Will give brainliest

Will Give Brainliest

Answers

Answer 1

Answer: 45 Degrees

Step-by-step explanation:


Related Questions

Which expression is equivalent to the given expression?
(10c6d-5)(2c-5d4

Answers

Answer:

if you simplify the expression you will get

\(20c^{7}d - 20 {c}^{6} {d}^{2} \)

Answer:

20c/d

Step-by-step explanation:

I got it right. Hope this helps.

Some quantity of prepared pap is contained in a clay dish. If by weight of pap and container, water is two ninths, cornflour is three fifteenth, sugar is one eighteenth and the rest is the dish. By what fraction of the dish and pap is the dish alone heavier than its content pap

Answers

The dish alone is heavier than its content of pap by a fraction of 1/18. To determine the fraction of the dish that is heavier than its content of pap.

We need to find the weight of the dish alone and compare it to the weight of the pap and dish combined.

Given that the weight of the pap and container is two ninths, the weight of the cornflour is three fifteenths, the weight of the sugar is one eighteenth, and the rest is the weight of the dish.

To find the weight of the dish, we need to subtract the weights of the pap, cornflour, and sugar from the total weight of the pap and container.

Let's assume the total weight of the pap and container is represented by the fraction 1.

Weight of the pap and container: 1
Weight of the cornflour: 3/15 = 1/5 (since 3/15 simplifies to 1/5)
Weight of the sugar: 1/18
Weight of the dish: 1 - (1/5 + 1/18) = (18 - 3 - 10)/90

= 5/90

= 1/18

Therefore, the weight of the dish alone is 1/18 of the total weight of the pap and container.

To find the fraction of the dish and pap that is heavier than the pap alone, we need to compare the weight of the dish to the weight of the pap.

Weight of the dish: 1/18
Weight of the pap:

1 - 1/18 = 17/18

The fraction of the dish and pap that is heavier than the pap alone is:

(Weight of the dish)/(Weight of the dish + Weight of the pap)

= (1/18)/(1/18 + 17/18)

= 1/18 divided by 18/18

= 1/18 multiplied by 18/18

= 1/18

Therefore, the dish alone is heavier than its content of pap by a fraction of 1/18.

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what is the distance between point A located at "-412" and point B located at "-217"

Answers

412-217

195 units

Just subtract them and that would be the distance I’m pretty sure

Name three adjectives to describe one of your recent math tests

Answers

Answer:

hard, stressful, sad

Step-by-step explanation:

Answer:

Obnoxious, boring, and irritated.

Janice ha a collection of 36 hairpin. 1/6 of them are red and the ret are black. How many black hair pin doe Janice have?

Answers

The number of black hair pin Janice have is 30.

Given:

Janice ha a collection of 36 hairpin.

1/6 of them are red.

The rest of the pins are black.

we are asked to find the number of black pin Janice have = ?

first calculate the number of red pins:

⇒ 1/6 of 36

⇒ 1/6 × 36

⇒ 6

Janice have 6 red pins, and the remaining as black pins.

⇒ subtract the red pins from the total.

⇒ black pins = 36-6

black pins  = 30

Hence the number of black pins Janice have is 30.

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the given set is a basis for a subspace w. use the​ gram-schmidt process to produce an orthogonal basis for w.

Answers

y₁ =  [1  -4  0  1] and y₂ = [5  1  -6  -1] is the orthogonal basis for w using Gram-Schmidt process.

Given,

The set;

x₁ = [1  -4  0  1]

x₂ = [7  -7  -6  1]

We have to produce the orthogonal basis for w using the Gram-Schmidt process;

Here,

y₁ = x₁ =  [1  -4  0  1]

Now,

Solve for y₂

y₂ = x₂ - [x₂y₁ / y₁y₁] y₁

That is,

y₂ = [7  -7  -6  1] - ( [7  -7  -6  1] [1  -4  0  1] / [1  -4  0  1] [1  -4  0  1] ) × [1  -4  0  1]

y₂ =  [7  -7  -6  1] - (7 + 28 - 0 + 1) / (1 + 16 + 0 + 1) × [1  -4  0  1]

y₂ = [7  -7  -6  1]  - 36/18 × [1  -4  0  1]

y₂ =  [7  -7  -6  1] - 2  × [1  -4  0  1]

y₂ =  [7  -7  -6  1] - [2  8  0  2]

y₂ = [5  1  -6  -1]

That is,

The orthogonal basis for w using Gram-Schmidt process is,

y₁ =  [1  -4  0  1] and y₂ = [5  1  -6  -1]

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Find the circumference of a circle with a radius of 9 meters. Use 3.14 for π. Round to the nearest hundredth if necessary.

Answers

Answer:56.52

Step-by-step explanation:

circumference = π*d

d=2r

d=2*9

d=18

3.14*18=56.52

Answer:

C =2ΠR

=2 x (3.14)( 9)

=56.52meters

10 x 33
what does this mean somoen help

Answers

Answer:

10 × 33 (multiply)

=330 is the answer

Answer:

It means 10 times 33 (330)

Hope it helps!

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\(GraceRosalia\)

The proportion of a normal distribution located between z = .50 and z = -.50 is ____.

Answers

The proportion of a normal distribution located between z = .50 and z = -.50 will be 38.2%.

We have,

A normal distribution located between z = 0.50 and z = -0.50,

So,

Now,

From the Z-score table,

We get,

The Probability corresponding to the Z score of -0.50,

i.e.

P(-0.50 < X < 0) = 0.191,

And,

The Probability corresponding to the Z score of -0.50,

i.e.

P(0 < X < 0.50) = 0.191,

Now,

The proportion of a normal distribution,

i.e.

P(Z₁ < X < Z₂) = P(Z₁ < X < 0) + P(0 < X < Z₂)

Now,

Putting values,

i.e.

P(-0.50 < X < 0.50) = P(-0.50 < X < 0) + P(0 < X < 0.50)

Now,

Again putting values,

We get,

P(-0.50 < X < 0.50) = 0.191 + 0.191

On solving we get,

P(-0.50 < X < 0.50) = 0.382

So,

We can write as,

P(-0.50 < X < 0.50) = 38.2%

So,

The proportion of a normal distribution is 38.2%.

Hence we can say that the proportion of a normal distribution located between z = .50 and z = -.50 will be 38.2%.

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Given: Circle WW (-4, 6)Radius = 10 unitsWhich point lies on circle W?(0,4)(2, 10)(4,0)O , (6, 16)

Given: Circle WW (-4, 6)Radius = 10 unitsWhich point lies on circle W?(0,4)(2, 10)(4,0)O , (6, 16)

Answers

SOLUTION

A point will lies on the circle if the distance between the point and the center of the circle gives the radius or is equal to the radius.

Given the center of the circle

\((-4,6)\)

Let find the distance between the center and the point (4,0)

The formula for the distance between two points is given as

\(\text{Distance}=\sqrt[]{(x_2-x_1)^2_{}+(y_2-y_1)^2_{}}\)

Given the point (-4,6) and (4,0)

\(x_1=-4,x_2=4,y_1=_{}6,y_2=0\)

Then substitute the value above into the formula, we have

\(\begin{gathered} \text{Distance}=\sqrt[]{(4-(-4)^2+(0-6)^2} \\ \text{Distance =}\sqrt[]{8^2_{}+(-6)^2} \\ \text{Distance}=\sqrt[]{64+36} \\ \text{Distance}=\sqrt[]{100} \\ \text{Distance}=10\text{units} \end{gathered}\)

Since the distance is equal to the radius of the circle,

Hence the point (4,0) lies on the circle

Give the explicit formula for the sequence.

-3, -9, -27, -81...

Give the explicit formula for the sequence.-3, -9, -27, -81...

Answers

Answer:     9 is the next number of this series. Similarly, apply thus rule. 9×2=18 and 18+9=27. Next is 27.

Step-by-step explanation:

What is the sum of the following equation? two tenths plus forty one-hundredths equals blank 50 points

forty-three hundredths

sixty one-hundredths

thirty-nine hundredths

eighty-two hundredths links=report

What is the sum of the following equation? two tenths plus forty one-hundredths equals blank 50 points

Answers

Answer: Expanded Notation to Numeric Form with Decim. Convert each problem to numeric notation. Ex) 4x 10+9+(2*70) +(6x/100). Answers. 49.26. 1) 7 * 100+ 2 ...

Step-by-step explanation:

I need help !! Omg omg omg omg help help help help

I need help !! Omg omg omg omg help help help help

Answers

Answer:

6

Step-by-step explanation:

Answer:

The answer is 6

Step-by-step explanation:

example 2 major premise: no dogmatists are scholars who encourage free thinking. minor premise: some theologians are scholars who encourage free thinking. conclusion: some theologians are not dogmatists. the major premise in example 2 is an proposition. the minor premise in example 2 is an proposition. the conclusion in example 2 is an proposition. therefore, the mood of the categorical syllogism in example 2 is .

Answers

The mood of the categorical syllogism in example 2 is AIO.

In your example, we have the following premises and conclusion:

1. Major Premise: No dogmatists are scholars who encourage free thinking.
2. Minor Premise: Some theologians are scholars who encourage free thinking.
3. Conclusion: Some theologians are not dogmatists.

The major premise in example 2 is an A proposition (All S are not P). The minor premise in example 2 is an I proposition (Some S are P). The conclusion in example 2 is an O proposition (Some S are not P).

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find the lateral area of the prism​

find the lateral area of the prism

Answers

Answer:

We know that the lateral area of any prism is the sum of the areas of its side faces. Thus, the lateral area of a triangular prism is the sum of the side faces, that is the three rectangular faces. The formula to find the lateral area of a triangular prism is, (a + b + c) h or Ph.

so

20×6= 120 sq in

Answer:

120 sq in.

Step-by-step explanation:

LA = ah

LA = 20 × 6

A = 120

Solve 2x + 32 + x = 17.

x = 5
x = 0.2
x = −0.2
x = −5
Please and thank you.

Answers

2x+32+x = 17

Combine 2x and X to get 3x.

3x+32 = 17

Subtract 32 on both sides.

3x = 17−32

Remains 32 of 17 to obtain −15.

3x = −15

Divide both sides by 3.

x = -15/3

Divide −15 by 3 to get −5.

x = −5

The last option is correct.

The value of x after solving the given equation 2x + 32 + x = 17, is x = -5, which is the last option.

Given an equation:

2x + 32 + x = 17

It is required to find the value of x after solving or simplifying the equation.

In order to get the value of x, the equation has to be solved in such a way that the terms with the variable have to be placed on one side and the constant terms on the other side.

Consider:

2x + 32 + x = 17

Add x and 2x since they are like terms in variables.

3x + 32 = 17

Subtract 32 from both sides of the equation.

3x = 17 - 32

3x = -15

Divide both sides of the equation by 3.

x = -5

Hence, the value of x is -5.

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If a ball is thrown into the air with a velocity of 40 ft/s, its height in feet after t seconds is given by y=40t−16t2.a) Find the average velocity for the time period beginning when t=2 and lasting(i) 0.5 seconds(ii) 0.1 second(iii) 0.05 seconds(iv) 0.01 secondb) Find the instantaneous velocity when t=2.

Answers

The average velocities for the given time periods has been calculated and the instantaneous velocity when t = 2 is -24 ft/s.

To find the average velocity for the given time periods, we need to calculate the change in position divided by the change in time. The formula for average velocity is:

Average Velocity = (Δy) / (Δt)

For the time period of 0.5 seconds:

Substituting t = 2 and t = 2.5 into the equation \(y = 40t - 16t^{2}\), we have:

\(y1 = 40(2) - 16(2^{2}) = 80 - 64 = 16 ft\)

\(y2 = 40(2.5) - 16(2.5^2) = 100 - 100 = 0 ft\)

Δy = y2 - y1 = 0 - 16 = -16 ft

Δt = 0.5 seconds

Average Velocity = (Δy) / (Δt) = (-16 ft) / (0.5 s) = -32 ft/s

For the time period of 0.1 seconds:

Substituting t = 2 and t = 2.1, we have:

\(y1 = 40(2) - 16(2^{2}) = 80 - 64 = 16 ft\\ y2 = 40(2.1) - 16(2.1^{2}) = 84 - 72.24 = 11.76 ft\)

Δy = y2 - y1 = 11.76 - 16 = -4.24 ft

Δt = 0.1 seconds

Average Velocity = (Δy) / (Δt) = (-4.24 ft) / (0.1 s) = -42.4 ft/s

For the time period of 0.05 seconds:

Substituting t = 2 and t = 2.05, we have:

\(y1 = 40(2) - 16(2^{2}) = 80 - 64 = 16 ft\\ y2 = 40(2.05) - 16(2.05^{2}) = 81 - 68.56 = 12.44 ft\)

Δy = y2 - y1 = 12.44 - 16 = -3.56 ft

Δt = 0.05 seconds

Average Velocity = (Δy) / (Δt) = (-3.56 ft) / (0.05 s) = -71.2 ft/s

For the time period of 0.01 seconds:

Substituting t = 2 and t = 2.01, we have:

\(y1 = 40(2) - 16(2^2) = 80 - 64 = 16 ft\\ y2 = 40(2.01) - 16(2.01^2) = 80.4 - 64.3216 = 16.0784 ft\)

Δy = y2 - y1 = 16.0784 - 16 = 0.0784 ft

Δt = 0.01 seconds

Average Velocity = (Δy) / (Δt) = (0.0784 ft) / (0.01 s) = 7.84 ft/s

To find the instantaneous velocity when t = 2, we need to calculate the derivative of the position function y(t) with respect to t.

Taking the derivative of \(y = 40t - 16t^{2}\) gives us the velocity function v(t):

\($v(t) = \frac{{d}}{{dt}} (40t - 16t^2) = 40 - 32t$\)

Substituting t = 2 into v(t), we have:

v(2) = 40 - 32(2) = 40 - 64 = -24 ft/s

Therefore, the instantaneous velocity when t = 2 is -24 ft/s.

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What is the range of the function in the graph below(photo imported)

Y is less than or equal to -2

Y is less than or equal to 0

Y is less than or equal to -1

all real numbers

What is the range of the function in the graph below(photo imported)Y is less than or equal to -2Y is

Answers

Answer: y is less than or equal to -1

How?

The graphs highest value it will ever reach, range wise, is -1. Therefore it isnt 0, or all real numbers.

The reason why it is -1 and not -2 is because the curve hits -1. Sure, -2 is included in the range, but y is less than or equal to -1 INCLUDES -2

:)

This diagram is a straightedge and compass construction of the bisector of angle BAC. Only angle BAC is given. Explain the steps of the construction in order. Include a step for each new circle, line, and point.

Answers

The steps are:

Using any radius and point A as the center, Draw an internal arc to connect lines BA and AC at points E and F, respectively. Draw an arc with point E as the center and the same or a different radius. Draw another arc with the same radius and point F as the center, intersecting the first arc at point G. From A to G, Draw a straight line. An angle bisector of BAC looks like this.

This is further explained below.

What is a compass construction?

Generally, Construction using a straightedge and a set of compasses sometimes referred to as ruler-and-compass construction or classical construction is a method for creating lengths, angles, and other geometrical figures.

In conclusion,

Using any radius and point A as the center, Draw an internal arc to connect lines BA and AC at points E and F, respectively. Draw an arc with point E as the center and the same or a different radius. Draw another arc with the same radius and point F as the center, intersecting the first arc at point G. From A to G.Draw a straight line. An angle bisector of BAC looks like this.

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A circle has a radius 12 mm. What is its area? use 3.14 to show your work.

Answers

A circle has a radius 12 mm. What is its area? use 3.14 to show your work
Ans:43.96 mm

Find the coordinates of point P along the directed line segment AB so that AP to PB is the given ratio. A(4, 5) , B (12, 9) ; 3 to 1
The coordinates of P are…?

Find the coordinates of point P along the directed line segment AB so that AP to PB is the given ratio.

Answers

For the line segment AB with coordinates A( 4,5) and B(12, 9) divided by point P in the ratio AP : PB = 3 : 1 then coordinates of P are ( 10,8).

As given in the question,

Given:

Line segment AB with coordinates A( 4,5) and B(12, 9)

Line segment AB divided by point P in the ratio AP : PB = 3: 1

Let (x ,y) be the coordinates of point P .

Coordinates of A(4,5) = ( x₁, y₁)

B(12,9) = (x₂ , y₂)

Ratio m : n = 3 : 1

Coordinates of point P is given by:

x = (mx₂ + nx₁)/ ( m+ n)

  = [3(12) + 1(4)] / (3+1)

  = ( 36 +4)/ 4

  = 40 /4

  = 10

x = (my₂ + n y₁)/ ( m+ n)

  = [3(9) + 1(5)] / (3+1)

  = ( 27 +5)/ 4

  = 32/4

  = 8

P(x ,y) = P(10, 8)

Therefore, For the line segment AB with coordinates A( 4,5) and B(12, 9) divided by point P in the ratio AP : PB = 3 : 1 then coordinates of P are ( 10,8).

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An ant can travel at a constant speed of 980 inches every 5 minutes.
1. How far does the ant travel in 1 minute?
2. At this rate ,how far can the ant travel in 7 minutes?

Answers

1. 196 a minute
2.1,372 in 7 mi s

Answer:

196 per minute, 1,372 per 7 min

Step-by-step explanation:

980/5=196

196*7=1,372

Use the quadratic formula to find the solution to the quadratic equation given
below.
x2-3x+
3x + = 0

Use the quadratic formula to find the solution to the quadratic equation givenbelow.x2-3x+3x + = 0

Answers

Answer:

Is E

explanation:

The box plots display data collected when two teachers asked their classes how many pencils they lose in a school year.

A box plot uses a number line from 5 to 47 with tick marks every one unit. The box extends from 8 to 14 on the number line. A line in the box is at 11. The lines outside the box end at 7 and 45. The graph is titled Mr. Johnson's Class, and the line is labeled Number Of Pencils.

A box plot uses a number line from 0 to 51 with tick marks every one unit. The box extends from 12 to 21 on the number line. A line in the box is at 14.5. The lines outside the box end at 0 and 50. The graph is titled Mr. Simpson's Class, and the line is labeled Number Of Pencils.

Which class lost the most pencils overall based on the data displayed?

Mr. Simpson's class; it has a larger median value 14.5 pencils
Mr. Johnson's class; it has a larger median of 11 pencils
Mr. Simpson's class; it has a narrow spread in the data
Mr. Johnson's class; it has a wide spread in the data

Answers

The class that lost the most pencils overall based on the data displayed is D. Mr. Johnson's class; it has a wide spread in the data

How to explain the information

The answer is Mr. Johnson's class. The median is the middle value in a set of data. In Mr. Johnson's class, the median is 11 pencils. This means that half of the students in his class lost 11 or fewer pencils, and half of the students lost 11 or more pencils.

In Mr. Simpson's class, the median is 14.5 pencils. This means that half of the students in his class lost 14.5 or fewer pencils, and half of the students lost 14.5 or more pencils.

Since the median for Mr. Johnson's class is lower than the median for Mr. Simpson's class, we can conclude that Mr. Johnson's class lost more pencils overall.

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On your boat, the base of the staysail is 10. 5 feet and the height is 30 feet. Find the area of the staysail

Answers

If the staysail is 10.5 feet and height is 30 feet then the area of the staysail is 157.5 feet²

To find the area of the staysail, we can use the formula for the area of a triangle:

Area of triangle = 1/2 x base x height

In this case, the base of the staysail is given as 10.5 feet and the height is given as 30 feet.

Substituting these values into the formula, we get:

Area of staysail = 1/2 x 10.5 feet x 30 feet

Simplifying the expression, we get:

Area of staysail = 0.5 x 10.5 feet x 30 feet

Area of staysail = 157.5 square feet

Therefore, the area of the staysail is 157.5 square feet. This means that if the staysail were to be laid flat, it would cover an area of 157.5 square feet.

                                     

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which of the following would tend to decrease the width of a confidence interval? i. increasing the sample size ii. using a higher confidence level iii. using a lower confidence level
A. I only
B. II only
C. III only
D. I and II only
E. I and III only

Answers

Both increasing the sample size (i) and using a lower confidence level (iii) would tend to decrease the width of a confidence interval. The answer is: E.

Increasing the sample size provides more data points, which leads to a more precise estimate of the population parameter. With a larger sample size, the variability within the sample is reduced, resulting in a narrower confidence interval.

Using a lower confidence level means being less confident in the estimation and allowing for a greater margin of error. A lower confidence level requires a smaller interval width to accommodate the increased uncertainty, resulting in a narrower confidence interval.

On the other hand, using a higher confidence level (ii) would tend to increase the width of a confidence interval. A higher confidence level indicates a greater degree of confidence in the estimation, requiring a wider interval to capture the range of possible values for the population parameter.

Hence, the correct option is: E. I and III only.

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For the following system a) What is the value of x? b ) What is the value of y ?

For the following system a) What is the value of x? b ) What is the value of y ?

Answers

Answer:

x = 12

y = -23

Step-by-step explanation:

to solve for this i think we have to do:

   y = -3x + 13

   -

   y = -2x + 1

-----------------------

   0 = -x + 12

-x = -12

x = 12

then i think.... i think you have to substitute to one of the equations

y = -3(12) + 13

y = -36 + 13

y = -23

then to check we substitute  to the second equation

-23 = -2(12) + 1 ?

-23 = -24 + 1?

-23 = -23

adult great basin rattlesnakes have a mean length of 40 inches and a standard deviation of 7.2 inches; the length of adult southern pacific rattlesnakes is also 40 inches on average, but with a standard deviation of 10.8 inches. both species have lengths that follow a normal distribution. you randomly select one great basin rattlesnake and one southern pacific rattlesnake. which is more likely be longer than 43.6 inches?

Answers

A Southern Pacific rattlesnake is more likely to be longer than 43.6 inches.

To calculate the probability of a rattlesnake having a length greater than 43.6 inches, we need to find the standard score (z-score) of 43.6 inches for each species and then use a standard normal table to find the corresponding probability.

The formula for the standard score is:

\($z = \frac{x - \mu}{\sigma}$\) where,

x is the value (43.6 inches)\($\mu$\) is the mean length of the species\($\sigma$\) is the standard deviation of the species.

For Great Basin rattlesnakes:

\($\mu\) = 40 inches

\($\sigma\) = 7.2 inches

So,

\($z = \frac{43.6 - 40}{7.2} = 0.5$\)

Using a standard normal table, we find that the probability of a Great Basin rattlesnake having a length greater than 43.6 inches is approximately 0.306.

For Southern Pacific rattlesnakes:

\($\mu\) = 40 inches

\($\sigma\) = 10.8 inches

So,

\($z = \frac{43.6 - 40}{10.8} = 0.333$\)

Using a standard normal table, we find that the probability of a Southern Pacific rattlesnake having a length greater than 43.6 inches is approximately 0.379.

So,  a Southern Pacific rattlesnake is more likely to be longer than 43.6 inches.

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A regular heptagon has a side of approximately 7.0 cm and an apothem of approximately 7.3 cm.
Find the area of the heptagon.
7.0 cm
7.3 cm
cm

A regular heptagon has a side of approximately 7.0 cm and an apothem of approximately 7.3 cm.Find the

Answers

Answer:

The formula for the area of a regular heptagon is:

A = (7/2) * s * a

where:

s = length of one side

a = length of the apothem

Plugging in the given values, we get:

A = (7/2) * 7.0 cm * 7.3 cm

A ≈ 178.715 cm²

Therefore, the area of the given heptagon is approximately 178.715 cm².

Prove the following identity. 1+ secx sin x tan x = sec² x

Answers

We are given the identity 1 + sec x sin x tan x = sec² x. Now, let us try to simplify the left-hand side of the identity using the fundamental trigonometric identity which is the Pythagorean identity.This identity states that sec² x = 1 + tan² x, so we will try to write tan x in terms of sec x and sin x since we already have sin x and sec x in the left-hand side of the identity.So, tan x = sin x/cos x. Using the definition of sec x as the reciprocal of cos x, we can simplify tan x to get:

tan x = sin x/cos x = sin x/1/cos x = sin x sec x

Substituting this into our original expression, we get:

1 + sec x sin x tan x = 1 + sec x sin x(sin x sec x)
= 1 + (sin² x) sec² x/ sec x
= (sec² x + sin² x)/ sec x
= 1/ sec x

Now, since sec² x = 1/ cos² x, we have:

1/ sec x = cos² x

Therefore, we have shown that the left-hand side of the identity simplifies to cos² x. This is equal to the right-hand side of the identity, proving the given identity.

Therefore, we have shown that the left-hand side of the identity simplifies to cos² x. This is equal to the right-hand side of the identity, proving the given identity.

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