WILL GIVE BRAINLIEST.
Two objects attract with a gravitational force of 140 units.
If the mass of one object is doubled and the mass of the other object is tripled and the separation distance between the objects' centers is doubled, then the new force of gravitational attraction would be ________ units.

Answer:

Ductility

Explanation:

is the physical property of a material associated with the ability to be hammered thin or stretched into wire without breaking. A ductile substance can be drawn into a wire.

The water budget equation for the Creek drainage basin is: Precipitation = Stream discharge + Evapotranspiration ± Change in storage.

To develop the water budget equation for this problem, we need to account for the inputs and outputs of water in the Creek drainage basin. The water budget equation can be expressed as,

P = Q + ET ± ΔS

P = Precipitation input (mm)

Q = Stream discharge (m³/s)

ET = Evapotranspiration (mm)

ΔS = Change in storage (mm)

First, let's convert the units of the given values,

Precipitation input (P) = 550 mm

Stream discharge (Q) = 1.8 m³/s

Now, let's determine the evapotranspiration (ET) and change in storage (ΔS) terms. However, the problem doesn't provide information about ET, so we cannot calculate it accurately. The problem doesn't provide information about ΔS, so we cannot calculate it accurately.

Given these limitations, we can write the simplified water budget equation for this problem,

550 mm = 1.8 m³/s + ET ± ΔS

Please note that without information about evapotranspiration and changes in storage, we cannot fully determine the water budget for the Creek drainage basin.

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The statement that is most likely true about the locations is that location A is farther from the equator than location B ( A )

The average temperature throughout the year is higher in location B then that of location A. The temperature is typically warmer near the equator and is typically cooler near the polar regions.

But some factors such as elevation, precipitation and ocean currents might affect the climate pattern. This change in temperature between equator and polar regions is due to the fact that equatorial regions receive more light and energy from the Sun than the polar regions.

Therefore, the statement that is most likely true about the locations is that location A is farther from the equator than location B ( A )

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In this scenario, the red team hits the ball over the net in 2 hits and it hits the floor 2 times before the blue team can hit the ball. Based on the given information, the red team would earn 2 points.

1. The red team hits the ball over the net in 2 hits. This means that the red team successfully makes the ball go over the net within 2 hits.

2. The ball then hits the floor 2 times before the blue team can hit it. This means that the ball bounces on the floor twice before the blue team has a chance to make a hit.

Since the red team successfully hits the ball over the net and it hits the floor twice before the blue team can make a hit, the red team would earn 2 points.

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Answer: A roller coaster does not have an engine to generate energy. The climb up the first hill is accomplished by a lift or cable that pulls the train up. This builds up a supply of potential energy that will be used to go down the hill as the train is pulled by gravity

Hope this helps! Good luck with future homework and exams!

Answer:

The frequency of the wave will be 53.85 Hz

Explanation:

to determine our answer, we can use the following formula "Speed = Wavelength x Frequency."

Speed = 280 m/s

wavelength = 5.2 meters

frequency = ?

meaning, 280 m/s=5.2 times x

divide each side by 5.2

x=700/13 or 53 11/13, or x=53.85

Its P path describes the change of state i.e from solid to liquid.

"A solid is that state of matter which has a fixed shape, mass, and volume. It suffers very small changes in volume by changing the temperature. It can not be compressed, e.g. — Sand, Wood, Copper, Ice, etc."

"A liquid is a sample of matter that conforms to the shape of a container in which it is held, and which acquires a defined surface in the presence of gravity. The term liquid is also used in reference to the state, or condition, of matter having this property."

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a. We can use the notation d₀(z) to represent the distance as a function of redshift:

\(do(z) = [(z + 1) / (z - 1)]^2\)

b. We can solve this equation numerically to find the minimum redshift Z₀.

\([(z + 1) / (z - 1)]^2 = (1 ± 0.1) * cz/H\)

c. In the critical universe, the redshift is zero for all distances. Therefore, we cannot derive a meaningful distance versus the redshift formula (d₁(z)) for the critical universe since the redshift is constant at zero.

d. There is no minimum redshift z₁ to distinguish the two cases.

e. We can solve this equation numerically to find the minimum redshift Z₁₀.

\([(Z10 + 1) / (Z10 - 1)]^2 = (1 ± 0.1) * cz/H\)

a. To derive an expression for distance as a function of redshift in the empty universe model, we'll start with the inverted formula for redshift as a function of distance (z(d)) from Exercise 1a and solve for distance (d) as a function of redshift (z). Let's use the notation do(z), where the subscript "0" denotes the null value of 2m.

In the empty universe model, the formula for redshift as a function of distance is given by:

\(z(d) = [(2m)^(-1/2) - 1] / [(2m)^(-1/2) + 1]\)

To invert this formula and express distance as a function of redshift, we'll solve for d:

\(z = [(2m)^(-1/2) - 1] / [(2m)^(-1/2) + 1]\)

Rearranging the equation:

\([(2m)^(-1/2) - 1] = z * [(2m)^(-1/2) + 1]\)

Expanding both sides:

\((2m)^(-1/2) - 1 = z * (2m)^(-1/2) + z\)

Isolating (2m)^(-1/2):

\((2m)^(-1/2) = (z - 1) / (z + 1)\)

Taking the reciprocal of both sides:

\((2m)^(1/2) = (z + 1) / (z - 1)\)

Squaring both sides:

\(2m = [(z + 1) / (z - 1)]^2\)

Now, we can use the notation do(z) to represent the distance as a function of redshift:

\(do(z) = [(z + 1) / (z - 1)]^2\)

b. If a distance measurement is accurate to 10 percent, we need to determine the minimum redshift Zo at which we can observationally distinguish the redshift versus distance of an empty universe from a strictly linear Hubble law (d = cz/H).

In the linear Hubble law, the relationship between distance (d) and redshift (z) is given by:

\(d = cz/H\)

Let's assume our observed distance (do) is within 10 percent of the distance predicted by the linear Hubble law. Therefore, we can write:

\(do = (1 ± 0.1) * cz/H\)

To distinguish between the empty universe model and the linear Hubble law, we need to find the redshift at which the distance differs by at least 10 percent. Let's substitute the expression for do(z) from part a into the equation:

\([(z + 1) / (z - 1)]^2 = (1 ± 0.1) * cz/H\)

We can solve this equation numerically to find the minimum redshift Zo.

c. For the critical universe with 2m = 1 (and Na = 0), we'll derive the distance versus redshift formula (dı(z)) using the results from Exercise 1a.

In the critical universe model, the formula for redshift as a function of distance is given by:

\(z(d) = [(2m)^(-1/2) - 1] / [(2m)^(-1/2) + 1]\)

Substituting 2m = 1:

\(z(d) = [(1)^(-1/2) - 1] / [(1)^(-1/2) + 1]\)

Simplifying:

\(z(d) = 0\)

In the critical universe, the redshift is zero for all distances. Therefore, we cannot derive a meaningful distance versus the redshift formula (dı(z)) for the critical universe since the redshift is constant at zero.

d. To observationally distinguish the redshift versus distance of a critical universe from a strictly linear Hubble law, we need to find the minimum redshift z1 at which the distance differs by at least 10 percent. However, since the redshift in the critical universe is always zero, there is no redshift at which the distance would differ from the linear Hubble law. Therefore, there is no minimum redshift z1 to distinguish the two cases.

e. To observationally distinguish the redshift versus distance of a critical universe from an empty universe with a 10 percent accuracy, we need to find the minimum redshift Z10.

Using the results from part a, the expression for distance in the empty universe (do(z)) is:

\(do(z) = [(z + 1) / (z - 1)]^2\)

To distinguish between the critical universe (redshift always zero) and the empty universe, we need to find the redshift Z10 at which the distance differs by at least 10 percent. Let's substitute the expression for do(z) into the equation:

\([(Z10 + 1) / (Z10 - 1)]^2 = (1 ± 0.1) * cz/H\)

We can solve this equation numerically to find the minimum redshift Z10.

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The rotational inertia of the plate about the axle is 2.5 × 10⁻⁴ kg m².

Rotational inertia measures how a good deal an object resists converting rotation. In linear motion, consistent with Newton's 2d regulation, we use mass to gauge an item's resistance to change however in rotational motion, rotational inertia serves the same motive.

calculation:-

mass of disc = 0.500 kg

radius = 2 cm

           = 0.02 m

Force = 0.400 N

Angular speed ω = 114 rad/s

angular acceleration α = ω/t = 114/5 = 22.8 rad/s²

I = Iplate + I disc

= 3.5 × 10⁻⁴ - 1× 10⁻⁴

Iplate = 2.5 × 10⁻⁴ kgm²

In physics and mechanics, torque is the rotational equation of linear pressure. it is also called the moment, a moment of force, rotational pressure, or turning effect, depending on the field of observation. It represents the capability of a force to produce an alternate inside the rotational movement of the frame.

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Telescopes designed to study the earliest stages in galactic lives should be optimized for observations in infrared light (Option C).

Telescopes designed to study the earliest stages of galactic formation need to observe light that can penetrate the dust clouds that often obscure these early events. Infrared light is well suited for this purpose because it has longer wavelengths than visible light and can penetrate dust clouds more easily. Infrared telescopes can detect the heat radiation given off by the dust, which is a signature of the formation of stars and planets.

Additionally, infrared light can reveal the presence of cold gas, which is necessary for the formation of stars. By using telescopes optimized for observations in infrared light, astronomers can gain important insights into the early stages of galactic lives.

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Answer:

6 seconds is the best answer

It will take 6 seconds to the football in the air.

Velocity is the rate that the position of an item changes relative to time. When forces are applied to an item, it accelerates. This acceleration affects the velocity.

The object's initial velocity, vi, is its speed before acceleration changes it. The new velocity, which has increased for a while, is the final velocity, or vf.

Initial Velocity, denoted as u, is the velocity at time period t = 0. It is the speed at which motion first occurs. There are four equations for starting velocity: The starting velocity is expressed as u = v - at if time, acceleration, and final velocity are given.

Therefore, It will take 6 seconds to the football in the air.

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Answer:

c

Explanation:

The marginal cost curve image  has been attached from which we can clearly, indicate that

ATC = average total cost

AFC = average fixed cost

AVC = average variable cost.

From the graph we can indicate that the marginal cost curve

(c) Lies above the AVC curve when the AVC curve slopes downward.

Answer:

A) s=1/2at^2

t=√(2s/a)=√(2x400)/10.0)=9.0s

B) v=at

v=10.0x9=90m/s

The speed that a fly with a mass of 0.65 g would need in order to have the same kinetic energy as a 1250 kg automobile traveling at a speed of 11 m/s is 2133.97 m/s.

Given:mass of fly, m1 = 0.65 g = 0.00065 kg

speed of automobile, v2 = 11 m/smass of automobile, m2 = 1250 kg

To find: Speed of fly with kinetic energy same as automobile

Formula:Kinetic energy = 0.5 * mass * speed²

Solution:Let v1 be the speed of the fly

Kinetic energy of automobile = Kinetic energy of fly0.5 * m2 * v2² = 0.5 * m1 * v1²

Substituting given values0.5 * 1250 * 11² = 0.5 * 0.00065 * v1²v1² = (0.5 * 1250 * 11²)/0.00065v1² = 4545454.55v1 = √(4545454.55)v1 = 2133.97 m/s

Therefore, the speed that a fly with a mass of 0.65 g would need in order to have the same kinetic energy as a 1250 kg automobile traveling at a speed of 11 m/s is 2133.97 m/s.

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Answer B) Light is right.

Electromagnetic waves, which include visible light, are one form of energy released in a stellar explosion on the far side of the galaxy. These electromagnetic waves can be seen as light on Earth because they move at the speed of light through the vacuum of space. Light, or electromagnetic radiation, is a form of energy that may be seen by the human visual system.

Different from the electromagnetic waves that make up light are infrared (A), radio (C), and sound waves (D), all of which are waves that can carry energy. Electromagnetic waves, which include visible light, are the most likely to reach Earth and be detected in the event of a stellar explosion in the distant universe. Sound waves can only travel through a medium like air, while infrared and radio waves can go through the vacuum of space because their wavelengths are so much longer than those of visible light.

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The block moves up the incline with a constant velocity, v² = 2gx.sin θ - 2μgd. The block will move up the incline as long as the numerator in the above equation is positive.

A block of mass m is placed in a smooth-bored spring gun at the bottom of the incline so that it compresses the spring by an amount x_c. The spring has spring constant k. The incline makes an angle theta with the horizontal and the coefficient of kinetic friction between the block and the incline is mu.

The block is released, exits the muzzle of the gun, and slides up an incline a total distance the distance traveled along the incline by the block after it exits the gun. Ignore friction when the block is inside the gun.

Also, assume that the uncompressed spring is just at the top of the gun (i.e., the block moves a distance x_c while inside of the gun). Use g for the magnitude of acceleration due to gravity. Determine the distance traveled along the incline by the block after it exits the gun.Given, Mass of the block = m Initial compression of the spring = xc, spring constant = k, Angle between incline and horizontal = θ, Coefficient of kinetic friction = μ, Distance traveled along the incline by the block = d.

Let us begin with the given problem,

the work done on the spring is

K = 1/2 k x_c²

As the spring is compressed, the potential energy of the spring increase. Thus, the work done on the block by the spring is -K.

This work is equal to the increase in kinetic energy of the block.

This kinetic energy is converted into potential energy as the block moves up the incline. Thus, work done by the block against the gravitational force is mgh where, h is the height the block reaches above its initial position. The work done against the friction is mgh.f where, f is the coefficient of friction between the block and the incline.

Then, K + mgh.f = 1/2mv²

where v is the velocity of the block after it exits the gun.

Determine the final velocity of the block,

v²= 2(k/m) x_c² - 2gh(f + sin θ).

The block moves up the incline with a constant velocity,

v² = 2gx.sin θ - 2μgd.

The above equation is obtained using the work-energy principle.

Then,

2gx.sin θ - 2μgd = 2(k/m) x_c² - 2gh(f + sin θ)

Here, solving for d, we get,

d = (1/2g) [x_c² (k/m) - μx_c² sin θ] / (μ + sin θ).

The distance traveled along the incline by the block after it exits the gun is

(1/2g) [x_c² (k/m) - μx_c² sin θ] / (μ + sin θ).

Thus, this is the required solution. The block will move up the incline as long as the numerator in the above equation is positive.

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Answer:A. Nuclear energy to thermal energy to kinetic energy to electric

energy

Answer:

C. in a cluster of galaxies

Explanation:

Gravity is considered to be a universal force of attraction which acts between all objects that has both mass, energy and occupy space. Therefore, it acts in such a way as to bring objects together.

Additionally, the gravity of earth makes it possible for all physical objects to possess weight.

A galaxy can be defined as a collection or group of many billions of stars and other planetary body which are existing independently.

Hence, Earth's location in space can be described as being in a cluster of galaxies within the solar system comprising of jupiter, mars, sun, venus, moon, etc.

Answer:

Explanation:

Given:

M = 20.0 kg

V₀ = 0 m/s

V = 16.0 m/s

___________

A - ?

A = M·V² / 2

A = 20.0·(16.0)² / 2 = 2 560 J

Answer: B 2560j

Explanation:

i got it right on edge 2022

It is usually best to reduce speed to suggested limit when  a driver gets to a speed hump and is denoted as option D.

This refers to a situation in which the speed or acceleration of a body is reduced while in the other hand, acceleration refers to the condition in which a body increases its speed or acceleration.

Speed humps are structures which are placed in the road in other to slow vehicles to between 10 to 15 mph. They ensure over speeding is checked due to it being dangerous to other users.

Applying brake or maintaining current speed may lead to the vehicle being tilted towards the front end which may result in collision and other forms of accident.

This therefore the reason why reducing speed to suggested limit is the most appropriate choice.

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The magnitude of the average force exerted by the seat belt on the dummy is 224N .

The average force is the force produced by an object moving over a specific period of time at a given rate of speed, or velocity. This velocity is not instantaneous or precisely measured, as the word "average" indicates.

mass of the dummy (m) = 80kg

velocity of the dummy (v) = 28 m/s

time (t) = 10 seconds

Average force exerted (F)

To calculate the average force;

According to the formula;

F = (m × v) ÷ t

Where;

F represents the force exerted

m represents the mass of the dummy

v represents the velocity

t represents the time

F = m * v/t

F = 80 *28/10

F = 224

F = 224 N

The force exerted by the seat belt on the dummy is 224N .

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Another name for the geometric optics theory of light is ray optics.

The geometric optics theory of light, also known as ray optics, is a simplified model of how light behaves. According to this theory, light travels in straight lines, or rays, and interacts with surfaces through reflection, refraction, absorption, and transmission. This theory is based on the assumption that the wavelength of light is much smaller than the size of the objects and structures it interacts with. Therefore, the wave nature of light is not considered in this theory.

Geometric optics is used in many practical applications, such as in the design of lenses, mirrors, and other optical systems. It provides a useful tool for predicting the behavior of light in simple optical systems, such as those used in cameras and telescopes. However, it has limitations and cannot explain some phenomena, such as interference and diffraction, which require the wave nature of light to be taken into account. For these situations, a different theory called wave optics or physical optics is used.

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Answer:

-0.75 m

Explanation:

The displacement of the girl is given by x = x₀cosωt where x₀ = maximum displacement of swing = 1.5 m, ω = angular frequency = π/3 rad/s and t = time of swing = 4 s

Substituting the values of the variables into the equation, we have

x = x₀cosωt

x = (1.5 m)cos(π/3 rad/s × 4 s)

x = (1.5 m)cos(2π/3)

x = (1.5 m)cos120°

x = 1.5 m × -0.5

x = -0.75 m

So, the girl is 0.75 m to the left of the equilibrium position 4 seconds into the motion.

To find the acceleration of the 2.84 kg block sliding down the inclined plane, use equation of motion.

Step 1: Identify the given values.
The initial velocity (u) = 1.58 m/s
The final velocity (v) = 5.29 m/s
The time (t) = 1.07 s

Step 2: Use the first equation of motion to find the acceleration.
The first equation of motion is: v = u + at

Step 3: Rearrange the equation to solve for acceleration (a).
a = (v - u) / t

Step 4: Substitute the given values into the equation.
a = (5.29 m/s - 1.58 m/s) / 1.07 s

Step 5: Calculate the acceleration.
a = 3.71 m/s²

So, the acceleration of the 2.84 kg block sliding down the frictionless inclined plane is 3.71 m/s².

Complete Question: the initial velocity of a 2.84 kg block sliding down a frictionless inclined plane is found to be 1.58 m/s. then 1.07 s later, it has a velocity of 5.29 m/s. Find the acceleration sliding down the frictionless inclined plane.

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Answer:

0.500 T

Explanation:

Since the change in time and the number of coils are both 1, I set the problem up to be 1.3=(1.5(x)-13(x)). I then plugged in numbers for x until I got the answer to be 1.3 V.

The composition of a particle with a css quark might be unaffected by an electric field. Option A is correct.

An electric field is an electric property that is connected with any location in space where a charge exists in any form. The electric force per unit charge is another term for an electric field.

The complete question is:

"A particle unaffected by an electric field could have a quark composition of. A) css B) bbb C) udc D) uud."

A particle unaffected by an electric field could have a css quark composition.

Hence, option A is correct.

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Answer:

yes it is C

Explanation:

The effect of the factors which he can he actually find out using only this lamp to determine the size of shadow is the light intensity and type of object.

This forms part of the scientific methods and is referred to as a procedure which is used to support or refute an hypothesis.

The size of the shadow is dependent on factors such as the light intensity and the type of object. Since the lamp produces the light in which the intensity can be gotten and the type of material it is in contact with then it therefore the correct choices.

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The roots of the given equation 4x² - 4xyy = 0 are real for y ∈ (0, 2.5) and P(roots are real) = 1/2.

Given equation is 4x² - 4xyy = 0. To find the probability that the roots of this equation are both real, we need to first solve the equation.

4x² - 4xyy = 0 ⇒ 4x² = 4xyy ⇒ x² = y²

The roots of this equation will be real if the discriminant is greater than or equal to zero.

Discriminant = b² - 4ac = 0 - 4(4)(-y²) = 16y²

For real roots, we must have 16y² ≥ 0 ⇒ y ∈ (-∞, ∞)

Now, we need to find the values of y that lie in the given range (0, 5) for which the roots are real.

Since we know that x² = y², we can say that x = ±y.

Therefore, the roots are real when y is such that the quadratic expression has equal roots or y ∈ {0, 2.5}.

Thus, the probability that the roots of the given equation are both real is the ratio of the length of the interval (0, 2.5) to the length of the entire interval 0, 5), which is equal to 1/2.

Therefore, P(roots are real) = 1/2.

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