Within the Discussion Board area, write 400-600 words that respond to the following questions with your thoughts, ideas, and comments. This will be the foundation for future discussions by your classmates. Be substantive and clear, and use examples to reinforce your ideas. Describe in detail the typical components that make up a microcontroller, including their roles, responsibilities and interaction with each other and the outside world. Be specific.
Answers
A microcontroller is comprised of various components that work together to provide processing power and control in embedded systems.
`These components include the central processing unit (CPU), memory, input/output (I/O) ports, timers/counters, and peripherals. Each component has a specific role and interacts with each other and the outside world to enable the microcontroller's functionality. The central processing unit (CPU) is the core component of a microcontroller and is responsible for executing instructions. It consists of an arithmetic logic unit (ALU), a control unit, and registers. The CPU fetches instructions from memory, performs calculations, and controls the overall operation of the microcontroller. Memory plays a crucial role in a microcontroller as it stores program instructions and data. It includes non-volatile memory (such as flash memory) to store the program code permanently, and volatile memory (such as random-access memory or RAM) for temporary data storage during program execution.
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Related Questions
when torublehooting an engine for too rich mixture to allow th engine to idle, what would be a possible cause
Answers
When troubleshooting an engine for too rich mixture to allow the engine to idle, the possible cause could be that there is a misadjusted carburetor.
This means that the air/fuel mixture is not adjusted properly and is allowing too much fuel into the engine, causing it to run rich. Another possible cause is that the fuel system may be clogged or dirty, causing the fuel to not be delivered properly to the engine. This can cause the engine to idle poorly and run rich.There are a few things that can be done to troubleshoot this issue.
The first step is to check the carburetor and make sure that it is adjusted properly. The air/fuel mixture should be adjusted so that the engine is running at the correct RPM and there is no hesitation or misfire. If the carburetor is misadjusted, it will need to be corrected.
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Technician A says that one planetary gear set can provide gear reduction, overdrive, and reverse. Technician B says that most transmissions today use compound (multiple) planetary gear sets. Which technician is correct?
Answers
Answer:
Both technician A and technician B are correct
Explanation:
A planetary gearbox consists of a gearbox with the input shaft and the output shaft that is aligned to each other. It is used to transfer the largest torque in the compact form. A planetary gearbox has a compact size and low weight and it has high power density.
One planetary gear set can provide gear reduction, overdrive, and reverse. Also, most transmissions today use compound (multiple) planetary gears set.
So, both technician A and technician B are correct.
a misfire code is a type ____ DTC
A) 1 or 2
B) a or b
C) c or d
D l or ll
Answers
Answer:
A misfire code is a type A DTC.
Explanation:
A misfire code is a type A DTC.
A Misfire generate unburned hydrocarbons thereby increasing the load on the catalytic converter. Misfires are due to incomplete combustion or lack of combustion.
Diagnostic Trouble Code (DTC) is a type of code used by the vehicle’s onboard diagnostics (OBD) system to alert when the vehicle has a problem. Type A DTC is the most serious DTC, this are emissions related. It requests illumination of the MIL after one failed driving cycle and stores a freeze frame DTC after one failed driving cycle.
Do you know anything about Android graphics?
Answers
Android provides a huge set of 2D-drawing APIs that allow you to create graphics.
Android has got visually appealing graphics and mind blowing animations.
The Android framework provides a rich set of powerful APIS for applying animation to UI elements and graphics as well as drawing custom 2D and 3D graphics.
Three Animation Systems Used In Android Applications:-1. Property Animation
2. View Animation
3. Drawable Animation
Which statement below can be used to read data from a file one character at a time?
A) inputFile.get(1)
B) inputFile.read(1)
C) inputFile.split(1)
D) inputFile.open(1)
Answers
Answer:
b
Explanation: because it says input file.read
A shaft is made from a tube, the ratio of the inside diameter to the outside diameter is 0.6. The material must not experience a shear stress greater than 500KPa. The shaft must transmit 1.5MW of mechanical power at 1500 revolution per minute.calculate the inside and outside diameter.
Answers
Answer: The inside diameter is approximately 0.39 meters and the outside diameter is approximately 0.65 meters.
Explanation:
The first step is to calculate the torque required to transmit 1.5 MW of power at 1500 rpm. The formula for torque is:
T = (P × 60) / (2 × π × N)
where T is torque, P is power, N is speed in revolutions per minute, and π is the mathematical constant pi. Substituting the given values, we get:
T = (1.5 × 10^6 × 60) / (2 × π × 1500) = 238.7 kNm
Next, we can use the formula for shear stress:
τ = (T × r) / J
where τ is shear stress, T is torque, r is the radius, and J is the polar moment of inertia. For a tube, J is equal to (π/2) × (D^4 - d^4), where D is the outside diameter and d is the inside diameter.
Since the ratio of inside diameter to outside diameter is 0.6, we can set d = 0.6D. Substituting this into the formula for J and simplifying, we get:
J = (π/2) × D^4 × (1 - 0.6^4) = 0.374πD^4
Substituting the given values for torque and shear stress, we get:
500 kPa = (238.7 kNm × r) / (0.374πD^4)
Solving for r/D, we get:
r/D = 0.054
Since r + d = D, we can substitute d = 0.6D and r = 0.054D into this equation and solve for D:
D = 0.65 meters (approx.)
Finally, we can calculate the inside diameter by using the given ratio:
d/D = 0.6
d = 0.39 meters (approx.)
Therefore, the inside diameter is approximately 0.39 meters and the outside diameter is approximately 0.65 meters.
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once scientist has asked a question conducted an investigation and analyzed the data his or hwr goalis to
Answers
Answer:
hola
Explanation:
Explanation:
so its an question?..........
8. 15 A manual arc welding cell uses a welder and a fitter. The cell operates 2,000 hriyr. The welder is paid $30/hr and the fitter is paid $25/hr. Both rates include applicable overheads. The cycle time to complete one welded assembly is 15. 4 min. Of this time, the arc-on time is 25%, and the fitter's participation in the cycle is 30% of the cycle time. A robotic arc welding cell is being considered to replace this manual cell. The new cell would have one robot, one fitter, and two workstations, so that while the robot is working at the first sta tion, the fitter is unloading the other station and loading it with new components. The fitter's rate would remain at $25/hr. For the new cell, the production rate would be eight welded assemblies per hour. The arc-on time would increase to almost 52%, and the fitter's participation in the cycle would be about 62%. The installed cost of the robot and worksta tions is $158,000. Power and other utilities to operate the robot and arc welding equipment will be $3. 80/hr, and annual maintenance costs are $3,500. Given a 3-year service life, 15% rate of return, and no salvage value, (a) determine the annual quantity of welded assem blies that would have to be produced to reach the break-even point for the two methods. (b) What is the annual quantity of welded assemblies produced by the two methods work. Ing 2,000 hryr?
Answers
The annual quantity of welded assemblies that would have to be produced to reach the break-even point for the two methods is approximately 15,983.
To determine the break-even point between the manual arc welding cell and the robotic cell, we need to calculate the total costs for each method and then equate them.
For the manual arc welding cell:
Labor cost per hour = (welder's hourly rate x arc-on time) + (fitter's hourly rate x fitter's participation in the cycle) = ($30 x 0.25) + ($25 x 0.3) = $11.25
Labor cost per welded assembly = labor cost per hour x cycle time per assembly / 60 = $11.25 x 15.4 / 60 = $2.89
Overhead cost per welded assembly = (labor cost per hour x (1 - arc-on time - fitter's participation in the cycle)) x cycle time per assembly / 60 = ($30 x 0.45) x 15.4 / 60 = $4.68
Total cost per welded assembly = labor cost per welded assembly + overhead cost per welded assembly = $2.89 + $4.68 = $7.57
Total cost per hour = total cost per welded assembly x production rate = $7.57 x 8 = $60.56
Total cost per year = total cost per hour x hours of operation per year = $60.56 x 2,000 = $121,120
For the robotic arc welding cell:
Labor cost per hour = fitter's hourly rate x fitter's participation in the cycle = $25 x 0.62 = $15.50
Labor cost per welded assembly = labor cost per hour x cycle time per assembly / 60 = $15.50 x 15.4 / 60 = $3.97
Overhead cost per welded assembly = power and utility cost per hour + annual maintenance cost / production rate = $3.80 + $3,500 / (8 x 2,000) = $3.80 + $0.22 = $4.02
Total cost per welded assembly = labor cost per welded assembly + overhead cost per welded assembly + (installed cost / (production rate x service life)) = $3.97 + $4.02 + ($158,000 / (8 x 3)) = $3.97 + $4.02 + $6,208.33 = $14.19
Total cost per hour = total cost per welded assembly x production rate = $14.19 x 8 = $113.52
Total cost per year = total cost per hour x hours of operation per year = $113.52 x 2,000 = $227,040
To find the break-even point, we set the total cost of the manual arc welding cell equal to the total cost of the robotic arc welding cell and solve for the annual quantity of welded assemblies:
$121,120 + x($7.57) = $227,040 + x($14.19)
$7.57x - $14.19x = $227,040 - $121,120
$-6.62x = $105,920
x = $105,920 / $6.62
x = 15,982.7
Therefore, the annual quantity of welded assemblies that would have to be produced to reach the break-even point for the two methods is approximately 15,983.
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the highway department paves one section of an interstate with type a concrete and ajoining section with type b concrete and observes how long it takes until cracks appear in each.
a. Observational
b. Experimental
Answers
This scenario can be described as an experimental study. An experiment involves manipulating variables to observe the effects on an outcome.
In this case, the highway department manipulates the type of concrete used (Type A and Type B) and observes the time taken for cracks to appear in each section. The explanation for this conclusion is that by actively controlling the type of concrete used, the department can compare the performance and durability of both types, allowing them to make informed decisions about which concrete is more suitable for future use. In an observational study, no variables would be intentionally manipulated; rather, the researcher would simply observe and gather data without any intervention.
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Toyotas more than 30 hybrid vehicles investment in zero emissions vehicle and working on developing hydrogen fuel cell vehicles not only protect the natural environment but also further his overall economic progress customer is generally has positive feelings towards companies that focus on______ efforts such as Toyotas
Answers
The missing term in the presented paragraph is environmental.
In recent years the effects of climate change have been strongly manifested around the world causing:
Forest firesFloodsHeatwavesCold wavesSnowfallThe rise in the level of rivers and seasDeglaciationTherefore, many companies have begun to investigate productive alternatives to reduce their environmental impact. In the case of the car industry, companies have deepened their research on other sources of energy such as:
ElectricSolarWindOne of them is Toyota, the Japanese brand that has developed cars that work hybrid, that is, with gasoline and electric power. This will reduce the emissions of CO2 and other harmful gases into the atmosphere.
Therefore, it is possible to infer that the missing term in the paragraph is Environmental.
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A horizontal force P is applied to a 130 kN box resting on a 33 incline. The line of action of P passes through the center of gravity of the box. The box is 5m wide x 5m tall, and the coefficient of static friction between the box and the surface is u=0.15. Determine the smallest magnitude of the force P that will cause the box to slip or tip first. Specify what will happen first, slipping or tipping.
Answers
Answer:
SECTION LEARNING OBJECTIVES
By the end of this section, you will be able to do the following:
Distinguish between static friction and kinetic friction
Solve problems involving inclined planes
Section Key Terms
kinetic friction static friction
Static Friction and Kinetic Friction
Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.
There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.
Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.
Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.
What do you think will happen to the demand curve if there is a sudden surplus for a certain commodity?
Answers
Answer:
the curve will flatten due to the supply and demand theory.
before adjusting drive-belt tension, technician a checks for proper pulley alignment. technician b looks up the specified belt tension in the vehicle's service manual. who is correct?
Answers
Answer:
Technician b is correct
Explanation:
Before adjusting drive-belt tension, it is very important to check the vehicle workshop manual for specified belt tension, so that you can match your reading against the specification in the vehicle's service manual. If the tension reading you have matches the suggested reading in the vehicle's service manual and the belt is not damaged then you do not need to proceed any further. But if the reading does not match, then you can adjust the belt tension.
Therefore, technician b is correct.
The team needs to choose a primary view for the part drawing. Three team members make suggestions:
- Team member 1 suggests an orthographic top view because that is how the plans for the part were submitted.
- Team member 2 suggests an isometric view showing side details that were documented within the submitted plans.
- Team member 3 suggests all three orthogonal views should be presented as the primary view.
What is the best way to proceed?
Answer choices below:
Answers
Answer:
Option 1
Explanation:
As the team has already submitted the plans for the part drawing, the best way to proceed would be how it was given in the plans. Hence, the option to be selected :
Team member 1 suggests an orthographic top view because that is how the plans for the part were submitted.Answer:
The first option
Explanation:
Team member 1 suggests an orthographic top view because that is how the plans for the part were submitted.
What is the primer coating that protects the metal from rusting on a Aftermarket part.. Flat Primer
Primer Sealer
Shipping Primer
Answers
For the accident of Gulf of Mexico Oil Spill, British Petroleum took the following steps to pay for the serious consequences (i=7% per quarter). Pay $3 billion at the end of the third quarter of 2010 and another $2 billion at the end of the fourth quarter of 2010. Make payments of $1.25 billion each quarter thereafter until a total of $20 billion (the total $20 billion includes the payments in 2010). a) Develop a cash flow diagram. b) What is the equivalent present value at the beginning of the third quarter of 2010? c) What is the equivalent present value at the beginning of the first quarter of 2010? d) What is the equivalent future value at the end of 2013?
Answers
a) Cash Flow Diagram:
```
|------> $3 billion ------>|
| |
|------> $2 billion ------>|
| |
$1.25 billion |------> $1.25 billion -->|
per quarter| per quarter |
| |
|------> $1.25 billion -->|
| per quarter |
| |
| ... (repeated) |
| |
|------> $1.25 billion -->|
| per quarter |
```
b) To calculate the equivalent present value at the beginning of the third quarter of 2010, we need to discount each cash flow to its present value using the given interest rate of 7% per quarter. The present values are then added together.
c) To calculate the equivalent present value at the beginning of the first quarter of 2010, we need to discount each cash flow to its present value using the given interest rate of 7% per quarter. However, since the cash flows start from the third quarter of 2010, we need to discount the first two quarters' payments to their present value as well. The present values are then added together.
d) To calculate the equivalent future value at the end of 2013, we need to find the future value of each cash flow using the given interest rate of 7% per quarter. The present values are then added together.
e) Calculations for parts b, c, and d. However, by applying appropriate discounting or compounding formulas based on the given interest rate, you can determine the equivalent present or future values at specific time points.
To analyze the cash flow associated with the Gulf of Mexico Oil Spill, we can create a cash flow diagram. Each arrow represents a cash flow, and the time periods are indicated below each arrow. The diagram shows the cash inflows and outflows over time.
a) Cash Flow Diagram:
```
|------> $3 billion ------>|
| |
|------> $2 billion ------>|
| |
$1.25 billion |------> $1.25 billion -->|
per quarter| per quarter |
| |
|------> $1.25 billion -->|
| per quarter |
| |
| ... (repeated) |
| |
|------> $1.25 billion -->|
| per quarter |
```
b) To calculate the equivalent present value at the beginning of the third quarter of 2010, we need to discount each cash flow to its present value using the given interest rate of 7% per quarter. The present values are then added together.
c) To calculate the equivalent present value at the beginning of the first quarter of 2010, we need to discount each cash flow to its present value using the given interest rate of 7% per quarter. However, since the cash flows start from the third quarter of 2010, we need to discount the first two quarters' payments to their present value as well. The present values are then added together.
d) To calculate the equivalent future value at the end of 2013, we need to find the future value of each cash flow using the given interest rate of 7% per quarter. The present values are then added together.
e) Calculations for parts b, c, and d. However, by applying appropriate discounting or compounding formulas based on the given interest rate, you can determine the equivalent present or future values at specific time points.
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The inspector should inspect insulation in unfinished spaces, including attics, _____ and foundation areas.
Answers
Answer:
basements
Explanation:
A (n) __________ sign indicates what a driver must or must not do. A. Advanced-warning B. Pavement markings C. High occupancy vehicles D. Regulatory (fill in the blank)
Answers
Answer:
A
Explanation:
A Warning a head is what they trying to say
Compute the volume percent of graphite, VGr, in a 3.1 wt% C cast iron, assuming that all the carbon exists as the graphite phase. Assume densities of 7.9 and 2.3 g/cm3 for ferrite and graphite, respectively.
Answers
Answer:
The volume percent of graphite is 9.9%
Explanation:
Given;
weight percent of graphite, C = 3.1wt%
density of ferrite, \(\rho _f\) = 7.9 g/cm³
density of graphite, \(\rho _g\) = 2.3 g/cm³
Determine the mass fraction;
\(W_f = \frac{C_g - C_0}{C_g -C_f} \\\\W_f =\frac{100 - 3.1}{100-0}\\\\W_f = 0.969\\\\\\W_g = \frac{C_0 - C_a}{C_g -C_f} \\\\W_g =\frac{3.1-0}{100-0}\\\\W_g = 0.031\)
Determine the volume fraction;
\(V = \frac{W_g/ \rho_g}{W_f / \rho_f \ + \ W_g / \rho_g} *100 \%\\\\V = \frac{0.031/ 2.3}{0.969 / 7.9 \ + 0.031 / 2.3}*100\%\\\\V = 9.9\%\)
Therefore, the volume percent of graphite is 9.9%
** CodeHS AP CSP 7.2.9 Top Movies **
PLEASE ANSWER THIS USING PYTHON!
Create a list of your favorite 4 movies. Print out the 0th element in the list. Now set the 0th element to be "Star Wars" and try printing it out again.
Answers
Here's a code in Python to create a list of 4 favorite movies and update the 0th element:
# Creating a list of favorite movies
movies = ["The Shawshank Redemption", "The Dark Knight", "The Godfather", "The Godfather: Part II"]
# Printing the 0th element in the list
print("Original 0th element:", movies[0])
# Updating the 0th element to "Star Wars"
movies[0] = "Star Wars"
# Printing the updated 0th element
print("Updated 0th element:", movies[0])
The output of the above code would be:
Original 0th element: The Shawshank Redemption
Updated 0th element: Star Wars
In this code, we first created a list of 4 favorite movies using the list constructor and stored it in a variable named movies. We then used the indexing operator [ ] to access and print the 0th element in the list, which is The Shawshank Redemption.
Next, we updated the 0th element in the list to be "Star Wars" using the same indexing operator and assigned the new value to the same element. Finally, we printed the updated 0th element to verify that the value has been successfully updated.
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Ethics is an important factor in the life of an engineer. What do you understand by the term’s personal ethics and professional ethics?
Ethical problems can be complex, and engineers may struggle finding solutions when problems arise. What resources can engineers use to help them?
Answers
When engineers face ethical problems or dilemmas, there are several resources they can use to help them navigate these situations: Codes of Ethics, Ethical Training and Education, Ethical Committees, etc.
Personal ethics refers to an individual's own moral principles and values that guide their behavior and decision-making in their personal life. It involves considering what is right or wrong based on one's own beliefs, values, and experiences. Personal ethics are subjective and can vary from person to person.
Professional ethics, on the other hand, refers to the ethical standards and principles that govern the behavior of professionals within their specific field or industry. For engineers, professional ethics encompass the moral obligations and responsibilities they have towards their clients, employers, colleagues, society, and the environment. Professional ethics provide a framework for engineers to ensure that their actions and decisions align with the values and expectations of their profession.
When engineers face ethical problems or dilemmas, there are several resources they can use to help them navigate these situations:
1. Codes of Ethics: Many professional engineering organizations have established codes of ethics that provide guidelines and standards for ethical conduct in the engineering profession. These codes outline the responsibilities and ethical principles that engineers should uphold.
2. Ethical Guidelines and Policies: Companies and organizations often have their own ethical guidelines and policies in place. These documents help engineers understand the ethical expectations within their specific workplace or industry.
3. Ethical Training and Education: Continuous education and training in ethics can equip engineers with the knowledge and skills to identify and address ethical issues. Professional development programs and workshops may focus on ethical decision-making and provide case studies or scenarios to enhance ethical reasoning.
4. Professional Networks and Support: Engaging with professional networks, such as engineering associations and societies, can provide engineers with opportunities to discuss ethical challenges with peers and seek advice or guidance from experienced professionals.
5. Ethical Committees and Advisors: Some organizations have dedicated ethics committees or advisors who can provide guidance and assistance when engineers encounter ethical problems. These committees may offer confidential consultations and help engineers navigate complex ethical issues.
6. Legal and Regulatory Resources: Laws and regulations play a crucial role in defining ethical boundaries and providing legal frameworks. Engineers can consult legal resources, regulations, and guidelines to ensure compliance with legal and ethical requirements.
7. Ethical Decision-Making Frameworks: Engineers can utilize ethical decision-making frameworks, such as the Ethical Decision-Making Model or the SAD Formula (Scrutinize, Analyze, and Decide), to systematically evaluate ethical dilemmas and arrive at well-considered decisions.
By utilizing these resources, engineers can enhance their understanding of ethics, address ethical challenges effectively, and uphold the highest standards of professional conduct.
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How does energy transition from one form to another as water moves from behind a dam to downstream of a dam?.
Answers
Answer:
potential energy changes to kinetic energy
Explanation:
What
IS
a
3-phase system.
Answers
Answer:
Explanation: Three-phase power is a three-wire ac power circuit with each phase ac signal 120 electrical degrees apart
18) Technician A says that adjustable wrenches should be used when
torquing fasteners. Technician B says that adjustable wrenches can round
the edges of fasteners. Which technician is correct?
A) Technician A only
B) Technician B only
O C) Both technicians
D) Neither technician
Answers
In an aircraft jet engine at takeoff, the combustion products expand adiabatically in the exhaust nozzle. At entrance to the nozzle, the pressure is 0.180 MPa and the temperature is 1200 K. The kinetic energy of the gas entering the nozzle is very much smaller than the kinetic energy of the gas leaving the nozzle. The specific heat of the exhaust gas varies with temperature approximately as follows: Cp = 0.959 + 1.16 X 10-4T + 3.65 X 10-8T2 , in which the units of cP are kJ/kg · K and Tis the temperature in K. The molecular weight of the exhaust gas is 30. Supposing the expansion to be frictionless (reversible) as well as adiabatic, show how the exhaust velocity and pressure will depend on the exhaust temperature for a series of values: 1100, 1000, and 900 K. At each temperature determine also the speed of sound VyRT'.
Answers
At entrance to the nozzle, the pressure is 0.180 MPa and the temperature is 1200 K. The kinetic energy of the gas entering the nozzle is very much smaller than ... The specific heat of the exhaust gas varies with temperature approximately as follows: ... Problem 4P: In an aircraft jet engine at takeoff, the combustion product.
In this exercise we want to calculate the temperature for each value informed in the text from the given equation, so we have to:
A)\(Cp = 0.959+ \frac{31910.95}{250000} \)
B)\(Cp = 0.959+ \frac{29010.95}{250000} \)
C)\(Cp = 0.959+ \frac{26110.95}{250000} \)
Then given the equation as:
\(Cp = 0.959 + 1.16 * 10^{-4}T + 3.65 * 10^{-8}T_2 \)
Replacing the value of T with the first value informed in the text we have:
A) 1100, will be:
\(Cp = 0.959 + 1.16 * 10^{-4}(1100) + 3.65 * 10^{-8}(1200)\\ Cp = 0.959+ \frac{31910.95}{250000} \)
B) 1000, will be:
\(Cp = 0.959 + 1.16 * 10^{-4}(1000) + 3.65 * 10^{-8}(1200)\\Cp = 0.959+ \frac{29010.95}{250000} \)
C) 900, will be:
\(Cp = 0.959 + 1.16 * 10^{-4}(900) + 3.65 * 10^{-8}(1200)\\Cp = 0.959+ \frac{26110.95}{250000} \)
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Given the following MATLAB statement: ( 3 + 2 ) / 5 * 4 + 5 ^ 2 In what order will these operations be done?
Answers
Answer:
first is the parentheses, (3+2)=5 next is the exponent 5^2=25, next is the division 5 / 5 = 1, then the multiplication 4*1=4 and then you add 4+25=29. so the answer is 29.
Care should be taken when purchasing yarn because, some products may appear jet black in the store but actually show a blue or green tint in natural light. True or False?
Answers
It is TRUE to state that care should be taken when purchasing yarn because, some products may appear jet black in the store but actually show a blue or green tint in natural light.
How is this so?Care should be taken when purchasing yarn because some products may appear jet black under artificial store lighting but display a different color tint, such as blue or green,in natural light.
The lighting conditions in the store can impact how colors appear, and it's important toconsider natural light conditions to accurately assess the true color of the yarn before making a purchase.
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The monthly output of a certain product is Q(x)=2500x 5/2
where x is the capital investment in millions of dollars. Find dQ/dx, which can be used to estimate the effect on the output if an additional capital investment of $1 million is made. dQ/dx=
Answers
The monthly output of a certain product can be given by the function
\(`Q(x) = 2500x^(5/2)`\)
where x is the capital investment in millions of dollars.
differentiate the function Q(x) with respect to x.
\(dQ/dx = d/dx(2500x^(5/2))\)
Using the power rule of differentiation, we have:
\(dQ/dx = (5/2) * 2500 * x^(5/2 - 1)dQ/dx
= 6250x^(3/2) `dQ/dx
= 6250x^(3/2)`\)
which gives us the effect on the output if an additional capital investment of $1 million is made.
Note: To estimate the effect on the output if an additional capital investment of $1 million is made, we substitute x with x+1 in the expression for `dQ/dx`. This gives us the new output and the increase in output due to the additional investment.
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You are about to perform PMCS on your M1114? What resource should you use for the procedures and instructions for performing PMCS?
Answers
The resources and instructions that should be used for the procedures of performing PMCS are:
Operator's manualsSafety cautions and warnings.Fording kitHeating and cooling systems.What is PMCS?PMCS is an acronym for preventive maintenance checks and services and it can be defined as the maintenance, checks, and services that are typically performed before, during, and after the use of any type of military equipment such as:
M1114M1151M1123Basically, the resources and instructions that should be used for the procedures of performing PMCS are:
Operator's manualsSafety cautions and warnings.Fording kitHeating and cooling systems.Read more on PMCS here: https://brainly.com/question/15720250
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Consider the following Moore’s law growth pattern (since 1980) for the number of transistors inside a particular commercial microprocessor: N = 1920 x 10 0.1637(Y – 1980) where Y is the year and N is the number of transistors. Assuming sustained Moore’s law growth, what will be the number of transistors in a microprocessor in year 2025? Using the same expression, calculate how many years it will take for the transistor count to increase by 100x
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Answer:
No. of transistors = \($4.1524 \times 10^{10}$\) transistors
Explanation:
Given that:
N = \($1920 \times 10^{0.163(Y-1980)}$\)
Y = 2025
N = \($1920 \times 10^{0.163(2025-1980)}$\)
N = \($4.1524 \times 10^{10}$\) transistors
Now at Y = 1980
Number of transistors N = 1920
Therefore,
\($1000 = 10^{0.163(Y-1980)}$\)
\($\log_{10} 1000=0.163(Y-1980)$\)
\($\frac{3}{0.163}=Y-1980$\)
18 ≅ 18.4 = Y - 1980
Y = 1980 + 18
= 1998
So, to increase multiples of 1000 transistors. it takes 18 years.