write the net ionic equation for the acid-base hydrolysis equilibrium that is established when ammonium nitrate is dissolved in water. (use h3o instead of h .)

Answer:

Question: What are ways static electricity can be created?

1. friction

2. induction

3.  Static cling

4. lightning

Answer: hope this helps :)

Explanation:

Heterogeneous:

soy sauce, pizza, fruit salad, halo halo, iced mango juice (assuming this is a mango milkshake), sago milk tea

Homogeneous:

vinegar, salt solution, sugar syrup

abno ka hahaha hatdog hamburger

260grams

The formula for calculating the moles of NaOH is expressed as

Determine the required mass of NaOH

Hence the grams of sodium hydroxide (NaOH) you need to make 6.5 L of 1.0M solution is 260grams

Answer

Ethanol and Ethylene Glycol

Procedure

Hydrogen bonding occurs when hydrogen forms a molecular bond with a highly electronegative element such as Oxygen, Nitrogen, and Fluorine. Based on the structure of the molecules we can see that ethane does not contain the previously mentioned elements, therefore it will not form hydrogen bonds. Dimethyl ether has an oxygen atom located in the middle of the molecule, making it difficult to form a bond with other dimethyl ether molecules.

Lastly, Ethanol and Ethylene Glycol possess OH groups which are free to interact with similar groups via hydrogen bonding. Additionally, these last compounds exhibit higher boiling points, which can indicate a stronger intermolecular bonding, which is a characteristic of hydrogen bonding.

Answer:Donates a hydrogen ion

Explanation:

Answer:

A gas is most soluble in water under conditions of high pressure, and low temperature.

Option b-A The isotope ⁷₂H (7He) is more tightly bound than ⁵₂H (5He).

The stability of an isotope depends on its binding energy, which represents the amount of energy required to break apart the nucleus into its constituent particles. Higher binding energy indicates greater stability and tighter binding of nucleons within the nucleus.

To determine which isotope is more tightly bound, we compare their binding energies. The binding energy is related to the mass defect, which is the difference between the sum of the masses of the individual nucleons and the actual mass of the nucleus.

In this case, the atomic mass of ⁷₂H (7He) is 7.027991 u, and the atomic mass of ⁵₂H (5He) is 5.012057 u. The greater the mass defect, the more tightly bound the nucleus. Since the mass defect of ⁷₂H (7He) is greater than that of ⁵₂H (5He), it implies that ⁷₂H (7He) has a higher binding energy and is more tightly bound.

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Answer:

What would be the likely outcome if you increased the concentration of substrate for an enzyme in the presence of a noncompetitive inhibitor? No change in enzyme activity would be observed.

Explanation:

The Iupac Name of given three compounds are 3,4,5-trimethylheptane, 2,2,3,3-tetramethylpentane and 2,2- dimethyl-3-ethylpentane.

For (1),

The longest straight chain have 7 carbon compound and having single bond, suffix of this compound is Heptane. Now there are three functional group of methyl there for prefix is trimethyl. Overall the name of compound is 3,4,5-trimethylheptane.

The longest straight chain have 5 carbon compound and having single bond, suffix of this compound is pentane. Now there are four functional group of methyl there for prefix is tetramethyl. Overall the name of compound is 2,2,3,3-tetramethylpentane.

The longest straight chain have 5 carbon compound and having single bond, suffix of this compound is pentane. Now there are three functional group of methyl and ethyl so they write according to alphabetic order. Overall the name of compound is 2,2- dimethyl-3-ethylpentane.

Thus, we concluded that the The Iupac Name of given three compounds are 3,4,5-trimethylheptane, 2,2,3,3-tetramethylpentane and 2,2- dimethyl-3-ethylpentane.

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In the recrystallization process, a short stem funnel is necessary when filtering out solids that did not dissolve upon heating because it helps to minimize the loss of the solution.

A short stem funnel has a smaller surface area, which reduces the amount of solution that can adhere to the funnel walls and be lost during the filtration process. Additionally, a short stem funnel allows for faster filtration, which also helps to minimize the loss of the solution.

Overall, the use of a short stem funnel in the recrystallization process helps to maximize the yield of the purified compound.

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It is possible to recover 44.01 g of iron from a 115 g sample of Fe2(CO3)3.

We need to first calculate the molar mass of Fe2(CO3)3.

The formula below can be used to determine the molar mass of Fe2(CO3)3:

2 x atomic mass of Fe + 3 x (atomic mass of C + 3 x atomic mass of O)

= 2 x 55.85 g/mol + 3 x (12.01 g/mol + 3 x 16.00 g/mol)

= 2 x 55.85 g/mol + 3 x (12.01 g/mol + 48.00 g/mol)

= 2 x 55.85 g/mol + 3 x 60.01 g/mol

= 2 x 55.85 g/mol + 180.03 g/mol

= 291.73 g/mol

Therefore, the molar mass of Fe2(CO3)3 is 291.73 g/mol.

Next, we need to calculate the amount of Fe2(CO3)3 in moles, which can be calculated as follows:

moles of Fe2(CO3)3 = mass of Fe2(CO3)3 / molar mass of Fe2(CO3)3

= 115 g / 291.73 g/mol

= 0.394 mol

Finally, we may use stoichiometry to determine the weight in grams of iron. We know that there are two moles of Fe for every one mole of Fe2(CO3)3 based on the chemical formula for Fe2(CO3)3. Consequently, the quantity of iron in moles is:

moles of Fe = 2 x moles of Fe2(CO3)3

= 2 x 0.394 mol

= 0.788 mol

The molar mass of iron is 55.85 g/mol. Therefore, the mass of iron in grams is:

mass of Fe = moles of Fe x molar mass of Fe

= 0.788 mol x 55.85 g/mol

= 44.01 g

Therefore, It is possible to recover 44.01 g of iron from a 115 g sample of Fe2(CO3)3.

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Answer:

A link is a fastening unit that attaches two parts of an object together

Different types of links have different characteristics

Answer:

Linking is the process of combining all the component object files. The linker determines where the code will reside in memory and how control will transfer between the components.

Minerals can be located using geochemical surveys and remote sensors that analyze satellite images. Following that, mining or quarrying is used to remove many minerals.

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The term defined as the fundamental particles of protons and neutrons is nucleons and the correct option is option B.

Nucleons include both protons and neutrons, which are the primary constituents of atomic nuclei. Electrons, on the other hand, are negatively charged particles that orbit the nucleus. Molecules are formed by the bonding of atoms, and quarks are elementary particles that combine to form nucleons.

Atoms with the same number of protons but different numbers of neutrons are called isotopes. They have almost similar chemical properties but are different in mass and therefore in physical properties.

Thus, the ideal selection is option B.

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Answer:

211.0

Explanation:

∆G(free energy) = ∆H(enthalpy) - T∆S(entropy)

∆H = 215KJ/mol

T = 90°C = 273 + 90

= 363K

∆S = 11J/mol/K or 11 × 10^-3kJ/mol/K

∆G = 215- 363(11 × 10^-3)

= 215 - 3.993

= 211.007

To the nearest tenth 211.0

While naming a compound, the less electronegative element is written first in the formula.

Generally, the less electronegative element is written first while writing the formula, though there are a few exceptions. Basically, carbon is always written first in a formula and hydrogen is after nitrogen in a formula such as NH₃. The common order of common non-metals in binary compound formulas is C, P, N, H, S, I, Br, Cl, O, F.

Generally, electronegativity is defined as a chemical property which describes the tendency of an atom or a functional group to attract electrons toward itself. The electronegativity of an atom is basically affected by both its atomic number and the distance that its valence electrons reside from the charged nuclei. And the more electronegative element is written in the first name of the compound.

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Answer:

When no coefficient is written in front of a formula it is assumed to be 1. 4. Numbers appearing in the formulas are known as subscripts. These can never be changed when balancing the equation or you will change the identity of the substance.

Explanation:

1. Reactants go on the left hand side and products go on the right hand side of a chemical equation. Be sure to write the correct formulas for the reactants and products.

· Remember atoms are conserved in a chemical reaction. ie they are neither created or destroyed. So all the atoms in the reactants must end up somewhere among the products.

2. Count the number of atoms of each element, compound or ion in the reactants and products. If they are not equal proceed further.

3. Balance the atoms one at a time by placing coefficients in front of the formula so that the numbers of atoms of each element are equal on both sides of the equation. Remember atoms may exist in an element, compound or ion.

· It is usually easier to start with the atoms that occur in only one substance on each side of the equation.

· Balance the atoms that occur in compounds before attempting to balance atoms that occur in elemental form. e.g. H2, O2 or Cl2

· To make it easier if a polyatomic ion appears unchanged on both sides of the equation treat it as a whole unit.

· When no coefficient is written in front of a formula it is assumed to be 1.

4. Numbers appearing in the formulas are known as subscripts. These can never be changed when balancing the equation or you will change the identity of the substance.

· Remember with subscripts, any number to the right of parentheses multiplies each subscript within the parentheses.

eg Fe2(SO4)3 contains 2 Fe atoms, 3 S atoms and 12 O atoms.

5. Finally make sure that all the coefficients are in the smallest possible whole number ratio.

The number which we will never use as a coefficient in any chemical reactions are decimals and fractions.

Coefficients are the numbers which are written before any chemical entity of any chemical reaction.

Coefficients of any reaction will not be:

Coefficients are generally use for balancing the chemical reactions.

So, we will not use decimals and fractions as a coefficient.

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Electron pairs around a central atom arrange themselves so that they can be as far apart as possible from each other. The repulsion between negatively charged electrons pairs in bonds or as lone pairs causes them to spread apart as much as possible

Explanation:

Answer:

Energy = 3.77 × 10⁻²⁸ J; radio wave.

Explanation:

In order to calculate the energy of an electromagnetic wave given its frequency, we have to use the following formula:

\(\boxed{E = hf}\),

where:

• E = energy of wave

• h = Planck's constant (6.63 × 10⁻³⁴ m² kg / s)

• f = frequency of wave (5.68 × 10⁵ Hz)

Using the formula and information above, we can calculate the energy of the wave:

E = 6.63 × 10⁻³⁴  ×  5.68 × 10⁵

  = 3.77 × 10⁻²⁸ J

Therefore, the energy of the wave is 3.77 × 10⁻²⁸ J, and it is a radio wave, as radio waves have frequencies of magnitude 10⁴ to 10⁵ Hz.

Answer:

aswer is A

Explanation:

because the CL,K,AR is correct since it is order right

Answer:

Explanation:

1. Sodium

2. Ammonium Carbonate

3. Potassium phosphate

4. Calcium sulphate

5. Zinc nitrate

6. Iron(III) oxide-hydroxide

7. Aluminium phosphate

8.Cobalt(III) Carbonate

9. Iron(II) sulfate

10. Magnesium chloride

11. Nitric acid

Answer:

1. Sodium

2. Ammonium Carbonate

3. Potassium phosphate

4. Calcium sulphate

5. Zinc nitrate

6. Iron(III) oxide-hydroxide

7. Aluminium phosphate

8.Cobalt(III) Carbonate

9. Iron(II) sulfate

10. Magnesium chloride

11. Nitric acid

Explanation:

Because of our belief in the law of conservation of mass, it seems reasonable that matter cannot be created or destroyed, only changed in form or transferred from one substance to another.

This law is fundamental to our understanding of the physical world, and it has many practical applications in fields like chemistry, physics, and engineering. It helps us to predict the outcomes of chemical reactions, to balance equations, and to understand the behavior of materials under different conditions.

The law of conservation of mass is a fundamental principle that underlies much of what we know about the world around us, and it will continue to play an important role in scientific research and development for years to come.

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Explanation:

Electronic Configuration of First 30 Elements with Atomic Numbers

Atomic Number Name of the Element Electronic Configuration

18 Argon (Ar) [Ne] 3s2 3p6

19 Potassium (K) [Ar] 4s1

20 Calcium (Ca) [Ar] 4s2

21 Scandium (Sc) [Ar] 3d1 4s2

26 more rows

Explanation:

NUMBER ELEMENT ELECTRON CONFIGURATION

1 Hydrogen 1s1

2 Helium 1s2

3 Lithium [He]2s1

4 Beryllium [He]2s2

5 Boron [He]2s22p1

6 Carbon [He]2s22p2

7 Nitrogen [He]2s22p3

8 Oxygen [He]2s22p4

9 Fluorine [He]2s22p5

10 Neon [He]2s22p6

11 Sodium [Ne]3s1

12 Magnesium [Ne]3s2

13 Aluminum [Ne]3s23p1

14 Silicon [Ne]3s23p2

15 Phosphorus [Ne]3s23p3

16 Sulfur [Ne]3s23p4

17 Chlorine [Ne]3s23p5

18 Argon [Ne]3s23p6

19 Potassium [Ar]4s1

20 Calcium [Ar]4s2

Answer:

C. The molecules move slower

Explanation:

The correct order of reactivity towards electrophilic aromatic substitution is:

b.) Phenol > benzene > chlorobenzene > benzoic acid

Phenol is more reactive than benzene towards electrophilic substitution reactions due to the presence of the -OH group (hydroxyl group) attached to the benzene ring. The lone pair of electrons on the oxygen atom in the -OH group can donate electron density to the ring, making it more nucleophilic and facilitating electrophilic attack.

Benzene, although less reactive than phenol, can still undergo electrophilic substitution reactions due to its aromaticity and delocalized electron system.

Chlorobenzene is less reactive than both phenol and benzene because the chlorine atom is an electron-withdrawing group. It withdraws electron density from the benzene ring, making it less nucleophilic and less prone to electrophilic substitution.

Benzoic acid is the least reactive among the options given. The carboxylic acid group (-COOH) is an even stronger electron-withdrawing group than the chlorine atom in chlorobenzene. It further reduces the electron density on the benzene ring, decreasing its reactivity towards electrophilic substitution.

Therefore, the correct order of reactivity towards electrophilic substitution is option b.

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the complete question is:

The correct order of reactivity towards electrophilic aromatic substitution is?

a.) Benzene > phenol > benzoic acid > chlorobenzene

b.) Phenol > benzene > chlorobenzene > benzoic acid

c.) Chlorobenzene > benzoic acid > phenol > benzene

d.) Benzoic acid > chlorobenzene > benzene > phenol

The chemical barrier of the body that is deigned to help prevent infection is  saliva.

Saliva is a fluid made up of salivary glands in your mouth. It is mostly consists of water but also contains  white blood cells, epithelial cells, electrolytes and enzymes.

Saliva promotes the blood clotting process because it contains tissue factor. The enzyme lysozyme is present in different tissues and its purpose is to attack the cell walls of many bacteria, that helps against infection

Other than Saliva, Tears also contains lysozyme enzyme, so they can also aid in healing the wounds. However, doctors do not recommend these procedures because of various reasons.

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The pz and s orbitals of the carbon atoms can mix in ethylene but cannot do so in methane due to the difference in their molecular geometries and bonding.

In ethylene (\(C_{2} H_{4}\)), the carbon atoms are \(sp^{2}\) hybridized, meaning that one s orbital and two p orbitals (px and py) combine to form three  \(sp^{2}\) hybrid orbitals.

These hybrid orbitals are responsible for forming sigma bonds with the hydrogen atoms and the other carbon atom. The remaining pz orbital, which is not involved in the hybridization, is available to form a pi bond between the two carbon atoms.
In contrast, in methane (\(CH_{4}\)), the carbon atom is  \(sp^{3}\) hybridized. In this case, the carbon atom's s orbital and all three p orbitals (px, py, and pz) combine to form four \(sp^{3}\)  hybrid orbitals. These orbitals are used to form sigma bonds with the four hydrogen atoms. Since all of the orbitals are involved in hybridization, there is no pz orbital available to mix with an s orbital.
The difference in the hybridization of carbon orbitals in ethylene and methane is due to their distinct molecular geometries and bonding arrangements.

In ethylene, the carbon atoms can mix their pz and s orbitals, while in methane, this mixing does not occur.

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