Answers
Angular speed , wi = 91 rpm
wi = 91 * 2pi/60 rad/s
wi = 9.11 rad/s
Frictional force , f = 0.20 * 16 = 3.2 N
part a) let the angular acceleration is a
Using the second law of motion
0.50 * 85 * 0.31^2 * a = 3.2 * 0.31
solving for a
a = 0.242 rad/s^2
The angular acceleration is 0.242 rad/s^2
b) Let the angle is theta
theta = 9.11^2/(2 * 0.242)
theta = 170 radian = 27.2 turns
The number of turns is 27.2
Angular velocity is the speed of an object in rotational motion. The distance traveled is denoted by θ and is measured in radians. Duration is measured in seconds. Angular velocity is therefore expressed in radians/second, or rad/s. Angular velocity is measured in radians per unit of time because it is the rate at which the central angle swept by an object changes as it moves around a circle.
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Related Questions
How much current is in a circuit with a 1.5 V battery and three
2-ohm resistances (bulbs) in series?
Answers
Answer: 0.25A
Explanation: To calculate the current in the circuit, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R):
I = V / R
In this case, the total resistance of the circuit is the sum of the individual resistances of the three bulbs in series, which gives us:
R = 2 + 2 + 2 = 6 ohms
The voltage of the battery is given as 1.5V.
So, using Ohm's Law, we can calculate the current in the circuit as:
I = V / R = 1.5 / 6 = 0.25 amps
Therefore, the current in the circuit is 0.25 amps.
The current in the circuit is 0.25 A.
Voltage across the circuit, v = 1.5 V
Resistance in each resistors, R = 2Ω
Since, the resistors are connected in series combination, their effective resistance,
R' = 3R
R' = 3 x 2
R' = 6Ω
According to Ohm's law, if the temperature and all other physical factors remain constant, the voltage across a conductor is directly proportional to the current that is flowing through it.
So, according to Ohm's law,
V = IR
Therefore, current flowing through the given circuit,
I = V/R
I = 1.5/6
I = 0.25 A
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For a mass - spring system that undergoes a simple harmonic motion with amplitude A , determine the position x at which the kinetic energy is equal to 3 times the potential energy ( KE = 3 PE ) .
Answers
The elastic potential energy of a spring is given by:
\(PE=\frac{1}{2}kx^2\)Where:
\(\begin{gathered} PE=\text{ potential energy} \\ k=\text{ spring constant} \\ x=\text{ distance of the spring is compressed} \end{gathered}\)Now, the total energy of the spring is given when the value of "x" is equal to the amplitude "A":
\(E_{tot}=\frac{1}{2}kA^2\)The total energy is converted into kinetic energy and elastic energy, therefore, we have:
\(\frac{1}{2}kA^2=\frac{1}{2}kx^2+\frac{1}{2}mv^2\)Since the kinetic energy is twice the potential energy we have:
\(\frac{1}{2}mv^2=2(\frac{1}{2}kx^2)=kx^2\)Now, we substitute the values in the equation:
\(\frac{1}{2}kA^2=\frac{1}{2}kx^2+kx^2\)Now, we can cancel out the spring constant "k":
\(\frac{1}{2}A^2=\frac{1}{2}x^2+x^2\)Now, we add like terms in the right side:
\(\frac{1}{2}A^2=\frac{3}{2}x^2\)Now, we multiply both sides by 2:
\(A^2=3x^2\)Now, we divide both sides by 3:
\(\frac{A^2}{3}=x^2\)Now, we take the square root to both sides:
\(\sqrt{\frac{A^2}{3}}=x\)Solving the operations:
\(\pm0.5A=x\)Therefore, the distance is 0.5A.
In physics, a is a group of related objects that interact with each other and form a complex whole.
Answers
Answer: a system
Explanation: just did the test
Answer:
system is correct
Explanation:
write down the following units in the ascending of their value A) mm nm cm um B) 1m 1cm 1km 1mm. convert the following units into SI without changing their values? A)3500g B)2.5km C)2h
Answers
Answer:
A) nm, um, mm, cm
B) 1mm, 1cm, 1m, 1km
A) 3500g, B) 2500m, C) 7200 seconds
John rolls a bowling ball down the lane with a velocity of 12 m/s. The ball slows down at a constant rate of 0.75 m/s2.
a) If it takes 2.5 seconds to reach the pins, how long is the lane?
b) What is the velocity of the bowling ball just before it hits the pins?
Please help ;-;
Answers
Answer:
b 1.3
Explanation:
The length of the lane is 27.66 m and the velocity of the bowling ball just before it hits the pins is 10.12 m/s.
State the three equations of motion?
The three equations of motion are -
v = u + at
S = ut + 1/2at²
v² - u² = 2aS
Given is a bowling ball that rolls down the lane with a velocity of 12 m/s. After that, the ball slows down at a constant rate of 0.75 m/s².
[u] = 12 m/s
[a] = 0.75 m/s²
Part A
time taken to reach the pins = [t] = 2.5 s
S = ut + 1/2at²
S = 12 x 2.5 + 1/2 x - 0.75 x 2.5 x 2.5
S = 12 x 2.5 - 2.34
S = 30 - 2.34
S = 27.66 m
Part B
Assume that the velocity is v m/s.
v² = u² + 2aS
v² = (12)² - 2 x 0.75 x 27.66
v² = 144 - 41.49
v² = 102.51
v = 10.12 m/s
Therefore, the length of the lane is 27.66 m and the velocity of the bowling ball just before it hits the pins is 10.12 m/s.
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Two arrows are fired horizontally with the same speed of 30.0 m/s. Each arrow has a mass of 0.100 kg. One is fired due east and the other due south. Find the magnitude and direction of the total momentum of this two-arrow system. Specify the direction with respect to due east.
Why do we have to do square root of the Momentum, also at the last to find the direction why we do Tan^-1. Please explain.
Answers
Answer:
P = P1 + P2 where P is a vector quantity
P1 = P2 = .10 kg * 30.0 m/s = 3 kg-m/sec
P = (p1^2 + p2^2)^1/2 add vectors and find magnitude of resultant
p = (3.0^2 + 3.0^2)^1/2 = 4.24 length of resultant vector
Since vectors are at right angles p is the length of the hypotenuse
tan θ = 3.0 / 3.0 = 1 where theta is measured with respect to the positive x-axis and will be below that axis
θ = tan^-1 1 = 45 deg (45 degrees below positive x-axis)
One can find the value of tan θ from the length of the x-y vectors and from tan θ obtain θ
. If two vectors are equal, what can you say about their components?
Answers
Answer:
If two vectors are equal, their components are also equal. For example, vector A and B both share the same x, y, and z components. By having the same components, the magnitude and direction does not change, which attest to how the vectors are identical.
So, if two vectors are equal, their components are also equal.
In vector mathematics, when two vectors are equal, it means their corresponding components are also equal. Thus, the magnitude and direction of the two vectors must be identical.
Explanation:In the world of mathematics, specifically vector mathematics, if two vectors are equal, that means their corresponding components are also equal. A vector is typically described by its individual components which are its magnitude (size) and direction.
For example, if vector A and vector B are equal, and vector A = \((x_1, y_1)\) and vector B = \((x_2, y_2)\), then\(x_1 = x_2\) and \(y_1 = y_2\). This applies to vectors in two-dimensional and three-dimensional spaces as well. Therefore, equality in vectors involves the same direction and magnitude causing the corresponding components to be equal.
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Three tiny charged metal balls are arranged on a straight line. The middle ball is positively charged and the two outside balls are negatively charged. The two outside balls are separated by 20 cm and the middle ball is exactly halfway in between. (HINT: Draw a picture; in your picture, the distance between the two outermost balls should be 20 cm.) The absolute value of the charge on each ball is the same, 1.45 μCoulombs (the meaning of μ, which is read as "micro", is 10-6). Give your answers in newtons.
a) What is the magnitude of the attractive force on either outside ball due ONLY to the positively-charged middle ball?
(b) What is the magnitude of the repulsive force on either outside ball due ONLY to the other outside ball?
(c) What is the magnitude of the net force on the outside of the ball
Answers
Answer:
\((a) 189.23 N\), \((b) 47.31 N\) and \((c) 141.92 N\).
Explanation:
Three balls are shown in figure having charge \(q=1.45 \mu C\). The middle ball, \(B\), is positively charged having charge \(+q\), and the remaining two outside balls, \(A\) and \(C\), are negatively charged having charged \(-q\) as shown.
\(AC=20 cm\) and \(AB=BC=10\) cm as B is the mid-point of AC.
Let \(d_1=AC=20\times 10^{-3}m\) and \(d_2=AB=BC=10\times 10^{-3}m\)
From Coulomb's law, the magnitude of the force, \(F\), between two point charges having magnitudes \(q_1 \& q_2\), separated by distance, \(d\), is
\(F=\frac {1}{4\pi\epsilon_0}\frac {q_1q_2}{d^2}\;\cdots (i)\)
where, \(\epsilon_0\) is the permittivity of free space and
\(\frac {1}{4\pi\epsilon_0}=9\times 10^9\) in SI units.
This force is repulsive for the same nature of charges and attractive for the different nature of charges.
Now, Using equations(i),
(a) The magnitude of attraction force between balls A and B is
\(F_{AB}=F_{BC}= \frac {1}{4\pi\epsilon_0}\frac {qq}{(d_2)^2}\)
\(\Rightarrow F_{AB}= 9\times 10^9}\frac {1.45\times 10^{-6}\times1.45\times 10^{-6}}{\left(10\times 10^{-3}\right)^2}\)
\(\Rightarrow F_{AB}=189.23 N\)
(a) The magnitude of the repulsive force between balls A and C is
\(F_{AC}= \frac {1}{4\pi\epsilon_0}\frac {qq}{(d_1)^2}\)
\(\Rightarrow F_{AC}= 9\times 10^9}\frac {1.45\times 10^{-6}\times1.45\times 10^{-6}}{\left(20\times 10^{-3}\right)^2}\)
\(\Rightarrow F_{AC}=47.31 N\)
(c) The magnitude of the net force, \(F_{net}\), on the outside of the ball is,
\(F_{net}=189.23-47.31 N\)
\(\Rightarrow F_{net}=141.92 N\)
Questions (1 point) What was the evidence that lead to the development of the principle of mass energy equivalence?
Answers
The evidence that lead to the development of the principle of mass energy equivalence are radioactivity, atomic spectra and photoelectric effect.
What is Einstein energy equation?The Einstein energy equation or the mass defect and binding energy are related by Albert Einstein's formula is given as;
E = mc²
where;
m is the mass defectc is the speed of the lightThe evidence that lead to the development of the principle of mass energy equivalence are listed below:
the discovery of radioactivity - this discovery was very important as it helps in the discovery of radioactive particles and nuclear energy.atomic spectraphotoelectric effect - showing the work function of different metal and kinetic energy of emitted electrons.Learn more about mass defect here: https://brainly.com/question/30914903
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A baseball is hit almost straight up into the air with a speed of 22 m/s. Estimate (a) how high it goes, and (b) how long it is in the air. (c) What factors make this an estimate ?
Answers
(a) The ball goes up to the height of 31.89 m. (b) The ball stays for 5.1 s in the air. (c) The acceleration due to gravity and wind resistance can affect the estimation.
What is Acceleration due to gravity?Acceleration owing to gravity is the term used to describe the rate at which a body's velocity changes as a result of the earth's gravitational pull. In general, it is assumed that the acceleration caused by gravity is in the downward direction.
The acceleration caused by gravity has been calculated as, however as it changes from location to location, it may have an impact on the estimation.
You may have thought that the wind has no impact, but it can actually generate drag and even cause the ball to shift course.
Therefore, (a) The ball goes up to the height of 31.89 m. (b) The ball stays for 5.1 s in the air. (c) The acceleration due to gravity and wind resistance can affect the estimation.
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A parallel circuit has four branch currents: 120 mA, 380 mA, 250 mA, and 2.1 A. How much current is supplied by the source?
Answers
A parallel circuit is an electrical circuit with more than one current path and all circuit components are connected between the same two sets of electrically common points. The current supplied by the source in a parallel circuit is equal to the sum of all branch currents in the circuit.
The sum of the branch currents in a parallel circuit can be calculated by adding up the values of the individual branch currents. In this case, we have four branch currents: 120 mA, 380 mA, 250 mA, and 2.1 A. Thus, the sum of the branch currents is:120 mA + 380 mA + 250 mA + 2.1 A= 2.85 ATherefore, the current supplied by the source in this parallel circuit is 2.85 A. This is because, in a parallel circuit, the current from the source is split between the different branches of the circuit. Each branch will have a different current, but the sum of all the branch currents will always equal the current supplied by the sourceFor such more question on parallel circuit
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2) A rolling disk, mass m and radius R, approaches a step of height R/2 with velocity v. (i) Taking the corner of the step as the pivot point, what is the initial angular momentum of the disk
Answers
The rolling disk's initial angular momentum is mR√[2(gR + v²)]/2
Using the law of conservation of energy, the initial mechanical energy E of the disk equals its final mechanical energy E' as it climbs the step.
So, E = E'
1/2Iω + 1/2mv² + mgh = 1/2Iω' + 1/2mv'² + mgh'
where I = rotational inertia of disk = 1/2mR² where m = mass of disk and R = radius of disk, ω = initial angular speed of disk, v = initial velocity of disk, h = initial height of disk = 0 m, ω' = final angular speed of disk = 0 rad/s (assumung it stops at the top of the step), v' = final velocity of disk = 0 m/s (assumung it stops at the top of the step), and h' = final height of disk = R/2.
Substituting the values of the variables into the equation, we have
1/2Iω² + 1/2mv² + mgh = 1/2Iω'² + 1/2mv'² + mgh'
1/2(1/2mR² )ω² + 1/2mv² + mg(0) = 1/2I(0)² + 1/2m(0)² + mgR/2
mR²ω²/4 + 1/2mv² + 0 = 0 + 0 + mgR/2
mR²ω²/4 + 1/2mv² = mgR/2
R²ω²/4 = gR/2 + 1/2v²
R²ω²/4 = (gR + v²)/2
ω² = 2(gR + v²)/R²
ω² = √[2(gR + v²)/R²]
ω = √[2(gR + v²)]/R
Since angular momentum L = Iω, the rolling disk's initial angular momentum is
L = 1/2mR² ×√[2(gR + v²)]/R
L = mR√[2(gR + v²)]/2
the rolling disk's initial angular momentum is mR√[2(gR + v²)]/2
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A thin half ring with a radius of R = 10 cm is uniformly charged with a linear density of = 1 Mikrokulon/m and located in a vacuum. Determine the force F of interaction between the half ring and a point charge q = 20 nC located at the center of curvature. (don't use chatgpt please)
Answers
Answer:
Explanation:
F = k * q * lambda * R * π * (1 - √2/2)
Substituting the given values of q, lambda, R, and k, we get:
F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)
F ≈ 8.58 x 10^-4 N
Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.
11. Approximatrly how many kelvins are equal to 60°F?
a. 439
b. 212
c. 902
d. 289
Answers
Read the text below. Each sentence is about one, two or no energy at all. (5 points) Name the type (s) of energy for each sentence, or leave the space blank (if in the sentence no energy is mentioned). Artan decided to paint the house. He moved the furniture, climbed the stairs, and began work. After two hours he took a break, ate lunch and turned on the radio to listen to some music. When done, turn on a heater to allow the paint to dry as quickly as possible. At dinner everything had ended. a) ............................................................................................................................................ b) ............................................................................................................................................ c) ............................................................................................................................................ d) ............................................................................................................................................ e) ............................................................................................................................................
Answers
What is the magnetic force on a 2.0-m length of (straight) wire carrying a current of 30 A in a region where a uniform magnetic field has a magnitude of 55 mT and is directed at an angle of 20° away from the wire?
Answers
To determine the magnetic force on a straight wire carrying a current in a uniform magnetic field, we can use the formula for the magnetic force:
F = I * L * B * sin(θ)
where:
F is the magnetic force,
I is the current in the wire,
L is the length of the wire,
B is the magnitude of the magnetic field, and
θ is the angle between the wire and the magnetic field.
In this case, the values are:
I = 30 A (current in the wire)
L = 2.0 m (length of the wire)
B = 55 mT = 0.055 T (magnitude of the magnetic field)
θ = 20° (angle between the wire and the magnetic field)
Substituting the values into the formula:
F = 30 A * 2.0 m * 0.055 T * sin(20°)
Calculating sin(20°):
F = 30 A * 2.0 m * 0.055 T * 0.3420
F ≈ 1.5714 N
Therefore, the magnetic force on the 2.0-meter length of wire carrying a current of 30 A in a region with a uniform magnetic field of magnitude 55 mT and at an angle of 20° away from the wire is approximately 1.5714 N.
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A mine of mass 190 kg in a volume of 1.150 m³ is shown in the figure. If the tension in the chain is 5.6×10^3 N. What is the density of the fluid that the mine is in?
Answers
ANSWER
661.61 kg/m³
EXPLANATION
Given:
• The mass of the mine, m = 190 kg
,• The volume of the mine, V = 1.150 m³
,• The tension in the chain, T = 5.6x10³ N = 5600 N
Find:
• The density of the fluid, ρ
Let's draw a free-body diagram of this situation first,
If the forces are in equilibrium,
\(F_b-T-F_g=0\)The buoyant force is given by the equation,
\(F_b=\rho gV\)Where ρ is the density of the fluid, and V is the submerged volume - in this case, the volume of the mine. We know the magnitude of the tension in the chain and the weight of the mine is,
\(F_g=mg\)Replace in the first equation,
\(\rho gV-T-mg=0\)Solving for ρ,
\(\rho=\frac{T+mg}{gV}\)Replace with the known values and use g = 9.81 m/s²,
\(\rho=\frac{5600N+190kg\cdot9.81m/s^2}{9.81m/s^2\cdot1.150m^3}\approx661.61kg/m^3\)Hence, the density of the fluid the mine is in is 661.61 kg/m³.
what is the difference between heat and temperature
Answers
One component of a magnetic has a magnitude of 0.045T and points along the +r axis, while the other component has a magnitude of 0.065T and points along the -y axis. A 1- gram particle carrying a charge of +2.0 ൈ 10-ହC Cis moving along the +Z and at a speed of 4.2 ൈ 10ଷ/. Determine the angle that the net force makes with respect to the +r axis,
Answers
The angle that the net force makes with respect to the x- axis, is determined as 55.3⁰.
Angle of the net force
The angle that the net force makes with respect to the +x axis, is determined as follows;
F = qvBsinθ
with respect to y-axisFy = qv(By)sinθ
with respect to x-axisFx = qv(Bx)sinθ
The angle that the net force makes with respect to the +x axis;
tanθ = Fy/Fx
tanθ = qv(By)sinθ / qv(Bx)sinθ
tanθ = By/Bx
tanθ = 0.065/0.045
tanθ = 1.444
θ = tan⁻¹(1.444)
θ = 55.3⁰
Thus, the angle that the net force makes with respect to the x- axis, is determined as 55.3⁰.
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WHAT IS THE MASS OF A PURE PLATINUM DISK
Answers
The mass of a pure platinum disc can be gotten by multiplying the density with the volume.
Therefore the mass is 2418.2 grams or 2.4182 kilograms.
What is mass?A body's mass is an inherent quality. Prior to the discovery of the atom and particle physics, it was widely considered to be tied to the amount of matter in a physical body.
The kilogram is the primary mass unit in the SI.
The resistance of the body to acceleration in the presence of a net force can be measured as mass.
Due to the lower gravity on the Moon, an object would weigh less than it does on Earth while maintaining the same mass. This is due to the fact that mass, coupled with gravity, determines the strength of weight, which is a force.
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What is the mass of a pure platinum disk with a volume of 113 cm3? The density of platinum is 21.4 g/cm3.
Give your answer in grams and kilograms.
Groups that play a pivotal role in the socialization process are called
A. master statuses.
B. aggregates.
C. secondary groups.
D. primary groups.
Answers
Answer:
Groups that play a pivotal role in the socialization process are called: primary groups.
Which of the following is a mixture?
a air
biron
Chydrogen
d nickel
Answers
Answer:
it will option option A hope it helps
13. The specific heat of zinc is 386 joules per kilogram per Celsius degree. The amount of heat energy required to raisethe temperature of 0.25 kilogram of zinc from 0°C to 28°C is most nearly(a) 1500 J(b) 2700 J(c) 3500 J(d) 4300 J
Answers
Given data
*The specific heat of zinc is c = 386 J/kg
*The given mass of zinc is m = 0.25 kg
*The initial temperature of zinc is t = 0°C
*The final temperature of zinc is T = 28°C
The formula for the amount of heat energy required to raise the temperature of 0.25 kilogram of zinc from 0°C to 28°C is given as
\(Q=mc(T-t)\)Substitute the values in the above expression as
\(\begin{gathered} Q=(0.25)(386)(28-0) \\ =2702\text{ J} \\ =2700\text{ J} \end{gathered}\)Thus, the amount of heat energy required to raise the temperature of 0.25 kilogram of zinc from 0°C to 28°C is Q = 2700 J and the correct answer is (b)
Two friends stand at the top of the White Cliffs of Dover in England. One throws a
stone with a velocity of 11 m/s at an angle of 30° above the horizontal off the cliff
and into the water below. The second drops the stone from rest. Both release the
stones at exactly the same time from a height of 110 m above the water. Assuming
no air resistance, how long after the first splash is the second splash?
F
0.60 s
G
1.1 s
H
3.6 s
J
4.7 s
Answers
The second splash is 1.1 s after the first splash.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction is displacement.
Given parameters:
Initial velocity of the First stone; u₁ = 11 m/s.
Initial velocity of the Second stone; u₂= 0 m/s.
Height of both cases; h = 110 m.
Acceleration due to gravity; g = 9.8 m/s².
So, If time taken by the first stone is t₁; then
h = u₁t₁ + 1/2 * gt₁²
⇒ 110 = 11 t₁ + 1/2*9.8 t₁²
⇒ 4.9 t₁² + 11 t₁ -110 = 0
So, by solving this quadratic equation we get: t₁ =3.73s.
And if time taken by the second stone is t₂; then
h = 1/2*g t₂²
⇒ t₂ = √(2h/g) = √(2×110/9.8) = 4.74 s.
Hence, the second splash happens after first splash by a time = (4.74 - 3.73) s = 1.01 s = 1.1 second ( approx.).
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A projectile is launched over level ground with an initial velocity of 65 m/s at 30° above the horizontal. What is
the projectile's time of flight? (SHOW WORK)
A. 3.6 s
B. 6.6 s
C. 11 s
D. 13 s
Answers
The projectile's time of flight is approximately 6.6 seconds, which is closest to option B.
Projectile Motion: What Is It?An object that is shot into the air and subsequently proceeds along a curved route while being pulled by gravity is said to be in projectile motion. There is no additional propulsion or lift involved. A ball that is tossed, a bullet that is shot from a pistol, or a rocket that is launched into space are examples of things in projectile motion.
We can use the kinematic equations of motion to calculate the projectile's time of flight. The initial velocity can first be divided into its horizontal and vertical components as follows:
\(Vx = V \times cos(\theta)\\= 65 m/s \times cos(30)\\= 56.18 m/s\\Vy = V \times sin(theta)\\= 65 m/s \times sin(30)\\= 32.5 m/s\\\)
where V is the magnitude of the initial velocity, and theta is the launch angle (30 degrees).
The horizontal velocity of the projectile remains constant throughout its flight, while the vertical velocity changes due to the effect of gravity. At the highest point of the trajectory, the vertical velocity becomes zero, and the time it takes to reach this point is equal to half of the time of flight.
The time it takes for the projectile to reach the highest point can be found using the following kinematic equation:
\(V_y = V_oy + a \times t\)
where Voy is the vertical component of the initial velocity (in this case, 32.5 m/s), a is the acceleration due to gravity (-9.81 m/s^2), and t is the time it takes to reach the highest point.
\(0 = 32.5 m/s + (-9.81 m/s^2) \times t\\t = 3.32 s\)
The total time of flight can be found by doubling the time it takes to reach the highest point:
time of flight = 2 × 3.32 s
= 6.64 s
Therefore, the projectile's time of flight is approximately 6.6 seconds, which is closest to option B.
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Find the work done by the gas during the following stages. (a) A gas is expanded from a volume of 1.000 L to 4.000 L at a constant pressure of 2.000 atm. (b) The gas is then cooled at constant volume until the pressure falls to 1.500 atm
Answers
Answer:
a) 607.95 J
b) 0 J
Explanation:
a) Initial volume = 1 L = 0.001 m^3
final volume = 4 L = 0.004 m^3
pressure = 2 atm = 202650 Pa (1 atm = 101325 Pa)
work done by the gas on the environment = PΔV
P is the pressure = 101325 Pa
ΔV is the change in volume from the initial volume to the final volume
ΔV = 0.004 m^3 - 0.001 m^3 = 0.003 m^3
work done by the gas = 202650 x 0.003 = 607.95 J
b) If the gas is cooled at constant volume, then the gas does no work. For a gas to do work, there must be a change in its volume.
Therefore the work done in cooling at constant volume until pressure falls to 1.5 atm = 0 J
What is the biggest agent of erosion?
a tornadoes
b pollution
c gravity
d water
Answers
Answer:
D - Water
Explanation:
D or A
a car with mass m1=1000kg moving at speed v1=6m/s hits a stationary truck with mass m2=5000kg. The impact is absolutely inelastic. Determine the speed of both car and truck immediately after the impact
Answers
Impact Speed means the maximum speed of impact tested upon the bumper of the vehicle pursuant to sections 581.6 and 581.7 of part 581 of title 49 of the Code of Federal Regulations.
In an inelastic collision, what occurs when two objects collide?An inelastic collision occurs when items cling together after impact and kinetic energy is not preserved. Because of this violation of conservation, the forces between colliding objects may convert kinetic energy to other types of energy, such as potential energy or thermal energy.To calculate the momentum of either individual vehicle, divide the total system momentum by two (approx. 11 200 kg*m/s). Once the momentum of the individual automobiles is known, the after-collision velocity may be calculated by simply dividing momentum by mass (v=p/m).To learn more about impact speed to refer:
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Students will design an experiment to determine how the magnitude of the force on a segment of straight, current-carrying wire depends on the length of the wire segment and on the strength of the magnetic field. Which of the following experimental procedures will allow the students to determine both of these relationships? A Making measurements of the force on several different straight segments of wire, increasing the length of the wire and increasing the magnetic field strength with each measurement. B Making measurements of the force on several different straight segments of wire, increasing the length of the wire and decreasing the magnetic field strength with each measurement с Making measurements of the force on several different straight segments of wire, keeping the length of the wire constant while increasing the magnetic field strength with each measurement. D Making measurements of the force on several different straight segments of wire, increasing the length of the wire while keeping the magnetic-field strength the same with each measurement, then repeating the measurements while decreasing the length of the wire and increasing the magnetic field strength with each measurement E Making measurements of the force on several different straight segments of wire, increasing the length of the wire while keeping the magnetic-field strength constant with each measurement, then repeating the measurements while keeping the length of the wire constant while increasing the magnetic field strength with each measurement.
Answers
The experimental procedures that will allow the students to determine both of these relationships is option E:
Making measurements of the force on several different straight segments of wire, increasing the length of the wire while keeping the magnetic-field strength constant with each measurement, then repeating the measurements while keeping the length of the wire constant while increasing the magnetic field strength with each measurement.What happens to the magnetic field when the length of wire increases?The formula F = IL x B calculates the magnetic force acting through a magnetic field on a current-carrying wire. The magnetic field acts on a wire when a current is conducted through it in a direction that is perpendicular to both the magnetic force.
By increasing the amount of current flowing through the wire, the magnetic field's strength can be enhanced. As you get further from the wire, the strength gets weaker. If the amount of current flowing through it stays constant, its length and thickness have no bearing.
Therefore, the length of the wire in the magnetic field has an impact on the magnetic force's strength as well. The force acting on a wire increases with wire length in a magnetic field.
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study of bluefish locomotion found that their tail motion produces an average thrust of 0.65 N . Suppose a 1.7 kg bluefish that is coasting horizontally at 0.45 m/s suddenly begins tail motion.
Answers
Answer:
he fish would travel a horizontal distance of 1.78 meters during the 2 seconds of tail motion
Explanation:
The initial horizontal velocity of the bluefish is 0.45 m/s. When it begins tail motion, it experiences an additional force due to the thrust produced by the tail. The thrust produced by the tail is 0.65 N. We can use Newton's second law to find the acceleration produced by this force:
F = ma
0.65 N = 1.7 kg * a
a = 0.38 m/s^2
This acceleration will cause the velocity of the bluefish to increase over time. The distance the fish travels during this time can be calculated using the kinematic equation:
d = vit + 1/2 at^2
where d is the distance traveled, vi is the initial velocity, a is the acceleration, and t is the time. Since the fish is initially coasting horizontally, its initial vertical velocity is 0 m/s. Therefore, vi = 0.45 m/s. The time interval for which the fish is tail-motoring is not given, so let's assume it is 2 seconds:
d = (0.45 m/s)(2 s) + 1/2 (0.38 m/s^2)(2 s)^2
d = 1.78 meters
Therefore, the fish would travel a horizontal distance of 1.78 meters during the 2 seconds of tail motion.