Answer:
q = 367 + c
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The volume of a large tank is 210 ft3. It is 5 3/5
ft wide and 1 4/5
ft high. What is the length of the tank?
Answer:
20 5/6 ft
Step-by-step explanation:
5 3/5 = 28/5
1 4/5 = 9/5
V = l * w * h
210 = l * 28/5 * 9/5
210 = l * 252/25
multiply both sides by 25/252
5250/25 = l
Reduce
20 5/6 = l
20 5/6 ft
Which of the following functions exhibit the end behavior f(x) —>infinite as x—> -infinite and f(x) —> -infinite as x—>infinite? Select all that apply. Please help me out! Nobody wants to help :(
The end behavior f(x) → ∞ as x → -∞ means that x-value is negative and y-value is positive. If this is the case, the other end part of the function is located in the 2nd quadrant.
The end behavior f(x) → -∞ as x → ∞ means that the x-value is positive and the y-value is negative. The other end part of the function is located in the 4th quadrant.
Looking at the choices, Option 1 and 4 exhibits these characteristics.
Under what circumstances is a score that is located 5 points above the mean a central value, relatively close to the mean?
a. When the population standard deviation is much less than 5
b. When the population mean is much less than 5
c. When the population mean is much greater than 5
d. When the population standard deviation is much greater than 5
The circumstance that the score is located 5 points above the mean a central value, relatively close to the mean is when the population standard deviation is much greater than 5.
What is the standard deviation?Standard Deviation is a measure which shows how much variation (such as spread, dispersion, spread,) from the mean exists. The standard deviation indicates a “typical” deviation from the mean. It is a popular measure of variability because it returns to the original units of measure of the data set.
Here, we have
The circumstance is a score that is 5 points above the mean considered a central value.We have to find under what circumstances is a score that is 5 points above the mean considered a central value--meaning it is relatively close to the mean.
We concluded from the above statement that when the population standard deviation is much greater than 5.
Hence, when the population standard deviation is much greater than 5 then, the score that is 5 points above the mean is considered a central value.
Therefore, the correct option is D.
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given the points (2,k) and (0,-6) for whick values of k would the distance between points sqaure root of 5
Given the points (2, k) and (0, -6), and the distance is √5
The distance between two points is calculated by the formula:
\(\begin{gathered} d=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2} \\ \text{where,} \\ (x_1,y_1)=(2,k) \\ (x_2,y_2)=(0,-6) \\ d=\sqrt{5} \end{gathered}\)Hence,
\(\begin{gathered} \sqrt[]{5}=\sqrt[]{(-6-k)^2+(0-2)^2} \\ \sqrt[]{5}=\sqrt[]{(-6-k)^2+(-2)^2} \\ \sqrt[]{5}=\sqrt[]{(-6-k)^2+4} \\ \text{squaring both sides} \\ 5=(-6-k)^2+4 \\ (-6-k)(-6-k)+4=5 \\ 36+6k+6k+k^2+4=5 \\ k^2+12k+36+4-5=0 \\ k^2+12k+35=0 \\ \text{factorize completely,} \\ (k^2+5k)+(7k+35)=0 \\ k(k+5)+7(k+5)=0 \\ (k+7)(k+5)=0 \\ k+7=0 \\ k=-7 \\ k+5=0 \\ k=-5 \end{gathered}\)Therefore, the values of k would be -5 or -7 [option A is correct]
How to add scientific notation with different exponents.
To add scientific notation with different exponents, you need to adjust the exponents so that they are equal. Once the exponents are aligned, you can add or subtract the corresponding coefficients.
First, identify the numbers in scientific notation that you want to add. Let's say you have two numbers, A and B, expressed in scientific notation as A x 10^n and B x 10^m, where n and m are the exponents.
To add these numbers, you need to adjust one of them so that the exponents are the same.
Choose the number with the smaller exponent and multiply both its coefficient and exponent by the appropriate power of 10 to match the exponent of the other number.
For example, if n < m, you would multiply number A by \(10^{m-n}\), which means multiplying the coefficient of A by \(10^{m-n}\) and keeping the exponent of 10 as n.
Once the exponents are aligned, you can add or subtract the coefficients of the adjusted numbers.
This will give you the final result in scientific notation.
It's important to note that if the exponents are significantly different, adjusting the exponents may involve multiplying or dividing by large powers of 10, which can affect the precision of the final result.
Therefore, it's advisable to retain the appropriate number of significant figures in your calculations.
In summary, to add scientific notation with different exponents, you adjust one of the numbers by multiplying its coefficient and exponent by an appropriate power of 10 to match the exponent of the other number.
Then, you can add or subtract the coefficients and express the result in scientific notation.
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help
Simplify the ratio of 0,5 kg: 250 g
Answer:
2:1
Step-by-step explanation:
.5 kg : 250g
the units must be same at both sides
500g : 250g
{as 1 kg = 1000g}
by simplifying both sides
10g : 5g
2g : 1g
2:1
each side of a square is increasing at a rate of 2 cm/s. at what rate (in cm2/s) is the area of the square increasing when the area of the square is 64 cm2?
At 32 cm^2/s rate the area of the square is increasing when the area of the square is 64 \(cm^{2}\)
As per given problem each side of a square is increasing at a rate of 2 cm/s. let side of square is x.so the area of it is A= \(x^{2}\).now differentiating w.r.t time A
\(\frac{dA}{dt}\)= 2x\(\frac{dx}{dt}\)
when A=64 \(cm^{2}\) x=8 cm
also given \(\frac{dx}{dt}\)=2cm/s
so \(\frac{dA}{dt}\)=2×2×8=32
So at 32 cm^2/s rate the area of the square is increasing when the area of the square is 64 \(cm^{2}\)
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Excision of benign lesions on chest, 0.4 cm, with simple closure.(CPT CODE??)
Excision of
benign lesions
on chest, 0.4 cm, with simple closure(CPT CODE)CPT code is a five-digit numeric code that is used to describe medical, surgical, and diagnostic procedures.
The CPT code for the Excision of benign lesions on chest, 0.4 cm, with simple closure is 11400. The CPT code 11400 is used to report the removal of benign lesions or skin tags. It is a
surgical
procedure performed to remove a benign lesion, which is a tumor that is not
cancerous
.
The
excision
of benign lesions is performed for a variety of reasons, including cosmetic purposes, symptom relief, or to prevent the
lesion
from becoming cancerous. Excision of benign lesions on chest, 0.4 cm, with simple closure is a minor surgical procedure that can be performed in an outpatient setting.
The simple closure refers to the wound closure technique, where the edges of the incision are brought together and closed with sutures or staples. A simple closure is used when the wound is small and does not require extensive tissue
rearrangement
or grafting. The excision of benign lesions on the chest, 0.4 cm, with simple closure is performed to remove a benign lesion or tumor from the chest area that measures 0.4 cm in size.
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A right triangle has side lengths d, e, and f as shown below.
Use these lengths to find sinx, cox, and tanx.
To accurately calculate the values of sinx, cosx, and tanx we use trigonometric functions.
To find sin(x), cos(x), and tan(x) in a right triangle with side lengths d, e, and f, we first need to identify which sides are opposite, adjacent, and hypotenuse relative to angle x. Let's assume that side d is opposite to angle x, side e is adjacent to angle x, and side f is the hypotenuse.
Now, we can use the definitions of the trigonometric functions:
1. sin(x) = opposite/hypotenuse = d/f
2. cos(x) = adjacent/hypotenuse = e/f
3. tan(x) = opposite/adjacent = d/e
These are the expressions for sin(x), cos(x), and tan(x) in terms of the given side lengths d, e, and f.
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What is the product of 0.04 and 0.2?
A:0.008
B:0.81
C:0.08
D:0.8
Answer:
A. 0.008
I hope this helps!
Answer:
A. 0.008
Step-by-step explanation:
Product mean you multiply, so you multiply 0.04 and 0.2 and you get 0.008
0.04 x 0.2 = 0.008
pleaseeeeee helpppppppp asappppp! thank you!
Answer:
\(2x^3+x^2-8x-4=(2x+1)(x+2)(x-2)\)
Step-by-step explanation:
Let's collect \(x^2\) between the first two terms, and -4 between the last two:
\(2x^3+x^2-8x-4=x^2(2x+1) -4 (2x+1)\)
At this point you should see there is a common factor\(2x+1\)between both terms, then let's collect that:
\(2x^3+x^2-8x-4=x^2(2x+1) -4 (2x+1) = (2x+1)(x^2-4)\)
Final step is recognizing a difference of squares (x and 2) in the second bracket, to end up our work!
\(2x^3+x^2-8x-4=x^2(2x+1) -4 (2x+1) = (2x+1)(x^2-4) =(2x+1)(x+2)(x-2)\)
Step-by-step explanation:
\(f(x) = {2}^{3} + {x}^{2} - 8x - 4\)
\( {x}^{2} (2x + 1) - 2(2x + 1) = 0\)
\((2x + 1)( {x}^{2} - 2)\)
\(x = \frac{ - 1}{2} \\ x = \sqrt{2} \)
hope it's helpful
Cans of wood varnish come in three sizes.
Small can: A 200 ml can costs £0.88.
Medium can: A 500 ml can costs £1.32.
Large can: A 1 litre can costs £3.60.
Calculate the cost of 1 litre for the small and medium cans.
Give your answer in pounds to 2 dp.
The cost of 1 liter for the small and medium cans is 4.4 and 2.4.
What is Unitary method?The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.
As,
Small can: A 200 ml can costs £0.88.
Medium can: A 500 ml can costs £1.32.
Large can: A 1 litre can costs £3.60.
Now, 200 ml = 0.2 l
500 ml = 0.5 l
For 0.2 l = 0.88
For 1 l= 0.88/0.2
For 1 liter = 4.4
For 0.5l medium can = 1.32
For 1 l medium can= 1.32/0.5
For 1 l medium can = 2.4
Hence, cost of 1 liter for the small can is £ 0.88 the cost of 1 liter for the medium can is £ 2.4.
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the roots of the equation X square + 2 X + 4 = 2 are necessarily what
Answer:
-1±i
Step-by-step explanation:
Im assuming the question is asking what the roots of x^2+2x+4=2 are.
1. x^2+2x+4= 2 - subtract 2 on both sides to set the quadratic equation equal to zero.
2. x^2+2x+2 - now, since this equation cannot be factored the quadratic formula must be used: -b±\(\frac{\sqrt{b^{2}-4ac}}{2a}\) (standard form: ax^2+bx+c)
3. -2±\(\sqrt{2^{2}-4(1)(2) }\)/2(1)= (-2±\(\sqrt{-4}\))/2
4. using complex numbers this can be rewritten as -1±i.
Which type of factoring is used to factor the following expression:
2x^2 + 7x- 30
Answer:
(2x - 5) • (x + 6)
In ANOP, the measure of P=90°, NO = 72 feet, and PN = 43 feet. Find the measure of 20 to the nearest degree.
The given figure and terms are used in this solution to determine the measure of 20 to the nearest degree:
In ANOP, the measure of P=90°, NO = 72 feet, and PN = 43 feet.
Find the measure of 20 to the nearest degree.
To solve the given problem, we'll use the Pythagorean theorem and trigonometric ratios.
Here's how we do it:
According to the Pythagorean Theorem, we know that OQ² = PQ² + OP²
Therefore, OQ² = 43² + 72²OQ² = 6409OQ = √6409OQ = 80.1
Therefore, the value of 20 can be calculated using the following formula:
tan 20° = PQ / OQ
PQ / OQ = tan 20°
PQ / 80.1 = tan 20°
PQ = 80.1 * tan 20°
PQ = 29.24 feet
Therefore, the value of the measure of 20 is 20°.
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Garlan makes a commission based upon the value of all he sells at his new job. For example in 30 minutes of his first workday, he earned $15 in commission for selling $150 worth of shoes.
100 POINTS PLEASE PLEASE HELP I NEED THE ANSWER ASAPP ;(
Answer:
y < -1/4 x +1
Step-by-step explanation:
Find two points on the dotted line
( 0,1) and (4,0)
We can use the slope formula
m = ( y2-y1)/(x2-x1)
= (0-1)/(4-0)
= -1/4
The slope is -1/4
The y intercept is where it crosses the y axis or 1
The equation of the line, using slope intercept form
y = mx+b
y = -1/4x +1
The line is dotted which means there is no equals, just greater than or less than. It is shaded below which means less than
y < -1/4 x +1
Answer:
\(y<-\frac{1}{4}x+1\)
Step-by-step explanation:
First, let's find the equation of the line.
From the graph, we can pick out two points to use: (0,1) (the y-intercept) and (4,0) (the x-intercept).
Find the slope. Let (0,1) be x₁ and y₁ and let (4,0) be x₂ and y₂
Find the slope:
\(m=\frac{y_2-y_1}{x_2-x_1}\)
Substitute:
\(m=\frac{0-1}{4-0}\\m=-1/4\)
Use the slope-intercept form:
\(y=mx+b\)
Where m is the slope and b is the y-intercept.
We already know the slope is -1/4 and the y-intercept is 1. So, substitute:
\(y=-\frac{1}{4}x+1\)
Now, replace the equal sign with an inequality. Note that the line is dotted, so we won't use "or equal to." Also note that the blue, shaded area is below the line. Thus, we will use less than. Therefore:
\(y<-\frac{1}{4}x+1\)
The sentences:
First, we picked out two points from the graph. Next, we used those two points to find the slope. We used the slope and one of the points to write our slope-intercept equation. Afterwards, we can determine from the graph that since the shaded area is below the dotted line, the equation must have a less than.
Solve the system of equations.
14x + 5y = 31
2x – 3y = -29
2 =
y =
Answer:
X,y=83/52 ,45/26
Step-by-step explanation:
just look up your answer and you will find the step by step. Hopefully this helped :)
Given the function h(x), find the value of h(-2). h(x) = x² + 4x - 7
Step-by-step explanation:
\({ \tt{h(x) = {x}^{2} + 4x - 7 }}\)
Substitute for x as -2;
\({ \tt{h( - 2) = {( - 2)}^{2} + 4( - 2) - 7}} \\ \\ { \tt{h( - 2) = 4 - 8 - 7}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ { \tt{h( - 2) = - 11}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \)
Answer:-9
Step-by-step explanation:
h(-2)=h(x)
it symbolize that x=-2;
so, we'll replace every x with -2:
-2^2+3*(-2)-7=4-6-7=-9
What is the slope of the line that passes through the points (-10,-8) and (-8,-16)? Write your answer in simplest form. Please help
Answer:
You can use the distance formula to find the slope. The distance formula is Y2-Y1/X2-X1. So, -16-(-8)/-8-(-10)=-8/2=-4. The slope of the line is -4.
:)
The graph shows the speed of an
airplane during a trip from City X to City Z.
a. Compare the intervals where the function is increasing.
b. Compare the intervals where the function is decreasing.
Speed
Time
From the given graph, the overall interval of function is increasing = [0,2] U [4, 5] & the function is decreasing in interval [6.5, 9.5].
What are graphs?Graphs are used by mathematicians to logically express or chart facts or values visually. A graph point often depicts the connection between two or more things. The nodes, often referred to as vertices, and edges that make up a graph are non-linear data structures. Glue ought to be used to join the nodes, also known as vertices. In this graph, the vertex numbers are 1, 2, 3, and 5, whereas the edge numbers are 1, 2, 1, 3, 2, 4, and (2.5). (4.5). graphics that graphically represent exponential growth in statistical charts like bar graphs, pie charts, and line graphs. the logarithmic graph with a triangle shape.
A function's rising or falling trend can be identified using any interval in the derivative's domain. if at then f′(x) > 0
A function's rising or falling trend can be identified using any interval in the derivative's domain. The function is considered to be rising on I if f′(x) > 0 at any point within the interval I. If f′(x) 0 occurs at every point along an interval I, the function is said to be dropping along that interval.
For the given graph,
the function is increasing in interval [0,2]
the function is constant in interval [2,4]
then again increasing in interval [4, 5]
the function is constant in interval [5, 6.5]
the function is decreasing in interval [6.5, 9.5]
So, the overall interval of function is increasing = [0,2] U [4, 5]
the function is decreasing from [6.5, 9.5]
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Please answer! It’s due today!!
Answer:
6
Step-by-step explanation:
what's the perimeter of the isoceles triangle shown below?
Answer:
16
Step-by-step explanation:
by using pythagorean theorem we know that the equal sides of the isosceles triangle are 5 units in length while the bottom side appears to be 6 units in length.
so we the perimeter is 16
Hi everyone,Can someone please help me please please I really really need help please answer it correct
Answer:
0<x<3
4<x<6
9<x<10
..........
Answer:
Hope it helps you
Step-by-step explanation:
Decreasing: A function is decreasing, if as x increases (reading from left to right), y decreases. In plain English, as you look at the graph, from left to right, the graph goes down-hill. The graph has a negative slope
So in given graph ,
Decreasing interval are ,
1) 9<x<10
2) 0<x<3
I done it using above definition you also check it from any other source and confirm it ..
The Brennan Aircraft Division of TLN Enterprises operates a large number of computerized plotting machines. For the most part, the plotting devices are used to create line drawings of complex wing airfoils and fuselage part dimensions. The engineers operating the automated plotters are called loft lines engineers. The computerized plotters consist of a minicomputer system connected to a 4- by 5-foot flat table with a series of ink pens suspended above it When a sheet of clear plastic or paper is properly placed on the table, the computer directs a series of horizontal and vertical pen movements until the desired figure is drawn. The plotting machines are highly reliable, with the exception of the four sophisticated ink pens that are built in. The pens constantly clog and jam in a raised or lowered position. When this occurs, the plotter is unusable. Currently, Brennan Aircraft replaces each pen as it fails. The service manager has, however, proposed replacing all four pens every time one fails. This should cut down the frequency of plotter failures. At present, it takes one hour to replace one pen. All four pens could be replaced in two hours. The total cost of a plotter being unusable is $50 per hour. Each pen costs $8. If only one pen is replaced each time a clog or jam occurs, the following breakdown data are thought to be valid: Hours between plotter failures if one pen is replaced during a repair Probability 10 0.05 20 0.15 30 0.15 40 0.20 50 0.20 60 0.15 70 0.10 Based on the service manager’s estimates, if all four pens are replaced each time one pen fails, the probability distribution between failures is as follows: Hours between plotter failures if four pens are replaced during a repair Probability 100 0.15 110 0.25 120 0.35 130 0.20 140 0.00 (a) Simulate Brennan Aircraft’s problem and determine the best policy. Should the firm replace one pen or all four pens on a plotter each time a failure occurs?
To determine the best policy for Brennan Aircraft's plotter pen replacement, we can simulate the problem and compare the expected costs for both scenarios: replacing one pen or replacing all four pens each time a failure occurs.
Let's calculate the expected costs for each scenario:
Replacing one pen:
We'll calculate the expected cost per hour of plotter failure by multiplying the probability of each failure duration by the corresponding cost per hour, and then summing up the results.
Expected cost per hour = Σ(Probability * Cost per hour)
Expected cost per hour = (10 * 0.05 + 20 * 0.15 + 30 * 0.15 + 40 * 0.20 + 50 * 0.20 + 60 * 0.15 + 70 * 0.10) * $50
Expected cost per hour = $39.50
Replacing all four pens:
We'll calculate the expected cost per hour using the same method as above, but using the probability distribution for the scenario of replacing all four pens.
Expected cost per hour = (100 * 0.15 + 110 * 0.25 + 120 * 0.35 + 130 * 0.20 + 140 * 0.00) * $50
Expected cost per hour = $112.50
Comparing the expected costs, we can see that replacing one pen each time a failure occurs results in a lower expected cost per hour ($39.50) compared to replacing all four pens ($112.50). Therefore, the best policy for Brennan Aircraft would be to replace one pen each time a failure occurs.
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The width of a rectangle measures (9v-5w) centimeters, and its length measures (9v+6w) centimeters. Which expression represents the perimeter, in centimeters, of the rectangle? 1+18v 2+36v Submit Answ
The perimeter of a rectangle is given by the formula:
Perimeter = 2 * (length + width)
In this case, the width of the rectangle is (9v - 5w) centimeters and the length is (9v + 6w) centimeters.
Substituting the values into the formula, we have:
Perimeter = 2 * ((9v - 5w) + (9v + 6w))
Simplifying the expression inside the parentheses:
Perimeter = 2 * (18v + w)
Distributing the 2 to both terms inside the parentheses:
Perimeter = 36v + 2w
Therefore, the expression that represents the perimeter of the rectangle in centimeters is 36v + 2w.
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12.4. draw the hasse diagram for the diagonal relation on s = {x,y,z}
. There are no other edges or lines connecting the nodes since the diagonal relation only holds for the self-loops.
To draw the Hasse diagram for the diagonal relation on the set S = {x, y, z}, we need to represent the elements of S as nodes and draw an upward-directed line between two nodes if and only if the diagonal relation holds between them.
In this case, the diagonal relation states that an element is related to itself. Therefore, each element in S will have a self-loop.
The Hasse diagram for the diagonal relation on S = {x, y, z} would look like this:
x
/ \
y z
In this diagram, each element (x, y, and z) is represented as a node, and there is a self-loop on each node since each element is related to itself in the diagonal relation
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A probability experiment is conducted. Which of these cannot be considered a probability outcome? A.0.64 B.-0.6 C.27% D. 1/2 E.0 F.1 G. 1.49 H. 130% I. -1/3 J. none of the above
The probability outcome that cannot be considered a probability outcome is B. -0.6.
This is because probabilities cannot be negative. All other options can be considered as probabilities, as they fall within the range of 0 to 1, or 0% to 100%. Remember that in a probability experiment, the probability of an event occurring is always between 0 and 1, or 0% and 100%. A probability of 0 means that the event will not occur, while a probability of 1 or 100% means that the event will definitely occur. Any value outside of this range is not a valid probability.
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help me please, im trying to get all my missing assignments innn
Answer:
A"= -5,2
B"= -6,-1
C"= -4,0
(I think these are right)
Answer:
A=(5,2)
B=(5,1)
C= (3,0)
Step-by-step explanation:
Given (x) = -x+2 and g(x)=2x^2-3x, determine an explicit equation for each composite function, then state its domain and range.
a) f(g(x))
b) g(f(x))
c) f(f(x))
d) g(g(x))
Explicit equation for each composite functions are:
a) f(g(x)) = -2x² + 3x + 2
b) g(f(x)) = 2x² - 7x + 6
c) f(f(x)) = x - 2
d) g(g(x)) = 2x^4 - 12x^3 + 21x² - 12x + 4
a) To find f(g(x)), we substitute g(x) into the function f(x). Given that f(x) = -x + 2 and g(x) = 2x² - 3x, we replace x in f(x) with g(x). Thus, f(g(x)) = -g(x) + 2 = - (2x² - 3x) + 2 = -2x² + 3x + 2.
The domain of f(g(x)) is the same as the domain of g(x), which is all real numbers. The range of f(g(x)) is also all real numbers.
b) To determine g(f(x)), we substitute f(x) into the function g(x). Given that
g(x) = 2x²- 3x and f(x) = -x + 2, we replace x in g(x) with f(x). Thus, g(f(x)) =
2(f(x))² - 3(f(x)) = 2(-x + 2)² - 3(-x + 2) = 2x² - 7x + 6.
The domain of g(f(x)) is the same as the domain of f(x), which is all real numbers. The range of g(f(x)) is also all real numbers.
c) For f(f(x)), we substitute f(x) into the function f(x). Given that f(x) = -x + 2, we replace x in f(x) with f(x). Thus, f(f(x)) = -f(x) + 2 = -(-x + 2) + 2 = x - 2.
The domain of f(f(x)) is the same as the domain of f(x), which is all real numbers. The range of f(f(x)) is also all real numbers.
d) To find g(g(x)), we substitute g(x) into the function g(x). Given that g(x) = 2x² - 3x, we replace x in g(x) with g(x). Thus, g(g(x)) = 2(g(x))² - 3(g(x)) = 2(2x² - 3x)² - 3(2x²- 3x) = 2x^4 - 12x^3 + 21x² - 12x + 4.
The domain of g(g(x)) is the same as the domain of g(x), which is all real numbers. The range of g(g(x)) is also all real numbers.
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