The exact value of A in the general solution is 13
Also, the DEQ is separable
How to determine the value of A in the general solutionFrom the question, we have the following parameters that can be used in our computation:
y = Ax² + C/x
The differential equation is given as
y' + y/x = 39x
When y = Ax² + C/x is differentiated, we have
y' = 2Ax - Cx⁻²
So, we have
2Ax - Cx⁻² + y/x = 39x
Recall that
y = Ax² + C/x
So, we have
2Ax - Cx⁻² + (Ax² + C/x)/x = 39x
Evaluate
2Ax - Cx⁻² + Ax + Cx⁻² = 39x
This gives
2Ax + Ax = 39x
So, we have
3Ax = 39x
By comparing both sides of the equation, we have
3A = 39
Divide both sides by 3
A = 13
Hence, the value of A in the general solution is 13
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Jessie borrowed $1800 from the bank at a rate of 7.5% simple interest per year. Over the course of 4 years, how much interest did he pay?
Why is vertex from important?
Answer:
The vertex form of a quadratic function is an expression that easily provides the coordinates of the vertex point on the parabola. The vertex point is the extreme point on a parabola. If the quadratic term is positive, the parabola opens up, therefore the vertex is a minimum point.
Step-by-step explanation:
how many college credit hours will you have earned by your high school graduation date? if you have not earned any hours enter
I have earned 10 college credit hours before end of my high school graduation date.
A credit hour is an approach to estimating how much credit an understudy gets for going to a course which relates to the hours out of each week spent in that course. Dissimilar to numerous conventional secondary school courses that expect understudies to go to class consistently, school courses may just meet a few times each week.
Each hour that an understudy spends in the class regularly compares to a credit hour. For instance, on the off chance that an understudy signs up for a class that meets for one hour on Monday, Wednesday, and Friday, that course would be worth three credit hours, which is normal of numerous school courses.
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suppose a research report states that the result of a between subjects one-way anova is f (3, 32) = 3.47 should the researcher reject the null hypothesis if using alpha = .05
Based on the given information, the researcher should not reject the null hypothesis if using an alpha level of 0.05.
In hypothesis testing, the null hypothesis is typically assumed to be true until there is sufficient evidence to reject it. To determine whether to reject the null hypothesis, researchers often compare the calculated F-value from an ANOVA test with the critical F-value. The critical F-value is based on the significance level (alpha) chosen for the test. In this case, the given F-value is 3.47 with degrees of freedom (3, 32), indicating that there are three groups and a total of 32 observations. To make a decision, the researcher needs to compare the calculated F-value to the critical F-value. If the calculated F-value is greater than the critical F-value, the null hypothesis is rejected. However, if the calculated F-value is less than or equal to the critical F-value, the null hypothesis is not rejected. Since the critical F-value corresponding to alpha = 0.05 is not provided in the question, we cannot determine whether the null hypothesis should be rejected.
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This probability is greater than the probability of flipping exactly two tails, which is .
Answer:
The probability of getting exactly two tails = 1/4
All the values greater than 1/4
or 3/4
Step-by-step explanation:
In a flip of a coin the probability of getting a tail is 1/2. If this is denoted by p =1/2 then q= 1-p= 1-1/2= 1/2
and if we have number of trials n=2
Then the binomial distribution can be applied.
(p+q)ⁿ =(p+q)² = 2c0p⁰q2 + 2c1p¹q¹ + 2c2p²q⁰
We wish to find probability of flipping exactly two coins given by 2c2p²q⁰
= 2c2 (1/2)²(1/2)⁰
= 1/4
So the probability of getting exactly two tails = 1/4
The probability greater than 1/4 can be all the values from 2/4, 3/4 ------1
or it can be found by
1- 1/4 = 3/4
as the total probability is always equal to 1
Graph the line with slope 3/2 and y intercept -6
Answer:
\(y = 3 \div 2x - 6\)
Step-by-step explanation:
You do this by placing the graph on -6, then you go up 3/2.
Step-by-step explanation:
Given the linear equation, y = 3/2x - 6:
where the slope, m = 3/2
and y-intercept, (0, -6).
I plotted the y-intercept on the graph, then used the slope (3 rise, 2 run) to plot the other points on the graph and create a line.
Attached is the screenshot of the graphed line.
Please mark my answers as the Brainliest, if you find this helpful :)
Can someone help me please ?
Initialize these numbers.
a 45
b 64
c 98
d 108
e 78
f 75
g 88
h 250
Answer:
you can eat this samosa then you will got answer
In the 1930s a prominent economist devised the following demand function for corn: p = 6,600,000 q1.3 , where q is the number of bushels of corn that could be sold at p dollars per bushel in one year. Assume that at least 13,000 bushels of corn per year must be sold. (a) How much should farmers charge per bushel of corn to maximize annual revenue? HINT [See Example 3, and don't neglect endpoints.] (Round to the nearest cent.) p = $ (b) How much corn can farmers sell per year at that price? q = bushels per year (c) What will be the farmers' resulting revenue? (Round to the nearest cent) per year
The price that maximizes annual revenue is $17.86 per bushel, which should be charged by the farmers; The quantity of corn that can be sold per year at 67,786 bushels per year; the farmers' resulting revenue will be $1,210,392.96 per year.
To find the price that maximizes annual revenue, we need to differentiate the revenue function with respect to the price and set it equal to zero:
Revenue = pq = (6,600,000q^1.3)q
= 6,600,000q^2.3
dRevenue/dp = q
Setting dRevenue/dp = 0, we get q = 0, which is not a valid solution. Therefore, we need to consider the endpoints of the feasible range, which is q >= 13,000.
At q = 13,000, we have p = 6,600,000*13,000^(-0.3) ≈ $17.86 per bushel.
At q → ∞, we have p → 0.
So, the price that maximizes annual revenue is $17.86 per bushel, which should be charged by the farmers.
The quantity of corn that can be sold per year at that price is given by
q = (p/6,600,000)^(1/1.3)
= (17.86/6,600,000)^(1/1.3)
≈ 67,786 bushels per year.
The farmers' resulting revenue will be Revenue = p*q
= $17.86 * 67,786
≈ $1,210,392.96 per year.
Therefore, the price that maximizes annual revenue is $17.86 per bushel, which should be charged by the farmers; The quantity of corn that can be sold per year at 67,786 bushels per year; the farmers' resulting revenue will be $1,210,392.96 per year.
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Find the directional derivative of f (x, y, z) = 2z2x + y3 at the point (1, 2, 2) in the direction of the vector 1/5akar i + 1/5akar j
(Use symbolic notation and fractions where needed.) directional derivative:
ఊhe directional derivative of f at the point (1, 2, 2) in the direction of the vector v = (1/5√2)i + (1/5√2)j is 2√2.
To find the directional derivative of the function f(x, y, z) = 2z^2x + y^3 at the point (1, 2, 2) in the direction of the vector v = (1/5√2)i + (1/5√2)j, we can use the formula for the directional derivative:
D_v(f) = ∇f · v
where ∇f is the gradient of f.
Taking the partial derivatives of f with respect to each variable, we have:
∂f/∂x = 2z^2
∂f/∂y = 3y^2
∂f/∂z = 4xz
Evaluating these partial derivatives at the point (1, 2, 2), we get:
∂f/∂x = 2(2)^2 = 8
∂f/∂y = 3(2)^2 = 12
∂f/∂z = 4(1)(2) = 8
Therefore, the gradient ∇f at (1, 2, 2) is given by ∇f = 8i + 12j + 8k.
Substituting the values into the directional derivative formula, we have:
D_v(f) = ∇f · v = (8i + 12j + 8k) · (1/5√2)i + (1/5√2)j
= 8(1/5√2) + 12(1/5√2) + 8(0)
= (8/5√2) + (12/5√2)
= (8 + 12)/(5√2)
= 20/(5√2)
= 4/√2
= 4√2/2
= 2√2
Hence, the directional derivative of f at the point (1, 2, 2) in the direction of the vector v = (1/5√2)i + (1/5√2)j is 2√2.
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The first bag of chips is selling for $2.68 for 10 oz and the bigger bag of chips sells for $3.48 for 14 oz. Which bag will you spend your money on and what is that cost per ounce of chip?
HELPPPPPPPPPPPPP
Answer:
2.68 for 10oz= 37 each nd
3.48 for 14 oz= 40
Step-by-step explanation:
its something like that
Two times a number added to the other number is 25. Three times the first numb
minus the other number is 20. Find the numbers.
Answer:
First number = 9
Second number = 7
Step-by-step explanation:
Let x be the first number and y be the second.
2x + y = 25
3x - y = 20
1) Add them together.
5x = 45
x = 9
2) Solve for y.
2(9) + y = 25
y=7
3) Check your work on the other equation.
3(9) - (7) = 20
27 - 7 = 20
20 = 20
Therefore the first number is 9 and the second number is 7.
The larger of two numbers is four times the smaller and their sum is 85. Find the two numbers.
Answer:
Let x be the smallest number, and let y and z be the larger numbers....therefore, we have..
(y + z) = 4x
And
x + (y + z) = 85 substitute for (y + z)
x + 4x = 85
5x = 85 divide by 5 on both sides
x = 17
And (y + z) = 4(17) = 68
Unfortunately, we cannot determine the exact values for y and z....there are infinite possibilities.....!!!
Step-by-step explanation:
Answer:
x = 68
y = 17
Step-by-step explanation:
Let the two numbers be x (larger number) and y (smaller number).
Condition 1:x = 4y -----------------(1)
Condition 2:x + y = 85 -----------(2)
Put Eq. (1) in (2)
4y + y = 85
5y = 85
Divide both sides by 5
y = 85/5
y = 17Put y = 17 in Eq. (1)
x = 4(17)
x = 68\(\rule[225]{225}{2}\)
A spinner has 8 equal-sized sections. Six of the sections are orange.
Answer:
6 put of 8, 3/4, or 75%
Step-by-step explanation:
Hope this helps ! :) good luck
Which equation has exactly one solution in common with the equation y = 6x - 2?
18x-3y=6
(1/2)y=3x-2
2y=4x-12
18x-12-3y
Answer: 18x-12-3y
Step-by-step explanation:
To find which equation has exactly one solution in common with y = 6x - 2, we need to determine the point where they intersect.
Substituting y = 6x - 2 into the equations given, we get:
18x - 3(6x - 2) = 6
Simplifying this equation gives us:
x = 2
Substituting x = 2 into y = 6x - 2, we get:
y = 6(2) - 2 = 10
Therefore, the point where y = 6x - 2 intersects with the other equations is (2, 10).
Now, we can substitute x = 2 and y = 10 into each of the other equations to see which ones have exactly one solution:
(1) 18x - 3y = 6:
18(2) - 3(10) = 6
36 - 30 = 6
This equation does not have exactly one solution at (2, 10).
(2) (1/2)y = 3x - 2:
(1/2)(10) = 3(2) - 2
5 = 4
This equation does not have exactly one solution at (2, 10).
(3) 2y = 4x - 12:
2(10) = 4(2) - 12
20 = 0
This equation does not have exactly one solution at (2, 10).
(4) 18x - 12 - 3y = 0:
18(2) - 12 - 3(10) = 0
36 - 12 - 30 = 0
This equation has exactly one solution at (2, 10).
Therefore, the equation that has exactly one solution in common with y = 6x - 2 is 18x - 12 - 3y = 0.
a. Provide an example of application of the Density Property of Real Numbers.b. State another property of numbers along with an example.
a. Adding the same number to two numbers produces the same result. Example: 4 + 3 = 7, 7 + 3 = 10, b. Commutative Property: Order does not matter. Example: 4 + 7 = 7 + 4.
The Density Property of Real Numbers states that between any two real numbers, there are an infinite number of other real numbers. This means that for any two real numbers, no matter how close or far apart they are, there is always a third number between them. An example of this property would be if we have two numbers, 4 and 7. If we add 3 to each of these numbers, we will get the same result. 4 + 3 = 7, and 7 + 3 = 10. This shows that no matter what two real numbers we pick, there will always be a third number between them, and when we add the same number to both of them, we will get the same result. Another property of numbers is the Commutative Property, which states that the order of the numbers doesn’t matter when performing certain operations. For example, when adding two numbers, 4 + 7 = 7 + 4. This means that it doesn’t matter which number comes first when adding. This property applies to other operations as well, such as multiplication, division, and subtraction.
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a 2.3-m-long string is under 26 n of tension. a pulse travels the length of the string in 54 ms .
In this scenario, we are given a string that is 2.3 meters long and under a tension of 26 N. Additionally, a pulse travels the length of the string in 54 ms.
When a pulse travels through a string, it causes the string to vibrate and move. The tension of the string determines how quickly the pulse can travel and how far it can go. In this case, the tension of 26 N is relatively high, which means that the pulse can travel quickly and over a significant distance.
The fact that the pulse travels the length of the string in 54 ms tells us something about the speed of the pulse. We can use the formula speed = distance / time to calculate the speed of the pulse. In this case, the distance is the length of the string, which is 2.3 m. The time is 54 ms, or 0.054 s.
So, speed = distance / time = 2.3 m / 0.054 s = 42.59 m/s.
We now know the speed of the pulse, but what about the tension and length of the string? We can use the formula v = sqrt(T/μ) to calculate the speed of a pulse in a string, where v is the speed of the pulse, T is the tension of the string, and μ is the mass per unit length of the string.
Rearranging this formula, we get T = μv^2. We can use this formula to find the tension of the string. Plugging in the values we know, we get:
T = μv^2 = (mass per unit length of string) * (speed of pulse)^2
We don't know the mass per unit length of the string, but we can find it using the formula μ = m / L, where m is the mass of the string and L is its length.
Assuming the string has a uniform density, we can calculate its mass using the formula m = ρAL, where ρ is the density of the string, A is its cross-sectional area, and L is its length.
We don't know the cross-sectional area, but we can make a rough estimate based on the thickness of the string. Assuming the string has a circular cross-section, we can use the formula A = πr^2, where r is the radius of the string.
Again, we don't know the radius of the string, but we can make a rough estimate based on its diameter. Assuming the string has a diameter of 2 mm, its radius is 1 mm, or 0.001 m.
Plugging in these values, we get:
A = π(0.001 m)^2 = 7.85 x 10^-7 m^2
m = ρAL = (density of string) * (cross-sectional area) * (length of string)
= (density of string) * (7.85 x 10^-7 m^2) * (2.3 m)
We don't know the density of the string, but assuming it is made of nylon or a similar material, its density is around 1100 kg/m^3. Plugging in this value, we get:
m = 2.039 x 10^-3 kg
μ = m / L = 2.039 x 10^-3 kg / 2.3 m = 8.86 x 10^-4 kg/m
Now we can use the formula T = μv^2 to find the tension of the string. Plugging in the values we know, we get:
T = μv^2 = (8.86 x 10^-4 kg/m) * (42.59 m/s)^2 = 159.3 N
So the tension of the string is 159.3 N, which is much higher than the original tension of 26 N. This makes sense, since the pulse travels quickly and over a significant distance, indicating that the tension must be high.
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Mrs . Bell had a 256-ounce bag of potting soil. What is the greatest number of 6-ounce pots she can completely fill with soil?
Answer:
42
Step-by-step explanation:
256 / 6 = 42.66666 since where only county full pots its 42
I need help and i need it quickly
100 points on the line!
Find the arclength of the curve r(t) = < 4t^2,2(sqrt(4))t, ln(t) > , 1 < t < 6
The arclength of the curve r(t) = < 4t², 2(√4)t, ln(t) >, 1 < t < 6, is (π + √2)/2.
To find the arclength of the curve r(t) = < 4t², 2(√4)t, ln(t) >, 1 < t < 6, we can use the following formula:arclength = ∫_a^b √[dx/dt² + dy/dt² + dz/dt²] dtwhere a = 1 and b = 6.
Let's begin by computing dx/dt, dy/dt, and dz/dt:dx/dt = 8t, dy/dt = 4, and dz/dt = 1/tNow, let's compute dx/dt², dy/dt², and dz/dt²:dx/dt² = 8, dy/dt² = 0, and dz/dt² = -1/t²
Therefore, the integrand is:√[dx/dt² + dy/dt² + dz/dt²] = √(8 + 0 + (-1/t²)) = √(8 - 1/t²)The arclength is then given by:arclength = ∫_1^6 √(8 - 1/t²) dtThis integral can be difficult to solve directly.
However, we can make a substitution u = 1/t, du/dt = -1/t², and rewrite the integral as:arclength = ∫_1^6 √(8 - 1/t²) dt= ∫_1^1/6 √(8 - u²) (-1/du) (Note the limits of integration have changed.)= ∫_1/6^1 √(8 - u²) du
This is now in a form that can be solved using trigonometric substitution.
Let u = √8 sinθ, du = √8 cosθ dθ, and substitute:arclength = ∫_π/4^0 √(8 - 8sin²θ) √8 cosθ dθ= 2∫_0^π/4 √2 cos²θ dθ= √2 ∫_0^π/4 (cos(2θ) + 1) dθ= √2 [sin(2θ)/2 + θ]_0^π/4= √2 (sin(π/2) - sin(0))/2 + √2 π/4= √2/2 + √2 π/4= (π + √2)/2
Therefore, the arclength of the curve r(t) = < 4t², 2(√4)t, ln(t) >, 1 < t < 6, is (π + √2)/2.
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Twelve hungry teenagers can devour a very large pizza in $20$ minutes. How many teenagers would it take to finish a very large pizza in $15$ minutes
Answer:
9 teenagers
Step-by-step explanation:
12/20 = x/15
180/20 = x
9 = x
-----------------------
9 teenagers would take to finish the large pizza in 15 mins
Write two different quadratic functions whose graphs pass through (4,0) and (1,0)
The quadratic equation of function in the standard form is Y = -1.25 x² + 5x.
Since quadratic equation's x-intercepts are (-5, 0). That indicated that the quadratic equation's two elements are (x + 5) and (x -0).
f(x) = a (x + 5) (x - 0) (x - 0)
= ax+5a
The quadratic equation's graph goes through (4, 0). thus, we must change equation 1 to read x = 4 and f(x) = 0.
0 = a × 4² + (5 × 4)
0 = a × 16 +20
The quadratic equation is known to have the form ax² + bx + c = 0.
f(x) = -1.25 + 5x
Consider y= F(x)
∴ Y = -1.25 x² + 5x.
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Lana had 475 Pokemon cards. She gave her little brother 125 of her cards. What percentage of her cards did Lana give away?
So, Lana gave away 26.32% of he Pokemon cards to her little brother.
To find the percentage of cards Lana gave away, we can use the formula:(Quantity given away / Total quantity) * 100.
In this case, Lana gave away 125 cards out of her total collection of 475 cards.Plugging these values into the formula, we have:
(125 / 475) * 100 = 0.2632 * 100 = 26.32%.
Lana gave away 26.32% of her Pokemon cards to her little brother.
Alternatively, we can calculate the percentage by subtracting the remaining cards from the total and finding the ratio:
Percentage given away
= (Cards given away / Total cards) * 100
= (125 / 475) * 100
= 26.32%.
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A soccer team uses 5-gallon coolers to hold water during games and practices. Each cooler holds 570 fluid ounces. The team has small cups that each hold 5.75 fluid ounces and large cups that each hold 7.25 fluid ounces.
The team utilizes 5-gallon coolers, small cups (5.75 fluid ounces), and large cups (7.25 fluid ounces) to manage and distribute water effectively during their soccer activities.
The soccer team uses 5-gallon coolers to hold water during games and practices. Each cooler has a capacity of 570 fluid ounces. This means that each cooler can hold 570 fluid ounces of water.
To serve the players, the team has small cups that hold 5.75 fluid ounces and large cups that hold 7.25 fluid ounces. The small cups are smaller in size and can hold 5.75 fluid ounces of water, while the large cups are larger and can hold 7.25 fluid ounces of water.
These cups are used to distribute the water from the coolers to the players during games and practices. Depending on the amount of water needed, the team can use either the small cups or the large cups to serve the players.
Using the cups, the team can measure and distribute specific amounts of water to each player based on their needs. This ensures that the players stay hydrated during the games and practices.
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Note the full question may be :
The soccer team wants to distribute water to the players using both small and large cups. If they want to fill as many small and large cups as possible from one 5-gallon cooler without any leftover water, how many small and large cups can be filled?
What's the slope actual answers please
Answer:
See below
Step-by-step explanation:
Line goes through 0,0 and 2,3
Slope = rise / run = 3 / 2 cm/week
What is the diameter of a circle if the circumference is 18.84 ?
Answer:
6
Step-by-step explanation:
FREE BRAINLESS THE FIRST PERSON WHO ANSWER THIS
leo spends $5 per week on music. write an equation that equation that determines the dollars spend D per week.
A. d=5w
b. d=5+w
c. w=5d
d. w=5+d
if a seed is planted, it has a 65% chance of growing into a healthy plant. if 12 seeds are planted, what is the probability that exactly 3 don't grow?
There is a 136.13 probability that 3 won't increase.
Only 0.65% of seeds will grow into robust plants.
There is a 0.35 probability that a seed won't grow into a robust plant.
In this case, n = 12 and r = 3.
11 seeds will sprout if 1 seed doesn't germinate. Raising 0.65 to the power of 11 and 0.35 to the power of 3 will result in the following: 11 seeds develop, and we use the 11th power; 3 seeds do not grow, so we use the power of 3:
So, the response is:
\({}^{12}C_3\) × \({(chance of successful growth) }^{11}\)x \((chance of Unsuccessful growth)^3\)
= \({}^{12}C_3\) × \(0.65^{11}\) × \({0.35}^3\)
= 362880 × 0.008750 × 0.042875
= 136.13
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1. Determine the values of a and k when 299,790,000 is written in scientific notation.2. Determine the values of a and k when 0.51 is written in scientific notation.
(a) On writing 299790000 in scientific notation , the value of a is 2.9979 and value of k is 8 .
(b) On writing 0.51 in scientific notation , the value of a is 5.1 and value of k is -1 .
What is Scientific Notation ?
The general form of writing a number in scientific notation is ⇒ \(a\times 10^{k}\) ;
Part (a) ;
the number is given to be : 299790000 ;
For writing it in scientific notation, decimal point will be placed after 2 ;
So , the scientific notation of the number is ⇒ \(2.9979 \times 10^{8}\) ,
On comparing it with the general form of scientific notation,
we get , a = 2.9979 and k = 8 .
Part (b) ;
the number is given to be : 0.51 ;
For writing it in scientific notation, decimal point will be placed after 5 ;
So , the scientific notation of the number is ⇒ \(5.1 \times 10^{-1}\) ,
On comparing it with general form of scientific notation,
we get , a = 5.1 and k = -1 .
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What is the square root of 16x^16
Answer:
4x⁸Step-by-step explanation:
\(\sqrt{16x^{16}}=\sqrt{16}\cdot\sqrt{x^{16}}=4\cdot x^8\)
The square root of 16x¹⁶ is 4x⁸
What is expression?
Expressions is the defined as mathematical statements that have a minimum of two terms containing variables or numbers
\(\sqrt{16x^1^6}\)
Rewrite \(16x^1^6\) as \((4x^8)^2\)
\(\sqrt{ (4x^8)^2}\)
Pull terms out from under the radical, assuming positive real numbers
\(4x^8\)
Hence, the square root of 16x¹⁶ = 4x⁸
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