With an initial velocity of 5 m/s at angle of 45 defree. how far will she trvael in air horizntally before she alnds?
Answers
With an initial velocity of 5 m/s at angle of 45 degree, the distance she would travel in air horizontally before she lands is approximately 2.551 meters.
To determine the horizontal distance traveled by the object in the air before it lands, we can use the equations of motion. Assuming no air resistance and a flat horizontal surface, we can calculate the horizontal range.
Given:
Initial velocity (v₀) = 5 m/s
Launch angle (θ) = 45 degrees
The horizontal range (R) can be calculated using the formula:
R = (v₀² * sin(2θ)) / g
where g is the acceleration due to gravity, which is approximately 9.8 m/s².
Substituting the given values:
R = (5² * sin(2 * 45)) / 9.8
R = (25 * sin(90)) / 9.8
Since sin(90) equals 1, the equation simplifies to:
R = (25 * 1) / 9.8
R = 2.551 m
Therefore, the object will travel approximately 2.551 meters horizontally before it lands.
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Related Questions
Consider mechanical energy to find the coefficient of friction between the sledge and the ground
Answers
Answer:
0.08
Explanation:
We can represent the situation with the following figure
Now, by the conservation of energy, we can write the following equation
\(\begin{gathered} K_i+U_i-Wnc=K_f \\ \frac{1}{2}mv_i^2+mgh-F_fd=\frac{1}{2}mv_f^2 \end{gathered}\)Where m is the mass, vi is the initial velocity, g is the gravity, h is the height, Ff is the force of friction, d is the distance traveled by the sledge, and vf is the final velocity.
Using the free body diagram, we get that the force of friction is equal to
\(\begin{gathered} F_n=mg\sin60 \\ \text{ Then} \\ F_f=\mu F_n \\ F_f=\mu mg\sin60 \end{gathered}\)Now, we can replace the expression for Ff in the equation above and solve for the coefficient of friction μ
\(\begin{gathered} \frac{1}{2}mv_i^2+mgh-(\mu mg\sin60)d=\frac{1}{2}mv_f^2 \\ \\ \frac{1}{2}v_i^2+gh-\mu gd\sin60=\frac{1}{2}v_f^2 \\ \\ \mu gd\sin60=\frac{1}{2}v_i^2+gh-\frac{1}{2}v_f^2 \\ \\ \mu=\frac{1}{gd\sin60}(\frac{1}{2}v_i^2+gh-\frac{1}{2}v_f^2) \\ \end{gathered}\)Replacing g = 9.8 m/s², d = 16 m, vi = 3 m/s, h = 8 m, and vf = 12 m/s, we get
\(\begin{gathered} \mu=\frac{1}{(9.8)(16)\sin60}(\frac{1}{2}(3)^2+(9.8)(8)-\frac{1}{2}(12)^2) \\ \\ \mu=0.08 \end{gathered}\)Therefore, the coefficient of friction is 0.08
Challenge question: An arrow is placed at 3 centimeters to the left of a converging lens. The image appears at 3 centimeters to the right of the lens. What is the focal length of this lens? (HINT: Place a dot to the right of the lens where the image of the tip of the arrow will appear. You will only be able to draw lines 1 and 2. Where does line 1 cross the principal axis if the image appears at 3 centimeters?)
Answers
The focal length of the converging lens based on the arrow placed 3 centimeters to the left and the imaged formed 3 cm to the right is 1.5 cm.
Focal length of the converging lensThe focal length of the converging lens is determined by applying the following converging lens formula.
1/f = 1/v + 1/u
where;
v is the image distance = 3 cmu is the object distance = 3 cmf is the focal length = ?1/f = 1/3 + 1/3
1/f = 2/3
f = 3/2
f = 1.5 cm
Thus, the focal length of the converging lens is 1.5 cm.
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Which of the following choices most accurately describes the behavior of the waves when they encounter the second medium?
a) Some of the waves were reflected while some were refracted. The refracted waves must have moved into a less dense medium since they refracted away from the normal. The reflected wave bounces off in a new direction at an equal angle, obeying the law of reflection.
b) Some of the waves reflect while other refract. The refracted waves must have moved into a denser medium since they refracted towards the normal. The reflected wave bounces off in a new direction at an equal angle, obeying the law of reflection.
c) Some of the waves reflect while other refract. The refracted waves must have moved into a denser medium since they refracted towards the normal. The reflected wave bounces off in a new direction at an equal angle, but does not follow the law of reflection since some of the waves were refracted.
d) Some of the waves were reflected while some were refracted. The refracted waves must have moved into a denser medium since they refracted away from the normal. The reflected wave bounces off in a new direction at an equal angle, obeying the law of reflection.
Answers
While some waves refract, others reflect. Since the refracted waves reacted in the direction of the normal, they must have gone into a denser material. The reflected wave obeys the law of reflection by bouncing off in a new direction at an equal angle. The right response is (b).
The two outcomes that can occur when waves collide with a barrier between two mediums with varying densities are accurately described by this statement.
Refraction and reflection are two different types of wave action. If the waves refract in the direction of the normal, they will go into a denser material.
The law of reflection, which stipulates that the angle of incidence is equal to the angle of reflection with regard to the normal at the point of reflection, is another principle that the reflected wave abides by.
Therefore, option (b) is the one that should be chosen.
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The unit of pressure known as the pascal is equal to:________
Answers
The unit of pressure known as pascal is equal to 1 Newton / (metre)^2
It is the pressure exerted by a force of 1 newton , which is applied on an area of 1 metre square.
1 pascal pressure means that 1 newton force is equally distributed over an area of 1 metre square .
It is a small unit used for low pressures.
Pascal is denoted by the symbol Pa
It is derived from the formula pressure = force / area.
When the state is being changes from gas to liquid through the process of condensation, the temperature...
*
(A) Increases
(B) Decreases
(C) Remains constant
(D) May increase or decrease
Answers
When the state is being changes from gas to liquid through the process of condensation, the temperature remains constant. That is option C.
What is condensation?Condensation is defined as the type of phase change of matters where by gaseous substances changes to a liquid state and this is exactly the opposite of evaporation.
Examples of condensation include the following:
Water droplets on the inside of windows.Dew on grass.A foggy mirror.Reading glasses fogging up.Water droplets on the outside of your cold drink.The temperature remains constant during condensation because the extra heat is utilized in changing the phase of state of matter.
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What type of energy is stored in the nucleus of an atom?
Answers
Answer:
Nuclear energy
Explanation:
The nucleus holds the energy together
Which event occurs during high tide?
a) All of Earth’s ocean levels rise.
b) The moon’s orbit is closer to Earth.
c) The gravity of the Sun and moon cause the Earth’s crust and water to bulge.
d) Earth’s crust and water are being pulled in opposite directions by the Sun and moon.
Answers
The moon’s orbit is closer to Earth is the event which occurs during high tide.
PerigeeThis occurs once in a month and is the phenomenon in which the moon is
closest to the Earth. This brings about an increase in the tide levels of the
water bodies.
This is the reason why the option B is the most appropriate option as the
moon’s orbit being closer to Earth also signifies a close proximity between
the moon and the earth
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Answer: The answer is: b) The moon’s orbit is closer to Earth.
Explanation: I have my ways :>
Have a great day!
-Sunny
A snowboarder is sliding back and forth on a half pipe at one point she leaves the top of the half pipe and slides to the other side choose when kinetic energy increases during the snowboarders ride
Answers
Answer:
he kinetic energy increases on the descent, being maximum at the lowest point of the trajectory.
Explanation:
In these semicircular sections the skaters slide from one side to the other, in the downward path their kinetic energy increases and their potential energy decreases; When it leaves the ramp and is in the air, the kinetic energy decreases rapidly, up to the point of maximum height where the kinetic energy is zero.
Consequently, the kinetic energy increases on the descent, being maximum at the lowest point of the trajectory.
Which athelete broke two world records twice this year?
Answers
Answer:
Michael
Explanation:
a 2 kg solid ball (solid like a bowling ball) is rolling down a horizontal street at 7.5 m/s. what is its total kinetic energy? note: you can find moments of inertia in the reading.
Answers
Thus, the total kinetic energy of the solid ball rolling down the horizontal street at 7.5 m/s is 78.75 J.
To calculate the total kinetic energy of the solid ball, we need to use the formula:
KE = 0.5 * I * w^2
where KE is the kinetic energy, I is the moment of inertia, and w is the angular velocity.
Since the ball is rolling down a horizontal street, it has both translational and rotational kinetic energy. To find the total kinetic energy, we need to add these two energies together.
The translational kinetic energy is given by:
KE_t = 0.5 * m * v^2
where m is the mass of the ball and v is its velocity. Plugging in the values given in the question, we get:
KE_t = 0.5 * 2 kg * (7.5 m/s)^2 = 56.25 J
To find the rotational kinetic energy, we need to calculate the moment of inertia of the solid ball. According to the reading, the moment of inertia of a solid sphere is:
I = 2/5 * m * r^2
where r is the radius of the sphere. Since the question doesn't give us the radius of the ball, we can't calculate the moment of inertia directly. However, we can use the fact that the ball is rolling without slipping to relate its linear velocity to its angular velocity.
The relationship between linear velocity and angular velocity is:
v = r * w
where v is the linear velocity, r is the radius, and w is the angular velocity. For a rolling ball, the linear velocity at the bottom of the ball is equal to the angular velocity times the radius:
v = r * w = 7.5 m/s
This allows us to find the radius of the ball:
r = v / w = 7.5 m/s / w
Now we can use the moment of inertia formula to find the rotational kinetic energy:
KE_r = 0.5 * I * w^2 = 0.5 * 2/5 * m * r^2 * (v / r)^2 = 0.2 * m * v^2
Plugging in the values given in the question, we get:
KE_r = 0.2 * 2 kg * (7.5 m/s)^2 = 22.5 J
Finally, we can find the total kinetic energy by adding the translational and rotational kinetic energies:
KE_total = KE_t + KE_r = 56.25 J + 22.5 J = 78.75 J
Therefore, the total kinetic energy of the solid ball rolling down the horizontal street at 7.5 m/s is 78.75 J.
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Naim Suleimanoglu of Turkey has a mass of about 62 kg, yet he can lift
nearly 3 times this mass. (This feat has earned Suleimanoglu the nick-
name of "Pocket Hercules.") If the potential energy associated with a
barbell lifted 1.70 m above the floor by Suleimanoglu is 3.04 x 10³ J,
what is the barbell's mass?
Answers
According to the problem The barbell's mass is 178 kg.
What is barbell's mass ?
The mass of a barbell can vary depending on the size and type of barbell. Standard barbells typically range from 10 kilograms (22 pounds) to 45 kilograms (99 pounds). Olympic barbells are typically 25 millimeters (1 inch) in diameter and are available in weights ranging from 15 kilograms (33 pounds) to 25 kilograms (55 pounds). Barbells with a smaller diameter, such as a women's barbell, usually weigh between 5 kilograms (11 pounds) and 15 kilograms (33 pounds). Powerlifting barbells are thicker and longer than standard barbells and usually weigh between 20 kilograms (44 pounds) and 25 kilograms (55 pounds).
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Where did all the golden carals go?
Answers
Answer:
Thanos went *snap*
Explanation:
In beams with circular cross sections, transverse shear stress acts parallel to the y axis over the entire depth of the shape.
a. true
b. false
Answers
The given statement is that in beams with circular cross-sections, transverse shear stress acts parallel to the y axis over the entire depth of the shape.
The tension that develops as a result of the internal shearing of a beam as a result of a shear force applied to the beam is known as shearing stress.
One-half of the difference between the primary stresses is the maximum shear stress. It should be noticed that the primary planes equation, 2p, results in two angles between 0° and 360°.
The primary stresses brought on by bending are typical tension and compression stresses. However, the state of stress within the beam also includes large normal stresses caused by bending in addition to shear stresses caused by the shear force, even though the former is often of a lesser order than the latter.
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Provw that fliw of heat ofhot to cold body increses etropy system
Answers
The flow of heat from a hot body to a cold body increases the entropy of the system. This phenomenon is explained by the second law of thermodynamics.
According to the second law of thermodynamics, the entropy of an isolated system tends to increase over time. Entropy is a measure of the disorder or randomness within a system. When heat flows from a hot body to a cold body, it naturally tends to spread out and distribute itself more evenly, resulting in an increase in entropy.
When heat is transferred, it moves from a region of higher temperature (hot body) to a region of lower temperature (cold body) until thermal equilibrium is reached. This transfer of heat occurs spontaneously in the direction that increases the entropy of the system. The increased entropy arises from the greater number of microstates available to the system when the heat is distributed across a larger number of particles.
By obeying the second law of thermodynamics, the flow of heat from a hot body to a cold body increases the overall disorder or randomness within the system, leading to an increase in entropy.
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he functional unit of the kidney is the .
Answers
Answer:
maintaining overall fluid balance regulating and filtering minerals from blood filtering waste materials from food, medications, and toxic substances.
Explanation:
Answer: Nephrons
Explanation: The structural and functional unit of the kidney is known as nephrons. These are microscopic structures found in the kidneys.
A healthy adult has 0.8 to 1.5 million nephrons in the kidney of a adult. Its main function is filtration of the blood.
Blood is filtered and the impurities are collected to excrete out of the body in the form of urine.
The Carson family's pancake recipe uses 2 teaspoons of baking powder for every 1/3 of a teaspoon of salt. How much baking powder would they need if they used 1 teaspoon of salt?
Answers
Answer:
6 teaspoons of baking powder required.
Explanation:
Given that
According to the recipe of pancake,
For every \(\frac{1}{3}\) teaspoon of salt, 2 teaspoons of baking baking powder is required.
To find:
How much baking powder will be needed, if 1 teaspoon of salt was used ?
Solution:
This problem can be solved using ratio.
\(\frac{1}3\) teaspoon of salt : 2 teaspoons of baking powder
Let us multiply the above ratio with 3.
\(\frac{1}{3}\times 3\) teaspoon of salt : 2 \(\times\) 3 teaspoons of baking powder
OR
1 teaspoon of salt : 6 teaspoons of baking powder
So, answer is 6 teaspoons of baking powder required.
Also, we can use the unitary method:
\(\frac{1}3\) teaspoon of salt needs = 2 teaspoons of baking powder
1 teaspoon of salt needs = \(\frac{2}{\frac{1}3}\) teaspoons of baking powder
1 teaspoon of salt needs = 2 \(\times\) 3 = 6 teaspoons of baking powder needed
So, the answer is:
6 teaspoons of baking powder required.
Answer:
6 teaspoons of baking powder
Explanation:
This is a simple ratio question.
Every 1/3 of a teaspoon of salt requires 2 teaspoons of baking powder.
Therefore, 1 teaspoon of salt will require:
= 1 x 2/1/3
= 2 x 3 = 6 teaspoons of baking powder
Hence, 6 teaspoons of baking powder would be needed if they had used 1 teaspoon of salt.
How many oxygens are in a pentoxide?
Answers
Answer:
four oxygen
Explanation:
10 kg of R-134a fill a 1. 115-m3 rigid container at an initial temperature of –30°C. The container is then heated until the pressure is 200 kPa. Determine the final temperature and the initial pressure. Use data from the steam tables
Answers
Gas has a final temperature of 273.6 K and a starting pressure of 177.6 kPa.
R-134a is 1,1,1,2-tetrafluoroethane, as is well known.
Using the ideal gas formula:
PV =nRT PV = w/M RT, where P = gas pressure =? and V = gas volume = 1.115 m3.
T = gas temperature (-30°C) = 273 + (-30) = 243K
R is 8.314 m3 Pa/mole, which is the gas constant. M = molar mass of R-134a gas = 102.03g/mole K = mass of gas = 10 kg = 10,000 g
When you plug in all the values provided, you get the ideal gas equation: P = 1.115m3 = 10000 g/102.03 g/mole 8.314 m3 Pa/mole. 177587.9687 Pa = 177.6 kPa = K 243K P
Consequently, the gas's starting pressure is 177.6 kPa.
We now need to determine the gas's final temperature.
Gay-Law Lussac states that for constant volume and number of moles, the pressure of a gas is precisely proportional to its temperature.
P∝T
P1/T1 = P2/T2
where
P1 is the initial pressure of gas = 177.6 kPa
P2 is the final pressure of gas = 200 kPa
T1 is the initial pressure of gas = ?
T2 is the final pressure of gas =
177.6 kPa/243K = 200 kPa/T2
T2 = 273.6 K
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8. in a hall experiment, a current of 25 a is passed through a long foil of ag, which is 0.1 mm thick and 3mm long. calculate the hall voltage produces across the width by a flux of 1.4 w/m2. if the conduction of ag is 6.8x10mho/m. estimate the mobility and hall coefficient.
Answers
The mobility and hall coefficient willl be 57.7 ×10⁻⁴ and 29.41 ×10⁻⁶ v.
What is electric current?Electric current is defined as the ratio of the charge flow in a given time interval. It is denoted by I. It has the unit is ampere.
Given data;
Electric current,I= 25 A
Thickness = 0.1 mm
Length = 3 mm
Flux = 1.4 w/m²
The charge density is found as;
\(\rm \rho =- \frac{1}{R_H} \\\\ \rho = 0.119 \times 10^{11} C/m^3\)
The value of the hall voltage is;
\(\rm V_H = BVd \\\\ V_H = B \frac{I}{\rho dt} d \\\\ V_H = \frac{BI}{\rho t } \\\\ V_H = \frac{0.14 \times 25 }{0.119 \times 10^{11} \times 0.1 \times 10^{-3}} \\\\ V_H = \frac{3.5 }{0.119 \times 10^7} \\\\ V_H = 29.41 \times 10^{-6} \ v\)
The mobility of electrons is;
\(\rm \mu_e = \frac{\rho}{n_e}\\\\ \mu_e = \frac{6.848 \times 10^7}{13.5 \times 10^{-30}\times 1.607 \times 10^{-19}} \\\\ \mu_e = 57.7 \times 10^{-4}\)
Hence the mobility and hall coefficient willl be 57.7 ×10⁻⁴ and 29.41 ×10⁻⁶ v.
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calculate the time taken to raise the temperature of 1.5 kg of water in a kettle from 15°C to 100°C given that specific heat capacity of water is 4200 J/kg/K and the heater is rated 250V , 2kW
Answers
Answer:
270 s or 4.5 min
Explanation:
First find the amount of heat needed:
q = mCΔT
q = (1.5 kg) (4200 J/kg/K) (100 − 15) K
q = 535,500 J
q = 535.5 kJ
Power is energy per time.
P = E / t
2 kW = 535.5 kJ / t
t = 270 s
Is the gravity on the moon and earth the same and why are they the same or different
Answers
HEY can anyone tell me the Atomic Mass of Helium and also what ever the number u get pls round it!!
Answers
Answer:
Hey!
Your answer is that the ATOMIC MASS of Helium is 4 u ROUNDED to 2 decimal places!
Explanation:
The precise amount is 4.002602 u.
I HOPE THIS HELPED YOU! :DQUESTION 17
Which statement best describes the difference between strong nuclear forces and weak nuclear forces? (2 points)
O Weak nuclear forces are involved when certain types of atoms break down. Strong nuclear forces are responsible for
holding atoms' nucleus together.
O Weak nuclear forces hold bonds between atoms together. Strong nuclear forces hold together the nucleus of an
atom,
O Strong nuclear bonds prevent atoms from falling apart. Weak nuclear bonds prevent compounds from falling apart.
O Strong nuclear forces are involved in breaking electrons from their shells. Weak nuclear forces hold protons in the
nucleus.
Answers
Answer: Weak nuclear forces are involved when certain types of atoms break down. Strong nuclear forces are responsible for holding atoms' nucleus together.
A particle is moving along a circular path of radius 2m and with a uniform speed of 6m/s. What will be the average acceleration when the particle completes half revolution
Answers
Average acceleration when the particle completes half revolution is 18 m/s^2.
What is centripetal acceleration?If you whirl a ball on the string over your head, then the ball is undergoing centripetal acceleration. If you drive a car around in circle, then your car is undergoing centripetal acceleration.
The average acceleration of a particle moving in a circular path is given by the formula: a = v^2/r, where v is the velocity of the particle and r is the radius of the circular path.
For the given particle, the velocity is 6 m/s and the radius is 2m. Therefore, the average acceleration is given by a = v^2/r = 6^2/2 = 18 m/s^2.
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Temperature and Location Data for Leadville and Kansas City
Leadville, Colorado Kansas City, Missouri
Latitude 39.2°N 39.1°N
Elevation 3,094 m 277 m
Average Yearly High Temperature 5°C 22°C
Leadville, Colorado is at almost the same latitude as Kansas City, Missouri. However, the two cities have different elevations and average yearly high temperatures.
Based on the information in the table, average yearly high temperature _______ as elevation _______.
A.
stays the same; decreases
B.
decreases; increases
C.
increases; increases
D.
decreases; decreases
Answers
Average yearly high temperature decreases as elevation increases.
What is the likely reason for the difference in average yearly high temperatures between Leadville and Kansas City?The difference in elevation between the two cities results in a difference in atmospheric pressure and thus a difference in temperature.
What effect would a decrease in latitude have on the average yearly high temperatures of Leadville and Kansas City?A decrease in latitude would likely increase the average yearly high temperatures of both cities due to the increased amount of solar radiation they receive.
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Bronco the skydiver, whose mass is 80 kg experiences 200 N of air resistance and gravity pulls on him with 800 N What is the acceleration of his fall?
Answers
Bronco the skydiver, whose mass is 80 kg experiences 200 N of air resistance and gravity pulls on him with 800 N. The acceleration of his fall 7.5 m/sec².
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
To find the acceleration,
F = mg
F = 80.(10)
F = 800 N
air resistance = 200 N
Net force = F - air resistance
= 800 - 200
= 600 N
600 = mass . acceleration
600 = 80 . acceleration
acceleration = 7.5 m/sec²
Bronco the skydiver, whose mass is 80 kg experiences 200 N of air resistance and gravity pulls on him with 800 N. The acceleration of his fall 7.5 m/sec².
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summarize how many methods can be used to determine the index of refraction of an optical material
Answers
Accurate determination of the index of refraction is important for many applications in optics and photonics, including lens design, fiber optics, and semiconductor processing.
There are several methods that can be used to determine the index of refraction of an optical material. One common method is to use a spectrometer to measure the angle of refraction as light passes through the material at various wavelengths. Another method involves measuring the critical angle at which total internal reflection occurs, which can be used to calculate the index of refraction. A third method is to use a prism to separate the different wavelengths of light and measure the angle at which each color is refracted. Other techniques include ellipsometry, interferometry, and polarimetry.
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4) A football player starts at the 40-yard line, and runs to the 25-yard line in 2 seconds.
a) What is their speed during that run?
b) What is their velocity?
I
c) If they kept running at that velocity for another 1.3 seconds, what would their
final position be?
Answers
Answer:
(a). Their speed during that run is 10 m/s.
(b). Their velocity is 6.86 m/s
(c). The final position is at 8.91 m.
Explanation:
Given that,
A football player starts at the 40-yard line, and runs to the 25-yard line in 2 seconds.
Suppose, the distance between 40 yard line and 25 yard line is 20 yard.
(a). We need to calculate their speed during that run
Using formula of speed
\(v=\dfrac{d}{t}\)
Where. d = distance
t = time
Put the value into the formula
\(v=\dfrac{18.288}{2}\)
\(v=10\ m/s\)during that run
(b). We need to calculate their velocity
Using formula of speed
\(v=\dfrac{\Delta d}{\Delta t}\)
Put the value into the formula
\(v=\dfrac{22.86-36.58}{2}\)
\(v=-6.86\ m/s\)
Negative sign shows the direction of motion.
(c). If they kept running at that velocity for another 1.3 seconds,
We need to calculate the final position
Using formula of position
\(d=vt\)
Put the value into the formula
\(d=6.86\times1.3\)
\(d=8.91\ m\)
Hence, (a). Their speed during that run is 10 m/s.
(b). Their velocity is 6.86 m/s
(c). The final position is at 8.91 m.
a 25-g ball is released from rest 80 m above teh surface of the earth. during the fall the total thermal energy of the ball and air increases by 15 j. just before it hits the surface its speed is.
Answers
The speed of the ball just before it hits the surface is 20m/s.
Here we have to find the speed of the ball just before it hit the surface.
So,
Mass of the ball = 25g = 0.025kg
Height from which it falls (h) = 80m
Thermal energy (E) = 15J
Now initial energy of the system is
\(E_{i}\) = mv²/r + mgh
The initial velocity is zero
Therefore \(E_{i}\) = mgh = 20J
Now the final energy of the system is:
\(E_{f}\) = mv²/r + mgh + 15
h = 0 as we have to find the speed when it hit the surface.
\(E_{f}\) = mv²/2 + 15
= 0.025 v² /2 + 15
As there is no external force applied
So the total energy of the system will be constant,
By conservation of energy:
\(E_{i}\) = \(E_{f}\)
20 = 0.025 v²/2 + 15
0.025v² = 10
v = 100/5
v = 20 m/s
Therefore the speed of the ball when it hit the surface is 20m/s.
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Can someone help me label this flower??
Answers
Hope this helps!!!!!!!!!!!!!
