Which two tundra ecosystems are very similar in terms of weather and terrain?
Aztec
Arctic
alpine
Antarctic

Answer:

your answer is 11

Explanation:

Answer:

C

Explanation:

a parallel circuit because there is more than one path

Answer:

C) a parallel circuit because there is more than one path

Explanation:

EDGE 2022

According to the statement, If a force 1.21 x 103 N is needed to bring a car moving at 22.0 m/s to a halt in 20.0 s then the mass of the car is 1.10 x 10³ kg.

The push or draw motion is the simplest definition of force. Contact forces and non-energies are two different kinds of forces. Nuclear force, gravitational force, mechanical force, electrostatic force, electrical force, spring force, and others are a few instances of forces.

According to formula

force = mass x acceleration

When the car is brought to a halt, its final velocity is 0 m/s.

[(Final velocity) – (Initial velocity)] / Time = acceleration

acceleration = (0 - 22.0 m/s) / 20.0 s

acceleration = -1.10 m/s²

Note that we have used a negative sign because the acceleration is opposite to the direction of the initial velocity.

1.21 x 10³ N = mass x (-1.10 m/s²)

mass = 1.21 x 10³ N / (-1.10 m/s²)

mass = -1.10 x 10³ kg

The negative mass value doesn't make sense physically, so we need to use the absolute value:

mass = 1.10 x 10³ kg

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The value of frictional force is 45.6 N

The amount of resistance a steel box experiences when traveling over a steel surface

μ = 0.80

the frictional force is a result

f = μ N

= 0.80\(\times\) 57

= 45.6 N

The force that prevents motion when the surfaces of two objects come into contact is known as friction. Friction lessens a machine's mechanical advantage, or, to put it another way, friction decreases the output-to-input ratio.

A car spends one-fourth of its energy-reducing friction. However, friction in the clutch and the tires also contribute to the vehicle's ability to maintain its position on the road.

One of the most important phenomena in the physical universe is friction, which affects everything from machinery to molecular structures to matches.

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We are given two vectors and we are asked to determine the direction of their sum. To do that we will rewrite them on coordinates form. For vector A, since it is a horizontal vector it only has an x-coordinate equivalent to its magnitude, like this:

For vector B we will use the following formula:

Replacing the values:

Solving the operations

1. To find the time when the body reaches the ground, we can use the vertical motion equation:

h = v₀y * t + (1/2) * g * t²

where:

h = height of the tower = 15m

v₀y = initial vertical velocity = v₀ * sin(θ) = 30m/s * sin(30°)

g = acceleration due to gravity = 9.8m/s²

t = time

Plugging in the values:

15 = (30 * sin(30°) * t) + (0.5 * 9.8 * t²)

Simplifying the equation:

15 = 15t * 0.5t² + 4.9t²

Combining like terms:

15 = 7.5t² + 4.9t²

Simplifying further:

15 = 12.4t²

Dividing both sides by 12.4:

t² = 15 / 12.4

Taking the square root of both sides:

t = √(15 / 12.4)

Calculating the value:

t ≈ 1.01 seconds

Therefore, the time it takes for the body to reach the ground is approximately 1.01 seconds.

2. To find the displacement vector, we need to calculate the horizontal and vertical components separately.

Horizontal component:

The horizontal displacement can be calculated using the formula:

x = v₀x * t

where:

v₀x = initial horizontal velocity = v₀ * cos(θ) = 30m/s * cos(30°)

t = time is taken to reach the ground (previously calculated as approximately 1.01 seconds)

Plugging in the values:

v₀x = 30m/s * cos(30°)

t = 1.01 seconds

Calculating the value:

v₀x ≈ 26.02 m/s

Vertical component:

The vertical displacement can be calculated using the formula:

y = v₀y * t + (1/2) * g * t²

where:

v₀y = initial vertical velocity = v₀ * sin(θ) = 30m/s * sin(30°)

g = acceleration due to gravity = 9.8m/s²

t = time is taken to reach the ground (previously calculated as approximately 1.01 seconds)

Plugging in the values:

v₀y = 30m/s * sin(30°)

t = 1.01 seconds

Calculating the value:

v₀y ≈ 15 m/s

Now we have the horizontal and vertical components of the displacement vector:

Horizontal component: x ≈ 26.02 m/s

Vertical component: y ≈ 15 m/s

Therefore, the displacement vector of the body is approximately (26.02 m/s, 15 m/s).

3. To find the angle when the body hits the ground, we can use the vertical and horizontal components of the velocity.

The horizontal component of the velocity, v₀x, can be calculated using the formula:

v₀x = v₀ * cos(θ)

where:

v₀ = initial velocity = 30m/s

θ = angle of projection = 30 degrees

Plugging in the values:

v₀x = 30m/s * cos(30°)

Calculating the value:

v₀x ≈ 26.02 m/s

The vertical component of the velocity, v₀y, can be calculated using the formula:

v₀y = v₀ * sin(θ)

where:

v₀ = initial velocity = 30m/s

θ = angle of projection = 30 degrees

Plugging in the values:

v₀y = 30m/s * sin(30°)

Calculating the value:

v₀y ≈ 15 m/s

Now, to find the angle when the body hits the ground, we can use the inverse tangent function:

θ = arctan(v₀y / v₀x)

Plugging in the values:

θ = arctan(15 m/s / 26.02 m/s)

Calculating the value:

θ ≈ 30.96 degrees

Therefore, the angle when the body hits the ground is approximately 30.96 degrees.

4. To find the maximum height, we can use the vertical motion equation:

h = v₀y² / (2 * g)

where:

h = maximum height

v₀y = initial vertical velocity = v₀ * sin(θ) = 30m/s * sin(30°)

g = acceleration due to gravity = 9.8m/s²

Plugging in the values:

h = (30 * sin(30°))² / (2 * 9.8)

Calculating the value:

h ≈ 27.55 meters

Therefore, the maximum height reached by the body is approximately 27.55 meters.

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In order to determine the signs of the changes in entropy (ΔS) and enthalpy (ΔH) for physical changes in a closed or isolated system, more specific information regarding the nature of the physical changes is needed. The signs of ΔS and ΔH can vary depending on the specific process occurring.

In general terms, if a physical change leads to an increase in disorder or randomness in the system, the change in entropy (ΔS) would be positive. On the other hand, if the physical change results in a decrease in disorder or an increase in orderliness, ΔS would be negative.

Regarding enthalpy (ΔH), if the physical change involves an exothermic process, where heat is released from the system to the surroundings, ΔH would be negative. Conversely, in an endothermic process, where heat is absorbed by the system from the surroundings, ΔH would be positive.

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Answer:

Explanation:you knoe i know

The flow speed of the ideal fluid in the wider section is 6 m/s.

The flow speed of the ideal fluid in the wider section is calculated by applying continuity equation as shown below.

A₁V₁  =  A₂V₂

Where;

πr₁²V₁² = πr₂²V₂²

r₁²V₁² = r₂²V₂²

V₂² = r₁²V₁² / r₂²

Where;

V₂² = r₁²V₁² / r₂²

V₂² = ( r₁²V₁²) / (2r₁)²

V₂² = ( r₁²V₁²)/(4r₁²)

V₂² = (V₁²)/(4)

V₂² = (12²)/4

V₂² = 36

V₂ = √36

V₂ = 6 m/s

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Answer:

When unbalanced forces act on an object at rest, the object will move. ... Second, when unbalanced forces act on a moving object, the velocity of the object will change. Remember that a change in velocity means a change in speed, direction or both speed and direction.........Eg.If you kick a football and it moves from one place to another, it means that unbalanced forces are acting upon it. Ball moves from one place to another after kicking it.

Answer:

unbalanced forces could change speed,direction

Explanation:

Example

if two people are pulling a rope and the other one is stronger the rope moves toward the stronger one cause the force is unbalanced

Answer:

m1 * m2) / r^2)

Where F is the gravitational force, G is the gravitational constant (6.67 x 10^-11 N*m^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between them.

In this case, the mass of the satellite is 2300 kg and the mass of Earth is 5.97 x 1024 kg. The distance between the satellite and Earth's surface is 5400 m.

Plugging these values into the formula, we get:

F = (6.67 x 10^-11 N*m^2/kg^2) * ((2300 kg * (5.97 x 1024 kg)) / (5400 m)^2)

F = (6.67 x 10^-11 N*m^2/kg^2) * ((136510000000000 kg^2) / (291600 m^2))

F = 3.34 x 10^-4 N

Therefore, the gravitational force between the satellite and Earth is approximately 3.34 x 10^-4 N.

Answer:

22487.9N

Explanation:

Any two objects of sufficient mass experience a gravitational pull or force between them that is dependant on their masses and how far away they are from each other. The formula for the gravitational force between two objects is:

\(F=G\frac{m_{1} m_{2} }{r^{2} }\)

where F is the gravitational force, G is the gravitational constant (equal to 6.67x\(10^{-11}\)), \(m_{1}\) and \(m_{2}\) are the masses of the two objects and r is the distance between their centres.

We know the satellite is 5400m above the earth surface, but we need to know the distance between their centres, not between their surfaces. To do this, we usually add the radius of each object to the distance between their surfaces, but since the satellite's radius is likely so small that it's negligible, we can just add Earth's radius, which is 6,371 km:

5400+6371000=6376400m

We know the value fo G because it's a constant, we are given the masses of the earth and the satellite (5.97x\(10^{24}\)kg and 2300kg respectively), and we now know the distance between their centres (6376400m). Now we can sub these values into our formula to find the gravitational force:

\(F=G\frac{m_{1} m_{2} }{r^{2} }\)

\(F=(6.67*10^{-11} )\frac{(2300) (5.96*10^{24} ) }{6376400^{2} }\)=22487.89596N

Answer:

The correct option is;

The index of refraction of the second medium is lower

Explanation:

The index of refraction of a material indicates the magnitude of the optical density of a material. The index of refraction or the refractive index, n, are indices (ratio) of the speed of light through an optically dense medium relative to the speed of light through a vacuum.

The definition of the refractive index is the number of times light travelling through a medium would be slower than light travelling through vacuum

Therefore, the index of refraction of a second medium that is less optically dense than a first medium from which light originates and travels through it would be lower than the index of refraction of the first medium

Answer:

i have no idea

Explanation:

Answer:

Specific heat capacity, = 1.2942 J/g°C

Explanation:

Given the following data;

Heat capacity = 685 J

Mass = 7.9 g

Initial temperature = 31°C

Final temperature = 98°C

To find the specific heat capacity of the substance;

Heat capacity is given by the formula;

\( Q = mcdt\)

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 98 - 31

dt = 67°C

Making c the subject of formula, we have;

\( c = \frac {Q}{mdt} \)

Substituting into the equation, we have;

\( c = \frac {685}{7.9*67} \)

\( c = \frac {685}{529.3} \)

Specific heat capacity, = 1.2942 J/g°C

If instead of dropping the mass, we had started with the mass moving up (from an initial push on the glider), and recorded until it stopped. The different manifestations of systemic errors are error due to Initial Push,  friction, external influences and measurement techniques.

If instead of dropping the mass, we start with the mass moving up (from an initial push on the glider) and record until it stops, it can introduce different manifestations of systemic errors compared to the scenario where the mass is dropped.

1. Error due to Initial Push: When the mass is pushed up initially, there might be inconsistencies or variations in the magnitude and direction of the applied force. These variations can affect the recorded data, such as the time it takes for the mass to stop or the distance it travels.

2. Error due to Friction: Friction plays a significant role in slowing down the mass. As the mass moves upwards, there will be frictional forces acting against its motion. The magnitude of these frictional forces can vary depending on factors like surface roughness, lubrication, and other environmental conditions. This can lead to inconsistencies in the recorded data, such as variations in the deceleration rate or the distance travelled before stopping.

3. Error due to External Influences: The mass is subjected to different external influences compared to when it is dropped. Factors like air resistance, vibrations, or disturbances from the pushing mechanism can affect the motion of the mass. These external influences can introduce uncertainties and inconsistencies in the recorded data.

4. Error due to Measurement Techniques: The methods used to measure the time, distance, or other parameters can introduce errors. For example, timing inaccuracies, parallax errors in reading distance, or limitations in the precision of measuring devices can impact the accuracy of the recorded data.

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The sound intensity level of 100 physics professors talking simultaneously is equal to 72 decibel.

Given the following data:

Sound intensity can be defined as a measure of the power of a sound wave per unit area. Thus, sound intensity is a quantity that can be used to measure the energy of sound and its unit of measurement is Watts per square meter.

Mathematically, sound intensity level is given by this formula:

\(\beta = 10 log(\frac{I}{I_{ref}} )\)

Note: The reference value of sound intensity is equal to \(1.0 \times 10^{-12}\;W/m^2\)

Thus, the sound intensity for one (1) professor is given by:

\(I_1 = 1.0 \times 10^{-12} \times 10^{5.2}\\\\I_1=1.585 \times 10^{-7}\;W/m^2\)

For 100 professors, the sound intensity is:

\(I_{100} = 1.585 \times 10^{-7} \times 100\\\\I_{100}=1.585 \times 10^{-5}\;W/m^2\)

Substituting the parameters into the formula, we have;

\(\beta = 10 log(\frac{1.585 \times 10^{-5}}{1.0 \times 10^{-12}})\\\\\beta = 10 log(15.58 \times 10^{6})\\\\\beta = 10 \times 7.2\\\\\beta =72\;dB\)

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Complete Question:

One physics professor talking produces a sound intensity level of 52 dB. It's a frightening idea, but what would be the sound intensity level of 100 physics professors talking simultaneously?

Answer:

72dB

Explanation:

The sound intensity level of one prof is given, that's your β1 (which is equal to 52dB).

Using the sound intensity level formula:

β1= 10log (\(\frac{I}{I_{o} }\)) = 52 dB

*This will be useful later on [even if β1 is known]

Set up the formula for β2 (β2 is going to be the new sound intensity, the one for the 100 profs):

β2 = 10 log( \(\frac{ 100 I}{I_{o} }\) )

*You need to multiply the intensity of one professor by 100 (because now there's more)

*do some algebra- pull out the 100

β2  = 10 log (100 \(\frac{I}{I_{o} }\))

*use log laws

β2 = 10 ( log(100) + log (\(\frac{I}{I_{o} }\)) )

*Now, isn't there a familiar part? Well, yes! The expression for β1!

β2 = 10log(100) + β1

β2 = 10log(100) + 52dB

*use your calculator

β2 = 73dB

^^^ that's your new sound intensity level

The linear velocity of the car whose wheel is revolving at 392 revolutions per minute with a radius of 27 inches is 62.93 miles per hour.

Given the radius of wheel (r) = 27 inches

revolutions per minute (n) = 392 = 392x60 = 23520 rev/hour

Circumference of the wheel (d) = 2π(27) = 169.56 inches

Convert to miles as = 169.56/12 = 14.13ft = 14.13/5280 = 0.002676miles

Let the linear velocity be = V

We know that V = d x n

V =  0.002676 x 23520 = 62.93 miles per hour

Hence the linear speed of the car is 62.93 miles per hour

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Using a cable with a tension of 1350 N , a tow truck pulls a car 5.00 km alone a horizontal roadway. Therefore,

(a) Cable work: 6,750,000 J horizontally.

(b) Cable work: 6,308,250 J at 35.0° above horizontal.

(c) No work by gravity.

To calculate the work done by the cable in each scenario, we need to consider the angle between the direction of the force applied and the displacement.

(a) If the cable pulls horizontally (0° above the horizontal):

In this case, the angle between the force and the displacement is 0 degrees, so the work done can be calculated as:

Work = Force * Displacement * cos(Ф)

Work = 1350 N * 5000 m * cos(0°)

Work = 1350 N * 5000 m * 1

Work = 6,750,000 J

The cable does 6,750,000 Joules of work on the car when it pulls horizontally.

(b) If the cable pulls at 35.0 degrees above the horizontal:

In this case, the angle between the force and the displacement is 35.0 degrees, so the work done can be calculated as:

Work = Force * Displacement * cos(Ф)

Work = 1350 N * 5000 m * cos(35.0°)

Work = 1350 N * 5000 m * 0.819

Work = 6,308,250 J

The cable does approximately 6,308,250 Joules of work on the car when it pulls at 35.0 degrees above the horizontal.

(c) The work done by gravity on the car is zero because gravity acts vertically downward, perpendicular to the displacement along the horizontal roadway. Therefore, the gravitational force does not contribute to the work done on the car in this scenario.

In both cases (a) and (b), the cable does the same amount of work on the tow truck as on the car since they are connected by the cable. So the work done by the cable on the tow truck would be equal to the values calculated above: 6,750,000 J in case (a) and 6,308,250 J in case (b).

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A measure of the speed with which perspiration is drawn from the skin's surface to the fabric's surface so it can evaporate, cool the body, and keep the wearer dry is called Moisture Wicking.

The term you are looking for to describe the measure of the speed at which perspiration is drawn from the skin's surface to the fabric's surface so it can evaporate, cool the body, and keep the wearer dry is called "Moisture Wicking."

Moisture wicking is a key property of many athletic and performance fabrics, allowing them to effectively manage sweat during physical activity. This process helps to maintain a comfortable body temperature and prevents discomfort caused by damp clothing.

The process of moisture-wicking involves several steps:

1. Perspiration is produced by the body to regulate its temperature.
2. The moisture-wicking fabric, usually made of synthetic materials like polyester or polypropylene, comes in contact with the skin and draws the sweat away from the body.
3. The fabric's surface area and the spaces between fibers allow the moisture to spread out, increasing the rate of evaporation.
4. As the moisture evaporates, it cools the body and helps maintain a comfortable temperature.
5. The fabric dries quickly, ensuring that the wearer remains comfortable and dry during physical activity.

In summary, moisture wicking is a crucial aspect of many performance fabrics, enabling them to efficiently manage sweat and maintain wearer comfort during physical activities.

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Pressure exerted by the wooden cube = 2 Pa

Surface area of cube = 5 cm² = 0.0005 m²

Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.

Formula of Pressure:

\( \boxed{ \bf{P = \dfrac{F}{A}}}\)

P → Pressure

F → Force

A → Surface Area

By substituting values in the formula, we get:

\( \rm \longrightarrow 2 = \dfrac{F}{0.0005} \\ \\ \rm \longrightarrow F = 2 \times 0.0005 \\ \\ \rm \longrightarrow F = 0.001 \: N \\ \\ \rm \longrightarrow F = 1 \: mN\)

\( \therefore \) Force applied by the cube on the floor = 1 mN

Answer:

−x direction decreasing in speed.

Explanation:

Hence, The provided capacitor must thus be linked in parallel with an 8F capacitor.

tanϕ= Xc −Xl/R

Xc = 1/ωC =500Ω

XL=ωL=100Ω

R=400Ω

Thus tanϕ= 400/400

​=1⟹ϕ=45∘

Power factor is given by cosϕ=1

⟹ϕ=0∘

⟹tanϕ=0

⟹Xc =XL

​=100Ω

⟹C=10μF

Hence, The provided capacitor must thus be linked in parallel with an 8F capacitor.

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It is obvious that the wing on the side with more ice stopping first is what produced the abrupt autorotative roll. The autopilot trimming the airplane towards the stall will make it difficult for them to recover from a spin.

Even a tiny coating of snow, ice, or frost on a plane's wings prevents takeoff since it can affect the mechanics of the aircraft. According to Nance, snow and ice on the wings might obstruct airflow. It changes the way the air flows across the wings.

This air slowing results in early air circulation separation across the impacted airfoil, which results in a reduction in lift. A thick layer of hard ice will increase stall speed by 5 to 10%. An airplane may be unable to take off normally or even land if there is even a slight quantity of frost on the airfoils.

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Triton, the largest moon of Neptune, is believed to have had an active past. The activity may have been powered by the tidal heating from Neptune. Tidal heating is a phenomenon in which the gravitational forces exerted by a planet cause heating in a moon's interior, creating a source of energy that can power geological activity.

There are several reasons why we suspect that Triton, Neptune's largest moon, has had an active past:

   Lack of craters: The relatively low number of craters on Triton's surface suggests that its surface has been modified or renewed over time. The presence of few craters indicates that geological processes have been active, such as volcanic activity or tectonic movements, which could have resurfaced or erased older crater features.

It's important to note that the exact mechanisms driving Triton's past or present activity are still under study and further exploration and research are needed to gain a deeper understanding of the moon's geological history and the specific energy sources at play.

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Create the Android App, set up the project, design the user interface, handle user input, perform calculations, and display the results.

Creating an Android App that calculates force and density can be done by following these steps:

Set up the project in Android Studio.

Design the layout of the user interface using XML, including TextViews, EditTexts, and a Button.

Define the necessary variables and views in the Java code.

Set an onClickListener for the button to perform the calculations.

Retrieve the user input from the EditText fields and convert them to appropriate data types.

Calculate the force using the formula F = ma and the entered mass and acceleration.

Display the calculated force in the result TextView.

Repeat steps 5-7 for calculating density if desired.

Run the app on an Android emulator or device to test its functionality.

The Simplifying User Input App developed in class can serve as a guide for implementing the user interface and handling user input.

You would need to modify the code to incorporate the force and density calculations based on the provided equations.

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Answer:

it takes 64 J of heat energy to heat 2 kg of lead from 265 K to 315 K.

Explanation:

To find out how much heat is needed to heat 2 kg of lead from 265K to 315 K, we can use the formula for specific heat capacity, which is:

q = mcΔT

Where:

q = heat energy (in joules)

m = mass of the substance (in kilograms)

c = specific heat capacity of the substance (in joules per kilogram per degree Celsius)

ΔT = change in temperature (in degrees Celsius)

The specific heat capacity of lead is 0.128 J/g°C. we need to convert it to J/kg°C

So, the heat energy needed is:

q = (2 kg)(0.128 J/kg°C)(315 K - 265 K)

q = (2 kg)(0.128 J/kg°C)(50 K)

q = 64 J

Therefore, it takes 64 J of heat energy to heat 2 kg of lead from 265 K to 315 K.

Answer:

Image result for What is meant by a 'closed system'?

A closed system is a physical system that does not allow transfer of matter in or out of the system, though, in different contexts, such as physics, chemistry or engineering, the transfer of energy

Explanation:

Answer:

A closed system is a physical system that does not allow transfer of matter in or out of the system, though, in different contexts, such as physics, chemistry or engineering, the transfer of energy is or is not allowed

Explanation: