You have four objects at rest, each of the same volume. Object A is partially submerged, and objects B, C, and D are totally submerged in the same container of liquid, as shown in Figure P10.60. Draw a force diagram for each object. Rank the densities of the objects from least to greatest and indicate whether any objects have the tame density

Answers

Answer 1

The force diagram for the give question has been attached below, describing the forces that they experience.

What is a force diagram?

A force diagram, also known as a free-body diagram, is a graphical representation of all the forces acting on an object. It is a visual tool used to analyze the motion of an object and predict how it will behave under different conditions.

In a force diagram, the object of interest is represented by a dot or a box, and all the forces acting on it are represented by arrows. The direction of each arrow indicates the direction of the force, while the length of the arrow represents the magnitude of the force. The forces are labeled with their names, such as gravitational force, normal force, frictional force, or tension force. When an object is submerged in a fluid, it experiences two types of forces: gravity and buoyancy. Gravity acts downwards and is proportional to the object's mass, while buoyancy acts upwards and is proportional to the fluid's density and the volume of fluid displaced by the object (also known as the object's displaced volume). The net force on the object is the difference between the upward buoyancy force and the downward gravitational force.

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You Have Four Objects At Rest, Each Of The Same Volume. Object A Is Partially Submerged, And Objects

Related Questions

7. Sally's mass on Earth is 50 kg. What is her weight on the moon?
The acceleration due to gravity she experiences on the moon is 1.652
a. 490 N
b. 8.3 kg
c. 50 kg
d. 82.6 N

7. Sally's mass on Earth is 50 kg. What is her weight on the moon?The acceleration due to gravity she

Answers

Answer:

82.6

Explanation:

Find the vector v with the given magnitude and the same direction as u. magnitude direction v = 6 u = 1, 1

Answers

The vector v with a magnitude of 6 and the same direction as u = [1, 1] is v = [6, 6].

The given vector u = [1, 1] has a magnitude of √(1² + 1²) = √2. To find a vector v with a magnitude of 6 and the same direction as u, we need to scale up the vector u by a factor of 6/√2.

The unit vector in the same direction as u is u/|u| = [1/√2, 1/√2]. To obtain v, we multiply this unit vector by the desired magnitude of 6, resulting in v = 6 × [1/√2, 1/√2] = [6/√2, 6/√2] = [3√2, 3√2]. Therefore, the vector v with a magnitude of 6 and the same direction as u is v = [3√2, 3√2], which can be simplified as v = [6, 6].

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The vector v with a magnitude of 6 and the same direction as u = [1, 1] is v = [6, 6].

The given vector u = [1, 1] has a magnitude of √(1² + 1²) = √2. To find a vector v with a magnitude of 6 and the same direction as u, we need to scale up the vector u by a factor of 6/√2.

The unit vector in the same direction as u is u/|u| = [1/√2, 1/√2]. To obtain v, we multiply this unit vector by the desired magnitude of 6, resulting in v = 6 × [1/√2, 1/√2] = [6/√2, 6/√2] = [3√2, 3√2]. Therefore, the vector v with a magnitude of 6 and the same direction as u is v = [3√2, 3√2], which can be simplified as v = [6, 6].

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I need help with this question someone

I need help with this question someone

Answers

The properties of group 18 elements, also referred to as noble gases or group 8 elements.

Eight valence electrons make them up.

They have enough electrons in their octet, therefore they don't need any more (stable).

are steady

Noble gases are those that are not reactive.

Why do elements desire to create ions?

In order to gain or lose valence electrons to the element they interact with, elements create ions. They acquire a whole octet as a result. You might be wondering what a whole octet is. When an element contains all 8 valence electrons and is stable, it is said to have an octet, rendering it nonreactive.

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A point particle that has charge +q and unknown mass m is released from rest in a
region that has a uniform electric fieldthat is directed vertically downward. The
particle hits the ground at a speed, where h is the initial height of the
particle. Find m in terms of E, q, and h.

Answers

The mass of the particle in terms of E, q, and h is m = h/(qE).

When a charged particle is released in a uniform electric field, it will experience a constant force given by:

F = qE

where F is the force acting on the particle, q is its charge, and E is the electric field strength.

Since the particle is initially at rest, its initial kinetic energy is zero.

Therefore, all of the potential energy of the particle at height h will be converted into kinetic energy when it reaches the ground.

The potential energy of the particle at height h is given by:

U = qEh

where U is the potential energy, q is the charge of the particle, E is the electric field strength, and h is the initial height of the particle.

When the particle hits the ground, its final kinetic energy is given by:

\(K = (1/2)mv2\)

where K is the kinetic energy, m is the mass of the particle, and v is the final velocity of the particle.

Since energy is conserved, the potential energy at height h is equal to the kinetic energy at the ground:

\(qEh = (1/2)mv2\)

Solving for m, we get:

\(m = 2qEh/v2\)

To find the final velocity v, we can use the kinetic equation:

v2 = u2 + 2as

where u is the initial velocity (which is zero in this case), a is the acceleration due to the electric field, and s is the distance travelled (which is equal to the initial height h).

The acceleration due to the electric field is given by:

\(a = F/m = qE/m\)

Substituting for a and s, we get:

v2 = 0 + 2(qE/m)h

Solving for v, we get:

v = sqrt(2qh/m)

Substituting this value of v in the expression for m, we get:

m = 2qEh/(2qh/m)

Simplifying, we get:

\(m = qEh/(q^2E^2)\)

m = h/(qE)

Therefore, the mass of the particle in terms of E, q, and h is m = h/(qE).

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The density of water is 1g/cm³ . If an object with a mass of 100g has a weight of 1 N on Earth, calculate the volume of water displaced by the object​

Answers

If an object with a mass of 100g has a weight of 1 N on Earth, the volume of water displaced by the object​ is 100 cm³.

To find the volume of water displaced by the object, take the formula:

Volume = Mass ÷ Density

According to question:

Mass of the object = 100g

Density of water = 1g/cm³

Change the mass to kilograms:

Mass = 100g ÷ 1000 = 0.1kg

By using the formula, it is possible to find the volume of water displaced:

Volume = 0.1kg / 1g/cm³

= 0.1kg / 1g/cm³ × 1000g/1kg × 1cm³/1g

= 0.1 × 1000 cm³

= 100 cm³

Thus, the volume of water displaced by the object​ is 100 cm³.

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A model rocket accelerates at 15.3 m/s2 with a force of 44 N.

Calculate the mass of the rocket. Round your answer to the nearest tenth of a kg.

The mass of the rocket is
kg.

Answers

Answer:

The answer is 2.88 kg

Explanation:

The mass of the object can be found by using the formula

\(m = \frac{f}{a} \\ \)

f is the force

a is the acceleration

From the question we have

\(m = \frac{44}{15.3} \\ = 2.875816...\)

We have the final answer as

2.88 kg

Hope this helps you

Answer:

2.9

Explanation:

In the equation you get 2.88 but you round that to the nearest tenth so you get 2.9

1. How much heat energy ( Q ) is required to heat 2.0 kg of copper from 30.0 oC to 80.0 oC?

Answers

Answer:

38500

Explanation:

I looked it up so it may be wrong

Use coefficients to balance the following equation: (if no coefficient is needed, use "1", do not leave
any box blank!)

Use coefficients to balance the following equation: (if no coefficient is needed, use "1", do not leaveany

Answers

Answer:

P₄ + 3O₂ → 2P₂O₃

Explanation:

To balance an equation we take each element one by one on each side and balance their atoms.

Like P₄ (Tetraphosphorus) in the left side has 4 atoms of phosphorus.

While on the right side P₂O₃ (Diphosphorus Trioxide) has 2 Phosphorus atoms.

So place 2 as a coefficient in front of P₂O₃.

Now Phosphorus atoms (4 atoms) are balanced on each side.

Now number of Oxygen atoms in P₂O₃ = 2 × 3 = 6

On the left left side number of Oxygen atoms in O₂ = 2

To balance Oxygen atoms in each side, place 3 as a coefficient before O₂ on the left.

Therefore, balance equation will be,

P₄ + 3O₂ → 2P₂O₃

A baseball has 5.8kg*m/s momentum before being hit by the bat. After being hit it has 6.79 kg*m/s in the opposite direction. What is the magnitude of the impulse applied to the baseball?​

Answers

Answer:

0.99kgm/s

Explanation:

Given parameters:

Initial momentum  = 5.8kgm/s

Final momentum  = 6.79kgm/s

Unknown:

Magnitude of the impulse applied to the baseball  = ?

Solution:

To solve this problem;

 The impulse applied to the baseball can be found by using the expression below:

 Impulse  = Final momentum   -   Initial momentum

Impulse  = 6.79kgm/s - 5.8kgm/s  = 0.99kgm/s

which device detects light in the ultraviolet and infrared spectrums in order to alert occupants to fires?

Answers

The device that detects light in the ultraviolet and infrared spectrums in order to alert occupants to fires is called a Flame Detector.

This device typically uses UV and IR sensors to identify the unique light signatures emitted by flames, allowing it to quickly and accurately detect fires and provide alerts to ensure occupant safety. A flame detector is a sensor created to recognize the presence of a flame or fire and act accordingly, enabling flame detection. Depending on the installation, possible responses to a flame detection include sounding an alarm, turning off a fuel line (such as a propane or a natural gas line), and turning on a fire suppression system.

When employed in industrial furnaces, for example, their purpose is to certify that the furnace is operating properly. They can also be used to turn off the ignition system, however frequently they don't do anything more than alert the operator or control system.

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How do you solving kinematic equations for horizontal projectiles?

Answers

See projectiles are very simple unless you understand its core concepts....projectile is nothing just mixture of upward motion and horizontal motion....
THE KEY IS FORGET THE NAME PROJECTILE...ITS JUST HORIZONTAL MOTION + VERTICAL MOTION
How do you solving kinematic equations for horizontal projectiles?

what is the radius of the event horizon for a black hole with a mass of 7.0 times the mass of the sun

Answers

R =(2)(6.67×10−11m^3/kgs2)(1.4×10^31kg)/(3x10^8m/s)^2

R=20,751m

An electric dipole of dipole moment 'p' is placed in the position of stable equilibrium in a uniform field of intensity 'E'. The torque required to rotate, when the dipole makes an angle Ө with the initial position is pE cos Ө pE sin Ө p cos Ө p tan Ө

Answers

Answer:

Torque by electric dipole = pEcos thita

Um, I need help finding objects- Name some for me, please :(

Answers

Answer:

table, book, water bottle, bed, vase, statue, etc.

Answer:

Every thing around you right now? is an object, your computer is an object also

Explanation:

Categorize each description below under the principle that describes that particular behavior of fluids.
Descriptions:
Describes hydraulic lifts
Describes airplane flight
Describes floating objects
Buoyant force equals weight of fluid displaced
Pressure decreases as a fluid moves faster
Pressure is the same throughout an enclosed fluid
Principles:
Archimedes' principle
Bernoulli's principle
Pascal's principle

Answers

each description below under the principle that describes that particular behavior of fluids:

Buoyant force equals weight of fluid displaced - Archimedes' principle

Pressure decreases as a fluid moves faster - Bernoulli's principle

Pressure is the same throughout an enclosed fluid - Pascal's principle

Describes hydraulic lifts - Pascal's principle

Describes airplane flight - Bernoulli's principle

Describes floating objects - Archimedes' principle

What is fluid?

Fluids are defined as any material that flows in response to an applied force; hence, liquids and gases are fluids. Fluids are non-fixed-shape substances that flow readily due to enlarged intermolecular gaps. Fluids include both liquids and gases. When exposed to such a stress, a fluid, any liquid or gas, or any substance in general cannot maintain a tangential, or shearing, force and suffers a constant change in form.

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a weather emergency siren is mounted on a tower, 105 m above the ground. on one hand, it would be a good idea to make the siren very loud so that it will warn as many people as possible. on the other hand, safety regulations prohibit the siren from exceeding an intensity level of 116 db for workers standing on the ground directly below the siren. assuming that the sound is uniformly emitted, what is the maximum power that the siren can put out? maximium power output: 4387.95 tools x10y w how far away from the base of the tower can a person be and still be able to hear the siren? neglect any absorption of sound energy by the air; although, in reality, such absorption would be significant at long distances. maximum audible distance:

Answers

The maximum power that the siren can put out is of 4.74 dB.

Given that,

The height of the tower above the ground is, h = 105 m

Sound intensity from the siren is, I = 116 dB

We know that, the maximum intensity of sound allowed is 11.6 B.

Then the intensity of sound in terms of W/m² can be found as follows,

log(I / I₀) = 11.6

I / I₀ = 10¹¹°⁶

I = 10¹¹°⁶ * I₀

⇒ 10¹¹°⁶ * 10⁻¹²

⇒ 10⁻⁰°⁴

At 105 m above the ground the intensity will be 105² times.

Then the intensity at source point = 10⁻⁰°⁴ * 105²

⇒ 0.398 * 105² = 4387.95 W/m²

The energy of sound from the source is given as,

4π* intensity= 4* 3.14* 4387.95 = 55112.65 W/m²

To convert into decibels:

log(55112.65/ 10⁻¹²) = log(55112.65+12) = 4.74 dB

Thus, we can conclude that the maximum power that the siren can put out is of 4.74 dB.

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(a) Derive an expression for the force per unit length between two long straight parallel current carrying conductors .Hence define SI unit of current (Ampere).

Answers

Answer:

F/L = μ₀I₁I₂/2πr

when a force of 2 x 10⁻⁷ N is produced between two conductors 1 m apart from each other and having a cross-sectional radius 1 m. The current on each conductor in this situation is 1 Ampere

Explanation:

Consider two conductors of same length parallel to each other. The Magnetic field due to current in 1st conductor is given by Ampere's Law as:

B₁ = μ₀I₁/2πr

where,

B₁ = Magnetic Field due to Conductor 1

μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²

I₁ = Current through conductor 1

r = radius of cross section of conductor

Now, the force of the conductors on each other is given by:

F₁₂ = B₁I₂L

where,

F₁₂ = Force of conductor 1 on conductor 2

B₁ = Magnetic Field of Conductor 1

I₂ = Current through conductor 2

L = Length

Therefore,

F₁₂ = μ₀I₁I₂L/2πr

The force of conductor 2 on conductor will also have same magnitude but opposite direction:

F₁₂ = |- F₂₁| = F

F/L = μ₀I₁I₂/2πr

F/L = μ₀I₁I₂L/2πr

Now, to define S.I unit of current (Ampere) we substitute values:

F/(1 m) = (4π x 10⁻⁷ N/A²)(1 A)(1 A)/2π(1 m)

F = 2 x 10⁻⁷ N

So, when a force of 2 x 10⁻⁷ N is produced between two conductors 1 m apart from each other and having a cross-sectional radius 1 m. The current on each conductor in this situation is 1 Ampere

An airplane starts from rest and accelerates at a constant rate of 3.0 m/s^2 for 30.0 s before leaving the ground.

Answers

Answer:

90m/s

Explanation:

acceleration depicts the rate of change in velocity per time, therefore an acceleration of 3m/s² means the object increases its velocity 3m/s every second therefore the second squared in the denominator

acceleration = (3m/s)/1s =3m/s²

Therefore, if the plane starts from rest (initial speed = 0m/s) and it increases 3m/s every second for 30 seconds you would have:

final_speed = initial_speed + 3m/s²*30s =0+3*30 m*s/s² = 90 m/s

A net force of 1,377 N accelerate a car from rest to 62.07 km/h in5.717 seconds. What is the weight of the car?

Answers

Given

F: Net force

a: accelaration

v0: initial speed

vf: final speed

t: time

Data

F = 1377 N

v0 = 0 m/s

vf = 62.07 km/h

t = 5.717

Procedure

Newton's second law of motion pertains to the behavior of objects for which all existing forces are not balanced. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object

\(F=ma\)

Now let us calculate the acceleration of the vehicle. But, first we must transform the units from km/h to m/s

v0 = 0km/h = 0m/s

vf = 62.07 km/h = 17.24 m/s

\(\begin{gathered} a=\frac{v_f-v_o}{t} \\ a=\frac{17.24-0\text{ m/s}}{5.717\text{ s}} \\ a=3.015\text{ m/s}^{}^2 \end{gathered}\)

Now let's calculate the mass of the car

\(\begin{gathered} m=F/a \\ m=\frac{1377N}{3.015m/s^2} \\ m=0.456\operatorname{kg} \end{gathered}\)

Now to calculate the weight of the car

\(\begin{gathered} W=mg \\ W=0.456\operatorname{kg}\cdot9.8m/s^2 \\ W=4475.8N \end{gathered}\)

The weight of the car is 4475.8N

you are asked to prepare 100ml of a 1.5m kbr solution. what mass of kbr do you need? show your calculation in the space provided.

Answers

To prepare 100ml of a 1.5m Kbr solution, 1.785 g of KBr is required.

Potassium bromide, also referred to as KBr, is a salt that is frequently employed as a sedative and anticonvulsant.

Kalii bromidum, tripotassium tribromide, and potassium bromide salt are some other names for potassium bromide.

The taste of the odorless potassium bromide salt, which comes in white crystals, colorless crystals, and white granular solids, is sharp, bitter, salty. The pH of aqueous KBr solutions is 7.

we can use the formula:

mass = molarity x volume x molar mass

where molar mass of KBr is 119.00 g/mol.

So,

mass = 1.5 M x 100 ml x (119.00 g/mol) / 1000 ml/L

mass = 1.785 g

Therefore, 1.785 g of KBr is required to prepare 100 ml of a 1.5 M solution.

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In the figure (Figure 1) the top wire is 1. 4 mm -diameter copper wire and is suspended in air due to the two magnetic forces from the bottom two wires. The current flow through the two bottom wires is 88A in each. Calculate the required current flow in the suspended wire

Answers

In the figure below the top wire is 1.20 mm diameter copper wire and is suspended in ...
1 answer
In the figure below the top wire is 1.20 mm diameter copper wire and is suspended in air due to the magnetic forces from the two bottom wires. The current ...

There are 24 time zones on earth separated by ________ degrees of longitude. fill in the number that goes in the blank, do not use any symbols just numbers.

Answers

There are 24 time zones on Earth separated by 15 degrees of longitude.

Each time zone represents a specific region where the local time is the same.

These time zones help coordinate activities and schedules across different parts of the world.

In conclusion, the Earth is divided into 24 time zones, each separated by 15 degrees of longitude.

Every time the earth rotates within a 24-hour period, it covers a 360° arc. According to this, it rotates 15° in an hour.

Thus, although there are few anomalies that take into account political boundaries, time zones have been divided into 24 equally spaced time zones for convenience's sake.

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a 0.165 kg mass is attached to a spring and undergoes simple harmonic motion with a period of 0.95 s. the total energy of the system is 3.1 j. find the amplitude of the motion. answer in units of m.

Answers

The amplitude of the motion is 0.608.The amplitude of a particle is its maximum departure from its equilibrium position or mean position, and its direction is always in the opposite direction.

What is the amplitude of the motion?

The amplitude of a particle is its maximum departure from its equilibrium position or mean position, and its direction is always in the opposite direction. Its dimensions are [L1M0 T0] and its S.I. unit is the meter.

It alludes to the greatest departure from equilibrium that an object in periodic motion can exhibit. As an illustration, consider how a pendulum moves through its equilibrium point (straight down) and then moves outward to its maximum distance.

The motion's angular frequency is

W=2\(\pi\)/T

  =2\(\pi\)/0.95

  =6.61

w=√k/m on a spring for a mass. Rearranging this formula results in

                                    k=wm²=0.165×6.61×6.61=7.209 N/m

A system performing simple harmonic motion has a total energy of

   E=a²k÷2 .Rearranging this formula results in

a=√2E÷k=√2×3.1÷7.209

   =0.608 m

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The voltage across two points in an electric circuit is
876 mV. A power source does 1 901 kJ of work
when moving a certain amount of charge between
these two points.
Determine the amount of charge that moved between
between the two points.

Answers

Answer:

V=w/q V= 1.2/0.4* 10 ^-3 V = 3 * 10 ^ 3 V = 3000 v

if its not correct let me know so I can figure it out

If a conductor is connected to "ground", then what is the charge on it?

positive

neutral

negative

determined by other nearby charges

Answers

If the conductor is connected to the ground, then it has a neutral charge.

Earth acts as a zero potential ground. So when you connect a positively charged conductor to the ground, the positive charge flows into the ground, resulting in the flow of electrons from the ground to the conductor. A ground wire acts as protection against unstable currents.

Under normal circuit conditions, no current flows through the ground wire. However, when an electrical accident such as a short circuit occurs, the ground wire removes the unstable current from the electrical system and leads it to the ground. The ground wire can be finger-safe as long as there is no electrical surge that causes current to flow through the ground wire.

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The path of a charged particle moving parallel to a uniform magnetic field will be a:______.

Answers

The path of a charged particle moving parallel to a uniform magnetic field will be straight line

Force on a charged particle moving in a magnetic field can be calculated by = q.(v*B )

q = charge of the particle

v = velocity of the particle

B = magnetic field

theta = angle between v and B

q . (v B sin (theta) )

Since,  particle is parallel to the magnetic field

hence , theta = 0°

so sin(theta) = sin 0° = 0

hence , force = 0

since , there is no force acting on the particle it will remain in that motion in hat it was when it initially came in the magnetic field . Hence It will be moving along a straight line path because the magnetic force on the charged particle is zero.

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A golf ball of mass 0.045 kg is hit off the tee at a speed of 34m/s . The golf club was in contact with the ball for 3.50*10^-3s .
Find the impulse imparted to the golf ball.??
Find the average force exerted on the ball by the golf club.??
Express your answer to two significant figures and include the appropriate units.

Answers

The average force exerted on the ball by the golf club is 490 N.

Thus,  F = p/t = 0.49 * 10³ N = 490 N.

Momentum is a metric for power and how challenging it is to stop an object. Zero momentum applies to any object that is not moving. tremendous, slow-moving objects have tremendous amounts of momentum.

A small, swiftly moving object also possesses a significant momentum. A bowling ball, for instance, has more momentum than a ping-pong ball if their velocities are equal.

This is because bowling balls are larger in mass than ping-pong balls.

Thus, The average force exerted on the ball by the golf club is 490 N.

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I RLLY NEED HELPPPP : A rusty pulley is used to lift a 2450 N motorcycle onto a transport truck. What is the efficiency of the pulley if 3500 N is used to lift the motorcycle 1.5 m onto the truck?

Answers

To calculate the efficiency of the pulley, we need to compare the actual work done by the pulley to the ideal work that should have been done.

The work (W) done in lifting an object is given by the equation:

W = F * d * cos(theta)

Where:

F is the applied force

d is the displacement

cos(theta) is the cosine of the angle between the applied force and the direction of displacement.
In this case, the applied force is 3500 N, the displacement is 1.5 m, and the angle between the force and displacement is 0 degrees (since they are in the same direction).
Therefore, the actual work done by the pulley is:

W_actual = 3500 N * 1.5 m * cos(0 degrees)

W_actual = 5250 J (joules)
The ideal work (W_ideal) would be the work done if the applied force were equal to the weight of the motorcycle (2450 N) and there were no energy losses.

W_ideal = 2450 N * 1.5 m * cos(0 degrees)

W_ideal = 3675 J (joules)
The efficiency (η) of the pulley is given by the ratio of the actual work done to the ideal work:

η = (W_actual / W_ideal) * 100%

Plugging in the values, we have:

η = (5250 J / 3675 J) * 100%

η ≈ 142.86%
Therefore, the efficiency of the pulley is approximately 142.86%.

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In an experiment, the percentage of error occurred in the measurement of physical quantities A, B, C and D are 1 %, 2 %, 3% and 4% respectively. Then the maximum percentage of error in the measurement of X,
where \(X = \frac{A^{2}B^{1/2} }{C^{1/3} D^3}\) , will be :

(a) 16%
(b) -10%
(c) 10%
(d) \([\frac{3}{13}]\) %

WITH WORKING PLSS!!!

Answers

The maximum percentage of error in the measurement of X is 10%.

So, the correct option is (c) 10%.

To find the maximum percentage of error in the measurement of X, we need to determine how the errors in the measurements of A, B, C, and D affect the calculation of X.

Let's assume that X is calculated using the formula:

X = A + B - C × D

To find the maximum percentage of error in X, we need to consider the worst-case scenario where all the errors add up in the same direction.

Let's calculate the maximum percentage of error step by step:

Percentage error in A = 1%

Percentage error in B = 2%

Percentage error in C = 3%

Percentage error in D = 4%

To calculate the maximum percentage error in X, we'll add up the absolute values of the errors:

Maximum percentage error in X = |1%| + |2%| + |3%| + |4%|

= 1% + 2% + 3% + 4%

= 10%

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the temperature at which water boils in la paz bolivia is 88 °c. convert this temperature in fahrenheit.

Answers

The temperature at which water boils in La Paz, Bolivia is approximately 190.4 °F.

The temperature at which water boils in La Paz, Bolivia is 88 °C. To convert this temperature to Fahrenheit, we can use the formula:
°F = (°C x 1.8) + 32

So,
°F = (88 x 1.8) + 32
°F = 190.4

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