The correct reading of the weighing scale is approximately 11232.08 N. Thus, the design group is right in their opinion that an integral analysis is required, and the scale indicates the weight of the volume of water in the tank plus the tank weight.
The design group is right in their opinion that an integral analysis is required. The scale indicates the weight of the volume of water in the tank plus the tank weight. For the correct reading of the weighing scale, use the following solution: Given information: Height of water in tank, h = 579.12 mm. Metal container's height, H = 609.6 mm. Inside cross-sectional area of the container, A = 0.3048 m². Empty weight of container, m(empty) = 2.27 kg. The mass flow rate measurement device shown in the figure below is to be designed as part of an experimental setup for fluid dynamics laboratory. The device has a metal container with an inside cross-sectional area of 0.3048 m² and a height of 609.6 mm, which weighs 2.27 kg when empty. Water flows through an opening in the top and out through the two equal-area openings in the sides. Under steady flow conditions, the height of the water in the tank is 579.12 mm. The advisor suggests using a catch and time technique for accurate mass flow rate measurement.
The formula for the mass flow rate of water is given as: Q = A*V, where, Q = Mass flow rate, A = Cross-sectional area, V = Velocity of flow. We need to find the value of the mass flow rate. Let's determine the value of V first. Velocity of flow, V = √(2*g*h) where, g = acceleration due to gravity = 9.81 m/s²h = height of water in the tank = 579.12 mm = 0.57912 m∴ V = √(2*9.81*0.57912)≈ 3.741 m/s. Now, let's determine the value of the mass flow rate. Mass flow rate, Q = A*V= 0.3048*3.741≈ 1.1422 m³/s.
Let's now find the weight of the water that flows into the container. Mass of water, m = Q*ρ, where,ρ = Density of water = 1000 kg/m³∴ m = 1.1422*1000≈ 1142.2 kg.
Weight of water, W = m*g= 1142.2*9.81≈ 11209.8 N.
Now, let's find the weight of the container.
Weight of container, W(container) = m(empty)*g
= 2.27*9.81≈
22.2757 N.
The total weight of the system, W(system) = W + W(container)
= 11209.8 + 22.2757
≈ 11232.08 N.
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A regular pentagonal garden plot has centre symmetry o and an area of 338 m2. Find the distance oa
The distance is 9.65 m.
Area of each triangular sector = 338/5
Angle subtended at center = 360° / 5 = 72°
Let, circumradius of pentagon = r
Side of pentagon = 2r sin36°
Apothem = rcos36°
Area of each sector = 1/2 (2r sin 36°)(rcos36°)
= \(r^{2}\)/2 sin72° = 338/5
\(r^{2}\) = 338/5 × 2/sin72° = 142.16
r = 11.9 m
Apothem = rcos36° = 9.65 m
Hence, the distance is 9.65 m.
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Does the size of the magnetic field change with the size of the magnet?
Answer:
Not all of the time, it can also depend on the strength of the magnet.
Explanation:
say you have a small very strong magnet, that might work just as well as a large but week magnet.
how to find coefficient of friction with mass and force
To find the coefficient of friction with mass and force, you can use the equation: \(\[ \text{{Coefficient of Friction}} = \frac{{\text{{Force}}}}{{\text{{Normal force}}}} \]\).
The coefficient of friction is a measure of the resistance between two surfaces when they are in contact and sliding against each other. It quantifies the amount of frictional force between the surfaces. The force here refers to the force applied parallel to the surface, which causes the object to move or resist motion. The normal force is the perpendicular force exerted by a surface to support the weight of an object. To calculate the coefficient of friction, you divide the force applied by the normal force.
For example, let's say you have a mass of 10 kg and a force of 50 N acting on it. If the object is on a horizontal surface with no vertical acceleration, the normal force would be equal to the weight of the object, which is \(\( \text{{mass}} \times \text{{gravitational acceleration}} \)\). If the gravitational acceleration is \(9.8 m/s\(^2\)\), then the normal force would be \(\( 10 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 98 \, \text{N} \)\). Plugging these values into the formula, the coefficient of friction would be \(\( \frac{50 \, \text{N}}{98 \, \text{N}} = 0.51 \)\).
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Ocean waves, electromagnetic waves, and stadium crowd waves are all most often referred to as what type of wave, so-named because the waves' periodic disturbances are at right angles to the direction of propagation?
Direct wave Propagation :-When radio waves travel from the transmitter antenna toward the receiver antenna in a straight line, both antennas are within each other's horizon view.
Ocean waves, electromagnetic waves, and stadium crowd waves are most often referred to as transverse waves. Transverse waves are so-named because the waves' periodic disturbances are at right angles to the direction of propagation. In these waves, the oscillation of the particles or fields is perpendicular to the direction of wave propagation, creating a distinct "up and down" motion along the path of the wave.
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_______ increases when air faces greater resistance against an object with a larger surface area. (4 letters)
The term that increases when air faces greater resistance against an object with a larger surface area is drag.
The drag force is created when a solid object moves through a fluid (liquid or gas), such as air, and experiences resistance to its motion.Drag can be affected by various factors, including the object's shape and surface area. In general, objects with larger surface areas will experience more drag than those with smaller surface areas because they create more friction with the surrounding fluid. For example, a flat, wide object like a barn door will experience more drag than a narrow object like a pencil because it has a larger surface area. Similarly, a parachute will experience a large amount of drag because of its large surface area, which creates a significant amount of friction with the air molecules around it.In order to minimize drag and increase efficiency, engineers and designers often try to create streamlined objects with minimal surface area. This can be seen in the design of cars, airplanes, and even swimsuits used by competitive swimmers. By minimizing drag, these objects are able to move more quickly and with less effort through their respective fluids.
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two girls drag a bag across the floor. One girl exerts a force of 10 newtons and the other girl a force of 30 Newton's in the same direction. Calculate the resultant force on the bag.
Answer:
Explanation:
The resultant would be a combination of the two forces. We need to add them together since they are exerting a force in the same direction.
10+30= 40 N of force
For the curve defined by r(t) = (e-t, 2t, et) = find the unit tangent vector, unit normal vector, normal acceleration, and tangential acceleration at t T(t) = Ñ(t) = ат aN = 2.
The unit tangent vector T(t) for the curve defined by r(t) = (e², 2t, e) at t = 2 is \(\[T(2) = \left(\frac{e^2}{\sqrt{e^4 + 16 + e^2}}, 4, e\right)\]\). The unit normal vector N(t) for the curve at \(\[N(2) = \left(\frac{-2e^2}{\sqrt{4e^4 + 1}}, 1, 0\right)\]\).
The normal acceleration ar at \(\[ar(2) = \frac{\sqrt{4e^4 + 1}}{\sqrt{e^4 + 16 + e^2}}\]\). The tangential acceleration at t = 2 is aT(2) = 0 since the curve is defined as a straight line and has no curvature.
Determine how to find the tangent vector?To find the unit tangent vector T(t), we take the derivative of the position vector r(t) with respect to t and normalize it by dividing by its magnitude. The derivative of \(\[T(t) = \frac{(e^2, 4, e)}{\sqrt{e^4 + 16 + e^2}}\]\).
To find the unit normal vector N(t), we differentiate T(t) with respect to t and normalize the resulting vector. The derivative of T(t) is (0, 0, 0), which means the curve is a straight line. Therefore, N(t) is constant and given by \(\[N(t) = \frac{(-2e^2, 1, 0)}{\sqrt{4e^4 + 1}}\]\).
The normal acceleration ar at t = 2 is the magnitude of the derivative of T(t) with respect to t, which simplifies to \(\[\frac{\sqrt{4e^4 + 1}}{\sqrt{e^4 + 16 + e^2}}\]\).
Since the curve is a straight line, there is no change in the direction of the velocity vector, and therefore, the tangential acceleration aT is zero.
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1).
A). Find the total resistance
B). Find the current
ww
1.5 V
1.5 V
R1
5Q
ww
R3
15 Ω
3). A. Find the total resistance
B. Find the current in each resistor.
C. Find the voltage across each resistor.
R2
10 Q
R1
R2
R3
50 100 150
E
25V
2). A). Find the total resistance
B). Find the total current
*
8
2
R₂
2012
ww
4). A. Find V1
ww
7
8₁
10 k
3
R₁
3802
6
R₂
210
B. Find V1 and V2
C. Why are V2 and V3 equal?
V₁-V,
5
E=V₁ + V₂
R₁
3012
R₂
1k0
A) To find the total resistance, we need to calculate the equivalent resistance of the resistors in series and parallel. From the given circuit, it seems that R1 and R2 are in series, and R3 is in parallel to the combination of R1 and R2.
The resistance of R1 and R2 in series can be added:
R1 + R2 = 5 Ω + 10 Ω = 15 Ω
The total resistance of R1 and R2 in series is 15 Ω.
The parallel combination of R1, R2, and R3 can be calculated using the formula:
1 / (R1 + R2) = 1 / 15 Ω
Adding R3 in parallel to this combination:
1 / (R1 + R2) + 1 / R3 = 1 / 15 Ω + 1 / 15 Ω = 2 / 15 Ω
Taking the reciprocal of the sum gives the total resistance:
1 / (2 / 15 Ω) = 15 Ω / 2
The total resistance is 7.5 Ω.
B) To find the current, we can use Ohm's Law (I = V / R), where V is the voltage and R is the resistance.
In this case, the voltage across the circuit is given as 1.5 V. Using the total resistance of 7.5 Ω:
I = 1.5 V / 7.5 Ω = 0.2 A or 200 mA
The current flowing through the circuit is 0.2 A or 200 mA.
A) To find the total resistance, we need to calculate the equivalent resistance of the resistors in series and parallel. From the given circuit, it seems that R1, R2, and R3 are in series.
The total resistance is the sum of R1, R2, and R3:
R_total = R1 + R2 + R3 = 50 Ω + 100 Ω + 150 Ω = 300 Ω
The total resistance is 300 Ω.
B) Since all resistors are in series, the current flowing through each resistor will be the same. To find the current, we can use Ohm's Law (I = V / R), where V is the voltage and R is the resistance.
The voltage across the circuit is given as 25 V. Using the total resistance of 300 Ω:
I = 25 V / 300 Ω = 0.0833 A or 83.3 mA (rounded to 3 decimal places)
The current flowing through each resistor is approximately 0.0833 A or 83.3 mA.
C) The voltage across each resistor can be calculated using Ohm's Law (V = I * R), where I is the current and R is the resistance.
Voltage across R1: V1 = I * R1 = 0.0833 A * 50 Ω = 4.165 V
Voltage across R2: V2 = I * R2 = 0.0833 A * 100 Ω = 8.33 V
Voltage across R3: V3 = I * R3 = 0.0833 A * 150 Ω = 12.495 V
The voltage across R1 is approximately 4.165 V, across R2 is approximately 8.33 V, and across R3 is approximately 12.495 V.
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2x+3y=10 answer must be in decimals
A train travels a 400-km route and makes five stops in seven hours. Which equation is used to calculate the train’s average speed?
A.
Average speed = Sum of instantaneous speeds
B.
Average speed = Total distance x Total time
C.
Average speed = Total distance + Total time
D.
Average speed = Total distance ÷ Total time
HELPPPPPP RNNN!!!
If the height of the ramp was 1.2 m above the floor, how long would it take for the marble to hit the
ground after it left the ramp?
Answer:
A ramp for unloading a moving truck, has an angle of elevation of 30∘. If the top of the ramp is 0.9m above the ground level, then find the length of the ramp.
Explanation:
Hopefully this helps!!!
When five equal positive charges are uniformly spaced along the x-axis, the force on the next to last charge on the right is directed where?
The force is applied to the next-to-last positive charge upon that right assuming 5 equal secondary electrons are distributed evenly along the x-axis.
What is the SI unit for force?Force seems to be a physical factor that alters or has the potential to alter an object's state either rest or motion as well as its shape. Newton is really the Substrate concentration of force. The "three components of force" are typically referred to by the force's size, distribution, and place of action. Force is frequently represented by line segments.
What characteristics does force have?Therefore, the characteristics of lines involving force are now that they begin at a positively charged ions and end at a negative charge, never cross, are proportionate to charge, and cannot pass through a conductor.
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(i) 10 m (ii) 20 m (iii) 40 m (iv) 80 m
(c) The maximum potential energy of the object if its mass is 200g 1 mark
(i) 100 J (ii) 120 J (iii) 160 j (iv) 200 J
(d) In the given graph the total mechanical energy will be 1 mark
(i) Same (ii) increases (iii) decreases (iv) will be zero.
(e) In the given graph the kinetic energy 1 mark
(i) Same (ii) increases (iii) decreases (iv) increases then decreases.
Answer:
20m
420=80m
100
increases
increases then decreases
When discussing newton™s laws of motion, which terms do people most likely use when talking about newton™s third law of motion? a. force and œacceleration b. inertia and œforce c. action and œreaction d. mass and œinertia
When discussing Newton's laws of motion, people most likely use the terms "action" and "reaction" when talking about Newton's third law of motion.
Newton's third law of motion states that for every action, there is an equal and opposite reaction. This means that whenever one object exerts a force on another object, the second object exerts an equal and opposite force back on the first object.
In other words, if object A pushes or pulls on object B with a certain force, then object B will push or pull back on object A with an equal and opposite force. This law applies to all types of forces, whether they are contact forces or non-contact forces, such as gravitational or electromagnetic forces.
This law is important in understanding how forces work in the physical world. It helps explain why things don't just keep accelerating indefinitely when a force is applied, and why forces always come in pairs. It also plays a crucial role in understanding the behavior of systems like rockets, airplanes, and cars.
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Starting with only the Balmer series light (visible light), how could we ensure that the solar panels generate a current that Mark can use for his power station? (It may help to look at the electromagnetic spectrum from week 3):.
We can ensure that the solar panels generate a current that Mark can use for his power station is by gradually increasing the brightness (amount) of light that we reflect on it.
Solar panel are photo-voltaic module or cells which means they uses sunlight as a source of energy to generate current.
when the sun rays hit a silicon crystal of the solar panel then the electron inside of the solar panel start to charge and travel rapidly. when such charged electron flow through the circuit then the solar panel generate electricity.
So, to optimize the electricity generation, the energy of light is to be maximized which is determined by the frequency of the source.
Hence, To ensure that the solar panels generate a current that Mark can use for his power station we need to gradually increase the brightness (amount) of light that we reflect on it.
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If a human being is exposed to a sound of 50000 hz at 180 decibles what will happen?
Exposure to a sound of 50,000 Hz at 180 decibels would have severe and potentially life-threatening consequences for a human being. Here's what would happen:
Hearing Damage: The human threshold for pain from sound is typically around 120-130 decibels. Exposure to a sound level of 180 decibels is significantly higher and can cause immediate and irreversible damage to the ears.
Physical Discomfort and Pain: Sound waves at such high intensity can cause intense physical discomfort, pain, and even physical harm. The high pressure variations caused by the sound can lead to damage to delicate tissues.
Tissue Damage: Extremely loud sounds can also cause damage to other parts of the body, not just the ears. The high sound pressure levels can cause physical damage to internal organs, blood vessels, and tissues.
Psychological Impact: Exposure to a sound at such a high volume can be psychologically distressing and traumatic. It can lead to a state of panic, disorientation, and extreme anxiety.
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A crate of mass m1 = 13.00 kg is pulled by a massless rope up a 36.9° ramp. The rope passes over an ideal pulley and is attached to a hanging crate of mass m2 = 16.30 kg. The crates move 1.41 m, starting from rest.Find the work done by gravity on the sliding crate.
The free body diagram of the system can be shown as,
The work done by gravity on sliding crate can be given as,
\(W=(m_1g\sin \theta)dcos180^{\circ}_{}\)The angle between distance and force is 180 because the force acts in the downward direction whereas the block slide in the upward direction.
Substitute the known values,
\(\begin{gathered} W=(13.0kg)(9.8m/s^2)\sin 36.9^{\circ}(1.41\text{ m)(-1)(}\frac{1\text{ J}}{1kgm^2s^{-2}}) \\ =-(179.634\text{ J)(}0.6) \\ \approx-107.8\text{ J} \end{gathered}\)Thus, the work done by gravity on the sliding crate is -107.8 J.
I need a detailed explanation!
In terms of Newton's Second Law, F = ma, why does it hurt when you kick a brick wall, but not when you kick a soccer ball?
Your task: Write a paragraph explaining why you would experience a different sensation when kicking a brick wall and a soccer ball.
Answer:
The brick wall has less mass compared to the soccer ball. With the ball you would have to use less force to make it go a certain distance. You would have to apply more force in the case of the brick wall to get it to go the same distance as the soccer ball.
Heavier things need more force and acceleration to move the same distance as lighter things because they have more mass.
Force by wall.
Take mass of wall as 120 kg and acceleration as 10m/s^2, Then the total force acting would be F = ma
120 * 10 = 1200 N
According to Newton's 3rd law of motion, Every action has an equal and opposite reaction. So, the force you apply on the wall is equivalent to the force the wall applies on you. Hence the wall applies a force of 1200 N on you which is why you get hurt.
Force by soccer ball.
The mass of a soccer ball is obviously lesser than the mass of a wall. Take mass of soccer ball as 0.5 kg and take the same acceleration as 10m/s.
F = ma, Hence
Force = 0.5 * 10 = 5 N
The force applied on the ball is much less compared to the force applied on the soccer wall that is just 5 N. Using the 3rd law of motion, we can prove that only a force of 5 N acts on us when we kick a ball. Hence it does not hurt.
Thus, proved.
Hope this helps.
Its simple if we check second law of Newton
\(\\ \rm\Rrightarrow F=ma\)
\(\\ \rm\Rrightarrow F\propto m\)
If mass is more force is more and vice versaWall has bigger mass so for force is required and hence more reaction force(Newton's third law)
Pls help I want to give more points to people this is for 100. yes 100 points
Who is number 15 on the Kansas City Chiefs
Answer:Patrick Mahomes
Explanation:
Answer:
Patrick Lavon Mahomes II
Explanation:
What is the lewis structure of water with the correct partial charges and non-bonding electrons?.
Hydrogen has partial positive charge and oxygen has partial negative charge.
The link between water is known to be H-O-H. The octet rule states that oxygen must be surrounded by 8 electrons. Four is provided by the two bonds with H. The remaining 4 therefore happen as non-bonding electrons. Since oxygen is more electronegative than hydrogen, it receives a partial negative charge as indicated in image as follows. Covalent bond is present between oxygen and hydrogen atom.
The Lewis structure, also referred to as an electron dot structure, uses a diagram to show how many valence electrons are available in an atom and ready to form bonds with other atoms to create molecules and, eventually, compounds.
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4. Mohith said "H, differs from 2H". Justify. (A
The statement is absolutely true. H differs from 2H.
Justification:
H represents a single atom of hydrogen. Basically hydrogen cannot exist as a single atom. It is diatomic.2H represents 2 atoms of hydrogen.Mass of H atom = 1 uMass of 2H atom = 2 × 1 u = 2uHope you could get an idea from here.
Doubt clarification - use comment section.
A car accelerates from 12 m/s to 24 m/s in 6 seconds. Calculate its acceleration.
Answer:
\( \boxed{\sf Acceleration \ (a) = 2 \ m/s^2} \)
Given:
Initial velocity (u) = 12 m/s
Final velocity (v) = 24 m/s
Time taken (t) = 6 seconds
To Find:
Acceleration (a) of the car
Explanation:
From equation of motion we have:
\( \boxed{ \bold{v = u + at}}\)
By substituting value of v, u & t in the equation we get:
\( \sf \implies 24 = 12 + 6a \\ \\ \sf \implies 6a + 12 = 24 \\ \\ \sf \implies 6a = 24 - 12 \\ \\ \sf \implies 6a = 12 \\ \\ \sf \implies a = \frac{12}{6} \\ \\ \sf \implies a = 2 \: m {s}^{ - 2} \)
\( \therefore\)
Acceleration (a) of the car = 2 m/s²
Answer:
\( \boxed{ \bold{ \huge{ \boxed{ \sf{2 \: m \:/{s} \: ^{2}}}}}}\)
Explanation:
Initial velocity ( u ) = 12 m/s
Final velocity ( v ) = 24 m/s
Time taken ( t ) = 6
Acceleration of the car = ?
Finding the acceleration
\( \boxed{ \sf{acceleration = \frac{v - \: u}{t}}} \)
\( \longrightarrow{ \sf{acceleration = \frac{24 - 12}{6} }}\)
\( \longrightarrow{ \sf{acceleration = \frac{12}{6}}} \)
\( \longrightarrow{ \sf{acceleration = \: 2 \: m/ {s} \: ^{2} }}\)
Hope I helped!
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If an object straight down falls 30m in 2 sec , how far will falls in 4 sec , what is the tail wind and headwind
Answer:
60 sec
Explanation:
60m because in every 30min in 2sec so 30 × 2= 60 min
Question 4 of 10
Which statement describes the path of electrons from a battery to a circuit?
O A. Electrons move through the battery from the positive terminal to
the negative terminal and then into the circuit.
OB. Electrons move away from the positive end of a battery and then
through the circuit toward the negative end of the battery.
O C. Electrons move away from the negative end of a battery and then
through the circuit toward the positive end of the battery.
OD. Electrons move through the battery from the negative terminal to
the positive terminal and then into the circuit.
SUBMIT
Which statement describes the path of electrons from a battery to a circuit?
The correct answer would be:
C. Electrons move away from the negative end of a battery and then
through the circuit toward the positive end of the battery.
(06.04 MC)
Which of the following best describes a human egg cell? (3 points)
Answer: A haploid cell formed in the female uterus
1. A car's velocity changes from 0 m/sec to 30 m/sec 10 seconds later. Calculate the car's average acceleration.
Answer:
3 m/s²
Explanation:
Take the difference between the initial speed(0) and final speed (30) and divide it by time (10).
final speed - initial speed
——_----------------------------
time.
in which direction is the puck moving at t = 3 s ? give your answer as an angle from the x-axis.
The puck is moving at an angle of 51 degrees from the x-axis.
As we can see from the graph of the question the value of x component of velocity \(v_{x}\) is nearly 24 cm/s and the value of y component of velocity \(v_{y}\) is constant throughout the journey of puck and is equal to 30cm/s. For any instant of time the direction is given by the slope of the graph tanθ which is equal to the y component divided by the x component.
At the instant when t= 3s
\(v_{x}= 24 cm/s\\v_{y}= 30 cm/s\\\)
Direction is given by the slope of the graph
tanθ= \(\frac{v_{y} }{v_{x} } = \frac{30}{24}\)= 1.25
θ= 51 degrees from x-axis (in anti-clockwise manner)
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what do linguists call small units of sound that carry meaning on their own?
Linguists call small units of sound that carry meaning on their own "morphemes".
Actually, phonemes are the smallest units of sound in a language that can distinguish meaning. They are abstract units of sound that differentiate one word from another word in a language. For example, in English, the sounds /p/ and /b/ are phonemes because they distinguish words like "pat" and "bat".
Morphemes, on the other hand, are the smallest units of language that carry meaning. They can be made up of one or more phonemes. For example, the word "cats" has two morphemes: "cat" and "-s" (which indicates plurality), and each of these morphemes is made up of phonemes.
So while phonemes are important in distinguishing meaning, morphemes are the smallest units of language that carry meaning on their own.
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what is the maximum distance we can shoot a dart, from ground level, provided our toy dart gun gives a maximum initial velocity of 2.78 m/s and air resistance is negligible?
If air resistance is negligible and our toy dart cannon generates a maximum initial velocity of 2.78 metres per second, we can shoot a dart up to a maximum distance of 0.74 metres from the ground.
Velocity is a time-dependent measure of how quickly an object's position changes in relation to a frame of reference. The velocity of an object indicates both its direction and speed of motion. Final velocity is a vector quantity that describes the speed and direction of a moving body after it has reached its maximum acceleration. The relationship between two points in physical space is given by the formula R = v2 sin2 theta/g.
R(max) equals v2/g if theta is 45 degrees.
R = 2.7^2 / 9.8 = .74 m
R = v^2 sin 2 theta / g
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Which climate favors mechanical weathering?
Cold climate favors rapid mechanical weathering, since the cold seasons cause the rock to contract.
What is mechanical weathering and what climate they favour?Mechanical weathering, sometimes referred to as physical weathering and disaggregation, causes rocks to break down. Water, whether liquid or solid, is usually present during mechanical weathering. For instance, liquid water can seep through fractures and fissures in rock.
Cold climates promote mechanical weathering because they force rocks to contract and compress during the colder months. The rocks degrade and break at higher temperatures. Temperature fluctuations cause the expansion and contraction of rock (with cold). As this continues repeatedly, the structure of the rock deteriorates. It breaks down over time.
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