Will give thanks and five stars for work shown and brainliest if multiple answers

Answer:

14.76

Step-by-step explanation:

First find the length of the diagonal across the bottom using the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

12^2+5^2 = c^2

144+25 = c^2

169 = c^2

Take the square root of each side

sqrt(169) = sqrt(c^2)

13 = c

Then find the length of the diagonal across the  middle using the Pythagorean theorem

7^2 + c^2 = d^2

7^2 + 13^2 = d^2

49+ 169 = d^2

218 = d^2

Take the square root of each side

sqrt(218) = sqrt(d^2)

14.76482306 = d

To the nearest thousandth

14.76

The expected number of dumplings that need to be eaten to find the first lucky dumpling is 40/3 or approximately 13.33.

To answer this question, we need to understand the concept of the expected number. The expected number is the average number of times an event is expected to occur if an experiment is repeated a large number of times.

The expected number of dumplings to be eaten to find the first lucky dumpling is the sum of the products of the probability of finding a lucky dumpling on the nth try and the number of dumplings eaten up to that point. In mathematical notation, we can write it as:

Expected number = (3/40) x 1 + (37/40) x (3/37) x 2 + (37/40) x (33/37) x (3/36) x 3 + ...

Simplifying this expression, we get:

Expected number = 40/3

This means that, on average, the group will need to eat about 13 or 14 dumplings before they find the first lucky one.

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Answer:

X= Negative 2/3 or -0.6

Step-by-step explanation:

here you go

a. The product of 4 and -3 is -12.

b. The product of 3 and 12 is 36.

a. To find the product of 4 and -3, we can multiply them together:

4 ⋅ (-3) = -12

Therefore, the product of 4 and -3 is -12.

b. To find the product of 3 and 12, we multiply them together:

3 ⋅ 12 = 36

So, the product of 3 and 12 is 36.

In both cases, we have used the basic multiplication operation to calculate the product.

When we multiply a positive number by a negative number, the product is negative, as seen in the case of 4 ⋅ (-3) = -12.

Conversely, when we multiply two positive numbers, the product is positive, as in the case of 3 ⋅ 12 = 36.

Multiplication is a fundamental arithmetic operation that combines two numbers to find their total value when they are repeated a certain number of times.

The symbol "⋅" or "*" is commonly used to represent multiplication.

In the given examples, we have successfully determined the products of the given numbers, which are -12 and 36, respectively.

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Answer:

pretty sure its 40cm

Step-by-step explanation:

hope this helps :)

Answer:

36cm

Step-by-step explanation:

Tan(14/12)=angle of ONP

Tan(42/X)=angle of LNM

singe those angels are the same;

Tan(14/12)=Tan(42/X)

14/12=42/X

14*X=42*12

X=(42*12)/14

X=36

The upper control limit (UCL) is approximately 2.0018 litres, and the lower control limit (LCL) is approximately 1.9982 litres, which would include roughly 95.5 percent of the sample means.

Now let's check if the process is in control using the given sample means:

To determine the upper and lower control limits for the sample means, we can use the formula:

Upper Control Limit (UCL) = Mean + (Z * Standard Deviation / sqrt(n))

Lower Control Limit (LCL) = Mean - (Z * Standard Deviation / sqrt(n))

In this case, we want to include roughly 95.5 percent of the sample means, which corresponds to a two-sided confidence level of 0.955. To find the appropriate Z-value for this confidence level, we can refer to the standard normal distribution table or use a calculator.

For a two-sided confidence level of 0.955, the Z-value is approximately 1.96.

Given:

Mean = 2.0 litres

Standard Deviation = 0.01 litres

Sample size (n) = 5

Using the formula, we can calculate the upper and lower control limits:

UCL = 2.0 + (1.96 * 0.01 / sqrt(5))

LCL = 2.0 - (1.96 * 0.01 / sqrt(5))

Calculating the values:

UCL ≈ 2.0018 litres

LCL ≈ 1.9982 litres

Therefore, the upper control limit (UCL) is approximately 2.0018 litres, and the lower control limit (LCL) is approximately 1.9982 litres, which would include roughly 95.5 percent of the sample means.

Now let's check if the process is in control using the given sample means:

Mean of the sample means = (2.005 + 2.001 + 1.998 + 2.002 + 1.995 + 1.999) / 6 ≈ 1.9997

Since the mean of the sample means falls within the control limits (between UCL and LCL), we can conclude that the process is in control.

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The 95% confidence interval for the average number of units that students in their college are enrolled in is (11.46,12.53)

We are given the number of students, n =  46, and  the mean of the sample which is x= 12.5, and the standard deviation of the sample which is s= 1.8 , the formula  we are referring to for calculating the confidence interval which is :

x ± t (s/√(n))

since for  this case, the degree of freedom is one less than the mean, which is 45, the critical value for the confidence of 95% with  the degree of freedom of 45 is 2.015

x + t(s/√(n)) = 12.5 +2.015*(1.8/6.78)=  12.53

x - t(s/√(n))= 12.5 -2.015*(1.8/6.78)= 11.46

The interval is (11.46,12.53)

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The set of integers is closed under the operation of addition because the sum of any two integers is always another integer and is therefore in the set of integers.

What are integers ?

An integer is a whole number (not a fractional number) that can be positive, negative, or zero. Examples of integers are: -5, 1, 5, 8, 97, and 3,043. Examples of numbers that are not integers are: -1.43, 1 3/4, 3.14, .

According to the Property of Closure, A set has the closure property under a particular operation if the result of the operation is always an element in the set.  If a set has the closure property under a particular operation, then we say that the set is “closed under the operation.”

Hence ,  the set of integers is closed under the operation of addition because the sum of any two integers is always another integer and is therefore in the set of integers.

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If we use alpha as the criteria or critical value for the maximum probability of incorrectly rejecting the null hypothesis, then when the p-value is less than alpha, the null hypothesis is rejected.

If we use alpha as the criteria or critical value for the maximum probability of incorrectly rejecting the null hypothesis, then when the p-value is less than alpha, the null hypothesis is rejected. This means that there is strong evidence to suggest that the alternative hypothesis is true and that the data set supports this conclusion. Therefore, we can conclude that the null hypothesis is not supported by the data and that we can reject it.
If we use alpha as the criteria or critical value for the maximum probability of incorrectly rejecting the null hypothesis, then when the p-value is less than alpha, the null hypothesis is rejected.

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Answer: l think the answer is -1

Answer:

10.7703296142

Step-by-step explanation:

Using "Desmos" a graphing chart and the hypotenuse formula, i have found the distance diagonally from point (4,7) and (2,2)

a.  y(t) = x(t-2) + x(2-t) is causal,

b. y(t) = c is memoryless, linear, time-invariant, and causal. It is stable.

c. y(t) = (cos(3t)]x(t) is causal and stable.

d.  y(n) = x(n - 2) – 2x(n - 8) is causal.

e. y(n) = nx(n) is memoryless, linear, time-invariant, causal, and stable.

f. y(n) = x(4n + 1) is causal.

a. y(t) = x(t-2) + x(2-t)

It is causal as the output at any time depends only on the present and past values of the input.

Stability cannot be determined from the given equation.

b. y(t) = c

This system is memoryless because the output y(t) is solely determined by a constant value c, regardless of the input.

It is linear as the output is a scaled version of the input x(t), and it is also time-invariant since shifting the input does not affect the output expression. It is causal and stable since it produces a constant output regardless of the input.

c. y(t) = (cos(3t)) × x(t)

It is time-invariant since shifting the input does not affect the output expression.

It is causal and stable as the output at any time depends only on the present and past values of the input.

d. y(n) = x(n - 2) – 2x(n - 8)

The system is time-invariant as shifting the input by a constant time results in the same output expression.

It is causal as the output at any time depends only on the present and past values of the input.

Stability cannot be determined from the given equation.

e. y(n) = nx(n)

This system is memoryless because the output y(n) is solely determined by the present value of the input x(n) multiplied by n.

It is linear since it consists of scaling the input by n.

It is time-invariant as shifting the input does not affect the output expression.

It is causal and stable as the output at any time depends only on the present value of the input.

f. y(n) = x(4n + 1)

It is linear as it involves a single scaling operation.

It is time-invariant as shifting the input does not affect the output expression.

It is causal as the output at any time depends only on the present and past values of the input.

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In the given problem, we need to investigate if the given systems are linear memoryless, linear, time-invariant, casual, and stable.

Let's discuss the given system step by step:

a) y(t) = x(t-2) + x(2-t)

Memoryless:

The system y(t) = x(t-2) + x(2-t) is not memoryless because the output at any given time t depends on the input over a range of time.

Linear:

The system y(t) = x(t-2) + x(2-t) is linear because it satisfies the following two properties

:i) Homogeneity

ii) Additivity

Time-invariant:

The system y(t) = x(t-2) + x(2-t) is not time-invariant because a time delay in the input x(t) causes a different time delay in the output y(t).

Casual:

The system y(t) = x(t-2) + x(2-t) is not casual because the system's output depends on the future input samples.

Stable:

The system y(t) = x(t-2) + x(2-t) is not stable because the impulse response of this system is not absolutely summable.

b) y(t) =Memoryless:

The system y(t) = is not memoryless because the output at any given time t depends on the input over a range of time.

Linear:

The system y(t) = does not satisfy the additivity property. Hence, it is not linear.

Time-invariant:

The system y(t) = is time-invariant because shifting the input causes the same amount of shift in the output.

Casual:

The system y(t) = is casual because the system's output depends on the present and past input samples.

Stable:

The system y(t) = is stable because the impulse response of this system is absolutely summable.

c) y(t) = (cos(3t)]x(t)Memoryless:

The system y(t) = (cos(3t)]x(t) is not memoryless because the output at any given time t depends on the input over a range of time.

Linear:

The system y(t) = (cos(3t)]x(t) is linear because it satisfies the following two properties:

i) Homogeneity

ii) AdditivityTime-invariant:

The system y(t) = (cos(3t)]x(t) is time-invariant because shifting the input causes the same amount of shift in the output.

Casual:

The system y(t) = (cos(3t)]x(t) is casual because the system's output depends on the present and past input samples.

Stable:

The system y(t) = (cos(3t)]x(t) is stable because the impulse response of this system is absolutely summable.

d) y(n) = x(n - 2) – 2x(n - 8)Memoryless:

The system y(n) = x(n - 2) – 2x(n - 8) is not memoryless because the output at any given time n depends on the input over a range of time.

Linear:

The system y(n) = x(n - 2) – 2x(n - 8) is linear because it satisfies the following two properties

:i) Homogeneity

ii) AdditivityTime-invariant:

The system y(n) = x(n - 2) – 2x(n - 8) is time-invariant because shifting the input causes the same amount of shift in the output.

Casual:

The system y(n) = x(n - 2) – 2x(n - 8) is not casual because the system's output depends on the future input samples.

Stable:

The system y(n) = x(n - 2) – 2x(n - 8) is stable because the impulse response of this system is absolutely summable.

e) y(n) = nx(n)Memoryless:

The system y(n) = nx(n) is memoryless because the output at any given time n depends on the present input sample.

Linear:

The system y(n) = nx(n) is not linear because it does not satisfy the homogeneity property.

Time-invariant:

The system y(n) = nx(n) is time-invariant because shifting the input causes the same amount of shift in the output.

Casual:

The system y(n) = nx(n) is not casual because the system's output depends on the future input samples.

Stable:

The system y(n) = nx(n) is not stable because the impulse response of this system is not absolutely summable.

f) y(n) = x(4n + 1)Memoryless:

The system y(n) = x(4n + 1) is memoryless because the output at any given time n depends on the present input sample.

Linear:

The system y(n) = x(4n + 1) is not linear because it does not satisfy the additivity property.

Time-invariant:

The system y(n) = x(4n + 1) is time-invariant because shifting the input causes the same amount of shift in the output.

Casual:

The system y(n) = x(4n + 1) is not casual because the system's output depends on the future input samples.

Stable:

The system y(n) = x(4n + 1) is not stable because the impulse response of this system is not absolutely summable.

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We can expect approximately 200 students to like baseball in a population of 1000 students.

To estimate the number of students who would likely like baseball in a population of 1000 students, we can use the concept of proportion.

Let's first calculate the proportion of students who like baseball in the survey of 150 students:

Proportion = Number of students who like baseball / Total number of students in the survey

Proportion = 30 / 150 = 0.2

Now, we can use this proportion to estimate the number of students who would likely like baseball in the population of 1000 students:

Number of students who like baseball = Proportion * Total number of students in the population

Number of students who like baseball = 0.2 * 1000 = 200

Therefore, based on the survey results, we can expect approximately 200 students to like baseball in a population of 1000 students.

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Check the picture below.

The value of cos in the right-angled triangle as a simple fraction is

24/25.

We know a right-angled triangle has three sides they are -: Hypotenuse,

Opposite and Adjacent.

We can remember SOH CAH TOA which is,

sin = opposite/hypotenuse, cos = adjecen/hypotenuse and

tan = opposite/adjacent.

We know cos = adjecen/hypotenuse.

Here the value of the adjacent is 48 and the value of the hypotenuse is 50.

Therefore, Expressing cos as a fraction in simplest terms would be,

cos = 48/50.

cos = 24/25.

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The correct answer is -60

When you look at -70 it looks like it would be higher then -60 but -60 is actually higher then -70 because it has a negative line.

Therefore, the correct answer is -60

Answer:

point a would be (-4,3) point b would be (0,5) point c would be (2,1)

Answer:

1/2

Step-by-step explanation:

Since there are 40 cards in total and 10 cards for each colour...the probability of drawing either a green card or red card will be 20/40 since there a are 20 green and red cards combined

Therefore the probability is 1/2

Answer:

1/2

Step-by-step explanation:

Le Test a MoNdoo

The sides of the triangle are (d) 12√2, 12√2, 24

The given parameters are:

In a 45-45-90 degree angle triangle, we have:

Hypotenuse = Opposite√2 and Hypotenuse = Adjacent√2

This means that:

Opposite =Adjacent

So, we have:

24 = Adjacent√2

Divide both sides by √2

Adjacent = 24/√2

Evaluate

Adjacent = 12√2

This means that:

Opposite = 12√2

Hence, the sides of the triangle are (d) 12√2, 12√2, 24

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The set notation will be S ∈ { 14, 16, 18, 20, 22, 24, 26, 28}.

When we have to represent set having defined specific number, we do my writing the number in curly bracket. When we have to represent the set having collection of continuous number between two specific defined number, we do by writing first and last number in small bracket.

As the terms given for the set is 14, 16, 18, 20, 22, 24, 26, 28 which are defined and specific terms so it will be represented by writing it in curly brackets

i.e. S ∈ { 14, 16, 18, 20, 22, 24, 26, 28}

Final answer,  the set will be S ∈ { 14, 16, 18, 20, 22, 24, 26, 28}

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Answer:

\(V = \frac{1}{3} (\pi \cdot 10^2 \cdot 16) \\\\V = \frac{1}{3} (1600 \pi ) \\\\V = 1675.52 \: m^3\)

The maximum amount of sand that can be stored in this structure is 1675.52 m³.

Step-by-step explanation:

The volume of a conical-shaped structure is given by

\(V = \frac{1}{3} (\pi \cdot r^2 \cdot h)\)

Where r is the radius and h is the height of the structure.

We are given that

radius = 10m

height = 16m

Substituting the above values into the formula, we get

\(V = \frac{1}{3} (\pi \cdot 10^2 \cdot 16) \\\\V = \frac{1}{3} (1600 \pi ) \\\\V = 1675.52 \: m^3\)

Therefore, the maximum amount of sand th can be stored in this structure is 1675.52 m³.

To subtract 2/3 from 11/12, we need to find a common denominator for the two fractions. The least common multiple (LCM) of 3 and 12 is 12. We can rewrite each fraction with a denominator of 12:

11/12 - 2/3 = (11/12) - (2/3) * (4/4) (Multiplying the denominator and numerator of 2/3 by 4 to get a denominator of 12)

11/12 - 8/12 = 3/12

Now that both fractions have a common denominator of 12, we can subtract the numerators:

11/12 - 2/3 = (11 - 8)/12 = 3/12

Simplifying this fraction by dividing both the numerator and denominator by 3, we get:

3/12 = 1/4

Therefore, 11/12 - 2/3 = 1/4.

Answer:

13 :V

Step-by-step explanation:

Answer: 13

Step-by-step explanation:

13 because 13+2=15 which would be the answer.

Answer:

N' (- 8, 2 )

Step-by-step explanation:

under a reflection in the y- axis

a point (x, y ) → (- x, y ) , then

N (8, 2 ) → N' (- 8, 2 )

It cannot determine causation as there may be other variables or factors that could be influencing the relationship between the two variables being analyzed.

Which one of the following cannot be determined from a scatterplot is a cause and effect relationship.

A scatterplot can show the strength and direction of a relationship between two variables, whether it is a positive or negative relationship, and whether it is curvilinear.

However, it cannot determine causation as there may be other variables or factors that could be influencing the relationship between the two variables being analyzed.

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2.5 is the mean of this distribution.

What is the distribution's mean?

Given: p = 0.05 and n= 50

Mean of the binomial distribution = n×p = 50 × 0.05 = 2.5

Therefore, option a is the correct answer. Other options are incorrect because these are irrelevant.

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Find the acute angle in the first quadrant used as a reference for

23, 128, 337, 128

The missing factor in the equation is -21

The Distributive Property introduces the multiplication operator an existing mathematical statement that involves the addition operator.

From the complete question, the equation is given as:

\(6 \times x= (3 \times 7) + (x \times 7)\)

Where x represents the missing factor.

So, we have:

\(6x= (21) + (7x)\)

Remove brackets

\(6x= 21 + 7x\)

Collect like terms

\(6x-7x= 21\)

Evaluate the like terms

\(-x= 21\)

Divide both sides by -1

\(x= -21\)

Hence, the missing factor in the equation is -21

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