Why do circular chromosomes not need telomerase? Circular chromosomes don't undergo lagging strand synthesis. Circular chromosomes have centromeres. Circular chromosomes always have nucleotides that DNA polymerase can new nucleotides to Circular chromosomes don't have RNA primers Circular chromosomes don't need DNA ligase Circular chromosomes tend to have a lower percentage of protein coding genes

Answer:

- all biomolecules could be called carbon - based molecules

- The monomers of DNA are nucleotides

- Cell membranes are made, in part, from phospholipids

- The monomers of starch are monosaccharides

Explanation:

Just got that question!

The statements that are true about the biological macromolecule include:

The biological macromolecules that contains false statements include

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cerebral cortex

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The population of beetles in the next three generations, considering the carrying capacity, is y1 = 130 beetles, y2 = 130 beetles, and y3 = 130 beetles.

The population of beetles can be calculated using the formula: y = y0 * (1 + r)^n, where y is the population at a given generation, y0 is the initial population, r is the intrinsic growth rate (expressed as a decimal), and n is the number of generations.

Given that the initial population (y0) is 60 beetles and the intrinsic growth rate (r) is 150% (or 1.5), we can calculate the population for the next three generations.

For the first generation (y1), we substitute y0 = 60, r = 1.5, and n = 1 into the formula: y1 = 60 * (1 + 1.5)^1 = 60 * 2.5 = 150 beetles.

For the second generation (y2), we substitute y0 = 60, r = 1.5, and n = 2 into the formula: y2 = 60 * (1 + 1.5)^2 = 60 * 6.25 = 375 beetles.

For the third generation (y3), we substitute y0 = 60, r = 1.5, and n = 3 into the formula: y3 = 60 * (1 + 1.5)^3 = 60 * 15.625 = 937.5 beetles.

However, since the environment can only sustain a maximum population of 130 beetles, we need to consider the carrying capacity.

To find the population at each generation while considering the carrying capacity, we compare the calculated population with the carrying capacity and use the smaller value as the population.

For y1, the population is 150 beetles, which exceeds the carrying capacity of 130 beetles. Therefore, y1 = 130 beetles.

For y2, the calculated population is 375 beetles, which is also above the carrying capacity. Thus, y2 = 130 beetles.

For y3, the calculated population is 937.5 beetles, which is still above the carrying capacity. Therefore, y3 = 130 beetles.

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B) You would seek to determine whether a trait is sex-related using pedigree data or a test.

A sex-linked pedigree will primarily have affected males, and the female carriers will typically be marked with a half-shaded circle.

The son must have only inherited his allele from his mother if the trait is x-linked, and the father may not be affected. RECEPTIVE WITH X-LINKS: The disease must be X-linked recessive when a affected non-founding son has two parents who are unaffected.

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its for the first onehypothesis

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Concept of evolution is a theory.

Evolution is a the change in the characteristics of a species over several generation and relies on the process of natural selection.

It is the process through which a population of a organism adapt to changing environment and pass its gene to the next generation.

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Answer:

Cycles in predator/prey populations.

Explanation:

Climate change, decrease of keystone species and the introduction of new species all contribute to instability of the ecosystem.

Answer:

C. They absorb it out of the air.

Explanation:

We breathe it out, plants breathe it in.

The ratio of lipid to protein in a membrane is 75% lipid to 25% protein by weight. To find the ratio of molecules, we need to convert the weight percentages to molecular ratios based on molecular weights.

First, we'll convert the molecular weights of the protein and lipid from kDa and Da to grams.

50 kDa = 50 x 10^3 Da = 50 x 10^3 / 6.022 x 10^23 g/mol = 83.33 g/mol

750 Da = 750 / 6.022 x 10^23 g/mol = 0.124 g/mol

Next, we'll use the molecular weights to calculate the number of moles of each component in 1 gram of the membrane.

For the protein:

1 g / 83.33 g/mol = 0.0120 moles/gram

For the lipid:

1 g / 0.124 g/mol = 8.06 moles/gram

Finally, we'll calculate the ratio of lipids to proteins based on the number of moles:

8.06 moles lipid / 0.0120 moles protein = 671.67 lipids per protein

So, there are approximately 671.67 molecules of membrane lipid for each molecule of protein.

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Answer:

After mitosis, the daughter cells will have the same number of chromosomes as the parent cell, so 6 chromosomes

Answer:

Chemical bond which enhance stability

Explanation:

When atoms react a chemical bond is being formed which makes it stable

The first haploid (n) stage of spermatogenesis is prophase II. False.  In spermatogenesis, the process of sperm cell development, the first haploid stage is actually prophase I, not prophase II.

Prophase I is the initial stage where the chromosomes condense and pair up in a process called synapsis. During this stage, genetic recombination occurs as the chromosomes exchange genetic material. Prophase I is further divided into five sub-stages: leptotene, zygotene, pachytene, diplotene, and diakinesis.

Following prophase I, the cells enter the next phase called metaphase I, where the paired chromosomes align at the equator of the cell. This is followed by anaphase I, where the homologous chromosomes separate and move towards opposite poles of the cell. Telophase I and cytokinesis then complete the first round of cell division.

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The type of chromosomal change which is represented in the diagram given is deletion. The correct option is A.

In genomics, a deletion is a type of mutation that involves the removal of one or more nucleotides from a segment of DNA.

A deletion can result in the loss of any number of nucleotides, ranging from a single nucleotide to an entire chromosome.

Because an insertion or deletion causes a frame-shift that alters the reading of subsequent codons.

This alters the entire amino acid sequence that follows the mutation, insertions and deletions are usually more harmful than a substitution that only changes one amino acid.

Thus, the correct option is A.

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Your question seems incomplete, the missing image is attached below:

In the body of Thom, B: "the number of fat cells is decreasing".

When a person loses weight through diet or exercise, the size of their fat cells decreases, but the number of fat cells remains constant. This means that the existing fat cells shrink as they release stored fat for energy use. This is why people who lose a significant amount of weight often still have visible pockets of fat on their body, even though their overall body fat percentage has decreased. So, the correct answer is "the number of fat cells is decreasing."

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They're trace fossils, not animal bodies. This coprolite can reveal an animal's diet. Scientists can determine what animal dropped coprolites based on its shape, size, and location.

Fossilized feces are known as coprolites. Because coprolites provide information for the animal's behavior rather than its shape, rather than being considered body fossils, they are instead categorized as trace fossils.

 A coprolite  can provide researchers with information about an animal's nutrition. Scientists are able to determine the species of animal that may have been responsible for the droppings by analyzing the shape and size of the coprolites as well as the location where they were discovered.

Because coprolites have a propensity to deteriorate so quickly, we only find them very infrequently. They are the marine species that are found the most frequently. The presence of coprolites in fish and reptiles is very common.

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Answer:

Insulin production

Explanation:

The gene for insulin can be I serted to an organism then the produced insulin will be used for treatment of diabetes

Answer:

Gibberellin

Explanation:

I've studied that gibberellin is a plant hormone that promotes cell elongation and division, causing the cells in the leaves to elongate and divide more, this leads to an increase in leaf size.

Hope it helps! :)

The plant hormone that helps in increasing the leaf size is the phytohormone Auxin .

Plants create signalling molecules called plant hormones, which are found in low concentration. All  plant's growth and progression are regulated by plant hormones.

There are basically five types of plant hormones that are considered to be essential for plant growth . They are Auxin , Cytokinin , Gibberellin , ABA , Ethylene .

The Cytokinin and Auxin work together to enhance the development of leaf as both of the phytohormones are responsible to modulate the growth of leaf as well  as controlling the cell cycle . These hormones are considered essential for plant growth and it occur naturally at various concentrations within plants throughout the duration .

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The anatomic differences which place the infant at risk for respiratory compromise transient tachypnea of the newborn.

Healthcare can simply be defined as an organized medical care given to a person, organization or even a community either by a doctor, nurse or any other licensed healthcare professional

However, healthcare-associated Infections, are those infections patients can get during their treatment for another condition due to bacteria, viruses, fungi, and other pathogens.

And for a good reason, the fundamental purpose of healthcare is to enhance healthy living and quality of life by giving quality healthcare services.

So therefore, the anatomic differences which place the infant at risk for respiratory compromise transient tachypnea of the newborn

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Saturated fatty acids are different to unsaturated fatty acids because they have no C=C double bonds.

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Answer:

lol best cop pun i've herd yet

Explanation:

i told my friend 10 jokes to make him laugh, but unfortunately no pun in 10 did

To determine the likely order of the genes on the chromosome based on the given recombination frequencies and distance, we can use the concept of genetic mapping and calculate the map distances between the genes.

Recombination frequency between P and O = 7.4%

Recombination frequency between N and O = 7.9%

Distance between N and P = 15.7 units, First, we can calculate the map distance between P and O: Map distance between P and O = Recombination frequency between P and O * Distance between N and P

Map distance between P and O = 7.4% * 15.7 = 1.1618 units, Next, we can calculate the map distance between N and O: Map distance between N and O = Recombination frequency between N and O * Distance between N and P, Map distance between N and O = 7.9% * 15.7 = 1.2363 units, Comparing the map distances, we see that the map distance between N and O is larger than the map distance between P and O. This suggests that the gene O is located between N and P. Based on this information, the likely order of the genes on the chromosome is: N ---- O ---- P.

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Answer: D. Plants do not eat, so both chloroplasts and mitochondria are needed to make enough energy for plants to grow.  

Explanation: Option A is invalid since plant cells do use ATP. Option B is invalid since animal cells don't make their energy with chloroplasts. Option D is the most realistic one since chloroplasts in the plant are the ones that make the food for the plants, plant doesn't have a "mouth" so they depend on chloroplast to make food.

The statement which best describes the similarity between living things is that "all living things undergo similar processes for getting rid of waste within their cells."

Living things are organisms that have biological systems and are capable of sustaining life. Animals such as tiny fleas or ants are related to much larger species such as alligators and manatees. The kingdom Animalia includes organisms that are multicellular, eukaryotic and lack cell walls.

Living things have many traits in common. They all require nutrients to survive and are made up of cells. There are many traits that all living things share, but some of them are more fundamental than others.

One fundamental trait that all living things share is the ability to get rid of waste within their cells. Living organisms produce waste as a result of their metabolism. This waste is often toxic to the organism, so it must be removed from the body as soon as possible.

All living things have ways of getting rid of waste within their cells. They can do this in a variety of ways, including excretion, perspiration, and urination. Therefore, living things all undergo similar processes for getting rid of waste within their cells.

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researchers recorded that a certain bacteria population declined from 270,000 to 200 in 36 hours. at this rate of decay, 3985200 bacteria will there be in 18 hours

The rate of radioactive decay, also known as the rate of decay, tells us how quickly the decaying nuclei change over time. The activity of the unstable atom will be revealed if the decay rate is taken as an absolute value.

Given that,

A = 200

A₀= 270000

K=?

t= 36 hours

A=A₀\(e^k\)t

Substitute the values in the formula.

200 = 270000 \(e^k\) 36

Solve for k.

Divide each side by 270000.

7.41 × 10⁻⁴ = ek 36

Take the natural log of each side.

or, ln (7.41 × 10⁻⁴ ) =  lnek 36

or, ln (7.41 × 10⁻⁴ ) =36 k lne

or, ln (7.41 × 10⁻⁴ ) = 36 k

or, -7.21 = 36 k

or, k = - 0.2003

We use this rate of growth to predict the number of bacteria there will be in 18 hours.

A=A₀\(e^k\)t

Putting the values we get -

or, A = 270,000 × (0.82) × (18)

or, A = 3985200

At this rate of decay, researchers can expect 3985200 bacteria.

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Answer:

D

Explanation:

bcs I don't really know

Answer:

Exocytosis is the process by which a large number of molecules are released

The physical change that occurs through the process of digestion is B Enzymes and acid break down food into smaller pieces for absorption.

The process of digestion breaks down food into smaller molecules that can be absorbed and utilized by the body. This complex system requires enzymes and acids to work together to break down larger pieces of food in order to facilitate optimal nutrition absorption.

The method of breaking down these foods is a chemical reaction that effectively reduces large, complex molecules into smaller, more manageable ones thanks to the use of enzymes and appropriate substances designed for such purpose.

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