Ydu have 50g of water in a beaker, and the water is 24 degrees Celsius. If
you divide the water into two beakers, with 25g in each beaker, what is
the temperature of each one?
Answers
If 50g of water in a beaker is split into two beakers i.e. 25g in each beaker, the temperature of each of one will still be 24°C.
What is temperature?Temperature is the degree of hotness or coldness of a body. Temperature is measured in °C.
According to this question, there is 50g of water in a beaker, and the water is 24 degrees Celsius.
If I divide the water into two beakers, with 25g in each beaker, the temperature of the water in each beaker will be 24°C.
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Related Questions
An object of mass 6 kg accelerates from 5 m/s to 9 m/s in 8 s. How much work was done on the object during this time? how much power was applied? what is its change in momentum?
Answers
Answer:
(1)540 J
(2)67.5 J/s or 67.5W
(3)look at underline statement in explanation
Explanation:
(1) acceleration = change in speed ÷ time
= (9-5)m/s ÷ 8s
= 0.50 m/s²
resultant force of object during motion
= mass(in kg) × acceleration
= 6 × 0.50 = 3 N
displacement of force applied
= area under speed time graph(when sketched out, it's a trapezium)
= ½ × (5+9) × 8
= 180m
work done is measured in joules
= force × displacement of force applied
= 3N × 180m
= 540 J
detailed explanation:
altho the final unit for the work done should be Nm, but J is equal to Nm.
(2) Power is measured by J/s
therefore power = 540 J ÷ 8s = 67.5 J/s or 67.5 W
(3) the object accelerates constantly along a straight road
Q.7. For a system with a transfer function of G(s)=- co² s² +2a+w² if the natural frequency is 0.5 and the damping ratio is 1.3, which of the following statements is correct regarding the unit step response of the system?
O A) Damped
O B) Undamped
O C) Underdamped
O D) Crittically Damped
O E) Overdamped
Answers
The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)
The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.
To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).
The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).
In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).
Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.
If co > co_critical, the system is considered overdamped (Option E).
If co = co_critical, the system is considered critically damped (Option D).
If co < co_critical, the system is considered underdamped (Option C).
Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.
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a 4.60 kg mass is placed on top of a vertical spring, which compresses a distance of 2.31 cm. calculate the force constant (in n/m) of the spring.
Answers
The restoring force of the spring cancels the weight of the mass, so by Newton's second law
∑ F = F[spring] - mg = 0 ⇒ F[spring] ≈ 45.1 N
where m = 4.60 kg and g = 9.80 m/s². Then the spring constant is k such that by Hooke's law,
F[spring] = k x
where x = 0.0231 m. Then the spring constant is
k = F[spring]/x ≈ 1950 N/m
a particle is projected from a point a with a velocity of 21m/s at an angle of 53.1 degees to the horizontal. one second later another particle is projected at a point 0.3m below a with initial velocity of 31.5m/s at an angle of 36.9 degrees to the horizontal.
(i) prove that the particles collide
(ii) find the time of collision
(iii) find the distance of collision from point of projection
Answers
Answer:
(i) Please see graph of the motion of the particles created with MS Excel and the calculations in the following sections
(ii) The time of collision is approximately 1.0 seconds
(iii) The common horizontal distance of point collision from the point of projection is approximately 25.2 meters
Explanation:
The velocity with which the first projectile was fired, v₁ = 21 m/s
The angle to the horizontal the particle is launched = 53.1°
The time at which the other particle was launched = 1 second later
The location from which the other particle was projected = 0.3 m below the first particle
The initial velocity of the second particle = 31.5 m/s
The angle to the horizontal at which the second particle was projected, θ = 36.9°
(i) The height reached, by each of the particle is given as follows;
y = u·t - 1/2·g·t²
For the first projectile, we have;
y = 21·(t₁+1)×sin(53.1°) - 9.81·(t₁+1)²/2 + 0.3
For the second projectile, we have;
y= 31.5·(t₁)×sin(36.9°) - 4.905·(t₁)²
If the two projectiles collide, we get;
21·(t₁+1)×sin(53.1°) - 9.81·(t₁+1)²/2 + 0.3 = 31.5·(t₁)×sin(36.9°) - 4.905·(t₁)²
Using a graphing calculator for simplifying, we get;
-11.93·t₁ + 12.2 = 0
t₁ = 12.2/11.93 ≈ 1.02
Therefore, at time t₁ = 1.02 seconds, after the launch of the second particle, the two particle will be at the same vertical height
However, whereby at the time, t₂, the particles collide, the horizontal distance travelled, 'x', will be equal;
We have;
x = u·cos(θ)·t₁
For the first particle, we have;
x₁₁ = 21 × cos (53.1°) × (t₂ + 1)
For the second particle, we have;
x₂₂ = 31.5 × cos (36.9°) × t₂
At the point of collision, we have;
x₁ = x₂
∴ 21 × cos (53.1°) × (t₂ + 1) = 31.5 × cos (36.9°) × t₂
31.5 × cos (36.9°) × t₂ - 21 × cos (53.1°) × t₂ = 21 × cos (53.1°)
t₂ = 21 × cos (53.1°)/(31.5 × cos (36.9°) - 21 × cos (53.1°) ) = 1.00219236871
t₂ ≈ 1.0 seconds
Given that t₁ ≈ t₂, the particles reach the same height and the same horizontal distance at the same time, t₂ ≈ 1.0 and therefore, they collide.
(ii) The time of collision is found above as t₁ ≈ t₂ ≈ 1.0 seconds
(iii) The horizontal distance of the point of collision from the starting point, 'x', is given as follows;
x = 21 × cos (53.1°) × (1.0 + 1) ≈ 25.2
The horizontal distance of the point of collision from the starting point, x ≈ 25.2 meters
The vertical distance of the point of collision from the starting point of the second particle, 'y', is given as follows;
y = 21 × (1+1)×sin(53.1°) - 9.81 × (1+1)²/2 + 0.3 ≈ 14
The vertical distance of the point of collision from the starting point of the second particle, y ≈ 14 meters
The magnitude of the distance from the starting point of the second particle, r = √(25.2² + 14²) ≈ 28.8
The magnitude of the distance from the starting point of the second particle, r ≈ 28.4 meters.
Two identical speakers are 3.50 m
and 5.20 m from a listener. What is
the lowest frequency (n = 0) that
would cause destructive
interference there?
(Unit = Hz)
Answers
Answer:
The difference in distance from the speakers is 5.2 - 3.5 = 1.7 m
The listener would be 1/2 wavelength out of phase with the speakers
1/2 y = 1.7 m where y is the wavelength
y = 3.4 m the required wavelength
f = v / y = 340 m/s / 3.4 m = 100 / sec lowest frequency
Answer:
100.8
Explanation:
Trust :)
Help!
In a school zone, speeding fines?
A. are the same.
B. are doubled.
C. are tripled.
Answers
A(n) is a material that charges CAN move freely through.
a. Electric insulator
b. Electric conductor
c. Electric discharge
Answers
Answer:
c
step by step explanation
discharges let electric charge move freely
Answer:
definitely b
Explanation:
conductors let electric charges move freely whereas insulators and discharge don't
hope this helps
A truck of mass 4000kg is at rest, but free to roll without resistance. If you push it forward with a force of 500N, the momentum at the end of 5 seconds of pushing will be _____
Answers
The momentum at the end of 5 seconds of pushing a truck of mass 4000kg, that is at rest but free to roll without resistance, with a force of 500N will be 2500 kg m/s.
To calculate the momentum, we first need to find the acceleration of the truck. We can use the formula F = ma, where F is the force applied, m is the mass of the truck, and a is the acceleration. Rearranging the formula to solve for a, we get a = F/m = 500N/4000kg = 0.125 m/s^2.
Next, we can use the formula for momentum, p = mv, where p is the momentum, m is the mass of the truck, and v is the velocity. Since the truck is at rest initially, the initial momentum is zero. After 5 seconds of pushing, the final velocity of the truck can be found using the formula v = u + at, where u is the initial velocity (which is zero in this case) and t is the time taken. Substituting the values, we get v = 0 + 0.125 m/s^2 x 5 s = 0.625 m/s.
Finally, we can find the momentum using p = mv = 4000kg x 0.625 m/s = 2500 kg m/s. Therefore, the momentum at the end of 5 seconds of pushing will be 2500 kg m/s.
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The specific gravity of an material is defined as the ratio of the density of the material to the density of water. The specific gravity of ice is 0.917, whereas that of seawater is 1.025.
What fraction of an iceberg is above the surface of the water?
\frac{V_{above}}{V_{total}} = ____________
Answers
The fraction of the iceberg that is above the surface of the water is 8.3 %.
The specific gravity of any material is defined as the ratio of the density of the material to the density of water.
Mathematically, the formula for specific gravity of materials =
= S.G = density of the material / density of water
Specific gravity of the iceberg = 0.917
Specific gravity of the seawater = 1.025
The fraction of the iceberg submerged in the seawater =
= 0.917 = 0.917 x 100 %
= 91.7 %
The fraction of the iceberg that is above the surface of the water =
= 1 - 0.917
= 0.083
= 0.083 x 100 %
= 8.3 %
Thus, the fraction of the iceberg submerged in the water is a function of the specific gravity of the iceberg.
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28. Ratman's rat mobile is traveling at 80m/s North when it turns on its rocket boosters
accelerating the rat mobile to 200 m/s in 4 seconds.
What's the rat mobiles acceleration?
Answers
The acceleration of rate mobile is 30 m/s².
Given - Initial velocity=80m/s , Final Velocity=200m/s , time= 4sec
To find out acceleration.
Principle- Acceleration means rate of change of velocity. Mathematically derivative of velocity with the function of time is acceleration.
a=dv/dt
a=(vₙ-v )/dt
substitute vₙ=200m/s , v=80m/s , dt=4sec
a= [ 200 -80 ]/4
a= 120/4
acceleration ⇒ a=30 m/s²
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The method of measuring distance in space using parallax is equivalent to surveyors on Earth doing _______________. The smaller the parallax of an object, the greater its __________. When we measure parallax, the distance between the two observers (or two vantage points) is called the ___________. The first parallax to a star was not measured until 1838 because the stars are so _______________. The distance at which a star has a parallax of one second of arc is called a __________. In 1989, astronomers launched a satellite called __________ to measure parallax even better from outer space.
Answers
Answer:
Triangulation
Distance
Baseline
Far away
Parsec
Hipparcos
Astronomers are known to estimate the distance of nearby objects in space through the use of stellar parallax, or trigonometric parallax.
They often measure a star's movement using the background of more distant stars as Earth revolves around the sun.
With the use of Parallax, one can get the best way to have the distance in astronomy,
Triangulation is often used instead of parallax to know the terrestrial distances by forming triangles with a predefined base and measuring the angles formed with the other two sides.
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If an object moves 21m north 16m east and 26m south what is the displacement of the object?
Answers
Explanation:
the net displacement of an object is
X-coordinate is
16.
Y-coordinate is
21-26=-5.
The magnitude of displacement is
d=√(〖16〗^2+(-5)^2 )=17 blocks.
The direction is
θ=tan^(-1)〖5/16〗=17° east of south.
therefore, I think it helps you.
__________ is the process of altering light so that the waves are all oscillating in the same plane.
Polarization
Reflection
Diffraction
Refraction
Answers
Polarized sunglasses block the waves in one direction and pass the other plane. Allows us to see objects below the surface of reflected lite coming off water.
What distance would an object need to be located in front of a converging lens for
the image to be the same size as the object?
Closer than F
Between F and 2F
Beyond 2F
At 2F
Answers
Answer:
2*F
Explanation:
If we put an object of a given size exactly at a distance 2*F from the lens, the virtual image (the image generated by the lens) will be generated at a distance 2*F from the lens and the size will be equal to the size of the real object (but the image will be inverted)
Now let's do the math.
The relation between the distance of the object to the lens O, and the distance between the image and the lens I is:
1/O + 1/I = 1/F
solving for O, we get:
1/O = 1/F - 1/I = (I - F)/(F*I)
O = F*I/(I - F)
Such that the relation between the height of the original object, H and the height of the virtual image H' is:
H/H' = -I/O
Replacing by O we get:
H/H' = -I/(F*I/(I - F))
If the sizes are equal, then H/H' = - 1 (remember that the image is inverted, thus the sign)
-1 = -I/(F*I/(I - F))
F*I/(I - F) = I
F*I = (I - F)*I
F = (I - F)
F + F = I = 2*F
The distance between the image and the lens is 2*F
O = F*I/(I - F) = F*2*F/(2*F - F) = 2*F
The object is at a distance 2*F from the lens.
Why is gravitational attraction less on the moon than it is on Earth?
Answers
Answer:
Explanation:
The Earth's Moon has considerably less mass than the Earth itself. Not only is the Moon smaller than the Earth, but it is only about 60 percent as dense as Earth. Thus, the gravitational attraction on the Moon is much less than it is here on Earth, and a person weighs less on the Moon.
calculate the work done by a girl of mass 40 kg when she climbs a stair case of 20 steps each of height 10 cm and acceleration is 10Nkg^-1
Answers
Answer:
i think its a 800x² hope you like it
Answer:
8964
Explanation:
465
A charge of 8.4 × 10–4 C moves at an angle of 35° to a magnetic field that has a field strength of 6.7 × 10–3 T.
If the magnetic force is 3.5 × 10–2 N, how fast is the charge moving?
9.1 × 10–5 m/s
1.3 × 10–4 m/s
7.6 × 103 m/s
1.1 × 104 m/s
Answers
Answer:
the correct answer is D
Explanation:
A 10-kg rock and a 20-kg rock are dropped at the same time and experience no significant air resistance. If the 10-kg rock falls with acceleration a, what is the acceleration of the 20-kg rock?.
Answers
When a 10-kg rock and a 20-kg rock are dropped at the same time and experience no significant air resistance the acceleration of both rocks is: the same and equal to the gravity
When an object is dropped (in the absence of air resistance) it has a positive acceleration equal to the gravity.
Therefore, no matter in which instant of the movement both rocks are, their acceleration will always be equal to the acceleration of gravity 32.17 ft/s², and after finishing their movements the acceleration will be equal to zero (0) because they will reach the ground and will be at rest.
What is gravity?In physics, gravity is the force of attraction that the earth exerts on all bodies possessing mass by pulling them toward its center.
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most searches of space for evidence of intelligent life concentrate on radio wavelengths because
a. Radio waves can travel long distances without much interference.
b. Radio waves are the most common form of communication.
c. Radio waves are easy to detect and decode.
d. Radio waves carry the most information.
Answers
Most searches of space for evidence of intelligent life concentrate on radio wavelengths because: a. Radio waves can travel long distances without much interference.
Radio waves have the advantage of being able to propagate through space over vast distances with relatively low levels of interference. Unlike other forms of electromagnetic radiation, such as visible light or X-rays, radio waves are not easily absorbed or scattered by cosmic dust, gas, or other intervening objects. This allows radio signals to traverse interstellar distances more effectively, increasing the chances of detecting potential signals from extraterrestrial civilizations.
While it is true that radio waves are commonly used for communication on Earth (option b), this fact alone does not explain why they are preferred for searching for intelligent life in space. Additionally, radio waves are not necessarily the easiest to detect and decode (option c), as that depends on the specific technology and methods employed. Moreover, the statement that radio waves carry the most information (option d) is not necessarily accurate, as information content depends on the complexity and encoding used in a communication system.
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Scientists have invented the equipment to harness the power of lighting for energy use. True or false
Answers
Let me know if it’s incorrect .
An emerging type of mobile phone is the cellular/satellite ____ phone that can be used with cellularservice when it is available and then switches to satellite service when cellular service is not available.a.dual-modec.duplexb.dual-cored.digital
Answers
An emerging type of mobile phone is the cellular/satellite dual-mode phone that can be used with cellular service when it is available and then switches to satellite service when cellular service is not available.
What is Dual-mode?
Mobile devices that use two separate carrier technologies are referred to as dual mode.
Example of an emerging mobile phone is: 5G mobile phones.
Hence, an emerging type of mobile phone is the cellular/satellite dual-mode phone that can be used with cellular service when it is available and then switches to satellite service when cellular service is not available.
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An emerging type of mobile phone is the cellular/satellite dual-mode phone that can be used with cellular service when it is available and then switches to satellite service when cellular service is not available.
What is Dual-mode?
Mobile devices that use two separate carrier technologies are referred to as dual mode.
Example of an emerging mobile phone is: 5G mobile phones.
Hence, an emerging type of mobile phone is the cellular/satellite dual-mode phone that can be used with cellular service when it is available and then switches to satellite service when cellular service is not available.
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In which city would Earth’s gravitational field strength be the smallest?
Answers
Mount Nevado, Huascarán in Peru has the lowest gravitational acceleration, at 9.7639 m/s2.
What is gravitational acceleration ?
An object in free fall in a vacuum experiences gravitational acceleration. This is the gradual increase in speed brought on solely by the gravitational pull. No matter their masses or compositions, all bodies accelerate at the same rate in a vacuum; the measurement and analysis of these rates is known as gravimetry.
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which is the peak wavelength of a blackbody curve for the brightest main sequence star? which is the peak wavelength of a blackbody curve for the brightest main sequence star? 644 nm you cannot tell, wavelength and brightness are not related 386 nm 483 nm
Answers
The peak wavelength of a blackbody curve for the brightest main sequence star would be 966 nm.
What is Blackbody radiation?
The peak wavelength of a blackbody curve is determined by the temperature of the object emitting the radiation, according to Wien's law. Therefore, the peak wavelength of a blackbody curve for the brightest main sequence star will depend on the temperature of that star.
The temperature of the brightest main sequence star varies depending on the star, but it is generally around 30,000 Kelvin. Using Wien's law (λ_max = b / T), where b is Wien's displacement constant, we can calculate the peak wavelength of a blackbody curve for a star at this temperature.
Substituting b = 2.898 × 10-³ m·K and T = 30,000 K, we get:
λ_max = 2.898 × 10-³ m·K / 30,000 K
λ_max ≈ 9.66 × 10-⁸ m
Converting this wavelength to nanometers, we get:
λ_max ≈ 966 nm
Therefore, the peak wavelength of a blackbody curve for the brightest main sequence star would be approximately 966 nm. None of the options provided match this result, so the correct answer is not given.
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How do scientists use patterns?
A. To organize results
B. To describe how something is made
C. To predict what might happen next
D. To send messages to other scientists
Answers
Answer:
c because you see with your eyes and c rhymes with eyes
What are three properties of electromagnetic waves?
Answers
Answer:Elas são ondas tridimensionais e transversais que viajam na velocidade da luz, transportando exclusivamente energia. Ademais, apresentam-se na forma de ondas de rádio, micro-ondas, infravermelho, luz visível, ultravioleta, raios x e raios gama, em ordem crescente de frequência e energia.
Explanation:
The following table shows the frequency of causes of defects on a printed-circuit-board. Defect Frequency Excess adhesive 190 Misplaced transistors 76 Defective board dimensions 211 Wrong component 107 Improperly positioned mounting holes 72 Components not adhering 166
Find the probability of each of the defects.
Round your answer to 4 decimal places.
Answers
To find the probability of each defect, we divide the frequency of each defect by the total frequency of all defects.
Excess adhesive: Probability = 190 / (190 + 76 + 211 + 107 + 72 + 166) = 190 / 822 = 0.2311 (approximately 23.11%)Misplaced transistors: Probability = 76 / (190 + 76 + 211 + 107 + 72 + 166) = 76 / 822 = 0.0924 (approximately 9.24%)Defective board dimensions: Probability = 211 / (190 + 76 + 211 + 107 + 72 + 166) = 211 / 822 = 0.2566 (approximately 25.66%)Wrong component: Probability = 107 / (190 + 76 + 211 + 107 + 72 + 166) = 107 / 822 = 0.1301 (approximately 13.01%)Improperly positioned mounting holes: Probability = 72 / (190 + 76 + 211 + 107 + 72 + 166) = 72 / 822 = 0.0876 (approximately 8.76%)Components not adhering: Probability = 166 / (190 + 76 + 211 + 107 + 72 + 166) = 166 / 822 = 0.2010 (approximately 20.10%)The probability of each defect is found by dividing the frequency of that particular defect by the total frequency of all defects. The total frequency of all defects is calculated by summing up the frequencies of all the defects. Then, the frequency of each defect is divided by the total frequency to obtain the probability.
For example, to find the probability of Excess adhesive, we divide its frequency (190) by the total frequency of all defects (822). Similarly, we calculate the probability for each defect by dividing its frequency by the total frequency.
These probabilities represent the relative likelihood of each defect occurring out of the total defects observed on the printed circuit board.
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How to integrate 1/ 1 + x2
Answers
The integral of 1/(1 + x²) is (1/2)ln|1 + x²| + C where C is the constant of integration.
Integration is a mathematical process of finding the antiderivative of a function. To integrate the given expression 1/(1 + x²), we will use the substitution method.
Let u = 1 + x², du/dx = 2x dx, then dx = du/2x and the integral becomes:
∫1/(1 + x²) dx = ∫1/u * (1/2x) du= (1/2)∫1/u du
The antiderivative of 1/u is ln|u| + C, where C is the constant of integration.
Therefore, the final solution of the integral is (1/2)ln|1 + x²| + C.
Let us work through the steps:
Step 1:Let u = 1 + x² and then differentiate both sides with respect to x to obtain du/dx. du/dx = 2x
Substitute 2x dx = du into the integral ∫1/(1 + x²) dx to get the integral in terms of u:∫1/u * (1/2x) du = (1/2) ∫1/u du
Step 2:Calculate the antiderivative of 1/u, which is ln|u|. Thus, the final solution is (1/2)ln|1 + x²| + C, where C is the constant of integration. The constant C will vary depending on the initial conditions of the problem.
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Select the correct answer from each drop-down menu. How can you summarize the ruler placement postulate? you can measure the between points a and b by using as zero.
Answers
The ruler placement hypothesis can be summed up as follows:
The set of points on the line and the set of real numbers are equivalent in every way, and the absolute value of the difference between the matching numbers is equal to the distance between two points.
According to this, a set of points on a line can be matched with a set of real numbers, and vice versa. In order to help you better understand the ruler placement postulate, a general overview is provided based on the fact that your question is incomplete.
A ruler is a tool or measuring device that is used to measure length and draw straight lines. A measure is used to determine the length in both measured and conventional units.
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true or flase form is an element of design that describes volume and mass ; the three dimensional aspects of objects that take up space.
Answers
form is an element of design that describes volume and mass ; the three dimensional aspects of objects that take up space is True.
Form is an element of design that refers to the three-dimensional aspects of objects, including volume and mass. It describes the physical shape and structure of an object, emphasizing its spatial presence and how it occupies and interacts with space. Form plays a crucial role in creating visual interest, defining the character of objects, and shaping the overall composition in various design disciplines, such as architecture, industrial design, and sculpture.
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Convert 13.6g/cm3 into kg/m3
Answers
Answer:
0.000136kg/m3
Explanation:
13.6 / 1000 = 0.0136kg/cm3
0.0136 / 100 = 0.000136kg/m3