you are asked to calibrate a 25 ml volumetric pipet. you determine that the temperature of your distilled water is exactly 23.5 degrees celsius. you carefully determined the mass of a clean dry beaker and found that it was 58.9557 g. you pulled water up to the mark and transferred this to the beaker and found that the new mass was 81.4781 g. what is the actual volume of the pipet? the density of water at 23.5 degrees celsius is 0.997403 g/ml.

Answers

Answer 1

The actual volume of the pipet 1.0037 is At about 4° Celsius, the density of fresh water reaches its maximum. The mass of water you pipetted is the difference in mass. Let's use the density to convert it to volume. The amount of water will be 1.0037 at 23.5 °C.

How can you figure out how much water a pipette will deliver?

The formula for figuring out how much water was dispensed by the pipette is V = w * Z, where w is the water's weight, Z is a conversion factor based on the water's density, and V is the computed volume.

What is the purpose of a volumetric pipet?

For a certain volume, volumetric pipettes are created to be extremely accurate. They can be utilized to move that amount of liquid that can be used to dilute or create a solution.

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Related Questions

PLZ HELP! QUESTION IS BELOW! :D

PLZ HELP! QUESTION IS BELOW! :D

Answers

Personal connection is a connection with your own self to something

Answer:

Explanation:

When we say anything is a wave, what exactly do we mean? The most intuitive and straightforward wave to envision is a water wave. A motion, more specifically, is a disturbance that propagates or travels away from its source. Water waves are caused by a disruption in the water's surface, such as a rock tossed into a pond or a swimmer splashing the surface continuously. The noise for sound waves is a rise of air pressure, which may be caused by the oscillating cone within a speaker. There are many kinds of disturbances in earthquakes, including surface disturbances and pressure disturbances under the surface. Even radio signals are best deciphered by using a comparison of sea waves Water waves are helpful to visualize since they are more than just a mental picture. The amplitude, period, frequency, and energy of water waves are all the same as they are for all waves. A small set of underlying principles can be used to describe all wave characteristics.

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The volume changes from 1.25L to 1.15L at a temperature of 313K, what is the final temperature?

Answers

Answer:

Below

Explanation:

Your question states the temperature is 313 K

to convert from K to °C   subtract 273.15

  313 K - 273.15 = 39.85 °C

est Your Knowledge Question 2 Question 2 of 3 2 Identify the variables that must remain constant to maintain an equilibrium constant and equilibrium position. : Color Variables that Must Remain Constant Variables that Do Not Need to Remain Constant : Concentration : Pressure # Size # Temperature Check Answer

Answers

The variables that must remain constant to maintain an equilibrium constant and equilibrium position are concentration, temperature, and pressure.

What is equilibrium constant?

Equilibrium constant (Kc) is defined as the ratio of the products of the concentrations of the products of a chemical reaction to the products of the concentrations of the reactants, each raised to their stoichiometric coefficients.

The term ‘equilibrium’ refers to a condition where the concentrations of the reactants and products in a reversible reaction are constant over time.

Identify the variables that must remain constant to maintain an equilibrium constant and equilibrium position

The variables that must remain constant to maintain an equilibrium constant and equilibrium position are given below:

Concentration Temperature Pressure

The variables that do not need to remain constant are color and size.

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A experiment calls for 45 gallons of a saline solution. You only have a saline solution and a saline solution. Let x represent the amount of saline solution and y represent the amount of saline solution, what is the
equation that describes the total amount of pure saline in the solution?

Answers

The equation that describes the total amount of pure saline in the solution is: x + y = 45.

In the given scenario, x represents the amount of saline solution and y represents the amount of saline solution. The experiment calls for a total of 45 gallons of the saline solution. Since the total amount of saline in the solution is the sum of the amounts in each component, the equation x + y = 45 represents the total amount of pure saline in the solution.

The equation simply states that the combined amounts of saline solution (x) and saline solution (y) should add up to 45 gallons, fulfilling the requirement of the experiment. It provides a straightforward mathematical representation of the relationship between the two components in terms of their total quantity.

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Which type(s) of solute dissolve readily in water?

A. polar

B. ionic

C. nonpolar

D. colloidal

Answers

\( \huge {\tt {\green{\fbox{\pink{ANSWER}}}}} \\ \)

➥ \( \: \sf {Both \: \: \: a. \: \blue{ Polar} \: \: and \: \: \: b. \: \blue{Ionic}}\)

Explanation:

The molecules of water are polar in nature due to the presence of a positive end as oxygen and a negative end as hydrogen.

Due to its polar nature, the molecules of water are attracted towards the ionic molecules. This electrostatic force of attraction called ion-dipole attraction that makes the ionic compounds readily soluble in water.

Therefore, the polar and ionic solutes are readily dissolvable in water .

ᥫ᭡

I think polar and ionic

Water, H2O, is a molecule made of oxygen and hydrogen. The bonds that hold water molecules together are due to shared ___________, and known as covalent bonds. Question 12 options: electrons neutrons photons protons.

Answers

Oxygen and hydrogen share electrons in the molecule of water to form covalent bonds.

What kinds of bonds exist?Covalent bonds: These are formed between nonmetals and electrons by sharing electrons.Ionic bonds: These are formed between metals, which lose electrons, and nonmetals, which gain electrons.Metallic bonds: There are formed between metals. Electrons are delocalized in a cloud.

Water, H₂O, is a molecule made of 2 nonmetals: oxygen and hydrogen. The bonds that hold water molecules together are due to shared electrons, and known as covalent bonds.

Oxygen and hydrogen share electrons in the molecule of water to form covalent bonds.

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Galvanizing is a process used to protect steel by applying a sacrificial coating? Which metal is used in galvanizing?A. ZincB. GoldC. CopperD. Aluminum

Answers

Galvanizing is indeed a process used to protect steel by applying a sacrificial coating, and the metal used in this process is Zinc.

Zinc is an excellent choice for galvanizing because it is more reactive than steel, meaning it will corrode before the steel does, thus protecting the steel from rust and other forms of corrosion.

During the galvanizing process, the steel is dipped into a bath of molten zinc, which then adheres to the surface of the steel. This coating of zinc not only protects the steel from corrosion but also acts as a barrier against moisture and other environmental factors that can cause damage to the steel. In summary, galvanizing with zinc is an effective way to protect steel from corrosion and ensure its longevity.

Galvanizing is a process used to protect steel from corrosion by applying a sacrificial coating. This coating acts as a barrier between the steel and the environment, preventing rust and ensuring the material's longevity.

The metal used in galvanizing is zinc (option A). When zinc is applied to steel, it forms a protective layer that prevents the steel from corroding. This is because zinc is more reactive than steel, so it corrodes first, acting as a "sacrificial" layer that protects the underlying steel.

This process is especially beneficial for outdoor structures and applications where steel is exposed to the elements, as it provides a long-lasting, cost-effective solution to protect the material from degradation.

In summary, galvanizing is a method of protecting steel by applying a sacrificial zinc coating, ensuring the durability and longevity of the steel material.

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Design a course of action for the development of a building project in
or highway, that provides for the maintenance of biodiversity in the plan,

Answers

Answer:

A, B & C form the vertices of a triangle.

∠ CAB = 90°, ∠ ABC = 73° and AB = 9.4.

Calculate the length of BC rounded to 3 SF

We need to build wildlife corridors for the prevention of road accidents.
Design a course of action for the development of a building project inor highway, that provides for the

Addition of _____________ to pure water causes the least increase in conductivity

Answers

organic molecules

because organic molecules does not dissociate in water

A cylinder of gas has a pressure of 4. 882 atm on one day. The next day, the same cylinder of gas has a pressure of 4. 690 atm, and its temperature is 8. 0 degrees celsius. What was the temperature (in degrees celsius) on the previous day?.

Answers

A cylinder of gas has a pressure of 4. 882 atm on one day, the temperature (in degrees celsius) on the previous day was 20 °C.

A unit called temperature is used to represent hotness or coolness on a variety of arbitrary scales. Additionally, it illustrates the transfer of heat energy organically.

We formula for,

\(\frac{P1}{T1} = \frac{P2}{T2}\)

We have,

Day one's pressure is 4.882 atm.

The following day's pressure is 4.690 atm.

The next day, with a pressure of 4.690 atm, the temperature is 8 °C.

We convert the degree into Kelvin,

8 + 273 = 281 K

Putting the values in the equation

\(\frac{4.882}{T1} = \frac{4.690}{281}\)

We get, T1 = 292.5K

293 K converting into Celsius

293 - 273 = 20 °C

Thus, the temperature on the previous day is 20 °C.

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Let's say you eat some food, jump down some stairs, run outside, and then go inside and turn on the lights. Name and describe all the forms of energy and energy transformations that would happen when you do this. You should find at least 4, but try to find more! (1 point for each type of energy)

Answers

Answer:Chemical energies,elastic energy,kinetic energy,Light energy :)

Explanation:

please help on question 7 and 8

please help on question 7 and 8

Answers

Answer:

7. 5km/h

8. 10km/h

I just need to add characters so i can post

A student creates the Beer's Law plot for Part 3 and finds the slope to be 3. 5 ✕ 103. In Part 4, the solution prepared by mixing 5. 0 mL of 2. 0 ✕ 10−3 M NaSCN with 5. 0 mL of 2. 0 ✕ 10−3 M Fe(NO3)3 shows an absorbance of 0. 700.

(a) Calculate the equilibrium concentrations of Fe3+, SCN−, and FeSCN2+.

[Fe3+ ] ___ M

[SCN− ] ___ M

[FeSCN2+ ] ___ M

(b) Calculate Keq.

_____

Answers

To solve this problem, we'll use the Beer-Lambert Law and the information given.

(a) According to the Beer-Lambert Law, the absorbance (A) is directly proportional to the concentration (c) of the absorbing species:

A = εlc

where A is the absorbance, ε is the molar absorptivity constant, l is the path length (in cm), and c is the concentration (in M).

Given:

Slope of the Beer's Law plot (εl) = 3.5 × \(10^3\)

Absorbance (A) = 0.700

Since we have a 1 cm path length, the slope (εl) is equal to the molar absorptivity constant (ε).

Substituting the values into the equation, we can calculate the equilibrium concentrations:

ε = \(3.5*10^3 M^{(-1)} cm^{(-1)}\)

A = 0.700

Using the Beer-Lambert Law equation, we can rearrange it to solve for the concentration (c):

c = A / (εl)

For Fe3+:

c(Fe3+) = A / (εl) = 0.700 / (3.5 × \(10^3\)) = 2 ×\(10^{(-4)}\) M

For SCN-:

c(SCN-) = A / (εl) = 0.700 / (3.5 × \(10^3\)) = 2 × 1\(0^{(-4)}\) M

For FeSCN2+:

Since FeSCN2+ is the product of the reaction between Fe3+ and SCN-, the concentration of FeSCN2+ at equilibrium will be zero until the reaction reaches equilibrium.

Therefore, the equilibrium concentrations are:

[Fe3+] = 2 × \(10^{(-4)}\) M

[SCN-] = 2 × \(10^{(-4)}\) M

[FeSCN2+] = 0 M

(b) To calculate the equilibrium constant (Keq), we'll use the equation:

Keq = ([FeSCN2+]) / ([Fe3+][SCN-])

Substituting the given values:

Keq = (0) / (\((2 * 10^{(-4)})^2\)) = 0

Therefore, Keq is equal to 0.

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If volume of a water sample is 11.3 ml and the mass is 11.349 g, what is the exact density of the sample?

Answers

The exact density of the water sample with volume 11.3ml and mass 11.349g  is 1.004g/ml.

Density of a solution is defined as the ration of mass of the solution to the volume of the solution. Density is measured in g/cm³ for solids, g/ml for liquids, and g/L for gases.

As per the definition of density ,we can write

Density of solution  = (Mass of the Solution / Volume of the solution)

Mass of the water sample = 11.349g

Volume of water sample = 11.3ml

Density of Water sample = (Mass of water sample/Volume of Water sample)

Density of Water sample = (11.349g / 11.3ml)

Density of Water sample = 1.004g/ml.

The exact density of the water sample with volume 11.3ml and mass 11.349g  is 1.004g/ml.

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What is the value of k for this aqueous reaction at 298 k?298 k? a b↽−−⇀c dδ°=10. 35 kj/mol

Answers

The value of k for this aqueous reaction at 298 k a b↽−−⇀c  dδ°=10. 35 KJ/mol is 30.37 mol.

What is K?

K is the song which is used to donate the equilibrium of a reaction and the equilibrium of the reaction can only be obtained when the concentration of reactant is equal to the concentration of the product.

K is also known as the equilibrium constant.

δG or dδ° = - R T In K

                     R = universal gas constant

                     T = 298 k or 24.4Celciuss

                      dδ°= 10. 35

substituting the value in the equation

10. 35 = - 8.313 ×  24.4 celcius  In k

 In k =  - 8.313 ×  24.4 celcius / 10. 35

 In k = 30.37 mol.

Therefore, the value of k for this aqueous reaction at 298 k a b↽−−⇀c  dδ°=10. 35 KJ/mol is 30.37 mol.

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Suppose 2,560 grams of low-level radioactive waste is buried at a waste disposal site. Assume that 10 grams of radioactive material gives off an acceptable level of radiation and that one half-life is 5.26 years. Write a paragraph in which you explain to townspeople how much time must pass before there is an acceptable ratiation level at the site.​

Answers

However, keep in mind that 20 mSv per year is the recommended amount for any radiation worker and is still regarded quite safe. This is the most radiation most of us will ever be exposed to.

after 1st half life , remaining sample would be 100/2=50 g

after 2nd half life , remaining sample would be 50/2=25 g

after 3rd half life , remaining sample would be 25/2= 12.5 g

What is a radioactive material's half-life?

The half-life of a radionuclide is the amount of time it takes for half of its radioactive atoms to decay. A decent rule of thumb is that you will have less than 1% of the initial quantity of radiation after seven half-lives. Click here to learn more about half life.

A short-term and whole-body dosage would result in rapid sickness, such as nausea and a reduction in white blood cell count, followed by death.

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42.08 years of  time must pass before there is an acceptable radiation level at the site.​

What is the half-life of a radioactive material?

The half life of a radioactive substance is the period of time during which its mass or number of atoms is decreased to half of what it was initially. The time it takes for a radioactive substance (or half of its atoms) to break down or transform into another substance is commonly used to define half-life.

Radioactivity, as its name suggests, is the act of generating radiation without any external cause. This is accomplished by an atomic nucleus that is unstable for whatever reason and "wants" to surrender some energy in order to change its configuration to one that is more stable.

After first half-life will remain 2560/2 i.e. 1280g of radioactive substance.

After second half-life will remain 1280/2 i.e. 640g

After 3rd half-life will remain 640/2 i.e. 320g

After 4th half-life will remain 160g

After 5th half-life will remain 80g

After 6th, 7th and 8th half-life will remain 40g, 20g and 10g respectively

It takes 8 half-lives to reach acceptable level of radiation i.e. 8*5.26 years

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what element is oxidized and what element is reduced in the following reaction? fe2o3(s) 3co(g) --> 2fe(s) 3co2(g)

Answers

Answer:its c

Explanation:Oxidized: loses electrons...

Fe+2 gains electrons

C starts at +2, and ends at +4, it lost 2 electrons.

O starts at -2, ends at -2

Where are skeletal muscles used? Are they voluntary?

Answers

The peripheral portion of the central nervous system (CNS) controls the skeletal muscles. Thus, these muscles are under conscious, or voluntary, control

Swift has a 1.43mol sample of carbon dioxide. If the pressure of the sample is 34.56 kPa, and the volume is 440.99 mL, what will the temperature of the sample be in Kelvin?

Answers

For this problem, we could use the ideal gas equation:

\(PV=nRT\)

Where P is the pressure, V is the volume, R is a constant and T is the temperature.

Before we start solving, we should remember the units:

P [atm]

V [L]

i need help with this guys

i need help with this guys

Answers

I have no idea I’m answering this because I need to ask more questions

Henry’s law constant for gas x is 3. 30 x 10-2 m/atm. What total volume of solution is needed to completely dissolve 1. 65 l of gas at a pressure of 725 torr and a temperature of 25 °c?.

Answers

Henry's law, a gas law in physical chemistry, asserts that the quantity of dissolved gas in a liquid is inversely proportional to the partial pressure of the gas above the liquid. Henry's law constant is the name of the proportionality constant.

William Henry, an English chemist, developed Henry's law around the beginning of the 19th century. It claims that the relationship between dissolved gas concentration and gas phase partial pressure is linear. The Henry's law constant is the name of the proportionality factor.

Kн K1 is equal to 1.25 x 10-3 mol dm-3 atm-2.

KH times Pgas equals soluble.

Solvability = 1.25 x 10-3 x 2.5

Solubility is equal to 3.125* 10-3 mol/dm2.

The Henry's law constant (KH), commonly known as the air-water partition coefficient, is the ratio of a compound's concentration in water to its partial pressure in the air at a given temperature.

For example, moles per cubic meter for water and atmospheres for air (atm-m3/mol), or in a dimensionless unit like KH′ = KH/(RT), where KH′ is the dimensionless unit Henry's law constant (atm-m3/mol), ideal gas constant (8.20575 105 atm-m3/mol-K), and water temperature (K).

When a compound's molecular weight is less than 200 grammes per mole and its Henry's law constant is more than 103 atm-m3/mol, it is often classified as volatile.

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calcium hydride (cah2) reacts with water to form hydrogen gas: cah2(s) 2h2o(l) → ca(oh)2(aq) 2h2(g) how many grams of cah2 are needed to generate 48.0 l of h2 gas at a pressure of 0.888 atm and a temperature of 32°c?

Answers

To generate 48.0 L of H2 gas at 0.888 atm and 32°C, approximately 30.3 grams of CaH2 are needed according to the given conditions and calculations using the Ideal Gas Law and stoichiometry.

To determine the grams of calcium hydride (CaH2) required to produce 48.0 L of hydrogen gas at a pressure of 0.888 atm and a temperature of 32°C, we employ the Ideal Gas Law. Firstly, converting the temperature from Celsius to Kelvin yields 305.15 K. Using the equation PV = nRT, where P represents pressure, V signifies volume, n denotes moles, R represents the ideal gas constant (0.0821 L*atm/(mol*K)), and T signifies temperature in Kelvin.

Rearranging the equation to solve for n, we find n ≈ 1.44 moles. By employing the balanced chemical equation, we determine that 0.72 moles of CaH2 are required, as 1 mole of CaH2 produces 2 moles of H2. Finally, using the molar mass of CaH2 (approximately 42.1 g/mol), we find that the quantity of CaH2 needed is roughly 30.3 grams.

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Which source of power can reduce emission of carbon dioxide?.

Answers

Answer:

Applying smart electric grid technologies can potentially reduce CO 2 emissions. Electric grid comprises three major sectors: generation, transmission and distribution grid, and consumption. Smart generation includes the use of renewable energy sources (wind, solar, or hydropower).

Explanation:

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it is the minimum amount of solute that can be dissolved in the solvent
A. Salt Solution C. Saturated Solution
B. Sugar Solution D. ​

Answers

Answer:A

Explanation:

Answer can be option C

A 780.0 g hard-water sample contains 276 mg Ca. What is the concentration in parts per million?

Answers

Answer:

353 ppm

Explanation:

PPM also refers to parts per million, it represents a low concentration of a solution. It represents 0.001 gram or a milligram in 1000 mL, equivalent to 1 mg per liter

Given that;

276 mg of Ca in 780.0 g of water

1 ppm = 1 mg/L

780 g = 780 mL = 0.78 L

Therefore;

= 276 mg/ 0.78 L  

=  353.84mg/L

= 353 ppm

What is the concentration of a solution made by diluting 5mL of a 0.250m stock is to a volume of 30mL

Answers

Answer: 0.04167m

Explanation:

By using M1V1=M2V2

Let M1 = 0.250m

     M2 = x

     V1 = 5mL

     V2 =30mL

(0.250)(5) = (M2)(30)

          M2 = 0.04167m

A student put a bottle of water and a can of sugared soda in the freezer to chill them quickly. when she took them out, the bottle of water was frozen but the can of soda was not. explain why this happened.

Answers

The soda water didn't freeze because of the depression in freezing point as compared to the water.

What is Freezing Point Depression ?

When a solute is added to a pure solvent , then the value of freezing point is reduced.

The decrease in the freezing point is directly proportional to the molality of the solute.

It is given in the question that

A student put a bottle of water and a can of sugared soda in the freezer to chill them quickly.

when she took them out, the bottle of water was frozen but the can of soda was not.

It is because water is the pure solvent , so freezing point is fixed but the soda water has sugar and Carbon Di oxide along with the solvent water , the presence of the sugar and Carbon -di-oxide decreases the freezing point of the soda water and so it doesn't freezes.

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Ariana is playing basketball with her friends. They are using an orange basketball. Why does her basketball look orange?


All visible light waves except orange are absorbed by the ball.
Only orange light waves are absorbed by the ball.
All visible light waves except orange are reflected by the ball
Only orange light waves reach the surface of the ball.

Answers

Ariana is playing basketball with her friends. They are using an orange basketball. Because all visible light waves except orange are absorbed by the ball.

The correct answer is A.

The color of an object is determined by the wavelengths of light that it reflects or absorbs.In the case of Ariana's basketball, it appears orange because it reflects orange light while absorbing other colors. When white light (which contains all visible colors) shines on the basketball, the orange light waves are reflected back to our eyes, while the other colors are absorbed by the ball. This selective absorption and reflection of light by the ball's surface result in us perceiving the basketball as orange in color.

The correct answer is A.

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Saline is a 0,154 M NaCl solution.
If the mass of NaCl is used to prepare saline solution was 45,045 grams, find the volume of solution that was obtained.
(Na:23; Cl:35,5)

Answers

Answer: The volume of solution is 200 ml

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

\(Molarity=\frac{n\times 1000}{V_s}\)

where,

n = moles of solute

\(V_s\) = volume of solution in ml

moles of \(NaCl\) = \(\frac{\text {given mass}}{\text {Molar mass}}=\frac{45.045g}{58.5g/mol}=0.77mol\)

Now put all the given values in the formula of molality, we get

\(0.154=\frac{0.77\times 1000}{V_s}\)

\(V_s=\frac{0.154\times 1000}{0.77}=200ml\)

Therefore, the volume of solution is 200 ml

FILL HTE BLANK. with their low ies and small eas, the members of group 1a(1) and 2a(2) are strong _____ agents. with their high ies and large eas, the members of group 6a(16) and 7a(17) are strong _____ agents.

Answers

With their low ionization energies and small effective atomic sizes, the members of Group 1A (1) and 2A (2) are strong reducing agents. With their high ionization energies and large effective atomic sizes, the members of Group 6A (16) and 7A (17) are strong oxidizing agents.

Group 1A (1) and 2A (2) elements (alkali metals and alkaline earth metals, respectively) have low ionization energies, meaning it requires relatively less energy to remove an electron from their outermost shell. Additionally, they have small effective atomic sizes, which means their outermost electrons are closer to the nucleus and experience less shielding from inner electron shells. These characteristics make them more likely to lose electrons and act as reducing agents in chemical reactions. They readily donate electrons to other substances, facilitating reduction reactions.

Group 6A (16) and 7A (17) elements (chalcogens and halogens, respectively) have high ionization energies, indicating it requires a significant amount of energy to remove an electron from their outermost shell. Moreover, they have large effective atomic sizes, causing their outermost electrons to be farther from the nucleus and experience more electron-electron repulsion. These factors make them highly electronegative and efficient at accepting electrons, making them strong oxidizing agents. They readily gain electrons from other substances, promoting oxidation reactions.

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--The given question is incorrect, the correct question is

"With their low ionization energies (IEs) and small effective atomic sizes (EAs), the members of Group 1A (1) and 2A (2) are strong  _____agents. With their high ionization energies (IEs) and large effective atomic sizes (EAs), the members of Group 6A (16) and 7A (17) are strong  _____ agents."--

Other Questions
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