why should you do you should

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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As the mass of the central star increases, the distance to the habitable zone increases and the size (width) of the habitable zone also increases.

The habitable zone is the distance from a star at which the liquid water could exist on the orbiting planet's surfaces. Habitable zone is also known as Goldilocks' zones, where the environmental conditions might be just right neither too hot nor too cold for life.

A star is a large luminous object which is found in space that produces heat and light energy as well as electromagnetic radiations. The habitable zone of a star is the zone where liquid water can be found. The distance to the habitable zone of a star increases with the increase in mass of the star.

Therefore, as the mass of the central star increases, the distance to the habitable zone also increases.

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Horizontal component , F cos θ.

Vertical component , F sin θ.

Now, as θ increases towards 90° cos θ decreases and

As θ increases towards 90° sin θ increases.

Therefore, horizontal component of F will decrease and vertical component will increase.

Hence, this is the required solution.

The statement "B. Gravity exists only on Earth" and the statement "E. Gravity doesn't exist between Earth and the sun"  is not true about gravity.

Gravity is a fundamental force of nature that exists in the whole universe, not just on Earth. It is a force that acts between any two objects that have mass. This means that statement "C. Gravity is a force that pulls two objects together" and "D. Gravity exists between two objects that have mass" are both true. Gravity plays a significant role in the functioning of our solar system. The sun's gravitational force acts on the planets, including Earth, keeping them in their orbits. Similarly, Earth's gravitational force attracts objects towards its center, giving weight to objects on its surface. Gravity is the force that holds Earth in orbit around the sun and is responsible for the planets' motion in the solar system. Gravity is a universal force that exists throughout the universe, acts between objects with mass, and plays a crucial role in celestial bodies' movements, including the interaction between Earth and the sun.

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Answer:

Explanation:

In this problem, we are required to solve for the total distance that the car travelled. and the displacement

A) the distance travelled by car

this can be gotten by summing all the distances the car has travelled.

i,e total distance= 60 miles+120 miles

total distance= 180 miles

B) the displacement of the car

the displacement can be gotten by  subtracting the final distance from the initial distance

final distance = 120 miles

initial distance= 60 miles

displacement= 120-60= 60 miles

Answer:

Organisms 2 and 3

Explanation:

When the pressure (100 N) and weight (40 kg) are entered into the appropriate fields, the gravity is 2 m/s².

Force and acceleration are linked by the equation F=ma. The characters "F," "m," and "a" stand for acceleration, mass, and force, respectively. Force is the ability of one object to exert a pull or force on another. Acceleration is the rate at which an object's speed changes.

Speed increase is the pace of progress of speed. Acceleration typically indicates a change in speed, but not always. Because its velocity is changing in the opposite direction, even if an object moves in a circle at the same speed, it will still accelerate.

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Answer: it would take 4 seconds

Explanation:

Answer:

The primary objective of food preservation is to prevent food spoilage until it can be consumed. Gardens often produce too much food at one time—more than can be eaten before spoilage sets in. Preserving food also offers the opportunity to have a wide variety of foods year-round. It's economic.

Explanation:

The orbital speed of the proton is 4.7 x 10⁶ m/s.

The orbital speed of the proton is calculated by applying the following equations as shown below.

Centripetal force of the proton = magnetic force of the proton

Fc = qVB

mv²/r = qvB

mv² = qvBr

v² = qvBr/m

v = qBr/m

where;

The orbital speed of the proton is calculated as follows;

v = (1.6 x 10⁻¹⁹ x 0.35 x 0.14) / (1.67 x 10⁻²⁷)

v = 4.7 x 10⁶ m/s

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Radon-222 is a naturally occurring radioactive isotope with a half-life of 4 days. The radioactive decay of radon-222 results in the emission of alpha particles, which are positively charged particles consisting of two protons and two neutrons. Alpha particles have a relatively short range and can be stopped by a piece of paper or a few centimeters of air. The decay of radon-222 can be represented by the following equation: 222Rn → 218Po + 4He. This means that the decay of one atom of radon-222 results in the formation of an atom of polonium-218 and an alpha particle.

To draw a graph showing the radioactive decay of radon-222, we can plot the number of radon-222 atoms remaining over time. The graph will be exponential in shape, meaning that the rate of decay decreases as the number of radon-222 atoms decreases. To begin, we can use the fact that the initial mass of the radon sample is 64 kg to calculate the initial number of radon-222 atoms.
The number of atoms of a radioactive isotope can be calculated using the following equation:
N = N0e-λt
where N is the number of atoms remaining, N0 is the initial number of atoms, λ is the decay constant (which is related to the half-life), and t is the time elapsed.
Using the half-life of radon-222 (4 days), we can calculate the decay constant as follows:
λ = ln(2)/t1/2
λ = ln(2)/4
λ = 0.173 day-1
We can then use this decay constant to calculate the number of radon-222 atoms remaining after a given amount of time. For example, after 4 days (one half-life), the number of atoms remaining is:
N = N0e-λt
N = 64e-0.173(4)
N = 31.6
This means that after one half-life, the number of radon-222 atoms has decreased by half. After two half-lives (8 days), the number of atoms remaining is:
N = N0e-λt
N = 64e-0.173(8)
N = 15.7
This means that after two half-lives, the number of radon-222 atoms has decreased by a factor of four.
To draw the graph, we can plot the number of radon-222 atoms remaining on the y-axis and the time elapsed on the x-axis. We can use the equation N = N0e-λt to calculate the number of atoms remaining at various times and plot these points on the graph. The resulting graph will be exponential in shape, with a steep initial slope that levels off over time.

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Given:

The mass of the sugar is m = 5 kg

The distance of the shelf from the counter is h = 0.33 m

Required: Work done to put the bag on a shelf above the counter.

Explanation:

The work done can be calculated by the formula

Here, g = 9.8 m/s^2 is the acceleration due to gravity.

On substituting the values, the work done will be

Final Answer: The work done to put the bag on a shelf above the counter is 16.17 J.

Answer:

The components of the force in the x and y-direction are -153.21 N and 128.56 N respectively.

Explanation:

Rectangular components of a vector

Given a vector \(\vec F\) as an ordered pair (f,θ), where f is the magnitude of the vector and θ is the angle it forms with the positive x-direction, the rectangular components of the vector are given by:

\(F_x=f.\cos\theta\)

\(F_y=f.\sin\theta\)

The force of f=200N forms an angle of θ=140°. The components of the force are:

\(F_x=200.\cos 140^\circ\)

Calculating:

\(F_x=-153.21~N\)

\(F_y=200.\sin 140^\circ\)

\(F_y=128.56~N\)

The components of the force in the x and y-direction are -153.21 N and 128.56 N respectively.

The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.

1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).

2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.

3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.

4. However, the given equation does not explicitly mention resistance.

5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).

6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.

7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).

8. Therefore, V = VR + VL.

9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.

10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.

The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.

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For two horses pull horizontally on ropes attached to a stump, the magnitude of F and its direction is mathematically given as

F=1711 N

dF= 135 degrees

Generally, the equation for the components of F1   is mathematically given as

For The x axis

1210 - F2x = 0

F2x = 1210

For the y axis

F2y = R

F2y = 1210

In conclusion

F = sqrt(2)*1210

F=1711 N

Fopt the direction of F2

dF= 90 + 45

dF= 135 degrees

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Answer:

Explanation:

The acceleration of an electron in an electric field is given by the equation:

a = qE/m

where a is the acceleration, q is the charge of the electron, E is the electric field, and m is the mass of the electron.

Given that the acceleration of the electron is 4.3 m/s^2, and the mass of the electron is 9.11 × 10^-31 kg, and the charge of the electron is -1.6 × 10^-19 C, we can solve for the electric field E:

E = ma/q

E = (4.3 m/s^2) × (9.11 × 10^-31 kg) / (-1.6 × 10^-19 C)

E = -2.44 × 10^4 N/C

The negative sign indicates that the direction of the electric field is opposite to the direction of the electron's motion. Therefore, the magnitude of the electric field required to accelerate an electron with an acceleration of 4.3 m/s^2 is 2.44 × 10^4 N/C and the direction is opposite to the direction of motion of the electron.

Answer:

A. Red, Green, Blue

B. None. They all hit the ground with the same speed.

C. Final Kinetic Energy = Initial Gravitational Potential Energy

Explanation:

A. This one is actually just common sense. If you think about it, the object that is being thrown downward will reach the ground first. The object thrown upwards will hit the ground the last. If you don't believe me, use just the vertical component of velocity and use acceleration = 9.8 m/s^2. Find the time it takes for an arbitrary displacement each ball will travel. You will find that the one pointed downward will reach the ground in the shortest amount of time. Just do the same math over for the rest of the balls and you can find the time it takes for each ball to hit the ground.

B. This one is actually really simple if you think about it. Using the Work-Energy theorem, using the system consisting a ball and the earth there will be no external forces doing work on the system. Since each ball is at some height "h" and the same initial speed, they will all have the same amount of energy in the beginning. If we set the ground as our reference point for gravitational potential energy, then there will be no gravitational energy as the height at that point will be 0. They all must have the same kinetic energy at the ground.

C.

Mechanical Energy Final = Mechanical Energy Initial + Net Work from non-conservative forces

Kinetic Energy Final + Gravitational Potential Energy Final = Kinetic Energy Initial + Gravitational Potential Energy Initial

I am using the symbol " ' " to indicate final speeds and heights

0.5*m*v'^2 + mgh' = 0.5*m*v^2 + mgh

0.5*m*v'^2 + 0 = 0.5*m*v^2 + mgh

(cancel out the mass)

0.5*v'^2 = 0.5*v^2 +gh

Since the "v" is the same initially for all three balls and "g" and "h" are the same for all three balls. The final speed v' must be the same for all three situations regardless of mass.

If you have any questions feel free to comment again. I'll try to clarify.

Answer:

The image seems to be behind the mirror, but nothing is really there.

Explanation:

Sample response edge 2021

Answer:

The answer is option A

Explanation:

why?

because to get the power, you need this equation. P= Work done/Time taken.

the unit of time are seconds, and the unit of work is kJ. So, the equation is=

360kJ/120s = 3kW

The useful power output of the crane is: A. 3.0 kW.

Given the following data:

To find the useful power output of the crane:

First of all, we would convert the time in minutes to seconds.

Conversion:

1 minutes = 60 seconds

2 minutes = 120 seconds.

360 kJ = 360,000 Joules.

Mathematically, the power output of a device is given by the formula;

\(Power = \frac{Energy}{Time} \\\\Power = \frac{360,000}{120}\)

Power output = 3000 Watts

In kilowatts, power output = 3.0 kW

Therefore, the useful power output of the crane is 3.0 kW.

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Answer:

20 characters

Explanation:

The bottle is squeezed, when a bottle with a reservoir is squeezed, is the fluid will come up through the bottom of the reservoir. Thus, the correct option is D.

A reservoir is an artificial lake where the water is stored. Most of the reservoirs are formed through the construction of the dams across major rivers. A reservoir can also be formed from a natural lake whose outlet has been dammed to control the water level in that.

When we squeeze an open bottle which is filled with water, the water in the bottle will spill out. When we squeeze a bottle, the material collapses where we squeeze it, however it expands in other areas, resulting in a constant volume. If the volume is constant, then we would think that the water should not spill out.

Therefore, the correct option is D.

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Answer: the value of the drain current ID is 3.56 mA

Explanation:

Given that;

IDSS = 8 mA

VP(VGS_OFF) = - 6 V.

VGS = - 2 V

value of the drain current ID = ?

Drain current ID is expressed as;

ID = IDSS [ 1 - (VGS/VP(VGS_OFF)) ]²

we substitute our value

ID = 8 [ 1 - (-2 / -6) ]²

ID = 8 [ 1 - 0.3333 ]²

ID = 8 [ 0.6667 ]²

ID = 8 [ 0.4444 ]

ID = 3.5552 ≈ 3.56 mA

Therefore the value of the drain current ID is 3.56 mA

An aerial photographic image's corners, edge-centers, or both may contain a series of marks known as fiducial marks. These traces are recorded on the original film by the camera.

Fiducial markers are tiny metal objects, usually made of gold, that are positioned inside or close to a tumor to help direct the placement of radiation beams during therapy. They are about the size of a grain of rice.

Tiny metal things are called fiducial markers (about the size of a grain of rice). They assist your healthcare professionals in aligning the radiation beams and guarantee that your radiation therapy is administered consistently.

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Fiducial marks are a set of marks that can be found in the corners, edge-centers, or both of an aerial photographic image. The camera captures these traces on the original film.

Given  the Ryerson Campus is at a scale of  1:1000

Then the photographic scale (s) = 1:3000

The focal length of camera (f) = 152mm = 0152m

The format is (k) =  230 x 230mm = 0.23m

the photographic scale (s) = F/H where H is the image height

1/3000 = 0.152 /H Then H = 456m

Assume that there is longitudinal overlap as P1 = 60% and side to side overlap as 30%. Therefore margin of ground photograph = (1-P1) x k/s

(1-0.6) x 0.23/1/3000 = 276mm

Now width of ground photograph = (1-0.3) x 0.23/1/3000 = 483m

Hence the central points are plotted within the area range in 276m x 483m magnitude.

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Answer:

V = a t      velocity after time t

t = 33.1 / 9.80 = 3.38 sec   (time ball had been falling)

S = 1/2 a t^2 = 55.9 m

So the ball had been falling  for 7 * 8 = 56 m  

The child was 7 floors from the top

Since he was on the eight floor the floors below him were

7 * 8 + 12 = 68 m     total floors below child

68 + 56 = 124 m      total height of building

Total floors in building = 7 + 7 + 1 = 15 floors

PE at top = KE at bottom

KE = m g h = .125 * 9.80 * 124 = 152 Joules

In "The Argonauts," Robinson effectively utilizes language techniques such as metaphor, repetition, and sentence structure to develop his argument to his younger self and engage young readers in the present. Through these techniques, Robinson creates a powerful and relatable narrative that resonates with his audience.

Robinson employs metaphors to convey complex ideas in a compelling and accessible manner. For instance, he compares his struggle with identity and gender to the mythical journey of the Argonauts, making it relatable and captivating for young readers. This metaphorical language enables readers to grasp the profound emotions and challenges he faced during his own personal journey.

Repetition is another technique Robinson employs to reinforce key ideas and create a rhythmic and memorable reading experience. By repeating certain phrases or concepts, he emphasizes their significance and invites readers to reflect on them. This repetition serves to engage young readers by encouraging them to contemplate their own experiences and perspectives.

Furthermore, Robinson carefully structures his sentences to create a sense of rhythm and flow, enhancing the overall readability and impact of his argument. Short, concise sentences create moments of clarity and emphasis, while longer, more descriptive sentences evoke a contemplative and introspective tone. This varied sentence structure adds depth and nuance to his narrative, captivating young readers and keeping them engaged throughout.

In conclusion, through the effective use of metaphor, repetition, and sentence structure, Robinson engages and captivates young readers, inviting them to reflect on their own identities and experiences. His language choices not only develop his argument to his younger self but also establish a connection with present-day young readers, making his work both impactful and relatable.

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We can calculate the time taken by the compass to hit the ground by using kinematic equations of motion. The motion of the compass is a free-fall motion since it is only under the influence of gravity. When the compass is dropped, it is initially at rest.

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Answer:

It's plastic.

trust me it's plastic, i've rad it somewhere.

All of them have something that's not like the others.

-- Rubber is the only one on the list that has two repeated letters.

-- Plastic is the only one on the list thagt has no repeated letters.

-- Plastic is the only one on the list that has no 'r' in its name.

-- Copper is the only one on the list that is an element, not a compound.

-- Copper is the only good electrical conductor on the list.

-- Plastic is the only one on the list with more than six letters in its name.

-- Rubber is the only one on the list with no 'p' in its name.

-- Plastic is the only one on the list that doesn't end in "-er".

Table sugar is a compound, it consists of carbon, hydrogen, and oxygen.

Hence, C is the correct answer.

The chemical state of matter consists :

Hence, table sugar is a compound because it is formed by more than 2 chemical elements, and they are chemically bonded together.

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Answer:

a. −0.12m/s

Explanation:

Given;

mass of the hockey goalie, m₁ = 65 kg

mass of the hockey puck, m₂ = 0.15 kg

velocity of the hockey puck, u₂ = 50 m/s

initial velocity of the hockey goalie, u₁ = 0

let the recoil velocity of the goalie = v

Apply Newton's third law of motion;

action and reaction are equal and opposite.

m₁v = -m₂u₂

65v = -(0.15 x 50)

65v = -7.5

v = - 7.5 / 65

v = -0.12 m/s

This shows that the goalie will move backwards with a velocity of 0.12 m/s.

Answer: 317.52

Explanation:

I'm just better