It is necessary to blank the spectrophotometer whenever the wavelength is changed to eliminate stray light interference and ensure accurate readings.
Spectrophotometers are used in biochemical laboratories to quantify the concentration of specific molecules in a sample. It works by measuring the intensity of light absorbed by the sample at a specific wavelength of light. The purpose of blanking the spectrophotometer is to eliminate any light absorption caused by impurities or other substances in the solvent or sample.
These impurities are referred to as stray light, and they can interfere with the readings of the spectrophotometer. Blank solutions are used to detect the presence of stray light and to correct the instrument to zero absorbance before taking the readings. The blank solution contains the same solvent and reagents used in the sample.
By blanking the spectrophotometer before taking the readings, it ensures that the readings are accurate, and the interference of stray light is eliminated.
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If an engine does 400 J of work in 5 s, how much power was generated?
A.8W
B.8000W
C.800W
D.80w
Answer:
the answer is c
Explanation:
If a 3kg ball 5m in the air is moving at 7m/s.
a. What is its kinetic energy?
b. What is its potential energy?
c. What is its mechanical energy?
a. Kinetic Energy = 49j
b. Potential Energy= 147 j
c. Mechanical Energy = 196 j
What is kinetic energy?Kinetic energy of an object is the energy that it possesses due to its motion which is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.
a. Kinetic Energy = 1/2 * m * v^2,
KE = 1/2 * 3kg * (7m/s)^2 = 49 J.
b. Potential Energy = m * g * h,
PE = 3kg * 9.8 m/s^2 * 5m = 147 J.
c. Mechanical Energy = KE + PE,
ME = 49 J + 147 J = 196 J.
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Taking into account the definition of kinetic, potencial and mechanical energy, if a 3kg ball 5m in the air is moving at 7m/s, the kinetic energy is 73.5 J, the potential energy is 147.15 J and the mechanical energy is 220.65 J.
Deinition of Kinetic energyKinetic energy is the energy possessed by a body or system due to its movement.
Kinetic energy is defined as the amount of work necessary to accelerate a body of a certain mass and in a position of rest, until it reaches a certain speed. Once the final speed is reached, the amount of kinetic energy accumulated will remain constant, that is, it will not vary, unless another force acts on the body again.
Kinetic energy is represented by the following expression:
Ec = 1/2×m×v²
Where:
Ec is kinetic energy, which is measured in Joules (J).m is mass measured in kilograms (kg).v is velocity measured in meters over seconds (m/s).Definition of Potential energyGravitational Potential Energy is the energy that an object possesses due to its position in a gravitational field and represents the potential that an object has to do work as a result of being located in a particular position within that gravitational field.
For an object with mass m, at height h, the expression applied to the gravitational energy of the object is:
Ep= m×g×h
Where:
Ep is the potential energy in joules (J).m is the mass in kilograms (kg).h the height in meters (m).g is the acceleration of fall in m/s² (approximately 9.81 m/s²).Definition of Mechanical energyMechanical energy is that which a body or a system obtains as a result of the speed of its movement or its specific position, and which is capable of producing mechanical work. This is:
Potential energy + kinetic energy = total mechanical energy
The principle of conservation of mechanical energy indicates that the mechanical energy of a body remains constant when all the forces acting on it are conservative (a force is conservative when the work it does on a body depends only on the initial and final points and not the path taken to get from one to the other.)
Kinetic energy in this caseIn this case, you know:
m= 3 kgv= 7 m/sReplacing the definition of kinetic energy:
Ec = 1/2×3 kg× (7 m/s)²
Solving:
Ec= 73.5 J
The kinetic energy is 73.5 J.
Potential energy in this caseYou know:
m= 3 kgh= 5 mg= 9.81 m/s²Replacing in the definition of potential energy:
Ep= 3 kg× 9.81 m/s²× 5 m
Solving:
Ep= 147.15 J
The potential energy is 147.15 J.
Mechanical energyBeing:
The kinetic energy is 73.5 J.The potential energy is 147.15 J.the mechanical energy can be calculated as:
Potential energy + kinetic energy = total mechanical energy
147.15 J + 73.5 J = total mechanical energy
Solving:
220.65 J = total mechanical energy
The mechanical energy is 220.65 J.
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the charge of 196 nc is uniformly distributed over the top surface of a circular plastic disk of radius 10.3 cm. what is the magnitude of the electric field on the axis of the disk at a distance of 11.3 cm from the disk's center?
The magnitude of the electric field on the axis of the disk at a distance of 11.3 cm from the disk's center is \(6.62 x 10^4 N/C.\)
Does electric field affect the magnetic field?Yes, an electric field can affect a magnetic field. Electric and magnetic fields are closely related and can interact with each other to produce electromagnetic phenomena.
What does Maxwell equation states?According to Maxwell's equations, a changing electric field creates a magnetic field, and a changing magnetic field creates an electric field. This means that the presence of an electric field can cause a change in a magnetic field, and vice versa.
The given numerical can be solved:
E = k * Q / (2 * R * h)
Replacing the given values, we get:
E = \((8.99 x 10^9 N \times m^2 / C^2) \times (196 x 10^-9 C) / (2 \times 0.103 m \times 0.113 m) = 6.62 x 10^4 N/C\)
So the magnitude of the electric field on the axis of the disk at a distance of 11.3 cm from the disk's center is\(6.62 x 10^4 N/C.\)
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what does it mean to be skeptical of health fraud
Something that is falsely advertised to help different health issues. An example could be Eyeball massagers
Are three coefficients of expansion alpha bita and gamma universal constant?
Answer:
As the temperature increases, the volume of the material also increases. This is known as thermal expansion. It can also be explained as the fractional change in the length or volume per unit change in the temperature.
The relation between alpha, beta, and gamma is given in the form of a ratio and the ratio is 1:2:3 and can be expressed as:
alpha=fracbeta2=fracgamma3
Following is the relation between the three:
L = L (1 + α.ΔT)
Where, α is the coefficient of linear expansion
A = A (1 + β.ΔT)
Where, β is the coefficient of aerial expansion
V = V (1 + γ.ΔT)
Where, γ is the coefficient of cubical expansion
V = V + γV.ΔT
V = V (1 + γ.ΔT)
L3 = L3 (1 + α.ΔT)3
L3 = L3 (1 + 3α.ΔT + 3α2.ΔT2 + α3.ΔT3)
L3 = L3 (1 + 3α.ΔT)
Alpha, beta, and gamma are related to one another in the form of a ratio, and that ratio is 1:2:3, and yes they are universal constants.
What is expansion?A substance's volume expands while its mass stays constant. Heating is typically the cause of expansion. When a substance is heated, the molecular bonds separating its particles weaken, the particles move more quickly, and the substance expands as a result.
Determine the relation as shown below,
L = L (1 + α × Δ T)
here, α is the coefficient of linear expansion
A = A (1 + β × Δ T)
here, β is the coefficient of aerial expansion
V = V (1 + γ × Δ T)
here, γ is the coefficient of cubical expansion
V = V + γ × V × Δ T
V = V (1 + γ × ΔT)
L3 = L3 (1 + α × Δ T)3
L3 = L3 (1 + 3α × ΔT + 3α2 × ΔT2 + α3 × ΔT3)
L3 = L3 (1 + 3α × Δ T)
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What is the formula of snell descartes on the refraction?
The relationship between the angles of incidence and refraction when a light ray passes across the boundary between two media with differing refractive indices is described by Snell-Descartes law.
Snell's law
n₁sinθ₁ = n₂sinθ₂
In the following equation, n1 and n2 stand for the refractive indices of the two media. θ₁ for angle of incidence (the angle between the incident ray and the normal to the boundary), and θ₂ for angle of refraction (the angle between the refracted ray and the normal to the boundary). Sometimes referred to as Snell-Descartes law, in its mathematical form.
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Which is the formula that describes the magnitude of an object's kinetic energy? A. kinetic energy = mass * (velocity)2 x 0.5
B. kinetic energy = mass x acceleration C. kinetic energy = mass x change in velocity
D. kinetic energy = mass x velocity
Answer:
A
kinetic energy=(mv²)/2
(1/2)(mv²)
(mv²)*0.5
where m=mass and v=velocity/speed
define boiling point
Answer:
Max. temp. in which water starts boiling....
Explanation:
eg. at 100 degree células.......
A wire, 20m long, is heated from a temperature of 5°C to 55°C. If the change in length is 0.020m, calculate the linear expansivity of the wire.
Answer:
0.01998⁰C;¹
Explanation:
you can see all steps in photo
Is the earth round? Or is it flat like some people say
Answer: The Earth is an oblate spheroid, meaning it is roughly spherical in shape but flattened at the poles and bulges at the equator. This shape has been scientifically proven through centuries of evidence and observations. While some people may claim that the Earth is flat, this idea is not supported by scientific evidence.
Jack cannot run as fast as Paul. He decides to go at his own pace and not run with Paul. Which principle of fitness is he following?
Progression
Overload
Individuality
Reversibility
Answer:
individuality
Explanation:
since he cannot run with paul he decided to run by himself making his exercise individual
Answer: individuality
Explanation:
(you can ignore this its just the deffintion of individuality)
This is a crucial principle, the fundamental fact that everyone is different! Everyone responds to training in a different way. If you are walking or cycling with a friend, and doing exactly the same amount of training, don’t be concerned if one of you gets fitter faster than the other – this is what individualisation is all about.
It might be that one of you is having some pressure at work or difficulties at home, but wherever it is, it’s surprising what can affect your training. Some days your training can go really well and the next day, even though it was exactly the same length workout, it can be a nightmare. This is individualisation.
A) What does the term greenhouse effect mean in relation to the Earth's climate?
b) How does atmospheric water vapor affect the climate? (
c) The atmosphere naturally contains carbon dioxide. Human activity produces carbon dioxide, for example, when carbon-based fuels are used. What is the reason that the increased concentration of carbon dioxide in the atmosphere changes the climate?
d) In climate change, the average temperature is predicted to rise, especially in the polar regions. How can the melting of continental glaciers and sea ice in polar regions accelerate the rise in temperature?
a) The greenhouse effect refers to the process by which certain gases in the Earth's atmosphere trap and re-emit heat from the sun, leading to a warming effect on the planet's surface.
These gases, including carbon dioxide, water vapor, methane, and others, act like a blanket around the Earth, absorbing and trapping the sun's radiation and preventing it from escaping into space.
b) Atmospheric water vapor is a key component of the Earth's climate system, as it plays a crucial role in the greenhouse effect. As water vapor absorbs and re-emits radiation from the sun, it helps to trap heat in the atmosphere and keep the planet warm.
However, the amount of water vapor in the atmosphere is strongly influenced by temperature and other factors, which can in turn affect climate patterns and weather events.
c) The increased concentration of carbon dioxide in the atmosphere changes the climate because it enhances the greenhouse effect. Carbon dioxide is a particularly potent greenhouse gas, as it absorbs and re-emits radiation across a range of wavelengths, effectively trapping more heat in the atmosphere. As humans burn fossil fuels and engage in other activities that release carbon dioxide into the air, the concentration of this gas increases, leading to a buildup of heat-trapping gases and a corresponding increase in global temperatures.
d) The melting of continental glaciers and sea ice in polar regions can accelerate the rise in temperature through a process known as positive feedback. As the ice melts, it exposes more land and water, which in turn absorb more solar radiation and heat up. This leads to further melting, which exposes even more land and water, and so on.
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derive an expression from the energy stored E, in a stretched wire of original length L cross sectional area A, e, tension e,and young modulus Y of the material of the wire
The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A
How to explain the expressionThe work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).
The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:
T = Y * (ΔL / L)
where Y is the Young's modulus of the material of the wire.
Now, let's calculate the work done to stretch the wire:
dW = T * dL
Integrating this expression from L to L + ΔL:
W = ∫ T * dL = ∫ Y * (ΔL / L) * dL
W = Y * ΔL * ∫ (dL / L)
W = Y * ΔL * ln(L) + C
Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.
Finally, the expression for the energy stored in the wire (E) is:
E = W = Y * ΔL * ln(L)
or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:
E = Y * e * ln(L) * A
Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:
E = Y * e * ln(L) * A
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12 A car travels in a straight line at speed v along a horizontal road. The car moves
against a resistive force F given by the equation
F = 400+kv²
where F is in newtons, v in ms-1 and k is a constant.
At speed v = 15ms-1, the resistive force F is 1100 N.
a
Calculate, for this car:
i the power necessary to maintain the speed of 15ms-¹,
ii the total resistive force at a speed of 30 ms-¹,
iii the power required to maintain the speed of 30ms-¹.
Answer:
i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii) Find the value of k first: F = 400 + k(15^2) k = 28/9 F = 400 +(28/9)(30^2) = 320
Explanation:
Do you think Mark Henry could be considered a leader? How and Why ?
Answer:
Mark Henry is considered as a leader as he inspired many people from his capabilities. He trained many people who wanted to become a strongest weight lifter.
Explanation:
Mark Henry was an American weight lifter who retired at the age of 45 on 26th October 2017. He was really strong person and has won many gold medals with his capabilities. In the childhood he was expelled from his school but he continued his journey towards his goals and became a strongest man in the world.
A boy threw a ball upward and it took 3 sec to reach the highest point. Determine the initial velocity of the ball.
Answer:
V initial = 29.4 m.s²
Explanation:
( Using the laws of motion)
V final = V initial + Acceleration × time
0 = V initial + ( -9.8)(3)
29.4 = V initial
* I took upward as positive that's why I substituted -9.8 *
* for V final we know that at maximum height the ball is not moving thats why is = 0 *
You would like to confirm Netwon's second law by running an experiment. You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude?
Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.
There is some other force present. This additional force is different for the two objects and accounts for the fact that the objects land at different times.
Newton's second law is not relevant in determining when an object will land on the ground.
One object must be heavier than the other and must therefore experience a greater gravitational acceleration.
Answer:
You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.
Explanation:
You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.
You decide to drop two different objects from a tall building and discover that one of the objects lands on the ground five seconds before the other object. What can you conclude? Newton's second law is not valid because each object should experience the same force of gravity and therefore should land at the same time.
A block weighing 200 N is pushing along a surface. If it takes 80 N to get the block moving and 40 N to keep the block moving at a constant velocity, What are the coefficients of friction μs and μk?
If a block weighing 200 N is pushing along a surface. If it takes 80 N to get the block moving and 40 N to keep the block moving at a constant velocity, the coefficients of friction μs and μk is: 0.4, 0.2.
What is the coefficients of friction us and uk?The coefficient of static friction (μs) can be determined using the equation:
fs = μs* Normal force
Where:
Normal force is the force perpendicular to the surface = weight of the block (200 N).
80 N = μs * 200 N
μs = 80 N / 200 N
μs = 0.4
Therefore the coefficient of static friction (μs) is 0.4.
The coefficient of kinetic friction (μk) can be determined using the equation:
f.k = μk * Normal force
Where:
Normal force = weight of the block (200 N).
40 N = μk * 200 N
μk = 40 N / 200 N
μk = 0.2
Therefore the coefficient of kinetic friction (μk) is 0.2.
Therefore the coefficients of friction are μs (coefficient of static friction) is 0.4 and μk (coefficient of kinetic friction) is 0.2.
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You and your dad are pushing your car out of the mud. You apply a force of 200 N and your dad applies a force of 250 N. What is the net force? Will the car move and if so, in what direction?
A. 450 N, yes, in the direction of the pushing
B. 0 N, no
C. 50 N, yes, in the direction of the dad
Answer:
I believe it's A (450 N)
Explanation:
Since both you and your dad are pushing in the same direction, you must add the force N to get the net force, which in this case in 450 N
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There are already several questions asking for this
question but the answers are neither complete nor correct. Please
read the question and help me with all the questions! Do not forget
= < 1. A uniform surface current flowing in the xy plane, described by surface current K = Kî generates a magnetic field MoK -î for z> 0 2 В. MOK -î for z < 0 2 a) Is it possible to find a magneti
The question is asking whether it is possible to find a magnetic vector potential for a given uniform surface current flowing in the xy plane and generating a magnetic field for different regions of space.
To determine whether it is possible to find a magnetic vector potential for the given scenario, we need to consider the conditions that must be satisfied. In general, a magnetic vector potential A can be found if the magnetic field B satisfies the condition ∇ × A = B. This is known as the magnetic vector potential equation.
In the given situation, the magnetic field is different for the regions above and below the xy plane. For z > 0, the magnetic field is described as B = MoK -î, and for z < 0, it is described as B = -MoK -î. To find the magnetic vector potential, we need to determine if there exists a vector potential A that satisfies the equation ∇ × A = B in each region.
By calculating the curl of A, we can check if it matches the given magnetic field expressions. If the curl of A matches the magnetic field expressions for both regions, then it is possible to find a magnetic vector potential for the given scenario. However, if the curl of A does not match the magnetic field expressions, then it is not possible to find a magnetic vector potential that satisfies the conditions.
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Warm air rises because it has less ___________.
Answer:
because it is less dense than the surrounding air
Explanation:
Mr X wa accued of peeding along a highway. He wa travelling at different peed,but an average peed of 80 km/h. Baed on thr given information, i Mr X gulity or innocent?
Mr. X is guilty if the average speed of the car was 80 km/h, if we consider the speed limit as 80 km/h.
Average speed i defined as the ratio of total distance and total time taken by the object to cover that distance. It may or may not be the constant speed of the whole journey. We can also say that average speed is the average of minimum speed and the maximum speed of the object during the entire journey. So there might be a point where Mr. X exceeded the speed above 80 km/h, which is the safe limit of speed. So Mr. X must be guilty for over speeding.
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A uniformly charged disk of radius 35.0cm carries charge with a density of 7.90× 10⁻³ C / m² . Calculate the electric. field on the axis of the disk at (a) 5.00cm,
The electric field on the axis of the disk at a distance of 5.00 cm is approximately 8.947 N/C.
To calculate the electric field on the axis of a uniformly charged disk, we can use the formula for the electric field due to a charged disk at a point on its axis:
E = (σ / (2ε₀)) * (1 - (z / √(z² + R²))),
where E is the electric field, σ is the charge density of the disk, ε₀ is the permittivity of free space, z is the distance from the center of the disk along the axis, and R is the radius of the disk.
Given:
Charge density (σ) = 7.90×10⁻³ C / m²,
Radius (R) = 35.0 cm = 0.35 m,
The distance along the axis (z) = 5.00 cm = 0.05 m.
Using these values, we can calculate the electric field on the axis of the disk at a distance of 5.00 cm.
Substituting the values into the formula:
E = (σ / (2ε₀)) * (1 - (z / √(z² + R²))),
E = (7.90×10⁻³ C / m²) / (2 * (8.854×10⁻¹² C² / N*m²)) * (1 - (0.05 m / √((0.05 m)² + (0.35 m)²))).
Simplifying the equation:
E = (7.90×10⁻³ C / m²) / (2 * (8.854×10⁻¹² C² / N*m²)) * (1 - (0.05 m / √(0.0025 m² + 0.1225 m²))),
E ≈ 8.947 N/C.
Therefore, the electric field on the axis of the disk at a distance of 5.00 cm is approximately 8.947 N/C.
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Please help this is about ecology. Who ever answers it first correctly I will give brainliest
An object of mass 50 g and density 5 g/cm3 is carefully lowered into a measuring cylinder containing 50 cm3 of water. What will the final volume reading be?
Answer: 60cm^3
Explanation:
Here we can use the relationship:
Density = mass/volume.
We know that density = 5g/cm^3 and mass = 50g, then we have:
5g/cm^3 = 50g/V
V = 50g/5g/cm^3 = 10cm^3
Then, when we introduce it in a cylinder with 50cm^3 of water, this is heavier than water (the density of the water is 1g/cm^3) it will sink, and the complete volume will be equal to the volume of the water plus the volume of the object:
Total Volume = 50cm^3 + 10cm^3 = 60cm^3
help please.
How many days occur between a new moon and a first quarter moon?
Answer:
7 days or a week
Explanation:
How much work is done on a cat that is pushed 50 meters with 3 N of force?
Answer:
150
Explanation:
work done = constant force x distance moved in the direction of force
W = F x S
(UNITS: J = N x m)
50 x 3 = 150
what do you think the average temperature will be this month in paris in degrees celsius?
Early morning clouds will change to partly cloudy sky later in the day temperature . High 52F. SW winds 10 to 20 mph.
What are France's typical degrees?Except for the Mediterranean region, where pleasant winters and scorching summers are more common, France typically experiences moderate winters and mild summers. The usual winter ranges from 32 to 46 degrees Fahrenheit, while the typical summer ranges from 61 to 75 degrees.
In July, how hot is Paris?Maximum daily temperatures in July ranged from 20°C to 43°C (68°F to 109°F). The range of daily lows in July is 45°F to 66°F (7°C to 19°C).
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objects of mass 5.0 kg and 2.0 kg are connected by a light cord that passes over a horizontal frictionless rod. a.) what is the acceleration of the system? b.) what is the tension in the cord on the 5.0 kg side? c.) what is the tension in the cord on the 2.0 kg side?
a) The acceleration of the system is 7.02 m/s².
b) The tension in the cord on the 5.0 kg side be 14.04 N.
c) The tension in the cord on the 2.0 kg side be 14.04 N.
Given parameters:
Mass of the two objects 5.0 kg and 2.0 kg.
They are connected by a light cord that passes over a horizontal frictionless rod.
Let the tension in the cord be T.
Acceleration of the system be a.
Then, equation of motion for 2 objects be:
T = 2.0 a
And. 5.0 g - T = 5.0 a
⇒ 5.0 × 10 -2.0 a = 5.0 a
⇒ 7.0 a = 50
⇒ a = 7.02 m/s².
And T = 2.0 ×7.02 N = 14.04 N.
Hence acceleration of the system be 7.02 m/s² and the tension in the both cord is 14.04 N.
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For the composite member of prob. 4. 37, determine the largest permissible bending moment when the member is bent about a vertical axis
The largest permissible bending moment for the composite bar is 0.083 Nm for the aluminum section and 0.000396 Nm for the brass section when the bar is bent about a vertical axis.
To determine the largest permissible bending moment for the composite bar, we need to calculate the moment of inertia for each material separately and use the parallel axis theorem to find the total moment of inertia.
The moment of inertia for the aluminum section is 5.19 × \(10^{-9}\)\(m^{4}\) and for the brass section is 1.23 × \(10^{-11}\)\(m^{4}\). The total moment of inertia for the composite bar is 5.22 × \(10^{-9}\) \(m^{4}\).
Using the allowable stress and moment of inertia, we can find the largest permissible bending moment for each section. For the aluminum section, the largest permissible bending moment is 0.083 Nm, and for the brass section, it is 0.000396 Nm.
Therefore, the largest permissible bending moment for the composite bar is 0.083 Nm for the aluminum section and 0.000396 Nm for the brass section, when the bar is bent about a vertical axis.
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