will a precipitate form when 0.050 l of 2.0 ×10-2 m naf is mixed with 0.010 l of 1.0 × 10-2 m ca(no3)2?

Answer:

1.51

⋅

10

24

Explanation:

This is a pretty straightforward example of how to sue Avogadro's number to figure out the number of molecules present in a given sample.

In your case, the sample is said to contain  

2.50

moles of water. Now, a mole is simply a very, very large collection of molecules. In order to have  

1

mole of a molecular compound you need your sample to contain  

6.022

⋅

10

23

molecules of that compound.  

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The water molecules are in a block of ice containing 0.750 mole of water. The number of water molecule is 4.52 x 10²³molecules.

Molecules are defined as a group of two or more atoms that together create the lowest recognizable unit into which a pure material can be separated while retaining its makeup and chemical qualities.

It can also be defined as a group of two or more atoms held together by attractive forces called as chemical bonds.

There are mainly three types of molecule.

1 mole of water molecules = 6.022 x 10²³ molecules

So, 0.750 mole of molecules = 6.022 x 10²³ x 0.750

                                                 = 4.52 x 10²³ molecules

Thus, the water molecules are in a block of ice containing 0.750 mole of water. The number of water molecule is 4.52 x 10²³molecules.

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There are approximately 4.45 x 10^24 atoms of iron (Fe) in a sample of 7.38 mol Fe.

To calculate the number of atoms, we use Avogadro's number (6.022 x 10^23 atoms/mol) as a conversion factor. Multiply the given amount of moles by Avogadro's number to obtain the number of atoms:

7.38 mol Fe * (6.022 x 10^23 atoms/mol) = 4.45 x 10^24 atoms Fe.

In the sample of 7.38 mol of iron, there are approximately 4.45 x 10^24 atoms of iron. This calculation is based on the concept that one mole of any substance contains Avogadro's number of particles, which is approximately 6.022 x 10^23 particles.

Therefore, when we multiply the given amount of moles (7.38 mol) by Avogadro's number, we can determine the number of atoms in the sample.

It is important to note that Avogadro's number represents the number of particles (atoms, molecules, ions, etc.) in one mole of a substance.

This constant allows us to relate the amount of substance in moles to the number of individual particles. In the case of iron (Fe), the sample of 7.38 mol contains approximately 4.45 x 10^24 atoms.

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Explanation:

350 g  *  25 C  * .39 J / (g C) = ~ 3400 J

During electrolysis, the product that we get at the cathode is the metal, for Ag, Ag is deposited at the cathode.

Changing a substance's chemical composition by passing an electric current through it is called electrolysis. When a substance loses or gains an electron, a chemical change has occurred (oxidation or reduction).

The procedure is performed in an electrolytic cell, a device made up of positive and negative electrodes that are held apart and submerged in a solution containing ions with opposite charges.

The substance that needs to be transformed can either be dissolved in the solution, form the electrode, or form the electrode itself.

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The molar concentration of a 12% sodium chloride solution is approximately 2.05 M.

To determine the molar concentration of a 12% sodium chloride solution, we need to convert the given percentage concentration into molarity.

First, we need to understand that the percentage concentration refers to the mass of the solute (sodium chloride) relative to the total mass of the solution.

In this case, a 12% sodium chloride solution means that there are 12 grams of sodium chloride in 100 grams of the solution.

To convert this into molar concentration, we need to consider the molar mass of sodium chloride, which is 58.5 g/mol.

We can start by calculating the number of moles of sodium chloride in 12 grams:

Moles of sodium chloride = mass of sodium chloride / molar mass of sodium chloride

Moles of sodium chloride = 12 g / 58.5 g/mol = 0.205 moles

Next, we calculate the volume of the solution in liters using the density of the solution. Since the density is not provided, we assume a density of 1 g/mL for simplicity:

Volume of solution = mass of solution / density

Volume of solution = 100 g / 1 g/mL = 100 mL = 0.1 L

Finally, we calculate the molar concentration (Molarity) by dividing the number of moles by the volume in liters:

Molar concentration = moles of solute / volume of solution

Molar concentration = 0.205 moles / 0.1 L = 2.05 M

Therefore, the molar concentration of a 12% sodium chloride solution is approximately 2.05 M.


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\((115.00)(0.25)+(117.00)(0.75)=\boxed{116.50 \text{ u}}\)

the number of hydroxyl groups increases is caused by a greater degree of hydrogen bonding between the molecules.

I hope this helps

Answer:

gas and liquid

Explanation:

Acid rain results when humans put excess amounts of sulfur dioxide (SO2) and nitrogen oxides (NOx) into the atmosphere.

These pollutants are released primarily from industrial processes and the burning of fossil fuels, which then react with water, oxygen, and other chemicals to form sulfuric acid and nitric acid. These acids then fall to the ground in the form of precipitation, known as acid rain.

Any type of precipitation that contains acidic elements, such as sulfuric or nitric acid, that falls to the ground from the atmosphere in wet or dry forms is referred to as acid rain, also known as acid deposition. This can apply to rain, snow, fog, hail, and even corrosive dust.

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Answer:

A material can become negatively charged by

A. gaining electrons

Answer:

D. Volume

Explanation:

Properties mentioned in the question;

colour = gray

Nonmetallic

Density = 3.8 g/mL

Volume = 48.3 mL

Of the mentioned, which is extensive ?

Extensive properties are those properties that are proportional to the amount of substance present.

The correct option is D. Volume. The other properties do not change with increasing or decreasing amount of the mineral

The amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.

To calculate the molarity of Kool Aid desired, we need to determine the number of moles of Kool Aid powder and sugar in the package. Since the molecular formula for sugar is C12H22O11, we can calculate its molar mass as follows:

Molar mass of C12H22O11 = (12 * 12.01) + (22 * 1.01) + (11 * 16.00)

= 144.12 + 22.22 + 176.00

= 342.34 g/mol

Given that the package contains 4.25 grams of Kool Aid powder, we can calculate the number of moles of Kool Aid powder using its molar mass:

Number of moles of Kool Aid powder = Mass / Molar mass

= 4.25 g / 342.34 g/mol

≈ 0.0124 mol

Similarly, for the sugar, which has a molar mass of 342.34 g/mol, we can calculate the number of moles of sugar using its mass:

Number of moles of sugar = Mass / Molar mass

= 192.00 g / 342.34 g/mol

≈ 0.5612 mol

Now, to calculate the molarity of the desired Kool Aid solution, we need to determine the volume of water. Given that 1.06 quarts is equal to 1 liter, and we have 2.00 quarts of water, we can convert it to liters as follows:

Volume of water = 2.00 quarts * (1.06 liters / 1 quart)

= 2.12 liters

To find the molarity, we use the formula:

Molarity (M) = Number of moles / Volume (in liters)

Molarity of Kool Aid desired = (0.0124 mol + 0.5612 mol) / 2.12 L

≈ 0.286 M

To prepare 65 mL of the desired molarity, we can use dilution calculations. We need to determine the volume of concentrated solution and the volume of water needed.

Let's assume the concentration of the concentrated Kool Aid solution is C M. Using the dilution formula:

(C1)(V1) = (C2)(V2)where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Given that C1 = C M and V1 = V mL, and we want to prepare a final volume of 65 mL (V2 = 65 mL) with a final concentration of 0.286 M (C2 = 0.286 M), we can rearrange the formula to solve for the volume of the concentrated solution:

(C M)(V mL) = (0.286 M)(65 mL)

V mL = (0.286 M)(65 mL) / C M

So, the amount of concentrated solution needed is (0.286 M)(65 mL) / C M, and the amount of water needed is 65 mL minus the volume of the concentrated solution.

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Answer:

5.77x10^-7 m or 577 nm (nanometers)

Explanation:

The wavelength, λ, and frequency, ν, of light are described by the equation:

c = λν

where c is the speed of light.  

c = 3.0x10^8 m/s

v = 5.2x10^14

λ = c/v

λ = (3.0x10^8 m/s)/(5.2x10^14) = 5.77x10^-7 m

since 1 m = 10^9nm, we can express this as 577 nm (nanometers)

577 nm.  This is in the yellow light span of wavelengths.

Answer:

6.02 × 1,023

Explanation:

One mole of oxygen gas, which has the formula O2, has a mass of 32 g and contains 6.02 X 1,023 molecules of oxygen but 12.04 X 1,023 (2 X 6.02 X 1,023) atoms, because each molecule of oxygen contains two oxygen atoms.

Answer:

6FCRXCTV

Explanation:

Answer:

b

Explanation:

a p e x

Answer:

boiling point is an intensive property because it stays the same no matter the amount of an element or molecule

Explanation:

We can't you use the equation Q = mc∆T to calculate how much thermal energy is needed to melt or boil a substance because this equation is to calculate for heat energy transferred between two objects where m is the mass of each object and c is the specific heat capacity

Thermal energy refers to the energy contained within a system that is responsible for its temperature and for thermal energy for melt any substance is latent heat and during boiling of any substances the heat energy supplied is used in increasing the energy of the water molecule which changes its state from liquid to gaseous

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Answer:

ternary

Explanation:

A ternary ionic compound is a polyatomic ionic compound composed of three or more different elements.

An ionic compound is a chemical complex made up of ions that are held together through electrostatic forces. The molecule is essentially neutral, however, it contains positively charged cations as well as negatively charged anions.

An ionic compound with three components is known as a ternary ionic compound. One type of cation including one type of anion are still present in a typical ternary ionic combination. Polyatomic ions are cations, anion, or both.

Therefore, a ternary ionic compound is a polyatomic ionic compound composed of three or more different elements.

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The equilibrium constant (Keq) for the reaction 2SO2(g) + O2(g) 2SO3(g) is correctly expressed as Keq = [SO3]2 / ([SO2]2 [O2]).

The ratio of the mathematical product of the concentrations of the products of a reaction to the mathematical product of the concentrations of the reactants of the reaction is known as the equilibrium constant (Keq). The balanced chemical equation causes each concentration to grow to the power of its corresponding coefficient.

Keq's "K" stands for "Constant," thus. At a specific temperature, the "eq" indicates that the reaction is at equilibrium. No matter what we would try to do with the concentrations, the value of this ratio remains at 0.0183.

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Using significant figures and rounding up, the resulting mass is 80.5 g.

When using addition or subtraction, the total number of significant figures is relevant. Instead, the last significant figure of every number is considered.

In 30.05, the last significant figure is 5, and it is in the hundredths. In 50.0, the last significant figure is 0, and it is in the tenths. Finally, in 0.4006, the last significant figure is 6, and it is in the ten thousandths. Of the three, the 0 from 50.0 is in the "highest" position, and so the last significant figure of the results should also be in the tenths.

If we add the numbers up, we get:

30.05 g + 50.0 g + 0.4006 = 80.4506 g

Because the last significant figure should be in the tenths, we are going to round up 4 to 5, because trailing numbers are greater than 0, so the final mass will be 80.5 g.

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By using Graham's law we can calculate that it will take the methane (CH₄) sample 4.2 s to effuse under the same conditions.

Graham's law connects the rates of effusion (RoE) of two gases and their molar masses (M):

\(\frac{RoE(A)}{RoE(B)} = \sqrt{\frac{M(B)}{M(A)} }\)

We can calculate the RoE for N₂ by using the given number of moles (n = 2.0 mol) and time (t = 5.5 s) needed for it to effuse:

RoE(N₂) = n/t

RoE(N₂) = 2.0 mmol / 5.5 s

RoE(N₂) = 0.36 mmol/s

Now, we can use the molar masses of nitrogen (M = 28 g/mol) and methane (M = 16 g/mol) to calculate the RoE(CH₄):

\(\frac{RoE(N_{2} )}{RoE(CH_{4} )} = \sqrt{\frac{M(CH_{4})}{M(N_{2} )} }\)

\(RoE(CH_{4} ) = \frac{RoE(N_{2} )}{\sqrt{\frac{M(CH_{4} )}{M(N_{2} )} } }\)

\(RoE(CH_{4} ) = \frac{0.36 mmol/s}{\sqrt{\frac{16 g/mol}{28 g/mol} } }\)

RoE(CH₄) = 0.48 mmol/s

Now we can use this to calculate the time 2.0 mmol of methane will require:

t = n(CH₄) / RoE(CH₄)

t = 2.0 mmol / 0.48 mmol/s

t = 4.2 s

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Answer:

b.troposphere

Explanation:

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In the given electrolytic cell setup having molten zinc iodide as the electrolyte, reduction of zinc ions to gray coloured zinc occurs at the cathode, whereas iodide ions get oxidized to reddish-brown iodine at the anode.

An electrolytic cell is a type of electrochemical cell that uses an external source of electrical energy to power a chemical process that would not occur otherwise. This contrasts with a galvanic cell, which serves as a power source and the cornerstone of a battery.

Any apparatus in which electrical energy is changed into chemical energy or vice versa is an electrolytic cell. Such a cell normally consists of two electrodes, which can be metallic or electronic conductors, kept apart from one another and in contact with an electrolyte, which is commonly an ionic substance that has been dissolved or fused.

In the given setup, the molten zinc iodide is the electrolyte, and the half reactions occurring at the two electrodes of the electrolytic cell are:

Half reaction at the cathode:

\(Zn^{2+} (l) + 2e^- \rightarrow Zn (s)\)

Half reaction at the anode:

\(2I^- (l) \rightarrow I_2 (s) + 2e^-\)

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Answer:

Groups: The vertical column of the periodic table that signifies the number of valence electrons in an element.

Period: The horizontal rows in the periodic table that signify the number of electron shells in an element.

Explanation:

Answer:Groups: The vertical column of the periodic table that signifies the number of valence electrons in an element. Periods: The horizontal rows in the periodic table that signify the number of electron shells in an element.

Explanation:

The table has seven rows and 18 columns. Each row represents one period; the period number of an element indicates how many of its energy levels house electrons.The columns of the table represent groups, or families, of elements.

1) Which element is oxidized

Oxidation numbers

I2: 0

ClO3-: for Cl +5 and for O is -2

IO3-: for I is +5 and for O -2

Cl-: -1.

According to the oxidation number

a. Iodine (I) has been oxidized. It changed from 0 to +5.

b. Chlorine has been reduced. It changed from +5 to -1

2) reducing agent and oxidizing agent

c. A reducing agent donates electrons. In the reaction, Iodine is the reducing agent.

d. An oxidizing agent accepts electrons. In the reaction, Chlñorine is the oxidizing agent.

3) Balancing the chemical equation

Step 1: break the reaction into two half-reactions.

Oxidation half-reaction

Reduction half-reaction

Step 2: balance all elements EXCEPT for hydrogen and oxygen

Oxidation half-reaction

Reduction half-reaction

Step 3: Balance OXYGEN. We do so by adding water molecules to the half-reactions as needed.

Oxidation half-reaction

Reduction half-reaction

Step 4: Balance HYDROGEN. We do so by adding protons (H+) to the half-reactions as needed.

Oxidation half-reaction

Reduction half-reaction

Step 5: Balance CHARGES. We do so by adding electrons

Oxidation half-reaction

Reduction half-reaction

Step 6: Multiply each half-reaction in such a way we can cancel the electrons.

Oxidation half-reaction

New oxidation half-reaction

Reduction half-reaction

New reduction half-reaction

Step 7: combine the half-reactions. We have 30e in the reactants and 30e in the products. We can cancel them and combine the remaining species.

New oxidation half-reaction

New reduction half-reaction

Overall reaction

Step 8: Balance the reaction by reducing the number of water molecules and protons.

Overall reaction

e. Balance the reaction

.