Write the quadratic equation whose roots are 6 and 2 with leading coefficient of 5.

Answers

Answer 1

Given:

The roots of a quadratic equation are 6 and 2.

Explanation:

The factors of a quadratic with roots 6 and 2 are,

\((x-6)\text{ and (x}-2)\)

The quadratic equation can be expressed as product of two factors. So,

\(\begin{gathered} (x-6)(x-2)=0 \\ x\cdot x-6\cdot x-2\cdot x-6\cdot(-2)=0 \\ x^2-6x-2x+12=0 \\ x^2-8x+12=0 \end{gathered}\)

Since leading coefficient is 5. So multiply the quadratic equation by 5.

\(\begin{gathered} 5(x^2-8x+12)=5\cdot0 \\ 5x^2-40x+60=0 \end{gathered}\)

So answer is,

\(5x^2-40x+60=0\)


Related Questions

what is 3x4x19x39x4x9x11x10x20squared-10473408000 tee-hee

Answers

Answer:

A seizure and a half

Step-by-step explanation:

Answer:

495962981439552000

I will mark you brainiest!

Determine the MOST PRECISE name for the quadrilateral below.
A) rhombus
B) parallelogram
C) square
D) trapezoid
E) kite

I will mark you brainiest!Determine the MOST PRECISE name for the quadrilateral below.A) rhombusB) parallelogramC)

Answers

The answer is A, rhombus.

what is the inverse of equation x^2+4x+1 applying to a domain of [-2, infinity)?

Answers

Let \(f(x) = x^2+4x+1\). If \(f^{-1}(x)\) is the inverse of \(f(x)\), then

\(f\left(f^{-1}(x)\right) = x\)

We're told that \(f(x)\) has a domain of x ≥ -2, so the above can only be valid for \(f^{-1}(x)\ge-2\).

Evaluate the left side in this equation and solve for the inverse :

\(f^{-1}(x)^2 + 4f^{-1}(x) + 1 = x \\\\ f^{-1}(x)^2 + 4f^{-1}(x) + 4 = x + 3 \\\\ \left(f^{-1}(x) + 2\right)^2 = x + 3 \\\\\sqrt{\left(f^{-1}(x)+2\right)^2} = \sqrt{x+3} \\\\ \left|f^{-1}(x) + 2\right| = \sqrt{x+3}\)

Since \(f^{-1}(x)\ge-2\), or \(f^{-1}(x)+2\ge0\), by definition of absolute value we have

\(\left|f^{-1}(x)+2\right| = f^{-1}(x)+2\)

Then it follows that

\(f^{-1}(x) + 2 = \sqrt{x+3} \implies \boxed{f^{-1}(x) = \sqrt{x+3}-2}\)

let C be the curve y=5sqrtx for 1.1

let C be the curve y=5sqrtx for 1.1

Answers

We can integrate this S = 2π ∫(1.1 to 4.4) (5√(4x + 25))/(2√x) dx over the given interval (1.1 to 4.4) to find the surface area.

We can evaluate the integral using numerical methods or a calculator to find the final answer.

We have,

To find the surface area of the revolution about the x-axis of the function f(x) = 5√x over the interval (1.1 to 4.4), we can use the formula for the surface area of revolution:

S = ∫(a to b) 2πy√(1 + (f'(x))²) dx

In this case,

f(x) = 5√x, so f'(x) = (d/dx)(5√x) = 5/(2√x).

Let's calculate the surface area:

S = ∫(1.1 to 4.4) 2π(5√x)√(1 + (5/(2√x)²) dx

Simplifying the expression inside the integral:

S = ∫(1.1 to 4.4) x 2π(5√x)√(1 + 25/(4x)) dx

Next, we can integrate this expression over the given interval (1.1 to 4.4) to find the surface area.

To find the surface area of revolution about the x-axis of the function

f(x) = 5√x over the interval (1.1 to 4.4), we need to evaluate the integral:

S = ∫(1.1 to 4.4) 2π(5√x)√(1 + 25/(4x)) dx

Let's calculate the integral:

S = 2π ∫(1.1 to 4.4) (5√x)√(1 + 25/(4x)) dx

To simplify the calculation, let's simplify the expression inside the integral first:

S = 2π ∫(1.1 to 4.4) (5√x)√((4x + 25)/(4x)) dx

Next, we can distribute the square root and simplify further:

S = 2π ∫(1.1 to 4.4) (5√(4x + 25))/(2√x) dx

Thus,

We can integrate this expression over the given interval (1.1 to 4.4) to find the surface area.

We can evaluate the integral using numerical methods or a calculator to find the final answer.

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A to the power of 0 multiply by A to the power of 6

Answers

Answer:

just a

Step-by-step explanation:

because if you do anything times by zero, it is zero.

Answer:

A^6

Step-by-step explanation:

This is the answer bc A^0 would stay the same so you would adding the exponents when you multiply therefore it's A^6

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A rectangular prism has a length of 2 meters, a width of 4 meters, and a height of 2 meters.
What is the volume of the prism?
Enter your answer in the box as a simplified mixed number or a decimal.
Basic
4.07 Quiz: Finding the Volume of a Prism
7.

Answers

If a rectangular prism has a length of 2 meters, a width of 4 meters, and a height of 2 meters. The volume of the prism is 16 cubic meters.

How to find the volume of the prism?

The volume of a rectangular prism is given by the formula:

Volume = length x width x height

Substituting the given values, we get:

Volume = 2 meters x 4 meters x 2 meters

Simplifying this expression, we get:

Volume = 16 cubic meters

Therefore, the volume of the prism is 16 cubic meters.

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Little help? Need answers asap :D

Little help? Need answers asap :D

Answers

Answer: y=3/4x + 8

Step-by-step explanation:

Answer:

Step-by-step explanation:

slope (m) = \(\frac{3}{4}\)

y-intercept (c) = 8

Writing in slope intercept form , y = mx +c

y = \(\frac{3x}{4}\) + 8

Hope it helps:)

-3 -2 -1 0 1 2 3 4 How can you find the length of CD
Number line

-3 -2 -1 0 1 2 3 4 How can you find the length of CD Number line

Answers

Answer:

3

Step-by-step explanation:

Because C is 1 and D is 4, so 4-1=3.

Gerald has a punch bowl in the shape of a hemisphere as shown below.

One cup is equivalent to approximately 15 cubic inches. Which of the following is closest to the maximum number of cups the punch bowl can hold?

A. 60 cups
B. 45 cups
C. 30 cups
D. 18 cups

Gerald has a punch bowl in the shape of a hemisphere as shown below.One cup is equivalent to approximately

Answers

The closest to the maximum number of cups the punch bowl can hold is 30

How to determine the number of cups?

The given parameters are:

1 cup = 15 cubic inches

Diameter of bowl, d = 12 inches

The radius is the half of the diameter.

So, we have:

r = 6

The volume of the bowl is then calculated using:

\(V = \frac{2}{3}\pi r^3\)

This gives

\(V = \frac{2}{3}\pi * 6^3\)

Evaluate

V = 452.16

The maximum number of cups is then calculated using:

Cups = 452.16/15

Evaluate

Cups = 30.1444

Approximate

Cups = 30

Hence, the closest to the maximum number of cups the punch bowl can hold is 30

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EXPLORE
The distance that the light from a lighthouse can be seen from a boat on the water is
a function of the height of both the lighthouse and the viewer above the water level.
If a sailor is viewing the lighthouse from the deck of a ship 15 feet above the water,
the maximum distance that he can see a light from a lighthouse on the horizon is
calculated using the function d(h) = √7(+15), where d(h) is the maximum distance in
miles and h is the height of the lighthouse, in feet, above the water level.
4
1.
In the 1850s, planning began for a lighthouse at Bolivar Point, Texas. Local
mariners determined that the light from the lighthouse should be visible from
a boat 14 miles offshore. Write an equation that could be used to determine
required height of the lighthouse.
15=√ 7+15

Answers

The maximum distance that the sailοr can see frοm the deck οf the ship is 0 miles.

What is a functiοn?

A special kind οf relatiοn knοwn as a functiοn is οne in which each input has precisely οne οutput. In οther wοrds, the functiοn generates exactly οne value fοr each input value. Because οne is mapped tο twο different values, the abοve graph depicts a relatiοnship rather than a functiοn. Hοwever, if οne were instead mapped tο a single value, the relatiοnship mentiοned abοve wοuld becοme a functiοn.

Additiοnally, οutput values can be equal tο input values. We knοw that the square rοοt functiοn is an increasing functiοn, which means that the value οf the functiοn increases as the input value increases.

Therefοre, tο find the maximum value οf the functiοn, we need tο find the maximum value οf h.

Assuming that the lighthοuse is οn the hοrizοn, which is apprοximately 3 miles away, we can use the Pythagοrean theοrem tο find the height οf the lighthοuse:

\(h^2 = (3)^2 - (15)^2h^2 = 9 - 225h^2 = -216\)

Since we cannοt take the square rοοt οf a negative number, there is nο real height fοr the lighthοuse that wοuld make it visible frοm a ship 15 feet abοve the water level.

Therefοre, the maximum distance that the sailοr can see frοm the deck οf the ship is 0 miles.

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| 10x | > -2 ?
Solving absolute value equations and inequalities

Answers

The answer is x>−1/5 or x<1/5

Can you draw the reflection Across the y-axis of the attached image.

Can you draw the reflection Across the y-axis of the attached image.

Answers

Answer:

see graph

Step-by-step explanation:

A reflection across the y-axis means the point is equal but opposite distance from the y-axis. This has no change on the y-value of the point, because no matter the y-value, the point will still be the same distance from the y-axis. Long story short, if you're reflecting across the y-axis, change the sign of the x-coordinate. If you're reflecting across the x- axis, change the sign of the y-coordinate.

Can you draw the reflection Across the y-axis of the attached image.

Write the slope-intercept form of the equation of the line described. 10.) through: ( 5 , 5 ) , perpendicular to Y= -5x +3

Answers

To find the line equation perpendicular to the line equation y = -5x + 3, we need to know that the product of the slopes of two linear equation must be = -1. Then, the slope of the line perpendicular to y = -5x + 3 is:

m1 = -5x ---> m2 = 1/5, so m1 * m2 = -5 * 1/5 = -1.

As we can see, the new slope is the inverse and the reciprocal of the original slope.

Then, we have that passes through the point (5, 5). For this, we can use the Point-Slope Form of the line:

\(y-y_1=m(x-x_{1)}\)

Where, x1 = 5, and y1 = 5. Hence:

\(y-5=\frac{1}{5}(x-5)\Rightarrow y-5_{}=\frac{1}{5}x-1\Rightarrow y=\frac{1}{5}x-1+5\)

Therefore, the line is:

\(y=\frac{1}{5}x+4\)

Use the appropriate formula to find (a) the monthly (n=12) payment on a loan with the given conditions and (b) the total interest that will be paid during the term of the loan.$9,200 is amortized over 6 years at an interest rate of 6.6%(a) the monthly payment is?(b) total interest paid is?

Answers

We will solve as follows:

We have that the interest rate is 6.6%:

\(P=\frac{(Pv\cdot R)}{(1-(1+R)^{n-1}}\)

Here we have P the monthly payment, Pv is the Present value, R is the periodic interest rate(APR/n) n is the total number of interest periods, so:

\(P=\frac{(9200)(\frac{0.066)}{12})}{(1-(1+\frac{0.066}{12})^{11})})\Rightarrow P\approx155.09\)

So, the monthly payment is approximately $155.09.

And the total interest paid is given by:

\(I=N\cdot M-P\Rightarrow I=(155.09)(72)-9200=I=1965.33\)

3x+12y=-8 show ur work

Answers

Here is the attached image for the answer. If you write it in in slope-intercept form, y=mx+b. You will get the answer below in the attached image.

3x+12y=-8 show ur work

In the following image, segment BD bisects segment AC, and three triangles are similar: AABC~ AADB~ ABDC. Complete the two-column
proof of the Pythagorean theorem.

3: A. (AC)DC) + (AC)(CD) = (AC)AC) + (BC)BC)

B. (AC)(CD) + (AC)(AD) = (BC)BC) + (AB)AB)

C. (AB)(CB) + (AD)CD) = (AC)AC) + (BC)BC)

D. (AC)BC) = (AC)(AC) + (BC)BC)





5: A.angle bisector postulate
B. triangles
C. common line segment
D. segment addition postulate

In the following image, segment BD bisects segment AC, and three triangles are similar: AABC~ AADB~ ABDC.

Answers

1. The Fill ups are as follow:

AB² +  BC² = AC. AD + AC. CD

2. Segment addition postulate

What is Pythagorean theorem?

The relationship between the three sides of a right-angled triangle is explained by the Pythagoras theorem, commonly known as the Pythagorean theorem. The Pythagoras theorem states that the square of a triangle's hypotenuse is equal to the sum of its other two sides' squares.

Given:

BC/ AC = CD/ BC and AB/ AC = AD/ AB

Now, BC² = AC. CD  and AB² = AC. AD

Using, Addition Property of Equality

AB² +  BC² = AC. AD + AC. CD

and, AB² +  BC² = AC (AD + CD)  [factor]

AD + CD = AD (segment addition postulate)

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PLATO

i got it correct :)

In the following image, segment BD bisects segment AC, and three triangles are similar: AABC~ AADB~ ABDC.

A popular streaming service surveyed all of the students at a school about the number of TV shows they streamed
last Friday night, then recorded the results.
Let M = the number of TV shows streamed last Friday night.
Number of Shows Streamed
0
1
2
3
Probability
0.095 0.203 0.326 0.187
Calculate the median of M. Use the histogram to corroborate your choice of the distribution's shape.
Since the shape of the distribution for number of TV shows streamed is
we expect the median
to be
the mean number of TV-shows streamed. This is confirmed when we calculate the
median to be compared to the mean of 2.187 TV shows streamed. The shape of the histogram supports the
relationship of the mean and the median because the mean is
4
0.174
5
0.015

Answers

Answer:

Step-by-step explanation:

To find the median, we need to find the middle value when the data is arranged in increasing order. We can use the cumulative probability to do this:

Number of Shows Streamed Probability Cumulative Probability

0 0.095 0.095

1 0.203 0.298

2 0.326 0.624

3 0.187 0.811

Since the cumulative probability for 2 is the smallest value greater than 0.5, the median is 2. Therefore, the median number of TV shows streamed is 2.

The histogram appears to have a roughly symmetric shape, which supports the assumption that the distribution is approximately normal.

Question 25 Given that a: b = 8:5 and b: c = 3:4, find the ratio a: b: c Give your answer in its simplest form.​

Answers

Answer:

24 : 15 : 20

Step-by-step explanation:

express ratios in fractional form and express b and c in terms of a

\(\frac{a}{b}\) = \(\frac{8}{5}\) ( cross- multiply )

8b = 5a ( divide both sides by 8 )

b = \(\frac{5}{8}\) a

also

\(\frac{b}{c}\) = \(\frac{3}{4}\) ( cross- multiply )

3c = 4b ( divide both sides by 3 )

c = \(\frac{4}{3}\) b = \(\frac{4}{3}\) × \(\frac{5}{8}\) a = \(\frac{5}{6}\) a

Then

a : b : c

= a : \(\frac{5}{8}\) a : \(\frac{5}{6}\) a ( multiply each part by 24, the LCM of 8 and 6 )

= 24a : 15a : 20a ( divide each part by a )

= 24 : 15 : 20 ← in simplest form

What is the slope of the line parallel to y=2/5x+7?

Answers

2/5 is the slope of a line parallel to the given equation. for line to be parallel they will have the same slope and different y-intercepts


\( {x}^{2} - 4 \div x - 2\)

Answers

Step-by-step explanation:

\(\dfrac{x^2-4}{x-2}\)

Apply identity a²-b² = (a-b)(a+b)

So, it will be

\(\dfrac{(x-2)(x+2)}{x-2}\)

Where x-2 gets cancelled from numerator and denominator.

Hence, x+2 is the answer.

Hope it helps :)

Which is more less -300 or -23

Answers

Answer:

-300

Step-by-step explanation:

because is in the negative and is a number bigger than 23 but in negative.

identify the coeffecient and the exponent for each term of 6x^(3)-4x

Answers

Answer:

Read the steps

Step-by-step explanation:

In the first term: 6x^3

leading coeffecient: 6

exponent: 3

In the second term: -4x

leading coeffecient: -4

exponent: 1

The coefficient and exponents are -

\(6x^{3}\) :   coefficient = 6      exponent = 3

\(-4x\) :  coefficient = 4      exponent = 1

We have -

f(x) = \(6x^{3} - 4x\)

We have identify the coefficient and the exponent in the f(x).

Calculate the value of exponent if -  \(e^{a} = e^{2x - 4}\) at x = 5.

Here, the exponent is \(a\). Then -

a = 2x - 4

For x = 5

a = 2 x 5 - 4

a = 6

According to the question -

f(x) = \(6x^{3} - 4x\)

for \(6x^{3}\) :   coefficient = 6     exponent = 3

for \(-4x\) :  coefficient = 4      exponent = 1

Hence, the coefficient and exponents are -

\(6x^{3}\) :   coefficient = 6      exponent = 3

\(-4x\) :  coefficient = 4      exponent = 1

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For what value of 2 will the function f(x), be continuous at x=0?
(See Image) Thanks

For what value of 2 will the function f(x), be continuous at x=0?(See Image) Thanks

Answers

(i) \(\lim_{x \to \pi/3}\) f(x) = 1 + √3.

(ii) \(\lim_{x \to \frac{\pi}{4}} f(x)\) does not exist.

For λ = 2.5, the function f(x) will be continuous at x = 0.

Given the function is,

f(x) = 1.5, when x = 0

    = 1 -2 sin x, when x < π/4

    = 1 + 2 sin x, when x > π/4

    = 1 + (sin λx/sin 5x)

Now,

\(\lim_{x \to \pi/3}\) f(x) = \(\lim_{x \to \pi/3}\) (1 + 2 sin x) [Since, π/3 > π/4]

                    = 1 + 2 sin (π/3)

                    = 1 + 2√3/2 = 1 + √3

Hence, \(\lim_{x \to \pi/3}\) f(x) = 1 + √3.

Now left hand limit is,

\(\lim_{x \to \frac{\pi^+}{4}}\) f(x) = \(\lim_{x \to \frac{\pi^+}{4}}\) (1 + 2sin x) = 1 +2 sin(π/4) = 1 + 2*(1/√2) = 1 + √2

and right hand limit is,

\(\lim_{x \to \frac{\pi^-}{4}}\) f(x) = \(\lim_{x \to \frac{\pi^-}{4}}\) (1 - 2 sin x) = 1 - 2*(1/√2) = 1 - √2

Since left hand limit and right hand limit are not equal so value of \(\lim_{x \to \frac{\pi}{4}} f(x)\) does not exist.

\(\lim_{x \to 0}\) f(x) = \(\lim_{x \to 0}\) (1 + (sin λx/sin 5x)) = 1 + \(\lim_{x \to 0}\) ((sin λx/λx)/(sin 5x/5x))*(λ/5) = 1 + λ/5

Since f(x) is continuous at x = 0.

So, \(\lim_{x \to 0}\) f(x) = f(0)

1 + λ/5 = 1.5

λ/5 = 1.5 - 1 = 0.5

λ = 2.5

Hence the value of λ will be 2.5.

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Answer if you can and help other people out

Answer if you can and help other people out

Answers

Answer:131.964 cm

Solution,

radius=21 cm

Circumference of circle=2 pi r

=2*3.142*21

=131.964 cm

hope it helps

Good luck on your assignment

answer is 131.64
Radius is 21cm
2x3.142x21 = 131.64

A baker made two cakes of the same size.

Answers

Woah really!? That’s so cool

Complete this sequence of numbers such that the difference between any two adjacent numbers is the same : 3/k, _, _, 9/2k.

Answers

The completed sequence is: 3/k, 3/k, 3/k, 9/2k.To complete the sequence of numbers with a constant difference between adjacent numbers, we can calculate the common difference by subtracting the first term from the second term.

Let's denote the missing terms as A and B.

The given sequence is: 3/k, A, B, 9/2k.

The common difference can be found by subtracting 3/k from A or B. Therefore:

A - 3/k = B - A = 9/2k - B.

To simplify, we can equate the two expressions for the                     common difference:

A - 3/k = 9/2k - B.

Next, we can solve for A and B using this equation.

Adding 3/k to both sides gives:

A = 3/k + 9/2k - B.

Now, we can substitute the value of A into the equation:

3/k + 9/2k - B - 3/k = 9/2k - B.

Simplifying further, we have:

9/2k - 3/k = 9/2k - B.

Cancelling out the common terms, we find:

-3/k = -B.

Multiplying both sides by -1, we get:

3/k = B.

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If 400 x 300 = 120,000
And 40 x 30 is 1,200


Fill in the blanks and show your work
*_____ x ______ = 12,000?

Answers

Answer:

this list

Step-by-step explanation:

1×12000=12000

2×6000=12000

3×4000=12000

4×3000=12000

5×2400=12000

6×2000=12000

8×1500=12000

10 ×1200=12000

12 ×1000=12000

19. A square has an area of 448 square meters. 20
What is the length of each side of the
square?
49

Answers

Answer:

The length of each side is approximately 21.16

Step-by-step explanation:

Note: square is a equilateral shape

Area = 448

Let x represent one side of the square

448 = x • x

sqrt of 448 = x

x = 21.16

(b) find a 90% confidence interval estimate for the population mean using the student's t-distribution.round the final answers to two decimal places.

Answers

The 90 % confidence interval estimate for the population mean using the student's t-distribution is [ 87.137 , 92.863 ] .

Given :

Suppose that the times to complete an obstacle course are normally distributed with an unknown mean and standard deviation. A random sample of 33 course times is taken and gives a sample mean of 90 seconds and a sample standard deviation of 10 seconds.

a 90% confidence interval estimate for the population mean using the student's t-distribution.round the final answers to two decimal places.

Confidence interval :

CI = X ± Z * s / √n

= 90  ±  1.6449 * 10 / √33

= 90 ± 2.863

= [ 87.137 , 92.863 ]

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Full question:

is in the image uploaded.

(b) find a 90% confidence interval estimate for the population mean using the student's t-distribution.round

Find Matrix mixed questions

Find Matrix mixed questions

Answers

The only matrix that is certainly symmetric is a)\((a^2 - b^2).\)

We know that a matrix A is symmetric if it is equal to its transpose, that is \(A = A^T.\)

a) \((a^2 - b^2)\)

We can write the transpose of this matrix as

\((a^2 - b^2)^T = (a^2)^T - (b^2)^T = a^2 - b^2\), which is equal to the original matrix. Therefore, this matrix is symmetric.

b) (A+B)(A-B)

Expanding this expression, we get \((A+B)(A-B) = A^2 - AB + BA - B^2.\)

Taking the transpose of this, we get \((A^2)^T - (AB)^T + (BA)^T - (B^2)^T = A^2 - BA + AB - B^2.\)

Since AB and BA may not be equal, we cannot say for certain that this matrix is symmetric.

c) ABA

Taking the transpose of this matrix, we get\((ABA)^T = A^T B^T A^T\). Since \(A^T and B^T\) may not commute, we cannot say for certain that this matrix is symmetric.

d) ABAB

Taking the transpose of this matrix, we get \((ABAB)^T = B^T A^T B^T A^T\). Again, since \(A^T and B^T\) may not commute, we cannot say for certain that this matrix is symmetric.

Therefore, the only matrix that is certainly symmetric is a) \((a^2 - b^2).\)

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Other Questions
what are tasks performed by pascaline? Pls help will put brainliest Molly and James tracked the average temperature in their city for the past 8 days. They recorded their temperature findings in this list. 74F , 79F , 76F, 85F, 87F, 83F, 86F, 78F What is the mean absolute deviation of this data set? Enter your answer in the box. How is "transition scoring opportunity" defined for purposes of the clear path rule? Ms. Ivysaur, a resident citizen, had the following data for a calendar year:Regular wage P100,000Overtime pay 15,000Thirteenth month pay 15,500SSS, Medicare, PagibigContributions & labor unions 5,000How much is her tax due? Older adults make impressions influenced by __________ information they receive; younger adults make impressions based on the most ______________ information they have. Write the phrase as an expression.the product of 3 and 12An expression is explain why do we need to run a standard when we analyze the distillation mixture with gc in our lab setting (2 pts)? You have to work on Distributive property 12(y+2) Anne Katz, the owner of Katz Sport Shop, lends $8,000 to Shelley Slater to help her open an art shop. Shelley plans to repay Anne at the end of eight years with interest compounded semiannually at 8%. At the end of eight years, Anne will receive: Find the slope of each line Y=-5x-1 How does the author elaborate onthe events that happened between1955 and 1970 (9 points) Find the directional derivative of f(?, y, z) = rz+ y at the point (3,2,1) in the direction of a vector making an angle of 11 with Vf(3,2,1). fu= A security incident is currently occurring on the company network. You discover that the attack involves a computer system that is attached to the network. You're unsure what kind of damage is being done to the network systems or data.Which of the following actions should you take FIRST?-----------------------------------------------------------------------------Determine whether you have the expertise to conduct an investigation, or whether you need to call in additional help.Stop the attack and contain the damage by disconnecting the system from the network.Examine the active computer system to analyze the live network connection, memory contents, and running programs.Document and photograph the entire scene of the crime including the current state of the attached computer system dawg help meee !!!!!! ANYONE HAVE THE TIME TO READ THIS AND TELL ME WHAT TO DO TO IMPROVE? PLEASE IT WOULD MAKE MY DAY!!!!!!!*Snow Day**Bill 12 years old*Joe Bills friend 11 years old*SCENE 1*TIME, PLACE, BASIC SETTING, ETC.**Narrator,It was a cold winter morning in the middle of January our Characters Bill and Joe(they are BFs)are having fun during a snow day when they hear a loud noise.*Bill*What was that Noise?*Joe* I have no idea lets go find out.*Bill*Yeah it sounded like it came form the forest over there. Lets go!.*Narrator* The to children wonder into the woods in search of the noise they have heard.BANG!!!.*Bill* WHOA!!!!!!Joe* (Whispers) Be quite theres something up there.Bill* (Says in a low voice)Its an alien spaceship!*SCENE ENDS*Scene 2Bill* Lets hide behind this bush.*Joe.*Wow thats so weird are you sure?*Bill.*Im sure. (Whispers)Uh-oh I think the Alien heard us!Joe* What makes you think that?Bill* Look!Narrator* Joe looks over Bill to see the alien fitted in what looks like armor wobbles over to where they are hiding.Joe* We got to get out of here!!They Jump out of the bush and the alien looks frightened. It turns around and begins to run wabble away.Joe*Wait we didn't mean to scare you!!Bill* I think hes more afraid of us then we are of him.Joe* Yeah, but weve got to help him hes not from here.Bill* I agree and maybe we will be able to make this Duo a Trio.Joe*Agreed Lets go!Narrator* The Duo try to find clues on where the alien has went.Bill* Joe, its getting late and we cant find him.Joe*Here!! A footprint!Bill* Nice it looks like he went into the caveJoe*There he is! In the cave.Narrator* The boys Cautiously enters the cave where they hear a slight rumbling and a CRASH.Bill*(Coughs)Joe are you ok?Joe*(Wheezes) Yeah but I think the cave fell in.Bill* Yeah.Joe* Wheres the Alien?Bill* I think that he is on the other side of the wall.Joe*We have to save him!Bill* I know but its pitch black we are going to need to get supplies.Narrator* The boys return to Joes house where they go into Joes Bedroom Where they got 2 Flashlight Glowsticks and Walkie Talkies.Joe* I think that we are ready to save a alien!END OF ACT 2Scene 3Narrator*The Boys return to the cave to help the alien. While Joe goes on top of the hill where the entrance to the cave is located while Bill goes in the cave to try find an opening.Bill* I think that I may have found a small hole but I cant seem to slip through it.Joe* Ok Ill keep looking up here if I find any holes ill let you know.Bill* Ok, AHHHHHHH!!!!!!Joe* Bill? Bill! Are you ok!?!Bill* Yeah Yeah Im fine but there a bigger problem now.Joe*Whats That?Bill* The Aliens stuck under a rock!!(The alien squirms and wiggles but cant get free.)Joe*Hold on Im on my way!Narrator*Bill looks down at the alien and sees he wont survive much longer so Bill takes matters into his own hands.Bill* I have to save this alien!(Bill Puts his hand on each side of the rock and begins to pull as hard as he cans)Bill*(Grunts) Come On!!Narrator* The rock begins to rise slowly but Bills strength is fading.Bill*(Whimpers) I cant hold it much longerJoe* Hang in there Im on my way!(The alien sees the effort and determination in Bills face and begins to help in the lifting of the rock)Bill* All..most..there..Narrator*As Bill and the alien strain to lift the Huge rock Joe runs as fast as he could to get back to where the where and just as the had used the last amount of there strength trying to lift the rock.Joe leaps into action and with there combined strength the alien shimmies out of underneath the rock. And with a loud thud the rock falls. But everything beings to shake For The cave is CAVING IN!!Bill* (Yells) WEVE GOT TO GET OUT OF HERE!!Joe*WE WILL NEVER MAKE IT!(The alien grabs the two boys and takes off running bolt at top speed out of the cave just as the roof falls in. The alien sets them down and bows as if it was saying thank you.)Bill*(Pants)Whoa what just happened?Joe*(Mumbles) I have no idea.(The alien looks at the two boys and pats them gently and there heads. As if he was saying Good Bye. The alien bolts out of sight and soon they see the alien ship fly over there heads out into the unknown universe.)Bill* The alien saved our lives.Joe* Yeah.(As they talk about what has just happened something falls from the sky)(Clash!)Bill* What is it?Joe*Its a figurine...an alien figurine. But what does it mean?Bill*I think it means never to forgetJoe* Yeah, Ill never forget today.Narrator* They boys pretured from the forest and walk toward the sunset arms hung over one another toward the place they call home.Bill*Yeah, me neither. But we can both agree it was a great snow day.*MOVIE/PLAY ENDS* Drag and drop the letters to correctly match them with the colonies they label on this map. For each right triangle below, find the missing side (Pythagoreans Theorem) and the missing angle (Angle Sum theorem.) La Semana Santa A) En Honduras es una fiesta patronal que se llama la feria de San Isidro.El festival de Tinku B) Bolivia es una celebracin del inca, pero no es religiosa.El festival de los voladores C) En Mxico es una celebracin durante las Pascuas.El carnaval de Ceiba D) En Guatemala los descendientes de los aztecas tienen una fiesta patronal. Who owns Champs in State College?