while erp systems offer many competitive advantages to users, particularly those in upper management, a significant disadvantage is their

The percentage of atrazine in the soil phase is 1.35*10^-8

The percentage of atrazine in the soil phase is 1.45%

The percentage of atrazine in the fish phase is 6.7*10^-5

The partition coefficient for atrazine between water and organic carbon (Koc) can be calculated using the empirical equation provided is 0.006.

The Kow value is 1.499. The distribution coefficient is 0.066.

The concentration of atrazine in water will be;

= 0.027 / 2000000 × 10^-8

= 1.35 × 20^-8

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Answer:

technician b?

Explanation:

Summary:

Ergonomics can be used to improve a student’s ability to focus on learning for say, when writing a long essay. Ergonomics helps with keeping the wrists comfortable with an ergonomic writing utensil and not straining the back with a comfortable sitting position. It helps with eye strain, keeping students at a comfortable distance from the board. And it reduces distractions to improve focus.

Longer version:

Sitting posture is a very important ergonomic factor which could influence a student's focus. Bad sitting posture could be caused by the height of chair and the desk position. Bad sitting posture often affects a child's level of attention or focus. Hence, choosing a an appropriate table and chair combination for different height measures should be considered. The distance between students and the lecture board should be considered as students have varying preferences. Hence, taking note of a comfortable distance for each student is an important concept. The removal of distractive elements in the classroom environment is also an ergonomic concept which could improve focus. Therefore, the concept of ergonomics applied in classroom environment could help improve student's focus.

Answer: Comfortable Furniture, Lighting, Reduced Noise, Correct Posture.

Explanation:

In My opion Ergonomics can be used significantly in the classroom environment to improve a student's ability to focus on learning in the following ways;

Comfortable furniture: By providing comfortable furniture such as desks, chairs, and tables, the students will be able to focus on learning for a more extended period.

Lighting: Adequate lighting in the classroom is essential for students as it can prevent eye strain and headaches.

Reduced noise: An environment with reduced noise will help students concentrate better on their studies.

Correct posture: Ergonomics can be used to promote the right posture among students while studying. Poor posture can cause health issues such as backaches and neck pain, which can negatively affect a student's ability to focus on learning.

In conclusion, ergonomics can significantly improve a student's ability to focus on learning by providing comfortable furniture, adequate lighting, reduced noise, and promoting correct posture.

Answer: Kristin is currently modifying a newly discovered plastic material to work on a new lightweight lacrosse stick.

Explanation:

The main function of a materials engineer is to develop, study and test materials that are used on order to make different products.

Material engineer solve problems in other engineering fields, like electrical, aerospace, civil, mechanical, chemical, and nuclear.

From the information given in the question, the correct option is "Kristin is currently modifying a newly discovered plastic material to work on a new lightweight lacrosse stick."

Answer:

nice

Explanation:

Answer:

The 17 distinct years Mariah Carey has topped Billboard's Hot 100, spanning an historic four consecutive decades:

1990

1991

1992

1993

1994

1995

1996

1997

1998

1999

2000

2005

2006

2008

2019

2020

2021

All these three are a long-term environmental consequence:

Oil sands are a mixture of sand, water, and bitumen (oil that is too heavy or thick to flow on its own). Bitumen is so thick that it behaves similarly to cold molasses at room temperature. As a result, this resource is sometimes referred to as "tar sands," but that term is incorrect because bitumen and tar (asphalt) are distinct compounds. "Oil sands" correctly identifies the end product derived from bitumen: crude oil.

The oil sands of Canada are the world's largest crude oil deposit. The oil sands (or tar sands, as they are sometimes incorrectly referred to) are a mixture of sand, water, clay, and a type of oil known as bitumen. We can recover oil from the oil sands thanks to innovation and technology, ensuring energy security in the future.

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Answer:

b

Explanation:

Answer:

b

Explanation:

Answer: True

Explanation: Iron is magnetic

Answer:

a

Explanation:

because if you do its right

Answer:

it's not included

Explanation:

plz exact ur explain

Answer:

si amor

Explanation:

Hoiykñjdnlklbutrk

The temperature of the gas in the tank is the ratio of heat capacities times the temperature of gas in the constant pressure line.

It should be noted that temperature simply means the measure of hotness and coldness in a body

From the given information, H is the enthalpy of gas on the constant pressure line, m is the mass flow rate and U is the internal energy of gas.

Here, the temperature of the gas in the tank is the ratio of heat capacities times the temperature of gas in the constant pressure line.

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Answer:

Explanation:

write each force in terms of magnitude and directions  

Fx = F sin Ф

Fy = F cos Ф

where Ф is to be measured from x axis.

∑F at y = o

FAy + FBy + FCy + FDy + FEy + FGy = 0

∑F at x = o

FAx + FBx + FCx + FDx + FEx + FGx = 0

Let  

FA = FA sin (110)   +   FA cos (110)

FB = 20 sin (270)  +  20 cos (270)

FC = 16 sin (140)    +  16 cos (140)

FD = 9 sin (40)       +  9 cos (40)

FE = 20 sin (270)    +  20 cos (270)

FG = FG sin (50)     +  FG cos (50)

add x and y forces:

FAx + FBx + FCx + FDx + FEx + FGx = 0

FAy + FBy + FCy + FDy + FEy + FGy = 0

FA sin (110)  + 0  + 16 sin (140)  + 9 sin (40)  + 0   + FG sin (50) = 0

FA cos (110) - 20 + 16 cos (140) + 9 cos (40) - 20 + FG cos (50 = 0

FA sin (110)  + 0  + 10.285  + 5.785  + 0   + FG sin (50) = 0

FA cos (110) - 20 - 12.257 + 6.894 - 20 + FG cos (50) = 0

FA sin (110)  + 16.070 + FG sin (50) = 0        

FA cos (110) - 45.363 + FG cos (50) = 0

solving for FA, and FG

FA = 13 kN

FG = 15.3 kN

From the given information, we can say that the sum of the upward forces is equivalent to the sum of the downward forces.

From the diagram, equating the component of the upward forces and the downward forces, we have:

\(\mathbf{-F_a sin 70 +F_c sin 40+F_d sin 40 + F_g sin50= F_b+F_e}\) --- (1)

Also, the sum of the horizontal positive x-axis as well as the horizontal negative x-axis can be computed as:

\(\mathbf{F_g cos 50 +F_d cos 40 = F_c cos 40 +F_a cos 70 --- (2)}\)

If:

\(F_B = F_E = 20 \ kN \\ \\ F_c = 16 \ kN \\ \\ F_D= 9\ kN\)

Then, from equation (1), we can have the following:

\(\mathbf{F_a sin 70 + 16 sin 40 + 9 sin40 + F_gsin 50 = (20 + 20 )kN}\)

collecting like terms;

\(\mathbf{F_a sin 70 + F_gsin 50 = 40 - 16 sin 40 - 9 sin40 }\)

\(\mathbf{F_a sin 70 + F_gsin 50 =23.93}\) --- (3)

From equation (2);

\(\mathbf{F_g cos 50 + 9cos 40 = 16 cos 40 + F_a cos 70}\)

collecting like terms:

\(\mathbf{F_g cos 50 -F_a cos 70 =16cos 40 -9cos 40}\)

\(\mathbf{-F_a cos 70 +F_g cos 50 =5.36 ----- (let \ this \ be \ equation (4))}\)

Suppose we equate (3) and (4) together using the elimination method;

\(\mathbf{F_a sin 70 + F_gsin 50 =23.93}\) --- (3)

\(\mathbf{-F_a cos 70 +F_g cos 50 =5.36 --- (4)}\)

Let's multiply (3) with ( cos 70 ) and (4) with (sin 70);

Then, we have:

\(\mathbf{F_a sin 70 cos 70 + F_gsin 50 cos 70 =23.93 cos 70}\)

\(\mathbf{-F_a cos 70 sin 70 +F_g cos 50 sin 70 =5.36 sin 70}\)

Adding both previous equations together, we have:

\(\mathbf{F_a sin 70 cos 70 + F_gsin 50 cos 70 =23.93 cos 70}\)

\(\mathbf{-F_a cos 70 sin 70 +F_g cos 50 sin 70 =5.36 sin 70}\)

\(\mathbf{(0 + F_g(sin 50 cos 70 + sin70 cos50) = 23.93 cos 70 + 5.36 sin 70)}\)

\(\mathbf{( F_g(0.262 + 0.604)) =(8.19 + 5.04)}\)

\(\mathbf{( F_g(0.866)) =(13.23)}\)

\(\mathbf{ F_g =\dfrac{(13.23)}{(0.866)}}\)

\(\mathbf{ F_g =15.28 \ N}\)

Replacing the value of \(\mathbf{F_g}\) into equation (3), to solve for \(\mathbf{F_a}\), we have:

\(\mathbf{F_a sin 70 + F_gsin 50 =23.93}\)

\(\mathbf{F_a sin 70 + 15.28sin 50 =23.93} \\ \\ \mathbf{F_a sin 70 +11.71 =23.93} \\ \\ \mathbf{F_a sin 70 =23.93-11.71 } \\ \\ \mathbf{F_a sin 70 =12.22 } \\ \\ \mathbf{F_a =\dfrac{12.22 }{sin 70}} \\ \\\)

\(\mathbf{F_a =13.01 \ N}\)

Therefore, we can conclude that the magnitudes of \(\mathbf{F_a}\) and \(\mathbf{F_g}\) are 13.0 N and 15.28 N respectively.

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(a) The velocity profile in the fluid or u is:

  \($$u=U_e\left(\frac{y}{H}\right)+\frac{1}{2 \mu}\left(\frac{\partial P}{\partial x}\right)\left(y^2-H y\right)$$\)

(b) The value of the pressure gradient for which the shear stress on the wall is equal to zero is:

\(& \frac{\partial P}{\partial x}=\frac{-U_\theta \mu}{H\left(y-\frac{H}{2}\right)}\end{aligned}$$\)

The pressure gradient, which is a physical quantity used in atmospheric science to describe the direction and rate at which pressure rises most quickly around a specific location, is typically defined as being of air, but it can also more broadly refer to any fluid.

Pascals per meter (Pa/m) is a dimensional unit used to express the pressure gradient. The gradient of pressure as a function of position is what it is mathematically referred to as. The force density is the name for the negative gradient of pressure.

Pressure gradients in petroleum geology and petrochemical sciences pertaining to oil wells, and more specifically in hydrostatics, refer to the gradient of vertical pressure in a column of fluid within a wellbore and are typically expressed in pounds per square inch per foot (psi/ft).

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They were made of stone blocks that were held together with lime mortar. Some were plastered over and painted.

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The forklift overturning is a very common way of getting injured from a forklift. Overturning the forklift means it tips over onto it's side due to the operator turning it too fast.

Answer:

The rate of heat transfer between pipe and its surrounding is found to be 1250 KW

Explanation:

Assuming no significant change in potential energy. When we apply the first law of thermodynamics to the given system of 1-D pipe, we get the following expression:

Q = m(h₁ - h₂)

where,

Q = Heat Transfer between pipe and surrounding = ?

m = mass flow rate of steam = 0.5 kg/sec

h₁ = Specific Enthalpy of steam at entrance = 4000 KJ/kg

h₂ = Specific Enthalpy of steam at exit = 1500 KJ/kg

Therefore, using these values in the equation, we get the value of heat transfer:

Q = (0.5 kg/sec)(4000 KJ/kg - 1500 KJ/kg)

Q = 1250 KW

Answer:

The typical structure of a report, as shown on this page, is often referred to as IMRAD, which is short for Introduction, Method, Results And Discussion. As reports often begin with an Abstract, the structure may also be referred to as AIMRAD.

Ground shaking is a term used to describe the vibration of the ground during an earthquake. Ground shaking is caused by body waves and surface waves. As a generalization, the severity of ground shaking increases as magnitude increases and decreases as distance from the causative fault increases.

The amount of gain that can be raised or lowered without causing the system to become unstable is referred to as the gain margin.

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Answer:

Read Below

Explanation:

Apparent power (volt-amperes) is the trigonometric sum of Real power (watts) and reactive power (volt-amperes reactive - VARs). Stated mathematically: VA squared = watts squared plus VARs squared

similarly, power factor, the ratio of real power to apparent power, is the cosine of the angle between the real power leg and apparent power hypotenuse of a right triangle (Reactive power being the other leg).

Just use these relationships and a bit of high school trigonometry and you can calculate the apparent power and power factor for the system you are describing.

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The power factor of the 65-kVA load, if the overall power factor is 0.85 lagging is 0.585 lagging​.

Apparent energy (volt-amperes) is the trigonometric sum of Real energy (watts) and reactive energy (volt-amperes reactive - VARs). Stated mathematically: VA squared = watts squared plus VARS squared similarly, energy component, the ratio of actual energy to obvious energy, is the cosine of the perspective among the actual energy leg and obvious energy hypotenuse of a proper triangle (Reactive energy being the opposite leg).

Just use those relationships and a chunk of excessive college trigonometry and you may calculate the obvious energy and energy component for the machine you're describing.

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Answer:

Along the zero to measure an object on a ruler

Fiscal policy is the use of government spending and taxation to influence the economy. It involves decisions made by the government regarding how much money should be spent on public goods and services, such as education, healthcare, and infrastructure, and how much revenue should be collected through taxes.

Fiscal policy is often used to promote economic growth and stability, such as during a recession when the government may increase spending to stimulate the economy. However, it can also be used to combat inflation by reducing government spending and increasing taxes.

Fiscal policy is defined as the use of government revenue collection (taxation) and expenditure (spending) to influence the economy. It is a tool utilized by the government to achieve economic objectives, such as promoting growth, managing inflation, reducing unemployment, and maintaining a stable balance of payments. Fiscal policy can be adjusted through changes in tax rates, government spending, and public debt management, depending on the economic goals and prevailing conditions.

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The maximum shear stress is  R = 25 MPa

Since the Von Mises stress in this case is less than the yield stress

From the circle, we can read off the principal stresses  as the two intersections of the circle with the horizontal axis. In this case, the principal stresses are:

σ1 = σavg + R = 35 MPa

σ2 = σavg - R = -15 MPa

The maximum shear stress is given by the radius of the circle, which is equal to half of the difference between the two principal stresses:

τmax = R = 25 MPa

In order to determine if the plate will yield under uniaxial tension with a yield stress of 80 N/mm², we first need to convert the units of the stress values we obtained earlier from MPa to N/mm²:

σ1 = 35 MPa = 35 N/mm²

σ2 = -15 MPa = -15 N/mm²

Substituting these values into the Von Mises yield criterion equation, we get:

σVM = √(35² - 35(-15) + (-15)²) = 51.96 N/mm²

Since the Von Mises stress in this case is less than the yield stress

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Answer:

B

Explanation:

Aluminium doesn't rust unless exposed to copper for a duration of time.

The range of force exerted at the end of the rope is; 285.7 N to 1,000 N.

The net horizontal force of the cylinder when it is at equilibrium position can be found by applying Newton's second law of motion. Thus;

∑F = 0

F - μF_n = 0

We are given;

F_n = 5 kN = 5000 N

μ = 0.2

Thus;

F - 0.2(5,000) = 0

F - 1,000 = 0

F = 1,000 N

The strength of the applied force will be increasing as the number of turns of the rope increases. Thus;

Minimum force = Total force/number of turns of rope

Since rope is wrapped three and half times, then;

number of turns = 3.5

Thus;

minimum force = 1,000/3.5

minimum force = 285.7 N

Thus, the range of force exerted at the end of the rope is 285.7 N to 1,000 N.

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Answer: A yield sign

Explanation:

Answer:

B is correct I believe

Answer: hello some data related to your question is missing attached below is the missing data

answer:

T2 = 265°C

Explanation:

First step : calculate sum of vertical forces

∑ y = 0

Fmg - 2(0.5 Fst ) = 0

∴Fmg = ( 12 * 10^6 ) ( 2 * π/4 (0.01)^2 )

          = 1884.96 N

Also determine the Compatibility equation in order to determine the change in Temperature

ΔT = 250°C

therefore Temperature at which average normal stress becomes 12.0 MPa

ΔT = T2 - T1

250°C = T2 - 15°C

T2 = 250 + 15 = 265°C

attached below is the detailed solution