x(t) h(t) h₂ (t) y(t) h₂ (t) 2) [20 pts] Find the equivalent transfer function H(s) = Y(s)/X(s) and impulse response h(t) h₂(t) = 5u(t-2) h₂(t) = e-³tu(t) h₂(t) = e¹u(t)
Answers
The equivalent transfer function H(s) = Y(s)/X(s) and the impulse response h(t) can be found for the given input-output relationship. The impulse response consists of three functions: h₂(t) = 5u(t-2), h₂(t) = e^(-³t)u(t), and h₂(t) = e^(t)u(t). The transfer function H(s) is obtained by taking the Laplace transform of each impulse response and multiplying them together.
To determine the transfer function H(s), we consider each individual impulse response and apply the Laplace transform. Starting with h₂(t) = 5u(t-2), where u(t) is the unit step function, we can directly obtain the Laplace transform. Applying the time-shifting property of the Laplace transform, the result is H₂(s) = 5e^(-2s)/s.
Moving on to h₂(t) = e^(-³t)u(t), we take the Laplace transform using the property of the Laplace transform for exponential functions. The result is H₂(s) = 1/(s + ³).
Lastly, for h₂(t) = e^(t)u(t), we again use the Laplace transform property for exponential functions. This yields H₂(s) = 1/(s - 1).
To obtain the overall transfer function H(s), we multiply these individual transfer functions: H(s) = H₁(s) * H₂(s) * H₃(s) = (5e^(-2s)/s) * (1/(s + ³)) * (1/(s - 1)).
The impulse response h(t) can be obtained by taking the inverse Laplace transform of H(s). This involves performing partial fraction decomposition on the transfer function H(s) and applying inverse Laplace transforms using tables or known formulas.
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Related Questions
Which of the following reduces friction in an engine A)wear B)drag C)motor oil D)defractionation
Answers
It is motor oil, as oil is used to reduce friction
Q-) please give me a reference about Tack coat? Pleae i need it please??!!
Answers
Answer:
Tack coat is a sprayed application of an asphalt binder upon an existing asphalt or Portland cement concrete pavement prior to an overlay, or between layers of new asphalt concrete.
Explanation:
Two friends are playing golf. The first friend hits a golf ball on level ground with an initial speed of 47.0 ms at an angle of 35.0∘ above the horizontal.
(a) Assuming that the ball lands at the same height from which it was hit, how far away from the golfer does it land? Ignore air resistance.
(b) The second friend hits another golf ball with the same initial speed as the first, but the initial velocity of the ball makes an angle with horizontal that is greater than 45 degrees. The second ball, however, travels the same horizontal distance as what you found in part (a), and it too lands at the same level from which it was hit. What was the angle in degrees above horizontal of the initial velocity of this second golf ball? Ignore air resistance.
Answers
Answer:
A) 211.81 m
B) 65°
Explanation:
We are told that the first friend hits a golf ball on level ground with an initial speed of 47 m/s at an angle of 35° above the horizontal.
Thus;
speed; u = 47 m/s
Projection angle; θ = 35°
A) We want to find how far away from the golfer the ball lands. This is simply the range. Range in projectile motion is given by the formula;
R = (u²•sin 2θ)/g
Plugging in the relevant values, we have;
R = (47² × sin(2 × 35))/9.8
R = 211.81 m
B) We are told that the second ball, travels the same horizontal distance as what is found in part (a).
Thus, R remains 211.81 m
Thus, the angle above horizontal of the initial velocity of this second golf ball will be;
90° - projection angle(θ) = 90 - 35 = 65°
tech a says that a slightly lean mixture offers good fuel economy and low exhaust emissions. Tech b says that a mixture that is too rich fouls spark plugs and causes incomplete burning. Who is correct
Answers
Explanation:
Exhaust emissions are gases that are expelled from vehicle engines and they include carbon monoxide, unburned fuel, nitrogen oxides and particulate matter such as mercury. These emissions can cause air pollution and green house effects which leads to climate changes. Low exhaust emissions can be achieved through the use of lean mixtures which has high air- fuel ratio and less emission. Therefore, Tech A is correct.
Rich mixtures are mixtures that are of low air- fuel ratios and it's burning in a diesel engine increases particulate matter emission, fouls spark plugs, causes incomplete burning. Therefore Tech B is equally correct. Hope this helps, thanks.
Which Finance jobs can someone pursue with only a high school diploma? Check all that apply.
PLS HURRY IM TIMED
Tax Preparer
Treasurer
Actuary
Teller
Loan Officer
Quantitative Analyst
Answers
Bank tellers, bookkeepers, tax examiners, auditing clerks, cashiers, and bill collectors are among the occupations that demand a high school graduation or prior job experience. Thus option A,D is correct.
What Finance jobs pursue with only a high school diploma?Depending on your field of study, degree type, and experience, you can obtain a number of entry-level positions with a finance degree. Some entry-level options include junior tax accountant, stockbroker, financial analyst, personal finance advisor, and banking assistant.
For entry-level positions in many financial careers, a bachelor's degree is necessary, and for management-level positions, a master's degree.
Therefore, Tax Preparer and Teller are included in Finance jobs can someone pursue with only a high school diploma.
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a fundamental fire concern with type iii construction is the_____.
Answers
A fundamental fire concern with type III construction is the unprotected exterior walls since this type of construction features non-combustible or limited combustible materials that do not withstand high temperatures or pressures that can be produced during a fire.
Type III building construction is a non-combustible construction type that is mainly made of concrete or masonry materials, which can help to protect the interior from fire damage. The other materials used in Type III construction include wood, which is limited to non-load bearing purposes such as doors, trim, and roof supports.
Type III construction has walls, floor, and roof assembly made of non-combustible materials, so it has good fire-resistance properties. However, Type III construction may not be entirely fireproof because it features unprotected exterior walls.
Unprotected exterior walls are the most significant cause for concern with type III construction because, during a fire, flames can easily spread up the building’s exterior walls. Consequently, the fire can jump from one building to another and even get into adjacent buildings.
This is the main reason why fire sprinklers and fire-rated glass are essential in type III construction.
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Match the jobs descriptions with the job titles.
budget analyst
bill collector
claims adjuster
Locate people who owe money and negotiate payment plans.
Review a company's expenses to determine if they exceed the targets.
Contact doctors and employers to ensure that there is no insurance fraud.
Answers
Bill collector: locate people who owe money and negotiate payment plans
Claims adjuster: contact doctors and employers to ensure that there is no insurance fraud.
What should be your strongest tool be for gulding your ethical decisions making process
Answers
Answer:
Recognize that there is a moral dilemma.
Determine the actor. ...
Gather the relevant facts. ...
Test for right versus wrong issues. ...
Test for right versus right paradigms. ...
Apply the resolution principles. ...
Investigate the trilemma options. ...
Make the decision.
Let X = 5∠40° and Y = 20∠–30°. Evaluation of complex numbers in polar form
The polar form of the quantity (X + Y)/X is _____∠_____°Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees
Answers
The polar form of the quantity (X + Y)/X is to be evaluated, where X = 5∠40° and Y = 20∠–30°.
The first step is to find the sum of X and Y, which is given by:
X + Y = 5∠40° + 20∠–30°
To add complex numbers in polar form, we need to convert them to rectangular form using the following formulas:
a∠θ = a cosθ + i a sinθ
X = 5 cos40° + i 5 sin40° = 3.825 + i 3.196
Y = 20 cos(–30°) + i 20 sin(–30°) = 17.32 – i 10
Substituting the values of X and Y, we get:
X + Y = (3.825 + 17.32) + i (3.196 – 10)
X + Y = 21.145 – 6.804i
Now, to find (X + Y)/X, we divide the sum by X:
(X + Y)/X = (21.145 – 6.804i) / (5∠40°)
To divide complex numbers in polar form, we need to divide the magnitudes and subtract the angles. Thus, we get:
(X + Y)/X = 4.229∠–20.96°
Since the question requires the angle to be in the range of negative 180 degrees to positive 180 degrees, we can add 360 degrees to the angle to get:
(X + Y)/X = 4.229∠339.04°
Therefore, the polar form of the quantity (X + Y)/X is 4.229∠339.04°.
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Which of following are coding languages used in controlling a robot? *
A. Scratch
B. B/B--
C. C/C++
D. Robot Z
Answers
Answer:
C/C++
Explanation:
C/C++
Rt = R1 + R2 + R3
\( \frac{1}{rt} = \frac{1}{r1} + \frac{1}{r2} + \frac{1}{r3} \)
If R1 = 4Ω , R2 = 6Ω and R3 = 8Ω (Ω= ohm)
Calculate: 4.1.1 Rt (series)
4.1.2 Rt (parallel)
Answers
Answer:
In series:
\( \frac{1}{r} = \frac{1}{r_{1} } + \frac{1}{r _{2} } + \frac{1}{r_{3} } \)
\( \frac{1}{r} = \frac{1}{4} + \frac{1}{6} + \frac{1}{8} \\ \\ \frac{1}{r} = \frac{13}{24} \\ \\ r = \frac{24}{13} \\ { \underline{r = 1.85 \: Ω}}\)
In parallel:
\(r = r _{1} + r _{2} + r _{3} \\ r = 4 + 6 + 8 \\ r = 18Ω\)
Use the following table to (i) decide which solvent(s) will dissolve poly(dimethyl siloxane) (PDMS) (PDMS = 14.9 MPa1/2) and polystyrene (PS) (ps = 18.7 MPa1/2) at room temperature, assuming that they are very high molecular weight polymers. Solvent n-Heptane Cyclohexane Benzene Chloroform Acetone Molar volume (cm' mol-1) Solubility parameter 8 (MPa1/2) 195.9 15.1 108.5 16.8 29.4 18.6 80.7 19.0 74.0 20.3 (ii) Which solvent is closest to the athermal limit for each polymer (i.e., which is the best solvent)?
Answers
Based on the solubility parameters, Acetone (with a solubility parameter of 19.0 MPa1/2) is the only solvent that falls within the range of both PDMS and PS. Therefore, acetone is capable of dissolving both PDMS and PS at room temperature.
To determine which solvent is closest to the athermal limit for each polymer, we need to compare the solubility parameter of each solvent to the square root of the cohesive energy density (CED) of each polymer. The athermal limit is defined as the solvent that has a solubility parameter closest to the square root of the CED of the polymer.
The square root of the CED for PDMS is 6.57 MPa1/2, and the closest solvent in the table is Cyclohexane (with a solubility parameter of 15.1 MPa1/2). Therefore, Cyclohexane is the best solvent for PDMS.
The square root of the CED for PS is 6.85 MPa1/2, and the closest solvent in the table is Chloroform (with a solubility parameter of 16.8 MPa1/2). Therefore, Chloroform is the best solvent for PS.
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what is the total impedance (a/c resistance) of one 8 ohm and one 16 ohm speaker wired (connected), in series?
Answers
One 8 ohm and one 16 ohm speaker wired (connected), in series, produce a total impedance (a/c resistance) of 24 ohms.
The definition of impedance?The measure of resistance to electrical flow is called impedance, and it is denoted by the letter Z. In ohms, it is measured. Impedance and resistance are the same in DC systems and are calculated by dividing the voltage across an element by the current (R = V/I).
How is total impedance calculated?An AC property of a circuit called impedance can change depending on the operating frequency Z = R - j/C + jL, where = 2f, is a typical representation of it.
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3. The _______on an electric motor provides information that will assist a
person in selecting, installing, and energizing the correct motor for the job.
Answers
Note that the nameplate or rating plate on an electric motor provides information that will assist a person in selecting, installing, and energizing the correct motor for the job.
Who invented the Electric Motor?The electric motor was not invented by a single individual, but rather its development involved the work of many scientists and inventors over time.
The earliest form of an electric motor was created in 1821 by Michael Faraday, who demonstrated the conversion of electrical energy into mechanical motion. Subsequent inventors such as Thomas Davenport, Nikola Tesla, and Galileo Ferraris made significant contributions to the development of the electric motor, paving the way for its modern-day applications in a wide range of industries.
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The typical Canadian worker is able to produce 100 board feet (a unit of measure) of lumber or 1000 light bulbs per year. The world price of a board foot of lumber is $20 and that of a light bulb is $1. Draw the production possibilities frontier for the average Canadian worker by manipulating the line segment labeled PPF.
Answers
Answer:
Explanation:
In the Canadian country, it is possible that the country is able to produce either 100 units of lumber or 1000 lightbulbs. Then, 100 lumber is equal to 1000 bulbs in the home, and hence, one lumber is equivalent to 10 bulbs. Therefore, the opportunity cost of lumber in the home is ten bulbs.
Thus, the country's production possibilities frontier PPF is a linear combination of 100 lumber and 1000 bulbs. The graphical diagram of the production possibilities frontier PPF can be seen in the image below.
Country C is capable of producing either 100 units of lumber or 1,000 lightbulbs. Therefore, in the residence, \(100\ lumber = 1000\ bulbs\), and thus \(1 \ lumber = 10\ bulbs\). As a result, the economic cost of lumber within the residence is equal to 10 bulbs.
This country's PPF, on the other hand, is a linear mixture of 100 trees and 1000 bulbs.In the global market, one log costs $20, and one light costs $1 therefore, in the global market, \(1 \ timber =20\ bulbs\). As a result, the price of lumber on the global market is high. The opportunity cost of lumber is lower in the home country. As a result, it'll be a lumber specialist. If it specialized entirely in timber, it would manufacture 100 pieces of lumber and trade them for up to 2000 bulbs.As a result, the proper answer is "Canada would focus on lumber production for its competitive advantage", therefore, following the trade, the country's CPF (BC) is a linear combination of 100 lumber and 2000 lights.
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C++ Character operations
A 2-character string, userPassword, is read from input. Replace each character in userPassword that is not alphabetic with '#'. Otherwise, userPassword is not changed.
Ex: If the input is 2q, then the output is:
#q
Code:
#include
#include
#include
using namespace std;
int main() {
string userPassword;
getline(cin, userPassword);
(input goes here)
cout << userPassword << endl;
return 0;
}
Answers
A password is a string of characters used to verify the identity of a user during the authentication process.
#include <iostream>
int main() {
int n = 2;
char userPassword[n];
for(int i = 0; i<n; i++){
std::cin>>userPassword[i];
if(isdigit(userPassword[i]))
userPassword[i]='*';
}
return 0;}
A password is a group of letters and numbers that is used to confirm a user's identity throughout the authentication process. Passwords are frequently used in conjunction with usernames; they are intended to be kept secret and unique to the user and grant access to a device, application, or website.
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A balanced three-phase inductive load is supplied in steady state by a balanced three-phase voltage source with a phase voltage of 120 V rms. The load draws a total of 10 kW at a power factor of 0.85 (lagging). Calculate the rms value of the phase currents and the magnitude of the per-phase load impedance. Draw a phasor diagram showing all tlme voltages and currents.
Answers
Answer:
Following are the solution to the given question:
Explanation:
Line voltage:
\(V_L=\sqrt{3}V_{ph}=\sqrt{3}(120) \ v\)
Power supplied to the load:
\(P_{L}=\sqrt{3}V_{L}I_{L} \cos \phi\)
\(10\times 10^3=\sqrt{3}(120 \sqrt{3}) I_{L}\ (0.85)\\\\I_{L}= 32.68\ A\)
Check wye-connection, for the phase current:
\(I_{ph}=I_L= 32.68\ A\)
Therefore,
Phasor currents: \(32.68 \angle 0^{\circ} \ A \ ,\ 32.68 \angle 120^{\circ} \ A\ ,\ and\ 32.68 -\angle 120^{\circ} \ A\)
Magnitude of the per-phase load impedance:
\(Z_{ph}=\frac{V_{ph}}{I_{ph}}=\frac{120}{32.68}=3.672 \ \Omega\)
Phase angle:
\(\phi = \cos^{-1} \ (0.85) =31.79^{\circ}\)
Please find the phasor diagram in the attached file.
Heat air rises, cools then falls. Air near heat is replaced by cooler air and the cycle repeats
Answers
Which of the following is the term for a sliding device that moves against or is moved by fluid pressure?
turbine
valve
piston
fluid
Answers
I hope I helped ! ((:
Answer:
piston
a sliding device that moves against or is moved by fluid pressure; usually consists of a cylindrical body within a cylindrical chamber
Explanation:
2021 EDGE I got it correct :D
Hard steering can be caused by
Answers
Answer:
Lack of fluid oil – lack of fluid oil in your vehicle, or a fluid leakage, can lead to heavy steering. If there is a lack of fluid oil, or a leak, this can reduce the pressure in the system, meaning the steering wheel does not receive enough supply of fluid to perform freely.
is it possible to construct a heat engine that creates no thermal pollution?
Answers
Yes, it is possible to construct a heat engine that creates no thermal pollution.
This can be achieved through the use of advanced materials, such as thermoelectric materials, that can convert waste heat back into useful energy, or through the use of a heat exchanger system that can transfer heat between different parts of the engine, reducing the amount of heat lost to the environment.
Heat engines operate based on the principles of thermodynamics, specifically the second law of thermodynamics, which states that heat will always flow from a region of higher temperature to a region of lower temperature. In a heat engine, heat is converted into work, but the process is never 100% efficient.
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which of the following is true for an npn bjt ? select one: a. the base current consists of mostly holes b. a p-type base is sandwiched between an n-type emitter and an n-type collector c. current flows primarily because of electrons injected into the base d. all of these e. current flows when either vbe or vbc are positive voltages
Answers
For an NPN , the base current is primarily made up .
Which of the following statements is accurate about a npn transistor's active region?The potential difference between the collector and the base is always less than 0.4 V, and the base current and collector current are directly proportional to one another.
What are two defining characteristics?Based on the types of the three main terminals, can be divided into NPN and PNP types. An NPN transistor is made up of two semiconductor junctions with a thin p-anode region, and a PNP transistor is made up of two semiconductor junctions with a thin n- cathode region.
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It is okay to download information without asking a lab instructor as long as it is for your online class. true
false
Answers
Answer: It is false
Explanation:
Because if you was an kid and you were looking at violent stuff then your parent or guardian catch you looking at it you will be in troble.
simple Brayton cycle using air as the working fluid has a pressure ratio of 10. The minimum and maximum temperatures in the cycle are 295 and 1240 K. Assuming an isentropic efficiency of 83 percent for the compressor and 87 percent for the turbine, determine (a) the air temperature at the turbine exit, (b) the net work output, and (c) the thermal efficiency.
Answers
Answer:
a) 764.45K
b) 210.48 kJ/kg
c) 30.14%
Explanation:
pressure ratio = 10
minimum temperature = 295 k
maximum temperature = 1240 k
isentropic efficiency for compressor = 83%
Isentropic efficiency for turbine = 87%
a) Air temperature at turbine exit
we can achieve this by interpolating for enthalpy
h4 = 783.05 kJ/kg ( calculated in the background ) at state 4 using Table A-17 for Ideal gas properties of air
T4 ( temperature at Turbine exit ) = 760 + ( 780 - 760 ) \((\frac{783.05-778.18}{800.13-778.18} )\) = 764.45K
b) The net work output
first we determine the actual work input to compressor
Wc = h2 - h1 ( calculated values )
= 626.57 - 295.17 = 331.4 kJ/kg
next determine the actual work done by Turbine
Wt = h3 - h4 ( calculated values )
= 1324.93 - 783.05 = 541.88 kJ/kg
finally determine the network output of the cycle
Wnet = Wt - Wc
= 541.88 - 331.4 = 210.48 kJ/kg
c) determine thermal efficiency
лth = Wnet / qin ------ ( 1 )
where ; qin = h3 - h2
equation 1 becomes
лth = Wnet / ( h3 - h2 )
= 210.48 / ( 1324.93 - 626.57 )
= 0.3014 = 30.14%
how should water be added to a concrete mix
Answers
When adding water to a concrete mix, it is important to follow the manufacturer's instructions and use the right amount of water. Too little water can result in a dry, crumbly mix that is difficult to work with, while too much water can weaken the concrete and reduce its strength.
To add water to a concrete mix, follow these steps:
Begin by measuring out the amount of dry concrete mix that you need.Place the dry mix in a clean, dry mixing container, such as a wheelbarrow or cement mixer.Slowly add water to the dry mix, using a hose or watering can.Mix the water and dry mix together until the water is evenly distributed and the concrete reaches a uniform, smooth consistency.Continue to add small amounts of water as needed until the concrete reaches the desired consistency.Once you have added the desired amount of water, continue to mix the concrete for an additional 2-3 minutes to ensure that the water is evenly distributed and the concrete is properly mixed.It is important to note that the exact amount of water needed will vary depending on the type of concrete mix you are using, as well as the weather conditions and the intended use of the concrete. Therefore, it is important to follow the manufacturer's instructions and use the recommended amount of water.
An elevation is.... * 10 points a. A detailed description of requirements, composition and materials for a proposed building. b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building. c. The development of the last remaining lots in an existing developed area, the new development within an area already served by existing infrastructure and services, or the reuse of already developed, but vacant properties. d. The practice of creating structures and using processes that are environmentally responsible and resource-efficient throughout a building's life-cycle from siting to design, construction, operation, maintenance, renovation and deconstruction.
Answers
Answer:
b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building.
Explanation:
An elevation is a three-dimensional, orthographic, architectural projection that reveals just a side of the building. It is represented with diagrams and shadows are used to create the effect of a three-dimensional image.
It reveals the position of the building from ground-depth and only the outer parts of the structure are illustrated. Elevations, building plans, and section drawings are always drawn together by the architects.
Consider a regenerative gas-turbine power plant with two stages of compression and two stages of expansion. The overall pressure ratio of the cycle is 9. The air enters each stage of the compressor at 300 K and each stage of the turbine at 1200 K. Accounting for the variation of specific heats with temperature, determine the minimum mass flow rate of air needed to develop a net power output of 105 MW.
Answers
Answer: the minimum mass flow rate of air required to generate a power output of 105 MW is 238.2 kg/s
Explanation:
from the T-S diagram, we get the overall pressure ratio of the cycle is 9
Calculate the pressure ratio in each stage of compression and expansion. P1/P2 = P4/P3 = √9 = 3
P5/P6 = P7/P8 = √9 =3
get the properties of air from, "TABLE A-17 Ideal-gas properties of air", in the text book.
At temperature T1 =300K
Specific enthalpy of air h1 = 300.19 kJ/kg
Relative pressure pr1 = 1.3860
At temperature T5 = 1200 K
Specific enthalpy h5 = 1277.79 kJ/kg
Relative pressure pr5 = 238
Calculate the relative pressure at state 2
Pr2 = (P2/P1) Pr5
Pr2 =3 x 1.3860 = 4.158
get the two values of relative pressure between which the relative pressure at state 2 lies and take the corresponding values of specific enthalpy from, "TABLE A-17 Ideal-gas properties of air", in the text book.
Relative pressure pr = 4.153
The corresponding specific enthalpy h = 411.12 kJ/kg
Relative pressure pr = 4.522
The corresponding specific enthalpy h = 421.26 kJ/kg
Find the specific enthalpy of state 2 by the method of interpolation
(h2 - 411.12) / ( 421.26 - 411.12) =
(4.158 - 4.153) / (4.522 - 4.153 )
h2 - 411.12 = (421.26 - 411.12) ((4.158 - 4.153) / (4.522 - 4.153))
h2 - 411.12 = 0.137
h2 = 411.257kJ/kg
Calculate the relative pressure at state 6.
Pr6 = (P6/P5) Pr5
Pr6 = 1/3 x 238 = 79.33
Obtain the two values of relative pressure between which the relative pressure at state 6 lies and take the corresponding values of specific enthalpy from, "TABLE A-17 Ideal-gas properties of air", in the text book.
Relative pressure Pr = 75.29
The corresponding specific enthalpy h = 932.93 kJ/kg
Relative pressure pr = 82.05
The corresponding specific enthalpy h = 955.38 kJ/kg
Find the specific enthalpy of state 6 by the method of interpolation.
(h6 - 932.93) / ( 955.38 - 932.93) =
(79.33 - 75.29) / ( 82.05 - 75.29 )
(h6 - 932.93) = ( 955.38 - 932.93) ((79.33 - 75.29) / ( 82.05 - 75.29 )
h6 - 932.93 = 13.427
h6 = 946.357 kJ/kg
Calculate the total work input of the first and second stage compressors
(Wcomp)in = 2(h2 - h1 ) = 2( 411.257 - 300.19 )
= 222.134 kJ/kg
Calculate the total work output of the first and second stage turbines.
(Wturb)out = 2(h5 - h6) = 2( 1277.79 - 946.357 )
= 662.866 kJ/kg
Calculate the net work done
Wnet = (Wturb)out - (Wcomp)in
= 662.866 - 222.134
= 440.732 kJ/kg
Calculate the minimum mass flow rate of air required to generate a power output of 105 MW
W = m × Wnet
(105 x 10³) kW = m(440.732 kJ/kg)
m = (105 x 10³) / 440.732
m = 238.2 kg/s
therefore the minimum mass flow rate of air required to generate a power output of 105 MW is 238.2 kg/s
Which of the following lists, among other things, the vehicle identification, the customer's concern or complaint, and costs for parts? A. Repair order B. Owner's manual C. Comeback report D. Service manual
Answers
Answer:
I think it is D.service manual
Explanation:
Because it is the vehicle identification
An electrical engineer at GRIDCO is given two separate toolboxes to keep his working tools. The first toolbox has 4 white fuses and 3 black fuses and the second toolbox has 3 white fuses and 5 black fuses. Suppose the engineer select a fuse from the first toolbox and placed unseen in the second toolbox. What is the probability that: (a) the fuse drawn from the second toolbox is black? (B) the fuse drawn from the second toolbox is white? (8) ane is white?
Answers
(a) The probability of drawing a black fuse from the second toolbox is 4/7.
(b) The probability of drawing a white fuse from the second toolbox is 3/7.
(c) The probability that one fuse is white is 27/49.
To calculate the probabilities, we need to consider the number of white and black fuses in each toolbox.
First, let's determine the total number of fuses in each toolbox:
First Toolbox:
Total fuses = 4 white fuses + 3 black fuses = 7 fuses
Second Toolbox:
Total fuses = 3 white fuses + 5 black fuses = 8 fuses
(a) The probability that the fuse drawn from the second toolbox is black:
The probability of drawing a black fuse from the second toolbox depends on the fuse selected from the first toolbox. There are two scenarios to consider:
Scenario 1: The fuse selected from the first toolbox is black.
In this case, the second toolbox will have 3 black fuses remaining out of the total 7 fuses.
Probability = (Number of black fuses in the second toolbox)/(Total number of fuses in the second toolbox)
Probability = 3/7
Scenario 2: The fuse selected from the first toolbox is white.
In this case, the second toolbox will have 5 black fuses out of the total 7 fuses.
Probability = (Number of black fuses in the second toolbox)/(Total number of fuses in the second toolbox)
Probability = 5/7
To calculate the overall probability, we need to consider the probability of each scenario and weigh it by the probability of selecting a fuse of that color from the first toolbox. Since the fuse from the first toolbox has an equal chance of being white or black, we need to take an average of the probabilities in both scenarios.
Probability of drawing a black fuse from the second toolbox = (Probability of scenario 1 + Probability of scenario 2)/2
Probability of drawing a black fuse from the second toolbox = (3/7 + 5/7)/2
Probability of drawing a black fuse from the second toolbox = 8/14
Probability of drawing a black fuse from the second toolbox = 4/7
Therefore, the probability of drawing a black fuse from the second toolbox is 4/7.
(b) The probability that the fuse drawn from the second toolbox is white:
Similarly, we can calculate the probability of drawing a white fuse from the second toolbox. It will be the complement of the probability of drawing a black fuse.
Probability of drawing a white fuse from the second toolbox = 1 - Probability of drawing a black fuse from the second toolbox
Probability of drawing a white fuse from the second toolbox = 1 - 4/7
Probability of drawing a white fuse from the second toolbox = 3/7
Therefore, the probability of drawing a white fuse from the second toolbox is 3/7.
(c) The probability that one is white:
To calculate the probability that one fuse is white, we need to consider both scenarios: either the fuse drawn from the first toolbox is white and the fuse drawn from the second toolbox is black, or the fuse drawn from the first toolbox is black and the fuse drawn from the second toolbox is white.
Scenario 1: Fuse drawn from the first toolbox is white, and the second toolbox has a black fuse:
Probability = (Probability of drawing a white fuse from the first toolbox) * (Probability of drawing a black fuse from the second toolbox)
Probability = (3/7) * (5/7)
Scenario 2: Fuse drawn from the first toolbox is black, and the second toolbox has a white fuse:
Probability = (Probability of drawing a black fuse from the first toolbox) * (Probability of drawing a white fuse from the second toolbox)
Probability = (4/7) * (3/7)
To calculate the overall probability, we need to sum up the probabilities of both scenarios:
Probability that one fuse is white = Probability
of scenario 1 + Probability of scenario 2
Probability that one fuse is white = (3/7) * (5/7) + (4/7) * (3/7)
Probability that one fuse is white = 15/49 + 12/49
Probability that one fuse is white = 27/49
Therefore, the probability that one fuse is white is 27/49.
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which graph best represents the relationship between the power required to raise an elevator
Answers
The graph that best represents the relationship between the power required to raise an elevator is a linear graph.
To determine the graph we need to understand the relationship between power, force, and velocity.
1. First, recall the formula for power: Power (P) = Force (F) x Velocity (v)
2. In the case of an elevator, the force required is equal to the weight of the elevator (mass x acceleration due to gravity): F = m x g
3. The velocity of the elevator remains constant as it moves upward at a steady speed.
Now, let's analyze the relationship between power and the elevator's movement:
1. As the elevator's mass (m) increases, the force required to lift it (F) also increases, which in turn increases the power needed.
2. When the elevator is moving at a constant speed, the velocity (v) remains the same.
In conclusion, the graph that best represents the relationship between the power required to raise an elevator will show a linear relationship between the power and the elevator's mass. As the mass of the elevator increases, the power required to lift it will also increase proportionally, assuming constant velocity.
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