You are an environmental engineer for Asinamali Ventures (Pty) Ltd, and
you are to design a particulate control device. The underlying principles in
designing these devices is grounded on separating particles from the
airstream. Articulate the three common mechanism that are used to
separate particulate matter from the airstream.

Answers

Answer 1

The three common mechanisms used to separate particulate matter from the airstream are filtration, cyclonic separation, and electrostatic precipitation.

Filtration is a widely employed mechanism for separating particulate matter from the airstream. In this process, the contaminated air passes through a filter medium that captures and retains the particles while allowing the clean air to pass through. The filter medium can be made of various materials, such as fabric, paper, or porous ceramics, which have the ability to trap particles based on their size and physical properties. Filtration is effective in removing both large and small particulate matter, making it a versatile and commonly used method in particulate control devices.

Cyclonic separation is another mechanism commonly used for particle separation. It utilizes the principle of centrifugal force to separate particles from the airstream. The contaminated air enters a cyclone chamber, where it is forced to rotate rapidly.

Due to the centrifugal force generated by the rotation, the heavier particles move towards the outer walls of the chamber and eventually settle into a collection hopper, while the clean air is directed towards the center and exits through an outlet. Cyclonic separation is particularly effective in removing larger and denser particles from the airstream.

Electrostatic precipitation, also known as electrostatic precipitators (ESPs), is a mechanism that relies on the electrostatic attraction between charged particles and collector plates to separate particulate matter. In this process, the contaminated air is passed through an ionization chamber where particles receive an electric charge.

The charged particles then migrate towards oppositely charged collection plates or electrodes, where they adhere and accumulate. The clean air is discharged from the precipitator. Electrostatic precipitation is highly efficient in removing both fine and coarse particles and is commonly used in industries where fine particulate matter is a concern, such as power plants and cement kilns.

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Related Questions

What are the two tools used to create an HTML code? Name one example of each tool.

Answers

Answer:

please mark me as BRAINLIEST

Explanation:

There are so many software packages available to develop HTML. The software packages can be grouped into two main categories: text-based (or code-based) editors.

...

WYSIWYG editors

Macromedia Dreamweaver.

Microsoft FrontPage.

Adobe GoLive.

If the number of turns in the coil is increased, the induced electromotive force in the coil will A. Increase B. Decrease C. Remains same D. None of the above

Answers

If the number of turns in the coil is increased, the induced electromotive force in the coil will A. Increase.

According to Faraday's law of electromagnetic induction, the magnitude of the induced electromotive force (EMF) in a coil is directly proportional to the rate of change of magnetic flux passing through the coil. The magnetic flux is influenced by factors such as the strength of the magnetic field and the number of turns in the coil.

When the number of turns in the coil is increased, more individual loops are present, resulting in a larger surface area for magnetic flux to pass through. As a result, a greater amount of magnetic flux is linked with the coil, leading to a higher rate of change of flux and an increased induced EMF.

Therefore, increasing the number of turns in the coil enhances the effectiveness of electromagnetic induction, resulting in a greater induced electromotive force.

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Consider pressurized water, engine oil (unused), and NaK (22%/78%) flowing in a 20-mm-diameter tube.

(a) Determine the mean velocity, the hydrodynamic entry length, and the thermal entry length for each of the fluids when the fluid temperature is 366 K and the flow rate is 0. 01 kg/s.

(b) Determine the mass flow rate, the hydrodynamic entry length, and the thermal entry length for water and engine oil at 300 and 400 K and a mean velocity of 0. 02 m/s

Answers

Answer:

To solve this problem, we need to use the Reynolds number, the Prandtl number, and the Darcy friction factor. The Reynolds number is a dimensionless number that describes the flow regime of the fluid, the Prandtl number characterizes the ratio of momentum diffusivity to thermal diffusivity, and the Darcy friction factor describes the frictional losses in the pipe.

(a)

For pressurized water at 366 K and a flow rate of 0.01 kg/s, we can calculate the mean velocity as follows:

v = m_dot / (rho * A), where

m_dot = 0.01 kg/s (mass flow rate)

rho = 997 kg/m^3 (density of water at 366 K)

A = pi * (0.02 m)^2 / 4 = 0.000314 m^2 (cross-sectional area of the tube)

v = 0.01 / (997 * 0.000314) = 3.18 m/s

The Reynolds number for water is:

Re = (rho * v * D) / mu, where

D = 0.02 m (diameter of the tube)

mu = 0.000283 Pa s (dynamic viscosity of water at 366 K)

Re = (997 * 3.18 * 0.02) / 0.000283 = 2.24e5

Using the Reynolds number, we can estimate the hydrodynamic entry length using the following equation:

L_hyd = 0.05 * Re * D

L_hyd = 0.05 * 2.24e5 * 0.02 = 224 m

For the thermal entry length, we use the following equation:

L_th = 0.05 * Re * Pr * D / Nu

where Pr is the Prandtl number and Nu is the Nusselt number. For water at 366 K, Pr = 5.5 and we can estimate Nu using the Dittus-Boelter correlation:

Nu = 0.023 * Re^(4/5) * Pr^(0.4)

Nu = 0.023 * (2.24e5)^(4/5) * 5.5^(0.4) = 244

L_th = 0.05 * 2.24e5 * 5.5 * 0.02 / 244 = 3.6 m

For engine oil (unused) at 366 K and a flow rate of 0.01 kg/s, we can calculate the mean velocity as follows:

v = m_dot / (rho * A), where

m_dot = 0.01 kg/s (mass flow rate)

rho = 890 kg/m^3 (density of engine oil at 366 K)

A = pi * (0.02 m)^2 / 4 = 0.000314 m^2 (cross-sectional area of the tube)

v = 0.01 / (890 * 0.000314) = 3.79 m/s

The Reynolds number for engine oil is:

Re = (rho * v * D) / mu, where

D = 0.02 m (diameter of the tube)

mu = 0.0003 Pa s (dynamic viscosity of engine oil at 366 K)

Re = (890 * 3.79 * 0.02) / 0.0003 = 4.72e5

Using the Reynolds number, we can estimate the hydrodynamic entry length using the following equation:

L_hyd = 0.05 * Re * D

L_hyd = 0.05 * 4.72e5 * 0.02 = 472 m

For the thermal entry length, we use the following equation:

L_th = 0.05 * Re * Pr * D / Nu

where Pr is the Prandtl number and Nu is the Nusselt number. For engine oil at 366 K, Pr = 130 and we can estimate Nu using the Dittus-Boelter correlation:

Nu = 0.023 * Re^(4/5) * Pr^(0.4)

Nu = 0.023 * (4.72e5)^(4/5) * 130^(0.4) = 2600

L_th = 0.05 * 4.72e5 * 130 * 0.02 / 2600 = 7.2 m

For NaK (22%/78%) at 366 K and a flow rate of 0.01 kg/s, we can calculate the mean velocity as follows:

v = m_dot / (rho * A), where

m_dot = 0.01 kg/s (mass flow rate)

rho = 1100 kg/m^3 (density of NaK at 366 K)

A = pi * (0.02 m)^2 / 4 = 0.000314 m^2 (cross-sectional area of the tube)

v = 0.01 / (1100 * 0.000314) = 2.87 m/s

The Reynolds number for NaK is:

Re = (rho * v * D) / mu, where

D = 0.02 m (diameter of the tube)

mu = 0.0018 Pa s (dynamic viscosity of NaK at 366 K)

Re = (1100 * 2.87 * 0.02) / 0.0018 = 3.48e5

Using the Reynolds number, we can estimate the hydrodynamic entry length using the following equation:

L_hyd = 0.05 * Re * D

L_hyd = 0.05 * 3.48e5 * 0.02 = 348 m

For the thermal entry length, we use the following equation:

L_th = 0.05 * Re * Pr * D / Nu

where Pr is the Prandtl number and Nu is the Nusselt number. For NaK at 366 K, Pr = 0.013 and we can estimate Nu using the Sieder-Tate correlation:

Nu = 0.027 * Re^(4/5) * Pr^(0.43)

Nu = 0.027 * (3.48e5)^(4/5) * 0.013^(0.43) = 67.3

L_th = 0.05 * 3.48e5 * 0.013 * 0.02 / 67.3 = 0.008 m

(b)

For water and engine oil, the mass flow rate is given as 0.01 kg/s, and the mean velocity is given as 0.02 m/s.

For water at 300 K:

rho = 996.6 kg/m^3 (density of water at 300 K)

mu = 0.000547 Pa s (dynamic viscosity of water at 300 K)

Pr = 7.02 (Prandtl number of water at 300 K)

Nu = 0.023 * Re^(4/5) * Pr^(0.4)

Re = (rho * v * D) / mu = (996.6 * 0.02 * 0.02) / 0.000547 = 1445

Nu = 0.023 * Re^(4/5) * Pr^(0.4) = 0.023 * (1445)^(4/5) * 7.02^(0.4) = 426.5

L_hyd = 0.05 * Re * D = 0.05 * 1445 * 0.02 = 14.45 m

L_th = 0.05 * Re * Pr * D / Nu = 0.05 * 1445 * 7.02 * 0.02 / 426.5 = 0.021 m

For water at 400 K:

rho = 958.4 kg/m^3 (density of water at 400 K)

mu = 0.000294 Pa s (dynamic viscosity of water at 400 K)

Pr = 4.41 (Prandtl number of water at 400 K)

Nu = 0.023 * Re^(4/5) * Pr^(0.4)

Explanation:

Using Raoult’s law, estimate the boiling temperature and mole fractions in the vapor phase that is in equilibrium with a liquid having 0.2608 mol fraction of ethanol, in a mixture ethanol/water at P = 1 atm.
If possible, solve non-numerically.

Answers

Answer:

\(T=92.16 \°C\)

\(y_{et}=0.433\\\\y_w=0.567\)

Explanation:

Hello,

In this case, the Raoult's law for this problem is:

\(y_{et}P=x_{et}P_{et}^{sat}\\\\y_{w}P=x_{w}P_{w}^{sat}\)

Which can be written as:

\(P=x_{et}P_{et}^{sat}+x_{w}P_{w}^{sat}\)

Thus, by using the Antoine equation, we can symbolically represent the the temperature at which such mixture boil:

\(1atm=0.2608*10^{(8.13484-\frac{ 1662.48}{238.131+T})}/760+0.7392*10^{(5.40221-\frac{1838.675}{-31.737+T-273.15})}/1.01325\)

The solution, by numerical iteration process (there is not way to solve it analytically) is 92.16 °C considering the data extracted from NIST database. Next, vapor fractions are:

\(y_{et}=x_{et}*10^{(8.13484-\frac{ 1662.48}{238.131+T})}/760/P\\\\y_{et}=0.2608*10^{(8.13484-\frac{ 1662.48}{238.131+92.16})}/760/1atm\\\\y_{et}=0.433\\\\y_w=1-y_{et}=1-0.433\\\\y_w=0.567\)

Regards.

1.4 A body with a mass of 2.5 tons moves on a horizontal surface. To maintain constant velocity, a force of 10 kN is used to drive the body. What is the coefficient of friction between the body and the horizontal surface?​

Answers

Answer:

  μ ≈ 0.408

Explanation:

The coefficient of friction is the ratio of friction force to normal force. The normal force is ...

  F = mg = (2500 kg)(9.8 m/s²) = 24.5 kN

Then the coefficient of friction (μ) is ...

  μ = (10 kN)/(24.5 kN) ≈ 0.408

car people i need some advice
what should be my first super car

car people i need some advice what should be my first super car
car people i need some advice what should be my first super car
car people i need some advice what should be my first super car

Answers

Answer:

The first one.

Explanation:

The first one without a doubt

this is perfect.........

A horizontal curve of a two-lane undivided highway (12-foot lanes) has a radius of 678 feet to the center line of the roadway. An old building (sight obstruction) is located 30 feet from the edge of the innermost lane. The road is level and the superelevation is 0.06. Please determine the maximum speed for safe vehicle operation on this horizontal curve.

Answers

Answer:

maximum speed for safe vehicle operation = 55mph

Explanation:

Given data :

radius ( R ) = 678 ft

old building located ( m )= 30 ft

super elevation = 0.06

Determine the maximum speed for safe vehicle operation

firstly calculate the stopping sight distance

m = R ( 1 - cos \(\frac{28.655*S}{R}\) )  ----  ( 1 )

R = 678  

m ( horizontal sightline ) = 30 ft

back to equation 1

30 = 678 ( 1 - cos (28.655 *s / 678 ) )

( 1 - cos (28.655 *s / 678 ) )  = 30 / 678 = 0.044

cos \(\frac{28.65 *s }{678}\)  = 1.044

hence ; 28.65 * s = 678 * 0.2956

s = 6.99 ≈ 7 ft

next we will calculate the design speed ( u ) using the formula below

S = 1.47 ut  + \(\frac{u^2}{30(\frac{a}{3.2} )-G1}\)  ----  ( 2 )

t = reaction time,  a = vehicle acceleration, G1 = grade percentage

assuming ; t = 2.5 sec , a = 11.2 ft/sec^2, G1 = 0

back to equation 2

6.99 = 1.47 * u * 2.5 + \(\frac{u^2}{30[(11.2/32.2)-0 ]}\)

3.675 u  + 0.0958 u^2 - 6.99 = 0

u ( 3.675 + 0.0958 u ) = 6.99

if, during inspection at engine overhaul, ball or roller bearings are found to have magnetism but otherwise have no defects, they

Answers

If ball or roller bearings are found to have magnetism during inspection at engine overhaul but otherwise have no defects, it could indicate the presence of residual magnetism.

This phenomenon occurs due to previous exposure to magnetic fields and is generally not a cause for concern. However, it is important to evaluate the level of magnetism and its potential impact on the bearing's performance before deciding whether replacement or further action is necessary. When ball or roller bearings are inspected during engine overhaul and exhibit magnetism without any other apparent defects, it suggests the presence of residual magnetism. Residual magnetism can occur in bearings that have been exposed to strong magnetic fields in the past, such as during the manufacturing or assembly process. This magnetism is typically caused by the alignment of the magnetic domains within the bearing material. In most cases, residual magnetism is not a significant concern and does not pose a threat to the bearing's functionality. However, it is crucial to assess the level of magnetism and its potential implications. Excessive magnetism can potentially interfere with the bearing's proper operation, leading to increased friction, heat generation, and premature wear. It can also attract ferromagnetic particles, such as debris or contaminants, which may cause further damage. To determine the impact of magnetism on the bearing's performance, specialized measurements and tests can be conducted. These evaluations involve gauging the strength of the magnetism and assessing its effect on critical parameters like clearance, lubrication, and rotation smoothness. If the magnetism levels are within acceptable limits and the bearing operates smoothly without any abnormal heat generation, it may not be necessary to replace the bearing. However, if the magnetism is deemed excessive or if there are concerns about potential performance issues, replacing the bearing might be recommended. The decision should be based on thorough analysis, considering factors such as the bearing's intended application, operational requirements, and manufacturer's guidelines. Additionally, it is essential to take preventive measures to minimize the risk of residual magnetism in new bearings, such as proper handling and storage procedures to avoid exposure to magnetic fields. In summary, if ball or roller bearings display magnetism during engine overhaul inspection but have no other visible defects, it indicates the presence of residual magnetism. While this phenomenon is generally not problematic, it is crucial to evaluate the level of magnetism and its potential impact on the bearing's performance. Conducting specialized measurements and tests can help determine whether replacement or further action is necessary. Ensuring proper handling and storage practices can help prevent the occurrence of residual magnetism in new bearings.

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Do not ________________ a tool. *
-clean up
-force
-stop
-unplug

Answers

Answer:Unplug or force?
Hdsubsjsbxudnsorryyyy

A triangular plate with a base 5 ft and altitude 3 ft is submerged vertically in water. If the base is in the surface of water, find the force against onr side of the plate. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Recall that the weight density of water is 62.5 lb/ft3.)

Answers

Answer:

Hydrostatic force = 41168 N

Explanation:

Complete question

A triangular plate with a base 5 ft and altitude 3 ft is submerged vertically in water  so that the top is 4 ft below the surface. If the base is in the surface of water, find the force against onr side of the plate. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Recall that the weight density of water is 62.5 lb/ft3.)

Let "x" be the side length submerged in water.

Then

w(x)/base = (4+3-x)/altitude

w(x)/5 = (4+3-x)/3

w(x) = 5* (7-x)/3

Hydrostatic force = 62.5 integration of  x * 4 * (10-x)/3 with limits from 4 to 7

HF = integration of 40x - 4x^2/3

HF = 20x^2 - 4x^3/9 with limit 4 to 7

HF = (20*7^2 - 4*7^(3/9))- (20*4^2 - 4*4^(3/9))

HF = 658.69 N *62.5 = 41168 N

EXAMPLE 15-7 First-Law Analysis of Combustion in a Bomb The constant-volume tank shown in Fig. 15-24 contains 1 lbmol of methane (CH₂) gas and 3 Ibmol of O₂ at 77°F and 1 atm. The contents of the tank are ignited, and the methane gas burns completely. If the final temperature is 1800 R, determine (a) the final pressure in the tank and (b) the heat transfer during this process. ​

Answers

Answer:

Try This Out!

Explanation:

To solve this problem, you need to use the first law of thermodynamics to analyze the combustion process that occurs in the constant-volume tank.

First, you need to determine the initial and final states of the system. The initial state is given as 1 lbmol of methane (CH₂) gas and 3 Ibmol of O₂ at 77°F and 1 atm. The final state is given as the same mixture of gases at 1800 R.

Next, you need to determine the heat transfer during the process. To do this, you can use the first law of thermodynamics in the form of the heat equation:

Q = ΔU + W

where Q is the heat transfer, ΔU is the change in internal energy, and W is the work done by the system.

Since the process occurs at constant volume, the work done by the system is zero. Therefore, the heat transfer can be calculated as:

Q = ΔU

You can then use the change in internal energy to determine the final pressure in the tank. The change in internal energy can be calculated using the internal energy of the reactants and products, which can be found from tables of thermochemical data or by using equations of state.

Once you have determined the heat transfer and the change in internal energy, you can use these values to calculate the final pressure in the tank using the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature.

You can then use the values of the final temperature and the number of moles of gas in the tank to calculate the final pressure.

I hope this helps! Let me know if you have any questions.

During the Sprint Planning that is moving ahead, the Scrum Team has become aware they won't be able to finish the work for all selected Sprint Backlog items. Which two of the following are usually the best actions?

Answers

When working on a project using the Scrum framework, it is important to plan ahead and select Sprint Backlog items that can be completed within the designated Sprint. However, sometimes unexpected issues can arise, and the Scrum Team may realize they won't be able to finish all of the selected items.

In such a situation, there are two actions that are usually considered the best course of action. The first action is to reassess the Sprint Backlog and reprioritize the remaining work. This means that the Scrum Team will review the backlog items and determine which items are the most important to complete within the Sprint, and focus their efforts on those items. The remaining items will be moved to the Product Backlog for consideration in future Sprints. The second action is for the Scrum Team to collaborate with the Product Owner and stakeholders to review the Sprint Goal and determine if it is still achievable given the change in circumstances. If the Sprint Goal is still achievable, then the Scrum Team can proceed with the reprioritization of the remaining work. However, if the Sprint Goal is no longer achievable, then the Scrum Team may need to cancel the Sprint and start a new Sprint Planning. In conclusion, when the Scrum Team becomes aware they won't be able to finish the work for all selected Sprint Backlog items, the best actions are to reassess the backlog and reprioritize the remaining work or collaborate with the Product Owner and stakeholders to review the Sprint Goal and determine if it is still achievable. By taking these actions, the Scrum Team can continue to work towards delivering a valuable product within the designated Sprint timeframe.

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I'm having trouble with picking the correct equations for this. Some ways equal 12.4 N-m, but that's wrong. 24.8 N-m is also wrong. I have 62sin60 and 62cos60, and the perpendicular should be 200mm.

I'm having trouble with picking the correct equations for this. Some ways equal 12.4 N-m, but that's

Answers

The couple of the moment of the two forces is 3.82 N.m

What is the Moment of the Couple?

We are given;

Force applied at A; F_a = 62 N

Force applied at C; F_c = 62 N

AB = BC = 200 mm = 0.2 m

Horizontal component of  F_a is; F_ax = 62 cos 50

Vertical component of  F_a is; F_ay = 62 sin 50

Horizontal component of  F_c is; F_cx = 62 cos 50

Vertical component of  F_c is; F_cy = 62 sin 50

Taking moments about point C gives;

M_c = F_ay * AB - F_ax * BC

M_c = (62 sin 50 * 0.2) - (62 cos 50 * 0.2)

M_c = 23.75 - 19.93

M_c = 3.82 N.m

Thus, the couple of the moment of the two forces is 3.82 N.m

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This colonial home is 40° I x 25' w plus a detached garage of 22 w x 20 I. How many SQ
FT of living space is there?

Answers

The total square feet of living space is 1400 square feet.

What is total square?

Total square is a mathematical concept that refers to the area of a two-dimensional shape such as a rectangle, square, triangle, or circle. Calculating the total square involves multiplying the length and width of the shape to determine the total area. In the case of a triangle, the height and base must be multiplied to calculate the total square. The total square of a circle is calculated by multiplying the radius of the circle by itself and then multiplying the result by pi. Total square is an important concept in mathematics, engineering, and architecture as it is used to calculate the amount of material needed to create a structure or object.

The main house is 40° x 25' = 1000 square feet.
The detached garage is 22' x 20' = 440 square feet.
Therefore, the total square feet of living space is 1400 square feet.

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why is tubing sometimes coiled when installed in a car or vechile

Answers

Answer:

Coiled tubing is often used to carry out operations similar to wire lining.

A stranded steel cable with known cross section and modulus of elasticity supports a 5-ton elevator. As the elevator is descending at a constant velocity, an accident causes the top of the cable, 70 ft above the elevator, to suddenly stop.

Required:
Estimate the maximum elongation and maximumtensile stress developed in the cable.

Answers

Answer:

I don't know sorry thanks for asking

Harlin is designing a new car engine that does not create pollution. Which technological design factor is probably the most
important for his design?
OA.
appearance
ОВ.
how easy it is to drive
OC.
environmental impact
OD.
cost

Answers

Answer: environmental impact

Explanation:

From the question, we are informed that Harlin is designing a new car engine that does not create pollution.

The technological design factor which is probably the most important for the design is the impact on the environment.

Pollution has a negative effect on the environment a d doing this shows that emphasis is placed on how the environmental issue of pollution can be tackled.

Kwan owns his own business installing, sanding, and finishing beautiful hardwood floors. Kwan works in the _____ pathway of the architecture and construction career cluster.

Answers

Kwan owns his own business installing, sanding, and finishing beautiful hardwood floors. Kwan works in the construction pathway of the architecture and construction career cluster. The correct option is B.

What is construction business?

Construction Business refers to any trade that installs, modifies, or repairs any commercial building element, component, material, or device.

Construction works include the construction, demolition, repair, or renovation of buildings, roads, bridges, or other structures, as well as the fabrication of steel structures and all other civil works.

Kwan runs his own company that installs, sands, and finishes beautiful hardwood floors. Kwan works in the architecture and construction career cluster's construction pathway.

Thus, the correct option is B.

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Your question seems incomplete, the missing options are:

A. Design/Pre-Construction

B. Construction

C. Maintenance/Operations

D. Production

Answer:

Construction

Explanation:

I took the test

What is avg, the phase difference between the two original phasors for which the amplitude of the combined phasors is equal to Asum,avg? Give your answer for avg as an angle between 0o and 180o.

Answers

The amplitude of the combined phasors is equal to 0° (0 degrees). This value is used in electricity.

What is a phasor?

A phasor is a complex number that describes the amplitude of a particular sinusoidal voltage and current.

In a phasor, the angular frequency, amplitude, and initial phase can be considered as time-invariant.

The angular frequency can be defined as the scalar measure of the rotation rate.

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1. Which of these best describes a programming language?
a. A set of rules where symbols represent actions.
b. A set of spoken commands for a robot.
c. An action performed by a robot.
d.
A list of behaviors the robot already completed.

Answers

The phrase "system of rules where symbols represent actions" sums up programming languages the best.

What best describes a programming language?

Symbols that represent actions are used in a computer language's set of rules. Programming languages are the set of instructions that a computer uses to carry out projects. A programming language is a vocabulary and a set of grammatical rules for telling a computer or other computing equipment to carry out particular tasks.

High-level languages such as BASIC, C, C++, COBOL, Java, FORTRAN, Ada, and Pascal are typically referred to as programming languages. instruction. The principles that specify how a language is structured are known as syntax. In computer programming, syntax refers to the rules that govern how words, punctuation, and symbols are organized in a programming language. To define algorithms or write programs to control a machine's behavior, programmers utilize programming languages.

Therefore the correct answer is option A ) A set of rules where symbols represent actions.

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Which part of a machine control unit interacts with the machine tools through electric signals?=]

A machine control unit is the electronic hardware that stores information and controls the machine tools. This unit contains a data processing unit that stores and manipulates data, and a ___________ that interacts with the machine tools through electrical signals.

Answers

Answer:

control loop unit

Explanation:

Edmentum/Plato

Why must fire extinguishers be routinely maintained

Answers

Answer:

Fire extinguishers controls the amount of pollution caused by smoke and burning. Although they have no expiring date, they won't last forever. Extinguishers should work for 5 to 15 years, but fire extinguishers be routinely maintained to make sure they remain effective.

Explanation:

BRAINLEST PLZ

Answer:

Fire extinguishers control the amount of pollution caused by smoke and burning. Although they have no expiring date, they won't last forever. Extinguishers should work for 5 to 15 years, but fire extinguishers are routinely maintained to make sure they remain effective.

If A = 10 and B = 20, then A>b and A = B is (True or False). Group of answer choices True False

Answers

Answer:

........

....... False

The answer to this is false

assume you have a simple beam 16 ft long supported on each end by r1 and r2. there is a concentrated load of 900 lb that is 4 ft from r2. reaction r1 is pinned 12 ft from the load. reaction r1 is 225 lb and r2 is 675 lb. what is the maximum bending moment in pounds per foot?

Answers

The maximum bending moment that the load has in pounds would be 2700lb.

What is the maximum bending moment?

When the shear force at that portion is zero or changes sign due to the point of contra flexure, when the bending moment is zero, the maximum bending moment occurs in the beam. Reason: Because it results in convexity downhill, the positive bending moment in a section is taken into account.

The shear force would then have to change the sign when it is at the load position.

Such that we would have

R₁ * 12

where R₁ = 225

225 x 12 = 2700

We can cross check the solution by solving for the right side

= R₂ x 12

= 675 lb x 12

= 2700 lb

Hence we would say that the maximum bending moment in pounds is 2700.

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beacuse thye want them to hav egoood and thye wn thme tto

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Answer:

I don't understand the question

I don’t understand what your asking

what responsibilities did gm engineers have in regard to either causing or resolving the problems with the cadillac seville and deville models?

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General Motors Co. creates, produces, and sells vehicles, including automobiles, trucks, and auto components. Through General Motors Financial Company, Inc., .

General Motors employees are urged to create situations that appreciate viewpoints, histories, and ideas that may differ from their own. We work well together, appreciate one another, and all have the same ambition to be creative and successful. We want to be the most diverse business in the world. A worldwide pioneer in establishing and pushing the norms of ethical business practises, Ethisphere, named General Motors as one of the World's Most Ethical Companies® in 2022, making it the only original equipment manufacturer automaker to get this honour.

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of the three types of hazard controls – engineering, administrative, and personal protective equipment (ppe) – ppe is the last line of defense.

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Of the three types of hazard controls – engineering, administrative, and personal protective equipment (PPE) – PPE is the last line of defense: True.

What is OSHA?

OSHA is simply an abbreviation for occupational safety and health administration that was created under the Occupational Safety and Health Act, so as to develop work-safety standards for workers and providing precautionary measures against all workplace hazards.

The three types of hazard controls.

Generally, there are three types of hazard controls and these include the following:

Engineering Controls. Administrative Controls. Personal Protective Equipment (PPE).

What is PPE?

PPE is an acronym for personal protective equipment and it can be defined as a terminology that is used to denote any piece of equipment which offer protection to different parts of the body while working in a potentially hazardous environment.

Also, some examples of personal protective equipment (PPE) used to protect the different parts of the body are:

RespiratorsFace maskFace shieldGlovesBootsHelmet

According to occupational safety and health administration (OSHA), the use of a faulty personal protective equipment (PPE) should be the last line of defense.

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Complete Question:

Of the three types of hazard controls – engineering, administrative, and personal protective equipment (PPE) – PPE is the last line of defense. True or False?

In which model of the system, the change in order is generated depending on the system activities. *
Static Model
Dynamic Model
Analytical Model
Numerical Model

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Answer:

Static Model

Explanation:

Gerald lawson

What was the problem that this Invention solved?

Before this invention what did we use/do?

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Gerald Lawson was an American engineer and video game pioneer who is best known for inventing the first home video game console with interchangeable game cartridges.

His invention, the Fairchild Channel F, solved the problem of limited game selection and the need for separate consoles for each game.Before the Fairchild Channel F, video games were typically built into dedicated consoles or arcade machines, meaning that each device could only play a single game or a limited selection of games. Lawson's invention allowed players to switch out game cartridges and play a variety of different games on the same console. This greatly expanded the potential game library for home consoles and helped pave the way for the modern video game industry.

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An electrical contractor employs 16 people. Five people earn $15 per hour, four people earn $17 per hour, and the remaining people earn $16 per hour. What is the total hourly wage earned by all 16 people

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Answer:

$255 per hour

Explanation:

Total number of employed people = 16

(i) 5 people earn $15 per hour

That means that the total amount earned by those 5 is;

5 x $15 = $75 per hour

(ii) 4 people earn $17 per hour

That means that the total amount earned by those 4 is;

4 x $17 = $68 per hour

(iii) The remaining people earn $16 per hour.

There are 7 people remaining. i.e

16 - 5 - 4 = 7

That means that the total amount earned by those remaining (7) is;

7 x $16 = $112 per hour

The total hourly wage is therefore the sum of all the results in i, ii and iii. i.e

Total = $75 + $68 + $112

Total = $255

Therefore, the total hourly wage earned by all 16 people is $255

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