Why is the state of matter a physical
property of matter?

Answer:Question

Select the correct answer. Sami was blowing soap bubbles in his room where the temperature was 23 °C and the pressure was constant. He blew a soup bubble of volume 45 mL. The bubble suddenly escaped from the window where the temperature outside was 12 °C. Explain what will happen to the soap bubble? The volume of the soap bubble will increase to 46.73 mL. The volume of the soap bubble will increase to 86.25 mL. The volume of the soap bubble will decrease to 23.47 mL. The volume of the soap bubble will decrease to 43.33 mL.​

Explanation:

Question

Select the correct answer. Sami was blowing soap bubbles in his room where the temperature was 23 °C and the pressure was constant. He blew a soup bubble of volume 45 mL. The bubble suddenly escaped from the window where the temperature outside was 12 °C. Explain what will happen to the soap bubble? The volume of the soap bubble will increase to 46.73 mL. The volume of the soap bubble will increase to 86.25 mL. The volume of the soap bubble will decrease to 23.47 mL. The volume of the soap bubble will decrease to 43.33 mL.​

Answer:

graphite

Explanation:

graphite is also good conductor of electricity

When a tree is growing on a rock its weight can crush the rock, as a form of mechanical weathering is not a way trees are considered to affect weathering

Weathering is a process that breaks down or disintegrates the rocks which are present on the surface of our planet. Biological life can also affect weathering in many ways.

Tree roots can grow through rock cracks causing the cracks to expand. Sprouts can start to grow near cracks in rocks. The sprout when it grows would start to put pressure on the rocks by the roots that would penetrate them and also by the weight it exerts when it turns to a tree.

Tree’s roots (and other vegetation) can release acids that can cause weathering of rock. Plants are capable of producing acids to protect themselves against invaders like microbes and insects. When plants release acids, it would change the chemical composition of the rock that would eventually break the rock. This type of weathering is called chemical weathering

Trees (and other vegetation) when decomposing can cause chemical weathering. When trees decompose it could produce acids like carbonic acid that would help in disintegration of rocks.

When a tree is growing on a rock its weight would not directly crush the rock, as a form of mechanical weathering. Rocks with crack would be the main source of mechanical weathering by rocks.

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For the given equation, the mole-to-mole ratio and volume-to-volume ratio for all the gaseous reactants and products are 1:1.

For the given equation:

CH4(g) + O2(g) → CO2(g) + H2O(g)

Reactant/Product:

CH4(g)

O2(g)

CO2(g)

H2O(g)

Mole-to-Mole Ratio:

By comparing the reactant and product coefficients, we may extract the mole-to-mole ratio from the balanced equation.

CH4(g): 1 mole

O2(g): 1 mole

CO2(g): 1 mole

H2O(g): 1 mole

All of the reactants and products have a mole-to-mole ratio of 1:1:1:1.

Ratio of Volume to Volume:

The ideal gas law, which states that under constant temperature and pressure, the volume of a gas is directly proportional to the number of moles in the gas, can be used to calculate the volume-to-volume ratio.

All gaseous reactants and products have a mole-to-mole ratio of 1:1, hence the volume-to-volume ratio will also be 1:1. As a result, the volume of drug A and substance B will be equal.

You can just take the volume of substance A as the value for substance B if you know the volume of substance A and are trying to solve for the volume of substance B. Alternatively, the quantity of substances A and Bwill be the same, given the 1:1 volume-to-volume ratio.

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Answer:

At standard room temperature, \([{\rm OH^{-}] \approx 2.5 \times 10^{-7}\; \rm M\) when \([{\rm H^{+}] = 4.0 \times 10^{-8}\; \rm M\).

Explanation:

The following equilibrium goes on in water:

\({\rm H_{2}O}\, (l) \rightleftharpoons {\rm H^{+}}\, (aq) + {\rm OH^{-}}\, (aq)\).

The forward reaction is known as the self-ionization of water. The ionization constant of water, \(K_{\rm w}\), gives the equilibrium position of this reaction:

\(K_{\rm w} = [{\rm H^{+}] \cdot [{\rm OH^{-}}]\).

At standard room temperature (\(25\; {\rm ^{\circ}C}\)), \(K_{\rm w} \approx 10^{-14}\). Also, \([{\rm H^{+}}] = 4.0 \times 10^{-8}\; \rm mol \cdot L^{-1}\). Substitute both values into the equation and solve for \([{\rm OH^{-}}]\).

\(\begin{aligned} {[}{\rm OH^{-}}{]} &= \frac{K_{\rm w}}{[{\rm H^{+}}]} \\ &\approx \frac{10^{-14}}{4.0 \times 10^{-8}} = 2.5 \times 10^{-7}\end{aligned}\).

In other words, in an aqueous solution at standard room temperature, \([{\rm OH^{-}] \approx 2.5 \times 10^{-7}\; \rm M\) when \([{\rm H^{+}] = 4.0 \times 10^{-8}\; \rm M\).

Density is an intensive property as it does not depend on the quantity of the substances Whereas mass and volume are extensive property. Therefore, 3.51g of nitric acid will remain in 3 liters of solution with a density of 1.171 g/ l.

Density tells about the compactness of the substances, how much dense is the substances in other words. Object that is more denser than water they just sink in the water.

Mathematically,

Density of solution = mass of solution ÷volume marked on the graduated cylinder

Substituting all the values in above formula, we get

1.171 g/ l = mass of solution/ 3 liters

mass of solution= 1.171× 3

mass of solution =3.51g

Therefore, 3.51g of nitric acid will remain in 3 liters of solution with a density of 1.171 g/ l.

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Let's see that the first compound represents an oxide which is a combination resulting from the union of a metallic or nonmetallic element with oxygen. To name an oxide, you have to write "___ oxide", where the line is the name of the element. In this case, lithium is the element that is bonded with oxygen, so its name is lithium oxide.

The second compound that you can recognize as water, is an oxide too. So its name is also hydrogen oxide.

Answer:

More importantly, V2O5 thin film has been found to be a TE material with a relatively high Seebeck coefficient [24,25].

Explanation:

If a sample of gas has a volume of 2.50 L at 236 kPa and 75.0 °C, the pressure 1.18 atm is required.

Only ideal gas is subject to the ideal gas law; vanderwaal gas is not. Here, Boyle's and Charles' gas laws are combined. As a result, the new gas pressure is 1.18 atm.

The relation between Pressure, volume, and temperature can be given as:

PV = nRT

In which:

P = pressure of  gas

V= volume of gas

n =number of moles of gas

T =temperature of gas

R = Gas constant

= 0.0821 L.atm/K.mol

Combining Boyle's and Charles' gas law

P₁V₁/T₁ = P₂V₂/T₂

{ (5.28atm) (2.50 L)} ÷348 K ={ (P2) (3.75 L)} ÷298 K

P₂ =1.18 atm

Thus, the new pressure of gas is 1.18 atm when the temperature is changed to 348K and volume is increased to 3.75 L.

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Answer:

tannins also have negative effects. They are often anti-nutritional and can hinder digestion and metabolism, unlike polyphenols AND

Tannins can also help obstruct the blood's absorption of iron, which may lead to many health problems.

Explanation:

Answer:

There are three types of periods in the modern periodic table: very short periods, short periods, and long periods.

The difference between very short periods and short periods is the number of elements they contain. Very short periods only contain two elements, while short periods contain eight elements. The difference between short periods and long periods is the number of orbitals that can be occupied by electrons in each period. Short periods can only have electrons in the s- and p-orbitals, while long periods can also have electrons in the d-orbital.

Here is a table summarizing the differences between very short periods, short periods, and long periods:

Answer:

an ideal gas does not exist except as a conceptual notion, an ideal. Physicists and chemists idealized the behaviour of real gases so that they could explain these phenomena. Under conditions of low pressure and high temperature, all gases behave like real gases, even gases such as UF6 .

Answer:

True

Explanation:

Acetic acid will neutralize the addition of a strong base in an acetic acid/acetate buffer system.

In an acetic acid/acetate buffer system, the main purpose is to resist changes in pH when small amounts of acid or base are added. When a strong base is added, it increases the concentration of hydroxide ions (OH-) in the solution, which can shift the pH towards the basic side.

To neutralize the added strong base and maintain the buffer system, acetic acid (CH3COOH) acts as the main keyword. Acetic acid, being a weak acid, can react with the hydroxide ions (OH-) to form water (H2O) and acetate ions (CH3COO-). This reaction helps in counteracting the increase in hydroxide ions, thereby stabilizing the pH of the buffer system.

Water (H2O), acetate ions (CH3COO-), and hydronium ions (H3O+) are already present in the buffer system and do not actively neutralize the strong base. It is the addition of acetic acid that replenishes the buffer's acid component and maintains its pH buffering capacity.

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Answer:

Valence electrons are negatively charged particles located in the outermost shell of atoms that can be transferred or shared with other atoms. Valence electrons are important in chemistry because the number of valence electrons in a particular atom can be used to determine how the atom will react chemically with other atoms.

Gravitational Potential energy:

The Gravitational potential energy of

an object at a point above the ground

is defined as the work done in raising

it from the ground to that point against

gravity.

Consider an object of mass "m" is raised

to heighth from the ground.

A force is required to do this. the

minimum force required to raise the

object is equal to the weight of the

object[mg]

The object gains energy equal to the

work done on it. Let the work done on

the object against gravity be "w"

WorkDone=W= Force x displacement

=mgxh

..W=mgh

since the workdone on the object is

equal to "mgh" an energy equal to "mgh"

units is gained by object.This is the

potential energy of object at height "h"

.. P.E=mgh

A metastable state is a state of the substrate in which the reaction can proceed but typically requires a catalyst. This statement best describes a metastable state. The correct answer is C.

A metastable state is a state of the substrate in which the reaction can proceed but typically requires a catalyst. It is a state of matter that is not in equilibrium but appears to be in equilibrium for a long time, after which it collapses to its most stable state.

Metastability is the quality of a non-equilibrium system to remain in a quasi-stable state for a longer period than predicted by the system's relaxation time.

Here are some characteristics of metastable states: The equilibrium changes in the state but not in the rate. The activation energy difference between a catalyzed and an uncatalyzed reaction makes up the metastable state. The state is made up of transient complexes with the substrate.

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The name of the compound is (Z)-4,5-dimethyl-4-hepten-1-ol.

It contains a double bond (hence the "en" ending) between the 4th and 5th carbons from the end, and a hydroxyl group (-OH) attached to the 1st carbon.

The "dimethyl" prefix indicates that there are two methyl groups (-CH3) attached to the 4th carbon,

The "hepten" prefix indicates that there are seven carbons in the molecule with a double bond between the 4th and 5th carbons.

The "ol" ending indicates that it is an alcohol with the hydroxyl group attached to the 1st carbon.

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Answer:

CH³–C=CH——CH³–CH=CH²

Explanation:

THIS IS PROPYNE TO PROPENE

Solvent extraction, or liquid-liquid extraction, is a commonly employed technique for separating specific compounds from a mixture.

When conducting experiments involving solvent extraction, it is crucial to include the density of the solvent as a physical property in the pre-lab write-up of your lab notebook.

Solvent extraction, or liquid-liquid extraction, is a commonly employed technique for separating specific compounds from a mixture.

This method involves shaking the mixture containing two immiscible liquids, allowing them to separate into distinct layers, and subsequently isolating the desired compound.

The density of the solvents plays a vital role in solvent extraction experiments. It determines the layer identification after phase separation.

By understanding the relative densities of the two liquids involved, we can predict which liquid will be the top layer and which will be the bottom layer.

The less dense liquid will float on top, while the more dense liquid will sink to the bottom.

This knowledge enables us to determine the layer that contains the target compound of interest.

Including the density of the solvents in the pre-lab write-up ensures accurate layer identification during the solvent extraction process.

It is an essential physical property that aids in the successful isolation of desired compounds.

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The number of molecules of water in a collection of snowflakes with a mass of 0.005 grams is approximately 1.67 x 10^20 molecules.

To determine the number of molecules of water in a collection of snowflakes with a mass of 0.005 grams, we need to use the concept of moles and Avogadro's number.

We know the molar mass of water is approximately 18.015 grams/mol.

Mass (g) = Number of moles × Molar mass (g/mol)

0.005 g = Number of moles × 18.015 g/mol

Number of moles = 0.005 g / 18.015 g/mol ≈ 0.000277 mol

Avogadro's number states that there are approximately 6.022 x 10^23 molecules in one mole of a substance.

Number of molecules = Number of moles × Avogadro's number

Number of molecules = 0.000277 mol × 6.022 x 10^23 molecules/mol

Number of molecules ≈ 1.667 x 10^20 molecules

Therefore, the correct answer is C) 1.67 x 10^20 molecules.

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There are 0.030 moles of ZnCl₂ in 100.0 ml of a 0.300 M solution.

Molarity is a unit of concentration used to describe the amount of a solute dissolved in a given volume of solvent. It is defined as the number of moles of solute per liter of solution.

To calculate the number of moles of ZnCl₂ in a solution, we need to use the formula:

moles = concentration (molarity) x volume (in liters)

Given:

Concentration (molarity) = 0.300 M

Volume = 100.0 ml = 100.0 ml / 1000 = 0.100 L

Using the formula, we can calculate the number of moles of ZnCl₂:

moles = 0.300 M x 0.100 L

moles = 0.030 mol

Therefore, there are 0.030 moles of ZnCl₂ in 100.0 ml of a 0.300 M solution.

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The air pollution that forms primarily from car exhaust in the presence of sunlight is called photochemical smog.

Photochemical smog is a type of air pollution that is formed when pollutants, particularly nitrogen oxides (NOₓ) and volatile organic compounds (VOCs) emitted from car exhaust and industrial emissions, react in the presence of sunlight. It is characterized by the presence of a brownish haze and the formation of various secondary pollutants, such as ozone (O₃) and peroxyacyl nitrates (PANs).

The formation of photochemical smog involves complex chemical reactions. Sunlight provides the energy needed to drive these reactions, which can lead to the production of highly reactive compounds like ozone. These reactions typically occur in urban areas with high traffic and industrial activity, where emissions from vehicles and other sources are abundant.

Photochemical smog is known to have detrimental effects on human health and the environment. It can contribute to respiratory problems, eye irritation, and the formation of ground-level ozone, which is harmful to both human health and vegetation. To mitigate photochemical smog, efforts are made to reduce emissions from vehicles, control industrial pollution, and implement air quality regulations.

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Answer:

it's volume also decrease

Answer:

Reflection-energy waves bouncing off the surface of an object

Explanation:

Explanation:

proton normally = atomic number

protons = 9

The conversion of pyruvate to acetyl CoA occurs in a cellular organelle called the mitochondria.

Mitochondria are often referred to as the "powerhouses" of the cell because they play a crucial role in energy production through cellular respiration.

During cellular respiration, pyruvate, which is the end product of glycolysis, undergoes further processing in the mitochondria. This step occurs in a specialized compartment of the mitochondria known as the matrix. Here, pyruvate is enzymatically converted to acetyl CoA through a series of reactions known as the pyruvate dehydrogenase complex.

The conversion of pyruvate to acetyl CoA is an important step in cellular respiration as it connects glycolysis, which occurs in the cytoplasm, to the subsequent citric acid cycle (also known as the Krebs cycle) that takes place in the mitochondria. Acetyl CoA is a key molecule that enters the citric acid cycle to generate further energy through the oxidation of carbon compounds.

The conversion of pyruvate to acetyl CoA is a critical metabolic step as it not only generates energy but also serves as a branching point for various metabolic pathways. Acetyl CoA can be further utilized for fatty acid synthesis, amino acid metabolism, or as a substrate for energy production through the citric acid cycle.

In summary, the conversion of pyruvate to acetyl CoA occurs within the mitochondria, specifically in the matrix, during cellular respiration. This step connects glycolysis to the citric acid cycle and plays a vital role in energy production and other metabolic processes.

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Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore,  production of 39 g of C\(_2\)H\(_2\) requires consumption of 53.6g of H\(_2\)O.

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance. We know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number.

moles of C\(_2\)H\(_2\)= mass of C\(_2\)H\(_2\)/molar mass of C\(_2\)H\(_2\)

                        =39 g /26.04

                        = 1.49moles

for 1 mole of C\(_2\)H\(_2\), 2 moles of H\(_2\)O is required.

for 1.49 moles of C\(_2\)H\(_2\), 2×1.49=2.98 moles of H\(_2\)O is required.

mass of water= moles× Molar mass

                       = 2.98×18

                       =53.6g

Therefore,  production of 39 g of C\(_2\)H\(_2\) requires consumption of 53.6g of H\(_2\)O.

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