You do 25 J of work in pushing a crate up a ramp. If the output work from the


inclined plane is 10 J, then what is the efficiency of the inclined plane?

Answer:

B

Explanation:

Complete Question

The complete question is shown of the first uploaded image

Answer:

Explanation:

 The  force vector acting upon the particle is \(\vec F\) (The magnitude is F )

  The displacement vector from point B to A is  \(\vec L\) (The magnitude is  L )

Generally workdone is mathematically represented as

     \(W_{BA} = \vec F * \vec L\)

But from the question we are to that vector L has a magnitude L  and  makes and angle \(\theta \ radian\) with the positive x-axis

also  we are told that Force is pointing to the left and is parallel to the horizontal  axis (i.e at angle  \(\pi \ radian\) (180°))

Generally the angle between the \(\vec F \ and \ \vec L\) is  \(\pi - \theta\)

Hence the workdone is mathematically represented as

       \(W_{BA} =F * L cos (\pi - \theta)\)

=>    \(W_{BA} =-F * L cos \theta\)

Here the negative sign shows that the displacement is acting in opposite direction to the direction of the workdone (the force applied )

Answer:

150.6 km

Explanation:

One mile is about 1.61 km so multiply 93.6 by 1.6 which gives you above 150.6

Answer:

Explanation:

From the question

Weight of painter = 500N

Weight of scaffold = x

Weight of painter + weight of scaffold = 2* 400 (since they are supported by two ropes)

Substitute

500 + x = 2(400)

500+x = 800

x =  800-500

x = 300N

Hence the weight of the  scaffold is 300N

Coal is extracted from mountain top by removal of top soil and the use of explosives.

A coal is definitely as the solid substance that is made up of mainly carbon and other constituent elements such as hydrogen, sulfur, oxygen, and nitrogen.

The uses of coal include the following:

To extract coal from the mountain top the following is carried out:

The top soil of the area involved us being removed and

Explosives are then used to expose the underlying coal seams.

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wellll that would be in earth crust

Answer:

in space

Explanation:

its a planet

According to the given statement the number x is 2. The number x represents the dimensions of the term p * a in the given equation.

By comparing the dimensions of both sides of the equation, we find that x is equal to 2.

The equation given is:

Volume per second = k * (p * a) / n

Where:
- k is a constant
- p is the excess pressure (force per unit area)
- a is the radius of the pipe
- n is the frictional quantity of dimension MLT⁻¹


To find the number x, we need to determine the dimensions of each term in the equation.

1. Dimension of Volume per second:

  - Volume has the dimension L³ (length cubed)
  - Time has the dimension T (time)
  - Therefore, Volume per second has the dimension L³  / T

2. Dimension of k:

  - The equation states that k is a constant. Constants are dimensionless.

3. Dimension of p * a:

  - Pressure has the dimension M / (L * T² ) (mass divided by length and time squared)
  - Radius has the dimension L (length)
  - Multiplying pressure by radius results in the dimension M / (L * T² ) * L = M / (L²  * T² )

4. Dimension of n:

  - Given in the question, n has the dimension MLT⁻¹
(mass times length times time to the power of -1)

Now, we can equate the dimensions:

L³  / T = k * (M / (L²  * T² )) * MLT⁻¹


Simplifying the dimensions:

L³  / T = k * M / (L²  * T² ) * MLT⁻¹


L³  / T = k * M / L²  * M / T²  * L^-1 * T⁻¹


L³  / T = k * M²  / L²  * T⁻¹


To equate the dimensions, both sides of the equation must have the same dimensions. Therefore:

L³ / T = k * M² / L² * T⁻¹


Comparing the dimensions on both sides, we can conclude:

L³ / T = k * M² / L²* T⁻¹

The dimensions on the left side are L^3 / T, and the dimensions on the right side are (k * M²) / (L² * T).

Therefore, the number x is 2.

The number x represents the dimensions of the term p * a in the given equation.

By comparing the dimensions of both sides of the equation, we find that x is equal to 2.

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The acceleration is the same, if the initial velocity is the same, the times of going up and down are the same.

If the initial velocity is the same for both processes, the acceleration is the same and the times are the same.

The relationship between the net force, the masses, and the acceleration of the bodies is established by Newton's second law.  

∑ F = m a

In the image of the block moving up and down the ramp in the attached, a free-body can be observed; in this example, the x-axis is parallel to the ramp and the y-axis is perpendicular. The reference system is a coordinate system with respect to which the forces are depicted.

Sinθ =  Wₓ/W

Cosθ =  W_y/W

Wₓ = WSinθ

W_y = Wcosθ  

Newton's second law for each axis.

Case 1. Block slides down on x-axis

Wₓ = ma

mg sinθ = ma

a = g sin θ

Case 2. Block rises

X-axis

- Wₓ = m a

- mgsin θ = a

a = - g sin θ

Acceleration is equal in both cases, if the block has the same initial speed, the rise and fall time is the same.

y = v₀ t - ½ a t²

y = ½ a t²

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Your question is incomplete, most probably the full question is this:

(b) The block takes time tup to slide up the ramp a distance x The block then takes time down to slide back down to the bottom of the ramp, where it has speed up. Is flows greater than equal to

or less tup?

tdown >tup -tdown = tup .tdown In a clear, coherent paragraph-length response that may also contain figures and/or equations, explain your reasoning. If you need to draw anything other than what you have shown in part (a) to

assist in your response, use the space below. Do NOT add anything to the figures in part (a).

300 meters = 0.186411 miles, 65 minutes = 1.08333 hours, 35 yards = 32.004 meters

1. To convert 300 meters to miles, you can use the conversion factor 1 mile = 1609.344 meters. So, 300 meters = 300/1609.344 miles = 0.186411 miles.
2. To convert 65 minutes to hours, you can use the conversion factor 1 hour = 60 minutes. So, 65 minutes = 65/60 hours = 1.08333 hours.
3. To convert 35 yards to meters, you can use the conversion factor 1 yard = 0.9144 meters. So, 35 yards = 35*0.9144 meters = 32.004 meters.
In summary:
300 meters = 0.186411 miles
65 minutes = 1.08333 hours
35 yards = 32.004 meters

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Answer:

the acceleration of the elevator is increasing

Explanation:

For this exercise we propose the solution using Newton's second law

         F -W = m a

         F = m (g + a)

If the net force increases, it implies that the acceleration of the elevator is increasing, since the acceleration of gravity is constant as the ascent is accelerating.

In problem #1, the temperature of a bolt cooling in a room is given by the differential equation T'' = -10/10(T - 23), with an initial condition T(0) = 30. Part (a) asks to use Euler's method with a step size of h = 0.5 to approximate the value of T(3). Part (b) asks to repeat the approximation with a step size of h = 0.2. Problem #2 involves solving the initial value problem analytically.

(a) To approximate T(3) using Euler's method with h = 0.5, we start with the initial condition T(0) = 30 and iteratively calculate the values of T using the formula T(n+1) = T(n) + h * T'(n), where T'(n) is the derivative of T at time n. By performing the calculations for n = 0, 1, 2, and 3, we obtain an approximation for T(3).

(b) Similar to part (a), we use Euler's method with h = 0.2 to approximate T(3). We repeat the iterative process and calculate T(n+1) using the formula T(n+1) = T(n) + h * T'(n) for n = 0, 0.2, 0.4, ..., 3.

Problem #2 asks to solve the initial value problem analytically. This involves finding the general solution to the given differential equation T'' = -10/10(T - 23) and applying the initial condition T(0) = 30. The solution will be a function of t, denoted as T(t), without including T'' in the answer. The exact solution will provide a more precise result compared to the approximations obtained using Euler's method.

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Answer:

The molecules of the soup in the pot move faster than those in the freezer.

Explanation:

The soup in the freezer is closer to being a solid than that in the pot. Therefore, it has more energy which will make the molecules move faster.

Answer:

Could you give information about the lab

Explanation:

Answer:

The spectrum of each astronomical object

Explanation:

I took the test and got it right

The diffraction angle is 20.66 degrees.

To find the answer, we have to know about the Bragg's law.

                         \(2dsin\theta=n \lambda\)

where; d is the separation of the rulings, \(\theta\) is the diffraction angle, n is the order of diffraction and lambda is the wavelength.

                     \(sin\theta=\frac{n\lambda}{2d} =\frac{2*600*10^{-9}}{2*1.7*10^{-6}} \\\\sin\theta=0.352\\\\\theta=sin^{-1}(0.352)=20.66 degree\)

Thus, we can conclude that, the diffraction angle is 20.66 degrees.

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When two astronauts, initially at rest and facing each other in space, push on each other, they will both move away from each other due to Newton's third law of motion and the conservation of momentum.

The given phenomenon can be explained using Newton's third law of motion and the conservation of momentum.

Apply Newton's third law of motion.
Newton's third law of motion states that for every action, there is an equal and opposite reaction. When the astronauts push on each other in space, the force applied by each astronaut on the other is equal in magnitude but opposite in direction.

Apply the conservation of momentum.
In this scenario, the total momentum of the astronauts before they push off each other is zero, as they are initially at rest. After they push off, the total momentum of the system must still be zero to conserve momentum.

Observe the resulting motion.
Due to the conservation of momentum, the astronauts will move away from each other with equal and opposite velocities. This means that their relative speeds and distances traveled will be the same but in opposite directions.

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Answer:

X: convex Y: Concave

Explanation:

Just got it right

The net force on the 1000 N barrel falling in air with an air drag of 400 N is 600 N

Net force is given by the following formula:

Net force = force of pull - opposite force

The following data were obtained from the question:

The net force on the 1000 N barrel falling in air can be obtained as illustrated below:

Net force = Weight of barrel - Force of resistance

Net force = 1000 - 400

Net force = 600 N

Thus, the net force on 1000 N barrel is 600 N

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I think Twelve is the answer

Answer:

A. Water pollution contributes to water scarcity.

Explanation:

Water pollution occurs when materials are disposed in water body, thus making it unfit for use. A polluted water can not be used for various purposes that water can be used for. Examples include: recreation, drinking, washing etc.

Water scarcity is the situation when available water is not sufficient for the use of organisms in a community. This majorly occurs in arid area.

Thus, since a polluted water renders water to be useless, therefore water pollution contributes  to water scarcity.

Answer:

Water contributes to water scarcity

Explanation:

pls nobody has ever given me brainiest pls give me brainliest

To determine the additional torque required to keep the rod from rotating, we need to consider the torques exerted by the forces acting on the rod.

Let's analyze the torques exerted by each force:
Fz = 30 N:
Since the force is acting at a perpendicular distance of 0.2 m from the axis of rotation, the torque exerted by this force is 30 N * 0.2 m = 6 N·m (counterclockwise).
F = 20 N: This force is also acting at a perpendicular distance of 0.2 m from the axis of rotation. The torque exerted by this force is 20 N * 0.2 m = 4 N·m (counterclockwise). F = 20 N: Similar to the previous force, this force is acting at a perpendicular distance of 0.2 m from the axis of rotation. The torque exerted by this force is 20 N * 0.2 m = 4 N·m (counterclockwise).
Fa = 20 N: Again, this force is acting at a perpendicular distance of 0.2 m from the axis of rotation. The torque exerted by this force is 20 N * 0.2 m = 4 N·m (counterclockwise). To keep the rod from rotating, the additional torque applied should balance the sum of the torques exerted by the forces. The sum of the torques exerted by Fz, F, and Fa is (6 N·m + 4 N·m + 4 N·m) = 14 N·m (counterclockwise). Therefore, an additional torque of 14 N·m (counterclockwise) must be applied to keep the rod from rotating. None of the given options accurately describe this additional torque, so none of the options provided are correct.

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By moving an 8-newton weight a distance of 5 meters in 4 seconds. you have generated 10 watts of power.

Power is defined as the rate at which work is done or energy is transferred. In this scenario, you have moved an 8-newton weight a distance of 5 meters in 4 seconds. To calculate the power generated, we can use the formula:

Power = Work / Time

The work done can be calculated using the formula:

Work = Force × Distance

In this case, the force is 8 newtons and the distance is 5 meters. Plugging these values into the formula, we get:

Work = 8 N × 5 m = 40 Joules

Now, we can calculate the power:

Power = Work / Time = 40 J / 4 s = 10 Watts

Therefore, you have generated 10 watts of power by moving the 8-newton weight a distance of 5 meters in 4 seconds.

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The absence of elastic energy in the given example, where a block rolls down an incline and collides with a cart, can be attributed to the nature of the collision and the absence of deformations or elastic materials involved.

Elastic energy is typically associated with objects or systems that can deform and store potential energy in their elastic components, such as springs or elastic materials. In the given scenario, the block and cart do not exhibit elastic behavior, and the collision is assumed to be perfectly inelastic, meaning the objects stick together after the collision without any loss of kinetic energy due to deformation or bouncing.

In a perfectly inelastic collision, the kinetic energy is not stored as elastic potential energy but is instead converted into other forms, such as heat or sound. Since there is no deformation or compression of elastic materials involved, there is no need to consider elastic energy in this particular example. The focus is primarily on the conservation of mechanical energy, where the initial kinetic energy is converted into potential energy as the carts move up the incline.

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Answer:

tbh vector does not have any direction at all the answer is 0

If you pull yourself to the center of the merry-go-round,  the rotation of the merry go round will decrease.

This is the radial acceleration experienced by a person moving in a circular path as the merry-go-round rotates about its mean position.

a = v²/r

where;

From the formula given above, as the radius of the merry go round increases, the centripetal acceleration of the merry go round decreases.

v = ωr

where;

Thus, when the radius of the circular path decreases, the speed of the merry go round will decrease as well.

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For a 3 m long ladder leaning against a frictionless wall, the minimum value of the coefficient of static friction is mathematically given as

mu=0.2886

Generally, the equation for the Force  is mathematically given as\(-\mu N_{1}+N_{2}=0\)

Therefore

\(\mu=\frac{1}{2}tan\theta\)

\(\mu=\frac{1}{2}tan30^{0}\)

mu=0.2886

In conclusion, the minimum value of the coefficient of static friction

mu=0.2886

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Answer:

True

Explanation:

Pre-questioning may help a reader focus on information s/he hopes to find in the reading selection.

Answer:

True!!

Explanation:

I took the practice thing on edge :))

In a circle at constant speed, the work done is zero since the Force is always perpendicular to the distance moved as you move incrementally around the circle.

An object moves in a circle at a consistent speed in a motion known as uniform circular motion. Any point on a propeller, for instance, that is rotating continuously, is moving uniformly in circles. The second, minute, and hour hands on a watch are some further examples. It is amazing that despite the constant rotation rate, points on these revolving objects are actually speeding. We must consider the motion in terms of vectors in order to see this.

A centripetal motion is an Objects having a constant speed have zero acceleration in one-dimensional kinematics. In two- and three-dimensional kinematics, a particle can experience acceleration even if its speed is constant if it follows a curved trajectory, like a circle.

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Answer:

\(v = 14.78m/s\)

Explanation:

Given

\(KE = 150J\)

\(p = 20.3kgm/s\)

Required

Determine the object's speed

Kinetic Energy is calculated as:

\(KE = \frac{1}{2}mv^2\)

Make m the subject

\(m = \frac{2KE}{v^2}\)

Momentum is calculated as:

\(p = mv\)

Make m the subject

\(m = \frac{p}{v}\)

So, we have:

\(m = \frac{p}{v}\) and \(m = \frac{2KE}{v^2}\)

Equate both expressions: \(m = m\)

\(\frac{2KE}{v^2} = \frac{p}{v}\)

Multiply both sides by v

\(v * \frac{2KE}{v^2} = \frac{p}{v}*v\)

\(\frac{2KE}{v} = p\)

Make v the subject

\(v = \frac{2KE}{p}\)

Substitute \(KE = 150J\) and \(p = 20.3kgm/s\)

\(v = \frac{2 * 150}{20.3}\)

\(v = \frac{300}{20.3}\)

\(v = 14.78m/s\)

Answer:

The total normal force acting on the system is approximately 58.8 N

Explanation:

The masses arranged in the stack are;

3 kg, 2 kg, and 1 kg

The mass of the stack system, m = 3 kg + 2 kg + 1 kg = 6 kg

Weight = The force of gravity on an object = m·g

Where;

m = The mass of the object

g = The acceleration due to gravity ≈ 9.8 m/s²

∴ The weight of the stack system, W ≈ 6 kg × 9.8 m/s² ≈ 58.8 N

The direction of the weight force = Perpendicular to the surface (acting downwards)

From Newton's third law of motion, the normal force acts perpendicular to the plane and it is equal in magnitude to the force acting perpendicular to the plane

∴ The magnitude of the total normal force acting on the system = The magnitude of the weight of the system ≈ 58.8 N

The (magnitude of the) total normal force acting on the system ≈ 58.8 N