who’s are you supposed to do question 5 and what is the answer??

Answer:

B

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = 4 , then

y = 4x + c ← is the partial equation

to find c substitute (- 3, - 1 ) into the partial equation

- 1 = - 12 + c ⇒ c = - 1 + 12 = 11

y = 4x + 11 ← equation of line

Answer:

r ≥ 220/11

Step-by-step explanation:

To solve for r, you first need to isolate r. To do that, divide both sides by 11. Therefore, you get r ≥ 220/11. 220/11 is the most simplified form of that fraction, so r ≥ 220/11 is the answer.

Answer:

The area of the sector of the circle is approximately

Step-by-step explanation:

The given parameters of the circle having a shaded sector are;

The radius of the circle, r = 4 meters

The measure of the arc bounding the sector = 135°

The area of a sector of a circle, 'A', is given as follows;

\(A = \dfrac{\theta}{360 ^{\circ}} \times \pi \times r^2\)

Therefore, the area, 'A' of the given sector of the circle, is given as follows;

\(A = \dfrac{135 ^{\circ}}{360 ^{\circ}} \times \pi \times (4\ cm)^2 \approx 18.85 \ cm^2\)

The area of the sector of the circle, with radius 4 cm and bounded by an arc, A ≈ 18.82 cm².

Answer: Marry Christmas!

Step-by-step explanation:

Answer: Im guessing u dont need an answer now so umm tyftp

Step-by-step explanation:

As a car dealer lowers a vehicle that was worth 18300 to 16000 by applying the formula of change in percentage we get that by 12.569 percentage (approximately) the price gets lowered .

The initial price of the car is set at P = 18300 (units)

The price after lowering drom P becomes A= 16000 (units)

Hence the change in price (or value) of the car, that is the price of the car is lowered by, C = (initial price - lowered price) = (P - A) = (18300 - 16000) units = 2300 units.

The formula for calculating percentage change is given as follows,

Change in percentage = [(Change in value)/ ( Initial value) ]*100

⇒Change in percentage = (C/ P)*100

⇒ Change in percentage =( 2300/ 18300)*100 = 12.569% (approximately)

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The equation \(d=50+20w\) represents the relationship between dollar amount in her bank account and the number of weeks of savings.

(a) It is given that amount in bank account is $50 , amount deposited by Priya is $20 and time period is 12 weeks .

Let " d " be the dollar and " w " be the weeks

Multiply the number of weeks w by 20 to get the total savings and add up how much money she had in the account initially.

Money deposit by Priya in 1 week = $20

Money deposit by Priya in 1 week = \(20\times w\)

Therefore , the equation will be \(d=50+20w\)

(b) Graph of given equation is given below :

Let " w " represents the x - axis and " d " represents the y - axis

For 1 week , amount will be \(d=50+20=60\)

For 2 week , amount will be \(d=50+20(2)=90\)

For 3 week , amount will be \(d=50+20(3) = 110\)

And so on..

From the graph ,the point which represents the amount after 3 weeks is

(3 , 110 )

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Answer:

Hello! I think x= 1.6 or 1.3 in this situation

Step-by-step explanation:

The fact that the number 7 on the left quadrilateral is 6.3, and the 4's are 3.6, I have come to the conclusion that x equals either 1.6 or 1.3.

The pressure is assessed through the ideal gas equation and Dalton's law

Partial Pressure of hydrogen gas in the gas collecting tube can be calculated as:

According to Dalton's law, the total pressure of the system will be the sum of partial pressure of all gases

In the system, the pressure is exerted by the water and  gas.

Total pressure = P(water) + P(Hydrogen)

P(hydrogen) = 746 mm Hg (given) = 19.8 mm Hg +

P(hydrohen) = = 746 mm Hg - 19.8 mm Hg

= 726.2 mm Hg

So, the partial pressure of Hydrogen was found to be 726.2 mm Hg.

To calculate the volume of hydrogen at STP, ideal gas equation is used.

For this, we calculate the moles of Hydrogen in given conditions:

Pressure = 726.2 mm Hg

 = 726.2/760

= 0.955 atm

Therefore, The pressure is assessed through the ideal gas equation and Dalton's law

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To determine which set of data most likely has a mean closest to 29.5, we need to analyze the shape and position of the histograms in relation to the value 29.5.

Looking at the histograms described:

The first histogram ranges from 9 to 48, and the upward trend starts from 1 and ends at 33, followed by a downward trend. This histogram suggests that there may be values lower than 29.5, which would bring the mean below 29.5.

The second histogram ranges from 15 to 48, with an upward trend from 1 to 30 and then a downward trend. Similar to the first histogram, it suggests the possibility of values lower than 29.5, indicating a mean below 29.5.

The third histogram ranges from 12 to 56, and the upward trend starts from 1 and ends at 32, followed by a downward trend. This histogram covers a wider range but still suggests the possibility of values below 29.5, indicating a mean below 29.5.

The fourth histogram ranges from 15 to 54 and exhibits multiple trends. While it has fluctuations, it covers a wider range and includes both upward and downward trends. This histogram suggests the possibility of values above and below 29.5, potentially resulting in a mean closer to 29.5.

Based on the descriptions, the fourth histogram, with its more varied trends and wider range, is most likely to have a mean closest to 29.5.

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Answer:

The distance the car traveled

Step-by-step explanation:

The answer is option d. -1.865, as it is the value that satisfies P(Z ≤ b) = 0.0311. The other options (-1.87, -1.86, -1.8) do not correspond to the given cumulative probability.

In this scenario, P(Z ≤ b) represents the cumulative probability of a standard normal distribution up to the value of b. To find the corresponding value of b, we need to find the z-score that corresponds to a cumulative probability of 0.0311.

By looking up the z-table or using a statistical calculator, we can find that the z-score corresponding to a cumulative probability of 0.0311 is approximately -1.865.

Therefore, the answer is option d. -1.865, as it is the value that satisfies P(Z ≤ b) = 0.0311. The other options (-1.87, -1.86, -1.8) do not correspond to the given cumulative probability.

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The greatest possible probability in any experiment is 1 as the least possible probability in any experiment is 0.

Probability simply means the likelihood of the occurence of an event.

In this case, the greatest possible probability in any experiment is 1 as the least possible probability in any experiment is 0.

Also, a probability around 0.5 means that the event is neither likely nor unlikely.

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Domain: For sales, x > 0 (positive values); for returns, x < 0 (negative values).

Range: F(x) ≥ 0 (non-negative values).

The given function is defined as follows:

For x > 0 (sale): F(x) = |x| * 0.015

For x < 0 (return): F(x) = |x| * 0.005

The domain of the function is the set of all possible input values, which in this case is all real numbers. However, due to the specific conditions mentioned, the domain is restricted to positive values of x for the "sale" scenario (x > 0) and negative values of x for the "return" scenario (x < 0).

Therefore, the domain of the function F(x) is:

For x > 0 (sale): x ∈ (0, +∞)

For x < 0 (return): x ∈ (-∞, 0)

The range of the function is the set of all possible output values. Since the function involves taking the absolute value of x and multiplying it by a constant, the range will always be non-negative. In other words, the range of the function F(x) is:

For x > 0 (sale): F(x) ∈ [0, +∞)

For x < 0 (return): F(x) ∈ [0, +∞)

In conclusion, the domain of the function F(x) is x ∈ (0, +∞) for sales and x ∈ (-∞, 0) for returns, while the range is F(x) ∈ [0, +∞) for both scenarios.

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The area between the singles and doubles sidelines in tennis is called the tramlines. Tramlines serve specific purposes and affect the rules and strategies of the game.

The tramlines, also known as alleyways or doubles alleys, are located on both sides of the tennis court, running parallel to the singles sidelines. They create additional playing areas for doubles matches, extending the width of the court. These tramlines are marked by lines that are typically one and a half feet wide.

During doubles play, each team member has their own respective tramline. The purpose of the tramlines is to define the legal hitting areas for players. When serving, the server must aim to hit the ball within the singles sideline and the tramline on their side of the court. After the serve, the ball is considered "in" if it lands within the tramlines and between the singles and doubles sidelines.

The presence of the tramlines influences the strategies and tactics used in doubles matches. Players can utilize the additional space to angle shots and create different angles for their opponents to cover. The tramlines also affect positioning and movement on the court, as players need to cover a wider area during rallies.

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The required quadratic function is y = -17/324 (x-12)(x-48)

The graph of a function is a visual representation of the relationship between the input values (often referred to as the "domain") and the output values (often referred to as the "range") of the function. The graph is typically drawn on a coordinate plane, with the input values plotted on the horizontal axis and the output values plotted on the vertical axis.

The graph of the function is in the image below:

The domain is (12,48)

Range: (0, 17)

The maximum value is 17

Axis of symmetry: x = 30

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Stewart, Oswaldo, Kevin, and Flynn go to a soccer day at the FC Dallas' arena, Toyota Stadium, in Frisco, Texas. The coach has a computer and video system that can track the height and distance of their kicks. All four soccer players are practicing up-field kicks, away from the goal. Stewart goes first and takes a kick starting 12 yards out from the goal. His kick reaches a maximum height of 17 yards and lands 48 yards from the goal. Oswaldo goes next and the computer gives the equation of the path of his kick as y=-= +148 - 24, where y is the height of the ball in yards and x is the horizontal distance of the ball from the goal line in yards. After Kevin takes his kick, the coach gives him a printout of the path of the ball Hegy Kevin's Kick Finally, Flynn takes his kick but the computer has a problem and can only give him a partial table of data points of the ball's trajectory. Flynn's Table: Distance from the 10 11 12 13 14 15 16 17 18 19 20 goal line in yards Height in yards 0 4.7 8.75 12.2 15 17.2 18.75 19.7 20 19.7 18.75 The computer is still not working but Stewart, Oswaldo, Kevin, and Flynn want to know who made the best kick. For each soccer player, • Write an equation to represent the quadratic function. • Create a graph to represent the quadratic functions • Identify the following: Domain o Range Maximum value (height) Axis of Symmetry x-intercepts Which soccer player made the best kick? Whose kick went the highest? Whose kick went the longest? Explain your answer and support with reasoning.

Rate is ratio that compares two quantities of different units.

A rate is a special ratio in which the two terms are in different units. Rate can also be defined as the ratio between two quantities of different units

For example, velocity is an example of rate, because it defined by the ratio of distance covered and time.

The unit of distance is metres and the unit of time is second. Therefore ;

velocity = distance /time. Therefore velocity is a rate.

Another example is ; Ade eat 5 mangoes for 20 days. The rate at which Ade eat is

1 day = 5/20

= 1/4 mangoes. This means Ade eats 1/4 mangoes per day.

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Answer:

The best way to measure an angle is to use a protractor. To do this, you'll start by lining up one ray along the 0-degree line on the protractor. Then, line up the vertex with the midpoint of the protractor. Follow the second ray to determine the angle's measurement to the nearest degree.

Step-by-step explanation:

Answer:

21) Angle A = 44 degrees

22) Angle A = 23 degrees

Step-by-step explanation:

The angles inside of every triangle always add up to 180 degrees, you can use this trigonometric identity to solve for x values:

Problem 21)

X + 59 + X + 51 + 84 = 180

2x + 194 = 180

2x = -14

x = -7

now solve for angle A:

Angle A = x + 51 = -7 + 51 = 44 degrees

Problem 22)

The square symbol inside a triangle denotes a 90 degree angle. Setting the angles equal to 180 degrees, you can find angle A again.

90 + x + 37 + x + 67 = 180

2x + 194 = 180

2x = -14

x = -7

now solve for angle A:

Angle A = -14 + 37 = 23 degrees

Answer:

um is like x an number if so it woukd be 2

Step-by-step explanation:

The probability that the mean blood pressure will be less than 125 is 0.9938

The mean of the pressure readings = 123

The standard deviation = 9.6

Total population = 144

The value is less than 125

The equation of the z-score is

z-score = (Observed value - Mean ) / (Standard deviation /\(\sqrt{N}\))

Substitute the values in the equation

z-score = (125 - 123) / (9.6/\(\sqrt{144}\))

= 2 / (9.6/12)

= 2 / 0.8

= 2.5

Using the statistical table

The probability of that their mean blood pressure less than 125

P(z < 2.5) = 0.9938

Therefore, the probability is 0.9938

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Based on the information given, we can determine that the equivalent Z score for someone who has completed 18 years of education is 1.3774. This indicates that the individual's education level is 1.3774 standard deviations above the mean.

To get the percentile rank for a score of 18 using the Frequencies procedure, we would need to know the complete distribution of the EDUC variable. However, assuming that the distribution is approximately normal, we can use the Z score we calculated earlier to estimate the percentile rank.
Using a standard normal table or calculator, we can find that a Z score of 1.3774 corresponds to a percentile rank of approximately 93.7. This means that an individual who has completed 18 years of education is at or above the 93.7th percentile in terms of education level compared to the rest of the population.

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Answer:

18√6

Step-by-step explanation:

From Pythagoras theorem,

b^2 + p^2=h^2

or, 1^2 + p^2 = 5^2

or, p^2=25 - 1

or, p=√24

or, p=2√6 (√24 = √4*√6

= 2*√6

= 2√6)

Again,

we know,

Area of parallelogram (A) = bash*height

=9*2√6

=18√6

The region R in the first quadrant bounded by the graph of y = Vx - 1, the x-axis, and the vertical line x = 10.The region is revolved about the y-axis to generate a solid. The required integral that gives the volume of the solid generated is obtained using the method of cylindrical shells.

If y = Vx - 1, then x = (y + 1)².The region R is bounded by the curve y = Vx - 1, the x-axis and the line x = 10, i.e., 0 ≤ x ≤ 10.The curve y = Vx - 1 is revolved about the y-axis to generate a solid.

Let R be any vertical strip of the region R of width dy, located at a distance y from the y-axis.A cylindrical shell with height y and thickness dy can be generated by revolving the vertical strip R about the y-axis.The volume of the cylindrical shell is given by:

dV = 2πy * h * dy

where h is the distance from the y-axis to the strip R.Since the strip R is obtained by revolving the region R about the y-axis, the distance from the y-axis to the strip R is given by:x = (y + 1)²∴ h = (y + 1)²The volume of the solid generated by revolving the region R about the y-axis is obtained by adding the volumes of all cylindrical shells:dV = 2πy * h * dyV = ∫₀ᵗ (2πy * h) dy'

where t is the height of the solid.The value of t is obtained by substituting x = 10 in the equation of the curve:y = Vx - 1 = V(10) - 1 = 3Since the region R is bounded by the curve y = Vx - 1, the x-axis and the line x = 10, the height of the solid is 3.So, t = 3.

The required integral that gives the volume of the solid generated by revolving the region R about the y-axis is:

V = ∫₀³ (2πy * (y + 1)²) dy= ∫₀³ (2πy³ + 4πy² + 2πy) dy= 2π [y⁴/4 + 4y³/3 + y²] from 0 to 3= (π/6) [54 + 108 + 9]= 37π cubic units.

Therefore, the integral that gives the volume of the solid generated by revolving the region R about the y-axis is 37π.

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The figure that shows a reflection of pre-image ABC over the y-axis is the third figure.

From the complete information, the triangle ABC is reflected over the y axis.

The vertices of the triangle are A(1, 1), B(3, 4) and C(3, 1). The vertices of the images are A(1, 1) = A'(-1, 1). B(3, 4) = B(-3, 4) ans C(3, 1) = C'(-3, 1).

In conclusion, the figure that shows a reflection of pre-image ABC over the y-axis is the third figure.

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To find the general solution of the given higher-order differential equation y''' − 6y'' − 7y' = 0, we first need to find the characteristic equation by assuming that y = e^(rt), where r is a constant. Substituting this into the differential equation, we get r^3 - 6r^2 - 7r = 0.

Factoring this, we get r(r - 7)(r + 1) = 0. So the roots of the characteristic equation are r1 = 0, r2 = 7, and r3 = -1.

Therefore, the general solution of the differential equation is y(t) = c1 + c2e^(7t) + c3e^(-t), where c1, c2, and c3 are constants that can be determined using initial or boundary conditions.

In summary, the general solution of the given higher-order differential equation y''' − 6y'' − 7y' = 0 is y(t) = c1 + c2e^(7t) + c3e^(-t), where c1, c2, and c3 are constants.

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An estimation can be made that a student relying purely on guessing can achieve a score of approximately 11 or 12 correct responses in the examination.

Considering the availability of four plausible choices for each query, the probability of untargeted guessing to yield a correct answer for any given question is a quarter (1/4).

It is notable that, in light of the mutual exclusivity and independence of the guesses, the number of accurate predictions can be effectively represented through a binomial distribution. Within this framework, the probability of success (p) is equated to 1/4, while the sample size (n) is 47.

The arithmetical representation of the average of a binomial distribution characterized by variables n and p is np, attained through conventional statistical principles. Consequently, it is possible to formalize the expected value of the aggregate quantity of precise suppositions that a pupil is capable of generating as follows:

The calculation of the mean value of a numerical dataset can be represented by the symbol 'mean'. This value can be determined by multiplying the total number of observations contained within the dataset, denoted by 'n', by the probability of a specific event taking place, referred to as 'p'. In the present scenario, presuming the value of n to be 47 and p to be 1/4, the arithmetic mean of the dataset can be ascertained as 11.75.

Drawing on statistical probabilities, it is possible to approximate that a student who relies solely on chance to answer the examination questions may attain a score of roughly 11 or 12 correct responses.

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The given relation is R: {(1),(2)}. The transactions T1 and T2 are: T1: UPDATE R SET A= A+1 ,T2: UPDATE R SET A= A*2  if T1 and T2 are both executed under Serializability isolation then the d) {(2),(3)} is not possible.

There are four possible results: {2, 3}, {2, 4}, {3, 4}, and {3, 5}. Now, let's analyze each option:Option A: {(4),(6)} can be obtained by executing T2 first and then T1. So, it is a possible result.Option B: {(3),(5)} can also be obtained by executing T2 first and then T1. So, it is a possible result.

Option C: {(3),(4)} can be obtained by executing T1 first and then T2. So, it is a possible result.Option D: {(2),(3)} cannot be obtained by executing T1 and T2 under Serializability isolation. The reason is that if we execute T1 first, we get {2, 3} as the intermediate state, and if we execute T2 after that, we get {4, 6} as the final state.

On the other hand, if we execute T2 first, we get {2, 4} as the intermediate state, and if we execute T1 after that, we get {3, 5} as the final state. Therefore, {(2),(3)} is not a possible result if T1 and T2 are both executed under Serializability isolation.So, the correct answer is option D, i.e., {(2),(3)}.

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The expected value of a gamble can be calculated by multiplying the probability of winning by the amount you could win and subtracting the probability of losing multiplied by the amount you could lose.

In this case, we are given that if a red card is drawn from a standard 52-card deck, you win $1200, and if a black card is drawn, you lose $1200.

First, let's determine the probability of drawing a red card from a standard 52-card deck. In a standard deck, there are 26 red cards (13 hearts and 13 diamonds) and 26 black cards (13 spades and 13 clubs). So the probability of drawing a red card is 26/52, which simplifies to 1/2 or 0.5.

Next, let's calculate the probability of losing, which is the probability of drawing a black card. Similarly, the probability of drawing a black card is also 26/52 or 1/2.

Now, we can calculate the expected value using the formula:
Expected value = (probability of winning * amount won) - (probability of losing * amount lost)

Expected value = (0.5 * $1200) - (0.5 * $1200)
Expected value = $600 - $600
Expected value = $0

Therefore, the expected value of the gamble is $0. This means that, on average, you neither win nor lose money in the long run by playing this gamble.

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