With a phasor diagram explain the most economical power factor
Answers
The most economical power factor can be explained using a phasor diagram.
In electrical power systems, the power factor is a measure of how efficiently the power is being utilized. It is the cosine of the angle between the voltage and current phasors in an AC circuit. A phasor diagram is a graphical representation that shows the magnitude and phase relationship between voltage and current.
To understand the most economical power factor, we need to consider the concept of apparent power (S), which is the product of the voltage (V) and current (I). In an AC circuit, the power consumed is the real power (P), which is the product of the voltage, current, and power factor (PF).
When the power factor is unity (PF = 1), the voltage and current phasors are in phase, resulting in maximum power factor. At this point, the circuit operates at its most economical condition. The real power consumed is equal to the apparent power, and there is no reactive power (Q) component.
However, when the power factor deviates from unity, the angle between the voltage and current phasors increases, leading to a decrease in the power factor. This results in a higher reactive power component, which can cause inefficiencies in the system.
To improve the power factor and make it more economical, power factor correction techniques are employed. These techniques involve the use of capacitors or inductors to introduce a reactive power component that counteracts the reactive power in the system, thereby reducing the angle between the voltage and current phasors.
By adjusting the power factor to unity, the reactive power is minimized, leading to more efficient power usage and reducing losses in the system. This results in cost savings for the consumer by reducing penalties imposed by utility companies for low power factor and improving the overall efficiency of power transmission and distribution systems.
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Related Questions
A four-lane divided multilane highway (two lanes in each direction) in rolling terrain has five access points per mile and 11-ft lanes with a 4-ft shoulder on the right side and a 2-ft shoulder on the left. The peak-hour factor is 0.84 and the traffic stream consists of 6% trucks, 4% buses, and 3% recreational vehicles. The driver population adjustment factor is estimated at 0.90. If the analysis flow rate is 1250 pc/h/ln, what is the peak-hour volume
Answers
Answer:
peak-hour volume = 1890 veh/h
Explanation:
Determine the peak-hour Volume
Applying the equation below
Vp = v / ( PHF * N * Fg * Fdp ) -------------- ( 1 )
where :
Vp = 1250
v ( peak - hour volume ) = ?
PHF ( peak hour factor ) = 0.84
N = 2 lanes per direction
Fg ( grade adjustment for rolling terrain ) = 0.99 ≈ 1
Fdp = 0.90
Back to equation 1
v = Vp ( PHF * N * Fg * Fdp )
= 1250 ( 0.84 * 2 * 1 * 0.90 )
= 1890 veh/h
/*************************************************************************
* Compilation: javac LZWmod.java
* Execution: java LZWmod - < input.txt (compress)
* Execution: java LZWmod + < input.txt (expand)
* Dependencies: BinaryStdIn.java BinaryStdOut.java
*
* Compress or expand binary input from standard input using LZW.
*
*
*************************************************************************/
public class LZWmod {
private static final int R = 256; // number of input chars
private static final int L = 4096; // number of codewords = 2^W
private static final int W = 12; // codeword width
public static void compress() {
//TODO: Modify TSTmod so that the key is a
//StringBuilder instead of String
TSTmod st = new TSTmod();
for (int i = 0; i < R; i++)
st.put(new StringBuilder("" + (char) i), i);
int code = R+1; // R is codeword for EOF
//initialize the current string
StringBuilder current = new StringBuilder();
//read and append the first char
char c = BinaryStdIn.readChar();
current.append(c);
Integer codeword = st.get(current);
while (!BinaryStdIn.isEmpty()) {
codeword = st.get(current);
//TODO: read and append the next char to current
if(!st.contains(current)){
BinaryStdOut.write(codeword, W);
if (code < L) // Add to symbol table if not full
st.put(current, code++);
//TODO: reset current
}
}
//TODO: Write the codeword of whatever remains
//in current
BinaryStdOut.write(R, W); //Write EOF
BinaryStdOut.close();
}
public static void expand() {
String[] st = new String[L];
int i; // next available codeword value
// initialize symbol table with all 1-character strings
for (i = 0; i < R; i++)
st[i] = "" + (char) i;
st[i++] = ""; // (unused) lookahead for EOF
int codeword = BinaryStdIn.readInt(W);
String val = st[codeword];
while (true) {
BinaryStdOut.write(val);
codeword = BinaryStdIn.readInt(W);
if (codeword == R) break;
String s = st[codeword];
if (i == codeword) s = val + val.charAt(0); // special case hack
if (i < L) st[i++] = val + s.charAt(0);
val = s;
}
BinaryStdOut.close();
}
public static void main(String[] args) {
if (args[0].equals("-")) compress();
else if (args[0].equals("+")) expand();
else throw new RuntimeException("Illegal command line argument");
}
Answers
This is the source code for an implementation of the LZW compression algorithm in Java, called LZWmod. Here's a brief overview of the program:
The program reads input from standard input (BinaryStdIn) and writes output to standard output (BinaryStdOut).The compress method performs LZW compression on the input.The expand method performs LZW decompression on the input.The main method checks the command line arguments to determine whether to compress or decompress the input.Here are some more details about the implementation:
The compress method uses a modified TSTmod class to implement a symbol table for LZW compression. The symbol table maps strings to integer codes, where each code corresponds to a unique string in the input. The symbol table is initialized with all single-character strings (i.e., the ASCII characters).The compress method reads the input one character at a time, appending each character to a StringBuilder called current. The method then checks if the symbol table contains current. If it does, it continues reading input and appending characters to current. If it doesn't, the method writes the code for the current substring to the output, adds the current substring to the symbol table, and resets current to the last character read.The expand method uses an array of strings to implement a symbol table for LZW decompression. The symbol table is initialized with all single-character strings (i.e., the ASCII characters), as well as an empty string to represent the end of the input.The expand method reads input one code at a time, using each code to look up a corresponding string in the symbol table. The method writes the string to the output, and then adds a new string to the symbol table by concatenating the previous string with the first character of the current string. If the current code is the next available code (i.e., equal to i), the method uses a special-case hack to add a new string to the symbol table that is the concatenation of the previous string with its first character.This implementation follows the standard LZW algorithm, with the modification of using StringBuilder instead of String objects in the symbol table keys.
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Acme Logistics provides "Less than truck load" (LTL) services throughout the U.S. They have several hubs where they use cross-docking to move goods from one trailer to another. Acme built its last hub 10 years ago, and it had 36 dock doors. The cost index at that time was 140, and the total cost was $6 million. Acme plans a new hub that will have 48 dock doors. The cost index now is 195, and Acme will use a capacity factor of 0.82. What is the estimated cost of the new hub?
Answers
Answer:
The answer is "$10.12 million"
Explanation:
To find the price of the 36 dock doors only at the current rate, just use the cost index.
\(C_n=C_k \times (\frac{I_n}{I_k})\\\\\)
\(= 6 \times \frac{195}{140} \\\\= \$ \ 8 \ million\)
Its current cost of 36 dock doors is, thus,\(\$ \ 8 \ million\). To calculate the price for 48 dock doors, just use the second formula now:
\(\to (\frac{C_A}{C_B})=(\frac{S_A}{S_B})^{X}\\\\\to C_A=C_B \times (\frac{S_A}{S_B})^{X}\\\\\)
\(=8 \times (\frac{48}{36})^{0.82}\\\\= \$ 10.12 \ million\)
a storage tank contains liquid with a density of 0.0361 lbs per cubic inch. the height of liquid in the tank is 168 feet. what is the pressure of the liquid at the bottom of the tank give your answer in psi
Answers
Answer:
Objects that float on water have densities less than the density of water; those that do not float on water have densisties greater than the density of water:
Float on water: d < 0.0361 lb/in³ (where d denotes denisity)
Do not float on water: d > 0.0361 lb/in³
Explanation:
I don't know if this works for it or not?
The phase sequence of a 3-phase system for which VAN = 120 /90o V and VBN = 120 /210o V is:_______
a) bca
b) abc
c) cab
d) acb
Answers
Answer:
b. abc
Explanation:
The phase rotation and its sequence is order in which voltage is reached to their respective sources. The wave forms of a polyphase flow through AC source to the panel. The three phase system has two possible sequence which can be a-b-c or c-b-a. The correct answer is therefore b.
Electrical Circuit question..
Answers
Answer:
Cool.
Explanation:
please hurry i’ll give you 15 points
Answers
Answer:
measures, dissolves, liquid, carbon dioxide, evaporates, water vapor, mold, decompose
When measuring Brake Drum, the Brake Micrometer is set to a Base Drum Diameter of 10 inches plus four notches
Answers
Answer:
Hope this helps ;) don't forget to rate this answer !
Explanation:
The base drum diameter is the diameter of the brake drum when it is brand new and has not been worn down by use. When using a brake micrometer to measure a brake drum, the instrument is set to a base drum diameter of 10 inches plus four notches. This means that the micrometer has been calibrated to measure brake drums with a diameter of 10 inches plus an additional four notches. The notches are used to account for wear on the brake drum and allow for accurate measurements even if the drum has been worn down from use.
a quantity of gas mean the molecular weight is compressed according to the law pv=constant the initialnpressure
Answers
The value of n is 1.08. The final pressure of the gas is 1.05 bar, the change in internal energy of the gas is -21.8 kJ, and the change in entropy of the gas is 0.013 kJ/K.
How do you calculate the values given above?To find the value of n, we can use the first law of thermodynamics and the ideal gas law to set up the following equation:
ΔU = Q - W
where ΔU is the change in internal energy of the gas, Q is the heat added to the gas, and W is the work done by the gas.
Since the work done by the gas is equal to the product of the pressure and volume of the gas, we can rewrite the above equation as follows:
ΔU = Q - pv
Substituting in the values for the heat added to the gas (Q = 3.78 kJ), the initial pressure and volume of the gas (p = 1.03 bar, v = 0.98 m^3), and the change in internal energy of the gas (-21.8 kJ) gives us the following equation:
-21.8 kJ = 3.78 kJ - 1.03 bar * 0.98 m^3
Solving this equation for n gives us a value of 1.08.
The final pressure of the gas may be calculated using the ideal gas law and the initial pressure and volume of the gas:
pv = constant
p = (1.03 bar * 0.98 m^3) / v
Substituting in the values for the initial pressure and volume of the gas gives us a final pressure of 1.05 bar.
Finally, the change in entropy of the gas can be calculated using the second law of thermodynamics:
ΔS = Q / T
where ΔS is the change in entropy of the gas, Q is the heat added to the gas, and T is the absolute temperature of the gas. Substituting in the values for the heat rejected during compression (3.78 kJ) and the absolute temperature of the gas at the end of compression (288 K) gives us a change in entropy of the gas of 0.013 kJ/K.
Therefore, the value of n is 1.08, the final pressure of the gas is 1.05 bar, and the change in entropy of the gas is 0.013 kJ/K. It can then be concluded the correct answers are as given above.
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The complete question goes thus:
A quantity of gas (mean molecular weight 36.2) is compressed according to the law pv = constant, the initial pressure and volume being 1.03 bar and 0.98 m respectively. The temperature at the start of compression is 17°C and at the end it is 115°C. The amount of heat rejected during compression is 3.78 kJ, cp = 0.92. Calculate (i) Value of n (ii) Final pressure (iii) Change in entropy
Please help ASAP!!
Which type of hazard causes the greatest loss to human lives in civil engineering companies?
A) falls
B) toxic gases
C) corrosives
D) shocks
E) explosive solid
Answers
Answer:
a. Falls
Explanation:
plato
.Write a program that uses a void function void miles_to_km() to generate a kilometer
conversion table for all even kilometers from 2 miles to 62 miles. Use two decimal
places for kilometers.
Answers
Explanation:
rational
Step-by-step explanation:
The discriminant (d) of a quadratic equation ax^2 + bx + c = 0ax
2
+bx+c=0 is:
\boxed{\mathrm{d =} \ b^2 - 4ac}
d= b
2
−4ac
.
If:
• d > 0, then there are two real solutions
• d = 0, then there is a repeated real solution
• d < 0, then there is no real solution.
In this question, we are given the quadratic equation 3x^2 + 4x - 2 = 03x
2
+4x−2=0 . Therefore, the discriminant of the equation is:
b² - 4ac = (4)² - 4(3)(-2)
= 16 - (-24)rational
Step-by-step explanation:
The discriminant (d) of a quadratic equation ax^2 + bx + c = 0ax
2
+bx+c=0 is:
\boxed{\mathrm{d =} \ b^2 - 4ac}
d= b
2
−4ac
.
If:
• d > 0, then there are two real solutions
• d = 0, then there is a repeated real solution
• d < 0, then there is no real solution.
In this question, we are given the quadratic equation 3x^2 + 4x - 2 = 03x
2
+4x−2=0 . Therefore, the discriminant of the equation is:
b² - 4ac = (4)² - 4(3)(-2)
= 16 - (-24)
= 40
Since the discriminant, 40, is greater than zero, the quadratic equation has 2 rational solutions.
= 40
Since the discriminant, 40, is greater than zero, the quadratic equation has 2 rational solutions.
What is the difference between geomatics and land surveying
Answers
Land surveying is the era used to gather records additionally a part of geomatics. but geomatics is a technology to discover ways to analysis that survey geospatial facts through diverse approach and making out a selection via it.
Land Surveying (or Engineering Surveying) is in truth a sub-area of Geomatics. however, in practice, there may be little to no distinction between the disciplines and the phrases get used interchangeably often.
A Geomatics engineer will employ sensors, knowledge and software to provide notably correct positional information for any of these scenarios.
Surveyors make specific measurements to decide belongings boundaries. They provide information applicable to the form and contour of the Earth's floor for engineering, mapmaking, and creation initiatives.
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You are the operations manager of the flight department of a mid-size corporation. Your company will be leasing a new aircraft. The company attorney (who does not have any aviation practical expertise) sent you a draft of the aircraft dry lease agreement for your review and approval.
Share your thoughts of the attached agreement with your classmates.
In your opinion, is this contract over or under inclusive? Which, if any , items would you add or remove from the agreement? Why?
Answers
The scenario presented is that of an operations manager of a flight department reviewing a draft aircraft dry lease agreement sent by a company attorney for approval.
What is the scenario presented in the paragraph?The given scenario describes a situation where an operations manager of a flight department needs to review a draft aircraft dry lease agreement prepared by the company attorney.
The manager needs to analyze the agreement and determine whether it is over-inclusive or under-inclusive.
In my opinion, it is difficult to determine the nature of the contract without examining the actual draft agreement. However, the manager should review the agreement carefully and ensure that it covers all necessary details such as rental terms, maintenance responsibilities, insurance requirements, and liability clauses.
Based on the findings, the manager can suggest any changes or additions to the agreement to safeguard the company's interests and minimize the risks associated with aircraft leasing
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define electrical engineering?
Answers
Answer:
Electrical engineering is an engineering discipline concerned with the study, design, and application of equipment, devices, and systems which use electricity, electronics, and electromagnetism. It emerged as an identifiable occupation in the latter half of the 19th century after commercialization of the electric telegraph, the telephone, and electrical power generation, distribution, and use.
Explanation:
A horizontal force P is applied to a 130 kN box resting on a 33 incline. The line of action of P passes through the center of gravity of the box. The box is 5m wide x 5m tall, and the coefficient of static friction between the box and the surface is u=0.15. Determine the smallest magnitude of the force P that will cause the box to slip or tip first. Specify what will happen first, slipping or tipping.
Answers
Answer:
SECTION LEARNING OBJECTIVES
By the end of this section, you will be able to do the following:
Distinguish between static friction and kinetic friction
Solve problems involving inclined planes
Section Key Terms
kinetic friction static friction
Static Friction and Kinetic Friction
Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.
There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.
Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.
Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.
Technician A says that tailor-rolled parts may be used for collision energy managements.
Technician B says that tailor-welded parts are aluminum and steel parts joined together. Who is right?
A Only
B only
Both A and B
Neither A nor B
Answers
What is the Bernoulli formula?
Answers
Answer:
P1+1/2pv2/1+pgh1=P2+1/2pv2/2+pgh2
Catalytic converters reduce the engine's tailpipe emissions of unburned hydrocarbons and carbon monoxide and
can be recycled.
Answers
Answer:
True
Explanation:
Below is a cut and paste. Also read where recycling shops will pay up to $200 to harvest the precious metals used in catalyst process. Thieves will actually steal them from parked cars!!
Catalytic converters also use an oxidative catalyst composed of platinum or palladium. It helps reduce hydrocarbons (HC) and carbon monoxide (CO). To start with, carbon monoxide and oxygen combine to form carbon dioxide (CO2). Then, unburnt hydrocarbons and oxygen combine to form carbon dioxide and water.
Oxidation reactions for carbon monoxide and unburned hydrocarbons
Answer:
True
Explanation:
IM doing it right now
The UHRS platform is optimized for Edge/Internet Explorer only. You can still use your favorite browser, but keep in mind that you may experience technical issues when working on UHRS with a different browser than Edge or Internet Explorer.
UHRS is optimized for...
Answers
It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.
What is a UHRS?The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.
Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.
A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.
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In the bridge circuit below, which formula will give a correct value for R4 in terms of the voltage between Vleft and Vright (dV
Answers
A bridge circuit is a type of electrical circuit that is used to measure the value of an unknown electrical component.
The bridge circuit shown in the figure below can be used to find the value of an unknown resistance,
R4.
It consists of four resistors, R1, R2, R3, and R4, which are connected in a closed loop.
The circuit is powered by a voltage source,
V1, and a variable voltage source,
V2, which is used to balance the circuit.
The voltage between Vleft and V right is denoted by d V.
The formula that will give a correct value for R4 in terms of the voltage between Vleft and Vright (dV) is given by:
R4 = (R2 * R3) / (R1 * (V1 / d V) - R2 - R3)
This formula is based on the principle of balancing the bridge circuit.
When the bridge is balanced, the voltage between Vleft and V right is zero,
and the ratio of R2 and R3 to R1 and R4 is equal.
the value of R4 can be calculated by using the ratio of R2 and R3 to R1 and (V1 / d V) - R2 - R3.
This formula can be used to find the value of any unknown resistor in a bridge circuit, provided that the circuit is balanced and the other resistor values are known.
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HELP PLEASE!! ASAP!!!!
can some answer this 2 questions please as paragraph i want it nowww it is graded what action should be taken to make it safe ? also the first question
Answers
Actions violated:
Long hair isn't tied upThe girl isn't wearing a lab coatThe girl isn't wearing safety gogglesExtra: There doesn't seem to be an emergency fire blanket in the safeActions to be taken:
Make sure the girl wears a lab coat or kick her outMake sure the girl wears safety goggles or kick her outMake sure her hair is tied up or kick her outEdit: Use these to write your paragraph.
Please help!!!!! Thank u
Answers
Answer:
which class is this. I don't know sry
62. where are the following parts of the sarcomere located: z-disc, h-zone, a-band, i-band, m-line?
Answers
The following parts of the sarcomere are located as shown below:Z-disc:
The Z-disc is a disc-like structure that serves as the sarcomere's boundary.
Z-discs are made up of proteins that are responsible for connecting the thin filaments to one another in adjacent sarcomeres. It is located between two sarcomeres.
H-zone: H-zone refers to the area of the sarcomere that is occupied exclusively by thick filaments. As the sarcomere contracts, the H zone becomes smaller as the actin filaments slide inwards. It is located in the middle of the A-band.
A-band: The A-band refers to the area of the sarcomere that is occupied by the entire length of the thick filaments. It is located in the center of the sarcomere and spans the length of the thick filaments.
I-band: The I-band refers to the area of the sarcomere that is occupied exclusively by thin filaments. It is located on either side of the Z-disc.
M-line: The M-line is the central point of the sarcomere that divides the H-zone into two equal halves. The M-line also serves as an attachment site for thick filaments. It is located in the middle of the sarcomere, running perpendicular to the Z-discs.
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what is projectile motion.????
Answers
Answer:
Projectile motion is a form of motion experienced by a launched object.
Answer:
Projectile motion is the motion of a body which experiences both vertical and horizontal motions ( trajection ) from point of flight up to the point of landing.
(35-39) A student travels on a school bus in the middle of winter from home to school. The school bus temperature is 68.0° F. The student's skin temperature is 94.4° F. Determine the net energy transfer from the student's body during the 20.00 min ride to school due to electromagnetic radiation. Note: Skin emissivity is 0.90, and the surface area of the student is 1.50m2.
Answers
Answer:
The net energy transfer from the student's body during the 20-min ride to school is 139.164 BTU.
Explanation:
From Heat Transfer we determine that heat transfer rate due to electromagnetic radiation (\(\dot Q\)), measured in BTU per hour, is represented by this formula:
\(\dot Q = \epsilon\cdot A\cdot \sigma \cdot (T_{s}^{4}-T_{b}^{4})\) (1)
Where:
\(\epsilon\) - Emissivity, dimensionless.
\(A\) - Surface area of the student, measured in square feet.
\(\sigma\) - Stefan-Boltzmann constant, measured in BTU per hour-square feet-quartic Rankine.
\(T_{s}\) - Temperature of the student, measured in Rankine.
\(T_{b}\) - Temperature of the bus, measured in Rankine.
If we know that \(\epsilon = 0.90\), \(A = 16.188\,ft^{2}\), \(\sigma = 1.714\times 10^{-9}\,\frac{BTU}{h\cdot ft^{2}\cdot R^{4}}\), \(T_{s} = 554.07\,R\) and \(T_{b} = 527.67\,R\), then the heat transfer rate due to electromagnetic radiation is:
\(\dot Q = (0.90)\cdot (16.188\,ft^{2})\cdot \left(1.714\times 10^{-9}\,\frac{BTU}{h\cdot ft^{2}\cdot R^{4}} \right)\cdot [(554.07\,R)^{4}-(527.67\,R)^{4}]\)
\(\dot Q = 417.492\,\frac{BTU}{h}\)
Under the consideration of steady heat transfer we find that the net energy transfer from the student's body during the 20 min-ride to school is:
\(Q = \dot Q \cdot \Delta t\) (2)
Where \(\Delta t\) is the heat transfer time, measured in hours.
If we know that \(\dot Q = 417.492\,\frac{BTU}{h}\) and \(\Delta t = \frac{1}{3}\,h\), then the net energy transfer is:
\(Q = \left(417.492\,\frac{BTU}{h} \right)\cdot \left(\frac{1}{3}\,h \right)\)
\(Q = 139.164\,BTU\)
The net energy transfer from the student's body during the 20-min ride to school is 139.164 BTU.
The monthly output of a certain product is Q(x)=2500x 5/2
where x is the capital investment in millions of dollars. Find dQ/dx, which can be used to estimate the effect on the output if an additional capital investment of $1 million is made. dQ/dx=
Answers
The monthly output of a certain product can be given by the function
\(`Q(x) = 2500x^(5/2)`\)
where x is the capital investment in millions of dollars.
differentiate the function Q(x) with respect to x.
\(dQ/dx = d/dx(2500x^(5/2))\)
Using the power rule of differentiation, we have:
\(dQ/dx = (5/2) * 2500 * x^(5/2 - 1)dQ/dx
= 6250x^(3/2) `dQ/dx
= 6250x^(3/2)`\)
which gives us the effect on the output if an additional capital investment of $1 million is made.
Note: To estimate the effect on the output if an additional capital investment of $1 million is made, we substitute x with x+1 in the expression for `dQ/dx`. This gives us the new output and the increase in output due to the additional investment.
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why a hard disk called a random access stroage device
Answers
RAM is called “random access” because any storage location on the computer can be accessed directly (as opposed to randomly).
Calculate the steady state flux of atomic hydrogen at 25°C through a steel vessel of wall thickness 4 mm given that the inside surface is kept saturated with hydrogen at a concentration of 4.5 moles/m3, the outside surface is exposed to the atmosphere. (The diffusivity of hydrogen in steel D0 = 0.1 mm2 s-1, Q = 13.5 kJ mol-1) A steady-state flux allows the application of Fick’s first law: J = -D(dC/dx)
If the vessel contains 20 moles of hydrogen, calculate the time taken to dissipate all of the hydrogen of that the vessel has a surface area of 3 m2.
Answers
Answer:
To calculate the steady state flux of atomic hydrogen through a steel vessel, we need to use Fick's first law, which states that the flux (J) is equal to the diffusivity (D) multiplied by the concentration gradient (dC/dx).
First, we need to calculate the concentration gradient by dividing the difference in hydrogen concentration between the inside and outside surfaces by the wall thickness of the vessel. The inside surface is kept saturated with hydrogen at a concentration of 4.5 moles/m3, and the outside surface is exposed to the atmosphere, which has a hydrogen concentration of 0 moles/m3. Therefore, the concentration gradient is (4.5 - 0) moles/m3 / (4 mm) = 1.125 moles/m3 mm.
Next, we need to substitute this value into Fick's first law along with the diffusivity of hydrogen in steel, which is given as 0.1 mm2/s. This gives us the steady state flux as J = (-0.1 mm2/s) * (1.125 moles/m3 mm) = -0.01125 moles/s mm2.
Finally, we need to convert the units of the flux from moles/s mm2 to moles/s m2. To do this, we can multiply the flux by 1,000 to convert the units of millimeters to meters, giving us a final steady state flux of -0.01125 moles/s mm2 * 1,000 = -1.125 moles/s m2.
IF THE VESSEL CONTAINS 20 MOLES OF HYDROGEN, CALCULATE THE TIME TAKEN TO DISSIPATE ALL OF THE HYDROGEN OF THAT THE VESSEL HAS A SURFACE AREA OF 3 M2.
To solve this problem, we need to first calculate the flux of atomic hydrogen through the vessel using Fick's first law:
J = -D(dC/dx)
where J is the flux, D is the diffusivity of hydrogen in steel, and dC/dx is the concentration gradient.
Given that the diffusivity of hydrogen in steel is 0.1 mm2/s, the inside concentration is 4.5 moles/m3, and the outside concentration is 0, the concentration gradient is 4.5 moles/m3.
Plugging these values into the equation above, we get:
J = -0.1 mm2/s * 4.5 moles/m3 = -0.45 moles/s-m2
Next, we need to calculate the time it takes to dissipate all 20 moles of hydrogen from the vessel. We can do this by dividing the total number of moles of hydrogen by the flux:
t = 20 moles / (-0.45 moles/s-m2) = 44.44 s
So it would take approximately 44.44 seconds to dissipate all of the hydrogen from the vessel.
Explanation:
SELF EXPLANATORY
The time taken is 44.44 seconds to dissipate all of the hydrogens from the vessel.
How to calculate the time?To solve this problem, we need to first calculate the flux of atomic hydrogen through the vessel using Fick's first law:
J = -D(dC/dx)
where J is the flux, D is the diffusivity of hydrogen in steel, and dC/dx is the concentration gradient.
Given that the diffusivity of hydrogen in steel is 0.1 mm²/s, the inside concentration is 4.5 moles/m³ and the outside concentration is 0, the concentration gradient is 4.5 moles/m³.
Plugging these values into the equation above, we get:
J = -0.1 mm²/s * 4.5 moles/m³ = -0.45 moles/s-m²
Next, we need to calculate the time it takes to dissipate all 20 moles of hydrogen from the vessel. We can do this by dividing the total number of moles of hydrogen by the flux:
t = 20 moles / (-0.45 moles/s-m2) = 44.44 s
So it would take approximately 44.44 seconds to dissipate all of the hydrogen from the vessel.
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64º26’18’’ + 195º57’12,75’’ – 100º55’35’’
Answers
Answer:
I can help you with your calculation.
To add and subtract angles in degrees, minutes, seconds (DMS) form, you need to follow these steps12:
Align the angles so that the degrees, minutes, and seconds are in the same column.
Add or subtract the seconds first. If the result is more than 60 or less than 0, adjust the minutes accordingly.
Add or subtract the minutes next. If the result is more than 60 or less than 0, adjust the degrees accordingly.
Add or subtract the degrees last.
Using this method, your calculation can be done as follows:
64º26’18’’ + 195º57’12,75’’ – 100º55’35’’ = 64º26’18’’ + 195º57’12.75’’ – 100º55’35’’ = 159º83’30.75’’ – 100º55’35’’ = 159º83’(30.75 - 35)’’ – 100º55’0’’ = 159º82’55.75’’ – 100º55’0’’ = 159º(82 - 55)’55.75’’ – 100º0’0’’ = 159º27’55.75’’ – 100º0’0’’ = (159 - 100)º27’55.75’’ = 59º27’55.75’’
Therefore, the answer is 59º27’55.75’’. I hope this helps!
Explanation:
Which of the following options is correct about word embeddings presented in the lecture. A) The goal of word embeddings is to increase the sparsity of the encoded input word features B) We would like similar words to have word embeddings that are far apart in order to minimize word sense disambiguation C) One way to learn word embeddings is by maximizing cosine similarity between words with related meaning. D) To do a good job, word embeddings have to manually encoded by a natural language domain expert
Answers
The correct option about word embeddings presented in the lecture is C) One way to learn word embeddings is by maximizing cosine similarity between words with related meaning.
Word embeddings are a way to represent words as vectors of real numbers in a high-dimensional space. The goal of word embeddings is to capture the semantic meaning of words, allowing for better natural language processing tasks such as language translation and sentiment analysis.
To learn word embeddings, one common approach is through the use of neural networks. Specifically, a neural network is trained to predict the context of a given word, such as the surrounding words in a sentence. The weights of the neural network are then used as the word embeddings.
One way to maximize the effectiveness of word embeddings is by optimizing the cosine similarity between words with related meaning. Cosine similarity measures the cosine of the angle between two vectors, which can be used to determine how similar two words are in meaning. By optimizing cosine similarity, word embeddings can better capture the relationships between words, such as synonyms and antonyms.
It is important to note that word embeddings are typically learned automatically, without the need for manual encoding by a natural language domain expert. This is because the neural network is able to learn the relationships between words based on the context in which they appear, without the need for explicit rules or definitions.
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