with increase in altitude the pressure of atmosphere is

​

Answer:

a) \(W_{Mercury}=92.5 N\)

b) \(W_{Mars}=92.8 N\)

c) \(W_{Saturn}=261.0 N\)

d) \(W_{Pluto}=15.5 N\)

Explanation:

First of all, we need to remember the value of gravity acceleration on each planet.

\(g_{Mer}=3.70 m/s^{2}\)

\(g_{Mar}=3.71 m/s^{2}\)

\(g_{Sat}=10.44 m/s^{2}\)

\(g_{Plt}=0.62 m/s^{2}\)

The definition of weigh is the product between the mass and the gravity acceleration, therefore we will have:

a) \(W_{Mercury}=25*3.70=92.5 N\)

b) \(W_{Mars}=25*3.71=92.8 N\)

c) \(W_{Saturn}=25*10.44=261.0 N\)

d) \(W_{Pluto}=25*0.62=15.5 N\)

I hope it helps you!

Answer:

No.

Explanation:

The atmosphere is made mostly of gases. Mainly nitrogen and oxygen. That's a nice suggestion though.

No, the co-efficient of friction cannot have a value such that a skier would be able to slide uphill at a constant velocity.

The co-efficient of friction represents the amount of resistance to motion between two surfaces in contact. When moving uphill, the force of gravity is acting against the skier's motion, which increases the frictional force. In order to maintain a constant velocity, the force of the skier pushing forward would have to match the force of friction, but with an increased frictional force, it would require a greater force from the skier to maintain that velocity. Therefore, it is not possible for a skier to slide uphill at a constant velocity due to the increased co-efficient of friction.
The answer is no, the coefficient of friction cannot have a value that would allow a skier to slide uphill at a constant velocity. The coefficient of friction is a measure of the resistance between two surfaces, in this case, the skis and the snow. When sliding uphill, the skier must overcome both friction and the gravitational force pulling them downhill. To slide uphill at a constant velocity, an external force would need to be applied, such as pushing or propelling themselves uphill. The coefficient of friction cannot be adjusted to overcome the force of gravity without an external force being applied.

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Answer:

turning on the lights

using my phone

using the microwave

If a batter hits a baseball with an exit velocity of 50 m/s at a launch angle of 40 degrees if the fence is 175 meters from the batter, Yes he would be able to hit a home run.

It can be defined as the motion of any object or body when thrown from the earth's surface and follows any curved path under the effect of the gravitational force of the earth.

As given in the problem, a batter hits a baseball with an exit velocity of 50 m/s at a launch angle of 40 degrees if the fence is 175 meters from the batter

The horizontal distance covered by the ball = u²sin2θ / g

                                                                        = 50²×sin80 / 9.81

                                                                        =250.97 meters

Thus, the horizontal distance covered by the baseball would be greater than 175 meters, therefore he would be able to hit the home run.

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Answer:

The momentum of the steel ball is 0.28 kg m/sec.

Explanation:

The momentum of an object can be calculated using the formula: momentum = mass x velocity. In this case, the mass of the steel ball is 100 g, which is equivalent to 0.1 kg. The velocity of the ball is 2.8 m/sec. Plugging in the values into the formula, we get:

momentum = 0.1 kg x 2.8 m/sec

momentum = 0.28 kg m/sec

So the momentum of the steel ball is 0.28 kg m/sec.

Answer

As the angle of incidence increases in Figure 2.8, a point is finally reached where the refracted ray does not emerge at the second layer but lie along the interface. This particular angle of incidence at which the angle of refraction is 90° and the refracted ray lies along the interface is known as the critical angle. At and beyond the critical angle, there is no transmitted ray and therefore a very high reflected ray will be recorded .

Therefore,

sinθisin90=Vp1Vp2

But, sin 90 = 1.

At critical angle,

sinθcritical=Vp1Vp2

A critical refracted wave travels along the interface between layers and is refracted back into the upper layer at the critical angle. The waves refracted back into the upper layer are called head waves or first-break refractions because at certain distances from a source, they are the first arriving energy. Recorded first-break refraction is shown in Figure 2.10.

Note that these first-break refractions can give us important information about the shallow velocities on land seismic data.

Note also that seismic data are acquired in such a way that reflections from horizons of interest are in the pre-critical region, even at the farthest offset in the data.

In reality, part of the seismic energy arriving at an interface is transmitted and refracted, and another part of the energy is reflected at that same interface. Given that there are many reflectors in the subsurface, there will be many paths from source to receiver, each of them with a different travel time. The proportion of energy reflected depends on the material properties of the two bounding layers and on the angle of incidence

To calculate the gradient of the stream, we need to determine the change in elevation per unit of horizontal distance.

In this case, the stream drops 45 meters over a horizontal distance of 15 kilometers. To find the gradient, we divide the vertical drop (45 meters) by the horizontal distance (15 kilometers). However, to ensure consistent units, we convert the 15 kilometers to meters by multiplying it by 1,000 (since there are 1,000 meters in a kilometer).

So, the calculation becomes:

Gradient = Vertical drop / Horizontal distance

        = 45 meters / (15,000 meters)

        = 0.003 meters per meter

This means that for every meter of horizontal distance, the stream drops by 0.003 meters vertically. Simplifying the expression, we can also express it as 3 millimeters (mm) per meter.

Therefore, the correct answer is d) 0.003 meters per kilometer.

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Energy is NEVER destroyed making this an interesting topic. In reality this energy is just isolated from that system and just changes states. You could do anything for your story, just make sure to include those points.

Hope this helped :)

Answer:6m

Explanation:

I guessed the answer and it was right. It was not the tall ones like 16 or 150 because it only took 1.1 second

Given that,

A penny takes 1.1 seconds to hit the ground.

To find,

How high up is the window?

Solution,

When the penny is dropped, its initial velocity is equal to 0 i.e.\(u=0\). The second equation of motion is used to find the relation between position and time. The second equation of motion is :

\(s=ut+\dfrac{1}{2}at^2\)

Where

s is the distance

a is acceleration

Here, s = the height of the window from the ground and a = g i.e. acceleration due to gravity

So,

\(s=\dfrac{1}{2}gt^2\)

Put all the values,

\(s=\dfrac{1}{2}\times 9.8\times (1.1)^2\\\\s=6.05\ m\)

or

\(s=6\ m\)

Answer:

The window is \(6\ m\) high. The correct option is (d).

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The mantissa distance, which is referred to as the decimal portion of a logarithm, has a value of 0.030 in this number.

A common logarithm's integral portion is known as the characteristic, and its non-negative decimal portion is known as the mantissa. If log 39.2 equals 1.5933, then 1 is the characteristic and 5933 is the logarithm's mantissa.

The base-10 logarithm's mantissa, which represents the digits of the provided integer but not its magnitude, is a common logarithm's fractional component. For instance, both ㏒10201.3010 and                    ㏒102002.3010 have a mantissa of 0.3010.

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Answer:

Explanation:

i think this will help

Considering the coordinates of the radars as well as the direction of the object in order to determine the object's position in terms of distance and angle. Sincе thе radars arе situatеd at (0,0) and thе sеcond radar is on thе еast sidе of thе first onе, wе can assumе that thе first radar is locatеd on thе x-pivot and thе sеcond radar is locatеd on thе positivе y-hub.

Lеt's say thе objеct is dеtеctеd at coordinatеs (x, y). The objесt's y-coordinativity will be negative and its x-coordinativity positive as it approaches the southern direction in the first quadrant.

We can use the distancе formula to determine the object's diameter from its origin (0, 0):

Distancée = (x + y) 2 The angle can be calculated with trigonometry. The angle can be summarized as:

= arctan(y/x) ii) We must consider the circles of overlap for each radar in order to calculate the overlap from the radar signal intersection in the first quadrant.

Due to the fact that both radars have distinctive overlap and divide the covered area into circles, the overlapped area will be the intersection of these circles.

Thе ovеrlapping arеa can bе calculatеd by finding thе arеa of thе intеrsеction of two circlеs. The formula for the area of the intersection of two circles can be complex and depends on the specific radii and dimensions that exist between the circles' centers.

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The pressure exerted by the water at the bottom of the well is 170000 Pa.

We can use the formula for pressure due to a liquid:

pressure = density × gravity × height

where;

Assuming the density of water is 1000 kg/m³ and the acceleration due to gravity is 9.81 m/s², we can calculate the pressure at the bottom of the well as:

pressure = 1000 kg/m³ × 9.81 m/s² × 17 m

pressure = 166970 Pa

Rounding off to two significant figures, the pressure exerted by the water at the bottom of the well is 170000 Pa.

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Answer:

A

Explanation:

This is to do with convection currents :)

Hope this helps!

Answer:

500kg

Explanation:

mass = newtons/force divided by the acceleration rate

m = 30,000/60

m = 500

The correct definition of kinetic energy is that kinetic energy is the energy an object has due to its motion.

It is defined as the work needed to accelerate an object from rest to its current velocity. Kinetic energy is proportional to the mass of the object and the square of its velocity and can be calculated using the formula KE = 0.5 × m × v², where m is the mass of the object and v is its velocity.

Kinetic energy is a scalar quantity and has units of joules (J) in the SI system. It is an important concept in physics and has a wide range of applications, from understanding the motion of objects in classical mechanics to describing the behavior of particles in thermodynamics and quantum mechanics.

Therefore, The correct definition of kinetic energy is that kinetic energy is the energy an object has due to its motion.

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Velocity, acceleration, force, and displacement, have magnitude and direction (ie vector quantity) in common

This is a which have both magnitude and direction. Example include:

This is a quantity which has magnitude but no direction. Example include:

From the above, we can see that velocity, acceleration, force, and displacement, have magnitude and direction (ie vector quantity) in common

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Explanation:

PRIMERO HACES EL RECUENTO DEL TIEMPO Y LO CONVIERTES EN

SEGUNDOS Y ENTONCES

t = 227 s      \(t_{AB}\) = 227 S - 38 s = 189 s

\(t_{BC}\) = 38 s

LUEGO USANDO LA ECUACIÓN DE GALILEO GALILEI SSUPONIENDO

QUE EL MOVIL VIAJA A VELOCIDAD CONSTANTE

v = 3.50 m/189 s = 0.0185 m/s

PARA LA DISTANCIA NTRE B Y C

\(x_{BC}\) = 0.0185 m/S( 38 s) = 0.703 m

LA HORA EN QUE EL MOVIL PASA POR A ES

11:43:15 - 38 s - 189 s = 11:39:29

Answer:

Mhm mhm yes very easy

Explanation:

The answer is 12345678910 and then subtract

Mark Brainliest!

Answer: Different types of fuels have varying compositions and release different amounts of pollutants when burned. Here are some common types of fuels and the pollutants associated with them:

Fossil Fuels:

a. Coal: When burned, coal releases pollutants such as carbon dioxide (CO2), sulfur dioxide (SO2), nitrogen oxides (NOx), and particulate matter (PM).

b. Petroleum (Oil): Burning petroleum-based fuels like gasoline and diesel produces CO2, SO2, NOx, volatile organic compounds (VOCs), and PM.

Natural Gas:

Natural gas, which primarily consists of methane (CH4), is considered a cleaner-burning fuel compared to coal and oil. It releases lower amounts of CO2, SO2, NOx, VOCs, and PM.

Biofuels:

Biofuels are derived from renewable sources such as plants and agricultural waste. Their environmental impact depends on the specific type of biofuel. For example:

a. Ethanol: Produced from crops like corn or sugarcane, burning ethanol emits CO2 but generally releases fewer pollutants than fossil fuels.

b. Biodiesel: Made from vegetable oils or animal fats, biodiesel produces lower levels of CO2, SO2, and PM compared to petroleum-based diesel.

Renewable Energy Sources:

Renewable energy sources like solar, wind, and hydropower do not produce pollutants during electricity generation. However, the manufacturing, installation, and maintenance of renewable energy infrastructure can have environmental impacts.

It's important to note that the environmental impact of a fuel also depends on factors such as combustion technology, fuel efficiency, and emission control measures. Additionally, advancements in clean technologies and the use of emission controls can help mitigate the environmental impact of burning fuels.

Answer:

88

Explanation:

Answer:

2

Explanation:

88 was wrong and the answer then said 2

Answer:

35.4 cm

Explanation:

We have that when the level of mercury on either limb is the same, the pressure of the trapped air, P₁ = Atmospheric pressure

Also the initial height of the mercury in the tube = The reading of the barometer = 75.0 cm

The initial length of the air column, l₁ = 6.3 cm

The final length of the air column, l₂ = 4.2 cm (The length is expected to decrease due to compression)

The volume, V = l × A

Where;

A = The cross sectional area of the tube

Therefore, the volume of the air column is directly proportional to the length of the air column

∴ V ∝ l

According to Boyles law, we have;

P₁·V₁ = P₂·V₂

Where;

P₁ = The initial pressure in the air column before more mercury is added

V₁ = The initial volume occupied by the air in the air column

P₂, and V₂ are the final pressure and volume of the air column respectively

Given that V = l·A, we can write;

P₁·l₁·A = P₂·l₂·A

P₂ = P₁·l₁·A/(l₂·A) = P₁·l₁/(l₂) = P₁ × 6.3/4.2 = 1.5·P₁

The pressure in the air column after more mercury is added, P₂ = 1.5 × P₁

P₁ = Atmospheric pressure, therefore;

The pressure in the air column after more mercury is added, P₂ = 1.5 × Atmospheric pressure

Pressure = h·ρ·g

Where;

ρ = The density of the substance

g = The acceleration due to gravity

h = The height of the column of the fluid

Given that the density and the gravitational force, can be taken as constant, we have that the pressure of the fluid is directly proportional to the height of the fluid column

Therefore, when the pressure doubles, the height of the fluid column doubles, and when the factor of increase is 1.5, we have;

The final level of the mercury, h₂ = 1.5·h₁ = 1.5×75 cm = 112.5 cm

The initial length of the closed end of the J tube, \(h_{closed1}\) = 6.3 cm + 75 cm = 81.3 cm

The final length of the mercury in the closed end, \(h_{closed2}\) = 81.3 cm - 4.2 cm = 77.1 cm

The difference in the level of mercury, Δh = h₂ - \(h_{closed2}\)

∴ Δh = 112.5 cm - 77.1 cm = 35.4 cm

The difference in the levels of mercury in the limbs, Δh = 35.4 cm

Answer:

C. The wave only transfers energy, not matter.

Explanation:

A boat that is bumped by a wave is not actually moved to another position in the water because the wave only transfers energy, not matter.

Basically, waves can only transfer energy over a distance from one point to another without moving matter such as a boat.

This ultimately implies that, a wave can only move an energy but do not move matter.

In science, matter can be defined as anything that has mass and occupies space. Thus, any physical object that is found on earth is typically composed of matter and are generally made up of atoms.

Answer: C

Explanation:

Answer:_COC1\/2+_H\/2O>_HC1+CO\/2

Explanation:

Need help asap

The minimum distance required by the car to stop a 62.5 m.

The mass of the car is given to be 1000 kg and it is travelling at a speed of 20 the brakes are applied by the car that is producing force of 5000 Newton.

Firstly the negative acceleration produced in the car will be,

F = Ma

M is the mass of the car,

F is the force appoint by the brakes and,

a is the negative acceleration.

Putting values,

5000 = 1000(a)

a = 5m/s².

So, the negative acceleration produced by the brakes is 5m/s².

The minimum distance required by the car to stop will be given by other relation,

D = U²/2a

Where, U is the initial speed of the car,

Putting values,

D = 25×25/2×5

D = 62.5m.

So, the stopping distance of the car will be 62.5 m.

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Answer:

A

Explanation:

When a ball is rolling down a ramp, it has maximum potential energy when it is at the top, and the kinetic energy is maximum at the bottom of the ramp.

Kinetic energy is the type of energy present in a body due to the property of its motion and potential energy is the kind of energy present in a body due to the property of its state.

Kinetic energy can be easily transferred from one body to another but potential energy is not transferable. Kinetic energy is relative with respect to nature and potential energy is non-relative with respect to nature.

As the ball is rolling down a ramp, its potential energy decreases and kinetic energy increases.  The ball has the maximum potential energy when it is at the top, and this potential energy is transformed into both translational and rotational kinetic energy as it rolls down.

When the ball is at the topmost height, its gravitational potential energy is maximum and zero kinetic energy. When a ball reaches the bottom of the ramp, it will have zero potential energy and maximum kinetic energy.

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The radiation is passed through the sheets, and if they are too thick or thin, the amount of radiation that passes through changes, and a signal is sent to the sheet rollers to adjust the thickness. Option C is the correct answer.

This process is called beta attenuation or beta gauge measurement. A radioactive source, usually a beta emitter, is placed on one side of the sheet, and a detector is placed on the other side. As the sheet passes through the beta gauge, beta particles emitted by the source pass through the sheet and are detected by the detector. The amount of beta particles detected is inversely proportional to the thickness of the sheet. Hence, Option: c is correct.

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