You decide to visit Santa Claus at the north pole to put in a good word about your splendid behavior throughout the year. While there, you notice that the elf Sneezy, when hanging from a rope, produces a tension of 415 N in the rope.
If Sneezy hangs from a similar rope while delivering presents at the earth's equator, what will the tension in it be? (Recall that the earth is rotating about an axis through its north and south poles.)

Answer:

0° C = 273.15 K

0 K = - 273.15° C

Explanation:

Hello there!

The Kelvin temperature scale refers to the absolute temperature scale. The division in the Kelvin scale is equal to a degree on the Celsius scale only it's difference is zero

The Celsius scale of zero (0°C) is the freezing point.

0 K is Absolute Zero.

•°• 0 K = - 273.15° C

0° C = 273.15 K

Furthermore, this is what I would like you to know about this scales;

The Kelvin scale is used for very low or very high temperatures where water is not involved.

Note:

The boiling point of water is 100°C.

I hope this helps you to understand more on this scales. Have a nice studies.

vf=vi+at

20=0+10.t

20=10t

t=2 s

Answer:

Wavelength = 9.68 meters

Explanation:

Given the following data;

Speed = 300,000,000m/s

Frequency = 31 Megahertz to Hertz = 31 * 10⁶ Hz

To find the wavelength;

Wavelength = speed/frequency

Wavelength = 300,000,000/31,000,000

Wavelength = 9.68 meters

Answer:

No

Explanation:

If a car decreases in speed to a stop from an initial speed of 21 m/s in a period of 13 s, the average acceleration is 1.62m/s².

The acceleration of a moving body can be calculated by dividing the change in velocity (∆V) by the time taken. That is;

a = v - u/t

Where;

According to this question, a car decreases in speed to a stop from an initial speed of 21 m/s in a period of 13 s. The average acceleration is as follows:

acceleration = 21 - 0/13

acceleration = 1.62m/s²

Therefore, if a car decreases in speed to a stop from an initial speed of 21 m/s in a period of 13 s, the average acceleration is 1.62m/s².

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Mid-ocean ridges happen along divergent plate boundaries, where new ocean floor is created as the Earth’s tectonic plates spread apart. As the plates separate, molten rock rises to the seafloor, producing large volcanic eruptions of basalt.

Answer:

proton is positively charged changechar

Explanation:

The point through which this ray will pass, after refraction by the lens is point D.

The refraction of light refers to the bending or change in direction that occurs when light passes from one medium to another. It is a phenomenon that happens due to the difference in the speed of light in different substances.

From the ray diagram given, after the light incident from point O, it will pass the converging at point D which is the focal length of the lens after refraction.

Thus, based on the converging lens given in the ray diagram, we can conclude that, the point through which this ray will pass, after refraction by the lens is point D.

So point D is the correct answer.

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Answer:

last answer

Explanation:

gripping it with the blade facing downward is the most efficient and safe way to use an exacto knife

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Jonathan needs to maintain a separation of 0.543 mm between the plates to get the desired charge, and a dielectric constant of 92.6 to achieve a separation of 5 mm with a dielectric.

(a) Using the equation Q = CV, where Q is the charge, C is the capacitance, and V is the voltage, we can solve for the capacitance: C = Q/V =\((8.15 x 10^-9 C) / (50 V) = 1.63 x 10^-10 F.\)

Then, using the formula for capacitance of parallel plate capacitors: C = ε0A/d, where ε0 is the permittivity of free space, A is the area of the plates, and d is the separation distance, we can solve for the separation distance: d =\(_{3}OA/C = (8.85 x 10^-12 F/m) x (0.01 m^2) / (1.63 x 10^-10 F) = 0.543 mm.\)

(b) To find the dielectric constant, we can use the formula for capacitance of a parallel plate capacitor with a dielectric: C = εrε0A/d, where εr is the relative permittivity or dielectric constant of the material. Solving for εr, we get: εr = Cd / ε0A = \((1.63 x 10^-10 F)\) x (0.005 m) / \((8.85 x 10^-12 F/m)\) x \((0.01 m^2)\) = 92.6.

Therefore, Jonathan should use a dielectric with a relative permittivity of 92.6 to achieve a separation of 5 mm.

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Answer:

60

Explanation:

A box has base dimensions of 30 cm x 30 cm and a mass of 3 kg. Calculate to what

depth it sinks when placed in a tank of water (assume the sides are sufficiently high,

so that it floats). Density of water = 1000 kgm-3. Assume g=10 ms-2 for this problem.​

Answer:

2.1m/s towards your grandmother's house

Explanation:

Given parameters:

Time taken  = 204s

Distance  = 430m

Unknown:

Velocity  = ?

Solution:

The velocity is determined by:

    Velocity  = \(\frac{displacement}{time}\)  

   Velocity  = \(\frac{430}{204}\)   = 2.1m/s towards your grandmother's house

Answer:

400 W

Explanation:

Ignoring the efficiency rating for the transformer we have to assume 100% .. Also, the power input to primary is equal to the power output in secondary.

This means that power input = 400 W = power output

Answer: The direct way that children affect their own acculturation is by peer watching and engagement.

Answer:One direct way in which children impact their own acculturation is through language acquisition. Children who are exposed to a new culture and language at a young age have the opportunity to learn and adopt the new language and cultural norms more easily than adults. As children interact with peers and adults in the new culture and use the new language, they develop their own sense of identity and acculturation, which can be different from that of their parents or other family members. Children may also participate in cultural activities or events, such as holidays or festivals, which further shape their understanding and experience of the new culture. Overall, children can actively participate in and shape their own acculturation process through language acquisition and cultural experiences.

Explanation:

The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C

To calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.

However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.

Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.

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Answer:

Below

Explanation:

To find the time it will take for Luis to stop, you can use this formula :

     time = Vfinal - Vinitial / acceleration

     time = 0m/s - 8.5m/s / -2.8 m/s^2

             = -8.5 / -2.8

             = 3.03567 s

Therefore it takes Luis 3.04 seconds to come to a stop. AKA option d)

Hope this helps! Best of luck <3

answer: The pitch of a sound is determined by the frequency of the sound wave. The higher the frequency, the higher the pitch. The amplitude of the wave, which determines its loudness, is not directly related to its pitch.

Therefore, to determine which wave will produce the highest pitch, we need to know the frequencies of the waves, not just their amplitudes (measured in decibels).

Answer:

The earliest known life-forms are putative fossilized microorganisms, found in hydrothermal vent precipitates, that may have lived as early as 4.28 Gya (billion years ago), relatively soon after the oceans formed 4.41 Gya, and not long after the formation of the Earth 4.54 Gya.

Explanation:

Is this what your looking for?

The radioactive decay of the isotope samarium -151 can be modeled by the differential equation dy/dt, The half-life of Sm-151 is approximately 90.02 years.

To find the half-life of Sm-151, we need to solve the given differential equation:

dy/dt = -0.0077y

At time t = 0 (initial time), y = y₀. We want to find the time (t(half)) at which y = y₀ ÷ 2.

Let's set up the equation for half-life:

y(t(half)) = y₀ ÷ 2

dy/dt = -0.0077y

dy/y = -0.0077 dt

∫(1/y) dy = ∫(-0.0077) dt

ln|y| = -0.0077t + C

ln|y₀| = -0.0077(0) + C

ln|y₀| = C

So, the equation becomes:

ln|y| = -0.0077t + ln|y₀|

|y| = exp(-0.0077t + ln|y₀|)

y = exp(-0.0077t + ln|y₀|

y₀/2 = exp(-0.0077t(half) + ln|y₀|)

exp(-0.0077t(half) + ln|y₀|) = y₀/2

ln(exp(-0.0077t(half) + ln|y₀|)) = ln(y₀/2)

(-0.0077t(half) + ln|y₀|) = ln(y₀/2)

-0.0077t(half) = ln(y₀/2) - ln|y₀|

-0.0077t(half) = ln(y₀/2) - ln(y₀)

-0.0077t(half) = ln(1/2)

t(half) = ln(1/2) ÷ -0.0077

t_half = 90.02 years

Therefore, The half-life of Sm-151 is approximately 90.02 years.

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The complete question is:

Half-Life The radioactive decay of Sm-151 (an isotope of samarium) can be modeled by the differential equation dy/dt= −0.0077y, where t is measured in years. Find the half-life of Sm-151.

that the relative placements of the charges as well as their multiples affect a set of ions' potential energy. When the specific charge have the same sign or have equal signs, the energy is positive. Or else, it is negative.

The force acting just on two objects affects the potential energy formula. The formula for gravitational force is P.E. (= mgh, where g seems to be the acceleration caused by gravity (9.8 m/s2 at the earth's surface) while h represents the elevation in metres.

As a result, the system's potential energy equals the sum of a work that was done to set up the entire system of two counts. The potential energy that exists in the combination of two charges in such an external field can be stated as follows: q1V(r1) = q2V(r2) + (q1q2/4or12).

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Answer:

Explanation:

The acceleration of an electron in an electric field is given by the equation:

a = qE/m

where a is the acceleration, q is the charge of the electron, E is the electric field, and m is the mass of the electron.

Given that the acceleration of the electron is 4.3 m/s^2, and the mass of the electron is 9.11 × 10^-31 kg, and the charge of the electron is -1.6 × 10^-19 C, we can solve for the electric field E:

E = ma/q

E = (4.3 m/s^2) × (9.11 × 10^-31 kg) / (-1.6 × 10^-19 C)

E = -2.44 × 10^4 N/C

The negative sign indicates that the direction of the electric field is opposite to the direction of the electron's motion. Therefore, the magnitude of the electric field required to accelerate an electron with an acceleration of 4.3 m/s^2 is 2.44 × 10^4 N/C and the direction is opposite to the direction of motion of the electron.

Answer:

the one with v = 25 m/s

Explanation:

Momentum = m * v

 if they both have the same mass (15000 kg) , then the one with the higher v has more momentum...I think A= 25 m/s

The correct answer is :

In octal,

Decimal         16  17   18  19  20  21  22 23  24  25  26  27  28  29  30 31  32

Octal             20  21  22  23 24  25 26 27  30  31   32  33  34  35  36 37  40

Hexadecimal 10   11   12  13  14   15  16  17   18   19   1A   1A   1C  1D  1E  1F  20

Decimal   8  9  10 11  12 13  14  15  16  17  18  19  20 21  22  23 24 25 26 27 28

Base13     8  9  A  B  C  10  11  12  13   14  15  16  17  18  19   1A  1B  1C 20 21 22

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Answer:

By the principle of corona discharge.

Explanation:

The charge on each ball will decreases over time due to the electrical discharge in air.

According to the principle of corona discharge, when the curvature is small, the discharge of the charge takes placed form the pointed ends.

Answer:

B 1,3, and 4

Explanation:

The drawing of the wave in the slinky shows the node and antinode

in the form of a standing wave pattern.

The speed of the wave pulse through the slinky, v = 18 m/s

The frequency with which the student vibrates the slinky, f = 4.5 Hz

Number of nodes in the slinky, n = 4 nodes

The wavelength of the slinky, λ, is given as follows;

\(\displaystyle \lambda = \mathbf{ \frac{v}{f}}\)

Therefore;

\(\displaystyle \lambda = \frac{18 \, m/s }{4.5 \, Hz} = \mathbf{4.0 \, m}\)

The attached drawing of the situation shows the wavelength of the

wave equal to the distance between three consecutive nodes, N

The number of loops = 3 complete loops + Half of a loop = 3.5 loops

The length of the wavelength, λ = Length of two complete loops

Height of the stairwell = 3.5 loops

2 loops = λ

Therefore;

\(\displaystyle Height \ of \ stairwell = \frac{\lambda}{2 } \times 3.5 = \mathbf{1.75 \cdot \lambda}\)

Which gives;

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