s²

From the above calculation we obtained the following values for acceleration due to gravity (g):

Object >>>> Acceleration due to gravity

Rock >>>>> 6.12 m/s²

Sand >>>>> 6.26 m/s²

Metal >>>>> 6.17 m/s²

Thus, closest approximation of the acceleration due to gravity of the planet is 6.1 m/s²

The coefficient of static friction is usually larger than the coefficient of kinetic friction, meaning it takes more force to get an object moving than to keep it moving.

For most surfaces, the coefficient of static friction is greater than the coefficient of kinetic friction.

The coefficient of static friction is the amount of force required to move an object that is initially at rest relative to a surface. This force is usually greater than the force required to keep the object moving, which is the coefficient of kinetic friction. This is because the static force must overcome the resistance of the surface, while the kinetic force is used to maintain the object's relative motion. This is why it takes more effort to start an object moving than to keep it going.

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Answer:

jhnnmhunn vgu fhbiy f

Explanation:

hjbgyvfvubhjgvg

Answer:10 kg

Explanation: momentum p = mv and m = p/v

Mass m = 2000 kgm/ s / 200 m/s

Answer:

M a = (M1 + M2) a = F         Newton's Second Law

F = (M2 - M1) g         net force on the system

a = (M2 - M1) / (M1 + M2) g

a = (9 - 7) / (9 + 7) g = 2 / 16 * 10.0 m/s^2 = 1.25 m/s^2

We will have the following:

First, we determine the time it takes for the motorcycle to traverse the 40 m:

Now, we will use the time to determine the height of the ramp:

So, the ramp was located 0.784 meters in height.

The cylinder would need to rotate at an angular speed of 1.44 x 10^-3 rad/s

To calculate the required angular speed of cylinder, we can use the following formula:

a_c = v^2 / r

where a_c is  centripetal acceleration, v is  linear speed, and r is the radius of the cylinder.

First, we can determine the free-fall acceleration on Earth, which is approximately 9.81 m/s^2.

20.0 miles = 32,186.88 meters, and 3.71 miles = 5,972.64 meters.

a = ω^2r,

Setting  centripetal acceleration equal to  free-fall acceleration, we have: \(9.81 m/s^2 = \omega^{2}(2,986.32 m)\)

ω = \(1.44 * 10^{-3} rad/s\)

Therefore, the cylinder would need to rotate at angular speed of 1.44 x 10^-3 rad/s to have the same centripetal acceleration at its surface as the free-fall acceleration on Earth.

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If you increase the initial position from which you drop the ball, the following changes:Time of flight will increase, Initial velocity will increase, Final velocity will increase, Final position will change, Acceleration will remain constant as long as the planet's mass and radius do not change.

QUESTION 3: Based on observations in the prelab, the size of the ball does not have any effect on the acceleration.

QUESTION 4: Based on observations in the prelab, the planet's mass has an effect on the acceleration. The more massive the planet, the greater the acceleration.

QUESTION 5: Based on observations in the prelab, the planet's radius has an effect on acceleration. The larger the planet, the greater the acceleration.

QUESTION 6: Based on observations in the prelab, the mass of the ball has an effect on the acceleration. The more massive the ball, the greater the acceleration.

QUESTION 7: The set of modified kinematic equations that best represent the experiment that will be performed is Vf = Vo + gt, d = Vit + 1/2 gt², Vf² = Vo² + 2gd.

QUESTION 8: The best choice to plot on the y-axis for the equation 0-yo+ • fogt is Oy.

QUESTION 9: When a standard Cartesian coordinate system is set up with the origin on the ground directly below the release point, all of the following quantities are going to be measured: Initial position, final position, initial velocity, final velocity, acceleration, and time of flight.

QUESTION 10: If the following equation is used to analyze the data from a graph: o-yo + 1/2 ayt², the best choice to plot on the x-axis to obtain a linear graph is ot.

QUESTION 11: After graphing the data, g will be found by taking the slope of the line. Therefore, the slope will be -9.8..

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The compression in the spring will be 4.9m

What is spring force?

The force needed to compress or extend a spring attached to an object is known as the spring force. A spring exerts an equal and opposite force on a body when the object exerts a force on it. It always acts to bring mass back to its equilibrium. Spring force exerted by the spring on the body is given by = where k is the spring constant of the spring x is the compression or extension caused in the spring. To find the x we can use this formula.

Now, according to the question we have

Spring constant=2000N/m

Mass attached to the spring=1000Kg

On substituting the values in the above formula, we get the compression as

F=kx

mg=kx

1000×9.8=2000×x

x=4.9m

Therefore, the compression in the spring is 4.9m

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By using the RAMP acronym, the students can examine and manage the risks connected with their diluting concentrated acid approach, resulting in a safer and more regulated experimental process.

To assess the risk of their planned procedure using the RAMP acronym, the best assessment for each letter would be as follows:

R - Recognize hazards: The students should identify and acknowledge any potential hazards associated with diluting concentrated acid.

A - Assess risks: The students should evaluate the risks associated with the procedure. This involves considering the probability and potential consequences of accidents or mishaps, such as acid splashes, improper handling, or inhalation of fumes.

M - Minimize risks: The students should take measures to minimize the identified risks. This includes implementing safety protocols and precautions.

P - Prepare for emergencies: The students should be prepared to respond to any potential emergencies or accidents that may occur during the procedure.

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A) I_t = I_i, C) 0.33 m, A) 0.53 times 10^-2 s

For the first question:

The correct expression for the transmitted intensity of an unpolarized beam of light passing through a polarizer is:

A) I_t = I_i

When an unpolarized light beam passes through a polarizer, the transmitted intensity is equal to the incident intensity. This means that the intensity of the light remains unchanged after passing through the polarizer.

For the second question:

The associated wavelength of a cell phone signal operating at 900 MHz can be calculated using the formula: wavelength = speed of light / frequency.

The speed of light is approximately 3.0 x 10^8 m/s.

Calculating the wavelength:

wavelength = (3.0 x 10^8 m/s) / (900 x 10^6 Hz)

wavelength = 3.33 x 10^-1 m

Therefore, the correct answer is:

C) 0.33 m

The wavelength of the cell phone signal is 0.33 meters.

For the third question:

To calculate the time it takes for a light signal to travel from one planet to another, we need to divide the distance between the two planets by the speed of light.

Calculating the time:

time = distance / speed of light

time = (1.6 x 10^6 m) / (3.0 x 10^8 m/s)

time = 5.33 x 10^-3 s

Therefore, the correct answer is:

A) 0.53 times 10^-2 s

The time for the light signal to travel from one planet to the other is 0.53 times 10^-2 seconds.

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Immiscible liquids are those which won't mix to give a single phase. Oil and water are examples of immiscible liquids - one floats on top of the other. It explains the background to steam distillation and looks at a simple way of carrying this out.

to find the modulus of elasticity MoE at 23% of moisture content based on the already given modulus of elasticity of 12% moisture content we need to consider a shrinkage behavior of material. the expected MoE comes out to be approximately \(6,836 N/mm².\)

given information:

Modulus of elasticity at 12% moisture content =7,920 N/mm²

resultant shrinkage or final shrinkage percentage FSP = 30%

To calculate the expected MoE at 23% moisture content we have the following equation:

MoE-23% =   \(MoE-12%\) \((1 - FSP (23 - 12) / (100 - 12))\)

MoE-23% = \(7,920 N/mm² × (1 - 0.30 × (23 - 12) / (100 - 12))\)

MoE-23% =\(7,920 N/mm² × (1 - 0.30 × 11 / 88)\)

MoE-23% = \(7,920 N/mm² × (1 - 0.1364)\)

MoE-23% = \(7,920 N/mm² × 0.8636\)

MoE-23% =  \(6,836 N/mm²\)

therefore the expected modulus of elasticity at 23% moisture content comes out to be approx \(6,836 N/mm²\).

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According to question, the correct matching of oscillations is A - B, B-C, C -B, D-B and E-B .

T = 2 Square root of L/g, where L is the pendulum's length and g is the acceleration brought on by gravity, is the formula for a pendulum's period.

The time it takes a body to make one complete to and from movement is the period of oscillation for that body. (ii) The acceleration of free fall caused by gravity is the rate at which a body's velocity increases over time as a result of the earth's gravitational pull when it is falling under its own weight (alone).

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The correct question is :

Figure Q14.24 represents the motion of a mass on a string. A What is the period of the oscillations?

A 12 S

B 24 S

C 36 S

D 48 S

E 50S

B What is the amplitude of the oscillation?

a 1.0 cm

b 2.5 cm

c. 4.5 cm

D 5.0 cm

E 9.0 Cm

The relationship between kinetic energy and speed is directly proportional.

The given problem is based on the Kinetic energy. The energy possessed by any object by virtue of its motion is known as kinetic energy of an object. The mathematical expression for the kinetic energy is given as,

\(KE = \dfrac{1}{2}mv^{2}\)

Here,

m is the mass of object.

v is the speed of object.

the mass of any object remains constant. Then, the kinetic energy is given as,

\(KE \propto v^{2}\)

Thus, we can conclude that the kinetic energy is directly proportional to the square of speed of object.

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Over the elastic range, the deformation of a spring is directly proportional to: B. the applied force.

Hooke's law states that the deformation (strain) of a spring is directly proportional to the applied force (stress) within the elastic range of the spring.

According to Hooke's law, the applied force affects the motion of an object attached to the end of a horizontal spring on a frictionless horizontal track.

Mathematically, Hooke's law force is modeled by this mathematical expression:

F = -kx

Where:

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Answer:

in the nucleus of the atom

Explanation:

a p 3 x

During sewer pipe installation using a laser, a laser beam is projected through the pipe until it hits a target beam(c).

The target beam acts as a reference point or marker that helps align the pipe correctly during installation. By hitting the target beam, the laser beam indicates the desired direction and position for the pipe, ensuring accurate installation.

The target beam is often placed at the other end of the pipe or at specific intervals along the pipe's path, allowing the construction crew to adjust the alignment and slope as necessary. This process helps ensure the proper installation of the sewer pipe, minimizing potential issues and ensuring efficient drainage.

So c is correct option.
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(A) This box glides, then slides up to 4.74 m before stopping . (B) The friction coefficient at the point of halting is 0.537. (C) The box would have slid 101.25 meters before coming to a stop if the coefficient of friction had stayed unchanged.

To solve this problem, we can use the work-energy theorem, which states that the net work done on an object is equal to its change in kinetic energy:

Net work = ΔK.E.

We can break the motion of the box into two parts: before and after the rough section. Before the rough section, the box is moving with a constant velocity, so the net work done on it is zero. After the rough section, the box slows down and comes to a stop, so the net work done on it is equal to its initial kinetic energy:

Net work = -K.E.

(A) To find how far the box slides before stopping, we need to find the distance over which the box is acted upon by the increasing frictional force. Let's call this distance x.

W (friction) = ∫₀ˣ F f(x') dx'

here,

F f(x') is frictional force at a distance x' from point P.

Since the coefficient of friction increases linearly with distance, we can express F f(x') as:

F f(x') = μ₀ + (μ f - μ₀) * (x'/x f)

here,

μ₀ is initial coefficient of friction at point P,

μ f is final coefficient of friction at distance x f = 12.5 m, and

x' ranges from 0 to x.

Reserving expression of F f(x') into the integral for W (friction):-

W (friction) = μ₀ * x + (μ f - μ₀) * (x²/2x f)

Express initial kinetic energy as:-

K.E. = (1/2) * m * v²

here,

m is mass of the box and

v is its initial velocity of 4.50 m/s.

Setting the net work equal to the change in kinetic energy:-

= μ₀ * x + (μ f - μ₀) * (x²/2x f)

= (1/2) * m * v²

= x² - 2x f * [(μ f - μ₀)/μ₀] * x - 2x f * (K.E./(μ₀ * m))  

= 0

Putting given values of μ₀, μ f, x f, m, and v:-

x = 4.74 m

Therefore, the box slides for a distance of 4.74 m before coming to a stop.

(B) To find the coefficient of friction at the stopping point, we can use the same equation we derived earlier for W (friction) and solve for μ f:-

= W (friction)

= μ₀ * x + (μ f - μ₀) * (x²/2x f)

= -K.E.

= μ f

= (2 * K.E. + μ₀ * x * (μ f - μ₀)/x f) / x²

Putting given values of K.E., μ₀, μ f, x f, and x:-

μ f = 0.537

Therefore, the coefficient of friction at the stopping point is 0.537.

(C)  If the coefficient of friction remained constant at μ₀ = 0.1000, then we can simplify the equation we derived for x by setting μ f = μ₀:

= μ₀ * x + (μ₀ - μ₀) * (x²/2x f)

= (1/2) * m * v²

Simplifying the second term:-

μ₀ * x = (1/2) * m * v²

Solving for x:-

x = (m * v²) / [2 * μ₀ * W (friction)]

here,

W (friction) is work done by friction.

To find W (friction), we can integrate the frictional force over the entire distance traveled by the box:-

= W (friction)

= ∫₀ˣ F f(x') dx'

here,

F f(x') is constant frictional force of μ₀.

Reserving this expression for W friction into the equation for x:-

x = (m * v²) / (2 * μ₀ * F f * x)

here,

F f is constant frictional force of μ₀.

Simplifying:-

x = (m * v²) / (2 * μ₀ * F f)

Putting given values of m, v, μ₀, and F f:-

x = 101.25 m

Therefore, if the coefficient of friction had remained constant at μ₀ = 0.1000, the box would have slid for a distance of 101.25 m before coming to a stop.

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