While it is impossible to know exactly what the intentions and artistic visions of ancient humans were, archaeologists can try to fit recognizable shapes to important objects in the natural world. The oldest artifact created by humans and thought to very possibly depict the night sky:_____________

Answer:

Force is useful to us because it changes or tries to change the positionof a body, it helps to change the direction of a moving object , it helps to change the speedof a moving body etc.

I hope this will help you

Please see attached picture for answer an explanation.

The moment of force about point O, is determined from the product of force and perpendicular distance

The moment of a force about a given point is the torque exerted by the applied force on the object. The moment of force is determined from the product of force and perpendicular distance of the applied force.

P = Fd

where;

Thus, the moment of force about point O, is determined from the product of force and perpendicular distance.

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The electric potential energy of the charge will be =3.5*10^8 J  

Electric potential energy is the energy that is needed to move a charge against an electric field.

F=Force experienced by the charge = 3.6*10^-4 N

q1 = magnitude of charge producing the electric field

q2 = magnitude of charge experiencing the electric force

r1 = distance between the two charges

Electric force experienced by the charge is given using coulomb's law as

\(F=\dfrac{kq_1q_2}{r^2}\)

\(3.6\times 10^{-4}=\dfrac{9\times 10^9 q_1q_2}{(9.8\times 10^{-5})^2}\)

\(q_1q_2=3.84\times 10^{-22}\)

Electric potential energy of the charge can be given as

\(U=\dfrac{kq_1q_2}{r}\)

\(U=\dfrac{(9\times 10^9)q_1q_2}{(9.8\times 10^{-5})^2}\)

\(U=3.5\times 10^{-8}\ J\)

Thus Electric potential energy of the charge can be given as \(U=3.5\times 10^{-8}\ J\)

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Answer:

D. ) The force would be zero newtons

Explanation:

Because

If you are at the center of the earth, gravity is zero because all the mass around you is pulling "up" (every direction there is up!)

So F=mg so if g is zero F is also zero

Conclusion statement defines the answer of a scientific problem based on the result of the experiment.

A scientific problem is solved by the scientific methods. A scientific method is the step-by-step approach to a conclusion of the problem. It may include the following steps.

Observation: It is the first step of the method. It is based on that how do you see the problem.

Hypothesis: It is the result you think that you will get.

Prediction: It is based on your scientific knowledge. If our hypothesis is correct than our prediction will also be true.

Experiment: It is the system or mechanism designed by you to test your hypothesis.

Conclusion: It is the final result based on the experiment of the method. This statement tells you whether your hypothesis is true or not.

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From the astronaut's point of view, the distance between the star and Earth remains the same at 7.00 ly. However, when the astronaut is returning back to Earth with a speed of 0.88c relative to Earth, then the distance covered by the astronaut on the return trip, as measured by the astronaut, is 11.06 light-years.

\(L = L_0 / \sqrt{(1 - v^2/c^2)}\)

The distance covered on the return trip is equal to the length of the distance between the star and Earth as measured by the astronaut.

Using the equation for length contraction, we get:

\(L = {7.00 ly} / \sqrt{(1 - (0.88c)^2/c^2)}\)

\(L =\frac{7.00 ly}{\sqrt{(1 - 0.7744)}}\)

\(L =\frac{7.00 ly}{0.6325}\)

L = 11.06 ly

Therefore, the distance covered by the astronaut on the return trip, as measured by the astronaut, is 11.06 light-years.

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The magnetic field around a current-carrying wire is directly proportional to the current and inversely proportional to the distance from the wire.

The magnetic field strength generated by a current-carrying wire follows the right-hand rule. As the current increases, the magnetic field strength also increases. This relationship is described by Ampere's law.

Additionally, the magnetic field strength decreases as the distance from the wire increases, following an inverse square law. This means that doubling the current will double the magnetic field strength, while doubling the distance from the wire will reduce the field strength to one-fourth of its original value. Therefore, the magnetic field around a current-carrying wire is directly proportional to the current and inversely proportional to the distance from the wire.

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To complete the sentences, we have

Equilibrium is the phenomenom in which no net force acts on an object.

Static equilibrium is equilibrium is which the body is at rest and has equaland balanced forces acting on it.

Dynamic equilibrium is equilibrium is which the body in motion and has equaland balanced forces acting on it.

So, to complete the sentences, we have

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If λ occurs as an eigenvalue of A with multiplicity r, then there are r linearly independent eigenvectors associated with λ, and the geometric multiplicity of λ is equal to r.

Let A be an n × n matrix. An eigenvalue of A is a scalar λ such that there is a nonzero vector x satisfying the equation Ax = λx. This equation can be rewritten as the linear system (A − λI)x = 0, where I is the identity matrix. Nontrivial solutions to this equation exist if and only if the matrix A − λI is singular, which means that its determinant is zero. Thus, the eigenvalues of A are the roots of the polynomial equation det(A − λI) = 0, which is called the characteristic equation of A. The algebraic multiplicity of an eigenvalue is the number of times it appears as a root of the characteristic equation. The geometric multiplicity of an eigenvalue is the dimension of the eigenspace associated with that eigenvalue. The eigenspace of an eigenvalue λ is the set of all eigenvectors of A associated with λ, along with the zero vector.

The rank of A is the dimension of its column space, which is the span of its column vectors. The rank of A is equal to the dimension of the row space of A, which is the span of its row vectors. The rank of A is also equal to the number of nonzero singular values of A. If the rank of A is r, then the dimension of the nullspace of A is n − r. If A has r linearly independent eigenvectors associated with a particular eigenvalue λ, then the geometric multiplicity of λ is r. If the algebraic multiplicity of λ is greater than its geometric multiplicity, then there are not enough eigenvectors to form a basis of the eigenspace associated with λ, which means that A is not diagonalizable. If the algebraic multiplicity of λ is equal to its geometric multiplicity, then A is diagonalizable. If λ occurs as an eigenvalue of A with multiplicity r, then there are r linearly independent eigenvectors associated with λ, and the geometric multiplicity of λ is equal to r.

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Answer:

a. y = (tanθ)x - 1/2gx²/(v₀cosθ)²

b. Range R = v₀²sin2θ/g

c. Time of flight T = 2v₀sinθ/g

Explanation:

a. Show that the path followed by the object is parabolic

Let the vertical component of its velocity be v₁ = v₀sinθ and the horizontal component of its velocity be v₂ = v₀cosθ where v₀ = initial velocity of the projectile.

Now, for its vertical displacement Δy = v₁t - 1/2gt²   (1)

Its horizontal displacement Δx = v₂t  (2)

From (2) t = Δx/v₂

Substituting t into (1), we have

Δy = v₁(Δx/v₂) - 1/2g(Δx/v₂)²

= (v₁/v₂)Δx - 1/2g(Δx)²/(v₂)² =

= (v₀sinθ/v₀cosθ)Δx - 1/2g(Δx)²/(v₀cosθ)²  

If we assume the initial position is at the origin, then Δx = x - 0 = x and Δy = y - 0 = y. So,

y = (tanθ)x - 1/2gx²/(v₀cosθ)² .

This is the required equation and it is a quadratic equation in x. Thus, the path followed by the projectile is parabolic.

b. The Range, R

The range, R is obtained when y = 0

So, 0 = (tanθ)x - 1/2gx²/(v₀cosθ)²

[(tanθ) - 1/2gx/(v₀cosθ)²]x = 0

x = 0 or (tanθ) - 1/2gx/(v₀cosθ)² = 0

x = 0 or (tanθ) = 1/2gx/(v₀cosθ)²

x = 0 or (tanθ)(v₀cosθ)² = 1/2gx

x = 0 or x = 2(sinθ/cosθ)(v₀cosθ)²/g

x = 0 or x = v₀²(2sinθ/cosθ)/g

x = 0 or x = v₀²sin2θ/g      [sin2θ = 2sinθ/cosθ]

So its range R = x = v₀²sin2θ/g    

c. Time of flight, T

The time of flight, T is obtained from (1) when Δy = 0 and t = T

So, 0 = v₁T - 1/2gT²

(v₁ - 1/2gT)T = 0

T = 0 or (v₁ - 1/2gT) = 0

T = 0 or v₁ = 1/2gT

T = 0 or T = 2v₁/g = 2v₀sinθ/g

So, the time of flight T = 2v₀sinθ/g

The sum of the x components of the forces acting on block 2 is expressed as the equation ∑F2x = Tcos(θ) - mgsin(θ).

A force is defined as the effect that causes the motion of an object with mass to change its velocity that is accelerated. It can be a push or a pull, always with magnitude and direction, making it a vector quantity.

The sum of the x components of the forces acting on block 2 is expressed as the equation ∑F2x = Tcos(θ) - mgsin(θ) where the T is the tension, m is the mass of the block, g is the acceleration of gravity, and θ is the angle of the incline.

This type of equation can be used to calculate the x components of the forces in a variety of situations for example, when the block is being pulled up an incline or when it is in equilibrium.

Thus, the sum of the x components of the forces acting on block 2 is expressed as the equation ∑F2x = Tcos(θ) - mgsin(θ).

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Your question is incomplete, most probably the complete question is:

What is ∑F2x, the sum of the x components of the forces acting on block 2? Take forces acting up the incline to be positive. Express your answer in terms of some or all of the variables tension T, m2, the magnitude of the acceleration of gravity g, and θ.

the maximum rms current that the neon sign can draw is 450 mA, and the power consumed by the sign at this maximum current is 5.85 watts. the voltage ratio (13 kV / 220 V).

To calculate the power consumed by the neon sign when drawing the maximum current allowed by the fuse, we can use the formula P = VI, where P is power, V is voltage, and I is current. Given that the voltage is 13 kV and the current is 450 mA (or 0.45 A), the power consumed is 5.85 watts.

Maximum rms current that the neon sign can draw: 450 mA

Power consumed by the neon sign at maximum current: 5.85 watts

The maximum rms current that the neon sign can draw is determined by the fuse in the transformer's primary winding. This fuse is rated at 0.45 A (rms). To find the maximum current drawn by the neon sign, we divide the fuse rating by the voltage ratio between the line voltage and the neon sign voltage. The voltage ratio is calculated by dividing the neon sign voltage (13 kV) by the line voltage (220 V). Multiplying this voltage ratio by the fuse rating gives us the maximum current in amperes, which is then converted to milliamperes.

To determine the power consumed by the neon sign at the maximum current, we use the formula P = VI. The voltage is given as 13 kV (rms), and the maximum current is 450 mA. Plugging these values into the formula, we can calculate the power consumed, which is given in watts.

Therefore, the maximum rms current that the neon sign can draw is 450 mA, and the power consumed by the sign at this maximum current is 5.85 watts.

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The correct option that best describes nuclear fusion is It involves the combining of two atoms into one larger atom.

Hence, the correct option is C.

Nuclear fusion is a process where two atomic nuclei combine to form a single, larger atomic nucleus. This process releases a significant amount of energy. In fusion reactions, the atomic nuclei are brought close enough together that the strong nuclear force can overcome the electrostatic repulsion between positively charged nuclei. This results in the fusion of the nuclei, forming a heavier atom.

Option A is incorrect because while nuclear fusion has the potential to fuel nuclear power plants, practical fusion reactors are still under development.

Option B is incorrect as it describes nuclear fission, not nuclear fusion. Nuclear fission involves the splitting of one atom into two smaller atoms, typically through the bombardment of a heavy atomic nucleus with a neutron.

Option D is incorrect as electrons do not initiate fusion reactions. Instead, the conditions required for fusion, such as high temperatures and pressures, are typically achieved through methods like heating the fuel or using powerful magnetic fields.

Therefore, The correct option that best describes nuclear fusion is It involves the combining of two atoms into one larger atom.

Hence, the correct option is C.

The given question is incomplete and the complete question is '' Which of the following best describes nuclear fusion?

A. It fuels nuclear power plants.

B. It involves the splitting of one atom into two smaller atoms.

C. It involves the combining of two atoms into one larger atom.

D. Its chain reactions can be initiated by electrons.''

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A pipe 45.0 cm long if the pipe is open at both ends.

a) The fundamental frequency is 382 Hz.

b) The frequency of the first overtone is 1146 Hz.

c) The frequency of the third overtone is 1910 Hz.

d) The frequency of the third overtone is 2674 Hz.

e) The highest harmonic that may be heard is the 52nd harmonic, with a frequency of 52f1 = 19844 Hz.

The fundamental frequency of a pipe that is open at both ends is given by

f1 = v/2L

Where v is the speed of sound in air and L is the length of the pipe.

a) Substituting the given values, we get

f1 = (344 m/s)/(2 × 0.45 m) = 382 Hz

Therefore, the fundamental frequency of the pipe is 382 Hz.

b) The frequency of the first overtone is given by

f2 = 3f1 = 3 × 382 Hz = 1146 Hz

c) The frequency of the second overtone is given by

f3 = 5f1 = 5 × 382 Hz = 1910 Hz

d) The frequency of the third overtone is given by

f4 = 7f1 = 7 × 382 Hz = 2674 Hz

e) The highest harmonic that may be heard by a person who can hear frequencies from 20 Hz to 20000 Hz is the one whose frequency is closest to 20000 Hz. The frequency of the nth harmonic is given by

fn = nf1

Therefore, the highest harmonic that may be heard is

n = 20000 Hz / f1 = 52.3

Therefore, the highest harmonic that may be heard is the 52nd harmonic, with a frequency of 52f1 = 19844 Hz.

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Answer:

El área de la placa es aproximadamente 5102.752 centímetros cuadrados.

Explanation:

Asumamos que el cambio dimensional como consecuencia de la temperatura es pequeña, entonces podemos estimar el área de la placa de cobre en función de la temperatura mediante la siguiente aproximación:

\(A_{f} = w\cdot l \cdot [1 + 2\cdot \alpha\cdot (T_{f}-T_{o})]\) (1)

Donde:

\(w\) - Ancho de la placa, en centímetros.

\(l\) - Longitud de la placa, en centímetros.

\(\alpha\) - Coeficiente de dilatación, en \(\frac{1}{^{\circ}C}\).

\(T_{o}\) - Temperatura inicial, en grados Celsius.

\(T_{f}\) - Temperatura final, en grados Celsius.

Si sabemos que \(w = 65\,cm\), \(l = 78\,cm\), \(\alpha = 17\times 10^{-6}\,\frac{1}{^{\circ}C}\), \(T_{o} = 20\,^{\circ}C\) and \(T_{f} = 400\,^{\circ}C\), entonces el área de la placa a la temperatura final:

\(A_{f} = (65\,cm)\cdot (78\,cm)\cdot \left[1+\left(17\times 10^{-6}\,\frac{1}{^{\circ}C} \right)\cdot (400\,^{\circ}C-20\,^{\circ}C)\right]\)

\(A_{f} = 5102.752\,cm^{2}\)

El área de la placa es aproximadamente 5102.752 centímetros cuadrados.

The production function will have constant returns to scale if 2αβ = 1

Constant returns to scale (CRS) implies that if all inputs increase by a factor of λ, the output increases by λ as well. The requirement for constant returns to scale (CRS) in a Cobb-Douglas production function with a new input factor is given by the sum of exponents on all variables equal to 1.

In this case, Y = AKαLβMγ.

Thus, we have that α + β + γ = 1 for constant returns to scale in K, L, and M, because the sum of the exponents is 1.

If the sum of the exponents is less than 1, it indicates decreasing returns to scale. If the sum of the exponents is greater than 1, it indicates increasing returns to scale. If we take γ = 0, we obtain the production function used in class, which is Y = AKαLβ, thus α + β = 1 for constant returns to scale in K and L.

When γ = 0, the answer we get is consistent with what we learned in class. Now, we consider the constant elasticity of substitution (CES) technology, where Y = [aKα + bLα]β. The production function will have constant returns to scale (CRS) in K and L if the sum of the exponents of K and L is equal to 1.

Therefore, αβ + αβ = 1, implying 2αβ = 1.

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Shielding occurs when two opposite charges are positioned on opposite sides of a cylindrical object, resulting in no electric field inside the cylinder.

The phenomenon of shielding occurs due to the cancellation of electric fields created by the opposite charges positioned on opposite sides of the cylinder. When the two charges are positioned outside the cylinder, they create electric fields that extend into the surrounding space.

However, inside the cylinder, the electric fields created by the charges have equal magnitudes but opposite directions. As a result, the electric fields cancel each other out, leading to a net electric field of zero inside the cylinder.

This cancellation of electric fields is a consequence of the superposition principle, which states that the total electric field at a point is the vector sum of the individual electric fields produced by each charge. In the case of shielding, the electric fields produced by the charges outside the cylinder have opposite directions and equal magnitudes, resulting in a complete cancellation inside the cylinder.

The shielding effect is particularly observed in conductive materials where charges are free to move. The charges redistribute themselves in such a way that the electric field inside the conductor is zero, known as electrostatic equilibrium. This redistribution of charges neutralizes the electric field and prevents it from penetrating the interior of the cylinder, effectively shielding the region inside from the external electric field.

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The electric field strength at point (x,y) = (20 mm, 0cm) is 16.76 N/C and the electric field strength at point (x,y) = (0cm, 20 mm) is 16.80 N/C.

The magnitude of the point charge is ± 5. 0 nC and distance between the point charges is 3. 0 mm. Let's first find the electric dipole moment;

p = qd= 5.0 nC × 3.0 mm = 15.0 × 10^−9 C m

The electric field strength at point (20 mm,0cm) is given by;

E= kp/r²

Electric field strength, E1 at point P1 (20 mm, 0 cm) is given by;

The distance of P1 from the charges is;

r1 = √(x₁ - x₂)² + (y₁ - y₂)²= √(20² + 1.5²) = 20.03 mm = 20.03 × 10⁻³ m

Using Coulomb's law;

F = kq₁q₂/r² ; where k = 9 × 10^9 Nm²/C²;

We can find the electric field strength at P1 using the formula:

E1= kp/r1² = (9 × 10^9 Nm²/C²) (15.0 × 10^−9 C m)/(20.03 × 10⁻³ m)²= (9 × 10^9 × 15 × 10^−9)/(20.03 × 10⁻³)²= 16.76 N/C

Now, let's find the electric field strength at point (0cm,20 mm). The electric field strength, E2 at point P2 (0cm, 20 mm) is given by;

The distance of P2 from the charges is;

r2 = √(x₁ - x₂)² + (y₁ - y₂)²= √(20² + 3) = 20.01 mm= 20.01 × 10⁻³ m

Using Coulomb's law;

F = kq₁q₂/r² ; where k = 9 × 10^9 Nm²/C²;

We can find the electric field strength at P2 using the formula;

E2= kp/r2² = (9 × 10^9 Nm²/C²) (15.0 × 10^−9 C m)/(20.01 × 10⁻³ m)²= (9 × 10^9 × 15 × 10^−9)/(20.01 × 10⁻³)²= 16.80 N/C

Therefore, the electric field strength at point (x,y) = (20 mm, 0cm) is E1 = 16.76 N/C. The electric field strength at point (x,y) = (0cm, 20 mm) is E2 = 16.80 N/C.

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The star Betelgeuse is about 600 light-years away. If it explodes tonight, approximately: we won't know about it until 600 years from now.

Rather than measuring time, a light-year measures distance (as the name might imply). The distance a light beam travels in a single Earth year is measured in "light-years," which is roughly equivalent to 6 trillion miles (9.7 trillion kilometers).

Because the cosmos is expanding, the light that goes the farthest is stretched the most, resulting in the object that emitted that light being farther away. The expanding cosmos is the reason we can see things up to 46.1 billion light-years away. According to a common model of the Universe, some of the most recently discovered objects may be more than 13 billion light years away.

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Answer:

its most definitely c. trust me

Explanation:

Answer:

increasing the masses of the objects and decreasing the distance between the objects

Answer:the objects have the same acceleration

Explanation:

The speed of the bullet can be determined using conservation of energy principles. The speed of the bullet is calculated to be approximately 194.6 m/s.

To solve this problem, we can start by considering the initial kinetic energy of the bullet and the final potential energy stored in the compressed spring. We can assume that the bullet-block system comes to a stop, which means that the final kinetic energy is zero.

The initial kinetic energy of the bullet can be calculated using the formula: KE_bullet = (1/2) * m_bullet * v_bullet^2, where m_bullet is the mass of the bullet and v_bullet is its velocity.

The potential energy stored in the compressed spring can be calculated using the formula: PE_spring = (1/2) * k * x^2, where k is the spring constant and x is the compression of the spring.

Since the kinetic energy is initially converted into potential energy, we can equate the two energies: KE_bullet = PE_spring.

Substituting the given values into the equations, we have: (1/2) * m_bullet * v_bullet^2 = (1/2) * k * x^2.

Solving for v_bullet, we get: v_bullet = sqrt((k * x^2) / m_bullet).

Plugging in the given values, we have: v_bullet = sqrt((108 N/m * (0.412 m)^2) / 0.0179 kg) ≈ 194.6 m/s.

Therefore, the speed of the bullet is approximately 194.6 m/s.

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Ans

It is being pulled toward the object by the objects gravity

Gravity:-

Answer:

They host three or more distinct ecosystems at different elevations.

Explanation:

I checked it, and its right.

Answer:

They host three or more ecosystems where animals cannot live.

Explanation:

Answer:

Established a government for the Northwest Territory, outlined the process for admitting a new state to the Union, and guaranteed that newly created states would be equal to the original thirteen states

Explanation:

Goooogle, so I hope this helps somewhat

Also, isn't this a History question? You put physics lol

Answer:

Explanation:

The collision between the 93kg fullback and the 127kg defensive tackle is an example of an inelastic collision. In an inelastic collision, the total kinetic energy of the system is not conserved as some of the energy is transformed into other forms such as heat or sound. The resulting final speed of both players would be 0m/s, indicating that they have come to a stop after the collision.

The wavelength of the light used in the Michelson interferometer is approximately 633 nm. The number of bright-dark-bright fringe shifts (N) is directly proportional to the distance moved by the mirror (d) and inversely proportional to the wavelength of the light (λ).

However, this value is for vacuum. The actual wavelength of light used in the Michelson interferometer is typically corrected for air, which has a refractive index of approximately 1.0003. Using this correction factor, λ = 1270 nm / 1.0003 = 1269 nm ≈ 633 nm To find the wavelength of the light in the Michelson interferometer, we can use the given information about the movement of mirror M2 and the fringe shifts observed. In a Michelson interferometer, when the mirror moves a certain distance, the path difference between the two arms changes by twice that distance.

This is because the light has to travel to the mirror and back. Calculate the total path difference: 2 * 70 μm = 140 μm (since the light travels to the mirror and back) Convert the path difference to meters: 140 μm * 10^-6 m/μm = 140 * 10^-6 m Calculate the number of wavelengths in the total path difference: 550 fringe shifts = 550 wavelengths (since one bright-dark-bright fringe shift corresponds to one wavelength)  Divide the total path difference by the number of wavelengths to find the wavelength of the light: (140 * 10^-6 m) / 550 = 254 * 10^-9 m Convert the wavelength to nanometers: 254 * 10^-9 m * 10^9 nm/m = 254 nm

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A transverse wave is a wave in which particles of the medium move in a direction perpendicular to the direction that the wave moves. Suppose that a slinky is stretched out in a horizontal direction across the classroom and that a pulse is introduced into the slinky on the left end by vibrating the first coil up and down. Energy will begin to be transported through the slinky from left to right. As the energy is transported from left to right, the individual coils of the medium will be displaced upwards and downwards. In this case, the particles of the medium move perpendicular to the direction that the pulse moves. This type of wave is a transverse wave. Transverse waves are always characterized by particle motion being perpendicular to wave motion.

A longitudinal wave is a wave in which particles of the medium move in a direction parallel to the direction that the wave moves. Suppose that a slinky is stretched out in a horizontal direction across the classroom and that a pulse is introduced into the slinky on the left end by vibrating the first coil left and right. Energy will begin to be transported through the slinky from left to right. As the energy is transported from left to right, the individual coils of the medium will be displaced leftwards and rightwards. In this case, the particles of the medium move parallel to the direction that the pulse moves. This type of wave is a longitudinal wave. Longitudinal waves are always characterized by particle motion being parallel to wave motion.