Answer:
Molecules are more spread apart in gasses than in solids.
Explanation:
In gasses, molecules are free to move around in their given space, allowing them to spread more.
Gases are less dense than solids because their volume is comparatively more than solids.
create PHet waves and explain the different when it increase and decrease
Un tren va a una velocidad de 18m/s frena y se detiene en 15s calcula su aceleracion y la distancia recorrida al frenar
Answer:
Acceleration is -1.2 m/s² and distance covered is 135 m.
Explanation:
A train going at a speed of 18m / s brakes and stops in 15s calculates its acceleration and the distance traveled when braking
Given that,
The initial speed of the train, u = 18 m/s
Final speed, v = 0
Time, t = 15 s
We need to find acceleration and distance traveled when braking. Let a is acceleration and distance traveled.
Acceleration,
\(a=\dfrac{v-u}{t}\\\\a=\dfrac{0-18}{15}\\\\a=-1.2\ m/s^2\)
Using third equation of motion,
\(v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{0^2-18^2}{2\times (-1.2)}\\\\d=135\ m\)
Hence, acceleration is -1.2 m/s² and distance covered is 135 m.
particles q1, q2, and q3 are in a straight line. particles q1 = -1.60 x10^-19 C, q2 = +1.60 x10^-19 C, q3 = -1.60 x 10^-19. .001 between each. what is q2.
Answer: it’s 0
Explanation:
Charlize got it right
The charge of the particle q₁ has a magnitude that equals that of proton.
The given parameters:
Charge on particle q1, = -1.6 x 10⁻¹⁹ CCharge on particle q₂, = 1.6 x 10⁻¹⁹ CCharge on particle q₃, = -1.6 x 10⁻¹⁹ CThe particle q₂ is a positive charge whose magnitude is equal to charge of proton.
A proton is a positive charge with a magnitude of 1.6 x 10⁻¹⁹ C. This charge exerts attractive force on a negative charge (electron).
Thus, the charge of the particle q₁ has a magnitude that equals that of proton.
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i’m willing to give anybody extra points plus brainliest if anybody is willing to help me with this. please help!! this is due soon.
1. The box will move to the right with a force of 50 N when a 75 N force is applied to the left.
2. The box will not move if a 50 N force us applied to the left.
For Balanced, B or Unbalanced forces, U the correct option are:
B A person jogging at a constant speedU A car accelerating at a green light.U Pushing a lawnmower across the yardB A cookie sitting on a plate.U Slowing down to stop at a red light.U A bowling ball knocking over pins.B A book sitting on a shelf.U A linebacker tackling a running back.B A person sitting on a chair.B A plane flying at a constant speed.What are balanced and unbalanced?Balanced forces are forces that do not produce an acceleration of an object. Net force will be zero.
Unbalanced forces are forces that produce an acceleration of a body. Net force will be greater than zero.
Considering the boxes:
1. Net force = 50 N
Forces to the left = 25 N + x
Forces to the right = 50 N
Net force = Force to the left + force to the right
50 N = 25 N + x - 50
x = 75 N
2. Net force = 0 N
Forces to the left = 75 N + x
Forces to the right = 125 N
Net force = Force to the left + force to the right
0 N = 75 N + x -125
x = 50 N
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A pulling force of F = 6.2 x 104 N is then applied to the other end. Find the elongation N of the rod if the Young's modulus for steel is 200 × 10⁹ m² O 1.1 mm
The elongation of the rod is 3.1 mm. This result is obtained using Hooke's Law and considering the applied force, Young's modulus, and cross-sectional area of the rod.
To find the elongation of the rod, we can use Hooke's Law, which states that the elongation of an object is directly proportional to the applied force and the material's Young's modulus.
Hooke's Law: ΔL = (F/A) * (L₀/E)
Where:
ΔL is the elongation of the rod
F is the applied force (6.2 x 10⁴ N)
A is the cross-sectional area of the rod (1.1 mm = 1.1 x 10⁻³ m)
L₀ is the original length of the rod
E is the Young's modulus for steel (200 x 10⁹ N/m²)
To calculate the elongation, we need to determine the original length of the rod. Let's assume it is L₀ = 1 m for simplicity.
Now, we can substitute the given values into the equation:
ΔL = (6.2 x 10⁴ N / (1.1 x 10⁻³ m²)) * (1 m / (200 x 10⁹ N/m²))
= (6.2 x 10⁴ N * 10⁶ m²) / (1.1 x 10⁻³ m² * 200 x 10⁹ N)
= (6.2 x 10⁴ * 10⁶) / (1.1 x 200 x 10⁻³)
= 3.1 x 10⁻³ m
= 3.1 mm
After calculating the expression, we find that the elongation of the rod is 3.1 mm. This result is obtained using Hooke's Law and considering the applied force, Young's modulus, and cross-sectional area of the rod.
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what do you add to distilled water for making it to conduct electricity
Answer:
we add salt to conduct electricity
Describe and identify problems relating to data management
Problems with data management may have a detrimental impact on a variety of issues. Bad risk management choices, data loss, information leakage, unauthorised, data pyramids, compliance with laws, an unsafe environment, a shortage of resources, etc. are instances among these.
What issues surround the handling of data?
These are a few potential issues in managing scientific, financial, or administration data that have been briefly explained.
Technical information not adequately recorded.
The administration of performance specifications is not under the PI's control.
Data not kept on file by the organization.
improper maintenance of financial or administrative data.
What would you say is data management?
Data administration is the act of gathering, arranging, and using data to job in an effective, economy, and judgement call.
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During an all-night cram session, a student heats up a 0.858 liter (0.858 x10 −3
m 3
) glass (Pyrex) beaker of cold coffee. Initially, the temperature is 18.2 ∘
C, and the beaker is filled to the brim. A short time later when the student returns, the temperature has risen to 90.6 ∘
C. The coefficient of volume expansion of coffee is the same as that of water. How much coffee (in cubic meters) has spilled out of the beaker?
approximately 2.093 x 10^(-6) cubic meters (or 2.093 milliliters) of coffee has spilled out of the beaker.To calculate the volume of coffee that has spilled out of the beaker, we can use the concept of thermal expansion. The change in volume is given by the formula ΔV = βVΔT, where β is the coefficient of volume expansion, V is the initial volume, and ΔT is the change in temperature.
First, let's convert the initial volume to cubic meters: V = 0.858 x 10^(-3) m^3.
Next, we calculate the change in temperature: ΔT = 90.6 - 18.2 = 72.4 °C.
The coefficient of volume expansion for water (and coffee) is approximately β = 3.4 x 10^(-4) °C^(-1).
Plugging in these values into the formula, we get:
ΔV = (3.4 x 10^(-4) °C^(-1)) * (0.858 x 10^(-3) m^3) * (72.4 °C) = 2.093 x 10^(-6) m^3.
Therefore, approximately 2.093 x 10^(-6) cubic meters (or 2.093 milliliters) of coffee has spilled out of the beaker.
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Explain retrograde motion and why it confused early astronomers as they viewed the motion of objects in the sky.
Answer:
Explanation:
Retrograde motion in astronomy is, in general, orbital or rotational motion of an object in the direction opposite the rotation of its primary, that is, the central object (right figure). It may also describe other motions such as precession or nutation of an object's rotational axis. Prograde or direct motion is more normal motion in the same direction as the primary rotates. However, "retrograde" and "prograde" can also refer to an object other than the primary if so described. The direction of rotation is determined by an inertial frame of reference, such as distant fixed stars.
Retrograde motion occurs when a planet far from another planet and from which it is seen rotates at lower speed, creating the impression that it is "retrograding" with respect to the other planet.
Early astronomers get confused as they viewed the motion in the sky because they tried to explain it in terms of the geocentric theory.
Let suppose that we have a planetary system formed by a star and two planets rotating uniformly around the star. Besides, we assume that both planets are rotating at different velocities, and that planet A is more far away from the star than planet B, then the velocity of the planet A relative to planet B is:
\(\vec v_{A/B} = \vec {v}_{A}- \vec {v}_{B}\) (1)
A retrograde motion of planet A occurs when \(\|\vec v_{A/B}\|\ne 0\) and if \(\|\vec v_{A}\| < \|v_{B}\|\) at least. In other words, retrograde motion exists when speed of planet A is less than speed of planet B, creating the impression that planet A is "retrograding" with respect to planet B. This question is easy to solve and to explain by considering the star as an inertial framework, base of the heliocentrical model.
Early astronomers were confused and unable to explain the phenomenon due to their adherence to geocentrical model, which assumed the Earth was the center of the solar system.
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A 2400W electric toaster is connected to a standard 120 V wall outlet. A family
measured their monthly toaster usage to be 6.5 hrs.
1) How much electrical energy (in kilowatt hours - kWh) did the toaster dissipate
during the measured month? (round to 1 decimal place & do not include units)
2) If the local power company charges $0.13/ kWh, then calculate (in $) the monthly
total cost of this toaster. (round to 2 decimals & do not include units)
Answer:
1) energy = 15.6 kWh, 2) total_cost = $ 2.03
Explanation:
1) The energy dissipated is the product of the power and the time of use In a month it was used t = 6.5 h and the power of the toaster is
P = 2400 W = 2,400 kW
energy = P t
energy = 2,400 6.5
energy = 15.6 kWh
using rounding to a decimal
energy = 15.6 kWh
2) The cost of energy is unit_cost = $ 0.13 / kWh
so the total cost
total_cost = energy unit_cost
total_cost = 15.6 0.13
total_cost = $ 2.028
rounding to two decimal places
total_cost = $ 2.03
You are gardening in the peak of summer, it hasn't rained in a week, and your plants are looking rough. You decide to water the plants for an hour. The next day you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. With what you know from class, please try and explain what is happening to your plants.
In the peak of summer, it hasn't rained in a week, and the plants are looking rough, so watering the plants for an hour is a good idea.
However, the next day, you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. Plants absorb water through their roots. The root system of a plant is responsible for drawing water and nutrients from the soil. A plant's root system must be able to absorb water quickly in order for the plant to grow and thrive. When the soil around the root system is dry, the roots will stop growing and will not be able to absorb water.
It may even start to die. Watering plants during the peak of summer is important because it will help keep the soil moist and prevent the roots from drying out. However, watering a plant too much can be harmful. If a plant is overwatered, the water may not be able to penetrate the soil and reach the roots. Instead, it may just sit on top of the soil, causing the roots to rot and die. This can cause the plant to wilt and die.To summarize, if the soil around the plant is too dry, the roots may not be able to absorb the water you gave them, causing the plant to look worse than before. Conversely, overwatering can also be harmful because the water may not be able to penetrate the soil and reach the roots, causing the roots to rot and die.
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What is the number at the end of an isotope’s name? atomic number neutron number mass number electron number
Answer:
C) mass number
Explanation:
I got it correct on edge
Answer: c
Explanation:
Use vector arrows to represent the velocity of a car that travels north at 50 mi/h and then travels east at 25 mi/h.
Answer:
See below
Explanation:
Assuming they travel at the two velocities for equal amounts of time
A cheetah runs at an average speed of 60mph. find the distance it runs in 30 s
Answer:60mph means it runs every minute.
Explanation: because it makes sense.
Answer:
2640 ft, or 1/2 mile
Explanation:
Recognizing that 30 s = 0.5 min, we can convert the units like this.
distance = speed × time
distance = (60 mi/h) × (1 h/(60 min)) ×(0.5 min) = 0.5 mi
In feet, that is ...
(5280 ft/mi)(0.5 mi) = 2640 ft
A cheetah runs 1/2 mile, or 2640 feet in 30 s.
I’m not sure how to determine the answer to this, I specifically need help with B.
Answer:
B. From positions A and D.
Explanation:
Types Of Energy Transfers
Heat can be transferred in three ways: by conduction, convection, and by radiation.
Conduction is the transfer of energy from one molecule to another by direct contact. Convection is the movement of heat by a fluid such as water or air. Radiation is the transfer of heat by electromagnetic waves.A machine with a velocity of 25 moves a load of 100N when an effort of 200N is applied. Calculate the mechanical advantage and efficiency of the machine.
To calculate the mechanical advantage of a machine, we use the formula: Mechanical Advantage (MA) = Load (L) / Effort (E)
Given:
Load (L) = 100 N
Effort (E) = 200 N
Plugging the values into the formula:
MA = 100 N / 200 N
MA = 0.5
So, the mechanical advantage of the machine is 0.5.
To calculate the efficiency of a machine, we use the formula:
Efficiency = (Output work / Input work) * 100
Given:
Effort (E) = 200 N
Velocity (V) = 25
We know that Work (W) = Force (F) * Distance (D)
The output work can be calculated as the product of the effort and the distance traveled by the effort. The input work can be calculated as the product of the load and the distance traveled by the load.
Let's assume that the distances traveled by the effort and the load are the same.
Output work = Effort (E) * Distance
Input work = Load (L) * Distance
Since the distances are the same, we can ignore them in the efficiency calculation.
Output work = 200 N * Distance
Input work = 100 N * Distance
Efficiency = (Output work / Input work) * 100
Efficiency = ((200 N * Distance) / (100 N * Distance)) * 100
Efficiency = 200%
So, the efficiency of the machine is 200%.
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Find the work done by f in moving a particle once counterclockwise around the given curve. f=(4x-2y)i (2x-4y)j, c: (x-5)^2 (y-5)^2=25
Evaluating the definite integral, we can determine the work done by the force vector field in moving the particle once counterclockwise around the given curve.
To find the work done by the force vector field F = (4x - 2y)i + (2x - 4y)j in moving a particle counterclockwise around the curve C defined by the equation (x - 5)^2 + (y - 5)^2 = 25, we can use the line integral formula for work:
Work = ∫ F · dr
where F is the force vector field and dr is the differential displacement along the curve C.
To evaluate the line integral, we need to parameterize the curve C. We can do this by letting x = 5 + 5cos(t) and y = 5 + 5sin(t), where t ranges from 0 to 2π.
Now, let's calculate the differential displacement dr:
dr = dx i + dy j
= (-5sin(t)) i + (5cos(t)) j
= -5sin(t)i + 5cos(t)j
Next, let's evaluate F · dr:
F · dr = (4x - 2y)(-5sin(t)) + (2x - 4y)(5cos(t))
= -20xsin(t) + 10ysin(t) + 10xcos(t) - 20ycos(t)
Substituting the parameterization x = 5 + 5cos(t) and y = 5 + 5sin(t) into F · dr, we get:
F · dr = -20(5 + 5cos(t))sin(t) + 10(5 + 5sin(t))sin(t) + 10(5 + 5cos(t))cos(t) - 20(5 + 5sin(t))cos(t)
Simplifying the expression, we have:
F · dr = -200sin(t) - 100sin(t)cos(t) + 100sin(t) + 100cos(t) - 200cos(t) - 100sin(t)cos(t)
Now, we can evaluate the line integral by integrating F · dr over the parameter range 0 to 2π:
Work = ∫ F · dr
= ∫[-200sin(t) - 100sin(t)cos(t) + 100sin(t) + 100cos(t) - 200cos(t) - 100sin(t)cos(t)] dt (from t = 0 to 2π)
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What is the net force on a 1000N barrel falling in air with an air drag of 400N?
The net force on the 1000 N barrel falling in air with an air drag of 400 N is 600 N
How do I determine the net force?Net force is given by the following formula:
Net force = force of pull - opposite force
The following data were obtained from the question:
Weight of barrel = 1000 NForce of resistance = 400 NNet force =?The net force on the 1000 N barrel falling in air can be obtained as illustrated below:
Net force = Weight of barrel - Force of resistance
Net force = 1000 - 400
Net force = 600 N
Thus, the net force on 1000 N barrel is 600 N
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If a rabbit accelerates from rest at 7.5 m/s2 for 3 seconds, how fast will it begoing? *
Given data:
* The initial velocity of the rabbit is u = 0 m/s.
* The acceleration of the rabbit is,
\(a=7.5ms^{-2}\)* The time taken is t = 3 s.
Solution:
By the kinematics equation, the final velocity of the rabbit is,
\(v-u=at\)Substituting the known values,
\(\begin{gathered} v-0=7.5\times3 \\ v=22.5\text{ m/s} \end{gathered}\)Thus, the velocity of the rabbit is 22.5 m/s.
An ion rocket engine produces 1 newton of thrust. What acceleration can it give to a space probe with a mass of 1000kg?.
According to the thrust force, the acceleration is 0.001 m/s².
We need to know about force to solve this problem. According to second Newton's Law, the force applied to an object will be proportional to mass and acceleration. Hence, it can be written as
F = m . a
where F is force, m is mass and a is acceleration
From the question above, we know that
F = 1 N
m = 1000 kg
By substituting the given parameters, we can calculate the acceleration
F = m . a
1 = 1000 . a
a = 1/1000 m/s²
a = 0.001 m/s²
Hence, the acceleration is 0.001 m/s².
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Two charges are aligned with a -2.5x10-6 C charge 0.50 m directly below a 3.0x10-6 C charge. Calculate the force acting on both charges, including direction.
Show work please.
density of water_____ g/l
The density of water is 1000 g/L. This is because density is the measure of mass per unit of volume, and water has a mass of 1 gram per milliliter (g/mL), which is equivalent to 1000 g/L.
In general, the density of a substance can be calculated by dividing its mass by its volume:
Density = Mass/Volume
So for water, with a mass of 1 gram per milliliter and a volume of 1 liter (which is equal to 1000 milliliters), the density would be:
Density = (1 g/mL) / (1000 mL/L) = 1000 g/L
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What happens to a circuit's resistance (R), voltage (V), and current (1) when
you change the thickness of the wire in the circuit?
A. V and I will also change, but R will remain constant.
B. R and I will also change, but V will remain constant.
O C. R, V, and I will all remain constant.
OD. R and V will also change, but I will remain constant.
When you change the thickness of the wire in a circuit, option B. the resistance (R) and current (I) will also change, but the voltage (V) will remain constant.
The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area (thickness). As the thickness of the wire changes, the cross-sectional area changes, which in turn affects the resistance. Thicker wires have a larger cross-sectional area, resulting in lower resistance, while thinner wires have a smaller cross-sectional area, resulting in higher resistance. Therefore, changing the thickness of the wire will cause a change in resistance.
According to Ohm's Law (V = IR), the voltage (V) in a circuit is equal to the product of the current (I) and the resistance (R). If the voltage is kept constant, and the resistance changes due to the thickness of the wire, the current will also change to maintain the relationship defined by Ohm's Law. When the resistance increases, the current decreases, and vice versa.
However, it's important to note that changing the thickness of the wire will not directly affect the voltage. The voltage in a circuit is determined by the power source or the potential difference applied across the circuit and is independent of the wire thickness. As long as the voltage source remains constant, the voltage across the circuit will remain constant regardless of the wire thickness. Therefore, the correct answer is option B.
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Comet is seen after a long period of time. Why?
Answer:
Long-period comets have orbital periods longer than 200 years. ... Since it is the sublimation of these volatiles from the nucleus of the comet as it nears the Sun that gives rise to the coma and highly-visible tails, long-period comets have more material with which to put on a show.
Explanation:
Find the gravitational force between the
Sun and the Earth.
Given Mass of the Sun = 1.99x10³0 kg
Mass of the Earth = 5.98x10²4kg
The average distance between the Earth
and the Sun = 1.5x10¹¹ m.
Answer:
The process is given in the pic.
I have taken the average masses so u substitute the values and solve hope it will help :)❤
Consider a pendulum of mass m, length R, and center of mass at R_cm from the axis of rotation. Assume that a force F_x is applied horizontally to the end of the pendulum. Write the equation of rotational equilibrium of the pendulum and express F_x in terms of the angle of oscillation, θ, with respect to the vertical direction.
The equation of rotational equilibrium for the pendulum can be written as:
F_x * R = -m * g * R_cm * sin(θ)
In this case, the two torques acting on the pendulum are due to the force F_x and the gravitational force acting on the center of mass (mg).
Solving for F_x, we get:
F_x = -(m * g * R_cm * sin(θ)) / R
where F_x is the applied horizontal force, R is the length of the pendulum, m is the mass of the pendulum, g is the acceleration due to gravity, R_cm is the distance of the center of mass from the axis of rotation, and θ is the angle of oscillation with respect to the vertical direction.
Therefore, the force F_x is expressed in terms of the angle of oscillation θ with respect to the vertical direction.
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a disk displaces 10 radians (rads) over a 2 second interval. the rotational velocity during that two second time interval was
According to the question the rotational velocity during the two second time interval is 5 radians per second (rad/s).
What is velocity?Velocity is a quantity that measures both the speed and direction of an object's motion. Velocity is a vector, meaning it has both direction and magnitude. Speed is the rate at which an object moves, while velocity is the rate and direction of an object's motion. Velocity is typically expressed in terms of meters per second (m/s). Velocity is different from acceleration, which is the rate of change in velocity over time.
The rotational velocity during the two second time interval is 5 radians per second (rad/s). This is calculated by dividing the total rotation of 10 radians by the two second time interval. Mathematically, this is expressed as:
Velocity = (Rotation / Time) = (10 rad / 2 s) = 5 rad/s
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Complete Question:
A disk displaces 10 radians (rads) over an 2 second interval. The rotational velocity during that 2 second time interval was rad/s.
You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between your feet and the ice. A friend throws you a 0.400-kg ball that is traveling horizontally at 10.0 m/s. Your mass is 70.0 kg. (a) If you catch the ball, with what speed do you and the ball move after ward
Answer:
0.38m/s
Explanation:
Given data
M1= 0.4kg
U1= 10m/s
M2= 70kg
U2= 0m/s
The system experiences an inelastic collision, the expression for inelastic collision is
M1U1+ M2U1= (M1+M2)V
Subsitute
0.4*10+ 70*0= (0.4+10)*V
4= 10.4V
4=10.4V
V= 4/10.4
V=0.38m/s
Hence the common velocity is 0.38m/s
A stone is thrown straight up. While the stone is rising:
A. its acceleration is upward and decreasing
B. its acceleration is upward and constant
C. its acceleration is upward and increasing
D. its acceleration is zero
E. None of the above.
Answer:
D. its acceleration is zero
Explanation:
Acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;
\(Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}\)
In this scenario, a stone is thrown straight up. While the stone is rising its acceleration is zero because it's initial velocity is zero and it's until the stone reaches its highest point before the acceleration becomes constant and acting downward.
Which option identifies the major method scientists use to share their research findings with other scientists?
a) conference presentations
b) peer-reviewed journals
c) newspaper articles
d) Internet videos
The major method scientists use to share their research findings with other scientists is (b) peer-reviewed journals.
What is peer-reviewed journals?The primary means through which scientists disseminate the results of their study to other scientists is through peer-reviewed publications. Research articles are submitted by scientists in this method to respectable scientific publications.
The papers are next subjected to a thorough examination by a group of subject-matter specialists known as peers or referees. Prior to being approved for publication, these experts evaluate the research's quality, validity, and importance.
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