Currently, seven astronauts are aboard the International Space Station (ISS).
The International Space Station (ISS) is a habitable artificial satellite in low Earth orbit. At present, there are seven astronauts who are currently aboard the ISS. As of August 2021, these are:
1. Akihiko Hoshide (Japan Aerospace Exploration Agency)
2. Thomas Pesquet (European Space Agency)
3. Megan McArthur (National Aeronautics and Space Administration)
4. Shane Kimbrough (National Aeronautics and Space Administration)
5. Mark Vande Hei (National Aeronautics and Space Administration)
6. Oleg Novitskiy (Roscosmos)
7. Pyotr Dubrov (Roscosmos)
These astronauts have been conducting experiments and research in various fields such as biology, physics, and medicine, among others. They have also been carrying out maintenance tasks and communicating with the ground team. The ISS serves as a platform for international cooperation and scientific advancements.
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Someone help!10 points!
Answer:
v=2
Explanation:
multiple both sides by 2 to get rid of franction
144=36v^2
then square root everything
12=6v
divide each by 6
v=2
The sides of a cube are each of length 1.00 m. each side is measured with an uncertainty
of 2%. the absolute uncertainty in the volume of the cube is?
The absolute uncertainty in the volume of the cube is 6%.
A cube is a solid object in three dimensions having six square faces, facets, or sides, three of which meet at each vertex. It looks like a hexagon when viewed from a corner, and its net is typically shown as a cross. One of the five Platonic solids, the cube is the only regular hexahedron. It contains 8 vertices, 6 faces, and 12 edges.
Volume of Cube = 3 Dimensions
2% uncertainty results in absolute errors of 0.02 m in 1 m on either side.
Its cubic volume is 3 x 0.02/1 x 100, or 6%.
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A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 8.0 m from the takeoff point.
If the kangaroo leaves the ground at a 22˚ angle, what is its takeoff speed?
What is its horizontal speed?
The kangaroo's horizontal speed will be 9.7 m/s and its departure speed will indeed be 10.65 m/s.
What is the sound's velocity?By observing the pace at which this compressed region moves through the medium, we may determine the sound speed. The sound wave travels at a speed of around 343 meters per second in low humidity at 20 degrees Celsius.
Briefing:The following equation relates the distance to the direction and initial velocity:
d = [v₀²sin2θ]/g, where θ – the angle of the jump.
Thus, v₀² = gd / (sin2θ) = (9.8×8)/0.69 = 113.62
v₀ = 10.65 m/s ( the take off speed).
The horizontal velocity equals:
vₓ = v₀cos 22° = 10.65 m/s × 0.92 = 9.7 m/s
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Asky wave is incident on the ionosphere at an angle of 60°. The electron density of this ionosphere layer is N = 24.536 × 10¹¹ electrons/m³
a. For the point of reflection, determine the refractive index of the ionospheric layer. (3 Marks)
b. Identify the critical frequency for the communication link. (2 Marks)
c. Determine the maximum usable frequency (2 Marks)
d. Give reasons why the transmissions would fail the following frequencies if the frequencies were 10 MHz and 30 MHz respectively. (4 Marks)
e. The lonosphere bends high frequency radio waves towards Earth. Discuss this bending phenomenon.
We can calculate the refractive index by substituting the values into the formula: n = √(1 - (2.774 × 10^6 / f)^2). The refractive index of the ionospheric layer can be determined using the formula n = √(1 - (f_ce / f)^2)
(a) The refractive index of the ionospheric layer can be determined using the formula n = √(1 - (f_ce / f)^2), where n represents the refractive index, f_ce is the electron gyrofrequency, and f is the frequency of the incident wave.
The electron gyrofrequency (f_ce) can be calculated using the formula f_ce = 8.978 × √(N), where N is the electron density. Substituting the given electron density value, we have f_ce = 8.978 × √(24.536 × 10^11) ≈ 2.774 × 10^6 Hz.
Now, we can calculate the refractive index by substituting the values into the formula: n = √(1 - (2.774 × 10^6 / f)^2).
(b) The critical frequency for the communication link can be determined using the formula f_c = f_ce / sin(θ), where f_c represents the critical frequency and θ is the angle of incidence. Substituting the given angle of 60°, we have f_c = 2.774 × 10^6 Hz / sin(60°).
(c) The maximum usable frequency (MUF) can be calculated using the formula MUF = f_c / sin(θ). Substituting the critical frequency and angle of incidence given in parts (b) and (a), respectively, we can find the MUF.
(d) Transmissions would fail at the frequencies of 10 MHz and 30 MHz because they are below the critical frequency. The critical frequency represents the maximum frequency that can be reflected back to Earth by the ionospheric layer. If the frequency of the transmission is below the critical frequency, the wave would penetrate through the ionosphere and not be reflected back, leading to a failed transmission.
(e) The ionosphere bends high-frequency radio waves towards Earth due to the phenomenon of refraction. When a radio wave encounters the ionosphere, which is composed of charged particles, it experiences a change in speed and direction. This change in speed and direction is due to the varying density and composition of the ionosphere at different altitudes.
As the radio wave passes through the ionosphere, its path is curved downward towards the Earth's surface. This bending phenomenon occurs because the refractive index of the ionosphere is greater than that of the surrounding vacuum or atmosphere. The higher the frequency of the radio wave, the greater the bending effect due to the higher electron density in the ionosphere at higher altitudes.
This bending of high-frequency radio waves allows for long-distance communication by enabling the waves to travel beyond the line-of-sight. It plays a crucial role in long-distance radio communication, especially in areas where direct line-of-sight transmission is obstructed by the Earth's curvature or other obstacles.
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A box is pulled with a force of 27N to produce a displacement of 17m. If the angle between the force and displacement is 30 degrees, Find the work done by the force
A box is pulled with a force of 27N to produce a displacement of 17m. If the angle between the force and displacement is 30 degrees, the work done by the force is 397.50Joules.
To find the work done, the given data are,
Force =27 N
Displacement = 30 degrees.
What is Work done?Work done can be defined as the body that moves with some acceleration and did some work with a force.
The product of the displacement and the applied force can be also defined as the Work done.
The formula for work done with the angle of the distance or displacement is written as,
W = F × d × cosθ
Substituting all the given data,
W= 27 × 17× cos(30)
= 397.50 joules.
The work done by the force can be calculated as 397.50 joules.
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How are atoms in a molecule held together?
through shared electrons
through shared neutrons
through shared protons
through shared energy
help pls
Which are examples of following etiquette rules? (Choose three)
Start and end meetings on time
Insist on picking up the check when dining out with coworkers
Treat everyone with dignity and respect
Use titles like doctor
Examples of following etiquette rules are:
Start and end meetings on timeTreat everyone with dignity and respectUse titles like doctorWhat are etiquette?Etiquette refers to the set of conventional rules and practices governing social behavior, including manners, courtesy, and appropriate conduct in various settings. Etiquette varies across cultures and situations, but it generally involves showing respect for others, demonstrating good manners and social skills, and adhering to accepted norms and standards of behavior.
Some common examples of etiquette include Saying "please" and "thank you" when making requests or receiving help and Using appropriate greetings and forms of address (e.g. "Mr." or "Ms.") in different situations
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Question 9 of 10: you purchased $100 each of three different stocks in january. stock a increased 30% in value. stock b increased 15% in value. stock c lost 20% of its original value. what was the overall net percentage of gain in the three stocks? (round to the nearest percent.)
The overall net percentage of gain in the three stocks purchased each with $ 100 in which stock a increased 30% in value. stock b increased 15% in value. stock c lost 20% of its original value is 8.3 %
Value of Stock a = 100 + 30%
Value of Stock a = $ 130
Value of stock b = 100 + 15%
Value of stock b = $ 115
Value of stock c = 100 - 20%
Value of stock c = $ 80
Net percentage gain = ( Net profit / Total investment - 1 ) * 100
Net profit = 130 + 115 + 80
Net profit = $ 325
Total investment = 100 + 100 + 100
Total investment = $ 300
Net percentage gain = ( 325 / 300 - 1 ) * 100
Net percentage gain = ( 0.083 ) * 100
Net percentage gain = 8.3 %
Therefore, the the overall net percentage of gain in the three stocks is 8.3 %
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Required information A contractor uses a paddle stirrer to mix a can of paint. The paddle turns at 29. 4 rad/s and exerts a torque of 16. 6 N-m on the paint, doing work on the paint at a rate of Power = TW = 16. 6 N-m x 29. 4 rad/s = 488. 0 W. An internal energy increase of 12. 3 kJ causes the temperature of the paint to increase by 1. 00 K. If there were no heat flow between the paint and the surroundings, what would be the temperature change of the paint as it is stirred for 5. 00 min? K
The temperature change of the paint as it is stirred for 5.00 min can be found using the equation ΔT = (Q / mc) x t.
1. We are given the internal energy increase of the paint, which is 12.3 kJ. We need to convert this to joules by multiplying it by 1000, since 1 kJ is equal to 1000 J. So, Q = 12.3 kJ x 1000 = 12,300 J.
2. The power output of the paddle stirrer is given as 488.0 W. We can use the equation P = ΔU / t, where P is the power, ΔU is the change in internal energy, and t is the time. Rearranging the equation, we can find ΔU = P x t. Substituting the given values, we get ΔU = 488.0 W x 5.00 min x 60 s/min = 146,400 J.
3. The change in internal energy, ΔU, is equal to the heat transfer, Q, in an isolated system where there is no heat flow with the surroundings. So, ΔU = Q. We can now substitute the values into the equation ΔT = (Q / mc) x t. Rearranging the equation, we get ΔT = ΔU / (mc). Substituting the known values, we get ΔT = 146,400 J / (m x c).
Note: To calculate the temperature change, we would need the mass of the paint and the specific heat capacity of the paint, which are not provided in the given information.
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True or false, anything can turn into a black hole.
Answer:
False. Not everything can turn into a black hole. The formation of a black hole requires a massive object, typically a star, to collapse under its own gravity. This collapse causes the object to become so dense that it creates a singularity, a point of infinite density at the center of the black hole, which is surrounded by an event horizon, the point of no return beyond which nothing, not even light, can escape. So, only objects with sufficient mass and gravity can become black holes.
Explanation:
which planet is known as evening star
Answer:
Mercury is a metal that is used in
Mercury can be seen as an evening "star" near the sun's setting point or as a morning "star" near the sun's rising point. The evening star was given the name Hermes, and the morning star was given the name Apollo, since the ancient Greeks thought they were two separate things. Mercury, the Roman god's messenger, is the planet's name.
What is the weight of a 328N emperor penguin?
Answer:
Weight = 3217.68
Explanation:
N times Gravity = weight
Gravity= 9.81
The weight of the emperor penguin whose mass is 328 Kg on is 3214.4 Newtons.
What is Weight ?
Weight is the force exerted by the earth on an object at the surface of the earth. Mathematically -
W = m x g
where -
[m] is the mass of object
[g] is acceleration due to gravity
Given is the mass of an emperor penguin as 328 Kg.
We can write -
Mass [m] = 328 kg
Acceleration due to gravity [g] = 9.8 m/s²
Therefore, the weight of the emperor penguin will be
W[P] = m x g = 328 x 9.8 = 3214.4 Newtons
Hence, the weight of the emperor penguin whose mass is 328 Kg on is 3214.4 Newtons
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PLEASE HELP WITH THE 6 FOLLOWING SCIENCE QUESTIONS (the topic is circuit symbols and equations):
1. How much charge flows through a speaker if it is on for 20 minutes and has a current of 10A?
2. 500 coulombs of charge flow through a bulb for 25 seconds. Calculate the current trough the bulb.
3. 12A of current and 984C of charge flow through a kettle. How long was the kettle switched on for?
4. A laptop is switched on for 5 hours. It has a current flowing through it of 12A. What is the total amount of charge that flowed through the laptop?
5. An ipad is left in standby mode for 3 hours. During this time, 2.16C of charge flowed through the ipad. How much current flowed through the ipad?
6. A small LED light as 200mA of current flowing through it and a charge flow of 150C. How many minutes and seconds was the light switched on for?
genuine answers please, don't waste answer slots if you don't actually have an answer, it's rather irritating x
1) I=Q/T then Q= I ×T 10* ( 20*60) = 10 (120) therefore the answer is 1200C
2) I= Q/T that is 500/ 25 and the answer is 20A
The amplitude of a particle executing simple harmonic motion is 5cm, while its angular velocity is 10 rads -1 . Calculate the magnitude of the maximum acceleration of the particle.
Answer:
a_max = 50 cm/s^2
Explanation:
To find the magnitude of the maximum acceleration of the particle, you take into account the equation of motion in a simple harmonic motion:
\(x=Acos(\omega t)\)
ω: angular velocity = 10 rad/s
A: amplitude = 5 cm
The acceleration is given by:
\(a=\omega^2 x\)
and the maximum acceleration is obtained when the cosine function is maximum, that is, when cos(wt) = 1. Then, you have:
\(a_{max}=\omega^2 x_{max}=\omega^2A\)
Then, you replace the values of w and A in order to calculate a_max:
\(a_{max}=(10rad/s)^2(5cm)=50\frac{cm}{s^2}\)
hence, the maximum acceleration is 50 cm/s^2
Two charges of 5 x 10-6 C are a certain distance apart. These two positive charges experience 3.6 N of repelling electrical force between them. How far apart are these charges?
Answer:
r = 0.2499 m
Explanation:
Use Coulomb's Law: \(F_{e} = kq_{1}q_{2} / r^{2}\) where Fe is the electric force, q1 and q2 are the 2 charges respectively, k is a constant (8.99*10^9 N • m^2 / C^2) and r is the distance.
\(3.6 N = (8.99*10^{9})(5*10^{-6})(5*10^{-6}) / r^{2}\)
r = 0.2499 m
The distance that should be apart from these charges should be considered when the r = 0.2499 m.
Calculation of the distance apart:Since
Two charges of 5 x 10-6 C are a certain distance apart. These two positive charges experience 3.6 N of repelling electrical force between them
So
here we use Columb law
Electric force = k * two charges * two charges)r^2
3.6 N = (8.99*10^9) * ( 5 * 10^-6) * (5*10^-6)r^2
r = 0.2499 m.
Hence, The distance that should be apart from these charges should be considered when the r = 0.2499 m.
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*Materials that regulate the flow of current through them *
1)Conductors
2)Insulators
3)Resistors
4)Electromagnets
Answer:
electromagnet
Explanation:
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what are the three examples that show relation between pressure and area in daily life.
Answer: The area of the edge of a knife's blade is extremely small.
Syringes are used to take blood for blood tests.
When air is sucked out of a drinking straw, the air pressure inside if decreases and the atmospheric pressure outside forces the liquid to go inside the straw.
Explanation:
A spring (k= 100 N/m) that is initially compressed launches a solid small toy ball of mass 0.250 kg from rest along a horizontal surface as shown. the ball does not slip ( meaning it is moving to the right and also rolling) as it moves to the right. If the balls final linear speed is 6.8 m/s find the initial compression distance of the spring
Given data:
The mass of the ball is m=0.25 kg.
The spring constant is k=100 N/m.
The speed of the ball is v=6.8 m/s.
The amount of energy stored in the spring in the form of elastic potential energy will equal to the kinetic energy of the ball. It can be applied as,
\(\begin{gathered} PE=KE \\ \frac{1}{2}kx^2=\frac{1}{2}mv^2 \end{gathered}\)Here, x is the compression in the spring.
Substitute the given values in above equation,
\(\begin{gathered} \frac{1}{2}(100)x^2=\frac{1}{2}(0.25)(6.8)^2 \\ x=0.34\text{ m} \end{gathered}\)Thus, the initial compression of the spring is 0.34 m.
With low-frequency stimulation, the muscle relaxes fully between contractions, resulting in ____________ twitches per stimulus.
With low-frequency stimulation, the muscle relaxes fully between contractions, resulting in identical twitches twitches per stimulus.
Alpha motor neurons are the motor neurons that innervate the fibers of the skeletal muscle. A number of branches, each innervating a different muscle fiber, are formed as the alpha motor neuron enters the muscle. A motor unit is made up of one alpha motor neuron and all of the muscle fibers it innervates. Small motor units with 3-5 muscle fibers per motor neuron are found in muscles that are involved in delicate, coordinated control. Our hand and eye muscles, as well as those that control eye movement, have very small motor units.
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coherent sources a and b emit electromagnetic waves with wavelength of 2.00 cm. point p is 4.86 m from a and 5.24 m from b. what is the phase difference at p between these two waves?
The phase difference at p between the two waves will be 4.7728 rad.
Those sources of light with the same frequency, wavelength and phase or having constant phase difference are called coherent sources.
The conditions provided here satisfies the young’s double slit experiment conditions and we can calculate the phase difference from the formula
Phase difference (φ) = 2πλx
we are having :
Wavelength (λ) = 2.00 cm
Distance of a from p = 4.86 m
Distance of b from p = 5.24 m
Then using the results of young’s double slit experiment ,
Phase difference (φ) = 2πλx
Where x is the difference between the distances of the points a and b from p
Therefore x = 5.24 – 4.86
x = 0.38 cm
being coherent sources , they both have same wavelength
therefore ,
(phase difference ) φ = 2 × 3.14 × 2.00 × 0.38
φ = 4.7728 rad
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1. What is the velocity of a go-kart with a mass
of 25 kg and 50 J of kinetic energy?
Answer:
Explanation:
The formula for KE is
\(KE=\frac{1}{2}mv^2\) which makes solving our problem for velocity super easy. We will rewrite the formula in terms of v to get:
\(v=\sqrt{\frac{2KE}{m} }\) and filling in:
\(v=\sqrt{\frac{2(50)}{25} }\) so
v = 2 m/s to the correct number of sig fig's
Describe three ways that solar energy can be used
Answer: Heat for making hot water
Heating buildings and cooking.
To generate electricity with solar cells or heat engines, and to take the salt away from sea water.
Explanation:
Why does the Moon orbit Earth?
a
There is magnetic attraction between the Earth and
the Moon
b
There is gravitational attraction between the Earth
and the Moon
с
There is chemical attraction between the Earth and
the Moon
d
There is mechanical attraction between the Earth
and the Moon
Answer:
B
Explanation:
Gravity, the attractive force between all masses, is what keeps the planets in orbit. Newton’s universal law of gravitation relates the gravitational force to mass and distance
The force of gravity is what gives us our sense of weight. Unlike mass, which is constant, weight can vary depending on the force of gravity (or acceleration) you feel. When Kepler’s laws are reexamined in the light of Newton’s gravitational law, it becomes clear that the masses of both objects are important for the third law, which becomes a3 = (M1+ M2) × P2. Mutual gravitational effects permit us to calculate the masses of astronomical objects, from comets to galaxies.
Can someone please help me? :(
Answer:something empty depressed
Explanation:
A wave of wavelength 0.3 m travels 900 m in 3.0 s. Calculate its frequency.
Answer: 1000 Hz
Explanation:
You can calculate frequency by dividing velocity by wavelength
Frequency = velocity/wavelength
Find velocity first.
900 m/3 s = 300 m/s
Plug values in to find frequency.
F = (300 m/s)/0.3 m
F = 1000 Hz
\(r=s^2/t^2\) 1. If s is tripled and t stays constant, r is multiplied by... 2. If t is doubled, and s stays constant, r is multiplies by...
Answer:
9 and 4
Explanation:
The relation is:
● r = s^2 / t^2
Triplind s means multiplying it by 3. Since it's an equation we should multiply both sides by the same number
Let k be the number we should multiply by r
●k* r = (3s)^2 / t^2
●k* r = 9s^2 /t^2
We have multiplied s^2 by 9 so we should do the same for r.
k = 9
■■■■■■■■■■■■■■■■■■■■■■■■■■
Doubling t means multiplying it by 2.
Let x be the number we shoukd multiply by r.
● x* r = s^2/(2t)^2
● x*r = s^2/ 4t^2
We have multiplied t^2 by 4 so we should do the same for r.
x= 4
two spherical objects have equal masses and experience a gravitational force of 85 n towards one another. their centers are 36 mm apart. determine each of their masses.
To determine the masses of the two spherical objects, we can use Newton's law of universal gravitation: F = G * (m1 * m2) / r^2
where F is the gravitational force, G is the gravitational constant (6.67430 × 10^-11 N m²/kg²), m1 and m2 are the masses of the objects, and r is the distance between their centers. In this case, the gravitational force is given as 85 N, and the distance between the centers of the objects is 36 mm = 0.036 m. Plugging in the values, we have: 85 N = (6.67430 × 10^-11 N m²/kg²) * (m1 * m2) / (0.036 m)^2. We are told that the two objects have equal masses, so we can let m1 = m2 = m. Simplifying the equation, we have: 85 N = (6.67430 × 10^-11 N m²/kg²) * (m * m) / (0.036 m)^2. Solving for m, we can rearrange the equation: m^2 = (85 N * (0.036 m)^2) / (6.67430 × 10^-11 N m²/kg²). m^2 ≈ 0.0222 kg². Taking the square root of both sides, we get: m ≈ √0.0222 kg. Calculating this expression will give us the approximate mass of each spherical object.
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Which principle of relative-age dating will you use when correlating the rock layers?
•Which principle of relative-age dating will you use when correlating the rock layers?
Answer:
•Superposition refers to the position of rock layers and their relative ages (Figure below). Relative age means age in comparison with other rocks, either younger or older. The relative ages of rocks are important for understanding Earth's history.
Explanation:
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A 20 kg sled stars at the top of a hill which is 10 m above the bottom and slides a distance of 50 m, ending at the bottom of the hill with a speed of 8 m/s. During the slide, the work done by gravity is about
Answer:
80 Joules.
Explanation:
Given that a 20 kg sled stars at the top of a hill which is 10 m above the bottom and slides a distance of 50 m, ending at the bottom of the hill with a speed of 8 m/s. During the slide, the work done by gravity is about ?
The parameters given are:
Mass M = 20 kg
Height h = 10 m
Velocity V = 8 m/s
The workdone by gravity will be equal to the total energy
At the bottom of the hill, the total energy will be equal to the maximum kinetic energy.
Maximum K.E = 1/2mv^2
K.E = 1/2 × 20 × 8
K.E = 80J
Therefore, the workdone by the gravity is equal to 80 Joules.
A paleontologist estimates that when a particular rock formed, it contained 12 mg of the radioactive isotope potassium-40. The rock now contains 3 mg of potassium-40. The half-life of potassium-40 is 1.3 billion years. About how old is the rock?
Answer:
2.6 billion yrs old
Explanation:
3 = 12 (1/2)^n n=2 half lives
2 * 1.3 bln = 2.6 bln