Why are we using raisins to observe
osmosis?

The work function for barium is 2.48eV. If light of 400nm is shined on the barium cathode, the maximum velocity of the ejected electron is 4.54 × 105 m/s.

Energy can be transferred from electromagnetic radiation to matter in the form of photons. The energy of each photon is equal to the product of Planck's constant (h) and the frequency of radiation (ν), which is related to the wavelength (λ) by the equation c = νλ, where c is the speed of light in vacuum. Because of the photoelectric effect, which is a quantum effect in which electrons are ejected from matter when exposed to radiation with sufficiently high frequency, this energy can ionize atoms or eject electrons from metal surfaces.

The maximum kinetic energy that an electron can acquire in the photoelectric effect is equal to the energy of the incident photon minus the work function of the metal. If the metal is irradiated with monochromatic radiation, the maximum kinetic energy of the photoelectron can be calculated using the equation KEmax = hν – φ, where KEmax is the maximum kinetic energy of the ejected electron, h is Planck's constant, and φ is the work function of the metal.Barium has a work function of 2.48 eV, and radiation with a wavelength of 400 nm has a photon energy of 3.1 eV. If the photon is absorbed by a barium atom, the maximum kinetic energy of the ejected electron is:KEmax = hν – φ = hc/λ – φ = 3.1 eV – 2.48 eV = 0.62 eV.To convert this to velocity, the kinetic energy must first be converted to joules, and then to velocity using the following equation:KE = ½ mv2 ⇒ v = √(2KE/m),where m is the mass of the electron, which is 9.11 × 10–31 kg.Therefore,v = √[2(0.62 × 1.6 × 10–19)/9.11 × 10–31] = 4.54 × 105 m/s.So, the maximum velocity of the ejected electron is 4.54 × 105 m/s.

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Answer:

A) half the original force

Answer:

D. The car is slowing down.

Explanation:

When a car slows down, the acceleration is in the opposite direction as the velocity. With that being said, the car would have negative acceleration.

hope this helps!! p.s. i really need brainliest :)

The mean lifetime of A is given by τ(A) = 26 × 10⁻¹⁰ s. The A decays into p + e⁻ + ve with a branching fraction of BR(A → p + e⁻ + ve) = 83 × 10⁻⁴.The mean lifetime of A⁺ (udc) is given by τ(A⁺) = 2-1 × 10⁻¹³ s.

The branching fraction of A into A⁺ + e⁺ + ve is given as follows: First, we can calculate the decay constant for A.λ = (1/τ) = (1/26 × 10⁻¹⁰) s⁻¹.The half-life of A is given by t₁/₂ = ln(2) / λ = (ln2 × τ) = 2.667 × 10⁻¹⁰ s. The branching fraction of A → A⁺ + e⁺ + ve is given as follows: BR(A → A⁺ + e⁺ + ve) = 1 - BR(A → p + e⁻ + ve) = 1 - (83 × 10⁻⁴) = 0.99917.

The measured value of the branching fraction of A → A⁺ + e⁺ + ve is BR(e+ve) = 2106 %.This is greater than 100%. Therefore, the value must be a typographical error. The correct percentage is probably 21.06%.The estimated branching fraction of A → A⁺ + e⁺ + ve is 99.917%, which is very close to 100%. This implies that the A mainly decays into A⁺ + e⁺ + ve.

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The magnitude of the electron's initial acceleration is \(2.53 * 10^_{30\) \(m/s^2\). Calculated using Coulomb's law and Newton's second law.

At the point when an electron is delivered close to a charged pole, it encounters an electric power because of the electric field created by the bar.

To find the extent of the electron's underlying speed increase, we really want to ascertain the power following up on it and afterward utilize Newton's subsequent regulation, which expresses that power is equivalent to mass times speed increase.

The power following up on the electron can be found utilizing Coulomb's regulation, which relates the extent of the electric power between two charged particles to the result of their charges and the distance between them. For this situation, the electron is set 9.0 cm free from the bar, which has a uniform direct charge thickness of 6.0 µC/m.

Utilizing Coulomb's regulation, we can find the size of the electric power following up on the electron:

\(F = k * (q1 * q2)/r^2\)

where k is Coulomb's consistent, q1 is the charge of the electron, q2 is the charge thickness of the bar, and r is the distance between the electron and the bar.

Subbing the given qualities, we get:

\(F = (9.0 * 10^9 N.m^2/C^2) * [(1.6 * 10^-19 C) * (6.0 * 10^-6 C/m)]/(0.09 m)^2 = 2.304 N\)

Then, we can utilize Newton's second regulation to track down the extent of the electron's underlying speed increase:

a = F/m

where an is the speed increase, F is the power determined utilizing Coulomb's regulation, and m is the mass of the electron.

The mass of an electron is around \(9.11 x 10^_-31} kg\). Subbing this worth, we get:

\(a = 2.304 N/9.11 * 10^-31 kg = 2.53 * 10^_{30}\) \(m/s^2\)

Thusly, the greatness of the electron's underlying speed increase is 2.53 x \(10^_{30\) \(m/s^2\).

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Average yearly high temperature decreases as elevation increases.

The difference in elevation between the two cities results in a difference in atmospheric pressure and thus a difference in temperature.

A decrease in latitude would likely increase the average yearly high temperatures of both cities due to the increased amount of solar radiation they receive.

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Answer:

  d  The energy is transformed to sound and heat energy.

Explanation:

Each time the basketball bounces, it makes sound waves, and dissipates energy in the form of heat in the material of the ball and the surrounding air. There is no light or chemical change involved.

The maximum possible speed of the train at the end of the first 4.0 km of the journey is 0 m/s.

To calculate the maximum possible speed of the train at the end of the first 4.0 km of the journey, we can apply the principle of conservation of energy.

Assuming there are no external forces like friction or air resistance, the initial potential energy of the train will be converted into kinetic energy.

The potential energy (PE) of the train at the beginning of the journey can be calculated as PE = mgh, where m is the mass of the train, g is the acceleration due to gravity (approximately \(9.8 m/s^2\)), and h is the height difference (in this case, we assume it to be zero).

The kinetic energy (KE) of the train at the end of the 4.0 km journey can be calculated as \(KE = (1/2)mv^2\), where v is the velocity of the train.

Since the potential energy is converted into kinetic energy, we can equate the two expressions:

PE = KE

\(mgh = (1/2)mv^2\)

Simplifying and canceling out the mass:

\(gh = (1/2)v^2\)

Substituting the values, \(g = 9.8 m/s^2\)and h = 0, we get:

\((9.8 m/s^2)(0) = (1/2)v^2\)

Simplifying further:

\(0 = (1/2)v^2\)

This equation tells us that the maximum possible speed of the train at the end of the first 4.0 km of the journey is 0 m/s.

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Answer:

240 miles

Explanation:

The car drove 60mph for 5 hours, so that's 60x5, which is 300. You then subtract 60 and get your answer: 240 miles.

The position-time graph gives the position of an object at any instant of time. The y-intercept gives the position of the object at the instant when the time is zero. That is, the y-intercept gives the initial position of the object.

Thus the given statement is false.

Answer:

Kg

Explanation:

mass is measured in kilograms

therefore its si unit is kg

A. The period of vibration is the time it takes for one complete oscillation to occur. It is the reciprocal of the frequency. The period of vibration can be calculated using the formula:

Period = 1/Frequency

Given that the frequency of vibration is 5.0Hz, the period of vibration is:

Period = 1/5.0 s

Period = 0.2 s

B. If the cart's mass is doubled while the spring constant remains unchanged, the frequency of vibration will not change. This is because frequency is dependent on the spring constant and the mass of the cart and not on the amplitude of the oscillation.

C. If the spring constant doubles while the cart's mass remains the same, the frequency of vibration will also double. This is because frequency is directly proportional to the square root of the spring constant. Therefore, doubling the spring constant would lead to an increase in the frequency of vibration by a factor of square root of 2.

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The Floating weight is affected by the buoyancy force.

As we clearly know that in buoyancy force the weight or any other object will float over the surface of the water and this force is known as buoyancy force. The reason behind the Buoyancy force is that the object seeming lighter in water.

The Buoyancy force can be define as the upward force exerted by the fluid on any weight or any object placed in it. The Buoyancy force is directly proportional to the density of the immersed fluid. The Buoyancy force is also proportional to the volume of the object immersed in the fluid.

So we can conclude that the floating weight is affected by the buoyancy force.

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Answer:

wood because, Coal, oil and natural gas are examples of natural gas. Biogas is the mixture of gases produced by the breakdown of organic matter in the absence of oxygen, usually consisting of certain quantities of methane and other constituents. therefore wood is not a fossil fuel

Answer:

1298.5watt

Explanation:

Power is defined as the rate at which work is done

Expressed mathematically as;

P = F × d/ t; F = force or weight of object ;d is height or distance sustain and t is time covered

Hence for 1 person the power consumption is ;

Note weight =mass× acceleration of free fall due to gravity,g

g is known as 9.8m/S2

Time taken is 1min which is 60 sec

60 ×9.8 × 5.3/60 = 51.94 watt

Hence for 25 persons we have

25 × 51.94 =1298.5watt

1.3kilo watt( kilo is 1000)

The work done by the escalator is 3,080.4 joules and the power requirement of the escalator to move 25 passengers every minute is approximately 51.34 watts.

The Work Done is calculated as:

Force (F) = 60 × 9.8

Distance (d) = 5.30 meters

Work (W) = F × d

Work (W) = (60 × 9.8) × 5.30

Work (W) = 3,080.4 joules

The Power is calculated as:

Time (t) = 1 minute

Power (P) = Work / Tim (t)

Power (P) = 3,080.4 / 60

Power (P) = 51.34 watts

Therefore, the power requirement of the escalator to move 25 passengers every minute is approximately 51.34 watts.

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The reason why we don't know the mass limit for a neutron star is that the physics of neutron stars is much more complex than that of white dwarfs.

Neutron stars are incredibly dense objects, with a mass that is typically between 1.4 and 2.1 times the mass of our sun. However, it is possible that neutron stars could have a much higher mass limit, but we simply don't know yet. This is because the behavior of matter at such extreme densities is not fully understood, and the equations of state that describe the properties of neutron stars are still being developed and refined.

As we continue to study and learn more about these fascinating objects, we may eventually be able to determine an upper limit for their mass.

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Answer:

Within the realm of Newtonian mechanics, an internal frame of reference or internal reference frame, is one in which newton's law of motions is valid

Answer:

is there a picture? so I can understand it more and it will be easier for me to answer. thank you

Answer:

The second one is more accurate because we were able to draw more precisely and accurately, the first picture was more of a general idea of the picture and the second picture was more of a detailed version.

Explanation:

I just did this assignment and this is what I turned in so yeah I hope this is good enough, if you need more of an explanation though ill try to lengthen it. =]

As an Irish immigrant living in the urban area in 1928, I would have been most likely to vote for Al Smith because he had a strong track record of supporting minority groups and working towards fair and equal treatment for all Americans.

As an Irish immigrant, I would have faced a lot of discrimination and prejudice in America during this time. Irish immigrants were often viewed as second-class citizens and were not given the same opportunities as native-born Americans. Al Smith understood this struggle firsthand, as he was also the son of immigrants and had experienced discrimination himself.

Furthermore, Al Smith was a Democrat, and the Democratic Party had a long history of supporting immigrants and minority groups. During his campaign, Al Smith promised to support immigrants and work towards fair and equal treatment for all Americans, regardless of their background.

In contrast, the Republican Party, which was led by Herbert Hoover in 1928, had a reputation for being less supportive of immigrants and minorities. While Hoover did not openly discriminate against these groups, he did not make them a priority in his campaign.

Overall, as an Irish immigrant living in the urban area in 1928, I would have been most likely to vote for Al Smith because he had a strong track record of supporting minority groups and working towards fair and equal treatment for all Americans.

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Answer:

a galaxy observed at a distance of 5 billion light-years

A galaxy observed at a distance of 10 billion light-years is most likely to be oldest (option C)

The reason, behind this phenomenon lies in the concept of travel time as we observe galaxies located away their light takes a time to reach us.

Consequently when we observe a galaxy at a distance we are essentially gazing at  an old galaxy which existed further back in time. Witnessing how it appeared in earlier times.

This implies that a galaxy observed at a distance of 10 billion years is more likely to be older compared to galaxies observed at distances (option C)

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Complete question:

Which of these galaxies is most likely to be oldest?

OA a galaxy in the Local Group

OB a galaxy observed at a distance of 5 billion light-years

OC a galaxy observed at a distance of 10 billion light-years

The solutions are i) The speed of the boy is 2 m/s. ii) The velocity of the boy is 0 m/s. iii) The velocity is zero and the speed of the boy is 10 m/s. iv) In the case of rectilinear motion the distance and displacements are equal.

i) To find the speed of the boy we can directly use the speed, distance, and time formula that is:

Speed= distance/time

Here we can see that the boy covers a distance of 100 m back and forth so the total distance he covered is 100 m + 100 m = 200 m.

The time he took for the journey is 50 s each side so the total distance is 50 s + 50 s = 100s

Now substituting the values in the formula, we get:

Speed = 200 m / 100 s

Speed = 2 m/s

Therefore the speed of the boy is 2 m/s.

ii)  The velocity is the vector quantity which means it indicates the speed of the boy in a particular direction. The velocity can be found by the formula:

Velocity = Displacement/Time

Now we can see that the initial and the final position of the boy are the same so there is no displacement, so displacement is 0.

Substituting the values into the formula we get

Velocity = 0 m/100 s

Velocity = 0m/s

Therefore the velocity of the boy is zero.

iii) According to the question the boy is just sitting on the merry-go-round and not changing his position with respect to the merry-go-round, his velocity is zero as there is no displacement. However, the merry-go-round is moving at a constant speed of 10 m/s, so the boy has a speed of  10 m/s with respect to the ground.

iv) When an object moves in a straight line. the distance moved and the magnitude of displacement are equal. So, in the case of rectilinear motion, the distance covered and the magnitude of the displacement are equal.

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The acceleration of the car is 17.44 m/s²

Friction is the opposition to the relative motion of an object over another.

Friction is a contact force that exists between two objects at their surfaces of contact.

Frictional force = Coefficient of friction * Normal reaction

The mass of the car = 9.32 * 10² Kg

Weight of the car = 9.32 * 10² * 9.81 = 9142.92 N

Frictional force = 0.222 *  9142.92 N

Frictional force = 2029.73 N

Force on the wheel = 9142.92 N * 2 = 18285.84 N

Net force = mass * acceleration =  18285.84 N - 2029.73 N

mass * acceleration = 16256.11 N

acceleration = 16256.11/932

acceleration = 17.44 m/s²

In conclusion, the frictional force is a contact force which opposes relative motion of an object over another.

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a. Velocity vector at t=20: (200 m/s, 200 m/s, 0 m/s) ; Position vector at t=20: (4000 m, 2040 m, -1960 m) ; b. Sketch of the trajectory (visual content not available) ; c. Time of flight: 40.82 s ; Range: 4000 m ; d. Maximum height: 2080.4 m

a. To find the velocity and position vectors for t = 20 seconds, we need to analyze the motion of the bullet in the x, y, and z directions separately.

In the x-direction:

- Initial velocity in the x-direction (Vx0) = 200 m/s (east)

- Acceleration in the x-direction (ax) = 0 m/s^2 (no horizontal force acting)

- Displacement in the x-direction (Δx) = Vx0 * t = 200 m/s * 20 s = 4000 m

In the y-direction:

- Initial velocity in the y-direction (Vy0) = 200 m/s (north)

- Acceleration in the y-direction (ay) = -9.8 m/s^2 (due to gravity)

- Displacement in the y-direction (Δy) = Vy0 * t + (1/2) * ay * t^2 = 200 m/s * 20 s + (1/2) * (-9.8 m/s^2) * (20 s)^2 = 4000 m - 1960 m = 2040 m

In the z-direction:

- Initial velocity in the z-direction (Vz0) = 0 m/s (no initial vertical velocity)

- Acceleration in the z-direction (az) = -9.8 m/s^2 (due to gravity)

- Displacement in the z-direction (Δz) = Vz0 * t + (1/2) * az * t^2 = 0 m/s * 20 s + (1/2) * (-9.8 m/s^2) * (20 s)^2 = -1960 m

Therefore, the velocity vector at t = 20 seconds is (200 m/s, 200 m/s, 0 m/s), and the position vector at t = 20 seconds is (4000 m, 2040 m, -1960 m).

b. Sketch of the trajectory:

 (Please note that I am unable to provide visual content as a text-based AI model.)

c. To determine the time of flight and range of the bullet, we need to find when the bullet returns to the ground.

- In the y-direction: The bullet returns to the ground when Δy = 0.

  200 m/s * t + (1/2) * (-9.8 m/s^2) * t^2 = 0

  Solving this quadratic equation, we find two solutions: t = 0 s (initial time) and t = 40.82 s.

  Since the bullet was fired upwards, we consider the positive solution.

  Therefore, the time of flight is approximately 40.82 seconds.

- In the x-direction: The range of the bullet is the displacement in the x-direction.

  Range = Δx = 4000 m.

d. To determine the maximum height of the bullet, we need to find the highest point it reaches.

- In the y-direction: The maximum height occurs when the vertical velocity (Vy) becomes zero.

  Vy0 + ay * t = 0

  200 m/s + (-9.8 m/s^2) * t = 0

  Solving for t, we find t ≈ 20.41 s.

  Plugging this time into the displacement equation in the y-direction:

  Δy = Vy0 * t + (1/2) * ay * t^2

  Δy = 200 m/s * 20.41 s + (1/2) * (-9.8 m/s^2) * (20.41 s)^2

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Answer:

\(\boxed {\boxed {\sf 1646.4 \ J }}\)

Explanation:

Gravitation potential energy can be found using this formula:

\(E_P=m*g*h\)

where m is the mass, g is the gravtiational acceleration, and h is the height.

The mass of the apple is 14 kilograms and it is 12 meters above the ground. Since this is on Earth, the acceleration due to gravity is 9.8 m/s².

\(m= 14 \ kg \\g= 9.8 \ m/s^2 \\h= 12 \ m\)

Substitute the values into the formula.

\(E_p= ( 14 \ kg )( 9.8 \ m/s^2)(12 \ m)\)

Multiply.

\(E_p= (137.2 \ kg*m/s^2)(12 \ m )\)

Multiply again.

\(E_P= 1646.4 \ kg*m^2/s^2\)

\(E_p=1646.4 \ J\)

This is already rounded to the tenth place, so it's the final answer.

The apple has 1,646.4 Joules of gravitational potential energy.

Answer:

F = 12 N

Explanation:

Given that,

Force of 5 N and 7 N respectively act on an object.

We need to find the resultant of the two vectors be at a maximum.

Force will be maximum when two forces acts in same direction. It means we can simply add them i.e.

F = 5 N + 7 N

F = 12 N

Hence, the resultant force is 12N.

Answer:

a. Pure white

b. Pure black

c. Hybrid