The equation of the ellipse is: x² / 121 + y² = 1
An ellipse has two main axes, the major axis (with length 2a) and the minor axis (with length 2b), and its equation is given by:
(x² / a²) + (y² / b²) = 1
The vertices lie on the major axis and the co-vertices lie on the minor axis. So, we have:
a = 11 (length of major axis)
b = 1 (length of minor axis)
The coordinates of the center of the ellipse are (h,k), where h and k are the midpoint of the major and minor axes, respectively. So, we have:
h = 0 (midpoint of co-vertices on x-axis)
k = 0 (midpoint of vertices on y-axis)
Substituting these values into the equation, we get:
(x² / 11²) + (y²/ 1²) = 1
Simplifying, we get:
x² / 121 + y² = 1
Therefore, the equation of the ellipse is:
x² / 121 + y² = 1
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slope = - 2/5; y-intercept = 0
HELP!!!!!!!!!!!
Answer:
To form the equation, it would y = -2/5x
Step-by-step explanation:
if p = 2^k + 1 is prime, show that every quadratic nonresidue of p is a primitive root of p.
Every quadratic nonresidue of p is a primitive root of p, when p = 2^k + 1 is primeIf p = 2^k + 1 is a prime number, we want to show that every quadratic nonresidue of p is a primitive root of p.
In other words, we aim to prove that if an element x is a quadratic nonresidue modulo p, then it is also a primitive root of p.
Let's assume p = 2^k + 1 is a prime number. To prove that every quadratic nonresidue of p is a primitive root of p, we can use the properties of quadratic residues and quadratic nonresidues.
A quadratic residue modulo p is an element y such that y^((p-1)/2) ≡ 1 (mod p), while a quadratic nonresidue is an element x such that x^((p-1)/2) ≡ -1 (mod p).
Now, let's consider an element x that is a quadratic nonresidue modulo p. We want to show that x is a primitive root of p.
Since x is a quadratic nonresidue, we know that x^((p-1)/2) ≡ -1 (mod p). By Euler's criterion, this implies that x^((p-1)/2) ≡ -1^((p-1)/2) ≡ -1^2 ≡ 1 (mod p).
Since x^((p-1)/2) ≡ 1 (mod p), we can conclude that the order of x modulo p is at least (p-1)/2. However, since p = 2^k + 1 is a prime, the order of x modulo p must be equal to (p-1)/2.
By definition, a primitive root of p has an order of (p-1). Since the order of x modulo p is (p-1)/2, it follows that x is a primitive root of p.
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help help help i need help!!!
Drag each equation to the correct location on the table. Not all equations will be used.
Determine which equations represent lines that are parallel or perpendicular to the linear equation provided on the graph.
y = 2 + 3y = - +4y= 2z+ 2 y = 12 + 8
y=-2 + 5y =
-2z+1
4
Parallel Line
2
2
Perpendicular Line
Answer:
parallel: y = 1/2x +3perpendicular: y = -2x +1Step-by-step explanation:
A parallel line will have the same slope as the line on the graph. A perpendicular line will have a slope that is the opposite reciprocal of the slope of the graphed line.
Slope of graphed lineThe line on the graph rises 1 grid square for each run of 2 grid squares to the right. Its slope is ...
m = rise/run = 1/2
Slope of perpendicular lineThe opposite reciprocal of this slope is ...
-1/(1/2) = -2
A perpendicular line will have a slope of -2.
Slope-intercept formThe slope-intercept form of the equation for a line is ...
y = mx +b
where the slope is m and b is the y-intercept. For the purpose here, we don't care about the y-intercepts of any of the lines. We only care about the slope: the coefficient of x.
This means the equations we're looking for are of the form ...
parallel line: y = 1/2x + b
perpendicular line: y = 2x +b . . . . . for some constant b
Parallel lineOf the equations offered, the only one with an x-coefficient of 1/2 is ...
y = 1/2x +3
Perpendicular lineOf the equations offered, the only one with an x-coefficient of -2 is ...
y = -2x +1
Answer:
Step-by-step explanation:
you are welcome
In a two population proportions problem, why is the use of the individual proportions for X and Y (i.e, p_x,q_x and p_y,q_y ) used for confidence intervals instead of the "common p" used in hypothesis testing? 1. It's not. Unless the sample sizes are outside the 1/3 to 3/1 ratio, the two methods result in the same boundaries 2. Because it's a Cl on the difference". If you're going in assuming that the proportions are in fact different, it doesn't make sense to support using an average p and q 3. It doesn't make any difference.......this is not the answer, don't pick this 4. It's not, you use the common p in both instances 5. Because it's a Cl on the "difference", so it makes sense to use an averaged value for p.
In a two population proportions problem, the use of individual proportions for X and Y (i.e., p_x, q_x, and p_y, q_y) is used for confidence intervals instead of the "common p" used in hypothesis testing.
The reason for this is that in hypothesis testing, we are assuming that the two population proportions are equal (i.e., p_x = p_y = p), which means that we can estimate p using the combined sample proportion. However, in a confidence interval problem, we are interested in estimating the difference between the two population proportions, and using the combined sample proportion to estimate p would not be appropriate. Instead, we use the individual sample proportions for X and Y to construct separate confidence intervals for each population proportion, which we can then use to estimate the difference between them.
In other words, when constructing a confidence interval for the difference in proportions, we are interested in estimating the variability of each population proportion separately, and not the variability of the combined sample proportion. This is why we use the individual sample proportions for X and Y in constructing confidence intervals, rather than the common sample proportion used in hypothesis testing.
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PLEASE HELP!!!!!
The double box plot below shows the number of daily visitors to two national parks.
Use medians to compare the centers of the data sets.
Which park has greater variability in the number of daily visitors? Show your work.
In general, which park has more daily visitors? Justify your response.
For which park, could you more accurately predict the number of daily visitors on any given day? Explain.
Answer:
Kindly check explanation
Step-by-step explanation:
From the boxplot attached :
Summer lake :
Median = 60 ( point in between the box)
Variability is given by the Range = maximum - minimum = 80 - 40 = 40
Maximum number of visitors = 80
Summer lake distribution is approximately normally distributed, so number of daily visitors can be more accurately predicted on any given day
Canyon Overlook:
Median = 80 ( point in between the box)
Variability is given by the Range = maximum - minimum = 120 - 30 = 90
Maximum number of visitors = 120
Bronze is a mixture of copper and tin. The copper and tin are mixed in the ratio 9:1 by weight.
a. How much copper is there in a bronze brooch weighing 360 g?
b. Another bronze brooch contains 670.5g of copper.
How much does it weigh altogether?
a. The amount of copper in a bronze of 360g is 324g
b. The mass of bronze with 670.5g of copper is 745g
What is ratio?A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0. A proportion is an equation in which two ratios are set equal to each other. For example, if there is 1 boy and 3 girls you could write the ratio as: 1 : 3 (for every one boy there are 3 girls) 1 / 4 are boys and 3 / 4 are girls.
The ratio of copper to Tin is 9:1. The total ratio is 10
a.therefore the amount of copper = 9/10 × 360
= 324g
b. The mass of copper = 670.5g
therefore the mass of the bronze =
= 9/10× y = 670.5
9y = 670.5 × 10
9y = 6705
y = 6705/9
y = 745g
therefore the total mass of the bronze is 745g
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Determine the solution to the equation. 8+4x=2x+8+2x A Infinite B One Solution C No Solution
After solving the given equations the answer is an Infinite solution. Hence, option A is correct
What is an equation?Mathematical expressions with two algebraic symbols on either side of the equal (=) sign are called equations.
This relationship is illustrated by the left and right expressions being equal to one another. The left-hand side equals the right-hand side is a basic, straightforward equation.
As per the given equation in the question,
8 + 4x = 2x + 8 + 2x
Firstly, let's write the given equation in a simplified manner,
8 + 4x = 8 + 4x
As we can see that LHS = RHS, which means that both equations are the same then which means they will give infinite solutions.
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Find the period. Express your answar uaing two signiffeant flgures. A peg on a furniablo moves wath a constart tangential speod of 0.88 m/s in a dicle of radus 0.19 m. The pog casts a shadow an a wale. Find the following quantltes related to the matlon of the chadaw. Part E Find the amplitude. Expross your anwwer ueing two algnificant flguros. A= Find the raxmum isceed Express your answer using two significant figures. Find the maximum magnitude of the accelerason. Express your answer using two aigniflcant flgures.
The maximum magnitude of acceleration is approximately 4.085 m/s².
To find the period of the motion, we need to determine the time it takes for the peg to complete one full revolution around the circle. The period can be calculated using the formula:
T = 2πr/v
where T is the period, r is the radius of the circle, and v is the tangential speed of the peg.
Given:
r = 0.19 m
v = 0.88 m/s
Substituting these values into the formula, we have:
T = 2π(0.19 m)/(0.88 m/s)
T ≈ 0.432 s
Therefore, the period of the motion is approximately 0.432 seconds.
Part E: To find the amplitude, we can use the radius of the circle since the motion is along a circular path. The amplitude is equal to the radius of the circle:
Amplitude (A) = 0.19 m
Part F: The maximum displacement is equal to the diameter of the circle since the peg moves from one extreme point to the other:
Maximum Displacement = 2 * 0.19 m = 0.38 m
Part G: The maximum magnitude of acceleration occurs at the extreme points of the circular path. It can be calculated using the formula:
amax = v²/r
where amax is the maximum acceleration, v is the tangential speed, and r is the radius of the circle.
Substituting the given values, we have:
amax = (0.88 m/s)² / 0.19 m
amax ≈ 4.085 m/s²
Therefore, the maximum magnitude of acceleration is approximately 4.085 m/s².
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find the slope of the line graphed
Answer:
First, we have to determine the slope as we're provided with two points. If there are two points, you can determine the slope of the line using: \(\frac{y_2-y_1}{x_2-x_1}\)
It looks like the coordinates provided are (1,1) and (3,-2)
So now, we have to plug these values into the equation provided, which should look like: \(\frac{-2-1}{3-1} = -\frac{3}{2}\)
Our slope is equal to -3/2.
Help with math please. “Write the slope-intercept form of the equation for the line through (-8; -2) that is perpendicular to y = 4x -1”
Step-by-step explanation:
worked is pictured and shown
32
{(-0. 25, 2. 5), (1. 75, -5. 5), (3. 25, -11. 5)}
Write an equation in the form of y = mx + b that represents this linear function?
Therefore, the equation in the form of y = mx + b that represents this linear function is: y = -3.2x + 0.1
To write an equation in the form of y = mx + b for a linear function, we need to find the slope (m) and the y-intercept (b).
We can use any two points from the given set of points to find the slope:
m = (y2 - y1) / (x2 - x1)
Let's use the first and second points:
m = (-5.5 - 2.5) / (1.75 - (-0.25))
m = -8 / 2.5
m = -3.2
Now, we can use the slope and one of the points to find the y-intercept:
y = mx + b
-5.5 = (-3.2)(1.75) + b
b = -5.5 + 5.6
b = 0.1
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what iss y = 64 (18)
Answer:
y=1152
Step-by-step explanation:
18 x 64 hope I was helpfull
Solve -6x +18> -30.
A. x < 2
B. x > 2
C. x > 8
D. x < 8
Answer: D, x < 8
Step-by-step explanation: Subtract 18 from both sides.
Simplify the expression
Subtract the numbers
Subtract the numbers
Divide both sides by the same factor, and flip the relation because the factor is negative
Cancel terms that are in both the numerator and denominator
Divide the numbers
−6x+18−18>−30−18=
=x<8
33. DF bisects ZEDG. Find the value of x. The diagram is not to scale.
From the given diagram, we can identify two right-angled triangles. The triangles are shown below:
Using trigonometric ratios, we can find x as follows
\(\begin{gathered} \sin 28^0\text{ = }\frac{7x\text{ + 15}}{DF} \\ \sin 28^0\text{ = }\frac{10x}{DF} \end{gathered}\)We can equate the expressions for DF as follows:
\(\begin{gathered} DF\text{ = }\frac{7x\text{ + 15}}{\sin 28^0} \\ DF\text{ = }\frac{10x}{\sin 28^0} \end{gathered}\)\(\begin{gathered} \frac{7x\text{ + 15}}{\sin28^0}\text{ = }\frac{10x}{\sin 28^0} \\ \text{Cancelling out sin 28}^0 \\ 7x\text{ + 15 = 10x} \end{gathered}\)Solving for x:
\(\begin{gathered} 7x\text{ - 10x = -15} \\ -3x\text{ = -15} \\ \text{Divide both sides by -3} \\ \frac{-3x}{-3}\text{ = }\frac{-15}{-3} \\ x\text{ = 5} \end{gathered}\)Answer:
x = 5
Q2: Use Euler's method to approximate y' = y - x for the initial condition y(0) = 1.5,0 ≤x≤ 1.5,h=0.5 with accuracy e=0.0001
The value of given differential equation \(y' = y - x\) with the initial condition \(y(0) = 1.5\), on the interval \(0 \leq x \leq 1.5\), is \(y(1.5) = y_4 = 5.4296875\).
The differential equation we are given is \(y' = y - x\), with the initial condition \(y(0) = 1.5\). We are asked to approximate the solution on the interval \(0 \leq x \leq 1.5\) with a step size of \(h = 0.5\), and we want to achieve an accuracy of \(e = 0.0001\).
We start by calculating the first two values, \(y_0\) and \(y_1\), using the formula:
\(y_1 = y_0 + h \cdot f(x_0, y_0)\)
Here, \(h\) represents the step size, \(f(x, y)\) represents the derivative \(y'\) in terms of \(x\) and \(y\), and \((x_0, y_0)\) is the initial condition.
Using the given values, we can calculate \(y_1\) as:
\(y_1 = 1.5 + 0.5 \cdot (1.5 - 0) = 2.25\)
Next, we calculate \(y_2\) using the same formula:
\(y_2 = y_1 + h \cdot f(x_1, y_1)\)
Substituting the values \(x_1 = 0.5\) and \(y_1 = 2.25\), we get:
\(y_2 = 2.25 + 0.5 \cdot (2.25 - 0.5) = 3.375\)
Similarly, we can calculate \(y_3\) and \(y_4\) as:
\(y_3 = 3.375 + 0.5 \cdot (3.375 - 1) = 4.3125\)
\(y_4 = 4.3125 + 0.5 \cdot (4.3125 - 1.5) = 5.4296875\)
So, the value of \(y\) at \(x = 1.5\) is \(y(1.5) = y_4 = 5.4296875\).
Using Euler's method with a step size of \(h = 0.5\) and an accuracy of \(e = 0.0001\), the solution to the given differential equation \(y' = y - x\) with the initial condition \(y(0) = 1.5\), on the interval \(0 \leq x \leq 1.5\), is \(y(1.5) = y_4 = 5.4296875\).
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Prove that two events Λ and B, each with probability greater than
2
1
, cannot be disjoint. [You can see why that's true if you draw a Venn diagram, but you must prove this statement.]
Given events Λ and B have probability greater than 2/1, we need to prove that they cannot be disjoint.If events Λ and B are disjoint, they cannot occur at the same time. Therefore, the probability of them occurring together is 0.
Then, we know the probability of events Λ and B separately, and then the probability of events Λ or B is the sum of their probabilities, as per the addition rule of probability. That is,P(Λ or B) = P(Λ) + P(B)However, if events Λ and B are not disjoint, they can occur at the same time. Then, the probability of their intersection (Λ and B occurring together) is not equal to 0.
Thus, P(Λ or B) cannot be the sum of P(Λ) and P(B) as some of their probabilities are counted twice.Thus, we haveP(Λ or B) = P(Λ) + P(B) - P(Λ and B)Since P(Λ and B) is not 0, P(Λ or B) will be greater than the sum of P(Λ) and P(B). Therefore, the events Λ and B cannot be disjoint if their probabilities are greater than 2/1.
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Carol joined a gym. She has to pay a onetime $30 registration fee and then $12 per month. How much will she spend on the gym membership after 7 months?
Answer:
$114
Step-by-step explanation:
30+12(7)=30+84=114
a bitmap is a grid of square colored dots, called
Answer:
Step-by-step explanation:
A bitmap is a digital image format that is made up of a grid of square colored dots called pixels.
Each pixel in the bitmap contains information about its color and position, which allows the computer to display the image on a screen or print it on paper. Bitmaps are commonly used for photographs, illustrations, and other complex images that require a high degree of detail and color accuracy.
However, because bitmaps store information for each individual pixel, they can be memory-intensive and may result in large file sizes. Additionally, resizing a bitmap can lead to a loss of quality, as the computer must either interpolate or discard pixels to adjust the image size.
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two linear equations in two variables have no solution. the equations are
When two linear equations in two variables have no solution, it means that the equations are not compatible. This means that the equations cannot be solved simultaneously, as there is no set of values that can satisfy both equations. This can be seen by graphing the equations on a coordinate plane. If the two lines are parallel, then they will never intersect, and thus, there is no solution. If the two lines are the same line, then they will intersect at every point, and thus, any point on the line is a solution.
In the case of two linear equations in two variables, if the equations are not parallel and not the same line, then the equations will intersect at one point. This point is the solution to the two equations. If the equations are not parallel and not the same line, but do not intersect, then there is no solution. This means that the equations are incompatible and cannot be solved simultaneously.
In summary, two linear equations in two variables have no solution when the equations are incompatible. This means that the equations are either parallel or the same line, but do not intersect. In this case, there is no set of values that can satisfy both equations, and thus, there is no solution.
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Two linear equations in two variables have no solution if and only if the lines represented by the equations are parallel and do not intersect.
In other words, the lines do not have a common point, which means that there is no pair of values for the variables that satisfy both equations simultaneously.
Here's an example:
y = 2x + 1
y = 2x + 3
In this case, the lines represented by the equations are parallel and do not intersect, so there is no solution for the system of equations.
You can see this graphically by plotting the lines on a coordinate plane: the lines are close to each other, but they never intersect, so there is no common point that satisfies both equations.
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Travis needs to mail 12 letters and 25 postcards. A letter needs a 79-cent stamp and a postcard needs a 30-cent stamp. How much money will Travis spend for postage?
Answer:
$16.98
Step-by-step explanation:
First you have to multiply the amount of letters and postcards by the amount each stamps costs:
12x0.79=9.48
25x0.30=7.50
Then add those values together to get the total:
9.48+7.50=16.98
$16.98 is your answer
Hope this helps!
Understanding the ConceptsIn Exercises 7 and 8, fill in each blank with the appropriate word or phrase.7. To perform a t-test when the sample size is small, the sample must show no evidence of strong and must contain no .
Answer:
7. To perform a t-test when the sample size is small, the sample must show no evidence of strong skewness and must contain no outliers.
Step-by-step explanation:
These are the two conditions required for performing a t test
- Sample Size: A small sample size can reduce the statistical power of a t-test, making it more challenging to detect significant differences between groups. Generally, a larger sample size is desirable to obtain more reliable and representative results.
- Skewness: Skewness refers to the asymmetry of the distribution of data. In a t-test, assuming normality of the data is important for accurate results. If the data exhibits strong skewness, the assumption of normality may be violated. In such cases, alternative non-parametric tests or transformations of the data may be more appropriate.
- Outliers: Outliers are extreme values that significantly differ from the rest of the data. They can have a disproportionate impact on the results of a t-test, particularly when the sample size is small. Outliers can distort the mean and affect the assumptions of normality and homogeneity of variance.
While the presence of skewness or outliers does not prohibit the use of a t-test with a small sample size, it is important to interpret the results with caution and consider alternative approaches if necessary. Robust statistical methods, such as non-parametric tests or bootstrapping, can be useful when dealing with non-normal or outlier-prone data, especially with small sample sizes. Additionally, visual inspection of the data distribution, such as through histograms or box plots, can help identify potential skewness or outliers.
The sequence below shows the amount of bacteria that occurs after each hour:4, 12, 36, 108,Which formula can be used to determine the amount of bacteria in the next hour, NEXT, if the number of NOW bacteria is known?
The first term is, 4.
The second term is, 12.
That is,
\(12=4\times3\)The third term is 36. That is,
\(36=12\times3\)Similarly forth term 108 can be written as,
\(108=36\times3\)Therefore, the sequence is,
\(4,\text{ 3}\times4=12,3\times12=36,3\times36=108,\ldots\)Therefore, the next term will be, 108 x 3. That is,
\(\text{NEXT}=3\times NOW\)OPtion a is correct.
Brenda records 76 songs on 4 albums
Answer:
The answer would be 19!
Hope this helps, please mark me brainliest
i would assume this is asking how many songs are on each album? in which case 76 (total songs) divided by 4 (total albums) equals 19, so there are 19 songs on each album. hope this helped! <3
a. Find m
b. you write the measures of
Write each expression as a single logarithm. log3 9 + log3 24
Answer: log3 (216)
Step-by-step explanation:
What is the solution to the equation? 98 g = 150 98 g = 150. 98 98 g = 150 minus 98. t = 52. 98 g = 150. 98 minus 98 g = 150 minus 98. t = 52. 98 g = 150. 98 98 g = 150 98. t = 52. 98 g = 150. 98 minus 98 g = 150 98. t = 148.
What is the solution to the equation 98 g = 150 98 g = 150. 98 98 g = 150 minus 98. t = 52. 98 g = 150. 98 minus 98 g = 150 minus 98. t = 52. 98 g = 150. 98 98 g = 150 98. t = 52. 98 g = 150. 98 minus 98 g = 150 98. t = 148.the equation 98 g = 150 is g = 1.53.
To solve for g, we need to isolate it on one side of the equation. We can do this by dividing both sides by 98.
98 g = 150
98 g/98 = 150/98
g = 1.53
Therefore, the solution to the equation is g = 1.53.
Conclusion: The solution to the equation 98 g = 150 is g = 1.53.
Main Answer: The correct equation to solve is 98g = 150. To find the solution, we need to isolate g by dividing both sides of the equation by 98.
1. Start with the given equation: 98g = 150
2. To isolate g, divide both sides by 98: g = 150 / 98
The solution to the equation 98g = 150 is g ≈ 1.53 (rounded to two decimal places).
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2. What is the 20th term of the arithmetic sequence?
2, 10, 18, 26,...
Answer:
154
Step-by-step explanation:
The difference is 8.
What is the inverse of function g(x) = -x-2/x+4 ? G^-1(x)=
Answer:
Step-by-step explanation:
Given the following information for a hypothetical economy, answer the questions that follow. C=200+0.8Yd I=150
G=100
X=100
M=50 Income taxes =50 Where C is consumption, Y d is the disposable income, 1 is investmer S government purchases, X is exports, and M is the imports A. Calculate the level of equilibrium (GDP) or Y. B. Calculate the disposable income C. Using the value of the expenditure multiplier, the Calculate new level of Y,
The level of equilibrium (GDP) or Y in the hypothetical economy is 600.
To calculate the equilibrium level of GDP, we need to equate aggregate expenditure to GDP. The aggregate expenditure (AE) is given by the formula AE = C + I + G + (X - M), where C is consumption, I is investment, G is government purchases, X is exports, and M is imports.
Given the values:
C = 200 + 0.8Yd
I = 150
G = 100
X = 100
M = 50
We can substitute these values into the AE formula:
AE = (200 + 0.8Yd) + 150 + 100 + (100 - 50)
AE = 450 + 0.8Yd
To find the equilibrium level of GDP, we set AE equal to Y:
Y = 450 + 0.8Yd
Since Yd is the disposable income, we can calculate Yd by subtracting income taxes from Y:
Yd = Y - taxes
Yd = Y - 50
Substituting this into the equation for AE:
Y = 450 + 0.8(Y - 50)
Now we solve for Y:
Y = 450 + 0.8Y - 40
0.2Y = 410
Y = 410 / 0.2
Y = 2050
Therefore, the equilibrium level of GDP (Y) is 600.
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