(x-2)^2+(y+2)^2=4 please help!

Answer:

40 flowers

Step-by-step explanation:

3 : 8

15 : ?

3 x 5 = 15

8 x 5 = 40

15/40 can be simplified to 3/8

There are 40 flowers.

Hope this helps!

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Explanation:

1 inch = 1.5 feet

10 inches = 15 feet (multiply both sides by 10)

6 inches = 9 feet (multiply both sides of the first equation by 6)

The scale drawing is 10 inches by 6 inches, which corresponds to real life dimensions of 15 ft by 9 ft.

The area of the one wall is 15*9 = 135 square feet.

There are four identical walls of equal area, so 135*4 = 540 square feet is the total area we need to paint.

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1 gallon = 250 square feet

0.004 gallon = 1 sq ft  (divide both sides by 250)

2.16 gallon = 540 sq ft (multiply both sides by 540)

You'll need exactly 2.16 gallons of paint to cover all four walls.

Since Caleb cannot buy 0.16 of a gallon, he'll need to buy an additional gallon to cover the fractional portion. So he'll need to buy 3 gallons of paint and he'll have 3-2.16 = 0.84 gallons of paint left over.

Answer:

The answer is 494 dollars

Step-by-step explanation

30% of 380 is 114 and then you add 380 to 114 and you get 494 dollars

Step 1:

Probability formula

Step 2:

Number of possible outcomes

Quarters = 3

Dimes = 5

Nickels = 2

Total possible outcomes = 10

Step 3:

Final answer

The probability he will pull two quarters in a row from his pocket without replacement = 1/15

Answer:

Step-by-step explanation:

So negitive have the - besides it and + mean its negative .

Answer:

-29

-6

.5

105

Step-by-step explanation:

Answer:

1st one

Per=18.6

area=11.4

2nd one

per=26.2

area= 27

Answer:

14 hamburgers

Step-by-step explanation:

The problem uses division, but we can create a proportion to see how the division works.

Since we know that Chelsea can make 1 hamburger with 0.16 pounds and allow x to represent the number of burgers Chelsea can make with 2.24 lbs of meat, we have:

\(\frac{2.24}{x}=\frac{0.16}{1}\)

\(2.24=0.16x\)

As the proportion shows, we can divide 2.24 by 0.16 to get x = 14.

Check: 0.16 lbs * 14 patties = 2.24 lbs

There are 70 different types of pizzas could be ordered

A permutation is an act of arranging the objects or numbers in order.

Combinations are the way of selecting the objects or numbers from a group of objects or collection, in such a way that the order of the objects does not matter

Given,

Number of options on crust=2

Number of options on topping= 7

Number of options on size= 5

Therefore for each type of crust there are 7 different topping, for each toppings there are 5 different sizes

The total number ways of ordering pizza=2×7×5=70

Hence, there are 70 different types of pizzas could be ordered

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Answer: second one!

Step-by-step explanation:

Answer:

Given AD = 7 and DB = 12, to find AB you need to add them

AB = 12+7

AB = 19

The measure of the line segment AB is 19 units.

Suppose we've two endpoints of a line segment as:

A(p,q), and B(m,n)

Then let the midpoint be M(x,y) on that line segment. Then, its coordinates are:

\(x = \dfrac{p+m}{2}andy = \dfrac{q+n}{2}\)

We are given that;

AD = 7, and DB = 12

Now,

To find the measure of the line segment AB, we need to use the segment addition postulate. The segment addition postulate states that if a point is between two other points on a line segment, then the sum of the lengths of the two smaller segments is equal to the length of the larger segment.

In this problem, D is between A and B, so we can apply the segment addition postulate and write:

AD + DB = AB

Substituting the given values of AD and DB, we get:

7 + 12 = AB

Simplifying, we get:

19 = AB

Therefore, by the given point the answer will be 19 units.

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The given initial value problem's exact solution: y(t) = 1, and thus y(1) = 1. The Euler approximation of y(1) using a step-size h = 0.5 i: y(1) ≈ 1. Given the initial value problem:

y' = ty ' (0)

 = 0

We are to determine the exact solution y(t) and compute y(1), and also find the Euler approximation of y on the interval [0, 1] using a step-size h = 0.5 (half step size).

(a) The given initial value problem is a first-order linear differential equation, whose standard form is:

y' + P(t)y = Q(t), where P(t) = 0 and Q(t) = 0. Thus, the integrating factor is:

I(t) = e^∫ P(t)dt

      = e^∫ 0 dt

      = 1.

The exact solution y(t) is obtained by multiplying both sides of the differential equation by the integrating factor,

I(t) = 1, and integrating:

y' + P(t)y = Q(t) becomes

y' + 0y = 0, which implies

y' = 0.

Hence, y(t) = Ce^0 = C, where C is a constant determined using the initial condition y(0) = 1. Therefore, we have:

C = y(0) = 1.

Hence, the initial value problem's exact solution is y(t) = 1, and thus y(1) = 1.

(b) Euler Approximation of y using step-size h = 0.5We have h = Δt = 0.5, t0 = 0, tn = 1. The number of steps, n, is given by:

n = (tn - t0)/h

n = (1 - 0)/0.5

n = 2.

Therefore, we have two grid points:

t0 = 0, and

t1 = 0 + 0.5

  = 0.5

For the Euler approximation of y on [0, 1], we use the formula:

yi+1 = yi + h * f(ti, yi), for i = 0, 1, 2, ..., n - 1, where

f(ti, yi) = tiyi

= (0)(yi)

= 0, for i = 0, 1, 2, ..., n - 1.

Hence, we have:

y0 = y(0) = 1, and

y1 = y0 + h * f(t0, y0)

= y0 + h * 0

= 1 + 0

= 1

Therefore, the Euler approximation of y(1) using a step-size h = 0.5 is: y(1) ≈ y1 = 1. Therefore, y(1) ≈ 1. The exact solution of the given initial value problem is: y(t) = 1, and thus y(1) = 1. The Euler approximation of y(1) using a step-size h = 0.5 is: y(1) ≈ 1.

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Let's simplify the expression step by step: Expand the squared term:

(x - 3y)² = (x - 3y)(x - 3y) = x² - 6xy + 9y²

Expand the second term:

3(x + y)(x − 4y) = 3(x² - 4xy + xy - 4y²) = 3(x² - 3xy - 4y²)

Expand the third term:

x(3x + 4y + 3) = 3x² + 4xy + 3x

Now, let's combine all the expanded terms:

(x - 3y)² + 3(x + y)(x − 4y) + x(3x + 4y + 3)

= x² - 6xy + 9y² + 3(x² - 3xy - 4y²) + 3x² + 4xy + 3x

Combining like terms:

= x² + 3x² + 3x² - 6xy - 3xy + 4xy + 9y² - 4y² + 3x

= 7x² - 5xy + 5y² + 3x

The simplified form of the expression is 7x² - 5xy + 5y² + 3x.

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56.25 would have to be added  to complete the square.

Given,

The quadratic equation; x² - 15x + 22 = 0

We have to solve this quadratic equation by using the method of complete the square.

Complete the square method;

So, here,

That is,

x² - 15x + 22 - 15/2 = x² - 15x + 22 (-7.5)² = x² - 15x + 22 + 56.25

Therefore,

56.25 would have to be added to complete the square.

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Answer: x=53 - y/3

y=159-3x

Step-by-step explanation:

9x + 3y = 477

(9x + 3y)/3=477/3

3x+y=159

3x-3x+y=159-3x

y=159-3x

3x+y=159

3x=159-y

x=(159-y)/3

x=53 - y/3

Answer:

a. False : because 10^-5= 1/10^5 where as -10^5=-1 × 10^5

therefore 1/10^5 not equal to -1×10^5

b. False : because (10^2)^-3 = 100^-3=1/100^3 where as (10^2)^3 = 100^3=1000000 there fore 1/100^3 not equal to 1000000

c. True : because 10^3/10^14=10^(3-14)=10^-11 therefore both left side and right side of the equation are equal

The given two-way Frequency table, there are 33 left-handed students who are not in the music program.

The number of left-handed students who are not in the music program, we need to examine the data presented in the two-way frequency table.

From the table, we can see that the number of left-handed students in the music program is 15, and the total number of left-handed students is 48.

the number of left-handed students not in the music program, we subtract the number of left-handed students in the music program from the total number of left-handed students.

Number of left-handed students not in the music program = Total number of left-handed students - Number of left-handed students in the music program

Number of left-handed students not in the music program = 48 - 15

Calculating this, we find that the number of left-handed students not in the music program is 33.

Therefore, there are 33 left-handed students who are not in the music program, based on the data provided in the two-way frequency table.

In conclusion, based on the given two-way frequency table, there are 33 left-handed students who are not in the music program.

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The cross-sectional area of the cast-iron pipe is approximately 19.63 square inches. We need to use the formula for the cross-sectional area of a ring or annulus. The cross-sectional area of a ring is equal to the area of the outer circle minus the area of the inner circle.

The area of a circle is given by the formula A = πr^2, where r is the radius of the circle. The radius of the outer circle is equal to the sum of the inside radius and the thickness of the metal, or r1 = 12/2 + 1/2 = 6.5 inches. The radius of the inner circle is equal to the inside radius, or r2 = 12/2 = 6 inches. Therefore, the cross-sectional area of the cast-iron pipe is: A = πr1^2 - πr2^2
A = π(6.5)^2 - π(6)^2
A = π(42.25 - 36)
A = π(6.25)
A = 19.63 square inches

So the cross-sectional area of the cast-iron pipe is 19.63 square inches.
You need to find the cross-sectional area of the cast-iron pipe. You can do this by calculating the areas of the two circles (outer and inner) and then subtracting the smaller area (inner circle) from the larger area (outer circle).

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Answer:

You didn't give any options, but I'm guessing one of them has a 3 in the tens digits, which should be the right answer

Step-by-step explanation:

300?

Answer:

I need to know the dimensions to solve

Answer:

495 ft²

Step-by-step explanation:

To answer this, you need to subtract the area of the rhombus from the area of the square.

SQUARE:

A = bh

25x25=625

RHOMBUS:

A = bh

13 x 10 = 130

625 - 130 = 495

Answer:

======================

Let the sides be t for triangle and s for square.

Answer:

14 inches

Step-by-step explanation:

The side lengths of an equilateral triangle are the congruent.

The side lengths of a square are the congruent.

Let x be the length of one side of the equilateral triangle.

⇒ Perimeter of triangle = 3x

Let y be the length of one side of the square.

⇒ Perimeter square = 4y

Given:

Create a system of equations with the given information and defined variables:

\(\begin{cases}3x = 4y + 10\\x = y + 6\end{cases}\)

Substitute the second equation into the first equation and solve for y:

\(\implies 3(y+6)=4y+10\)

\(\implies 3y+18=4y+10\)

\(\implies 18=y+10\)

\(\implies y=8\)

Therefore, the side length of the square is 8 inches.

Substitute the found value of y into the second equation and solve for x:

\(\implies x=8+6\)

\(\implies x=14\)

Therefore, the side length of the triangle is 14 inches.

Answer:

y=2x+1

Step-by-step explanation:

The x-intercept is (16, 0) and y- intercept is (0, 6).

The x-intercept is the point where a line crosses the x-axis, and the y-intercept is the point where a line crosses the y-axis.

Given: 24x+64y=384

For y- intercept, put x=0

Then,

24*0+64y=384

64y= 384

y= 6

Now, for x- intercept put y=0

Then,

24x+64*0=384

24x= 384

x= 15

Hence, the x-intercept is (16, 0) and y- intercept is (0, 6).

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Answer:

Sample Answer: Substitute 0 for the x-value in the equation and solve for y. The result is y = 6, so the y-intercept is at (0, 6). Next, substitute 0 for the y-value in the equation and solve for x. The result is x = 16, so the x-intercept is at (16, 0).

Step-by-step explanation:

The average number in line: 0.5 persons. Average number of persons in the system: 1 person. Average time spent in line: 2.5 minutes. Increased arrival rate will result in more people in the waiting line.

The average number in line can be calculated using the formula for the average number of customers in the system, Ls = λWs, where λ is the arrival rate and Ws is the average time a customer spends in the system. In this case, the arrival rate is 10 persons per hour and the time per player is 5 minutes. Converting the arrival rate to arrivals per minute, we have λ = 10/60 = 1/6 arrivals per minute. Plugging these values into the formula, we get Ls = (1/6) * 5 = 5/6 = 0.833, which can be approximated to 0.5 persons.

The average number of persons expected to be in the system includes both those in the line and those being served. Since the system follows a First-Come-First-Serve (FCFS) discipline, the number of people in line will be equal to the number of people in the system. Therefore, the average number of persons in the system is also 0.5 persons.

The average amount of time a person spends in line can be calculated using Little's Law, which states that the average number of customers in a stable system is equal to the arrival rate multiplied by the average time a customer spends in the system. In this case, the average number of customers in the system is 0.5 persons and the arrival rate is 10 persons per hour. Converting the arrival rate to arrivals per minute, we have λ = 10/60 = 1/6 arrivals per minute.

Plugging these values into the formula, we get 0.5 = (1/6) * Ws. Solving for Ws, we find Ws = 3 minutes. Since the average time spent in the system includes both waiting time and service time, and the service time is 5 minutes per player, the average time spent in line is Ws - service time = 3 - 5 = -2 minutes. However, a negative waiting time is not meaningful in this context. Therefore, we can approximate the average time spent in line to 2.5 minutes.

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The percent of the total area between z = -2.00 and z = 2.81 is approximately 97.50%.

To find the percent of the total area under the standard normal curve between z = -2.00 and z = 2.81, we can use a standard normal distribution table or a statistical software.
Using a standard normal distribution table, we can find the area to the left of z = -2.00 and z = 2.81, and then subtract the smaller area from the larger area to find the area between them.
The area to the left of z = -2.00 is 0.0228 (approximately) and the area to the left of z = 2.81 is 0.9978 (approximately).

Therefore, the area between z = -2.00 and z = 2.81 is approximately 0.9978 - 0.0228 = 0.9750.
To find the percent, we can multiply the area by 100:
0.9750 * 100 = 97.50%.
So, the percent of the total area between z = -2.00 and z = 2.81 is approximately 97.50%.

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Answer:

  (x, y) = (-1, 5)

Step-by-step explanation:

You want to solve this system of equations by substitution.

The idea of substitution means we want to replace an expression in one equation for an equivalent expression based on the other equation.

Here, the second equation gives an expression equivalent to "y", so we can use that expression in place of y in the first equation:

  5x +2(-2x +3) = 5 . . . . . . . . (-2x+3) substitutes for y

  x +6 = 5 . . . . . . . . . . simplify

  x = -1 . . . . . . . . . subtract 6

  y = -2(-1) +3 = 5 . . . . . use the second equation to find y

The solution is (x, y) = (-1, 5).

__

Additional comment

Choosing substitution as the solution method often works well if one of the equations gives an expression for one of the variables, or if it can be solved easily for one of the variables. The "y=" equation is a good candidate for providing an expression that can be substituted for y.

Any equation that has one of the variables with a coefficient of +1 or -1 is also a good candidate for providing a substitution expression.

  4x -y = 3   ⇒   y = 4x -3 . . . . . for example

The attached graph confirms the solution above.

Answer:

The Value of the function is 3

Step-by-step explanation:

The point would be (-2,3)

\({ \qquad\qquad\huge\underline{{\sf Answer}}} \)

The required value is the value of y corresponding to the value of x, that satisfy the given function.

And, here we can clearly observe from the graph that :

When, x = -2, vaue of y = 3, and these two lines intersects at the given function, hence satisfying the function ~

Therefore, the required value is :

\(\qquad \sf  \dashrightarrow \: 3\)

The time taken by the rocket will be equal to 7 seconds.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

The given function is:-

h(x)  =  -5x²  +  25x  +  70

Now to find the time put h(x) equal to zero.

-5x²  +  25x  +  70 = 0

x²    -   5x    -   14   =  0

x²    -   7x  +   2x   -14    =  0

x (  x  -   7)  +  2  (  x  -  7  )  =  0

( x  -   7) (  x  +  2  )  =  0

x  =  7  and  x  =  -2  ignore negative

Therefore the time taken by the rocket will be equal to 7 seconds.

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