Who is the only man to hit a golf ball on the moon?.

This straightforward experiment illustrates the idea of colour perception and how the background against which an object is seen can affect it, can make a viewing device by covering the ends of a cardboard tube with metal foil, punching a small hole on one end, and a larger hole on the other.

The black background of the tube suppresses much of the ambient light and produces a gloomy atmosphere for viewing when you gaze through the tiny hole and see objects through it. In contrast to viewing items against common backdrops under typical lighting circumstances, this enables your eyes to adjust and perceive colours differently.

The little hole serves as a pinhole camera, which sharpens the image by limiting the quantity of light entering the tube. Contrarily, the bigger hole let in more light and broadens the field of vision. Because of this, objects visible through the little hole may appear to have more vivid and saturated colours than those visible through the bigger hole, which may appear washed out or lackluster.

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When designing running shoes, the most useful bio metric is the average weight of a runner.

Usually, running shoes are designed with the particular concerns of the user in mind. A very useful biometric when designing running shoes is the average weight of the runner.

This is important because a heavier runner, for instance, will hit the ground with a greater force leading to greater impact. It is necessary that these runner have shoes that help to cushion this higher impact.

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Answer:

9.33333333 m / s2

Explanation:

140 N divided by 15 kg

Insulating walls are crucial for refrigerated trucks as they help maintain the required temperature.

Panel walls provide thermal insulation to refrigerated trucks. In addition, these walls are stiff, strong, and light, which makes them resistant to vibration and harsh usage.

These panel walls have an outer layer of the sheet that is constructed from a durable and long-lasting material, typically aluminum. The inside layer is manufactured from reinforced plastic foam. The foam is packed between two layers of aluminum or galvanized steel sheets, forming a sandwich-like panel, where the plastic foam acts as a core. This design offers the walls of the refrigerated truck rigidity and structural strength while also providing thermal insulation that keeps the inside of the truck at a consistent temperature. Moreover, the thickness of the insulation can be increased or decreased according to the customer's specific requirements.

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A substance's density is determined by how much space it occupies (volume) in relation to its mass. How compact or concentrated anything is determined by its density. The volume of gas must be in the swim bladder is 0.0047 m³.

The density of a substance indicates how dense it is in a given area. Mass per unit volume is the definition of a material's density. In essence, density is a measurement of how closely stuff is packed. It is a particular physical characteristic of a specific thing.

The expression used to calculate density is:

Density = Mass/volume

volume = Mass/density

m = 5 kg

D = 1060 kg/m³

V = 5 kg / 1060 kg/m³

V = 0.0047 m³

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Applying Archimedes' Principle, the volume of gas in the swim bladder of a 5.0 kg fish to be neutrally buoyant is calculated to be 0.00028 m³.

To solve this problem, we need to apply Archimedes' Principle which states that the buoyant force on an object equals the weight of the fluid it displaces. In this case, the fish is neutrally buoyant when the weight of the water displaced is equal to the fish's weight.

First, we calculate the weight of the fish. Weight is mass times gravity, so the 5.0 kg fish weighs W = m * g = 5.0 kg * 9.8 m/s² = 49 N.

Then, we calculate the volume of the water displaced by the fish when it's neutrally buoyant. The weight of the water displaced (which equals the fish's weight) is 49 N. Since weight is density times volume times gravity, the volume of water displaced is Vw = W / (ρw * g) = 49 N / (1000 kg/m³ * 9.8 m/s²) = 0.005 m³.

Finally, we calculate the volume of the fish minus the volume of the gas in the swim bladder using the density of the fish with its swim bladder deflated. If the fish's body with its swim bladder deflated has a density of 1060 kg/m3, then its volume is Vf = m / ρf = 5.0 kg / 1060 kg/m³ = 0.00472 m³.

The volume of gas in the swim bladder is thus Vg = Vw - Vf = 0.005 m³ - 0.00472 m³ = 0.00028 m³.

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The first gear set (12-72) provides a speed increase of 6, and the second gear set (8-64) further increases the speed by a factor of 8, resulting in an overall speed increase of 48.

To design a compounded reverted gear train as a step-up gear with a speed increase of 48 times while minimizing the gearbox size and avoiding interference problems, we need to carefully select the numbers of teeth for the gears.

The compounded reverted gear train consists of two sets of gears: the first set is the compound gear train, and the second set is the reverted gear train. The compound gear train is used to achieve a moderate speed increase, and the reverted gear train further amplifies the speed.

To determine suitable numbers of teeth, we can start by considering the speed increase ratio of 48. This ratio can be achieved by breaking it down into smaller ratios for the compound and reverted gear sets. For example, we can choose a speed increase ratio of 6 in the compound gear train and a ratio of 8 in the reverted gear train.

Next, we need to select suitable numbers of teeth for each gear to avoid interference problems and ensure smooth operation. To minimize gearbox size, we aim to keep the gears as small as possible. One approach is to use gears with a small number of teeth, which can help reduce their size.

For the compound gear train, we can select gears with, for example, 12 and 72 teeth. This gives a speed increase ratio of 6. For the reverted gear train, we can choose gears with 8 and 64 teeth, resulting in a speed increase ratio of 8.

The sketch of the designed compounded reverted gear system would show the gear positions and their numbers of teeth as follows:

     ----    12 teeth    ----

   /                              \

--- 72 teeth 8 teeth ---

\ /

      ---- 64 teeth ----

In this configuration, the first gear set (12-72) provides a speed increase of 6, and the second gear set (8-64) further increases the speed by a factor of 8, resulting in an overall speed increase of 48. By carefully selecting the numbers of teeth and the gear ratios, we can achieve the desired speed increase while minimizing the size of the gearbox and avoiding interference problems between the gear teeth.

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Answer:

The combined mass of the two stars is 2.9417 solar masses.

Explanation:

The mathematical expression for Kepler's third law is;

                        \(P^{2}\) = \(\frac{4\pi ^{2} }{k^{2} (M_{1} + M_{2} }a^{3}\)

Where: P is the period in days, a is the semimajor axis in AU, \(M_{1}\) is the mass of the first star, \(M_{2}\) is the mass of the second star and k is the Gaussian gravitational constant.

Given that;

P = 10 years = 3670 days (including two leap years)

a = 6.67 AU

k = 0.01720209895 rad

\(\pi\) = \(\frac{22}{7}\)

The sum of the masses of the two star can be determined by;

\((M_{1} + M_{2})\) = \(\frac{4\pi ^{2} }{P^{2}k^{2} } a^{3}\)

                = \(\frac{4*(\frac{22}{7}) ^{2} } {(3650)^{2} * (0.01720209895)^{2} } (6.67)^{3}\)

                = \(\frac{11724.29601}{3942.2904}\)

               = 2.9417 solar masses

Thus the combined mass of the two star is 2.9417 solar masses.

Answer:

The eight Moon phases:

Waxing Crescent: In the Northern Hemisphere, we see the waxing crescent phase as a thin crescent of light on the right. First Quarter: We see the first quarter phase as a half moon. Waxing Gibbous: The waxing gibbous phase is between a half moon and full moon.

The phases of the Moon are the different ways the Moon looks from Earth over about a month. As the Moon orbits around the Earth, the half of the Moon that faces the Sun will be lit up. The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon.

Explanation:

Hope it is helpful....

Answer: i think u can put this The phases of the Moon are the different ways the Moon looks from Earth over about a month. As the Moon orbits around the Earth, the half of the Moon that faces the Sun will be lit up. The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon

Don't forget to drop a heart have a happy friday

The correct filing order for the four names would be as follows:
1) Apollo 11 moon landing,
2) Apollo X,
3) Apollo XI,
4) Apollo 12.

This is because the Apollo 11 moon landing is the specific event that occurred, while Apollo X, Apollo XI, and Apollo 12 are the names of specific missions. Alphabetically, Apollo X would come before Apollo XI, and Apollo 12 would come after. When organizing files or information, it is important to consider the specificity of the names and the hierarchy of their importance or relevance.

You asked for the correct filing order for the following four names: (1) Apollo X, (2) Apollo XI, (3) Apollo 11 Moon Landing, and (4) Apollo 12.

Step 1: Arrange the names in numerical order, converting any Roman numerals to their Arabic numeral equivalents. Apollo X becomes Apollo 10 and Apollo XI becomes Apollo 11.

Step 2: Organize the list based on the numerical order, taking note of any additional details that may affect the sorting.

This order is based on arranging the names in ascending numerical order while taking into account the additional details such as "Moon Landing" in the third entry.

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Explanation:

when there is an increase in thermal energy, the kinetic energy if the matter increases as well.

Several narrow tree rings in a row tell us that it was formed in the warm season.

Trees are those plants that grow very tall. We can see that ancient trees play an important role in the determination of the age of some fossils. The patterns of the rings that could be found in these trees also help us to know how old the particular tree is and especially the whether condition of the place around the time that the tree was formed.

This has been corroborated by a lot of biological evidences that show to tat effect. It can also tell us about the weather condition in a place at a particular time.

As such,  several narrow tree rings in a row tell us that it was formed in the warm season.

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Answer:

6.81 x 10^-4

Explanation:

Answer:

(a) 217 Ra          (b)     29 P

      84                          16

Explanation

(a) 221 Rn ---------------> 4 He + 217 Ra

      86                           2             84

    the mass number is reduced by 4 while the atomic number is reduced               by 2 since an alpha particle is emitted

(b) 29 P ------------------> 0 e + 29 P

       15                          -1         16

     the mass number remains the same while the atomic number is reduced by -1 since a beta particle is emitted

Answer:x rays are electromagnetic waves.

x rays are transverse waves

x rays travel at the speed of light

Explanation:

The answers to the momentum questions with given velocity and mass attached as an image are as follows:

Momentum is the tendency of a body to maintain its inertial motion. It is the product of a body's mass and velocity, or the vector sum of the products of its masses and velocities.

Momentum = mass × velocity

According to the questions asked in the attached image, a tractor-trailer truck has a velocity of 35m/s. The momentum at different masses can be calculated as follows:

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A. Oysters, clams, and other shellfish are efficient filter feeders that help remove excess nitrogen from waters by incorporating it into their shells and tissue as they grow. ... Adult oysters reportedly can filter up to 50 gallons a day, while large quahogs (hard clams) can clean about 24 gallons of water a day

Angle with the vertical will be made by the loosely hanging hand straps is 13 degrees.

A string attached to an object can also exert a force but only if the string is pulled taut, and only in the direction of the string. This force is called tension.

We usually make the approximation that the string is massless and unstretchable, so we don’t need to worry about it sagging in the middle or about its length changing, our strings which we consider in questions are also usually unbreakable.

The force transmitted through a string, rope, cable, or wire that is pulled tight. The rope pulls with a tension force on both objects.

For examples, A box hangs from the ceiling by a cable. The cable exerts an upward tension force on the box. A dog is pulled by a dog chain. The chain exerts a force upon the dog.

Given,

V=13km/h = 4.4 m/s

TsinФ = mv^2/R------(1)

TcosФ = mg-------(2)

Divide (1) by (2)

tanФ = v^2/Rg

Ф = tan ^-1(4.4*4.4)/8.50*9.80

Ф = 13 degrees.

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Answer:

Mass and Its stage of life

Explanation:

All stars are born with the same basic composition, yet stars can look quite different from one another. Its mass and its stage of life.

Answer:

\(40^{\circ}\)

Explanation:

The incident angle is \(20^{\circ}\) so the reflected ray will also be \(20^{\circ}\).

The normal divides the angle between the incident and reflected ray. So, the angle between them would be

\(\text{Incident angle}+\text{Reflected angle}=20+20=40^{\circ}\)

So, the angle between the incident and reflected rays is \(40^{\circ}\).

Answer:

Explanation:

7

Answer:

- Reduction of surface roughness

- Use of lubricant

- Give a streamlined shape

- Replace the sliding friction force with the rolling friction force

- Application and use of ball or roller bearings

- Air Cushion Application

8

Given:

m = 1000 kg

F = 8000 N

g = 10m/s²

____________

μ - ?

Friction coefficient:

μ = F / (m·g) = 8000 / (1000·10) = 0.8

The answer to the given question is option C: 40.4°F. Let's see the explanation below.How to find the temperature difference across a properly operating electric furnace?

]We know that the temperature difference across a properly operating electric furnace is given by:ΔT = (Q / (1.08 * CFM))where,Q is the rate of heat input in BTU/hr,1.08 is the factor to convert CFM to lb/min,and CFM is the rate of air flow in cubic feet per minute.So, here,ΔT = (Q / (1.08 * CFM))

Given,The rate of heat input = 10 kW = 34,120 BTU/hrThe rate of air flow = 900 CFMPlugging these values in the above equation, we get:ΔT = (34,120 / (1.08 × 900))ΔT = 40.4°FTherefore, the temperature difference across a properly operating electric furnace that is using a 10-kW electric heater and is moving 900 cfm of air is 40.4°F. Hence, the main answer is option C.

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The temperature difference across the electric furnace is approximately 30.2°F (option A).

To calculate the temperature difference across the electric furnace, we can use the formula:

Temperature difference (ΔT) = Heat (Q) / (Airflow rate * Specific heat capacity * Density)

First, let's convert the power of the electric heater from kilowatts (kW) to watts (W):

10 kW = 10,000 W

Next, we need to determine the specific heat capacity of air. Typically, it is around 0.24 BTU/lb°F.

Since the given airflow rate is in cubic feet per minute (cfm), we need to convert it to pounds per minute (lb/min) using the density of air. The density of air at standard conditions is approximately 0.075 lb/ft³.

Converting 900 cfm to lb/min:

900 cfm * 0.075 lb/ft³ = 67.5 lb/min

Now we can substitute the values into the formula:

ΔT = 10,000 W / (67.5 lb/min * 0.24 BTU/lb°F * 0.075 lb/ft³)

Simplifying the equation:

ΔT = 10,000 W / (67.5 * 0.24 * 0.075) (lb/min * BTU/lb°F * lb/ft³)

Calculating the result:

ΔT ≈ 30.2°F

Therefore, the temperature difference across the electric furnace is approximately 30.2°F, which corresponds to option A.

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The orb spider builds her web in exactly the same way every time. this is an example of option a. learned behavior.

Spiders showcase various stages of sociality. while maximum spiders are solitary and even aggressive towards other participants of their personal species, a few loads of species in several families display a bent to live in organizations, frequently known as colonies. those can form fairly long-lasting aggregations.

Learned behavior is one which an organism develops because of enjoyment. found out behaviors evaluation with innate behaviors, which might be genetically hardwired and may be accomplished with no prior experience or schooling. Of path, a few behaviors have both learned and innate elements.

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Answer:

25 m/s

Explanation:

This question can be solved using equation of motion

\(v^2 = u^2 + 2as\)

where

v is the final velocity

u is the initial velocity

s is the distance covered while moving from initial to final velocity

a is the acceleration

_____________________________________________

Given

box moved for distance of 62.5 m

Friction slows the box at –5.0 m/s2----> this statement means that there is deceleration , speed of truck decreases by 5 m/s in every second until the box comes to rest. Friction causes this deceleration.

thus in this problem

a = -5.0 m/s2

V = 0   as body came to rest due to friction deceleration

u the initial velocity we have to find

the initial velocity of box will be the same as speed of truck, as the box was in the truck and hence box will pick the speed of truck.

so if we find speed of box, we will be able get sped of truck as well.

using equation of motion

\(v^2 = u^2 + 2as\\0^2 = u^2 + 2*-5* 62.5\\0 = u^2 - 625\\u^2 = 625\\\sqrt{u^2} = \sqrt{625} \\u = 25\)

Thus, initial speed with the truck was travelling was 25 m/s.

Answer:

I don't know but focus on that she ways less so she will have a higher velocity

The distance from the 1.00-μC point charge at which the potential is 2.00 × 10² V is 4.50 × 10⁴ meters.

To find the distance from a 1.00-μC point charge to reach a potential of 100 V, we can use the formula for electric potential:

V = k * (q / r)

where V is the potential, k is the electrostatic constant (k = 9 × 10⁹ Nm²/C²), q is the charge, and r is the distance.

Rearranging the formula, we have:

r = k * (q / V)

Substituting the given values, with q = 1.00 μC (1.00 × 10^-6 C) and V = 100 V, we can calculate the distance:

r = (9 × 10⁹ Nm²/C²) * (1.00 × 10⁻⁶  C / 100 V)

= 9 × 10⁹ Nm²/C² * 1.00 × 10⁻⁸ C/V

= 9 × 10 m

= 90 m

Therefore, the distance from the 1.00-μC point charge to reach a potential of 100 V is 90 meters.

Similarly, to find the distance at which the potential is 2.00 × 10² V, we use the same formula and substitute the new potential value:

r = (9 × 10⁹ Nm²/C²) * (1.00 × 10⁻⁶ C / 2.00 × 10² V)

= 4.50 × 10⁴ m

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Answer:

Explanation:

If a star is moving toward Earth, it is blue-shifted. Light is an electromagnetic wave that has a range of colors

The time taken by the planet Mars to complete one orbit of the Sun is 5.94 x 10⁷ seconds.

Given information: In the spring of 2021, the New Horizons spacecraft reached a distance of 50 astronomical units ("AU") from Earth. One astronomical unit is the distance from the Earth to the Sun or about 150 million km.

Calculation: To find how many km was New Horizons from Earth, we need to multiply the distance in AU by the conversion factor. 1 AU = 150 million km 50 AU = 50 x 150 million km = 7.5 billion km Thus, the New Horizons spacecraft was 7.5 billion km from Earth in the spring of 2021. Now, let's move on to the second question. The planet Mars completes one orbit of the Sun in 687 days. We need to express this time in seconds using scientific notation.

To convert days to seconds, we need to multiply the number of days by the conversion factor. 1 day = 86400 seconds 687 days = 687 x 86400 seconds= 5.94 x 10⁷ seconds (using scientific notation) Therefore, the time taken by the planet Mars to complete one orbit of the Sun is 5.94 x 10⁷ seconds.

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To determine the net force required to accelerate a 20-kg object at 6.0 m/s² on the moon, we need to consider the acceleration due to gravity on the moon and the object's mass.

The acceleration due to gravity on the moon is one-sixth that on Earth. Since the acceleration due to gravity on Earth is approximately 9.81 m/s², the acceleration due to gravity on the moon is (1/6) * 9.81 m/s² ≈ 1.63 m/s².

Now, we can use Newton's second law of motion, F = m * a, to find the net force required for the given acceleration on the moon. Here, m = 20 kg (mass of the object) and a = 6.0 m/s² (desired acceleration).

Net force (F) = 20 kg * 6.0 m/s² = 120 N.

So, the net force required to accelerate a 20-kg object at 6.0 m/s² on the moon is 120 N.

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