You are designing a building assigned to SDC D that is not a high occupancy, essential, or hazardous facility. S
DS

= 0.45 g, S
DI

=0.27 g, T=2.0,R=6, and the total dead load =5,000kips. What is the base shear? A. 50kips B. 115kips C. 137kips D. 287kips

Answers

Answer 1

According to the given information, SDC D refers to Seismic Design Category D, which means it requires a design seismic response acceleration parameter of SDS = 0.45 g.

The design seismic response parameter at short periods SDI is 0.27g.The formula to calculate base shear is as follows: V = Cs W Where,Cs = seismic response coefficient

W = the total weight of the building Cs is calculated by the formula: Cs = ( SDS / R ) * ( W / Wt ) * I, where SDS is the design seismic response parameter at short periods, R is the response modification coefficient,

W is the total weight of the building, Wt is the total effective weight of the building, and I is the importance factor. I is 1.0 for normal structures. The total weight of the building, W, is equal to the sum of the dead load, live load, and any other lateral load.

Here, the total dead load is given, which is 5,000 kips. Therefore, the total weight of the building will be 5000 kips. The response modification coefficient R is equal to 6 as per the given information.

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Related Questions

In your own words how does an airplane take off?

Answers

Answer:

Explanation:

How does an aircraft take off?

They are lift, weight, thrust and drag. Lift pushes the airplane up. The way air moves around the wings gives the airplane lift. The shape of the wings helps with lift, too.

HOPE THIS HELPS!

a worn or defective axle bearing will likely make what type of noise?

Answers

A worn or defective axle bearing will likely make a whining or growling defective axle . Axle bearings serve a vital role in the suspension and drivetrain system of a vehicle.

They are responsible for supporting the weight of the vehicle, as well as transmitting the rotation of the axle to the wheels.

When an axle bearing is worn or defective, it can cause a range of issues and symptoms. The most common symptom of a bad axle bearing is noise.

This noise can be heard as a whining or growling sound, which will usually increase in intensity as the vehicle's speed increases.

Other symptoms of a bad axle bearing may include vibration or shaking in the vehicle, as well as poor handling or steering.

In conclusion, if you hear a whining or growling noise coming from your vehicle, it is likely that the axle bearing is worn or defective. It is important to have this issue addressed as soon as possible, as a bad axle bearing can lead to more serious problems with your vehicle's suspension and drivetrain system.

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Generic Motors (GM) is making plans for its weekly operation for next year. GM makes three lines of
cars: Luxury (L), Mid-sized (M), and Economy (E). They have divided the country into four regions:
Northeast (NE), Northwest (NW), Southeast (SE) and Southwest (SW). They have two factories that can
ship to the four distribution center via train. Each distribution center will need to provide cars to the
dealers in that region; this is done via trucking. Note that since customers need their cars within a week,
everything is built on a weekly production and shipment schedule. The following information is included:
1) Production costs and capacities at the two factories for the three lines.
2) Retail cost of the three lines.
I
3) A weekly demand model for each of the four regions.
4) Shipping information from the factories to the distribution center of the four regions.
5) Shipping information from the distribution center to the dealers.
You have been asked to maximize the expected weekly profit for GM.
Make sure the spreadsheet is well documented! Use the color coding and headers we used all
semester long. You do not need to reproduce the spreadsheet in the report except the decision tree,
and a summary of your results.

Answers

You need all of this is what

What does the T wave on an ECG tracing represent?

Answers

The T wave on an ECG tracing represents the repolarization of the ventricles of the heart.

During the cardiac cycle, the heart undergoes a series of electrical and mechanical events that are reflected in the ECG tracing. The T wave is the last wave in the ECG cycle and is generated by the repolarization of the ventricles. Repolarization refers to the period when the cells in the ventricles reset their electrical charges to their resting state after the depolarization phase that generates the QRS complex. The T wave is typically a small, rounded wave that follows the QRS complex and is normally in the same direction as the QRS complex. The shape and duration of the T wave can provide important information about the health of the heart, as abnormalities in the T wave can be indicative of certain cardiac conditions such as myocardial ischemia or electrolyte imbalances.

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List three main commodity areas that drive agriculture

Answers

Common agricultural commodities include dairy products, wheat, and coffee. You can invest in and “trade” these products virtually, without running a farm and purchasing and storing the items yourself.

there is usually a positive side and a negative side to each new technological improvement?

Answers

Answer:

positive sides:

low cost improves production speedless timeeducational improvements

negative sides:

unemployment lot of space required increased pollution creates lots of ethical issues

Which company produces comprehensive patch management software?
Quest
Motorola
Apple
Sony

Answers

If I’m not mistaken it is Quest. I could be completely wrong or I could be right. I really don’t know but I guess you’ll have to go with it if you choose my answer. But Quest seems to be correct.

which material/beam tested showed the least deflection? a. aluminum beam a (0.5 x 0.5) b. aluminum beam b (0.25 x 0.5) c. steel beam d (0.5 x 0.5) d. aluminum beam c (0.5 x 0.25)

Answers

Option c is correct. The steel beam d (0.5 x 0.5) tested showed the least deflection. Beam deflection refers to the state in which a beam has changed from its initial shape as a result of a force, load, or weight.

Beam deflection refers to the state in which a beam has changed from its initial shape as a result of a force, load, or weight. Obtaining equations that allow us to accurately calculate beam deflections in a variety of real-world situations is one of the most significant uses of beam deflection. Analysis of statically indeterminate beams also takes into account deflections.

In terms of structural engineering, deflection is the movement of a beam or node from its initial position as a result of loads and forces acting on the member. It is also referred to as displacement and can result from externally applied loads as well as from the structure's own weight and the force of gravity that applies to it.

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When the process is in control but does not meet specification which type of error is it?

Answers

When the process is in control but does not meet specification, it is referred to as a special cause error.

What is the term for a process in control but not meeting specification?

In statistical process control, a process is considered to be in control when it operates within the defined limits and shows only random variations. However, when a process is in control but does not meet the desired specifications, it indicates the presence of a special cause error.

Special cause errors are attributed to specific factors or events that cause the process to deviate from the expected outcome. These errors are typically unpredictable and require investigation and corrective action to bring the process back within the desired specifications.

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what is the transfer function? what is the steady-state error, ess? what is the natural frequency? you can assume ra

Answers

The transfer function is a mathematical representation of the relationship between the input and the output of a system. The steady-state error, or ess, is the difference between the desired output and the actual output when the system reaches a steady state. The natural frequency is the frequency of the system's response without any external forces.

Transfer Function: Transfer Function is used in signal processing, control engineering, and other disciplines that deal with systems or signals. The ratio of output to input in Laplace transform is known as the transfer function.

Steady-State Error: The error that happens when the system is at a stable state is referred to as a steady-state error. The difference between the desired and actual response is known as steady-state error. A system's ability to track a specific input as time progresses is characterized by this kind of error. If the input signal is a unit step, then the steady-state error is referred to as the static error coefficient. The coefficient of the steady-state error is frequently used to classify systems in control engineering.

Natural Frequency: Natural frequency is a term used in physics to describe how quickly an object vibrates when it is set in motion. The number of oscillations made by a system in a given time period without any external force acting on it is referred to as its natural frequency. A natural frequency is a measure of a system's stiffness and mass. In a control system, it is the frequency at which the system oscillates in the absence of any input.

A natural frequency is also known as an undamped natural frequency or a resonance frequency, and it is represented by the symbol \(\omega_n\).You can assume the following in the problem. If you have any specific values, kindly provide them.

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which failure mode is due to a short that occurs between the positive and negative plates within a battery cell?

Answers

Answer:

Electrical short.

Explanation:

Why do you have to know each testing tools?​

Answers

Answer:

YAH A BLINK

Explanation:

If u are asking about softwares

then,

Software testing tools are often used to assure firmness, thoroughness and performance in testing software products.

\(#Liliflim\)

since every tool is important, it is also important that we know and learn how to use it for the coming of the day so we can fix the things that are broken to us.

the process of breaking the wbs into smaller and smaller deliverables is called: group of answer choices functional design detailed specifications value engineering decomposition

Answers

Decomposition is the process of breaking the Work Breakdown Structure (WBS) into smaller and smaller deliverables. This process is also sometimes referred to as value engineering or detailed specifications. By decomposing the WBS into smaller pieces, it becomes easier to assign tasks, assign costs, and plan out timelines.

The decomposition process begins by taking the major deliverables of the project and breaking them down into smaller tasks. From there, each task is further broken down into even more specific tasks. This process is repeated until all tasks have been broken down into their smallest components.

The purpose of decomposition is to create a well-defined scope of the project so that it can be managed in an efficient manner. It allows managers to easily identify the resources, cost, and timeline of each task, as well as provide a way to evaluate the progress of each task. It also allows for better control of the overall project.

Decomposition is a critical part of the project management process, as it ensures the project is organized and defined. This ultimately leads to an overall better result for the customer.

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Which of the following is a valid IP address/prefix to assign to a host? 172.31.0.255/16 172.16.255.128/25 201.18.149.33/25 10.255.0.0/8

Answers

The valid IP address/prefix to assign to a host is 172.16.255.128/25.

172.31.0.255/16: This is a valid IP address, but the prefix length (/16) includes many hosts beyond the current network, so it cannot be assigned to a host.172.16.255.128/25: This is a valid IP address with a prefix length (/25) that allows for 128 hosts. It can be assigned to a host.201.18.149.33/25: This is a valid IP address with a prefix length (/25) that allows for 128 hosts, but it is not in the private IP address range, so it cannot be assigned to a host on a private network.10.255.0.0/8: This is a valid IP address with a prefix length (/8) that includes all IP addresses from 10.0.0.0 to 10.255.255.255. It is not specific to a single host and cannot be assigned to a host.

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Answers

Answer:

thats a really cool design or whatever you got there.

Explanation:

niceeeeeeee :)

Select one correct statement: A) Specific ions are necessary for metals and alloys.B) An environment that causes SCC of one alloy would also causes SCC of another alloy.C) As specific ions form a film on the metal surface, hence, those ions which form films may be adequate to cause SCC.

Answers

Answer:

option  C

Explanation:

The correct statement is As specific ions form a film on the metal surface, hence those ions which form films may be adequate to cause SCC

other options are wrong as ; specific ions are not necessary for metals and alloys and also an environment causing SCC for an alloy might not cause SCC of another alloy found in the environment

How did the chinese prepare their iron differently than their western counterparts?.

Answers

The Chinese would cast the iron they had into molds to make identical objects.

Hope it helps :)

An organization has published applications on its web servers. The applications are accessible to users in the organization when they are authenticated via Active Directory.
What RAS capability will allow the organization's applications to be accessible to users outside of the organization?

Answers

Where an organization has published applications on its web servers and the applications are accessible to users in the organization when they are authenticated via Active Directory the RAS capability that will allow the organization's applications to be accessible to users outside of the organization is; "Web Application Proxy"

What is Web Application Proxy?

In Windows Server Remote Access, the Web Application Proxy is a role service. It provides reverse proxy capabilities, allowing users to access corporate resources on any device from outside the corporate network.

Web Application Proxy functions in two ways. It enables enterprises to grant end users outside of the company selective access to apps running on servers within the organization. It also acts as a stumbling block between business applications and the Internet.

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Can someone help me plz!!!

Can someone help me plz!!!

Answers

Answer:

15 000 000 Ohms

Explanation:

1 Mega Ohm = 1 000 000 Ohms

So,

15 Mega ohms =15 000 000 Ohms

It is 15,000,000 ohms

6.15 A modified CRC procedure is commonly used in communications standards. It is defined as follows: X¹6D (X) + XL (X) R(X) = Q+ P(X) P(X) FCS = L(X) + R (X) where L(X) = X15 + X14 + X¹3 + + X + 1 and k is the number of bits being checked (address, control, and information fields). a. Describe in words the effect of this procedure. b. Explain the potential benefits. c. Show a shift-register implementation for P(X) X16+ X12 + X³ + 1.

Answers

A modified CRC procedure appends a checksum to transmitted data for error detection and correction, improving data reliability and enabling efficient error identification and correction.

A modified CRC procedure is widely used in communication standards to ensure data integrity and reliability. When transmitting data, it is essential to detect and correct any errors that may occur during transmission. The CRC procedure achieves this by adding a checksum to the data, allowing the receiver to verify the integrity of the received data. This procedure involves polynomial division, where the data with an appended FCS is divided by a predefined polynomial P(X). The resulting remainder is the FCS, which is sent along with the data. At the receiver's end, the same polynomial division is performed, and if the remainder is zero, it indicates that the data has been received without any errors. However, if a non-zero remainder is obtained, it signifies the presence of errors.The benefits of using this modified CRC procedure are significant. Firstly, it provides a reliable method for error detection. By appending the FCS to the data, the receiver can compare the calculated remainder with the received FCS. If they match, it indicates that the data is error-free. Secondly, this procedure allows for efficient error detection. The polynomial division can be performed using simple shift registers, making it computationally efficient. Additionally, CRC is capable of detecting various types of errors, including single-bit errors, burst errors, and some multi-bit errors.By implementing a shift-register for P(X) = X¹⁶+ X¹² + X³ + 1, we can create a hardware implementation of the CRC procedure. The shift-register has 17 stages, corresponding to the degree of the polynomial. The input bits are fed into the register from the left, and the bits on the rightmost stage represent the remainder (R(X)). Each clock cycle, the bits in the register are shifted to the right, and new bits are entered from the left. The feedback connections are determined by the polynomial coefficients, with taps placed at positions 16, 12, and 3.This implementation allows for efficient computation of the CRC, making it suitable for real-time data transmission.

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One mole of carbon dioxide is to be compressed adiabatically from 1 bar and 25°C to 10 bar. Because of irreversibilities and poor design of the compressor, the compressor work required is found to be 25 percent greater than that for a well-designed (reversible) compressor. Compute the outlet temperature of the carbon dioxide and the work that must be supplied to the compressor for both the reversible and irreversible compressors for the two cases below. a) Carbon dioxide is an ideal gas with a constant-pressure heat capacity of 37.151 J/(mol K). b) Carbon dioxide is an ideal gas with the constant-pressure heat capacity given in Appendix A.II.

Answers

We can approach this problem by using the adiabatic compression equations and the relationship between work, pressure, and volume for reversible and irreversible processes. The adiabatic compression equations are:

p1V1^γ = p2V2^γ

T1V1^(γ-1) = T2V2^(γ-1)

where p is pressure, V is volume, T is temperature, and γ is the specific heat ratio of the gas (which is approximately 1.4 for carbon dioxide).

a) For an ideal gas with a constant-pressure heat capacity of 37.151 J/(mol K), the work required for a reversible adiabatic compression is:

W = -nCp(ΔT) = -nCp(T2 - T1)

where n is the number of moles of gas, Cp is the constant-pressure heat capacity, and ΔT is the change in temperature. Using the adiabatic compression equations, we can solve for the outlet temperature (T2) and the work required for the irreversible compression (W_irr):

p1V1^γ = p2V2^γ
T1V1^(γ-1) = T2V2^(γ-1)

Substituting p1 = 1 bar, p2 = 10 bar, V1 = nRT1/p1, and solving for V2, we get:

V2 = V1(p1/p2)^(1/γ) = (nRT1/p1)(p1/p2)^(1/γ)

Using the second adiabatic compression equation, we can solve for T2:

T2 = T1(p2/p1)^((γ-1)/γ) = T1(10/1)^0.4 = 316 K

Substituting n = 1 mole, Cp = 37.151 J/(mol K), T1 = 25°C = 298 K, and T2 = 316 K into the reversible work equation, we get:

W_rev = -nCp(T2 - T1) = -37.151 J/(mol K) * (316 K - 298 K) = -667.6 J

The work required for the irreversible compression is 25% greater than the reversible work, so we have:

W_irr = 1.25 * W_rev = -834.5 J

b) For an ideal gas with the constant-pressure heat capacity given in Appendix A.II, we can use the same approach as above, but substitute the appropriate Cp value. Let's assume that the Cp value given in Appendix A.II is valid for temperatures between 25°C and 316 K. Then, we have:

Cp = 29.07 J/(mol K)

Substituting this value into the reversible work equation, we get:

W_rev = -nCp(T2 - T1) = -29.07 J/(mol K) * (316 K - 298 K) = -524.3 J

Using the same adiabatic compression equations as above, we can solve for T2 and W_irr:

V2 = (nRT1/p1)(p1/p2)^(1/γ) = (1 mol * 8.314 J/(mol K) * 298 K / 1 bar) * (1 bar / 10 bar)^(1/1.4) = 0.0159 m^3

T2 = T1(p2/p1)^((γ-1)/γ) = 298 K * (10/1)^0.4 = 316 K

W_irr = 1.25 * W_rev = -655.4 J

Therefore, for an ideal gas with the constant-pressure heat capacity given in Appendix A.II, the outlet temperature of the carbon dioxide is 316 K, and the work that must be supplied to the compressor for the reversible and irreversible compressors are -524.3 J and -655.4 J, respectively.

The user manual states an accuracy of 0.1% of the reading for a tachometer (an instrument measuring the rotation speed of a shaft or disk, as in a motor or other machine) with an analog display dial graduated in 5 revolutions per minute (rpm) increments. Estimate the design stage uncertainty at 5000 rpm.

Answers

Answer: the design stage uncertainty is ±5.6 rpm

Explanation:

Given that;

machine with an analog display dial graduated in 5 revolutions per minute (rpm) increments; Q = 5 rpm

now lets calculate zero order uncertainty in this machine

⇒ ± 1/2Q =  1/2(5) = ± 2.5 rpm

given that accuracy is 0.1% of reading

0.1% of 5000 rmp = 0.1/100 × 5000 = 5 rpm

now the design stage uncertainty at 5000 rpm will be;

⇒ √((5)² + (2.5)²)

= √(25 + 6.25)

= √ 31.25

= ±5.59 ≈ ±5.6 rpm

Therefore the design stage uncertainty is ±5.6 rpm

what can be the main disadvantage of pulse amplitude modulation?​

Answers

Answer:

transmission bandwidth required is very large.

Explanation:

The gear with the least number of teeth is called the

Answers

Its called the Spur gear

64º26’18’’ + 195º57’12,75’’ – 100º55’35’’

Answers

Answer:

I can help you with your calculation.

To add and subtract angles in degrees, minutes, seconds (DMS) form, you need to follow these steps12:

Align the angles so that the degrees, minutes, and seconds are in the same column.

Add or subtract the seconds first. If the result is more than 60 or less than 0, adjust the minutes accordingly.

Add or subtract the minutes next. If the result is more than 60 or less than 0, adjust the degrees accordingly.

Add or subtract the degrees last.

Using this method, your calculation can be done as follows:

64º26’18’’ + 195º57’12,75’’ – 100º55’35’’ = 64º26’18’’ + 195º57’12.75’’ – 100º55’35’’ = 159º83’30.75’’ – 100º55’35’’ = 159º83’(30.75 - 35)’’ – 100º55’0’’ = 159º82’55.75’’ – 100º55’0’’ = 159º(82 - 55)’55.75’’ – 100º0’0’’ = 159º27’55.75’’ – 100º0’0’’ = (159 - 100)º27’55.75’’ = 59º27’55.75’’

Therefore, the answer is 59º27’55.75’’. I hope this helps!

Explanation:

Which directive tells the assembler to recognize 80x86 instructions that use 32-bit operands?A) .STACK 4096B) .586C) .MODEL FLATD) none of them

Answers

Answer:

Explanation:The directive that tells the assembler to recognize 80x86 instructions that use 32-bit operands is:

B) .586

The .586 directive enables the assembler to recognize and support instructions specific to the 586 (Pentium) processor and later versions. This includes instructions that use 32-bit operands, as the 586 processor and subsequent processors introduced the ability to work with 32-bit data.

A) .STACK 4096 is a directive used to allocate stack memory for the program.

C) .MODEL FLAT is a directive that specifies the memory model used for the program, but it does not directly enable recognition of 32-bit operands.

Therefore, the correct answer is B) .586.

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Convenience items like liquid egg are a lot more expensive?
True
Or False

Answers

It’s true because convenience stores are more expensive so that means overall the items would be more expensive.

Answer:

True

Explanation:

It's just because of the processing

2. A silo (base not included) is to be constructed in the form of a cylinder surmounted by a hemisphere. The cost of construction per square unit

of surface area is twice as great for the for the hemisphere as it is for the cylindrical side wall. Determine the dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum. Neglect the thickness of the silo and waste in construction.​

Answers

An extremum is a point where the function has its highest or lowest value, and at which the slope is zero.

The dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum is as follows;

Height of cylinder = 2 × Radius of cylinder

Reason:

The given parameters are;

Form of silo = Cylinder surmounted by a hemisphere

Cost of construction of hemisphere per square unit = 2 × The cost of of construction of the cylindrical side wall

Required:

The dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum

Solution:

The fixed volume of the silo, V, can be expressed as follows;

\(V = \pi \cdot r^2 \cdot h + \dfrac{2}{3} \cdot \pi \cdot r^3\)

\(h = \dfrac{V - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 }\)

Where;

h = The height of the cylinder

r = The radius of the cylinder

The surface area is, Surface Area = 2·π·r·h + 2·π·r²

The cost, C = 2·π·r·h + 2×2·π·r² = 2·π·r·h + 4·π·r²

Therefore;

\(C = 2 \times \pi \times r\times \dfrac{V - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 } + 4 \cdot \pi \cdot r^2 = \dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r}\)

\(C = \dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r}\)

At the minimum value, we have;

\(\dfrac{dC}{dr} =0 = \dfrac{d}{dr} \left(\dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r} \right) = \dfrac{16 \cdot r^3 \cdot \pi - 6 \cdot V}{3 \cdot r^2}\)

Which gives;

16·π·r³ = 6·V

\(V = \dfrac{16 \cdot \pi \cdot r^3}{6} = \dfrac{8 \cdot \pi \cdot r^3}{3}\)

Which gives;

\(h = \dfrac{\dfrac{8 \cdot \pi \cdot r^3}{3} - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 } = 2 \cdot r\)

h = 2·r

The height of the silo, h = 2 × The radius, 2

Therefore, the dimensions to be used if the volume is fixed and the cost is to be kept to a minimum is, height, h = 2 times the radius

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Suppose we are given three boxes, Box A contains 20 light bulbs, of which 10 are defective, Box B contains 15 light bulbs, of which 7 are defective and Box C contains 10 light bulbs, of which 5 are defective. We select a box at random and then draw a light bulb from that box at random. (a) What is the probability that the bulb is defective? (b) What is the probability that the bulb is good?​

Answers

Answer:

0.49

0.51

Explanation:

Probability that bulb is defective :

Let :

b1 = box 1 ; b2 = box 2 ; b3 = box 3

d = defective

P(defective bulb) = (p(b1) * (d|b1)) + (p(b2) * p(d|b2)) + (p(b3) * p(d|b3))

P(defective bulb) = (1/3 * 10/20) + (1/3 * 7/15) + (1/3 * 5/10))

P(defective bulb) = 10/60 + 7/45 + 5/30

P(defective bulb) = 1/6 + 7/45 + 1/6 = 0.4888

= 0.49

P(bulb is good) = 1 - P(defective bulb) = 1 - 0.49 = 0.51

A pump transfers water from a lake to a reservoir, which is located 29.2 m above the lake, at a rate of 11.5 L/s. Determine the amount of power (in kW) required to pump water from the lake to the reservoir.

Answers

Answer:

\(P=3290.84KW\)

Explanation:

From the question we are told that:

Height\(h=29.2m\)

Rate \(Q=11.5L/s=>11.5*10^{-3}\)

Generally the equation for Power is mathematically given by

\(P=\rho*g*Q*h\)

\(P=1000*9.81*11.5*10^{-3}*29.2\)

\(P=3290.84KW\)

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