You have been appointed as a member of the Technology Incorporation Committee (TIC) of your facility? [2 marks] A. What is strategic technology incorporation and what is its goal? B. Outline the typical objectives of strategic technology incorporation. [6 marks) C. What is the primary goal of technology planning? Provide a detailed discussion of the FOUR types of evaluation that should be performed for technology planning [22 marks] selection process D. Technology acquisition can be divided into two subprocesses, selection and procurement Discuss FOUR dimensions that should be considered in the [20 marks] E. What is the goal of technology procurement? The most common method of acquisition is purchasing. Review the common ways of conducting a purchase. [20 marks) F. Discuss the following alternatives to purchasing [5 marks] Lease [5 marks] ii. Rental [5 marks] iii. Consumable-Purchase Agreement [5 marks] iv. Revenue-Sharing Agreement

Answer: Si (Yes)

Explanation:

Answer:

Protozoario o protozoo es un organismo unicelular y eucariota (con núcleo celular definido) perteneciente al Reino protista. Los protozoarios se encuentran junto con los protófitos o algas simples, generalmente acuáticas, dentro del Reino protista o también denominado Reino protoctista.

Explanation:

Answer:

Yes, it was caused by an insider or outsider.

Explanation:

Yes, I believe that this event was caused by an insider or outsider. This is because, if a USB removable flash drive is attached to all the office computers by an insider and now an outsider sends a mail to the company’s General group mail; if the mail has a link that contains some infected worms and virus; once anybody clicks on the link in the mail then, all the computers will be affected by the virus.

Therefore, this event may be caused by the insider who clicked the infected link or by the outsider sent the infected link in the mail.

Answer:

it’s IGS

Explanation:

because i read

Answer:

snap trap baits

Explanation: its kind of obvi, but i took the test and got it right.

Answer:

Engine oil level.

Brake fluid.

Power steering fluid.

Answer:

D. Collects radiation reflected from Earth.

Explanation:

Answer:

Shallow foundations, often called footings, are usually embedded about a metre or so into soil. ... Another common type of shallow foundation is the slab-on-grade foundation where the weight of the structure is transferred to the soil through a concrete slab placed at the surface.

Explanation:

Because I said so.

Distributed systems engineering is a field that deals with the development and design of software systems that operate across multiple computers or devices. As such, there are several key design issues that need to be considered in order to create an efficient, effective, and reliable distributed system.

The six principal design issues that must be addressed in distributed systems engineering are: 1. Scalability: A distributed system must be able to handle an increasing number of users and devices without compromising its performance or reliability. This means that the system must be designed to accommodate a wide range of loads, from light to heavy, and be able to scale up or down as needed. 2. Fault tolerance: Distributed systems are inherently more complex than centralized systems, and therefore more prone to failures. Fault tolerance is the ability of a system to continue operating even in the face of hardware or software failures. 3. Security: Security is a critical concern in distributed systems, as data and applications are spread across multiple devices and networks. Designing a secure system requires careful consideration of access control, encryption, and other security measures.

4. Consistency: Consistency is the ability of a distributed system to provide the same results to all users, regardless of their location or the device they are using. Achieving consistency requires careful management of data replication and synchronization. 5. Performance: A distributed system must be able to provide high performance and low latency, even in the face of heavy loads and network congestion. This requires careful tuning of network protocols and optimization of application code. 6. Interoperability: A distributed system must be able to interoperate with other systems and devices, regardless of the platform or technology used. Achieving interoperability requires careful consideration of standardization and communication protocols. In conclusion, designing an efficient and effective distributed system requires careful consideration of the six principal design issues discussed above. Addressing these issues during the design phase can help ensure that the system is reliable, scalable, secure, consistent, high-performing, and interoperable.

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Answer:

Explanation:

The thermal resistance (R) of a layer of thickness d given in °C·m²·h/kJ is ...

  R = d/k

so the thermal resistances of the layers of furnace wall are ...

  R₁ = 0.200/4 = 0.05 °C·m²·h/kJ

  R₂ = 0.120 2.8 = 3/70 °C·m²·h/kJ

  R₃ = 0.05/0.25 = 0.2 °C·m²·h/kJ

  R₄ = 0.003/240 = 1.25×10⁻⁵ °C·m²·h/kJ

So, the total thermal resistance is ...

  R₁ +R₂ +R₃ +R₄ = R ≈ 0.29286 °C·m²·h/kJ

__

The rate of heat loss is ΔT/R = (1450 -90)/0.29286 = 4643.70 kJ/(m²·h)

__

The temperature drops across the various layers will be found by multiplying this heat rate by the thermal resistance for the layer:

  fire brick: (4543.79 kJ/(m²·h))(0.05 °C·m²·h/kJ) = 232 °C

so, the fire brick interface temperature at the common brick is ...

  1450 -232 = 1218 °C

For the next layers, the interface temperatures are ...

  common brick to magnesia = 1218 °C - (3/70)(4643.7) = 1019 °C

  magnesia to steel = 1019 °C -0.2(4643.7) = 90.06 °C

_____

Comment on temperatures

Most temperatures are rounded to the nearest degree. We wanted to show the small temperature drop across the steel plate, so we showed the inside boundary temperature to enough digits to give the idea of the magnitude of that.

a. To estimate the carbon content of the steel, we need to consider the carbon content of pearlite and ferrite. Pearlite typically has a carbon content of around 0.76% while ferrite has a very low carbon content, close to 0%.

Using these values and the proportions of pearlite and ferrite in the microstructure, we can calculate the estimated carbon content:

Carbon Content = (%Pearlite * Carbon Content of Pearlite) + (%Ferrite * Carbon Content of Ferrite)

             = (0.4 * 0.76) + (0.6 * 0)

             = 0.304

Therefore, the estimated carbon content of the steel is approximately 0.304 (or 0.30%).

b. If the steel is heated to 730 degrees C and held there for a long period of time, it would reach the eutectoid temperature. At this temperature, the microstructure that would be obtained is known as spheroidite. Spheroidite is a fine dispersion of cementite particles within a ferrite matrix. It forms when pearlite is heated above the eutectoid temperature and held for a sufficient time.

c. If the steel is heated to 850 degrees C, it would be above the critical temperature known as the austenitizing temperature. At this temperature, the steel would transform completely into the austenite phase. Austenite is a solid solution of carbon in iron with a face-centered cubic (FCC) crystal structure. It is non-magnetic and can dissolve a significant amount of carbon. Therefore, the equilibrium microstructure at 850 degrees C would be austenite.

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Answer:

b. American Society of Mechanical Engineers

Explanation:

The "American Society of Mechanical Engineers" (ASME) is an organization that ensures the development of engineering fields. It is an accreditation organization that ensures parties will comply to the ASME Boiler and Pressure Vessel Code or BPVC.

The BPVC is a standard being followed by ASME in order to regulate the different pressure vessels and valves. Such standard prevents boiler explosion incidents.

Answer:

speed(0)

square_length = int(input("What is the length of the square?"))

def draw_square():

   pendown()

   for i in range(4):

       forward(square_length)

       left(90)

   penup()

penup()

setposition(-200, -200)

draw_square()

penup()

setposition(-200, 200 - square_length)

draw_square()

penup()

setposition(200 - square_length, 200 - square_length)

draw_square()

penup()

setposition(200 - square_length, -200)

draw_square()Explanation:

The entity declaration includes the name of the entity and a set of port declaration. So declaration that includes the name of ports and direction of flow through the ports by (in, out or inout).

A "black box" is an apparatus, system, or piece of equipment used in research, computer, or engineering that generates meaningful data while concealing any details of its internal operations. Its conclusions' justifications are still "black," or ambiguous. Unable to be understood internally, a black box system can only be understood in terms of its inputs and outputs.

With the traditional "black box test," approach only the stimulus/response behavior will be taken into account when analyzing an open system in order to infer the (unknown) box. In the given diagram, there are no outs for ports B as all are written in before std-logic. Meanwhile, in port a, the same goes but there are 5 inputs and 3 outputs. Not 6 as bun_b_bun_c is treated as one input, not two. The black-box diagrams that are defined by the following vhdl entity are attached below:

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A Use-Case Diagram (UCD)refers to all the possible interactions that a person or one system can possibly have with another system, represented in a graphical format.

There are four main constituents of a use-case diagram. They are:

UCDs are used to

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Horizontal components of reaction at A is 0 N

Vertical components of reaction at A is 3200 N

Reaction at B on the beam is 900 N.m

Lets solve the question in detail.

The horizontal and vertical components of reaction at A, as well as the magnitude of the reaction at B on the beam, can be determined with the given information. Let's start by calculating the reaction at point A:

The horizontal reaction at A = F1cos(90°) = 1200cos(90°) = 0 N
The vertical reaction at A = F1sin(90°) + F2sin(0°) = 1200sin(90°) + 2000sin(0°) = 3200 N

Now, let's calculate the reaction at B:
Reaction at B = F1sin(90°) + F2sin(90°) = 1200sin(90°) + 2000sin(90°) = 3200 N
Magnitude of the reaction at B = √[(1200sin(90°))2 + (2000sin(90°))2] = √[(1200)2 + (2000)2] = 900 N.m

Therefore, the horizontal components of reaction at A is 0 N, the vertical components of reaction at A is 3200 N, and the reaction at B on the beam is 900 N.m.

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A type of heating and air conditioning system that relies only on heated or cooled water to adjust the air temperature is known as a hydronic system.

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Answer:

b

Explanation:

The amplitude of the sinusoid is 28384 *x soít cos.

Amplitude is defined as the greatest deviation from equilibrium of a point on a vibrating body or wave in terms of displacement or distance traveled. In most cases, amplitude is calculated by looking at a wave graph and determining the height of the wave from rest. The strength or intensity of the wave is gauged by its amplitude.

Sinusoid is defined as a signal with sine wave characteristics. In the liver, spleen, and bone marrow, sinusoids and irregular tubules transport blood in place of venules and capillaries. The sine or cosine functions from trigonometry form the foundation of sinusoidal signals, which are periodic functions.

Thus the amplitude of the sinusoid is 28384 *x soít cos.

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The statement "Russian architecture emphasized the rectangle; Inca architecture emphasized the sphere" best describes the differences between architectural developments in Russian and Inca culture.

Russian architecture spans many styles and eras, including Byzantine, Baroque, Neoclassical, and Modernist.

Traditional Russian architecture frequently features wood and brightly coloured decorations, whereas more formal styles such as Baroque and neoclassical favour stone and stucco facades.

Russian architecture has also historically placed great importance on the use of symmetry and geometric shapes, particularly the rectangle.

Thus, the phrase "Russian architecture emphasised the rectangle; Inca architecture emphasised the sphere" best describes the differences in architectural developments in Russian and Inca cultures.

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Answer:

Following are the solution to this question:

Explanation:

In point a:

This takes me six weeks for both the took ideas that I was searching for but it continued for 3 years (12 weeks) as it's an intern.  

In point b:

Finding job:

\(\to f = \frac{1}{6} = 0.166\) jobs weekly  

Separation of jobs:

\(\to \frac{ 1}{12}=0.083\) employment per week.  

In point c:

Its natural rate of unemployment is:  \(\frac{U}{L} = s+(s \times f)\).  

The normal level of employment for that community I represent, once we add up from that preceding section, is as follows:

\(\to \frac{U}{L} = 0.083+ (0.083\times 0.166) = 0.096\)

If on average, it requires six weeks to find another job or the work lasted 12 weeks, the group's unemployment level is \(0.096 \ \%\).

Electrotechnology is important to aerospace engineering for what key reason is option B. Spacecrafts need advanced electrical systems.

Electrotechnology plays a critical role in aerospace engineering because spacecrafts need advanced electrical systems to function.

These systems are responsible for powering and controlling various subsystems on the spacecraft, such as the propulsion system, the communication system, and the environmental control system.

Therefore, Electrotechnology is used to design and build these systems, as well as to troubleshoot and maintain them. It involves the use of electricity, electronics, and electromechanical systems to control and manipulate the flow of electrical energy.

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Answer:

STEP1 Cut to Rough Length

STEP2 Cut to Rough Width

STEP 3 Face-Jointing

HOPE THAT HELPSSS!!!

Positive correlations of handle steeper incline of bicycle is a. Light weight frame.

A positive relationship implies that as one variable increments, the other variable moreover increments. Within the setting of cycling, handle steepness can influence the rider's pose and consolation level, which in turn can impact components such as speed, continuance , and generally performance.

Hence, Components which will influence the relationship between handle steepness and cycling execution might incorporate the rider's wellness level, the landscape being ridden on, the sort and quality of the bike components, and other person inclinations or variables.

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Answer:

a. 6.48 kW b. 1678.34 kg c. 777.92 W d. 201.42 kg

Explanation:

(a) the rate of heat transfer to the iced water in the tank

The rate of heat transfer to the outer surface of the spherical tank is P = P₁ + P₂ where P₁ = rate of heat transfer to the outer surface by radiation and P₂ = rate of heat transfer to the outer surface by convection through air

P₁ = εσAT⁴ where ε = emissivity of outer surface ε= 1, σ = Stefan-Boltzmann constant = 5.67 × 10⁻⁸ W/m-K⁴, A = area of outer surface of spherical tank = 4πR² where R = outer radius of spherical tank = inner radius + thickness = inner diameter/2 + 5 cm = 2 m/2 + 0.05 m = 1 m + 0.05 m = 1.05 m and T = temperature of surroundings = 20 °C = 273 + 20 = 293 K.

P₁ = εσAT⁴

P₁ = 1 × 5.67 × 10⁻⁸ W/m-K⁴ × 4π(1.05 m)² × (293 K)⁴

P₁ = 1 × 5.67 × 10⁻⁸ W/m-K⁴ × 4π(1.1025 m²) × 7370050801 K⁴

P₁ = 184285909263.7647π × 10⁻⁸ W

P₁ = 578951258703.16 × 10⁻⁸ W

P₁ = 5789.51 W

P₂ = hA(T - T₁) where h = coefficient of thermal convection of air = 2.5 W/m²-K, A = outer surface area of spherical tank = 4πR², T = temperature of surroundings = 20 °C = 273 + 20 = 293 K and T₁ = temperature of outer surface of spherical tank = 0 °C = 273 + 0 = 273 K.  

P₂ = hA(T - T₁)

P₂ = 2.5 W/m²-K × 4π(1.05 m)² × (293 K - 273 K)

P₂ = 2.5 W/m²-K × 4π(1.1025 m²) × 20 K

P₂ = 220.5π W

P₂ = 692.72 W

So, P = P₁ + P₂ = 5789.51 W + 692.72 W = 6482.23 W

Since we are neglecting the thermal resistance of the spherical tank, the rate of heat absorption of the outer surface equals the rate of heat absorption in the inner surface. The rate of heat absorption at the inner surface equals the rate of heat transfer to the iced water.

So, rate of heat transfer to the iced water = P = 6482.23 W = 6.48223 kW 6.48 kW

(b) the amount of ice at 0°C that melts during a 24-h period. The heat of fusion of water is 333.7 kJ/kg.

Since the amount of heat, Q = Pt where P = heat transfer rate to iced water = 6482.23 W and t = time = 24 h = 24 h × 60 min/h × 60 s/min = 86400 s.

Also, Q = the latent heat required to melt the ice at 0 °C = mL where m = mass of ice melted and L = latent heat of fusion of ice = 333.7 kJ/kg

So, Pt = mL

m = Pt/L

= 6482.23 W × 86400 s/333.7 × 10³ J/kg

= 560064672/333.7 × 10³

= 1678.34 kg

(c) the rate of heat transfer to the iced water in the tank for this double-walled tank configuration

Since P is the rate of heat transfer to the outer surface, this is also the rate of heat transfer to the outer 0.5 cm thick wall = P₃ = 6482.23 W

P₃ = kA(T - T₃)/d where k = thermal conductivity of outer wall = 15 W/m²-K

A = surface area of outer wall = 4πR'² where R' = radius of outer wall = radius of inner wall + thickness of inner wall + thickness of vacuum + thickness of outer wall = 2.0 m/2 + 0.5 cm + 1.5 cm + 0.5 cm = 1 m + 2.5 cm = 1 m + 0.025 m = 1.025 m, T = temperature of surroundings = 20 °C = 273 + 20 = 293 K, T₃ = temperature of inner surface of outer wall of spherical tank and d = thickness of outer surface of tank = 0.5 cm = 0.05 m

P₃ = kA(T - T₃)/d

making T₃ subject of the formula, we have

P₃d = kA(T - T₃)

P₃d/kA = (T - T₃)

T₃ = T - P₃d/kA

substituting the values of the variables into the equation, we have

T₃ = 293 K - 6482.23 W × 0.05 m/[15 W/m-K × 4π(1.025 m)²]

T₃ = 293 K - 324.1115 Wm/[15 W/m-K × 4π(1.050625 m²)]

T₃ = 293 K - 324.1115 Wm/[63.0375π W/m-K)]

T₃ = 293 K - 324.1115 Wm/[198.0381 W/m-K)]

T₃ = 293 K - 1.64 K

T₃ = 291.36 K

Since the 1.5 cm thick air space is evacuated, all the heat gets to the inner 0.5 cm thick wall by radiation.

So P = εσAT₃⁴

P₄ = εσAT₃⁴ where ε = emissivity of outer surface ε = 0.15, σ = Stefan-Boltzmann constant = 5.67 × 10⁻⁸ W/m-K⁴, A = area of inner surface of outer wall of spherical tank = 4πR"² where R" = outer radius of inner thick wall of spherical tank = inner radius + thickness of inner wall = inner diameter/2 + 0.5 cm = 2 m/2 + 0.005 m = 1 m + 0.005 m = 1.005 m and T = temperature of outer wall = 291.36 K.

P₄ = 0.15 × 5.67 × 10⁻⁸ W/m-K⁴ × 4π(1.005 m)² × (291.36 K)⁴

P₄ = 0.15 × 5.67 × 10⁻⁸ W/m-K⁴ × 4π(1.010025 m²) × 7206422389.51 K⁴

P₄ = 24762024365.028π × 10⁻⁸ W

P₄ = 77792193833.18 × 10⁻⁸ W

P₄ = 777.92 W

Now P₄ is the heat transfer rate to the inner surface which is at temperature T₄

Since T₄ = 0 °C, P₄ is the rate of heat transfer to the iced water

So, rate of heat transfer to the iced water P₄ = 777.92 W

(d) the amount of ice at 0°C that melts during a 24-h period for this double-walled tank configuration

Since the amount of heat, Q = P₄t where P₄ = heat transfer rate to iced water = 777.92 W and t = time = 24 h = 24 h × 60 min/h × 60 s/min = 86400 s.

Also, Q = the latent heat required to melt the ice at 0 °C = mL where m = mass of ice melted and L = latent heat of fusion of ice = 333.7 kJ/kg

So, P₄t = mL

m = P₄t/L

= 777.92 W × 86400 s/333.7 × 10³ J/kg

= 67212288/333.7 × 10³

= 201.42 kg

In computer science, the recurrence relation is used to calculate the time complexity of a recursive function. Here, we are to write a recurrence relation for the running time of the recursive version of Insertion sort.

Insertion sort can be expressed as a recursive procedure as follows:In order to sort A[1…n], we recursively sort A[1…n−1] and then insert A[n] into the sorted array A[n−1].Algorithm to insert A[n] into the sorted array A[1..n-1]:1. Recursive call to sort A[1..n-1].2. Put the last element in the correct position by shifting the array. Let's denote the time taken by the function as T(n).The worst-case scenario happens when the input array is sorted in decreasing order. In this case, each time we enter the loop and slide an element to the right, we must compare it to each element in the sorted sub-array. Therefore, the time complexity of the insertion sort algorithm in the worst-case is O(n2). The recurrence relation for the running time of the recursive version of insertion sort is given by:T(n) = T(n-1) + nwhere n is the input size, T(n-1) represents the time taken by the function to sort n-1 elements, and n is the time taken to sort n elements.The base case for this recurrence is when there is only one element, i.e., T(1) = 1.The time complexity of insertion sort can be determined using the recurrence relation. So, T(n) is given by:T(n) = T(n-1) + n= T(n-2) + (n-1) + n= T(n-3) + (n-2) + (n-1) + n= ........= T(1) + 2 + 3 + ... + (n-1) + n= n(n+1)/2= O(n2)In conclusion, we can say that the time complexity of the recursive version of insertion sort is O(n2).

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The kind of attack that the PDC Bank application is subjected to due to compromised data is: Adversarial artificial intelligence

Adversarial artificial intelligence is a form of attack on a neural network where a wrong algorithm is entered into the system to deceive the end user.

The aim of this machine learning method is to deceive the end user.

This is what happens to the PDC Bank when its data was compromised in the course of improving the machine learning accuracy.

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Answer: B the first person to propose the heliocentric model of the solar system was Nicolaus Copernicus

Explanation:

The stress at elastic limit is 1.27 N/mm^2, the Young's modulus is 254 N/mm^2, the percentage elongation is 57.5%, the percentage reduction in area is 97.44%, and the ultimate tensile stress is 696.67 N/mm^2.

Stress = Force / Area

Young's modulus = Stress / Strain

Percentage elongation = (extension / gauge length) x 100%

Percentage reduction in area = [(original area - area at neck) / original area] x 100%

Ultimate tensile stress = Maximum load / Area

Diameter of specimen = 100 mm

Gauge length = 100 mm

Extension at 70 KN load = 0.50 mm

Load at elastic limit = 10 KN

Maximum load = 140 KN

Total extension at fracture = 58 mm

Diameter at neck = 16 mm

We can calculate the area of the specimen as follows:

Area = π/4 x d^2

Area = π/4 x (100 mm)^2

Area = 7853.98 mm^2

The stress at elastic limit can be calculated as:

Stress = Load / Area

Stress = 10 KN / 7853.98 mm^2

Stress = 1.27 N/mm^2

The Young's modulus can be calculated as:

Strain = Extension / Gauge length

Strain = 0.50 mm / 100 mm

Strain = 0.005

Stress = Load / Area

Load = Stress x Area

Load = 1.27 N/mm^2 x 7853.98 mm^2

Load = 9982.16 N

Young's modulus = Stress / Strain

Young's modulus = 1.27 N/mm^2 / 0.005

Young's modulus = 254 N/mm^2

The percentage elongation can be calculated as:

Percentage elongation = (extension / gauge length) x 100%

Percentage elongation = (58 mm - 0.50 mm) / 100 mm x 100%

Percentage elongation = 57.5%

The percentage reduction in area can be calculated as:

Original area = π/4 x (100 mm)^2 = 7853.98 mm^2

Area at neck = π/4 x (16 mm)^2 = 201.06 mm^2

Percentage reduction in area = [(original area - area at neck) / original area] x 100%

Percentage reduction in area = [(7853.98 mm^2 - 201.06 mm^2) / 7853.98 mm^2] x 100%

Percentage reduction in area = 97.44%

The ultimate tensile stress can be calculated as:

Area at neck = π/4 x (16 mm)^2 = 201.06 mm^2

Ultimate tensile stress = Maximum load / Area

Ultimate tensile stress = 140 KN / 201.06 mm^2

Ultimate tensile stress = 696.67 N/mm^2

Therefore, the stress at elastic limit is 1.27 N/mm^2, the Young's modulus is 254 N/mm^2, the percentage elongation is 57.5%, the percentage reduction in area is 97.44%, and the ultimate tensile stress is 696.67 N/mm^2.

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Creating a truth table or mathematical equation for a circuit that is designed to harm or destroy any location, including New Jersey or any other place, is against ethical and moral guidelines.

It is not appropriate to engage in discussions or provide guidance on activities that involve illegal, harmful, or unethical behavior. If you encounter any situation that may pose a threat to individuals, communities, or the environment, it is important to report it to the appropriate authorities immediately.

So, if you have a legitimate and legal question related to circuit design or any other appropriate topic, Please refrain from requesting guidance or information on any illegal or harmful activities.

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a. calculations / markings. An essential component of the electrical profession is the manufacture of conduits. When done well, it can resemble a piece of art.

When carried out improperly, it may be against construction codes, result in equipment failures, and endanger the integrity of the entire electrical system. A conduit installed incorrectly may potentially prevent the passage of wire, rendering the entire system unusable.

All sizes and varieties of electrical conduits must be installed correctly and effectively, and this expectation extends to our apprentices and journeymen. Conduits can be bent using a wide variety of methods and equipment.

Both in the classroom and on the job, our apprentices receive training. We invest a lot of time learning and perfecting the skill of conduit manufacture and installation in order to prepare our apprentices.

To ensure that our employees are the best in the business, we have spent tens of thousands of dollars on the newest tools and equipment.

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all conduit fabrication jobs begin with accurate measurements, ? , and ? . select one: a. calculations / markings b. calculations / proper bending tools c. investigation / material estimate d. markings / proper bending tools. explain.

what is you're question :)

Answer:

Explanation:

what is the question