Write as a product
1-25x^2+10xy-y^2

Please help with explanation
Will award brainliest.

Answer:

1.3

Step-by-step explanation:

Hope this is correct, if not sorry

The recursive formula for Lindsey's scores is aₙ = aₙ₋₁ \(\times\) r, and the explicit formula is aₙ \(= 67 \times r^{(n-1).\)

To find the recursive and explicit formulas for the given geometric sequence, let's analyze the pattern of Lindsey's scores.

From the given information, we can observe that Lindsey's scores are increasing at the same rate.

This suggests that the scores form a geometric sequence, where each term is obtained by multiplying the previous term by a common ratio.

Let's denote the first term as a₁ = 67 and the common ratio as r.

Recursive Formula:

In a geometric sequence, the recursive formula is used to find each term based on the previous term. In this case, we can write the recursive formula as:

aₙ = aₙ₋₁ \(\times\) r

For Lindsey's scores, the recursive formula would be:

aₙ = aₙ₋₁ \(\times\) r

Explicit Formula:

The explicit formula is used to directly calculate any term of a geometric sequence without the need to calculate the previous terms.

The explicit formula for a geometric sequence is:

aₙ = a₁ \(\times r^{(n-1)\)

For Lindsey's scores, the explicit formula would be:

aₙ \(= 67 \times r^{(n-1)\)

In both formulas, 'aₙ' represents the nth term of the sequence, 'aₙ₋₁' represents the previous term, 'a₁' represents the first term, 'r' represents the common ratio, and 'n' represents the term number.

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Answer:

The answer is 3.

Step-by-step explanation:

In order to get 5 as the denominator, you would divide 25 by 5. Hence, you would do the same to the numerator. 15 divided by 5 equals three.

Hope this helps! Stay safe! So cool that you live in the UK!

xx gloriouspurpose xx

p.s. from america lol

5>-4  i think i cant seeeeeee it man

Answer:

x 4/5 - 3.5

Step-by-step explanation: I honestly dont know if this is right

The minimum score required for a letter of recognition is approximately 28.1 (rounded to one decimal place).

The minimal rating required for a letter of recognition, we want to locate the rating that corresponds to the pinnacle 11% of the distribution.

The z-score that corresponds to the pinnacle 11% of the distribution.

A trendy everyday distribution desk or calculator to discover this value:

P(Z > z) = 0.11

From the table, we discover that the z-score that corresponds to a cumulative likelihood of 0.11 is about 1.22.

Next, we can use the formulation for standardizing a score:

z = (x - μ) / σ

Rearranging this formula, we can remedy for x:

x = z × σ + μ

Substituting the values given in the problem, we get:

x = 1.22 × 5.3 + 21.3

x = 28.066

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To find the median of the random variable with the given probability density function f(x) = 0.09e^(-0.09x) on the interval [0, +∞), we need to determine the value of x at which the cumulative distribution function (CDF) reaches 0.5. The median represents the point at which half of the probability is below and half is above.

The probability density function (PDF) f(x) describes the relative likelihood of the random variable taking on different values. In this case, the PDF is given by f(x) = 0.09e^(-0.09x) on the interval [0, +∞).

To find the median, we need to calculate the cumulative distribution function (CDF), which represents the accumulated probability up to a certain point. The CDF is found by integrating the PDF from the lower bound of the interval to x. In this case, the CDF is given by F(x) = ∫[0, x] (0.09e^(-0.09t)) dt.

We need to find the value of x for which F(x) = 0.5, as the median represents the point where half of the probability is below and half is above. Solving the equation F(x) = 0.5 will give us the median value for the random variable.

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♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

\(3y = 2x - 3\)

Divide sides by 3

\( \frac{3}{3} y = \frac{2}{3} x - \frac{3}{3} \\ \)

\(y = \frac{2}{3}x - 1 \\ \)

This is the slope-intercept form of the given line.

The coefficient of x in slope-intercept form of the linear functions shows the slope .

Thus the slope of the given line is ⅔ .

_________________________________

Remember from now on ;

Multiply of the slopes of the lines which are perpendicular to each other equals -1.

Suppose the slope of the line which question asked is m .

So :

\( \frac{2}{3} \times m = - 1 \\ \)

Multiply sides by 3

\(3 \times \frac{2}{3} \times m = 3 \times ( - 1) \\ \)

\(2m = - 3\)

Divide sides by 2

\( \frac{2}{2} m = \frac{ - 3}{2} \\ \)

\(m = - \frac{3}{2} \\ \)

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

\(y - 6 = - \frac{2}{3}(x - 0) \\ \)

\(y = - \frac{2}{3} x + 6 \\ \)

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Two questions about systems aaa and bbb, the given system is:

System aaa: x = -1/3 and y = -7/3
System bbb: x = -1/3 and y = -7/3

To answer two questions about systems aaa and bbb, let's first clarify the given system:

System aaa:
x - 4y = 9

System bbb:
2x + y = -3

Question 1: Solve system aaa.
To solve system aaa, we'll use the method of substitution:

Step 1: Solve one equation for one variable.
From the first equation in system aaa, we can isolate x:
x = 4y + 9

Step 2: Substitute the expression from Step 1 into the other equation.
Substitute the expression for x in the second equation of system aaa:
2(4y + 9) + y = -3

Step 3: Simplify and solve for y.
8y + 18 + y = -3
9y + 18 = -3
9y = -3 - 18
9y = -21
y = -21/9
y = -7/3

Step 4: Substitute the value of y into the expression for x.
Using the first equation in system aaa:
x - 4(-7/3) = 9
x + 28/3 = 9
x = 9 - 28/3
x = (27 - 28)/3
x = -1/3

Therefore, the solution to system aaa is x = -1/3 and y = -7/3.

Question 2: Solve system bbb.
To solve system bbb, we'll use the method of substitution:

Step 1: Solve one equation for one variable.
From the second equation in system bbb, we can isolate y:
y = -2x - 3

Step 2: Substitute the expression from Step 1 into the other equation.
Substitute the expression for y in the first equation of system bbb:
x - 4(-2x - 3) = 9

Step 3: Simplify and solve for x.
x + 8x + 12 = 9
9x + 12 = 9
9x = 9 - 12
9x = -3
x = -3/9
x = -1/3

Step 4: Substitute the value of x into the expression for y.
Using the second equation in system bbb:
y = -2(-1/3) - 3
y = 2/3 - 3
y = 2/3 - 9/3
y = -7/3

Therefore, the solution to system bbb is x = -1/3 and y = -7/3.

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Using the t-distribution, as we have the standard deviation for the sample, the 95% confidence interval is (71.63, 84.36).

The confidence interval is:

\(\overline{x} \pm t\frac{s}{\sqrt{n}}\)

In which:

The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 4 - 1 = 3 df, is t = 3.1824.

The parameters are given as follows:

\(\overline{x} = 78, s = 10, n = 4\)

Hence, the bounds of the interval are given by:

\(\overline{x} - t\frac{s}{\sqrt{n}} = 78 - 3.1824\frac{10}{\sqrt{4}} = 71.63\)

\(\overline{x} + t\frac{s}{\sqrt{n}} = 78 + 3.1824\frac{10}{\sqrt{4}} = 84.36\)

The 95% confidence interval is (71.63, 84.36).

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Answer:

(62.09, 93.91)

Step-by-step explanation:

The correct answer on Khan

Answer:

See below ~

Step-by-step explanation:

Given : 3 angles of a Δ

Solving :

Finding the angles

To determine if the polynomial is even, odd, or neither, we substitute -x for x in the polynomial and simplify. -3(-x)² + 6(-x) = -3x² - 6x. Since the polynomial is not equal to its negation, it is neither even nor odd.

To write the equation of the line with an x-intercept at -6 and a y-intercept at 2, we can use the slope-intercept form of a line, y = mx + b, where m is the slope and b is the y-intercept.

In this case, the y-intercept is given as 2, so the equation becomes y = mx + 2. To find the slope, we can use the formula (y2 - y1) / (x2 - x1) with the given points (-6, 0) and (0, 2). We find that the slope is 1/3. Thus, the equation of the line is y = (1/3)x + 2.

For the polynomial f(x) = -3x² + 6x, the degree is 2 and the leading coefficient is -3. The end behavior of the graph is determined by the degree and leading coefficient. Since the leading coefficient is negative, the graph will be "downward" or "concave down" as x approaches positive or negative infinity.

To find the zeros, we set the polynomial equal to zero and solve for x. -3x² + 6x = 0. Factoring out x, we get x(-3x + 6) = 0. This gives us two solutions: x = 0 and x = 2.

The x-intercept is the point where the graph intersects the x-axis, and since it occurs when y = 0, we substitute y = 0 into the polynomial and solve for x. -3x² + 6x = 0. Factoring out x, we get x(-3x + 6) = 0. This gives us two x-intercepts: (0, 0) and (2, 0).

To determine if the polynomial is even, odd, or neither, we substitute -x for x in the polynomial and simplify. -3(-x)² + 6(-x) = -3x² - 6x. Since the polynomial is not equal to its negation, it is neither even nor odd.

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The function that models the temperature of the room over time is:

y = 67   for t < 0

y = 0.2t + 67  for 0 ≤ t ≤ 25

y is unknown   for t > 25 (cooling period, without specific information)

To model the temperature of the room over time, we can define a piecewise function that represents the behavior of the furnace turning on and off.

Let's denote y as the temperature of the room and t as the time in minutes.

For t < 0 (before the furnace turns on), the temperature remains constant, so we can set y = 67° as the initial temperature.

For 0 ≤ t ≤ 25 (while the furnace is running), the temperature increases linearly from 67° to 72° over the 25-minute duration. We can use the equation of a line to represent this increase:

y = mt + b

Since the temperature starts at 67° (when t = 0) and reaches 72° (when t = 25), we have two points on the line: (0, 67) and (25, 72). Using these points, we can find the slope (m) and y-intercept (b) of the line.

m = (y2 - y1) / (t2 - t1) = (72 - 67) / (25 - 0) = 5 / 25 = 0.2

Using the point-slope form of a linear equation, we can write the equation of the line as:

y - 67 = 0.2t

Simplifying, we get:

y = 0.2t + 67

For t > 25 (when the furnace is off), the temperature starts to cool down. Since the problem does not provide specific information about the cooling rate, we cannot determine a specific function for this period. We can assume that the temperature gradually decreases over time, but without further information, we cannot determine the exact form of this function.

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Answer: The weight of one person is 22 units and the other is 110 units.

Step-by-step explanation:

Let x = weight of one person, then the weight of the other person = 5x

According to the question,

Sum of weight of both persons = 132

⇒ x+ 5x = 132

⇒ 6x = 132

Divide both sides by 6 , we get

x= 22

Other [person's weight = 5(22) = 110 units.

Hence, the weight of one person is 22 units and the other is 110 units.

Answer:

$300

Step-by-step explanation:

1/4of $1800=$450-$150=$300

If we randomly select someone who was aboard the titanic, what is the probability that person is a man, given that he died is 1360/1517.

Probability is a way to gauge how likely something is to happen. Many things are difficult to forecast with absolute confidence. Using it, we can only make predictions about the likelihood of an event happening, or how likely it is. Probability can vary from 0 to 1, with 0 being an impossibility and 1 denoting a certainty. For pupils in Class 10, probability is a crucial subject since it teaches all the fundamental ideas of the subject. One is the probability of every event in a sample space.

Probability that person is a man, given that he died,

P(x) = Favorable outcome/Total

= 1360/ 1517.

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With the help of factorisation we can conclude our answer.

acc to our question-

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Answer:

x = 12.48

Step-by-step explanation:

Simplifying

12(x + -13) = 13(12 + -1x)

Reorder the terms:

12(-13 + x) = 13(12 + -1x)

(-13 * 12 + x * 12) = 13(12 + -1x)

(-156 + 12x) = 13(12 + -1x)

-156 + 12x = (12 * 13 + -1x * 13)

-156 + 12x = (156 + -13x)

Solving

-156 + 12x = 156 + -13x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '13x' to each side of the equation.

-156 + 12x + 13x = 156 + -13x + 13x

Combine like terms: 12x + 13x = 25x

-156 + 25x = 156 + -13x + 13x

Combine like terms: -13x + 13x = 0

-156 + 25x = 156 + 0

-156 + 25x = 156

Add '156' to each side of the equation.

-156 + 156 + 25x = 156 + 156

Combine like terms: -156 + 156 = 0

0 + 25x = 156 + 156

25x = 156 + 156

Combine like terms: 156 + 156 = 312

25x = 312

Divide each side by '25'.

x = 12.48

Simplifying

x = 12.48

Answer:

x=72±2180313=72±21803√13

Step-by-step explanation:

Answer:

9 x

Step-by-step explanation:

Simplify the following:

((3^4/3^0)^2 x)/(3^6)

Hint: | Compute 3^6 by repeated squaring. For example a^7 = a a^6 = a (a^3)^2 = a (a a^2)^2.

3^6 = (3^3)^2 = (3×3^2)^2:

((3^4/3^0)^2 x)/((3×3^2)^2)

Hint: | Evaluate 3^2.

3^2 = 9:

((3^4/3^0)^2 x)/((3×9)^2)

Hint: | Multiply 3 and 9 together.

3×9 = 27:

((3^4/3^0)^2 x)/(27^2)

Hint: | Evaluate 27^2.

| 2 | 7

× | 2 | 7

1 | 8 | 9

5 | 4 | 0

7 | 2 | 9:

((3^4/3^0)^2 x)/729

Hint: | For all exponents, a^n/a^m = a^(n - m). Apply this to 3^4/3^0.

Combine powers. 3^4/3^0 = 3^(4 + 0):

((3^4)^2 x)/729

Hint: | For all positive integer exponents (a^n)^m = a^(n m). Apply this to (3^4)^2.

Multiply exponents. (3^4)^2 = 3^(4×2):

(3^(4×2) x)/729

Hint: | Multiply 4 and 2 together.

4×2 = 8:

(3^8 x)/729

Hint: | Compute 3^8 by repeated squaring. For example a^7 = a a^6 = a (a^3)^2 = a (a a^2)^2.

3^8 = (3^4)^2 = ((3^2)^2)^2:

(((3^2)^2)^2 x)/729

Hint: | Evaluate 3^2.

3^2 = 9:

((9^2)^2 x)/729

Hint: | Evaluate 9^2.

9^2 = 81:

(81^2 x)/729

Hint: | Evaluate 81^2.

| | 8 | 1

× | | 8 | 1

| | 8 | 1

6 | 4 | 8 | 0

6 | 5 | 6 | 1:

(6561 x)/729

Hint: | In (x×6561)/729, divide 6561 in the numerator by 729 in the denominator.

6561/729 = (729×9)/729 = 9:

Answer:  9 x

Answer:

9

Step-by-step explanation:

\( {3}^{ - 6} {\bigg( \frac{ {3}^{4} }{ {3}^{0} } \bigg)}^{2} \\ \\ = {3}^{ - 6} {\bigg( \frac{ {3}^{4} }{ 1 } \bigg)}^{2} ( \because \: {a}^{0} = 1) \\ \\ = {3}^{ - 6} {( {3}^{4} )}^{2} \\ \\ = {3}^{ - 6} {3}^{8} \\ \\ = {3}^{ - 6 + 8} \\ \\ = {3}^{2} \\ \\ = 9\)

(1,2,4)

Range describes the y-values of a graph.

Range

Range is the y-values that a graph covers. Remember that the y-values are found on the vertical axis. If the graph is not continuous, then the values between the points are not included in the range. Similar to the range, the domain of a graph is the x-values that a graph covers. If there is a coordinate point with a y-value, then that y-value should be included in the range.

Finding Range

In order to find the range, we need to find all the unique y-values of the graph. Additionally, the range is given in numerical order. This means starting from the least value and going up to the greatest. The lowest y-value is 1, then 2, and finally 4. Even though there are two points where y = 2, we are only looking for unique values. This means that the range is (1,2,4).

Answer:

The scale factor of a dilation is 3.

Step-by-step explanation:

Given the length ST of the rectangle RSTU

The length ST of the rectangle = 8 units

It is clear that the corresponding length S'T' = 23 is 3 times the length of the original length ST = 8

i.e.

S'T' = 3(ST)

S'T' = 3(8)      ∵ ST = 8

S'T' = 24

It indicates that the RSTU has been dilated by a scale factor of 3.

As the scale factor 3 > 1, it also indicates that the dilated rectangle R'S'T'U is enlarged.

Therefore, the scale factor of a dilation is 3.

Answer: b. The perimeter of a square in relation to the side length.

I hope this helps you :)

With 99% confidence, we estimate that the difference in proportions of drivers without a violation in the first five-year period between those who took a driver's ed course and those who did not is between -0.069 and 0.229.

To construct a 99% confidence interval for the difference in proportions between drivers who had taken a driver's ed course and those who had not, we can use the formula for the confidence interval for the difference in two proportions:

CI = (p1 - p2) ± Z * sqrt((p1 * (1 - p1) / n1) + (p2 * (1 - p2) / n2))

where p1 and p2 are the sample proportions, n1 and n2 are the sample sizes, and Z is the critical value corresponding to the desired confidence level.

In this case, for drivers who had taken a driver's ed course:

p1 = 96/120 = 0.8 (proportion without violation)

n1 = 120 (sample size)

For drivers without a driver's ed course:

p2 = 72/100 = 0.72 (proportion without violation)

n2 = 100 (sample size)

Now we need to determine the critical value, Z, for a 99% confidence level. The critical value corresponds to the desired significance level (1 - confidence level) and depends on the sampling distribution, which in this case is the standard normal distribution. For a 99% confidence level, the significance level is 1 - 0.99 = 0.01. Consulting a standard normal distribution table or using statistical software, we find that the critical value for a 99% confidence level is approximately 2.576.

Now we can substitute the values into the formula:

CI = (0.8 - 0.72) ± 2.576 * sqrt((0.8 * (1 - 0.8) / 120) + (0.72 * (1 - 0.72) / 100))

Calculating the values within the square root:

CI = 0.08 ± 2.576 * sqrt((0.8 * 0.2 / 120) + (0.72 * 0.28 / 100))

CI = 0.08 ± 2.576 * sqrt(0.00133 + 0.002016)

CI = 0.08 ± 2.576 * sqrt(0.003346)

CI = 0.08 ± 2.576 * 0.05782

CI = 0.08 ± 0.149

Finally, the confidence interval for the difference in proportions is:

CI = (0.08 - 0.149, 0.08 + 0.149)

CI = (-0.069, 0.229)

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answer y = -222 when x = 74

Step-by-step explanation:

84 / -252 = 74 / y

84y = (-252)(74)

84y = -18,648

   y =  -18,648 / 84

   y = - 222

answer y = -222 when x = 74

Answer:

Step-by-step explanation:

Answer:

men=150

women=250

total=400

Step-by-step explanation:

a) fraction of men

men/total=150/400=15/40

men/total =3/8

b)let married be x

so unmarried wil be 250-x

married/unmarried=3/2

x / 250-x =3/2

x =3(250-x)/2

2x =750-3x

5x=750

x=750/5

x =150

married =150

unmarried=250-150=100

c)20% of men will be :20x150

100

: 30

no of men =150+20%

=150+30

=180

d)no. of women decreased=250-60

=190

percentage of women leaved=% x 250

100

190x100/250=%

76 =%

76% women leaved

It took too much time

MARK ME BRAINLIEST THANKS MY ANSWER PLEASE

DO FOLOW

we can use the proportion: (Number of votes received by the candidate) / (Total number of votes) = 43% / 100%. the candidate received approximately 37.41 votes.

In the given local election, the candidate received 43% of the votes. To determine the number of votes they obtained, we need to use a proportion. A proportion is an equation that states that two ratios are equal.

Let's represent the number of votes received by the candidate as "x." The total number of votes cast in the election is stated as 87.

We can set up the proportion:

x / 87 = 43% / 100.

To solve for "x," we can cross-multiply:

100 * x = 43% × 87.

Simplifying further, we have:

x = (43/100) × 87.

By multiplying the fraction (43/100) by 87, we can determine the number of votes received by the candidate. Evaluating this expression, the candidate received approximately 37.41 votes.

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The equivalent expression of the expression given as 1/x/x+3 is 1/x(x+3)

The expression is given as:

1/x/x+3

Rewrite as:

1/x/x+3 = (1/x)/x+3

Express the quotient as product

1/x/x+3 = 1/x * 1/x+3

Evaluate the product

1/x/x+3 = 1/x(x+3)

Hence, the equivalent expression of the expression given as 1/x/x+3 is 1/x(x+3)

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73% of mature maple trees are between 60 and 90 feet. The required percentage is 73%

Given that the heights of mature maple trees are approximately normally distributed with a mean of 80 feet and a standard deviation of 12.5 feet.

The formula for the z-score is given by:

z = (X - μ)/σ, where X = 60, μ = 80, and σ = 12.5

Substitute the values, we get

z = (60 - 80) / 12.5

= -1.6

The z-score for 60 feet is -1.6.

The formula for the z-score is given by:z = (X - μ)/σ, where X = 90, μ = 80, and σ = 12.5

Substitute the values, we get

z = (90 - 80) / 12.5= 0.8

The z-score for 90 feet is 0.8.

To find the proportion of mature maple trees between 60 and 90 feet, we need to find the area under the standard normal curve between z = -1.6 and z = 0.8.

Using the standard normal distribution table or calculator, we can find the area under the curve as follows:

Area = 0.7881 - 0.0516= 0.7365

Therefore, the proportion of mature maple trees between 60 and 90 feet is 73% (rounded to the nearest whole percent).

Hence, the correct answer is option (D).

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Answer

The average rate of change of the function y = 18 on the interval [1000, 10,000] is ZERO

SOLUTION

Problem Statement

The question wants us to find the average rate of change of the function y = 18 on the interval [1000, 10,000].

Method

- The function given is a constant function. This means that for every value of x from -∞ to +∞, the value of the function will always be y = 18.

- Since y is a function of x (albeit a constant function of x), it can be written as y = f(x).

- With these in mind, we can find the average rate of change of the function using the formula given below:

- Note that since the function is a constant function, we should expect that its rate of change should be ZERO since the function is constant throughout despite the value of x.

Let us apply the formula above to find the average rate of change of the given function.

Implementation

The average rate of change of the function y = 18 is gotten below:

Final Answer

The average rate of change of the function y = 18 on the interval [1000, 10,000] is ZERO