write the symbol for an atom or ion with three electrons, three protons, and five neutrons.

The treatment for magnesium poisoning involves slowly injecting 10mL of calcium gluconate (2.2mmol of calcium in a 10mL vial; formerly known as 10% solution) into the vein over the course of 10 minutes.

What are the symptoms and treatment for magnesium sulfate toxicity?

Early symptoms of magnesium toxicity include nausea, feeling heated, flushing, somnolence, double vision, slurred speech, and weakness. The first sign of magnesium toxicity is typically the loss of patellar reflexes, which happens with serum magnesium levels of 9 mg/dl to 12 mg/dl.

What symptoms indicate toxicity from magnesium sulfate?

Keep an eye out for the warning signs and symptoms of magnesium sulfate toxicity, such as hypotension, areflexia (loss of DTRs), respiratory depression and arrest, oliguria, shortness of breath, chest pains, slurred speech, hypothermia, confusion, and circulatory collapse.

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Answer: number of electron in respective sub shell or orbital

Explanation:

In an electron configuration, the superscripts (written as numbers above the orbital symbols) represent the number of electrons present in each orbital. They indicate the distribution of electrons among different energy levels and sublevels within an atom.

Superscripts are characters or numbers that are positioned slightly above the normal line of text. They are typically smaller in size and are used to indicate various types of information or formatting in written text.

The superscripts are determined based on the rules of filling electron orbitals, such as the Pauli exclusion principle and Hund's rule. These rules govern the arrangement of electrons in the orbitals according to their energy levels and sublevels.

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Based on electronegativity of atoms, the inductive effect increases as the electronegativity of the atom increases and the electronegative atom is closer to the site of the acidic proton.

The inductive effect occurs due to the difference in electronegativity of atoms bonded together in which electronegative atoms increases the acidity but decreases the basicity of a compound.

The inductive effect is becomes stronger with decreasing distance between atoms, thus it is effective across short distances only.

Therefore, the inductive effect increases as the electronegativity of the atom increases and the electronegative atom is closer to the site of the acidic proton.

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A scientist adds iodine as an indicator to an unknown substance. The indicator revealed about the substance is that there is a presence of starch. The correct option is c.

Iodine is a chemical element. The atomic number of iodine is 53, and it is the heaviest halogen. It is black or blue. It is present in liquid. Furthermore, it helps in the making of thyroid hormones.

It is also used as an indicator. It is used as an indicator to find substances in the solution. Furthermore, it changes its color when there is a presence of a substance.

There is the presence of starch in the solution. Because the color of the solution changes to blue. It is used to test starch in the solution, where it gives intense color.

Thus, the correct option is c. the presence of starch.

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The question is incomplete. Your most probably complete question is given below:

a. the presence of glucose

b. the presence of lipids or fat

c. the presence of starch

d. the presence of baking powder

The empirical formula for pyrite is FeS2.

HOW TO CALCULATE EMPIRICAL FORMULA:

46.5 mass % Fe = 46.5g of Fe

53.5 mass % S = 53.5g of S

Fe = 46.5g ÷ 56g/mol = 0.83mol

S = 53.5g ÷ 32g/mol = 1.67mol

Fe = 0.83mol ÷ 0.83 = 1

S = 1.67mol ÷ 0.83 = 2.014

Approximately, the ratio of Fe to S is 1:2. Therefore, the empirical formula of pyrite is FeS2.

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Fractional distillation would be more suitable for a., b., and c., while simple distillation would be more suitable for d.

a. Fractional distillation would be more suitable for preparing drinking water from seawater. This is because seawater contains a mixture of salts and other impurities that have different boiling points. Fractional distillation allows for the separation of components based on their boiling points, which is useful for separating water from the other impurities.

b. Fractional distillation would be more suitable for separating benzene from toluene. This is because the boiling points of these two compounds are relatively close together, making it difficult to separate them using a simple distillation. Fractional distillation allows for more precise temperature control and therefore better separation of components with similar boiling points.

c. Fractional distillation would be more suitable for obtaining gasoline from crude oil. Crude oil is a complex mixture of hydrocarbons with a wide range of boiling points. Fractional distillation allows for the separation of these components based on their boiling points, which is useful for obtaining gasoline with a specific range of boiling points.

d. Simple distillation would be more suitable for removing diethyl ether from p-dichlorobenzene. This is because diethyl ether and p-dichlorobenzene have significantly different boiling points, so a simple distillation would be sufficient for separating them. Fractional distillation would not be necessary as the separation would be easily accomplished by a simple distillation.

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Explanation:

B → Boron → Atomic number 5

Be → beryllium → Atomic number 4

B - Hybridization → 1S² 2S² 2P¹

\( \sf Boron - \boxed{↿↾} \: \boxed{↿↾} \: \boxed{ \small↾ }\huge\boxed{ }\huge\boxed{ }\)

Be - Hybridization → 1S² 2S²

\( \sf Beryllium →\boxed{↿↾} \: \boxed{↿↾} \: \huge\boxed{ }\huge\boxed{ }\huge\boxed{ }\)

from above data we can see that the outermost orbital of Beryllium i.e. 2S is fully filled & that of boron have 1 electron in 2P orbital. It will require more energy to remove one electron from beryllium Because it will disturb the stability, on other hand the boron will lose one electron easily to attain full filled outermost electron hence it will require less energy for 1st ionization.

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Answer:

single covalent bond

Explanation:

The bond formed between two atoms each sharing one electron is called single covalent bond

The figure 1 is the structure of diamond. The type of bond in diamond is covalent sp³ bond. DIamond exists in hexagonal arrangement of carbon atoms.

Allotropes are substances formed from a single elements with different number in various size and shape. Carbon exhibit catenation property which means it can forms chains with other carbon in any large number.

The allotropes of carbon are diamond, graphene and fullerene. Diamond is hexagonal arrangement of carbons atom bonded covalently in sp³ hybridisation.

In graphene as shown in the second figure, bonded carbons atoms are arranged as layers where carbon is in sp²hybridisation. In the case of fullerenes, there are both hexagonal and pentagonal rings adjacent to each and are formed by 60-70 carbons.

In all these allotropes, the bond type between two carbons atoms is covalent. Covalent bond is formed by sharing of electrons between the two atoms.

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The mechanism that accounts for the reaction of 4-bromotoluene with sodium amide to form a mixture of 3- and 4-aminotoluene is nucleophilic aromatic substitution by addition-elimination. The correct alternative id option 2.

In this mechanism, the sodium amide acts as a strong nucleophile and attacks the electrophilic carbon in the aromatic ring of 4-bromotoluene.

The resulting intermediate is a highly unstable negative charge on the carbon atom of the ring, which is stabilized by the electron-withdrawing effect of the bromine substituent. The negative charge is delocalized around the ring, making the intermediate highly reactive.

The intermediate then undergoes an elimination reaction, in which the bromine atom is displaced by the incoming nucleophile, the sodium amide.

This creates an unstable intermediate with a negative charge on the carbon atom and a positively charged nitrogen atom. This intermediate quickly rearranges to form the final product mixture of 3- and 4-aminotoluene.

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In the context of nucleotides, the bond being referred to in part b is typically the phosphodiester bond.

The chemical groups involved in the formation of phosphodiester bonds are the hydroxyl (-OH) group of the 3' carbon of one nucleotide and the phosphate group (-PO₄) attached to the 5' carbon of the adjacent nucleotide.

During DNA or RNA synthesis, the hydroxyl group on the 3' carbon of the deoxyribose or ribose sugar of one nucleotide undergoes a condensation reaction with the phosphate group of another nucleotide. This reaction releases a molecule of water and forms a phosphodiester bond between the two nucleotides.

This process is repeated to create the polymer chain of DNA or RNA, with phosphodiester bonds linking successive nucleotides together.

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Answer:

The melting and boiling points of molecular compounds are generally quite low compared to those of ionic compounds. This is because the energy required to disrupt the intermolecular forces between molecules is far less than the energy required to break the ionic bonds in a crystalline ionic compound

Answer:

An outlier on a scatter plot represents something that doesn't fit.

The outlier on this scatter plot is D.(105, 320) might represent a newborn shark

With this experiment, we can conclude that when ATP synthase binds to ATP and the ATP synthase rotates.

Definition of ATP Synthase Adenosine triphosphate (ATP) is produced by the enzyme ATP synthase during the process of cellular respiration. The primary source of energy used by cells is ATP.

a catalytic enzyme that uses inorganic phosphate and ADP to create ATP The big protein enzyme known as ATP synthase, which produces energy for the cell, is the location to which angiostatin binds.

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The species would be an anuran (an amphibian)

We need to answer this in English.

Here we want to find "A species that mates on the surface and then deposits its eggs in the water to be surrounded by sperm"

This would be known as a species of amphibian called an anuran, specifically a frog or toad.

Frogs and toads belong to the order Anura and have a characteristic reproductive cycle that involves external fertilization. During reproduction, the male releases his sperm into the water, and the female deposits her eggs in the water as well. The eggs are externally fertilized by sperm that swim around them. This process is known as external or external fertilization.

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1. if 17.5 grams of MgCl2 are reacted, 16.3 grams of AlCl3 are produced.

2. the number of grams of CO2 produced is 0.78 mol * 44.0 g/mol = 34.3 g.

3. 440.64 grams of HCl are produced by the reaction of 48.5 grams of CH4.

we need to find the number of moles of MgCl2 that are present i question 1 :

n = m/M = 17.5 g / (95.21 g/mol) = 0.184 mol

we the can find the number of moles of AlCl3 that are produced:

n = 0.184 mol * (2 mol AlCl3 / 3 mol MgCl2) = 0.123 mol

in conclusion, we find the number of grams of AlCl3 produced:

m = n * M = 0.123 mol * (133.34 g/mol) = 16.3 g

We can say that if if 17.5 grams of MgCl2 are reacted, 16.3 grams of AlCl3 are produced.

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The element first discovered in the Sun's spectrum and then found on Earth 30 years later is helium. In 1868, French astronomer Pierre Janssen and English astronomer Sir Norman Lockyer observed a yellow spectral line in the Sun's light during a solar eclipse.

This line did not correspond to any known element at that time. Lockyer and British chemist Edward Frankland suggested that the line was due to a new element, which they named "helium," after the Greek word for the Sun, "Helios." It was not until 1895, nearly 30 years after its initial discovery in the Sun's spectrum, that helium was found on Earth.

Scottish chemist Sir William Ramsay isolated helium by treating the mineral cleveite with acid. Ramsay's discovery confirmed the existence of helium as an element both in the Sun and on Earth. Helium is the second most abundant element in the universe and has various applications, including as a coolant in medical and scientific equipment, and in lighter-than-air balloons.

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Answer:

Explanation:

The new volume can be found by using the formula for Boyle's law which is

\(P_1V_1 = P_2V_2\)

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the new volume

\(V_2 = \frac{P_1V_1}{P_2} \\\)

So we have

\(V_2 = \frac{500000 \times 200}{250000} = \frac{100000000}{250000} = \frac{10000}{25} \\ \)

We have the final answer as

Hope this helps you

Answer:

Strong nucleophile, good leaving group, polar aprotic solvent, methyl or primary halide. The correct answer is option: b.

In an SN2 reaction, a nucleophile attacks the carbon atom to which the leaving group is attached, while the leaving group departs from the molecule. The reaction proceeds in a single step, with the nucleophile and leaving group involved in the transition state. A strong nucleophile is required to attack the carbon atom, and a good leaving group is necessary to depart from the molecule. Methyl or primary halides are preferred substrates because they are less hindered, making the attack by the nucleophile easier. Option b is correct.

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Answer:

It is double displacement reaction

Answer:

4.08 L

Explanation:

At standard temperature and pressure, a mole of any gas equals 22.4 L.

We have 0.182 mol of CO₂ gas. We know that every mole of gas is 22.4 L, so

\(0.182mol*\frac{22.4L}{1mol} =4.08L\)

⇒ 4.08 L of CO₂ is the answer

SI Unit: Volume = 4.133 L of carbon dioxide

Non-SI Unit: Volume = 4.079 L carbon dioxide

At STP conditions (Standard Temperature and Pressure), which is conditions at 100 kPa and at 0°C or 273.15 K, it is a given that the volume of  1 mole of ideal gas is 22.71 L.

\(\large \textsf{$\therefore$ if 1 mol of CO$_2$ = 22.71 L}\\\\\large \textsf{hence, 0.182 $\times$ 1 mol of CO$_2$ = 22.71 $\times$ 0.182}\\\\\large \textsf{$\implies$ \boxed{\boxed{$volume = 4.133 L of CO$_2}}}\)

Note: The value used for pressure above, 100 kPa (kilopascals), is a standard SI unit (International System of Units), used by most countries around the world.

However, another commonly used value for pressure (though not the preferred SI unit), is 1 atm (atmospheric pressure), which is equivalent to 101.325 kPa.

Using this value, the volume of 1 mole of ideal gas at STP is then 22.41 L. Solving this:

\(\large \textsf{if 1 mol of CO$_2$ = 22.41 L}\\\\\large \textsf{$\therefore$ 0.182 $\times$ 1 mol of CO$_2$ = 22.41 $\times$ 0.182}\\\\\large \textsf{$\implies$ \boxed{\boxed{$volume = 4.079 L CO$_2}}}\)

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E) 1-iodo-1-methylcyclohexane.SN1 reaction is a type of substitution reaction. SN1 stands for substitution nucleophilic unimolecular. In SN1, the rate-determining step involves the breakdown of the leaving group rather than the formation of the C-nucleophile bond.

The reaction proceeds in two stages: 1) the formation of an intermediate carbocation, and 2) the reaction between the carbocation and the nucleophile. This mechanism is known as the SN1 mechanism. It is used for the reaction of secondary and tertiary alkyl halides. It is a slow reaction, the reaction rate depends on the concentration of the alkyl halide but not the nucleophile. It is a two-step mechanism that occurs in two steps. The first step involves the formation of a carbocation intermediate, while the second step involves the reaction between the intermediate and the nucleophile.The term "solvolysis" refers to a substitution reaction in which the solvent molecule acts as the nucleophile. Solvent molecules can be polar or nonpolar, and the reaction rate depends on the solvating power of the solvent.

A reaction that proceeds through an SN1 mechanism is known as solvolysis.Alkyl halides undergo solvolysis reactions with methanol to form alcohols. The reaction rate of this reaction depends on the strength of the bond between the alkyl group and the halogen. The bond strength decreases from iodine to fluorine, so the reactivity of the alkyl halides increases in the following order: 1-fluorohexane < (R)-2-bromohexane < 1-iodohexane < iodocyclohexane < 1-iodo-1-methylcyclohexaneSo, the given alkyl halide that reacts most rapidly via an SN1 solvolysis reaction in hot methanol is 1-iodo-1-methylcyclohexane.An explanation of why 1-iodo-1-methylcyclohexane reacts most rapidly via an SN1 solvolysis reaction in hot methanol is that in this case, the carbocation intermediate formed is stabilized by the presence of the methyl group, and the iodine atom has a high atomic number, making it polarizable and allowing it to form a more stable carbocation than the other alkyl halides. Thus, the reaction of 1-iodo-1-methylcyclohexane is faster than the others.

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The difference in melting and boiling points between sodium metal and sodium chloride reveals the relative strengths of metallic bonds and ionic bonds.

1. Metallic bonds: In metallic bonding, positively charged metal ions are surrounded by a sea of delocalized electrons. These electrons are free to move throughout the structure, creating a bond between the metal ions. The strength of metallic bonds depends on the number of delocalized electrons and the size of the metal ions. Generally, metals with more delocalized electrons and smaller ions have stronger metallic bonds.

2. Sodium metal: Sodium metal has a relatively low melting and boiling point because it forms weak metallic bonds. Sodium atoms have only one valence electron, which is easily lost to form a positively charged sodium ion. In the solid state, the positive sodium ions are held together by the sea of delocalized electrons. These bonds are relatively weak, requiring less energy to break and allowing sodium metal to melt and boil at lower temperatures.

3. Sodium chloride: Sodium chloride is an ionic compound composed of positively charged sodium ions and negatively charged chloride ions. Ionic bonds are formed through the transfer of electrons from one atom to another, resulting in the formation of charged ions. In the solid state, the positive and negative ions are held together by strong electrostatic attractions. These ionic bonds are much stronger than metallic bonds, requiring more energy to break. As a result, sodium chloride has a higher melting and boiling point compared to sodium metal.

In conclusion, the lower melting and boiling points of sodium metal compared to sodium chloride indicate that metallic bonds are weaker than ionic bonds. Sodium metal forms weak metallic bonds due to the presence of a sea of delocalized electrons, while sodium chloride forms strong ionic bonds through the transfer of electrons. This difference in bond strength accounts for the disparity in their melting and boiling points.

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Answer

3.075 g Fe²⁺

Procedure

The formula of iron (II) sulfite is FeS, to get the grams of Fe²⁺ present, we need to determine the ratio of the elements that form the molecule.

Fe = 55.845 g/mol

S = 32.065 g/mol

FeS = 55.845 g/mol + 32.065 g/mol = 87.91 g/mol

Ratio Fe = 55.845/87.91= 0.6353

Ratio S= 32.065/89.91 = 0.3647

Grams of Fe²⁺ = 4.84 (0.6353) = 3.075 g Fe²⁺

A 1 liter volumetric flask can be filled with distilled water until it reaches the graduation mark, 58.44 g of NaCl and this amount of salt can be used to create a 1M solution of the salt.

In this case, we must determine the volume of the solution as well as the mass of sodium chloride (NaCl) required to make a 1 molar solution of the salt.

The molarity formula,  

Molarity=Moles of Solute Volume of Solution, must be used.

The whole solution, in steps:

The moles of NaCl must first be determined. The solution has a 1 M molarity and a 1 L volume.

As a result, moles of NaCl may be computed as,

1 liter of solution equals 1 mole of NaCl.

1 M x 1 L equals 1 mol of NaCl.

In light of this, there is one mol of NaCl in the solution.

Using the quantity of NaCl's moles, we must now determine the mass of NaCl.

Math processing error: Number of moles

58.44 g/mol is the molar mass of sodium chloride, which has a molecular weight of 1 mol.

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So, to create a 1 M solution, we'll need 58.44 g of NaCl.

We will now talk about making a NaCl solution at a single molar strength.

A 1 liter volumetric flask can be filled with distilled water until it reaches the graduation mark, 58.44 g of NaCl and this amount of salt can be used to create a 1M solution of the salt.

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The correct options for A, B, C, D, E and F are true, false, false, false, true and false respectively.

A. True.

According to kinetic molecular theory, lighter gas molecules move with a higher average velocity than heavier gas molecules at a constant temperature.

B. False.

The average kinetic energy of gas molecules at a constant temperature is independent of their mass.

C. False.

A real gas performs at its most optimal when the volume of the container is relatively large and the gas molecules move relatively slowly.

D. False.

The effect of interparticle interactions on the behavior of a gas diminishes as the temperature increases.

I. True.

The number of collisions per unit area increases as more gas molecules are supplied to a container of constant volume and temperature (constant V and T).

F. False.

Kinetic molecular theory states that the pressure remains constant for a constant volume and mole of a gas.

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Your question is incomplete, most probably the complete question is:

Which of the following statements is(are) true? For the false statements, correct them.

a. At constant temperature, the lighter the gas molecules, the faster the average velocity of the gas molecules.

b. At constant temperature, the heavier the gas molecules, the larger the average kinetic energy of the gas molecules.

c. A real gas behaves most ideally when the container volume is relatively large and the gas molecules are moving relatively quickly.

d. As temperature increases, the effect of inter particle interactions on gas behavior is increased.

e. At constant $V$ and $T,$ as gas molecules are added into a container, the number of collisions per unit area increases resulting in a higher pressure.

f. The kinetic molecular theory predicts that pressure is inversely proportional to temperature at constant volume and moles of gas.

Answer:

190

Explanation:

Gold has atomic number of 79, which is the number of protons.

Mass number = #protons + #neutrons = 79 + 111 = 190

When dissolved in water, salts can either produce acidic, basic, or neutral solutions depending on the ions they produce. If the salt contains an anion that is the conjugate base of a weak acid or a cation that is the conjugate acid of a weak base, the resulting solution will be acidic or basic, respectively.

For example, the salt sodium chloride (NaCl) is neutral because it produces the ions Na+ and Cl-, which do not have any acidic or basic properties. On the other hand, the salt ammonium chloride (NH4Cl) produces the ions NH4+ and Cl-, with the NH4+ ion acting as an acid and donating a proton to water molecules to produce H3O+ ions. This results in a solution that is acidic, with a pH less than 7.
8 Similarly, the salt sodium acetate (NaCH3COO) produces the ions Na+ and CH3COO-, with the CH3COO- ion acting as a weak base and accepting protons from water molecules to produce OH- ions. This results in a solution that is basic, with a pH greater than 7.
In order to determine whether a salt will produce an acidic, basic, or neutral solution, it is important to consider the properties of the ions it produces and their interactions with water molecules.
In summary, the acidity or basicity of a salt solution depends on the ions it produces when dissolved in water. The balanced chemical equations for the reactions causing the solution to be acidic or basic involve the ionization of weak acids or bases in the salt solution.

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Answer:

oxygen

Explanation:

plants and animals use oxygen