You are designing a simulation for which day of the week people are born. You assign numbers to each day of the week, from, Sunday =0 through Saturday =6. You decide to use a sample size of 20.

Use the random number table to conduct your first trial, working from left to right.
39017 66124 37046 59285 15208 47185 76426 23648 51239 88346 59268 71307 37420 69307 98648 45960

Which chart matches the results from your first trial?

Answer:

20x^4

Step-by-step explanation:

Answer:

The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²vvvThe diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²The diagram shows measures of some of the line segments in APQR. 4.5 /62.58° Q Length of QS P Area of APQR S ㅏ Use the given information to find the measures of the unknown angles and segment shown below. Round your answers to the nearest whole number. Length of PS units 6.4 -5.0- units R units²v

Step-by-step explanation:

its E and A

Answer:

The solutions to the inequality are B, E, and F: 25, 36, and 9.

Step-by-step explanation:

The solutions to the inequality √x < 10 are the values of x that make the inequality true when plugged in. To find these values, we can square both sides of the inequality:

√x < 10

x < 10^2 = 100

So, the values of x that make the inequality true are those that are less than 100. The options that satisfy this condition are:

A. 100 (not a solution)

B. 25 (solution)

C. -100 (not a solution)

D. 105 (not a solution)

E. 36 (solution)

F. 9 (solution)

Answer: Addition.

Step-by-step explanation:

The word descended gives you a hint to use subtraction.

Answer: -1

Step-by-step explanation:

just plug in -16 for t.

-16 + 5

———

11

SIMPLIFY TOP

-11

—-

11

-1

Answer:

\(-1\)

General Formulas and Concepts:

Pre-Alg

Order of Operations: BPEMDAS

Step-by-step explanation:

Step 1: Define

\(\frac{t+5}{11}\)

t = -16

Step 2: Evaluate

The area of the trapezoid is 24cm².

It should be noted that the area of a trapezoid is calculated as:

Area = h × (a + b//2

where h = height

Area = 4 × (4 + 8)/2

Area = 4 × 12/2

Area = 4 × 6

Area = 24cm²

The area is 24cm²

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Answer:

B, the parabola is narrower.

Step-by-step explanation:

Given the parent square function: x^2.

A vertical stretch by a scale factor of 3 is made to transform x^2 into 3x^2.

A stretch makes the function narrower, a compression makes the function wider.

Therefore the parabola is narrower.

Answer:

-512

Step-by-step explanation:

The common ratio is multiplying by 4, therefore 4 muliplyed by -128 is -512

Answer:

2π|b| 2 π | b

Step-by-step explanation:

Answer:

In general, a mixed economy is "a combination of individual choice and government protection," although the balance tends to lean more towards individual choice.

Answer:

a combination of individual choice and government protection

Step-by-step explanation:

Answer:

8 is answer why can't I send

Answer:

slope = \(\frac{5}{4}\)

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (0, - 4) and (x₂, y₂ ) = (8, 6)

m = \(\frac{6+4}{8-0}\) = \(\frac{10}{8}\) = \(\frac{5}{4}\)

Answer:

x=2, y=5

Step-by-step explanation:

the triangle that x is in is a right triangle (don't remember the theorem sorry)

use pythagorean theorem (a^2 + b^2 = c^2)

x is the hypotenuse(c)

1 squared plus /3 squared =c squared

1+3= c squared

4= c squared

c=2

x=2

find y using pythagorean theorem as well

/12 squared plus 2 squared = y squared

y is the hypotenuse

12+4=y squared

16= y squared

4=y

add one to account for that extra little piece

y=5

... I don't see z

Answer:

y= if it is the hypoteneuse for the whole triangle it √16 or 4, if it is the side of the smaller triangle it is 3

x=√4 which is 2

z= I don't think ther's a z

Answer:

3

Step-by-step explanation:

so six people want 4 slices each or 24 slices in all

1 pizza= 8 slices

24/8= 3 pizzas

if my answer helps please mark as brainliest.

On simplification of 15 - 3(8 - 6)², we get 3. Thus, the correct answer is A

For simplification, we follow the rule of BODMAS. This rule states that one solves the equation in the following order: Brackets, Exponents or Order, Division, Multiplication, Addition, and Subtraction in order to get the right answer.

According to this rule, we first solve the Brackets

Therefore, 15 - 3(8 - 6)²

Then we solve the exponents and we get

= 15 - 3(2)²

Then we solve the multiplication operation in the equation

= 15 - 3(4)

Lastly, we solve the subtraction operation

= 15 - 12

= 3

Thus, we get 3 as the final answer after solving this equation.

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As asked in the question the value of xz and y will be even ,

xz is even and y is also even

given

X = factor of Y

Y = factor of Z

Therefore,

z= mnz = mnx  , xz = even

because

either z even, so the answer is directly yes or x is even (or both) but if x is even and as then  z= mnz = mnx must be even too (one of the multiples of z is even, so z is even too).

(2) y=  even

because

as z=ny then as one of the multiples of z even then only  z  will be even

Integers are the collection of whole numbers and negative numbers. Similar to whole numbers, integers also does not include the fractional part. Thus, we can say, integers are numbers that can be positive, negative or zero, but cannot be a fraction. We can perform all the arithmetic operations, like addition, subtraction, multiplication and division, on integers.

The examples of integers are, 1, 2, 5,8, -9, -12, etc. The symbol of integers is “Z“.

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Answer:

A. 281.25-525a=2.75s

Step-by-step explanation:

The equations that could represent the relationship between the number of students, s, the number of adults, a, and the dollar amount received at the game is 281.25 – 5.25a = 2.75s

Answer:

im pretty sure its a

Step-by-step explanation:

9514 1404 393

Answer:

  -4/3

Step-by-step explanation:

Quadratic ax² +bx +c can be written in factored form as ...

  a(x -p)(x -q)

for zeros p and q. The expanded form of this is ...

  ax² -a(p+q)x +apq

Then the ratio of the constant term to the leading coefficient is ...

  c/a = (apq)/a = pq . . . . the product of the zeros

For your quadratic, the ratio c/a is -4/3, the product of the zeros.

_____

Additional comment

You will notice that the sum of zeros is ...

  -b/a = -(-a(p+q))/a = p+q

Answer:

\( \green{ \boxed{ \bf \: product \: of \: the \: zeros \: = - \frac{4}{3} }}\)

Step-by-step explanation:

We know that,

\( \sf \: if \: \alpha \: and \: \beta \: \: are \: the \: zeroes \: of \: the \: \\ \sf \: polynomial \: \: \: \pink{a {x}^{2} + bx + c }\: \: \: \: then \\ \\ \small{ \sf \: product \: of \: zeroes \: \: \: \alpha \beta = \frac{constant \: term}{coefficient \: of \: {x}^{2} } } \\ \\ \sf \implies \: \pink{ \boxed{\alpha \beta = \frac{c}{a} }}\)

Given that, the polynomial is :

\( \bf \: 3 {x}^{2} - 2x - 4\)

so,

\( \sf \: so \: product \: of \: zeroes \: \: = \frac{ - 4}{3} = - \frac{4}{3} \)

1. The number of computations (hashes) required for finding a collision at 80% and 10% probabilities is 1.8447 x 10^19.

2. It will take approximately 47,891 seconds (or 13.3 hours) to find a collision at 10% probability.

The number of computations (hashes) required for finding a collision at 80% and 10% probabilities depends on the size of the hash function output. Let's assume a hash function output size of 128 bits for this example.

For finding a collision at 80% probability, we need to use the birthday attack algorithm. The number of hashes required can be calculated using the following formula:

N = sqrt((2^(n+1))*ln(1/(1-p)))

where n is the size of the hash output in bits (n=128 in this case), p is the desired probability of finding a collision (p=0.8 in this case), ln is the natural logarithm, and sqrt is the square root function.

Substituting the values, we get:

N = sqrt((2^(128+1))*ln(1/(1-0.8))) = 2^64.3155 = 1.8447 x 10^19

Therefore, we need 1.8447 x 10^19 hashes to find a collision at 80% probability.

For finding a collision at 10% probability, we can use the following formula:

N = sqrt((2^(n+1))*ln(1/(1-p)))

Substituting the values, we get:

N = sqrt((2^(128+1))*ln(1/(1-0.1))) = 2^55.9724 = 4.7891 x 10^16

Therefore, we need 4.7891 x 10^16 hashes to find a collision at 10% probability.

If we have a computer that can process a trillion hashes per second, we can calculate the time required to find a collision at 10% probability as follows:

time = N / rate

where N is the number of hashes required to find a collision (N=4.7891 x 10^16), and rate is the rate of hashes that the computer can process per second (rate=1 trillion = 1 x 10^12).

Substituting the values, we get:

time = (4.7891 x 10^16) / (1 x 10^12) = 4.7891 x 10^4 seconds

Therefore, it will take approximately 47,891 seconds (or 13.3 hours) to find a collision at 10% probability with a computer that can process a trillion hashes per second.

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Answer:

C. The ice cube melts as the water reaches thermal equilibrium.

Step-by-step explanation:

I put an ice cube in a glass of warm water and it melted.

Answer:

C

Step-by-step explanation:

The ice cube melts as the water reaches thermal equilibrium.

Answer:

The two numbers are 6 and 19

Step-by-step explanation:

Assume that the two numbers are x and y

We are given that:

The sum of the two numbers is 25

This means that:

x + y = 25 ..........................> equation 1

We are also given that:

One number is twice the other plus 7

This means that:

x = 2y + 7 ..........................> equation 2

Substitute with equation 2 in equation 1 and solve for y:

2y + 7 + y = 25

3y + 7 = 25

3y = 18

y = 6

Now, substitute with the value of y in equation 2 to get x as follows:

x = 2y + 7

x = 2(6) + 7

x = 12 + 7

x = 19

Based on the above, we can conclude that the two numbers are:

6 and 19

Hope this helps :)

x+y=25 => x=-y+25

x= 2y+7

x=-y+25

x=2y+7

subtract the first equation from the 2nd

0=3y-18

y=6

x=19

please mark me as brainlist

(a) Complex zeros of a polynomial come in pairs.

If a + bi is a zero of a polynomial then its conjugate a - bi is also a zero of the polynomial.

The given complex zeros of R(x) are 1 + 3i and -2i.

1 - 3i is the conjugate of 1 + 3i.

Hence, another zero of R(x) is 1 - 3i

b)

Since the polynomial R(x) is of order 13 then R(x) must have 13 zeros.

The given complex zeros of R(x) are 1 + 3i and -2i. We also know that the conjugates of 1 + 3i and -2i are zeros of R(x). Hence, R(x) has at least 4 complex roots

Hence, the maximum number of real zeros of R(x) is (13 -4).

The maximum number of real zeros of R(x) is 9

c) Let the maximum number of nonreal zeros (complex roots) be n

Complex roots come in pairs. Therefore, n must be even.

Hence, n ≤ 13 - 1 = 12

n ≤ 10

We have been given a real zero of R(x), 3 ( With the multiplicity of 4).

12 - 4 = 8

Therefore,

n ≤ 8.

Hence the maximum number of nonreal zeros of R(x) is 8

The value of the 10% trimmed mean is approximately 1.3027. To calculate the 10% trimmed mean, we need to trim off the lowest and highest 10% of the data and then find the mean of the remaining values.

First, let's sort the data in ascending order:

0.2, 0.21, 0.26, 0.3, 0.33, 0.41, 0.54, 0.57, 1.41, 1.7, 1.84, 2.2, 2.26, 3.06, 3.24

Next, we calculate the number of values to trim from each end:

10% of 15 (total number of values) = 0.1 * 15 = 1.5

Since we can't remove half a value, we round up to the nearest whole number, which is 2.

Now, we remove the two lowest and two highest values:

0.26, 0.3, 0.33, 0.41, 0.54, 0.57, 1.41, 1.7, 1.84, 2.2, 2.26

Finally, we calculate the mean of the remaining values:

(0.26 + 0.3 + 0.33 + 0.41 + 0.54 + 0.57 + 1.41 + 1.7 + 1.84 + 2.2 + 2.26) / 11 = 14.33 / 11 ≈ 1.3027

Rounding to four decimal places, the value of the 10% trimmed mean is approximately 1.3027.

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The Graduate Record Examination (GRE) is a test required for admission to many U.S. graduate schools. Students’ scores on the quantitative portion of the GRE follow a normal distribution with mean 150 and standard deviation 8.8.A graduate school requires that students score above 160 to be admitted.

Proportion of combined GRE scores can be expected to be over 160:We are given that the mean is 150 and the standard deviation is 8.8. We have to calculate the proportion of combined GRE scores that can be expected to be over 160.The standardized score is calculated as:z = (x - μ) / σwhere x = 160, μ = 150, and σ = 8.8Then we have:z = (160 - 150) / 8.8z = 1.136The area under the standard normal distribution curve to the right of 1.136 is 0.127. This means that 12.7% of combined GRE scores can be expected to be over 160.Proportion of combined GRE scores can be expected to be under 160:To calculate the proportion of combined GRE scores that can be expected to be under 160, we can subtract the proportion that is over 160 from the total proportion, which is 1.

So, the proportion of combined GRE scores that can be expected to be under 160 is:1 - 0.127 = 0.873This means that 87.3% of combined GRE scores can be expected to be under 160.Proportion of combined GRE scores can be expected to be between 155 and 160:We can use the same formula to calculate the proportion of combined GRE scores that can be expected to be between 155 and 160. First, we need to calculate the standardized scores for 155 and 160.z1 = (155 - 150) / 8.8z1 = 0.568z2 = (160 - 150) / 8.8z2 = 1.136Then, we need to find the area under the standard normal distribution curve between these two standardized scores.Using a standard normal distribution table or calculator, we find that the area between z = 0.568 and z = 1.136 is 0.155.

Therefore, the proportion of combined GRE scores that can be expected to be between 155 and 160 is 0.155. This means that 15.5% of combined GRE scores can be expected to be between 155 and 160.What is the probability that a randomly selected student will score over 145 points?We are given that the mean is 150 and the standard deviation is 8.8. We have to calculate the probability that a randomly selected student will score over 145 points.The standardized score is calculated as:z = (x - μ) / σwhere x = 145, μ = 150, and σ = 8.8Then we have:z = (145 - 150) / 8.8z = -0.568The area under the standard normal distribution curve to the right of -0.568 is 0.715. This means that the probability that a randomly selected student will score over 145 points is 0.715.

In summary, we can expect that 12.7% of combined GRE scores will be over 160, and 87.3% of combined GRE scores will be under 160. The proportion of combined GRE scores that can be expected to be between 155 and 160 is 15.5%. A randomly selected student has a probability of 0.715 of scoring over 145 points and a probability of 0.5 of scoring less than 150 points. Finally, a student who earns a quantitative GRE score of 142 has a percentile rank of 18.2%. These calculations are based on the normal distribution of GRE scores with a mean of 150 and a standard deviation of 8.8.

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Answer:

y = 5x - 3

Step-by-step explanation:

Answer:

y=3(x+4)²+2

Step-by-step explanation:

Answer:

I think it is the first one as you add the 4 like from the other