Which type of isomers are dimethyl maleate and dimethyl fumerate? 1.Enantiomers. 2.Constitutional isomers 3.Diastereomers 4.They are conformational isomers and enantiomers. 5.They are constitutional isomers and diastereomers. 6.Conformational isomers 7.They are not isomers.

The correct formula for a compound formed from the elements Al and O is Al₂O₃.

Correct option is C.

Aluminum oxide is an oxide of aluminum with the chemical formula Al₂O₃ which is primarily composed of two chemically bonded aluminum and oxygen atoms. Aluminum oxide chemical compounds exist in various forms, with the most common being alpha, gamma, and theta.

The solid compound is an odorless, white powder which is insoluble in water and is a major component of the Earth's crust. It occurs naturally as corundum, bauxite, and cryolite and can be synthetically produced through burning aluminum metal or dissolving alumina tri-hydrate.

Aluminum oxide is widely used in a variety of applications due to its unique properties such as hardness, thermal conductivity, electrical conductivity, optical properties, and chemical inertness.

Correct option is C.

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To convert 1.709 x 10^(-5) cm³ to μm³, we need to know the conversion factor between cm³ and μm³.

1 cm is equal to 10,000 μm since 1 cm = 10 mm and 1 mm = 1000 μm. Therefore, 1 cm³ is equal to (10,000 μm)³.

Calculating the conversion factor:

(10,000 μm)³ = 1,000,000,000,000 μm³

Now, we can convert the given value:

1.709 x 10^(-5) cm³ * 1,000,000,000,000 μm³ / 1 cm³ = 1.709 x 10^(-5) x 1,000,000,000,000 μm³ / 1 = 1.709 x 10^7 μm³

Since the given value has 4 significant figures (1.709), we need to express the final answer with the same number of significant figures. Therefore, the converted value of 1.709 x 10^(-5) cm³ to μm³, with the correct number of significant figures, is approximately 1.709 x 10^7 μm³.

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If a saturated solution of a solute is made using 41.0 g of H2O at 20.0 °C, the amount of additional solute that can be added when the temperature is increased to 30.0 °C depends on the solubility of the solute. The solubility of most substances tends to increase with temperature, so more solute can be dissolved. The specific solubility data or a solubility curve is needed to determine the exact amount of additional solute that can be added.

When the temperature of a solvent increases, the solubility of many substances generally increases as well. This means that more solute can be dissolved in the solvent. However, the amount of additional solute that can be added when the temperature is increased from 20.0 °C to 30.0 °C depends on the solubility characteristics of the specific solute.

To determine the exact amount of additional solute that can be added, one would need to consult the solubility data or a solubility curve for the particular solute at different temperatures. These resources provide information on the maximum amount of solute that can be dissolved in a given amount of solvent at various temperatures. By referring to the solubility data, one can find the maximum solubility of the solute at 30.0 °C and calculate the difference between the currently saturated solution and the new solubility value to determine how much more solute can be added.

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Answer:

Testing prototypes is an inherent part of finalizing designs. Nobody wants to wonder why users are not utilizing an app the way it should be utilized or why they can’t seem to complete a purchase on your website. And nobody wants to rework something that’s already been shipped. 

Conducting tests as early as the prototyping stage can help you avoid these unfortunate scenarios. User research with Qualaroo can help you validate your current design and uncover new areas of focus for the next iteration. Use Qualaroo to understand how people use your interface early on in the design process and evolve your prototype into a working product faster.

moms home  a hole

hope your happy about the poop youve done

Answer:

C₂H6

Explanation:

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). Option A

A hydrocarbon is a compound that consists of only carbon and hydrogen atoms. It is important to identify the formula that represents a hydrocarbon among the given options:

A) C₂H6: This formula represents ethane, which is a hydrocarbon. Ethane consists of two carbon atoms bonded together with single bonds and six hydrogen atoms.

B) C₂H5OH: This formula represents ethanol, which is not a hydrocarbon. Ethanol contains a hydroxyl group (-OH), indicating the presence of oxygen in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

C) C₂H5Cl: This formula represents ethyl chloride, which is not a hydrocarbon. Ethyl chloride contains a chlorine atom (Cl) in addition to carbon and hydrogen atoms. It is a haloalkane, not a hydrocarbon.

D) C₂H6O: This formula represents ethanol, which, as mentioned before, is not a hydrocarbon. Ethanol contains an oxygen atom (O) in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). It consists only of carbon and hydrogen atoms, making it a suitable representation of a hydrocarbon.

In summary, the formula C₂H6 (option A) represents a hydrocarbon, while the other options contain additional elements (oxygen or chlorine) that make them non-hydrocarbon compounds. Option A

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The mass of water that can be made would be 36.03 grams.

From the balanced chemical equation:

1 mole N2H4 produces 4 moles H2O2

0.750 mole N2H4 will produce = 0.750 x 4/1 = 3.000 moles H2O2 (limiting reactant)

0.500 mole H2O2 is used, which is less than the amount produced by N2H4, so it is also a limiting reactant.

Now, we can use the mole ratio between H2O2 and H2O to calculate the moles of water produced:

1 mole H2O2 produces 4 moles H2O

0.500 mole H2O2 will produce = 0.500 x 4/1 = 2.000 moles H2O (limiting reactant)

Finally, we can use the molar mass of water to convert the moles of water to grams:

2.000 moles H2O x 18.015 g/mol = 36.03 g H2O

Therefore, 36.03 grams of water can be made from the given amounts of N2H4 and H2O2.

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Answer:

Solid turns to liquid and liquid to gas

Explanation:

ice cube to water, water to carbon

The solubility product constant expression for AgI is:

AgI(s) ⇌ Ag⁺(aq) + I⁻(aq)

The Ksp expression for AgI is given as 1.47 x 10⁻¹⁶.

Since AgI dissociates into 1 Ag⁺ ion and 1 I⁻ ion, the molar solubility (s) of AgI is equal to the concentration of Ag⁺ and I⁻ ions in the solution.

Let's assume the molar solubility of AgI is s M.

Since the molar solubility (s) of AgI is equal to the concentration of Ag⁺ and I⁻ ions, we have:

[Ag⁺] = s M

[I⁻] = s M

Using the stoichiometry of the balanced equation, the expression for the solubility product constant is:

Ksp = [Ag⁺][I⁻] = s^2

Substituting the given Ksp value, we have:

1.47 x 10⁻¹⁶ = (s)^2

Taking the square root of both sides, we get:

s = √(1.47 x 10⁻¹⁶)

Calculating the square root, we find:

s ≈ 3.83 x 10⁻⁹ M

Since the solubility is given in grams per milliliter (g/mL), we need to convert the molar solubility to grams per milliliter using the molar mass of AgI.

The molar mass of AgI is:

Ag: 107.87 g/mol

I: 126.90 g/mol

AgI: 107.87 g/mol + 126.90 g/mol = 234.77 g/mol

To convert the molar solubility (s) to grams per milliliter (g/mL):

s (g/mL) = (molar solubility (M) * molar mass of AgI (g/mol)) / 1000

Substituting the values, we have:

s (g/mL) = (3.83 x 10⁻⁹ M * 234.77 g/mol) / 1000

Calculating the value, we find:

s (g/mL) ≈ 9.0 x 10⁻¹² g/mL

Therefore, the solubility of silver iodide (AgI) in grams per milliliter (g/mL) at the given temperature is approximately 9.0 x 10⁻¹² g/mL.

The solubility of silver iodide (AgI) in grams per milliliter can be calculated using the concept of solubility product constant (Kₛₚ). Given that the Kₛₚ of AgI is 1.47 x 10⁻¹⁶.

The solubility product constant (Kₛₚ) is a measure of the equilibrium between a solid and its dissolved ions in a saturated solution. For silver iodide (AgI), the equilibrium equation can be expressed as:

AgI(s) ⇌ Ag⁺(aq) + I⁻(aq)

The Kₛₚ expression for this equilibrium is:

Kₛₚ = [Ag⁺][I⁻]

Given the Kₛₚ value of AgI as 1.47 x 10⁻¹⁶, it indicates that the product of the concentrations of Ag⁺ and I⁻ ions in the saturated solution is equal to 1.47 x 10⁻¹⁶.

To determine the solubility of AgI in grams per milliliter, we need to know the molar mass of AgI and the volume of the saturated solution. The molar mass of AgI is 234.77 g/mol, which is the sum of the atomic masses of silver (Ag) and iodine (I).

To convert the concentration of Ag⁺ or I⁻ ions to grams per milliliter, we need to divide the concentration (in moles per liter) by the molar mass (in grams per mole) and multiply by the solution volume (in milliliters).

However, without the given volume of the saturated solution, it is not possible to calculate the solubility in grams per milliliter directly using the Kₛₚ value. The solubility information typically depends on both temperature and the presence of other ions or substances in the solution. Therefore, additional data or an experimental approach would be needed to determine the solubility of AgI in grams per milliliter at the given temperature.

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Y-ray photons with a wavelength of 2.45×10-5 nm.  energy of photon is 8.11 × 10⁻¹²J.

given data is as follows :

wavelength = 2.45 × 10⁻⁵ nm

energy of photon is given by  the following formula , we get :

E = hf

where E = energy of photon

h = Planck constant = 6.63 × 10⁻³⁴ j.s

f = frequency

and frequency = c / λ

the formula will be:

E = h c / λ

c = speed of light = 3 × 10⁸ m/s

E = (6.63 × 10⁻³⁴ × 3 × 10⁸ ) / 2.45 × 10⁻⁵ × 10⁻⁹

E = 8.11 × 10⁻¹²J

Thus, Y-ray photons with a wavelength of 2.45×10-5 nm.  energy of photon is 8.11 × 10⁻¹²J.

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Answer:

From top to bottom coyote, crow, squirrel, then acorn

Explanation:

The coyote has the least amount of energy and its the biggest predator so it belongs at the top. The crows eat squirrels and the squirrels eat acorns.

Answer:

Icelandic water and geothermal power is harnessed to produce methanol.

Explanation:

When \(K_{3}PO_{4}\) dissolves in water, it dissociates into three \(K^{+}\) ions and one \(PO_{4} ^{3-}\) ion for each formula unit. So, for each formula unit of  \(K_{3}PO_{4}\), four ions are produced in total.

To determine the ions produced when  \(K_{3}PO_{4}\)dissolves into water and how many of each are produced for each formula unit of  \(K_{3}PO_{4}\), we need to examine the chemical formula.

\(K_{3}PO_{4}\) is potassium phosphate, which consists of 3 potassium (K+) ions and 1 phosphate (\(PO_{4} ^{3-}\)) ion. When \(K_{3}PO_{4}\)  dissolves in water, it dissociates into its ions.

For each formula unit of  \(K_{3}PO_{4}\) , the ions produced are:
- 3 potassium (\(K^{+}\)) ions
- 1 phosphate (\(PO_{4} ^{3-}\)) ion

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The isomer with the higher equilibrium vapor pressure at 20 celsius is the cis-isomer of 1,2-dichloroethene. This is because the cis-isomer has a more symmetrical structure, with the two chlorine atoms on the same side of the double bond, which allows for stronger intermolecular forces of attraction between molecules.

These stronger intermolecular forces lead to a higher boiling point and vapor pressure.
On the other hand, the trans-isomer has a less symmetrical structure, with the two chlorine atoms on opposite sides of the double bond, which leads to weaker intermolecular forces of attraction between molecules. As a result, the trans-isomer has a lower boiling point and vapor pressure than the cis-isomer.
Overall, the molecular structure of each isomer plays a critical role in determining its vapor pressure. The more symmetrical the structure, the stronger the intermolecular forces and the higher the vapor pressure. In this case, the cis-isomer has a more symmetrical structure and thus has a higher equilibrium vapor pressure at 20 celsius.

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Answer:

single replacement

Explanation: N/A

a)  The pressure can be found by rearranging the Ideal Gas Law equation and solving for P. b)  A straight line in the graph signifies that the reaction is of that particular order. c) we can find the rate constant using Rate = k[C₄H₆]ⁿ.

At 625 K, the compound C₄H₆ (1,3-butadiene) undergoes a reaction in a rigid vessel. Two trials with varying initial concentrations help determine the reaction rate. (a) To calculate the initial pressure in Trial 1, we need to use the Ideal Gas Law equation (PV = nRT) with the provided initial concentration and temperature (625 K). The pressure can be found by rearranging the equation and solving for P.

(b) Analyzing the data plotted in the graphs allows us to determine the reaction order with respect to C₄H₆. The graph with a linear relationship between the concentration of C₄H₆ and the rate of the reaction will indicate the order (zero, first, or second). A straight line in the graph signifies that the reaction is of that particular order.

(c) With an initial reaction rate of 0.0010 mol/L in Trial 1, the rate constant, k, can be calculated using the rate law equation: Rate = k[C₄H₆]ⁿ, where n is the reaction order obtained in part (b). By plugging in the values and solving for k, we can find the rate constant for the reaction at 625 K.

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Answer:

\(\%O=64.2\%\\\\\%Ni=35.8\%\)

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to tell that since the total mass is 16.50 g and 5.87 g correspond to nickel, then the mass of oxygen is:

\(m_O=16.50g-5.87g=10.63g\)

And therefore, the resulting percent composition turns out to be:

\(\%O=\frac{10.60}{16.50} *100\%=64.2\%\\\\\%Ni=\frac{5.87}{16.50} *100\%=35.8\%\)

Regards!

Percentage composition is the percentage of the mass of the individual element. The percentage composition of oxygen is 64.2% and of nickel is 35.8%.

Mass is the amount of weight occupied by the sample or an element in a compound or molecule.

Given,

The total mass of the compound = 16.50 gm

Mass of nickel = 5.87 gm

The mass of oxygen is calculated as: 16.50 - 5.87 = 10.63 gm.

The percentage composition of oxygen is calculated as:

\(\dfrac{10.60}{16.50} \times 100\% = 64.2\%\)

The percentage composition of nickel is calculated as:

\(\dfrac{5.87}{16.50} \times 100\% = 35.8\%\)

Therefore, the percentage of oxygen is 64.25% and of nickel is 35.8%.

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A probing question that lies within the scope of physics could be: "What is the nature of dark matter and dark energy, and how do they influence the expansion of the universe?

Dark matter and dark energy are hypothetical forms of matter and energy that are believed to exist based on their observed gravitational effects on galaxies and the expansion of the universe.

Dark matter is thought to be a type of matter that does not interact with light or other electromagnetic radiation, while dark energy is an unknown form of energy that is causing the universe to expand at an accelerated rate.

Exploring the nature of dark matter and dark energy falls under the purview of physics because it involves understanding the fundamental forces and particles that govern the behavior of the universe.

Physicists study these phenomena by analyzing the gravitational effects they have on visible matter, conducting experiments to detect dark matter particles, and developing theoretical models to explain their properties and interactions.

Addressing this probing question requires the application of various branches of physics, such as cosmology, astrophysics, particle physics, and quantum mechanics.

Researchers employ observational data, theoretical frameworks, and advanced technologies to investigate the nature and origin of dark matter and dark energy, contributing to our understanding of the fundamental nature of the universe and its evolution.

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Concentration - 3

Phase - 1

Catalyst - 4

Surface area - 2

Answer: Molar masses 40.8 and 100.1

Explanation:

Answer:

Radiometric dating

Explanation:

Radiometric dating would be the most effective way since it is a technique that can establish the age of objects older than a few thousand years.

Answer:

10.5 k.J.

Explanation:

Answer:

NA = 6.02214076×10^23 mol−1.

Explanation:

1 mole of helium gas contains 6.02 x10^23 helium atoms. So multiply this by 3 after solving the equation.

There are 1.8066 x 10 ^24 atoms in 3 moles of helium

1 mole of any substance is equal to 6.022 × 1023 atoms , This is called the  Avogadro's Number and it represents 12 grams of pure carbon.

Hence,

I mole of Helium = 6.022 × 1023 atoms

Therefore,  

3 moles of helium will be 3 x   6.022 × 1023 atoms

3 moles of helium =1.8066 x 10 ^24 atoms

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Answer:

3.5g

Explanation:

\(Density=\frac{mass}{volume}\\ Mass= Density X Volume\\Mass = 0.875 X 4.0\\Therefore, Mass = 3.5 g\)

Answer:

3.703703703703

Explanation:

If you have 56. 8 g of sulfur (S), then probably you have approximately 1.772 moles of sulfur.

To determine the number of moles of sulfur (S) from the given mass, first of all you need to divide the given mass by the molar mass of sulfur.

The molar mass of sulfur (S) is approximately 32.06 g/mol.

Using the given mass of sulfur:

Moles of sulfur (S) = Mass of sulfur / Molar mass of sulfur

Moles of sulfur (S) = 56.8 g / 32.06 g/mol

Moles of sulfur (S) ≈ 1.772 mol

Therefore, you have approximately 1.772 moles of sulfur.

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Answer:

Explanation:

1. 40.08 + 35.45(2) = 110.98

2. 14.01 + 1.01(5) + 16.00 = 35.06

3.  107.87 + 12.01(2) + 1.01(3) + 16.00(2) = 165.91

4. 137.33(3) + 30.97(2) + 16.00(8) = 601.93

5. 26.98(2) + 16.00(9) + 12.01(3) = 216.06

6. 65.39 + 14.01(2) + 16.00(6) = 189.41

Check me if I'm wrong.

Answer:

the ball will first change direction then change the direction and at last the ball will speed up until it falls to the ground.

Explanation:

Rodney hit a high fly ball over second base in a championship baseball game. Because the ball was also being acted on by the force due to gravity, the ball will first change direction then change the direction and at last the ball will speed up until it falls to the ground.

(force of gravity is exerted by the Earth on the object)

Answer:

10 moles

Explanation:

of moles = given mass /atomic mass = 280 g /28 g = 10 moles of Si atoms in 280g sample.

Answer:

10 moles

Explanation:

of moles = given mass /atomic mass = 280 g /28 g = 10 moles of Si atoms in 280g sample