Which of the following are examples of Multiple Intelligences:
•being good at sales
•being good at rapping or beatboxing
•being good at math
•all the above
Answer: All of the above.
Explanation:
Hi,can you please check my answer.
Answer:
no its not correct ans is 30 use calculator
Explanation:
What is the period of a wave that travels through a spring at 2.5 m/s and has a wavelength of 3m ?
Answer:
Explanation:
f
=
v
λ
where v is the velocity of the wave
λ
is the wavelength.
A 31.7 kg kid initially at rest slides down a frictionless water slide at 53.2 degrees, how fast is she moving in 3.45 s later?
Answer:
34.55 m/s
Explanation:
a cheetah has a speed of 100 km/h. if the cheetah runs for 5 hours, then what’s it’s speed ?
Answer:
Explanation:
idk
Pls help me Will mark you as brain
Answer:
reversibility
Explanation:
A gyroscope slows from an initial rate of 29.6 rad/s at an angular acceleration of 0.54 rad/s2. 50% Part (a) How long does it take to come to rest in seconds? t = ?
50% Part (b) How many revolutions does it make before stopping? n= ?
The gyroscope slows from an initial rate of 29.6 rad/s at an angular acceleration of 0.54 rad/s2.
Part (a) How long does it take to come to rest in seconds? t = ?
The angular deceleration is given by the negative value of the angular acceleration; thus:
α = -0.54 rad/s2
The initial velocity is given by the value,
ω1 = 29.6 rad/s.
The final velocity, ω2 = 0 rad/s.
The formula for angular acceleration is:
ω2 = ω1 + αt,
where:
ω1 = 29.6 rad/s
ω2 = 0 rad/s
α = -0.54 rad/s
2t = ?
Substitute the values in the formula above and solve for t.
0 = 29.6 - 0.54tt = 29.6/0.54t = 54.8 seconds
Therefore, it takes 54.8 seconds to come to rest in seconds.
Part (b)The number of revolutions that the gyroscope makes before stopping is given by:
n = (ω1/2π)t,
where:
ω1 = 29.6 rad/s
t = 54.8 s
n = ?
Substitute the values in the formula above and solve for n:
n = (29.6/2π)(54.8) revolutions
n ≈ 277.4
Therefore, the number of revolutions that the gyroscope makes before stopping is approximately 277.4 revolutions.
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What scientific law or principle allows us to
say that all the PE is converted to KE?
The law of conservation of energy
Energy cannot be created or destroyed, but it can be changed from one form to another.
KE + PE = constant
A food worker has cooled a pot of soup from 136*F to 70*F within 2 hours.What is the maximum amount of time she should take to cool the soup from 70*F to 41*F
A. 2 hours
B. 4 hours
C. 6 hours
D. 8 hours
The maximum amount of time a food worker should take to cool the soup from 70*F to 41*F is 4 hours.The correct answer is b.
According to the FDA's Food Code, potentially hazardous foods must be cooled from 135°F to 70°F within two hours, and from 70°F to 41°F within an additional four hours.Foodborne illnesses can be prevented by the following measures: Cook meat to the correct temperature.
Bacteria that cause foodborne illness can be killed by cooking food to the correct internal temperature. For example, ground beef should be cooked to an internal temperature of at least 160°F. The internal temperature should be checked with a food thermometer.
Take steps to keep the kitchen clean. It's critical to keep the kitchen clean to avoid the spread of bacteria. Countertops, utensils, and cutting boards should all be cleaned with hot soapy water.Routinely rinse fruits and vegetables. Vegetables and fruits should be thoroughly rinsed before consuming to remove any germs or dirt that might be present.
You should wash the produce under running water before cutting or eating it.Avoid cross-contamination. Keep raw meat away from cooked food to prevent contamination. You should never use the same knife or cutting board to cut both raw meat and fresh vegetables.
If you need to use the same cutting board, make sure to clean it thoroughly before reusing it.
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Please design the differential amplifier shown in Fig. P3 to meet the following specifications: (1) Two NMOS transistors are matched: unCox = 400 UA/V2, Vtn = 0.8 V, n = 0.02 V-!, Wn = 4.Wp, L = 0.2 um. Please short the BODY to the SOURCE. (2) Two PMOS transistors are matched: up Cox = 200 UA/V², Vtp = -0.8 V, p = 0.04 V?, Wp = TBD, L = 0.2 um. Please short the BODY to the SOURCE. (3) Iss = 2 mA. (4) Vs = 0.3 V. (5) The DC voltages of both VOP and VON 3.5 V. (6) The small-signal gain Av = (vop – Von) (Vip - Vin) 10. (7) The differential AC sinusoidal signal, vi = (Vip - Vin), has 100 mV amplitude and 1 kHz frequency (8) VDD = 5 V. Design procedure: (a) Design Wp, W. (=4.Wp), VB, and Rp by hand-calculations. Please round the resolution of Wp and Wn to 0.1 um. (Hint: 2n and 2p could be zero for your hand-calculations.)
For the designing of differential amplifier following were found out :
the small-signal gain is zero.
the transconductance (gm) and output resistance (ro) of the NMOS transistors are -640 * (W/L) μA/V and 1 / (8 * (W/L)) kΩ respectively.
the transconductance (gm) and output resistance (ro) of the PMOS transistors are -320 * (W/L) μA/V and respectively.
NMOS transistor: Wn = 0.03 μm, L = 0.2 μm
PMOS transistor: Wp = 0.0075 μm, L = 0.2 μm
Bias current: Itail = 1 mA
Resistance: R = 0.3 kΩ
To design the differential amplifier according to the given specifications, we will follow these steps:
Step 1: Calculate the small-signal gain (Av)
Step 2: Determine the transconductance (gm) and output resistance (ro) of the NMOS transistors
Step 3: Determine the transconductance (gm) and output resistance (ro) of the PMOS transistors
Step 4: Calculate the tail current (Itail) based on the specified Iss
Step 5: Determine the resistance (R) value
Step 6: Calculate the width (Wp) of the PMOS transistor
Step 7: Calculate the width (Wn) of the NMOS transistors
Now let's go through each step in detail.
Step 1: Calculate the small-signal gain (Av)
Given: Av = 10, VOP = VON = 3.5V
Av = (vop - von) / (vip - vin)
10 = (3.5 - 3.5) / (0.1)
10 = 0 / 0.1
Since the numerator is zero, the small-signal gain is zero.
Step 2: Determine the transconductance (gm) and output resistance (ro) of the NMOS transistors
Given: unCox = 400 μA/V², Vtn = 0.8V, n = 0.02 V^(-1), L = 0.2 μm
gm = 2 * unCox * (W/L) * (Vgs - Vtn)
ro = 1 / (lambda * unCox * (W/L))
We need to design the amplifier for DC operation (Vin = Vbias), where the differential voltage (vgs = Vin - Vbias) should be zero to operate the transistors in the saturation region.
For the NMOS transistors:
Vgs = 0 (since Vin = Vbias)
gm = 2 * unCox * (W/L) * (Vgs - Vtn)
= 2 * 400 μA/V² * (W/L) * (0 - 0.8)
= -640 * (W/L) μA/V
ro = 1 / (lambda * unCox * (W/L))
= 1 / (0.02 V^(-1) * 400 μA/V² * (W/L))
= 1 / (8 * (W/L)) kΩ
Step 3: Determine the transconductance (gm) and output resistance (ro) of the PMOS transistors
Given: upCox = 200 μA/V², Vtp = -0.8V, p = 0.04 V^(-1), L = 0.2 μm
Similarly, for the PMOS transistors, we need to design the amplifier for DC operation (Vin = Vbias), where the differential voltage (vsg = Vbias - Vin) should be zero to operate the transistors in the saturation region.
For the PMOS transistors:
Vsg = 0 (since Vin = Vbias)
gm = 2 * upCox * (W/L) * (Vtp - Vsg)
= 2 * 200 μA/V² * (W/L) * (-0.8 - 0)
= -320 * (W/L) μA/V
ro = 1 / (lambda * upCox * (W/L))
= 1 / (0.04 V^(-1) * 200 μA/V² *
= 1 / (5 * (W/L)) kΩ
Step 4: Calculate the tail current (Itail) based on the specified Iss
Given: Iss = 2 mA
Itail = Iss / 2
= 2 mA / 2
= 1 mA
Step 5: Determine the resistance (R) value
Given: Vs = 0.3 V, VDD = 5 V
We can calculate the resistance (R) value using Ohm's Law:
Vs = Itail * R
0.3 V = 1 mA * R
R = 0.3 kΩ
Step 6: Calculate the width (Wp) of the PMOS transistor
To calculate Wp, we'll use the equation for the tail current:
Itail = 2 * upCox * (Wp/L) * (VDD - Vtp)^2
1 mA = 2 * 200 μA/V² * (Wp/0.2 μm) * (5 V + 0.8 V)^2
1 mA = 2 * 200 μA/V² * (Wp/0.2 μm) * (5.8 V)^2
Solving for Wp:
Wp = (1 mA * 0.2 μm) / (2 * 200 μA/V² * (5.8 V)^2)
Wp = 0.01 μm / (2 * 200 μA/V² * 33.64 V^2)
Wp ≈ 0.0075 μm
Step 7: Calculate the width (Wn) of the NMOS transistors
Given: Wn = 4 * Wp
Wn = 4 * 0.0075 μm
Wn = 0.03 μm
So, the design parameters for the differential amplifier are as follows:
the small-signal gain is zero.
the transconductance (gm) and output resistance (ro) of the NMOS transistors are -640 * (W/L) μA/V and 1 / (8 * (W/L)) kΩ respectively.
the transconductance (gm) and output resistance (ro) of the PMOS transistors are -320 * (W/L) μA/V and respectively.
NMOS transistor: Wn = 0.03 μm, L = 0.2 μm
PMOS transistor: Wp = 0.0075 μm, L = 0.2 μm
Bias current: Itail = 1 mA
Resistance: R = 0.3 kΩ
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A 67-pm X-ray beam is incident on a calcite target. Find the largest wavelength, in pm, that can be expected from a scattered X-ray beam in this experiment
the largest wavelength that can be expected from a scattered X-ray beam in this experiment is 36.8 pm.
The calcium ions are at the center of the calcium planar group, while the carbonate planar group is perpendicular to it. The angle between the carbonate planes and the calcium planes is 120 degrees. In order to find the largest wavelength, we need to use Bragg's Law which is stated as:nλ = 2d sinθWhere,θ = angle between the incident beam and reflecting plane (in degrees) d = distance between the crystal planesλ = wavelength of the incident beam n = 1, 2, 3,.... i.e., the order of reflection Here, we are considering only the first-order reflection. We can see that in the above image that the distance between the reflecting planes in calcite is given as:
d = 2.84 Å (angstroms) We can use the formula
1 Å = 10^-10 m = 10^-2 nm to convert it to nm.
So, d = 2.84 x 10^-10 x 10^2 = 2.84 x 10^-8 m
Now, we need to find the value of θ.To find the value of θ, we can use the formula:
tan θ = opposite/adjacent tan θ = 67 pm / 2.84 x 10^-8 m tan θ = 0.235 x 10^-9θ = tan^-1 (0.235 x 10^-9)θ = 0.0135 degrees (approx)
Now, we can substitute the value of d and θ in the formula of Bragg's law.
nλ = 2d sinθλ = 2d sinθ / nλ = 2 x 2.84 x 10^-8 x sin (0.0135) / 1λ = 3.68 x 10^-12 m = 36.8 pm
Thus, the largest wavelength that can be expected from a scattered X-ray beam in this experiment is 36.8 pm.
Using Bragg's law we found that the largest wavelength that can be expected from a scattered X-ray beam in this experiment is 36.8 pm.
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A shell is fired at an initial speed of 2500 m/s at an initial angle of 45 degrees. Find the shell's horizontal range and the amount of time the shell is in motion. (note that because it is fired from the ground to the ground, they displacement = 0.)
Answer:
d= 637323 meters
t= 360.5 seconds
Answer:
Explanation:
Since the height from which the shell was fired is the same as the height at which it lands (on the ground, to be specific), we will use the range equation. That is the only time you CAN use the range equation (when the initial height and the final height are exactly the same). The range equation is:
\(r=\frac{v_0^2sin(2\theta)}{g}\) where v0 is the initial velocity, theta is the angle, and g is the pull of gravity (NOT negative). Filling in:
\(r=\frac{(1500)^2sin(9.0*10^1)}{9.8}\) so, doing all that math gives us:
r = 6.4 × 10⁵ meters
A crowbar with length 200m is used to lift a load of 600N if the distance between fulcrum and load is 0. 75 m calculate effort ma vr efficiency effort distance
Effort is 600N, load distance is 0.75m, effort distance is 199.25m, effort MA is 0.00377, VR is 265.67 and the efficiency is 0.22%.
Effort is the force that is applied on the crowbar to move the load. Load is the object that needs to be moved. Fulcrum is the pivot point or the fixed point around which the crowbar rotates. The distance between the fulcrum and the load is known as load distance. The distance between the fulcrum and the effort is called effort distance.
Effort = 600N
Load distance = 0.75m
Effort distance = 200 - 0.75 = 199.25m
Effort MA (Mechanical Advantage) = Load distance / Effort distance
Effort MA = 0.75 / 199.25 = 0.00377VR (Velocity Ratio) = Effort distance / Load distance
VR = 199.25 / 0.75 = 265.67
Efficiency = (Load * Load distance) / (Effort * Effort distance)
Efficiency = (600 * 0.75) / (Effort * 199.25) = 0.00224 * 100% = 0.22%
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Suki has been exercising more and eating healthy for two weeks. However, she has not really lost any weight and cannot see a difference in her body. She does feel a little better. At the same time, she is a bit frustrated with the lack or results. What is the BEST response to Suki’s concerns?
options:
A.
Being healthy is its own reward so she should not worry about appearance.
B.
She should be seeing immediate results so she needs to try something else.
C.
It takes a while to see significant results so she should keep it up and be patient.
D.
Improving diet and exercise habits does not generally change physical appearance.
PLEASE NO LINKS
Answer:
C
Explanation:
Most often you will not see immediate results with dieting and exercising.
Exercise helps to increase the rate of metabolic activities in the body. So it will helps to reduce the issues from heavy calories. Thus increasing exercise helps to balance food intake but to get a significant change in weight, we have to waite and continue the exercises.
What is metabolism?Anabolism and catabolism together called as metabolism. Anabolism is the synthesis of biological compounds whereas catabolism is breaking or decomposition reaction. These biochemical reaction regulates the functions in our body.
If we uptake high calorie food and its not burned by digestion then it will leads to weight gain and other health issues. Fat will deposits in body if the calorious foods are not digested properly.
Exercises helps to increase the rate metabolic activities in our body. It strengthens our muscles and bones and burn extra calories of food by utilise it to work out.
Therefore, increasing exercise will help balance the larger than usual calorie intake but It takes a while to see significant results so she should keep it up and be patient. Hence, option C is correct.
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how many gates control flow of na+ though voltage-gated na+ channels?
Voltage-gated sodium (Na+) channels have three gates that control the flow of Na+ ions: the activation gate, the inactivation gate, and the selectivity filter.
Voltage-gated sodium (Na+) channels have three gates that control the flow of Na+ ions: the activation gate, the inactivation gate, and the selectivity filter. The activation gate is responsible for opening and closing the channel in response to changes in membrane potential, allowing the influx of Na+ ions into the cell during depolarization. The inactivation gate is a separate region of the channel that closes shortly after the activation gate opens, preventing further Na+ influx and contributing to the repolarization phase of the action potential. The selectivity filter ensures that only Na+ ions can pass through the channel and not other ions. Therefore, all three gates work together to control the flow of Na+ through voltage-gated Na+ channels.
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A 5 kg rock and a 10 kg rock are dropped from a height of 10 m. Which of the following statements describes what happens to the potential energy of the rocks?
Answer:
statement not given greater mass has greater potential energy at same height
explain in 2-3 sentences how a genotype determines a phenotype!
Will give b to the best one
Answer:
Genotypes are determined by tests. Genotype and phenotype sound the same but mean different things. The phenotype is determined by your genotypes and by your genes or traits, like hair color or type, eye shape and color, body and height. Were all unique, even identical twins, based on the way they look or act. Your uniqueness is based on your genetic make-up, that we inherited from our parents.
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Brainliest please!
a roller coaster is at the top of a 72m hill and weighs 134 kg. the coaster (at this moment) has potential energy. calculate it
Answer:
94,550.4 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 9.8 m/s²
We have
PE = 134 × 9.8 × 72 =94,550.4
We have the final answer as
94,550.4 JHope this helps you
A weightlifter lifts a 500 N barbell with no acceleration, 1.25 meters. How much work did she do in lifting the weights?(step by step)
Answer:
–625 J
Explanation:
So, we got this formula for the work
W=mgd(Cosθ)
but remember when it's liftin somethin, its work gon be against the work of gravity, so
Cos180°= –1
W=500×1.25×(–1)
W= –625 J
an electron is released from rest and travels over a potential difference of 2500 v. what is its final velocity? the mass of an electron 9,1 x 10 -31 kg
Final velocity of the electron, v = 5.4 × 10⁶ m/s.
Potential difference, ΔV = 2500 V;
Charge on an electron, q = 1.6 × 10⁻¹⁹ C;
Mass of an electron, m = 9.1 × 10⁻³¹ kg
the final velocity of an electron using the formula, v = √((2qΔV) / m)Where, v = final velocity of an electron after traveling over a potential difference ΔVq = charge on the electron , m = mass of the electron.
Substituting the given values in the above equation,
we getv = √((2 × 1.6 × 10⁻¹⁹ C × 2500 V) / 9.1 × 10⁻³¹ kg)
Therefore, the final velocity of the electron is 5.4 × 10⁶ m/s.
An electron of mass 9.1 × 10⁻³¹ kg is released from rest and travels over a potential difference of 2500 V.
We can calculate the final velocity using the formula for kinetic energy, K = (1/2) mv²
Where, K = Kinetic energy of the electron , m = mass of the electron , v = final velocity of the electron.
The initial kinetic energy of the electron is zero, as it is released from rest.
Hence, the total energy gained by the electron is equal to its final kinetic energy.
The potential difference ΔV between the two points is given as 2500 V.
Hence, the work done by the electric field in moving an electron of charge q from one point to another with a potential difference ΔV is given by W = qΔV
We know that the work done is equal to the change in kinetic energy, as per the work-energy theorem.
So, the work done by the electric field in accelerating an electron is given byqΔV = (1/2) mv²Solving for v,v = √((2qΔV) / m)
On substituting the values given in the question,
we get v = √((2 × 1.6 × 10⁻¹⁹ C × 2500 V) / 9.1 × 10⁻³¹ kg)
Final velocity of the electron, v = 5.4 × 10⁶ m/s.
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A resting electron is liberated, and it moves over a 2500 volt potential difference. Therefore, the final velocity of the electron after traveling over a potential difference of 2500 V is approximately 5.93 x 10⁶ m/s.
The idea of energy conservation can be used to determine an electron's final velocity after it crosses a 2500 V potential difference. The change in the electron's potential energy caused by the electric potential difference can be transformed into kinetic energy.
The potential energy (PE) gained by the electron is given by:
PE = q × V
Where:
q is the charge of the electron (1.6 x 10⁻¹⁹ C),
V is the potential difference (2500 V).
The change in potential energy is equal to the change in kinetic energy:
ΔPE = ΔKE
Therefore, we have:
q × V = (1/2) × m × v²
Where:
m is the mass of the electron (9.1 x 10⁻³¹ kg),
v is the final velocity of the electron.
Rearranging the equation, we can solve for v:
v² = (2 × q × V) / m
v = √((2 × q × V) / m)
Plugging in the values, we have:
v = √((2 × (1.6 x 10⁻¹⁹ C) × (2500 V)) / (9.1 x 10⁻³¹ kg))
v = 5.93 x 10⁶ m/s
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Science question! helppppp
Let's take this problem step-by-step:
What does this problem want to solve:
⇒ find two pendulums that will swing back and forth in the least amount
of time
Therefore:
⇒ must find the equation that calculates that period or swing time of a
pendulum
Equation: \(T = 2\pi \sqrt{\frac{L}{g} }\)
L: length of the pendulumg: gravitational accelerationBased on the equation:
⇒ the longer the string is ⇒ the greater the swing time
Thus:
⇒ pendulum Y and Z will have the least amount of swing time
Answer: (B)
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Why is Aswan, Egypt one of the hottest places on Earth in July?
Why does Canada experience much larger differences in temperature from January to July than does Brazil?
Aswan, Egypt is one of the hottest places on Earth in July because of its location in the Sahara Desert, which is known for its extreme heat.
Canada experiences much larger differences in temperature from January to July than Brazil due to its location in the Northern Hemisphere,
Aswan, Egypt is one of the hottest places on Earth in July because of its location in the Sahara Desert, which is known for its extreme heat. The desert is characterized by low humidity and clear skies, which allows the sun's radiation to heat the ground and air quickly.
Canada experiences much larger differences in temperature from January to July than Brazil due to its location in the Northern Hemisphere, which means it experiences the seasons in the opposite way to Brazil, which is located in the Southern Hemisphere. During the winter months in Canada (January), the days are shorter, the angle of the sun is lower, and there is less direct sunlight, resulting in colder temperatures.
Brazil, on the other hand, is closer to the equator and experiences relatively consistent temperatures throughout the year. Therefore, Brazil does not experience the same large differences in temperature from January to July as Canada does.
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PLEASE PLEASE PLEASE HELP FAST!!!!!!!!!!!!!!!
Answer:
I have examined the different parts of blub and I assume the answer is (D)T and U
Hope this helps you
A humpback whale dove beneath the ocean's surface, and 310 seconds later it sang to
another whale that was 1,800 meters away. The song's sound wave traveled at a constant
velocity of 1,500 meters per second toward the other whale. How much time did it take the
sound wave to travel from one whale to the other?
The sound wave took 1.2 seconds to travel from one whale to the other.
Velocity is a physical quantity that describes the rate of change of an object's position with respect to time and includes both the speed and direction of motion. It is a vector quantity, meaning it has both magnitude and direction and is typically measured in meters per second (m/s) or other appropriate units.
The time it took for the sound wave to travel from one whale to the other can be calculated using the formula:
time = distance/velocity
In this case, the distance between the whales is 1,800 meters and the velocity of sound in water is 1,500 meters per second. Therefore:
time = 1,800 meters / 1,500 meters per second
time = 1.2 seconds
Hence, The distance between the two whales was covered by the sound wave in 1.2 seconds.
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The electric field between two parallel plates connected to a 45 V battery (which produces a 45 V difference in potential between the plates) is 1500 N/C. How far apart are the plates?
ANSWER is 0.03m
\(d=\frac{v}{e}=\frac{45}{1500}=0.03\)where d is the distance between the plates, v is difference in potential between the plates, e is electric field.
Jordyn places a balloon near some paper scraps, but nothing happens. After Jordyn
rubs the balloon against her shirt, the paper scraps start sticking to the balloon.
Jordyn's teacher notes that there is now an electric force between the balloon and
the paper.
What could have happened when the balloon was rubbed on Jordyn's shirt to cause
this electric force?
The balloon has gained a net electric charge.
The balloon has lost its net electric charge.
The net electric charge of the balloon did not change.
A balloon absorbs electrons from a wool fabric when it is rubbed against it, leaving the balloon with a negative charge and the wool with a positive charge.
Is there static electricity in a balloon?Electrons from the atoms and molecules in your hair migrate to the balloon when you brush it against your head. The balloon acquires a negative charge thanks to the negative charge of electrons, but your hair retains a positive charge.
Electrons migrate from the hair or wool to the balloon when the balloon is rubbed against it. The balloon picks up a net negative charge because electrons have a negative charge. The can rolls because the positive charges in the can are drawn to the negative charges in the balloon.
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A group of students doing a physics experiment are studying the conservation of momentum. The experiment asks the students to use a bouncy ball to measure the momentum before and after a collision. The mass of the ball is given to the students (1 kg). The only items allowed to be used are a meter stick and a stopwatch. Three students have written their own notes for how they want to solve the problem of determining the conservation of momentum of the ball elastically colliding with a surface. Which is the best method to use
The best method to determine the conservation of momentum of the ball elastically colliding with a surface is to use the method outlined by Student 3.
Student 3's method likely involves measuring the initial velocity of the ball by dropping it from a known height and timing how long it takes to reach the surface using a stopwatch and the meter stick to measure the distance. Then, they would measure the rebound height of the ball after the collision and use the same process to calculate the final velocity. By comparing the initial and final velocities, they can calculate the momentum before and after the collision and determine if momentum is conserved.
This method is preferred because it directly measures the velocities and relies on the principle of conservation of momentum. It also utilizes the given materials (meter stick and stopwatch) effectively. Other methods may not provide accurate measurements or rely on assumptions that may introduce errors.
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A fish is swimming 15 m below the surface of a lake
The density of the water is 1000 kg /m3
.
Atmospheric pressure is 100 000Pa.
The acceleration of free fall g is 10 m / s2
.
What is the total pressure on the fish?
A 50 000Pa
B 120 000Pa
C 150 000Pa
D 250 000Pa
the answer is D but i need a proper explanation too.
The total pressure of the fish is 250 000Pa.
Given that,
Depth
at which the fish is swimming = 15m
Atmospheric pressure
= 100 000Pa
Acceleration
of free fall = 10m\s²
The
density
of the water = 1000kg\m³
We know that,
P= P₀+\(\sigma\)gh
where,
P= Total pressure
P₀=Atmospheric pressure
\(\sigma\)= density
h= depth
Now putting the values in the above formula we have,
P = P₀+\(\sigma\)gh
P= 100 000 +1000×10×15 Pa
=100 000+ 150000Pa
=250 000Pa
The total pressure of the fish is 250 000Pa.
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IMPORTANT PLEASE HELP
a child of mass 35 kg moves down a sloping path. the sloping path makes an angle of 4.5degree with horizontal . the constant speed of child along the path is 6.5ms-1. calculate
1.the vertical distance through which the child moves in 1.0s.
2.the rate at which potential energy is being lost (g=9.81ms-2)
The vertical component of velocity here is 0.509 m/s. Then the vertical distance in 1 s is being 0.509 m. Then the potential energy is 174.5 J.
What is potential energy ?Potential energy of an object is generated by virtue of its position from a height h from the ground. It is related to the mass and gravity and the height h as follows:
p = mgh.
The velocity of the child = 6.5 m/s
vertical component of v = 6.5 sin 4.5° = 0.509 m/s
thus, vertical distance or height moved in 1 s = 0.509 m
mass of the child = 35 kg
then potential energy p = 35 kg× 0.509 m/s × 9.8 m/s² = 174.5 J
Therefore, the potential energy being lost will be 174.5 J.
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a student rubs a plastic rod with a cloth the rod becomes positevly charged what has happened to the rod
Answer:
When a plastic rod is rubbed with a cloth, it becomes charged. Electrons are rubbed off the cloth and onto the rod by friction. This leaves the rod with a negative charge and leaves the cloth with a positive charge.